To evaluate the predictive performance of the tree model, we need to create the lift chart using the test data and analyze its shape.
A lift chart is a graphical representation of the performance of a predictive model. It can be used to evaluate the effectiveness of a model in identifying a target variable, compared to a random guess. The lift chart shows how much better the model is performing than a random guess, at different levels of the target variable.
To produce a lift chart for a decision tree model, we typically first rank the test data according to the predicted probabilities of the target variable. Then, we divide the data into equal-sized segments, called quantiles, based on the predicted probabilities. For example, if we divide the data into 10 quantiles, the first quantile will contain the 10% of cases with the lowest predicted probabilities, the second quantile will contain the next 10% of cases, and so on, up to the 10th quantile, which will contain the 10% of cases with the highest predicted probabilities.
For each quantile, we calculate the ratio of the number of cases in that quantile that have the target variable to the number of cases we would expect to see if the model was performing no better than random chance. This ratio is called the lift, and it represents how much better the model is performing than random chance, at that level of the target variable.
We can then plot the lift for each quantile on a graph, with the x-axis representing the quantiles and the y-axis representing the lift. A good model will have a lift chart that is above the diagonal line, which represents the performance of a random guess.
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Jaxon made 5% of his free throws over the season. If he shot 220 free throws, how many did he make?
Answer:
Jaxon made 11 free throws over the season.
Step-by-step explanation:
If he made 5% of his free throws, we know that he will make 5% of the total number of free throws he took, which is 220:
We multiply 220 by 0.05, or 5% to find out how many free throws he made:
220*0.05 = 11
After that, we now know that Jaxon made 11 of his free throws out of 220 over the course of the season, or 5%.
Label the net for the cylinder. Then find the surface area of the cylinder. Give your answer in terms of π and as a decimal number rounded to the nearest tenth.
The surface area of the cylinder is approximately 94.2 ft².
What is surface area?Surface area refers to the total area of the external or outer part of an object. It is the sum of the areas of all the individual surfaces or faces of the object. Surface area is typically measured in square units, such as square inches (in²), square feet (ft²), or square meters (m²), depending on the unit of measurement used.
According to the given information:
The surface area of a cylinder is the sum of the lateral surface area (the curved surface) and the area of the two circular bases.
The formula for the lateral surface area of a cylinder is given:
Lateral Surface Area = 2πrh
where r is the radius of the cylinder and h is the height of the cylinder.
Plugging in the given values for the radius (r = 3 ft) and height (h = 2 ft), we can calculate the lateral surface area:
Lateral Surface Area = 2π * 3 * 2 = 12π ft²
The formula for the area of a circle (which represents the bases of the cylinder) is given:
Circle Area = πr²
Plugging in the given value for the radius (r = 3 ft), we can calculate the area of each circular base:
Circle Area = π * 3² = 9π ft²
Since there are two bases in a cylinder, we multiply this by 2 to account for both bases:
2 * Circle Area = 2 * 9π = 18π ft²
Now, we can add the lateral surface area and the area of the two bases to find the total surface area of the cylinder:
Total Surface Area = Lateral Surface Area + 2 * Circle Area
= 12π + 18π
= 30π ft²
As a decimal rounded to the nearest tenth, the surface area of the cylinder is approximately 94.2 ft²
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Trigonometric funcions
Which equation are true
Answer:
C and D
Step-by-step explanation:
cosA = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{4}{5}[/tex] ⇒ C
sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{3}{5}[/tex] ⇒ D
HELP!! View image! THANK U
The probability of selecting no Independents is $\frac{{7 \choose 2} + {8 \choose 2}}{{20 \choose 2}} = \frac{91}{190} \approx 0.4789$.
In ABC, m A= 62° and mB=39⁰.
In XYZ, m Y=39° and m Z=79⁰.
Include in Your Answer:
What is mC?
What is mX?
• Is it possible for these two triangles to be similar? Why or
why not?
y
∝
√
x
If
y
=
60
when
x
=
36
find,
x
when
y
=
80
If y is proportional to the square root of x and y = 60 when x = 36, then the value of x when y = 80 is 64
We are given that y is proportional to the square root of x, or y ∝ √x.
Using the constant of proportionality k, we can write this relationship as:
y = k√x
To solve for k, we can use the values given in the problem
y = 60, x = 36
60 = k√36
60 = k × 6
k = 60 / 6
Divide the numbers
k = 10
Now that we know k, we can use the same equation to find x when y = 80
80 = 10√x
Squaring both sides, we get
6400 = 100x
x = 64
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The given question is incomplete, the complete question is:
y ∝ √x If y = 60 when x = 36, find x when y = 80.
Nina uploaded a funny video on her website, which rapidly gains views over time.
The relationship between the elapsed time, ttt, in days, since Nina uploaded the video, and the total number of views, V(t)V(t)V, left parenthesis, t, right parenthesis, is modeled by the following function:
V(t)=500⋅(1. 8)t
Complete the following sentence about the daily percent change in the views of the video.
Every day,
\%%percent of views are
the total number of views of the video
Every day, the number of views of the video increases by 80% of the previous day's views.
Every day, the number of views of the video increases by a certain percentage. To find the daily percent change in the views, we can use the formula for percent change, which is given by:
percent change = ((new value - old value) / old value) * 100
In this case, the old value is the number of views at the start, which is 500, and the new value is the number of views after one day, which is given by:
V(1) = 500*(1.8)^1 = 900
Substituting these values into the formula, we get:
percent change = ((900 - 500) / 500) * 100 = 80%
In other words, for every day that passes, the number of views of the video is multiplied by a factor of 1.8.
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Perform the operation. ( − 10x ^2 + 2 x− 10 ) − (-10x^2+3)
Answer:
2x-13
Step-by-step explanation:
First flip the operation to be (-10x^2+2x-10) + (10x^2-3).
Then you simplify it. The 10x^2 would get canceled out. You would then get 2x-13.
Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of 13 people took the trip. She was able to purchase coach tickets for $380
and first class tickets for $1200. She used her total budget for airfare for the trip, which was $9040. How many first class tickets did she buy? How many coach tickets did she buy?
number of first class tickets bought=
Answer: Sarah bought 5 first class tickets and (13-5) = 8 coach tickets.
Step-by-step explanation: The taken a toll of one to begin with lesson ticket is $1200 and the fetched of one coach ticket is $380.
So, the full taken a toll of first class tickets would be 1200x and the entire cost of coach tickets would be 380(13-x) = 4940 - 380x.
The overall fetched of the tickets is given as $9040, so we will set up the taking after condition:
1200x + 4940 - 380x = 9040
Streamlining and tackling for x, we get:
820x = 4100
x = 5
Explain why the value of 0.6 is greater than the value of 0.39.
Answer:
B
Step-by-step explanation:
The value of 0.6 is greater than the value of 0.39 because 0.6 represents a larger proportion or fraction of a whole than 0.39 does.
To compare these two values, we can think of them as parts of a whole. For example, we can consider 0.6 as 60% of a whole and 0.39 as 39% of the same whole. When we compare 60% and 39%, it is clear that 60% is greater than 39%.
Another way to compare these two values is to convert them to fractions. 0.6 can be written as 6/10 or 3/5, while 0.39 can be written as 39/100.
When we compare 6/10 and 39/100, we can see that 6/10 is greater than 39/100 because 6/10 represents 6 parts out of 10, while 39/100 represents 39 parts out of 100.
Therefore, we can conclude that the value of 0.6 is greater than the value of 0.39 because it represents a larger proportion or fraction of a whole.
Find H. C. F of each set of number using long division method 80,215,245and720
The H. C. F of 80,215,245 and 720 using long division method is 5.
The long division method to find the Highest Common Factor (H.C.F.) of 80, 215, 245, and 720.
Divide the largest number by the smallest number.
720 ÷ 80 = 9 with a remainder of 0
Divide the smallest number by the remainder from the previous step.
80 ÷ 40 = 2 with a remainder of 0
Divide the remainder from the previous step by the next smallest number.
40 ÷ 5 = 8 with a remainder of 0
Divide the remainder from the previous step by the next smallest number.
5 ÷ 5 = 1 with a remainder of 0
We have reached a remainder of 0, which means that 5 is the H.C.F. of the given numbers.
Therefore, the H.C.F. of 80, 215, 245, and 720 is 5.
We can also verify this by listing the factors of each number and finding the common factors:
80: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80
215: 1, 5, 43, 215
245: 1, 5, 7, 35, 49, 245
720: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 16, 18, 20, 24, 30, 36, 40, 45, 48, 60, 72, 80, 90, 120, 144, 180, 240, 360, 720
The common factors are 1, 5, and 40.
The largest common factor is 5, which is the same as what we obtained using the long division method.
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5. Select Yes or No to indicate whether each ordered pair is a point of intersection
between the line x - y = 6 and the circle y² - 26 = -x².
Ordered Pair
(1,-5)
(1,5)
(5,-1)
To determine if each ordered pair is a point of intersection between the line x - y = 6 and the circle y² - 26 = -x², we need to substitute the values of x and y in both equations and see if they are true for both.
Select Yes or No to indicate whether each ordered pair is a point of intersectionFor the ordered pair (1, -5):
x - y = 6 becomes 1 - (-5) = 6, which is true.
y² - 26 = -x² becomes (-5)² - 26 = -(1)², which is false.
Therefore, (1, -5) is not a point of intersection.
For the ordered pair (1, 5):
x - y = 6 becomes 1 - 5 = -4, which is false.
y² - 26 = -x² becomes (5)² - 26 = -(1)², which is true.
Therefore, (1, 5) is a point of intersection.
For the ordered pair (5, -1):
x - y = 6 becomes 5 - (-1) = 6, which is true.
y² - 26 = -x² becomes (-1)² - 26 = -(5)², which is false.
Therefore, (5, -1) is not a point of intersection.
So the answer is:
(1,-5) - No
(1,5) - Yes
(5,-1) - No
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An object moving at speed s for time t travels distance st. The Brown family is taking a road trip. This morning, they drove for 2. 5 hours at a speed of 65 miles per hour. How far did the family drive this morning?
Write your answer as a whole number or decimal
The total distance Brown family drove this morning at the speed of 65 miles per hour in 2.5 hours is equal to 162.5 miles.
Let 's' represents the speed of the moving object.
And 't' represents the time to cover distance.
The speed was 65 miles per hour.
And the time they drove was 2.5 hours.
The distance the Brown family drove this morning
= Multiplying their speed by the time they drove.
This implies,
distance = speed x time
Substitute the values we have,
The distance they drove this morning is equal to,
⇒ distance = 65 miles per hour x 2.5 hours
⇒ distance = 162.5 miles
Therefore, the distance drove by Brown family this morning is 162.5 miles at the speed of 65 miles per hour.
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Problem
The table compares the heights (in centimeters) and the weights (in kilograms) of Karim's friends.
Can the weight of Karim's friends be represented as a function of their height?
Height (centimeters) Weight (kilograms)
163
163163
65
6565
167
167167
70
7070
154
154154
60
6060
172
172172
70
7070
167
167167
68
6868
159
159159
58
5858
160
160160
64
6464
166
166166
69
6969
Choose 1 answer:
Choose 1 answer:
(Choice A) Yes
A
Yes
(Choice B) No
B
No
Weight cannot be represented as a function of height.
Can the weight be represented as a function of their height?No, the weight of Karim's friends cannot be represented as a function of their height.
To represent weight as a function of height, there should be a consistent relationship between the height and weight values.
However, from the given data, we can see that for the same height, there are different weight values, and for the same weight, there are different height values.
This indicates that there is no one-to-one relationship between height and weight, and hence weight cannot be represented as a function of height.
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clerks at mosier data systems key in thousands of insurance records each day for a variety of client firms. samples of the work of 20 clerks are gathered. ceo donna mosier carefully examines 100 records entered by each clerk and counts the number of errors. mosier wants to set control limits to include 99.73% of the random variation in the data entry process. which type of process control chart should she use?
Donna Mosier should use an Individuals control chart to set control limits for the data entry process.
An Individuals control chart is a type of process control chart used to monitor the process when the sample size is one. In this case, Mosier is examining 100 records entered by each of the 20 clerks, making the sample size one.
To set control limits that include 99.73% of the random variation in the data entry process, Mosier can use the following steps:
Calculate the mean and standard deviation of the number of errors for each clerk based on the 100 records examined.Calculate the Upper Control Limit (UCL) and Lower Control Limit (LCL) using the formulas: UCL = mean + 3 * standard deviation and LCL = mean - 3 * standard deviation.Plot the individual data points for each clerk on the Individuals control chart, with the UCL and LCL as the upper and lower boundaries, respectively.Monitor the data points over time to detect any trends, shifts, or out-of-control points that may indicate a process issue.By using an Individuals control chart, Mosier can set control limits to monitor the data entry process and detect any issues before they become major problems.
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I need some help bro
Answer:
first answer is correct
y = -1/2 x^2 + x + 1
Step-by-step explanation:
based on the graph, you can find two points
(2,1) and (0,1)
I input (2, 1) to each equation to check
y = -1/2 x^2 + x + 1 is correct
please help! and explain and show work of how you got the answer. I will mark you brainliest.
Answer: i dont know if this is right but i put a^4+b^4=c^4
Step-by-step explanation:
I have no idea tho
patients scheduled to see their primary care physician at a particular hospital wait, on average, an additional eight minutes after their appointment is scheduled to start. assume the time that patients wait is exponentially distributed. what is the probability a randomly selected patient will see the doctor within eleven minutes of the scheduled time?
The probability is approximately 0.446 or 44.6%.
Waiting time is exponentially distributed, we can use the cumulative distribution function (CDF) of the exponential distribution to solve this problem.
Let X be the waiting time in minutes.
X is exponentially distributed with a mean of 8 minutes.
The rate parameter λ is equal to 1/8.
The CDF of the exponential distribution is given by:
[tex]F(x) = 1 - e^(-\lambda x)[/tex]
The probability that a patient will see the doctor within eleven minutes of the scheduled time.
The value of F(11) - F(0).
[tex]F(11) = 1 - e^(-\lambda \times 11) = 1 - e^(-11/8)[/tex] ≈ 0.554
[tex]F(0) = 1 - e^(-\lambda \times 0) = 1 - e^0 = 1[/tex]
Therefore, the probability that a randomly selected patient will see the doctor within eleven minutes of the scheduled time is:
F(11) - F(0) ≈ 0.554 - 1 ≈ 0.446
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20. The wallpaper border that runs all the way around a room is 5f² +19f+ 11 long. Three sides of the room have the following lengths of border: 6f, 5f-7, 2f^2+2. What is the length of the fourth side of the room?
In linear equation, 3f² + 8f + 16 feet is the length of the fourth side of the room.
What is linear equation?
An algebraic equation with simply a constant and a first- order( direct) element, similar as y = mx b, where m is the pitch and b is the y- intercept, is known as a linear equation.
The below is sometimes appertained to as a" direct equation of two variables," where y and x are the variables. Equations whose variables have a power of one are called direct equations. One illustration with only one variable is where layoff b = 0, where a and b are real values and x is the variable.
= 5f² + 19f + 11 - 6f - 5f + 7 - 2f² - 2
= 3f² + 8f + 16 feet
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The expression that represent the length of the fourth side of the room is [tex]3f^2 + 8f + 16[/tex].
What is expression ?
Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation. Unknown variables, integers, and arithmetic operators are the components of an algebraic expression. There are no symbols for equality or inequality in it.
Here Total length of the room = [tex]5f^2+19f+11[/tex]
Three sides length of the room = 6f , 5f-8 and [tex]2f^2+2[/tex]
Fourth side = Total length - sum of length of three sides
=> [tex]5f^2+19f+11-(6f+5f-7+2f^2+2)[/tex]
=> [tex]5f^2+ 19f + 11 - 6f - 5f + 7 - 2f^2 - 2[/tex]
=> [tex]3f^2 + 8f + 16[/tex] .
The expression that represent the length of the fourth side of the room is [tex]3f^2 + 8f + 16[/tex].
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Currently, Jana's grandmother is 5.25 times older than Jana.
Jana's mother is 2.5 times older than Jana. In 3 years, the sum
of all three of their ages will be 149 years. Write and solve an
equation to find Jana's current age. Then find her mother's
and grandmother's current ages.
Step-by-step explanation:
j = jana's age
m = mom's age = 2.5 j
g = grandma's age = 5.25 j summed, they equal 149 IN THREE YEARS
j+3 + 2.5j +3 + 5.25 j + 3 = 149
8.75 j + 9 = 149
8.75 j = 140
j = 16 y/o
mom = 2.5 j = 40 y/o
g-ma = 5.25 j = 84 y/o
lee had scored the following points in his first 8 games 12,14,14,15,8,10,3,15 enter the number of points lee needs to score in the nest game to increase his keam score to 13 points
Lee needs to score a total of 26 points in the next game to increase his mean score to 13 points.
Calculating the score in the next gameGiven that
Scores = 12,14,14,15,8,10,3,15
To increase his mean score to 13 points,
Lee needs to have a total of 13 x 9 = 117 points after the next game.
He has already scored a total of 12+14+14+15+8+10+3+15 = 91 points in the first 8 games.
Therefore, Lee needs to score a total of 117 - 91 = 26 points in the next game to increase his mean score to 13 points.
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Your friend incorrectly factors the expression below as 7x(5-2xy). Factor the expression below correctly. What error did your friend make?
35x - 14xy
Answer:
The answer is 7x(5-2y)
Step-by-step explanation:
35x-14xy
7x(5-2y)
the error made is the x in the bracket
Anyone have the answers
Answer:
The answer is 7 pens
what is the confidence interval estimate of the population mean examination score if a sample of applications provided a sample mean (to the nearest whole number
This means that we can be 95% confident that the true population means examination score falls within this range based on the sample data.
The confidence interval estimate of the population means examination score can be calculated using the sample mean and the margin of error. The margin of error depends on the level of confidence and the sample size.
For example, if a sample of 100 applications provided a sample mean score of 80, and a 95% confidence level is used, the confidence interval estimate of the population mean examination score would be:
Margin of error = (critical value) x (standard error)
The critical value for a 95% confidence level with 99 degrees of freedom is 1.984. The standard error can be calculated using the formula:
Standard error = (standard deviation) / sqrt(sample size)
If the standard deviation of the examination scores is known, it can be used in the formula. If not, the sample standard deviation can be used as an estimate.
Assuming a sample standard deviation of 10, the standard error would be:
[tex]Standard\ error = \frac{10} { \sqrt{(100)}} = 1[/tex]
Therefore, the margin of error would be:
Margin of error = 1.984 x 1 = 1.984
The confidence interval estimate of the population means examination score would be:
80 ± 1.984, or between 78.016 and 81.984.
This means that we can be 95% confident that the true population means examination score falls within this range based on the sample data.
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The 95% confidence interval for the population mean examination score would be between 72.23 and 77.77, to the
nearest whole number.
To determine the confidence interval estimate of the population mean examination score based on a sample mean
provided to the nearest whole number, we need to know the sample size and the level of confidence.
Assuming a normal distribution and a level of confidence of 95%, we can use the following formula to calculate the
confidence interval estimate:
Confidence interval = sample mean +/- (critical value) x (standard error)
The critical value can be found using a t-distribution table or a calculator, based on the sample size and degrees of
freedom (n-1). For a sample size of 30 or more, we can use the z-score instead of the t-score.
The standard error is the standard deviation of the sample divided by the square root of the sample size.
For example, if a sample of 50 applications provided a sample mean of 75, and the standard deviation was 10, the
standard error would be 10/sqrt(50) = 1.41.
Assuming a level of confidence of 95%, the critical value for a sample size of 50 and degrees of freedom of 49 would be 1.96.
Therefore, the confidence interval estimate would be:
75 +/- 1.96 x 1.41 = 75 +/- 2.77
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#4 Please help!!!!!!!!!!
Answer:150°
Step-by-step explanation:
Evan takes 100 milligrams of medicine. The amount of medicine in his bloodstream decreases by 0.4 milligram each minute for a number of minutes, m, after that. He writes the expression 100 - 0.4m to find the amount of medicine in his bloodstream after m minutes. Which statement about his expression is true?
The statement that is true about Evan's expression is that it represents a linear function of the amount of medicine in his bloodstream, where the initial amount is 100 milligrams and the rate of change is -0.4 milligrams per minute.
What is the equivalent expression?
Equivalent expressions are expressions that perform the same function despite their appearance. If two algebraic expressions are equivalent, they have the same value when we use the same variable value.
The expression 100 - 0.4m represents the amount of medicine in Evan's bloodstream after m minutes, where the amount of medicine decreases by 0.4 milligrams each minute.
The coefficient of the variable m (-0.4) represents the rate of change of the amount of medicine in Evan's bloodstream per minute. It tells us that for every one minute that passes, the amount of medicine in his bloodstream decreases by 0.4 milligrams.
The constant term (100) represents the initial amount of medicine in Evan's bloodstream before the medicine starts to decrease.
Therefore, the statement that is true about Evan's expression is that it represents a linear function of the amount of medicine in his bloodstream, where the initial amount is 100 milligrams and the rate of change is -0.4 milligrams per minute.
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cuantos números
primos son a la vez la suma y la diferencia
Answer: there is only one number
Answer:
Solo hay un número primo que se puede escribir como suma de dos números primos y también como diferencia de dos números primos.
Espero haber ayudado :D
which data set is more centered around a high peak??
a. may
b. july
c. neither
d. both
The correct option a. may.The data shown in the may histogram is more centered around a high peak.
Explain about the histograms:A graph called a histogram is used to show the frequency distribution of a small number of data points for a single variable.
Histograms frequently divide data into different "bins" or "range groups" and count however many points are in each bin.The histogram illustration below shows test results for students. The scores of the student are divided into various ranges. Each bar's height indicates the number of students who received a score within that range.For the given two histograms,
May has the peak value for the frequency of day at 14.
July has the peak value for the frequency of day at 10.
Thus, The data shown in the may histogram is more centered around a high peak.
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Complete question-
which data set is more centered around a high peak??
a. may
b. july
c. neither
d. both
The diagram for the question is shown.
What are the domain and range of this exponential function?y=2x–9
The value of both domain and range of this exponential function is (−∞,∞).
y = 2x-9
The domain of the function can be defined as all real numbers except the ones where the expression is undefined. In the case of 2x-9, there is no real number for which this expression is undefined. Therefore, a domain of this exponential function is (−∞,∞).
The range of the function is defined as the set of all valid y values. In this case, all real numbers are valid values of y. Therefore, the range of this exponential function is (−∞,∞).
Therefore, domain of y = 2x-9 is (−∞,∞) and range is also (−∞,∞).
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Solve the equation
2x/3+1=7x/15+3
The answer is X = 10
⇒ Given [tex]\frac{2x}{3} + 1 = \frac{7x}{15} + 3[/tex]
⇒ [tex]\frac{2x+3}{3} = \frac{7x+45}{15}[/tex]
⇒ 15(2x + 3) = 3(7x + 45)
⇒ 30x + 45 = 21x + 135
⇒ 30x - 21x = 135 - 45
⇒ 9x = 90
⇒ x = [tex]\frac{90}{9}[/tex]
⇒ Therefore X = 10
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