Answer:
CCl4
Explanation:
Let us look at the structure of CCl4 closely in order to really determine if it is the correct answer to the question or not.
While it is true that the electro negativity of carbon is 2.5 and that of chlorine is 3.0, hence an electro negativity difference of 0.5 exists between carbon and chlorine leading to the presence of four polar covalent bonds in the carbon tetrachloride molecule. We must also observe that the molecule, carbon tetrachloride, has a tetrahedral molecular geometry. This implies that the four dipoles in the molecule are symmetrical and cancel out each other hence the molecule is non polar. Being a non polar molecule, only London forces are expected to be present as an intermolecular force, hence the answer.
A sample of gold weighs 1.2 oz. The sample is pounded into a thin rectangular sheet with an area of 400. sq. ft. The density of gold is 19.3 grams per cm3. What is the thickness of the foil in centimeters?Given: 28.35 g = 1 oz, 1 ft = 12 inches, 1 inch = 2.54 cm
Answer:
thickness of the gold sheet = 4.74 * 10⁻⁶ cm
Explanation:
mass of gold sample = 1.2 oz,; area of rectangular gold sheet = 400 sq. ft
Converting mass of gold from oz. to g
1 oz. = 28.35 g
mass of gold sample in grams = 1.2 * 28.35 g = 34.02 g
Converting from feet to cm;
1 feet = 12 * 2.54 cm = 30.48 cm
1 sq. ft = (30.48)² = 929.0304 cm²
area of gold in cm² = 400 * 929.0304 cm² = 371612.16 cm²
Since the density of a solid is constant
Density = mass/volume
Volume = mass/density
where volume =area * thickness
therefore, area * thickness =mass/density
thickness = mass/(density * area)
substituting the value; thickness = 34.02 g/(19.3 gcm⁻³ *371612.16 cm²)
thickness of the gold sheet = 4.74 * 10⁻⁶ cm
Identify the type of solid for AgCl. Identify the type of solid for AgCl. metallic atomic solid nonbonding atomic solid molecular solid ionic solid networking atomic solid
Silver chloride (AgCl) is a crystalline solid substance that is composed of silver and chloride ions. AgCl is an ionic solid. Thus, option D is correct.
What are ionic solids?Ionic solids are substances that show the properties of solid matter and have ionic, positive, and negative charges in them. They are linked together by the attraction of the opposite charges.
The silver metal in the molecule has a positive charge and the chloride ions are negative in charge making them establish an ionic bond.
The solid molecule is held together by ionic bonds and not the covalent or other metallic bonds. The cations and anions of AgCl are linked together by the electrostatic forces that make their structure appear strong and brittle.
Therefore, AgCl has been known as an ionic solid.
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warming oceans temperatures directly lead to all of the following except A sea level rising B coral bleaching C ocean deoxigenation D pollution
Answer:
D. pollution
Explanation:
Increase in ocean temperature is one of the major consequence of global warming which directly leads to rise in sea level, coral bleaching and ocean deoxygenation.
Warming ocean temperatures do not leads to pollution directly whereas pollution leads to warming ocean temperatures. So, in the case of pollution, the effect is opposite.
Hence, the correct option is D.
A piece of bismuth with a mass of 22.5 g is submerged in 46.3 cm3 of water in a graduated cylinder. The water level increases to 48.6 cm3. What is the density of indium to the proper number of significant figures
Answer:
[tex]\rho = 9.78\frac{g}{cm^3}[/tex]
Explanation:
Hello,
In this case, in order to compute the density of bismuth we need to apply the formula:
[tex]\rho =\frac{m_{Bi}}{V_{Bi}}[/tex]
Nonetheless, the volume is computed by the difference:
[tex]V_{Bi}=48.6-46.3=2.30cm^3[/tex]
Therefore:
[tex]\rho = \frac{22.5g}{2.30cm^300}\\\\\rho = 9.78\frac{g}{cm^3}[/tex]
Regards.
The following skeletal oxidation-reduction reaction occurs under basic conditions. Write the balanced OXIDATION half reaction.
Bi(OH)3 + NO2 → Bi + NO3-
Answer:
[tex]N^{4+}O_2+2OH^-\rightarrow (N^{5+}O_3)^-+1e^-+H_2O[/tex]
Explanation:
Hello,
In this case, for the given reaction, we first start by the writing of the oxidation states of all the involved elements:
[tex]Bi^{3+}(OH)^-+N^{4+}O^{2-}_2\rightarrow Bi^0+(N^{5+}O^{2-}_3)^-[/tex]
In such a way, we are noticing nitrogen is undergoing an increase in its oxidation state, therefore it is being the oxidized species, for which the oxidation half reaction, should be (considering basic conditions):
[tex]N^{4+}O_2+H_2O+2OH^-\rightarrow (N^{5+}O_3)^-+1e^-+2H^++2OH^-\\\\N^{4+}O_2+H_2O+2OH^-\rightarrow (N^{5+}O_3)^-+1e^-+2H_2O\\\\N^{4+}O_2+2OH^-\rightarrow (N^{5+}O_3)^-+1e^-+H_2O[/tex]
Best regards.
A student has a sample of CaSO4 hydrate and it weighs 0.4813 grams. He heats it strongly to drive off the water of hydration, and after subsequent heatings, the student finds the anhydrous compound has a constant mass of 0.3750 grams. Find the formula of the hydrate.(2 points)
Answer:
CaSO4•3H2O.
Explanation:
Let the compound be CaSO4.xH2O.
The following data were obtained from the question:
Mass of hydrated compound (CaSO4.xH2O) = 0.4813g
Mass of anhydrous compound (CaSO4) = 0.3750g
Next we shall determine the mass of the water is the hydrated compound.
This is illustrated below:
Mass of water = mass of hydrated – mass of anhydrous.
Mass of water = 0.4813 – 0.3750
Mass of water = 0.1063g
Next, we shall determine the number of mole of the anhydrous compound and the number of mole of the water present in the compound. This is illustrated below:
Molar mass of anhydrous CaSO4 = 63.5 + 32 + (16x4) = 159.5g/mol
Mass of anhydrous CaSO4 = 0.3750g
Mole of anhydrous CaSO4 =...?
Mole = mass /Molar mass
Mole of anhydrous CaSO4 = 0.3750/159.5 = 2.35×10¯³ mole
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H2O = 0.1063g
Number of mole of H2O =.?
Mole = mass /Molar mass
Mole of H2O = 0.1063/18 = 5.91×10¯³ mole
Next we shall determine the ratio of number of mole of anhydrous CaSO4 to that of H2O. This is illustrated below:
Mole of anhydrous CaSO4 = 2.35×10¯³ mole
Mole of H2O = 5.91×10¯³ mole
Ratio of anhydrous CaSO4 to H2O =>
CaSO4 : H2O => 2.35×10¯³ /5.91×10¯³
CaSO4 : H2O => 1 : 3
Therefore, for 1 mole of the anhydrous CaSO4, there are 3 moles of H2O.
Therefore, the formula for the hydrate compound CaSO4.xH2O => CaSO4•3H2O.
Which one of the following processes is endothermic? A) Boiling a liquid. B) Freezing a solid. C) Condensation of a gas into a liquid. D) Condensation of a gas into a solid.
Answer:
D) Condensation of a gas into a solid.
Explanation:
An endothermic process is a process that absorbs heat from the surroundings.
A) Boiling a liquid.
This gives off heat to the surroundings. An exothermic process.
B) Freezing a solid.
In this process, the water releases heat to the surroundings, so it is an exothermic process
C) Condensation of a gas into a liquid.
As water vapor condenses into liquid, it loses energy in the form of heat. Therefore, this process is exothermic.
D) Condensation of a gas into a solid.
This process absorbs heat from the surrounding, hence it is an endothermic proccess.
Boiling a liquid is an endothermic process.
An endothermic reaction is a type of chemical reaction in which energy is consumed in the form of heat, so the product obtained has more energy than the reactants.
Boiling a liquid is an endothermic process, since the liquid needs heat to transition into a gaseous one.
The endothermic reaction involves an increase in enthalpy, which refers to a magnitude whose variation reveals the level of energy that a thermodynamic system exchanges with the environment.
On the other hand, when the reaction involves releasing energy in the form of heat or light, the process is called an exothermic reaction.
When a matter in a liquid state turns into a solid state (that is, it solidifies) and when a matter in a gaseous state turns into a liquid (it condenses), an exothermic reaction occurs.
Therefore, we can conclude that boiling a liquid is an endothermic process where energy is absorbed in the form of heat.
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Consider the equilibrium reaction. 4A+B↽−−⇀3C After multiplying the reaction by a factor of 2, what is the new equilibrium equation?
A 1.0 L buffer solution is 0.300 M HC2H3O2 and 0.045 M LiC2H3O2. Which of the following actions will destroy the buffer?
a) Adding 0.050 moles of HC2H3O2
b) Adding 0.075 moles of HCl
c) Adding 0.0500 moles of LiC2H3O2
d) Adding 0.050 moles of NaOH
e) None of the above will destroy the buffer.
Answer:
b) Adding 0.075 moles of HCl
Explanation:
A buffer is defined as the aqueous mixture of a weak acid and its conjugate base or vice versa (Weak base with its conjugate acid).
The buffer of the problem is the acetic acid / lithium acetate.
The addition of any moles of the acid and the conjugate base will not destroy the buffer, just would change the pH of the buffer. Thus, a and c will not destroy the buffer.
The addition of an acid (HCl) or a base (NaOH), produce the following reactions:
HCl + LiC₂H₃O₂ → HC₂H₃O₂ + LiCl
The acid reacts with the conjugate base to produce the weak acid.
And:
NaOH + HC₂H₃O₂ →NaC₂H₃O₂ + H₂O
The base reacts with the weak acid to produce conjugate base.
As the buffer is 1.0L, the moles of the species of the buffer are:
HC₂H₃O₂ = 0.300 moles
LiC₂H₃O₂ = 0.045 moles
The reaction of HCl with LiC₂H₃O₂ consume all LiC₂H₃O₂ -because there are an excess of moles of HCl that react with all LiC₂H₃O₂-
As you will have just HC₂H₃O₂ after the reaction, the addition of b destroy the buffer.
In the other way, 0.0500 moles of NaOH react with the HC₂H₃O₂ but not consuming all HC₂H₃O₂, thus d doesn't destroy the buffer.
What is a rate law?
A. An equation that relates the rate of a reaction to the equilibrium
position
B. An equation that relates the reaction rate to the concentrations of
the reactants
C. An equation that relates the rate constant to the temperature of a
reaction
D. An equation that relates the concentrations of reactants to the
rate constant
Answer:
B
Explanation:
The rate law is a way for us to measure the rate of a given reaction by comparing it to the concentration of the reactants. Based on the mole ratios of the reactants, we can hypothesize that adding more reactant will speed up the rate of reaction due to the simple principle that if there is more of an opportunity for molecules or atoms to collide, then the rate of reaction will be faster. Hope that helps :)
A rate law is an equation that relates the reaction rate to the concentrations of the component reactants.
Rate lawsIn chemistry, rate laws are mathematical expressions that relate the rate of a reaction to the concentrations of the component reactants in the reaction.
For example, consider the following reaction:
A + B -----------> C + D
The rate law for the reaction is given as:
Rate = k[tex][A]^m[B]^n[/tex] where k = rate constant and m/n = order of reactions.
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A (aq) + 2 B (aq) ⇌ 2 C (aq) For the reaction above and the ICE table below, what value should be placed in the Change for the concentration of A? Make sure you use the correct sign.
Answer:
-0.01 M
Explanation:
Let's consider the following reaction.
A(aq) + 2 B(aq) ⇌ 2 C(aq)
We will make an ICE chart.
A(aq) + 2 B(aq) ⇌ 2 C(aq)
I 0.10M 0.10M 0M
C -x -2x +2x
E 0.10-x 0.10-2x 2x
According to the chart, the concentration of C at equilibrium is:
2x = 0.02
x = 0.01
The value in the change row for A is:
-x = -0.01 M
A student is conducting their science experiment on the effect of caffeine on
dogs. He has 3 groups of test subjects. The 1st group of dogs receives plain
water. The 2nd group of dogs receives 10 mg of caffeine each, and the 3rd group
receives 50 mg of caffeine each. He will measure their activity levels by
recording how long each dog runs without stopping, after giving them the pills.
What is the dependent variable in this experiment?
A. The amount of dogs tested.
B. The dogs that receive water.
C. The amount of caffeine given.
D. The amount of activity.
Answer:
The amount of activity
Explanation:
Write the complete electron configuration for the titanium atom.
Answer:
Explanation:
First we should fill the 4s then only 3d.
A 28.4 g sample of an unknown metal is heated to 39.4 °C, then is placed in a calorimeter containing 50.0 g of water. Temperature of water increases from 21.00 °C to 23.00 °C. What is the specific heat of this metal in this problem?
Answer:
THE SPECIFIC HEAT OF THE METAL IS 0.8983 J/g °C
Explanation:
In solving the problem, we have to understand that:
Heat lost by the metal = Heat gained by the water in the bomb calorimeter
First is to calculate the heat evolved from the reaction
Heat = mass * specific heat * change in temperature
Mass of water = 50 g
specific heat of water = 4.184 J/g °C
Change in temperature = 23 - 21 = 2 °C
So therefore,
Heat = 50 * 4.184 * 2
Heat = 418.4 J
Next is to solve for the specific heat of the metal;
Heat lost by the metal is the same as the heat gained by water
Heat = mass * specific heat of metal * change in temperature
Change in temperature = 39.4 °C - 23 °C = 16.4 °C
418.4 = 28.4 * C * 16.4
C = 418.4 / 28.4 * 16.4
C = 418.4 / 465.76
C = 0.8983 J/ g °C
The specific heat of the metal is hence 0.8983 J/g °C
half-reaction for the reduction of liquid water to gaseous hydrogen in basic aqueous solution
Answer:
2H₂O (liq) + 2e⁻⇒ H₂ (g) + 2OH⁻ (aq)
Explanation:
In reduction-oxidation reaction two reactions take place, one is oxidation and the other is reduction reaction. In an oxidation reaction, there is the loss of an electron whereas in the reduction reaction there is gain of electron occus.
Reduction reaction occurs on the cathode, in a reduction of water there is gain of 2 electrons to gaseous hydrogen in basic aqueous solution. half-reaction for the reduction of liquid water to gaseous hydrogen in basic aqueous solution-
2H₂O (liq) + 2e⁻⇒ H₂ (g) + 2OH⁻ (aq)
How are sodium (Na) and potassium (K) similar?
O
A. They rarely react.
B. They are hard metals.
O O
C. They are highly reactive.
D. They are soft nonmetals.
Answer:
They are also relatively soft metals: sodium and potassium can be cut with a butter knife.
Answer:A
Explanation:
Once the chromatographic column has been prepared, why is it important to allow the level of the liquid in the column to drop the level of the alumina before applying the solution of the compound to be separated?
Answer: Chromatography is a technique which is used for the separation of components present in a mixture into sub-components.
Explanation:
The solvent or liquid used for the separation of the chromatographic mixture should lie below the spot point where the mixture is loaded in an alumina column. This is done to prevent the air bubbles formations, which can lead to poor sanitation. Also this is done to prevent the mixing of the mixture to be separated with the solvent instead of running with the solvent via capillary action.
What causes the electrons to flow through a wire in a lead-acid battery?
Answer:
The potential difference between the cathode and anode are set up from the chemical reaction. Inside the battery electrons are pushed by the chemical reaction toward the positive end creating a potential difference. It is this potential difference that drives the electrons through the wire.
Consider the three statements below. Which numbered response contains all the statements that are true and no false statements?
I. Hydration is a special case of solvation in which the solvent is water.
II. The oxygen end of water molecules is attracted toward Ca2+ ions.
III. The hydrogen end of water molecules is attracted toward Cl- ions.
a) I, II, and III
b) I and II
c) III
d) I
e) II
Answer:
a) I, II, and III
Explanation:
For the first statement;
Solvation, is the process of attraction and association of molecules of a solvent with molecules or ions of a solute. if the solvent is water, we call this process hydration.
This means the statement is TRUE.
For the second statement;
The negatively-charged side of the water molecules are attracted to positively-charged ions. In the case of water, the oxygen end is the negatively charged side of water. This means the statement is TRUE.
For the third statement;
The positively-charged side of the water molecules are attracted to the negatively-charged chloride ions. In the case of water, the hydrogen end is the positively charged side of water. This means the statement is TRUE.
Going through the options, we can tell that the correct option is option A.
. A compound X, containing C, H, and O was found to have a relative molar mass of 6o
whilst 20.0g of X contained 8.0g of C and 1.33g of H. Calculate the empirical formula
of compound X, and hence determine its molecule formula. show calculation
Answer:
empirical formula = CH2O
molecular formula = C2H4O2
What is science?
O A. Attempting to solve ethical problems through research
O B. Learning about the physical world through observation
O C. Determining a body of knowledge that never changes
O D. Using rules and patterns to predict what humans will do
SUBMIT
Answer:
The answer is B
Explanation:
Answer:
B. Learning about the physical world through observation
Explanation:
A p e x 2021 :) Trust me!
why homoannular diene in uv spectrometry have higher wavlenth than hetroannular diene?
Answer:
Homoanular dienes have a greater base value than heteroanular dienes
Explanation:
Woodward in 1945 gave a set of rules relating the wavelength of maximum absorption to the structure of a compound. These rules were modified by Fieser in 1959. These sets of rules describe the absorption of organic molecules in the UV region of the electromagnetic spectrum.
Each system of diene or triene has a given fixed value at which maximum absorption is expected to occur according to Woodward rules. This given fixed value is called the base or parent value. If the two double bonds are trans to each other, the diene is said to be transoid. If the two double bonds belong to different rings, the system is said to be heteroanular and the base value in each case is 215nm. If the double bonds are cis to each other (cisoid), or the two double bonds are in the same ring (homoanular), then the base value is 253nm.
Since λmax = base value + ∑ substituent contributions + ∑ other contributions, if the other contributions are not very significant, homoanular diene will have a greater λmax because of its larger base value compared to heteroanular diene. This correlates well with the fact that conjugated systems absorb at a longer wavelength.
What is the electron configuration for N (nitrogen)?
A. 1521p5
B. 1s22s23s 3p
O cly 1s22s22p3
O D. 1s 2s22p 3s
SUBMIT
Answer:
[tex]1s^22s^22p^3[/tex]
Explanation:
Nitrogen has the atomic number = 7
So, No. of electrons = 7
Electronic Configuration:
[tex]1s^22s^22p^3[/tex]
Remember that:
s sub shell holds upto 2 electrons while p sub shell upto 6
which contains more alcohol , a 12 oz. bottle of beer, a 4 oz glass of wine, or a 4 oz. of 100 proof liquor?
A. Beer
B. Wine
C. Hard liquor
D. All are approximately the same
the answer is hard liquor
How many liters of a 1 M NaOH stock solution would you need to make 785 mL of a 215 mM NaOH dilution? (m.w. = 40.00 g/mol) Do not include units in your answer; report your answer in the requested units.
Answer:
0.1688L of the 1M NaOH stock solution
Explanation:
A 215mM = 0.215M solution of NaOH contains 0.215 moles per liter. As you want to prepare 785mL = 0.785L of the 0.215M you will need:
0.785L × ( 0.215mol / L) = 0.1688 moles of NaOH.
These moles of NaOH comes from the 1M stock solution, that means the volume of 1M NaOH solution you need is:
0.1688 moles NaOH × (1L / 1mol) =
0.1688L of the 1M NaOH stock solutionThe volume of the stock solution of 1 M NaOH stock solution needed to make 785 mL of a 215 mM NaOH dilution is 0.169 L
From the question given above, the following data were obtained:
Molarity of stock (M₁) = 1 M
Volume of diluted solution (V₂) = 785 mL = 785 / 1000 = 0.785 L
Molarity of diluted solution (M₂) = 215 mM = 215 / 1000 = 0.215 M
Volume of stock solution needed (V₁) =?
The volume of the stock solution needed can be obtained as follow:
M₁V₁ = M₂V₂1 × V₁ = 0.215 × 0.785
V₁ = 0.169 LTherefore, the volume of the stock solution needed is 0.169 L
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A wave has a frequency of 23.0 Hz and a wavelength of 14.9 m. What is the velocity of the wave?
1.54 m/s
8.1 m/s
37.9 m/s
343 m/s
Answer:
343 m/s
Explanation:
Velocity Formula (Wave): v = fλ
v - velocity
f - frequency
λ - wavelength
We are given f = 23.0 and λ = 14.9. Simply plug it into the formula:
v = 23.0(14.9)
v = 342.7
v ≈ 343
Answer:
343 m/s
Explanation:
There is a formula to calculate the velocity of a wave given the frequency and wavelength.
Velocity = Frequency × Wavelength
v = f λ
v = 23 × 14.9
v = 342.7 ≈ 343
Which of the following substances would you predict to have the highest DHvap? Group of answer choices CH3CH2CH2CH3 CH3CH2OH HF CH3Cl HOCH2CH2OH
Answer:
a) [tex]CH_3CH_2CH_2CH_3[/tex]
Explanation:
In this question we have the following answer choices:
a) [tex]CH_3CH_2CH_2CH_3[/tex]
b) [tex]CH_3CH_2OH[/tex]
c) [tex]HF[/tex]
d) [tex]CH_3Cl[/tex]
e) [tex]HOCH_2CH_2OH[/tex]
We have to remember the relationship between intermolecular forces and vapor pressure. If we have stronger intermolecular forces we will have less vapor pressure because the molecules have more interactions between them, so, the molecules will prefer to stay in a liquid state rather than a gaseous state. Now, we have to check each molecule:
a) [tex]CH_3CH_2CH_2CH_3[/tex] (Van der waals interactions)
b) [tex]CH_3CH_2OH[/tex] (Hydrogen bonding)
c) [tex]HF[/tex] (Hydrogen bonding)
d) [tex]CH_3Cl[/tex] (Dipole-dipole interaction)
e) [tex]HOCH_2CH_2OH[/tex] (Hydrogen bonding)
For molecules b, c and e we have hydrogen bond to a heteroatom (O, N, S, or P). In this case oxygen, therefore we will have hydrogen bonding interactions (a very strong interaction). So, we can discard these ones.
In molecule e, we have "Cl" bond to a "C" therefore we will have the presence of a dipole (due to the electronegativity difference). If we have a dipole, we will have a dipole-dipole interaction (a strong interaction, less than hydrogen bonding but still is a strong interaction).
In molecule a, we have only Van der Waals interactions because in this molecule we have only carbon and hydrogen atoms bonded by single bonds. So, we will have a non-polar molecule. These interactions are the weakest interactions of all the molecules given. So, if we have weaker interactions the molecules can be converted to a gas state more easily and we have more vapor pressure.
Need help with chemistry question
Answer:
See explanation
Explanation:
In this case, we have to check two variables:
1) The leaving group
2) The carbon bonded to the leaving group.
Let's check one by one:
2-chloro-3-methylbutane
In this molecule, the leaving group is "Cl", the carbon bonded to the leaving group has two neighbors. Therefore, we have a secondary substrate.
1-phenylpropan-1-ol
In this molecule, the leaving group is "OH", the carbon bonded to the hydroxyl group has two neighbors also. So, we have a secondary substrate.
(E)-pent-3-en-2-yl 4-methylbenzenesulfonate
In this case, the leaving group is "OTs" (Tosylate), the carbon bonded to the tosylate group has as a neighbor a double bond. Therefore, we have an allylic substrate.
3a-bromooctahydro-1H-indene
In this molecule, the leaving group is "Br", the carbon bonded to the bromine has three neighbors. So, we have a tertiary substrate.
1-iodo-3-methylbutane
In this molecule, the leaving group is "I", the carbon bonded to the iodide has only one neighbor. So, we have a primary substrate.
See figure 1
I hope it helps!
Find the pH. What are the pH values for the following solutions? (a) 0.1 M HCl (b) 0.1 M NaOH (c) 0.05 M HCl (d) 0.05 M NaOH
Answer:
(a) [tex]pH=1[/tex]
(b) [tex]pH=1.3[/tex]
(c) [tex]pH=13[/tex]
(d) [tex]pH=12.7[/tex]
Explanation:
Hello,
In this case, we define the pH in terms of the concentration of hydronium ions as:
[tex]pH=-log([H^+])[/tex]
Which is directly computed for the strong hydrochloric acid (consider a complete dissociation which means the concentration of hydronium equals the concentration of acid) in (a) and (c) as shown below:
(a)
[tex][H^+]=[HCl]=0.1M[/tex]
[tex]pH=-log(0.1)=1[/tex]
(b)
[tex][H^+]=[HCl]=0.05M[/tex]
[tex]pH=-log(0.05)=1.3[/tex]
Nevertheless, for the strong sodium hydroxide, we don't directly compute the pH but the pOH since the concentration of base equals the concentration hydroxyl in the solution:
[tex][OH^-]=[NaOH][/tex]
[tex]pOH=-log([OH^-])[/tex]
[tex]pH=14-pOH[/tex]
Thus, we have:
(b)
[tex]pOH=-log(0.1)=1\\pH=14-1=13[/tex]
(d)
[tex]pOH=-log(0.05)=1.3\\pH=14-1.3=12.7[/tex]
Best regards.
how many moles of a solute is present in 4.00L of an 8.30M solution
Answer:
The number of moles of solute present in 4.00 L of an 8.30 M solution is 33.2
Explanation:
The Molarity (M) or Molar Concentration is the number of moles of solute per liter of solution; in other words it is the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:
[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]
Molarity is expressed in units ([tex]\frac{moles}{liter}[/tex]) or M.
In this case:
molarity= 8.30 Mnumber of moles of solute= ?volume= 4.00 LReplacing:
[tex]8.30 M=\frac{number of moles of solute}{4 L}[/tex]
Solving:
number of moles of solute= 8.30 M* 4 L= 8.30 [tex]\frac{moles}{liter}[/tex] * 4 L
number of moles of solute =33.2
The number of moles of solute present in 4.00 L of an 8.30 M solution is 33.2
Answer:
33.2 is the answer
Explanation:
did the test already :)