Functional languages like LISP are not composed of statements, but instead are a nested set of functions.
a) True
b) False

True
False

Answer:

The CPU performs basic arithmetic, logic, controlling, and input/output (I/O) operations specified by the instructions in the program. The computer industry used the term "central processing unit" as early as 1955.

Answer:

The Cpu is like the brain of the computer it's responsible for everything from running a program to solving a complex math equation.

Answer:

The answer to this question is given below in the explanation section.

Explanation:

Shelly recorded an audio composition for her presentation. She needs to follow the following proper orders to get composition done for her presentation.

Answer:

She connected her microphone to her computer.

She selected the record option in her DAW.

She added effects to her audio composition.

She saved the audio composition in an appropriate file format.

She saved her audio composition on an optical drive.

Answer:

What are the choices?

Explanation:

Answer:

line 2 it needs quotation marks :D

Explanation:

Let's address the few mistakes in your code so far. First, age is of type string and year is of type int. You're trying to subtract an int by a string and that doesn't work. Also, you have inconsistent quotes "Hello '. You should always use the same type of quote. The (year - age)) isn't properly formatted into the print statement. There is no plus adding it.

Here's my working code:

import datetime

name = input("What is your name? ")

age = int(input("How old are you? "))

year = datetime.datetime.now().year

print("Hello " + name + " you were born in " + str((year - age)))

I just fixed your code. Best of luck.

In python, date and time seem to be not its type of data, but the date and time named module can be imported for it to work with the time and date. So, the program and its description can be defined as follows:

Program Explanation:

Program:

import datetime#import package datetime

name = input("What is your name? ")#defining a variable name that uses an inputs method to input string value

age = int(input("How old are you? "))#defining a variable age that uses an inputs method with the int to input value

year = datetime.datetime.now().year#defining a variable year that takes current value in it

print("Hello " + name + " you were born in " + str((year - age)))#defining a print method that print name value with born year

Output:

Please find the attached file.

Learn more:

brainly.com/question/19032453  

Answer:

There should be a double space between each citation

The citation entries should be in alphabetical order.

The second and third lines of the last entry should be indented

Explanation:

The bibliography page contains some formatting errors which should be corrected before it is standard and acceptable.

First of all, in MLA (and most other styles), it is important to double space each citation to make them easily readable and eliminate errors.

Next, the citation entries needs to be in alphabetical order and not random which makes it easy to find a source.

Also, there needs to be indentation in the second and third lines of the last entry.

Answer:

B,C,E is the answer

Explanation:

I got it right on test...

sorry if its too late

Hope it helps someone else :D

Answer:

You need to order 11100 pizzas.

Explanation:

A couple of assumptions here.

Each pizza has 12 slices.  Each guest will eat 4 slices (1/3 of a pizza).

83 * 1/3 = 28 pizzas

28 = 11100

Answer:its a play

Explanation:

Answer:

A. It is a play

Explanation:

Got the answer correct on the quiz

Answer:

Internet Protocol (IP), which uses a set of rules to send and receive messages at the Internet address level; and. additional network protocols that include the Hypertext Transfer Protocol (HTTP) and File Transfer Protocol (FTP), each of which has defined sets of rules to exchange and display information.

Explanation:

could i plz have brainliest so close to next rank

HTML is a Language while HTTP is a Protocol.

HTML tags are used to help render web pages. The Hypertext Mark-up Language (or HTML) is the language used to create documents for the World Wide Web.

HTTP (Hypertext Transfer Protocol) is a protocol for transferring the hypertext pages from Web Server to Web Browser. HTTP is a generic and stateless protocol which can be used for other purposes as well using extensions of its request methods, error codes, and headers. Basically, HTTP is a TCP/IP based communication protocol, that is used to deliver data (HTML files, image files, query results, etc.) on the World Wide Web.

Answer:

C.

Explanation:

The answer is: A) True

n = int(input("How many numbers do you want to sum? "))

total = 0

for x in range(n):

   total += int(input("Enter a number: "))

print("Sum: "+str(total))

I hope this helps!

Following are the program to the given question:

Program Explanation:

Program:

Sum = 0#defining a variable sum that hold an integer value

t= int(input("Enter the total number you want to add: "))#defining a t variable that input value from user-end

for i in range(t):#defining a loop that add inputs values from above user-input range

   n= int(input("Enter value "+str(i+1)+": "))#defining loop that inputs n value

   Sum += n; #defining sum variable that adds user-input value

print("Sum of entered number: "+str(Sum))#using print method that print added value

Output:

Please find the attached file.

Learn more:

brainly.com/question/16025032

Answer:

Explanation:

The following code is written in Java. It asks the user for an input and saves it in a String variable. Then it loops through all the characters in the string and counts the spaces. Finally, it prints the total number of spaces in the String.

public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter Line Now:");

       String userInput = in.nextLine();

       int spaceCount = 0;

       for (int x = 0; x < userInput.length(); x++) {

           if (userInput.charAt(x) == ' ') {

               spaceCount++;

           }

       }

       System.out.println(spaceCount);

   }

Answer:

Input a series of integer numbers and split the string from the input to get a list. Then check and convert each string to integer with a list comprehension. Create a new variable with a value equal to the set of the list ( to get unique values) then check for the occurrence of each value in the original list.

Explanation:

This algorithm is used to check for the occurrence of values in a list that has been sorted in ascending order. This is faster if the items in the list is not converted to integer yet (still strings) before writing a for loop to check the value count in the list.

Answer:

public class Main

{

public static void main(String[] args) {

 minMax(1, 2, 3);

 minMax(100, 25, 33);

 minMax(11, 222, 37);

}

public static void minMax(int n1, int n2, int n3){

    int max, min;

    if(n1 >= n2 && n1 >= n3){

        max = n1;

    }

    else if(n2 >= n1 && n2 >= n3){

        max = n2;

    }

    else{

        max = n3;

    }

    if(n1 <= n2 && n1 <= n3){

        min = n1;

    }

    else if(n2 <= n1 && n2 <= n3){

        min = n2;

    }

    else{

        min = n3;

    }

    System.out.println("The max is " + max + "\nThe min is " + min);    

}

}

Explanation:

*The code is in Java.

Create a function named minMax() that takes three integers, n1, n2 and n3

Inside the function:

Declare the min and max

Check if n1 is greater than or equal to n2 and n3. If it is set it as max. If not, check if n2 is greater than or equal to n1 and n3. If it is set it as max. Otherwise, set n3 as max

Check if n1 is smaller than or equal to n2 and n3. If it is set it as min. If not, check if n2 is smaller than or equal to n1 and n3. If it is set it as min. Otherwise, set n3 as min

Print the max and min

Inside the main:

Call the minMax() with different combinations

Answer:

3

Explanation:

sorry if I'm wrong...it's been a while since I took a coding class.

Answer:

public class Main

{

public static void main(String[] args) {

 int[] numbers = new int[40];

 for (int i=0; i<40; i++){

     numbers[i] = i * 3;

 }

 for (int i=0; i<40; i++){

     System.out.println(numbers[i]);

 }

}

}

Explanation:

*The code is in Java.

Initialize an integer array with size 40

Create a for loop that iterates 40 times. Inside the loop, set the number at index i as i*3

i = 0, numbers[0] = 0 * 3 = 0

i = 1, numbers[1] = 1 * 3 = 3

i = 2, numbers[2] = 2 * 3 = 6

.

.

i = 39, numbers[39] = 39 * 3 = 117

Create another for loop that iterates 40 times and prints the values in the numbers array

Answer:

#include

#include

#include

#include

using namespace std;

struct courseInfo{

string name;

int unit;

char grade;

};

struct Student {

string fName;

string lName;

string idNumber;

courseInfo courses[2];

int unitCompleted;

double gpa;

};

Student s;

bool openFile(ifstream &in);

void Print_info_one(Student s);

void Read_info(Student &s);

float Find_points(char c) ;

bool openFile(ifstream &inFile){

string line;

int i=0,k=0;

string fName="", lname="", id="", name1="", name2="";

char grade1, grade2;

int unit1, unit2;

if (inFile.is_open())

{

while (getline(inFile, line))

{

while (line[i] != ',')

{

fName += line[i];

i++;

}

i++;

i++;

while (line[i] != ' ')

{

lname += line[i];

i++;

}

i++;i++;

while (line[i] != ' ')

{

id += line[i];

i++;

}

i++;

int count=0;

while (count <2)

{

name1 += line[i];

i++;

if(line[i] == ' ' ) count++;

}

i++;

grade1 = line[i];

i++;i++;

unit1 = line[i]-'0';

i++;i++;

count=0;

while (count <2)

{

name2 += line[i];

i++;

if(line[i] == ' ' ) count++;

}

i++;

grade2 = line[i];

i++;i++;

unit2 = line[i]-'0';

}

inFile.close();

s.fName = fName;

s.lName = lname;

s.idNumber = id;

s.courses[0].name = name1;

s.courses[0].grade = grade1;

s.courses[0].unit = unit1;

s.courses[1].name = name2;

s.courses[1].grade = grade2;

s.courses[1].unit = unit2;

s.unitCompleted = unit1 + unit2;

s.gpa = (unit1*Find_points(grade1) + unit2*Find_points(grade2))/(unit1+unit2);

}

else

{

cout << "Error reading file\n";

return false;

}

return true;

}

void Print_info_one(Student s){

cout << "Name: " << s.fName << ", " << s.lName << " ID Number: " << s.idNumber << " Course 1 Name: " << s.courses[0].name << " Grade: "

<< s.courses[0].grade << " Units: " << s.courses[0].unit << " Course 2 Name: " << s.courses[1].name << " Grade: "

<< s.courses[1].grade << " Units: " << s.courses[1].unit << " Unit completed: " << s.unitCompleted << " GPA:" << s.gpa << endl;

}

void Read_info(Student &s){

}

float Find_points(char grade){

switch (grade)

{

case 'A':

return 4.0;

break;

case 'B':

return 3.0;

break;

case 'C':

return 2.0;

break;

case 'D':

return 1.0;

break;

case 'F':

return 0;

break;

default:

break;

}

return 0;

}

int main() {

ifstream inFile;

std::fstream fs;

fs.open ("input.txt", std::fstream::in );

Print_info_one(s);

return 0;

Explanation:

In python 3.8, we can use a simple print statement.

print(('h0 '*3 +'Merry Christmas\n')*2)

Answer:

Explanation:

public class RecursiveCalls {

public static void backwardsAlphabet(char currLetter) {

if (currLetter == 'a') {

System.out.println(currLetter);

}

else {

System.out.print(currLetter + " ");

backwardsAlphabet(--currLetter);

}

return;

}

public static void main (String [] args) {

char startingLetter = '-';

startingLetter = 'z';

// Your solution goes here

backwardsAlphabet(startingLetter);

return;

}

}

Answer:

I'd that IT can help in a great many different fields like

Mathematics, in a manner of solving complex math equations

Statistics, in a manner of creating complex graphs with millions of points

Modeling, in a manner of creating models from scratch, either for cars, personal projects or characters for video games and entertainment

Advertising, in a manner of using IT to create not only the advertisements themselves but also, spreading that advertisement to millions in a single click

Music/Audio, in a manner of creating new sounds and music that wouldn't be able to work in any practical manner

Explanation:

Answer:

Following are the code to the given question:

int power(int x, int n)//defining a method power that accepts two integer parameters

{

if (n == 0)//defining if block to check n equal to 0

{

return 1; //return value 1

}

else//defining else block

{

x = x * power(x, --n); //use x variable to call method recursively

}

return x; //return x value

}

Explanation:

In the above-given code, a method power is defined that accepts two integer variable in its parameter, in the method a conditional statement is used which can be defined as follows:

Answer:

Convert 1.5GB to KBs = 1500000kb

1500000kb/950kb ≈ 1579

Explanation:

A flash disk is a storage device. It has enough memory to store large files. In the given question, the flash disk has a memory of 1.5GB and can store 1578.94 music files of 950KBs each.

A flash disk is a data storage device that uses flash memory specifically : a small rectangular device which is designed to be plugged directly into a USB port on a computer. It is often used for transferring files from one computer to another computer system.

Flash disks have no mechanical platters or access arms. It is termed "disk" because of the data which are accessed as if they were on a hard drive. The disk storage structure is emulated.

In the given question, the flash disk contains 1.5GB memory and has to store music files of 950KBs each. For determining the number of music files which can be stored in the flash disks, we have to first convert the unit of flash disk from GB to KB:

1GB = 1,000,000 KB

1.5 GB = 1,500,000 KB

size of music file = 950 KB

Number of music files that can be stored = storage in the flash disk ÷ size of the music file

Number of music files = 1500000KB ÷ 950KB

Number of music files = 1578.94

Learn more about Flash disk here:

https://brainly.com/question/1130880

#SPJ2

Answer:

true

Explanation:

sent = input("")

count = 0

new_sent = ""

for i in sent:

   if count == 0:

       new_sent += i

       count += 1

   else:

       if i.isupper():

           new_sent += " "+i.lower()

       else:

           new_sent += i

print(new_sent)

The above code works if the user enters the sentence.

def func(sentence):

   count = 0

   new_sent = ""

   for i in sentence:

       if count == 0:

           new_sent += i

           count += 1

       else:

           if i.isupper():

               new_sent += " " + i.lower()

           else:

               new_sent += i

   return new_sent

print(func("StopAndSmellTheRoses."))

The above code works if the sentence is entered via a function.

Answer:

if(condition){

}

else  {

  // something we want to print

  if(condition) {

     // ...

  }

  else {

     // ...

  }

}

Explanation:

Create code blocks using curly braces { ... }.

Use proper indentation to visibly make it clear where code blocks start and end.

Answer your answer is Macro

Explanation:

Macro shares language both the computer and the programmer can undestand.

Answer:

thanks for the free points

Answer:

C#

if(user_grade >=9 && user_grade <=12)

{

   Console.WriteLine("In Highschool");

}

Python

if user_grade >= 9 & user_grade <= 12:

  print("In Highschool")

Java

if(user_grade >=9 && user_grade <=12)

{

   System.println("In Highschool");

}

Explanation:

Answer:

The output of the program is (d)

Tango Hernados Hideaway

Swing Hound Dog

Explanation:

Analyzing the given code segment

In class Dance,

A method named dance was defined with an instance of two string variables/values

which are name and song

public Dance(String name, String s)

In the main of the program,

The first line creates an instance of Dance as dance1

dance1 is initialized with the following string values: "Tango","Hernandos Hideaway"

- The first string value "Tango" will be passed into the name variable of the Dance method

- The second string value "Hernandos Hideaway" will be passed into the song variable of the Dance method

Next, another instance of Dance is initialized as dance2

dance2 is initialized with the following string values: "Swing","Hound Dog"

- The first string value "Swing" will be passed into the name variable of the Dance method

- The second string value "Hound Dog" will be passed into the song variable of the Dance method

On line 3 of the main: System.out.println(dance1.toString());

The values of dance1, which are "Tango","Hernandos Hideaway" are printed

On line 4 of the main: System.out.println(dance2.toString());

The values of dance1, which are "Swing","Hound Dog" are printed

Hence, option d answers the question