Four swimmers, Daniela, Camille, Brennan, and Amy, compete on a relay team. For the first race of the year, Daniela begins the relay. The other three swimmers can swim in any order. The sample space, S, for the event is shown below. S = {CBA, CAB, BAC, BCA, ACB, ABC} After the first race, it is determined that Camille is a strong finisher and should be the final swimmer in the race.

Answers

Answer 1

Answer:

A = {CBA, CAB, BCA, ACB}

Step-by-step explanation:

Answer 2

Answer: A. {CBA, CAB, BCA, ACB}

Step-by-step explanation: Id appreciate it if anyone else could explain why that is the answer. (?)


Related Questions

Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.78.

Requried:
a. Compute a 95% CI for the true average porosity of a certain seam if the average porosity for 20 specimens from the seam was 4.85.
b. Compute a 98% CI for true average porosity of another seam based on 16 specimens with a sample average of 4.56.
c. How large a sample size is necessary if the width of the 95% interval is to be 0.40?
d. What sample size is necessary to estimate the true average porosity to within 0.2 with 99% confidence?

Answers

Answer:

a) The 95% CI for the true average porosity is (4.51, 5.19).

b) The 98% CI for true average porosity is (4.11, 5.01)

c) A sample size of 15 is needed.

d) A sample size of 101 is needed.

Step-by-step explanation:

a. Compute a 95% CI for the true average porosity of a certain seam if the average porosity for 20 specimens from the seam was 4.85.

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.95}{2} = 0.025[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.025 = 0.975[/tex], so [tex]z = 1.96[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.96*\frac{0.78}{\sqrt{20}} = 0.34[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 4.85 - 0.34 = 4.51

The upper end of the interval is the sample mean added to M. So it is 4.35 + 0.34 = 5.19

The 95% CI for the true average porosity is (4.51, 5.19).

b. Compute a 98% CI for true average porosity of another seam based on 16 specimens with a sample average of 4.56.

Following the same logic as a.

98% C.I., so [tex]z = 2.327[/tex]

[tex]M = 2.327*\frac{0.78}{\sqrt{16}} = 0.45[/tex]

4.56 - 0.45 = 4.11

4.56 + 0.45 = 5.01

The 98% CI for true average porosity is (4.11, 5.01)

c. How large a sample size is necessary if the width of the 95% interval is to be 0.40?

A sample size of n is needed.

n is found when M = 0.4.

95% C.I., so Z = 1.96.

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.4 = 1.96*\frac{0.78}{\sqrt{n}}[/tex]

[tex]0.4\sqrt{n} = 1.96*0.78[/tex]

[tex]\sqrt{n} = \frac{1.96*0.78}{0.4}[/tex]

[tex](\sqrt{n})^{2} = (\frac{1.96*0.78}{0.4})^{2}[/tex]

[tex]n = 14.6[/tex]

Rounding up

A sample size of 15 is needed.

d. What sample size is necessary to estimate the true average porosity to within 0.2 with 99% confidence?

99% C.I., so z = 2.575

n when M = 0.2.

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.2 = 2.575*\frac{0.78}{\sqrt{n}}[/tex]

[tex]0.2\sqrt{n} = 2.575*0.78[/tex]

[tex]\sqrt{n} = \frac{2.575*0.78}{0.2}[/tex]

[tex](\sqrt{n})^{2} = (\frac{2.575*0.78}{0.2})^{2}[/tex]

[tex]n = 100.85[/tex]

Rounding up

A sample size of 101 is needed.

A camera shop stocks eight different types of batteries, one of which is type A76. Assume there are at least 30 batteries of each type.

Required:
a. How many ways can a total inventory of 30 batteries be distributed among the eight different types.
b. How many ways can a total inventory of 30 batteries be distributed among the eight different types if the inventory must include at least four A76 batteries?
c. How many ways can a total inventory of 30 batteries be distributed among the eight different types if the inventory includes at most three A7b batteries?

Answers

Answer:

a. 10295472 ways

b. 4272048 ways

c. 6023424 ways

Step-by-step explanation:

Given that:

Camera shop stocks ----- 8 different types of batteries

one of which is ---- A76

Assume that there are ------ at least 30 batteries of each type.

a.

How many ways can a total inventory of 30 batteries be distributed among the eight different types.

The number of ways a total inventory of 30 batteries be distributed is :

[tex]= \left \{ {{30+8-1} \atop {30}} \right. \}[/tex]

[tex]= \left \{ {{37} \atop {30}} \right. \}[/tex]

[tex]=\dfrac{37!}{30! *7!}[/tex]

[tex]= \dfrac{37*36*35*34*33*32*31*30!}{30!*7*6*5*4*3*2*1}[/tex]

[tex]= \dfrac{37*36*35*34*33*32*31}{7*6*5*4*3*2*1}[/tex]

= 10295472 ways

b.

How many ways can a total inventory of 30 batteries be distributed among the eight different types if the inventory must include at least four A76 batteries?

If we must include 4  A76 batteries; then the number of ways a total inventory of 30 batteries can be distributed among eight different types of batteries will be:

30 - 4 = 26 batteries

Now;

[tex]= \left \{ {{26+8-1} \atop {26}} \right. \}[/tex]

[tex]= \left \{ {{33} \atop {26}} \right. \}[/tex]

[tex]=\dfrac{33!}{26! \ \ 7!}[/tex]

[tex]=\dfrac{33*32*31*30*29*28*27*26!}{26! \ * \ 7*6*5*4*3*2*1}[/tex]

[tex]=\dfrac{33*32*31*30*29*28*27}{ \ 7*6*5*4*3*2*1}[/tex]

= 4272048 ways

c. If we must include at most three A7b batteries. the number of ways that a total inventory of 30 batteries can be distributed among eight different types of inventory is:

[tex]= \sum \limits ^3 _{x=0} \left \{ {{(30-x)+7-1} \atop {30-x}} \right. \} \\ \\ \\ = \sum \limits ^3 _{x=0} \left \{ {{(30-0)+7-1} \atop {30-0}} \right. \} = (^{36}_{30})+(^{35}_{29})+ (^{34}_{28})+ (^{33}_{27})[/tex]

[tex]= \dfrac{36!}{30! * 6!} + \dfrac{35!}{29! * 6!} + \dfrac{34!}{28! * 6!} + \dfrac{33!}{27! * 6!}[/tex]

= 1947792 + 1623160 + 1344904 + 1107568

= 6023424 ways

What are the characteristics of a socialist economy? What are the pros and cons of this type of economy?

Answers

Answer:

The pro is Political Control, the cons, however, are many.

Step-by-step explanation:

However, A Socialist Economy cons outweigh its pros. The only thing that is a PRO is you dictating it, preventing people from success. Wanna know the cons? The Cons are more Regulations, to which chokes more businesses of their money, they function, & motive. To which it has a chain reaction of: The Businesses not employing people, more people are out of work, which means more people ain't buying stuff to support the businesses, which means the businesses are out of business, they shut down.

The Economy ain't something that you can stop, or go, & it ain't statistics. An Economy is just.. people, that's it. It's just people, they are the ones that work, run businesses & factories, they are the ones that buy N' sell. They create, craft, invent, innovate, etc.

Here's a quote that I have: "The more you choke it from breathing in, the less it breathes out". That's my stance on regulation & Socialism, to which Socialism is just Voluntary Communism, & A Permanent Ideological belief that Big government Involvement is the way to go.

To which, it's not!

For what value of the variable: 1. are the values of the expressions 2m−13 and m+3 equal? 2. is the value of 2x+1 twenty greater than 8x+5? 3. is the value of 9−y twice as much as the value of y?

Answers

Answer:

1.-   m = 13

2.-   [tex]x<-\frac{2}{3}[/tex]

3.-   y = 3

Step-by-step explanation:

In all cases we need to start with an equation or an inequality and slove for the variable:

Case 1.   : 2 m - 13 = m + 3

[tex]2m-13=m+3\\2m-m=3+13\\m=16[/tex]

Case 2.   : 2 x + 1 > 8 x + 5 + 20

[tex]2x+1>8x+25\\1-25>8x-2x\\-24>6x\\-4 >x\\x<-4[/tex]

Case 3.  :  9 - y = 2  y

[tex]9-y=2y\\9=2y+y\\9=3y\\y=3[/tex]

Which parent function is f(x) = x^2?
O A. An exponential parent function
OB. The linear parent function
C. The absolute value parent function
D. The quadratic parent function

Answers

Answer:

D. Quadratic parent function.

Step-by-step explanation:

Which statement best describes the function below?
f(x)=x2-x2-9x+9

Answers

Answer:

B. It is a many-to-one function.

Step-by-step explanation:

To find what the function below is, you can use the Function Grapher and Calculator from Math is Fun to graph the function.

As you can see, the graph passes the vertical line test, since each x-value has exactly one y-value.

According to the diagram below, the function will be a many-to-one function, since there are y-values that have three different x-values.

So, your answer will be B. it is a many-to-one function.

Hope this helps!

You buy a 33-pound bag of flour for $9 or you can buy a 1- pound bag for $0.39. Compare the per pound cost for the large and small bag. How much is the pounds per dollar

Answers

Answer:

see below

Step-by-step explanation:

9 dollars / 33 lbs = .272727 dollars per lb

.39 / 1 lbs = .39 per lb

The large bag is less expensive

Step-by-step explanation:

33lb bag = $9.00

1lb = $0.39

$9.00 bag per pound is $.0.27 per pound

If I bought 33, 1 pound bags it would cost $12.87

cheaper by $ 3.87 to buy the 9lb bag.

Write an equation in point-slope form for each line.
(If possible please show work)

Answers

Answer:

y= -2x+3

Step-by-step explanation:

Point slope form= y=mx+b

The m is the slope.

So, we have an incomplete equation right now: y= -2x+b

We want to find b. We can do that by plugging in values for the x and y coordinates. Fortunately, we do have a set of coordinates, (1, 1)!

We plug them in:

1= -2(1)+b

1= -2+b

b=3

So, since we have the slope and the b, also called the y-intercept, we can form an equation!

y= -2x+3


Find value of z and simplify completely.

Answers

Answer:

310

Given:

A right triangle in which an altitude is drawn from the right angle vertex

To find: value of X

We have leg rule in similarity in right triangle as:

[tex] \frac{leg}{part} = \frac{hypotenuse}{leg} \\ [/tex]

Plugging the given values,

[tex] \frac{z}{3} = \frac{3 + 27}{z} \\ z \times z = 3(3 + 27) \: \: (cross \: multiplication) \\ {z}^{2} = 9 + 81 \\ {z}^{2} = 90 \\ z = \sqrt{90} \\ z = 3 \sqrt{10} [/tex]

Hope this helps...

Good luck on your assignment..

For the data set represented by this box plot, what is the value of the maximum? maximum:

Answers

Answer:

140

Step-by-step explanation:

The maximum is the furthest the line that goes out the furthest, the minimum would be about 83-84

Answer:

the other person is correct!

Step-by-step explanation:

9/3 *[(18-10)-2^2]


36

12

0.25

0.75

Answers

Answer:

12

Step-by-step explanation:

Use the PEMDAS

there is a parenthesis and exponents

9/3{(8) - 4)}

Multiply and divide 9/3= 3

Also subtract 8-4 = 4

3{8-4}

3(4)= 12

Factor by grouping 5x^3+6x^2+25x+30

Answers

Answer:

(5x + 6) (x² + 5)

Step-by-step explanation:

5x³ + 6x² + 25x + 30

= x² (5x + 6) + 25x + 30    -- Group 5x³ and 6x²

= x² (5x + 6) + 5 (5x + 6)    -- Group 25x and 30

= (5x + 6) (x² + 5)  -- Both terms have a common factor of 5x + 6

A horizontal force of 480 n is applied to a stationary wooden box in one direction and a 600 n horizontal force is applied in the opposite direction. What is the additional force is needed for the box to remain stationary

Answers

Answer:

Step-by-step explanation:

In a static position, the sum of the forces is always 0.

so:

F1 = 480 N

F2 = -600 N

F3 = ?

F1 + F2 + F3 = 0

480 - 600 + F3 = 0

F3 = 120 N (the answer is positive, so the force acts in the same direction as F1)

Write the equation of each line in slope-intercept form.
(If possible please show work)

Answers

Answer:

[tex]\displaystyle y = -\frac{2}{3}\, x - 9[/tex].

Step-by-step explanation:

The slope-intercept form of a line on a cartesian plane should be in the form:

[tex]y = m\, x + b[/tex],

where:

[tex]m[/tex] is the slope of the line, while [tex]b[/tex] is the [tex]y[/tex]-coordinate of the point where the line intersects the [tex]y[/tex]-axis.

The question states that the slope of this line is [tex]\displaystyle -\frac{2}{3}[/tex]. In other words, [tex]\displaystyle m = -\frac{2}{3}[/tex]. The next step is to find the value of [tex]b[/tex]. That could be done using the information that the point [tex](-6,\, -5)[/tex] is on this line.

Note that the slope-intercept form of a line [tex]y = m\, x + b[/tex] is essentially an equation about [tex]x[/tex] and [tex]y[/tex]. For a point [tex](x_0,\, y_0)[/tex] to be on that line, [tex]x = x_0[/tex] and [tex]y = y_0[/tex] should satisfy its equation. In other words, it must be true that [tex]y_0 = m\, x_0 + b[/tex].

For the point [tex](-6,\, -5)[/tex], [tex]x_0 = -6[/tex] and [tex]y_0 = -5[/tex]. The equation would be:

[tex]\underbrace{-5}_{y_0} = m \times \underbrace{(-6)}_{x_0}+ b[/tex].

Besides, the slope of this line is already known to be [tex]\displaystyle m = -\frac{2}{3}[/tex]. Therefore, this equation would become:

[tex]\displaystyle \underbrace{-5}_{y_0} = \underbrace{\left(-\frac{2}{3}\right)}_{m} \times \underbrace{(-6)}_{x_0}+ b[/tex].

Solve this equation for [tex]b[/tex]:

[tex]b = -9[/tex].

Hence, the slope-intercept form ([tex]y = m\, x + b[/tex]) of this line would be:

[tex]\displaystyle y = -\frac{2}{3}\, x - 9[/tex].

I have k quarters, five less quarters than nickels and one more than twice as many dimes as quarters. Find the value of the coins in cents in terms of k.

Answers

Answer:

(35k + 20) cents

Step-by-step explanation:

First of all, let us have the value of each unit:

1 quarter = 25 cents

1 nickel = 5 cents

1 dime = 10 cents

Given that number of quarter = k

Quarters are 5 lesser than Nickels, so number of nickels = k+5

One more than twice as many dimes as quarters:

k = 2 [tex]\times[/tex] Number of Dimes + 1

So, number of dimes = [tex]\frac{1}{2}(k-1)[/tex]

Value of quarters = [tex]25 \times k[/tex] cents

Value of nickels = [tex]5 \times (k+5) = (5k+25)\ cents[/tex]

Value of dimes = [tex]\frac{1}{2}(k-1) \times 10 = (5k-5)\ cents[/tex]

So, total value of coins =

[tex]25k + 5k +25 +5k-5\\\Rightarrow (35k+20)\ cents[/tex]

Describe fully the single transformation that’s maps triangle A onto triangle B.

Answers

Answer:

reflection of the axis y=4

Step-by-step explanation:

becuase it is reflected on itself

Answer:

Reflect Triangle A by the line y = 4

Step-by-step explanation:

The answer is reflect Triangle A by y = 4 because the two triangles are symmetric.

A professor gives a statistics exam. The exam has 100 possible points. The scores for the students in the second classroom are as follows:
88 88 92 88 88 72 96 88 84
Calculate the sample size, n, and the sample mean, M n = M =
While grading the exam, the professor realizes that one of the questions covered material that was not yet covered in the lectures. This question was worth 20 points, so he decides to add 20 points to everyone's score.
Calculate the new n and M.

Answers

Answer:

N = 9

M = 87.11

Step-by-step explanation:

According to the situation, the data provided and the solution are as follows

The scores for the student in the classroom is

= 88 88 92 88 88 72 96 88 84

The different student's number of scores is 9

The solution of new n and M is shown below:-

Sample size (n) = 9

Sample mean (m) is

[tex]= \frac{Sum\ of\ all\ data\ values}{Sample\ size}[/tex]

= [tex]\frac{88 + 88 + 92 + 88 + 88 + 72 + 96 + 88 + 84}{9}[/tex]

[tex]= \frac{784}{9}[/tex]

= 87.11

A pet store has 32 more dogs than cats. If there are a total of 144 dogs and cats altogether, then how many cats does the pet store have?

PLZ ANSWER ASAP THANKS

Answers

Answer:

56 cats

88 dogs

Step-by-step explanation:

x=cats

x+32=dogs

x+x+32=144

2x=144-32

2x=112

x=112/2

x=56 (56 cats)

x+32=88 (88 dogs)

Answer:

56

Step-by-step explanation:

In order to solve this question you need to subtract 32 by 144 then divide that answer by 2.

So we know that they're 32 more dogs then cats and there is 144 dogs and cats all together.

[tex]144 - 32 = 112[/tex]

Divide it in half

[tex]112 \div2=56[/tex]

[tex]56+32 = 88[/tex]

[tex]= 56[/tex]

Therefore they're 56 cats in the pet store.

Hope this helps.

is lmn congruent to opq if so name the postulate

Answers

Answer:

Option (A)

Step-by-step explanation:

Given:

LM ≅ OP

MN ≅ PQ

∠M ≅ ∠P

To Prove:

ΔLMN ≅ ΔOQP

                   Statements                      Reasons

1). LM ≅ OP                                   1). Given

2). MN ≅ PQ                                 2). Given

3). ∠P ≅  ∠M                                3). Given

4). ΔLNM ≅ ΔOQP                      4). By the SAS postulate of congruence.

                                                         [Side - Angle - Side]                          

Therefore, Option (A) will be the answer.

Simplify The square root of 5 (6-4 the square root of 3)

Answers

Answer:

7.75

Step-by-step explanation:

6-4=2

2 times the square root of 3=3.46410161514

square root of 5 times 3.46410161514=7.74596669242

to 2dp=7.75

Simplify e^ln4
A. 1/4
B. 4
C. 1n4
D. E^4

Answers

Answer:

The answer is option B.

4

Step-by-step explanation:

Using the expression

[tex] {e}^{ ln(x) } = x[/tex]

[tex] {e}^{ ln(4) } = 4[/tex]

Hope this helps you

Reflected across the x-axis ? How is look in the figure

Answers

Answer:

Well a shape reflecting across the x axis will look like some thing in the image below.

Look at both images.

If the area to the left of x in a normal distribution is 0.187, what is the area to the right of x? (Enter an exact number as an integer, fraction, or decimal.)

Answers

Answer:

Area to the right is 0.813

Step-by-step explanation:

Since the area under the full normal distribution should render "1" (one), then the area to the right of x  should be:

1 - area to the left of x = 1 - 0.187 = 0.813

The area to the right of x in this normal distribution will be 0.813.

What is a normal distribution?

The majority of the observations are centered around the middle peak of the normal distribution, which is a continuous probability distribution that is symmetrical around its mean.

The probabilities for values that are farther from the mean taper off equally in both directions. Extreme values in the distribution's two tails are likewise rare.

Not all symmetrical distributions are normal, even though the normal distribution is symmetrical. 

We know that the total area described in a normal distribution is 1.

Given, that the area to the left of x in a normal distribution is 0.187.

So, the area to the right of x will be,

1 - 0.187.

= 0.813.

learn more about normal distribution here :

https://brainly.com/question/15103234

#SPJ2

PLEASE HELPP! f(x)= -3x + 3
Which of the graphs represent the inverse of the function F??

Answers

Answer:

Answer is Y

Step-by-step explanation:

A 7 cm x 5 cm rectangle sits inside a circle with radius of 6 cm. What is the area of the shaded region? Round your final answer to the nearest hundredth. Please answer fast! ​

Answers

Answer:78.14cm^2

Step-by-step explanation:

There are members on the board of directors for a certain​ non-profit institution. a. If they must elect a​ chairperson, first vice​ chairperson, second vice​ chairperson, and​ secretary, how many different slates of candidates are​ possible? b. If they must form an ethics subcommittee of four​ members, how many different subcommittees are​ possible?

Answers

Answer: a. 1320

b.495

Step-by-step explanation:

Complete question is provided in the attachment.

Total members on the board = 12

a. Persons to chose : chairperson, first vice​ chairperson, second vice​ chairperson, and​ secretary

i.e. Total 3 posts in an order.

Number of ways to choose 3 persons from 12 in an order = [tex]^{12}P_3[/tex]  [By permutation]

[tex]=\dfrac{12!}{(12-3)!}\\\\=\dfrac{12!}{7!}\\\\=12\times11\times10\\\\=1320[/tex]

hence, 1320 different slates of candidates are​ possible .

b. number of ways to choose 4 members out of 12 ( order not matters)=[tex]^{12}C_{4}[/tex] [By combinations]

[tex]=\dfrac{12!}{4!8!}\\\\=\dfrac{12\times11\times10\times9}{24}\\\\=495[/tex]

Hence, the number of different subcommittees are​ possible =495

How much time will it take Jenny to bike 15 miles if she bikes at a speed of 6 mph?

Answers

Answer:

this lesson, we will investigate the relationship between the distance traveled, the rate or speed or travel, and the time that it takes to travel that distance at that rate.  We will also look at a few other related products.

Distance  =  (Rate)(Time)

The equation that relates distance, rate, and time is

        d  =  rt

Where d is the distance traveled, r is the rate, and t is the time.  On the CAHSEE exam, you will be given two of these and will be asked to use the above equation to find

took Markus half an hour to drive home from work.  He averaged 34 miles per hour.  How far does Markus live from his work?SolutionWe are given that it takes 1/2 an hour for the trip.  This is a time:        t  =  1/2We are given that he averages 34 miles per hour.  This is a rate:        r  =  34We are asked how few he has traveled.  This is a distance.  We use the d=rt equation:        d  =  rt             =  (34)(1/2)            =  17

Answer:

2.5 hours

Step-by-step explanation:

First, try rewriting Jenny's speed in it's fraction form: 6 mi/hr

Next, use the units to set up an equation that relates Jenny's speed to the distance they want to travel. Let's call the unknown time t:

6mi/hr=15mi/t

1/t=6/15 (mi/hr•1/mi)

t=15/6 (hrs/mi•mi)= 15/6 (hrs•mi/mi)= 15/6 hrs

t=2.5hrs

So it'd take Jenny 2.5hrs at 6mph to go 15 miles. The key here is to keep track of the units. You can treat them like fractions and reduce them away as if they were numbers or variables.

What is the measure of angle ABC? Please answer quickly!

Answers

Answer:

ABC = 88

Step-by-step explanation:

Angle Formed by Two Chords  = 1/2( sum of Intercepted Arcs)

ABD = 1/2 ( 131+ 53)

ABD = 1/2 (184)

       =92

ABC = 180 -ABD

ABC = 88

Each of 100 students in the Allen School can only take 1 CSE class each, between the four classes CSE 311, CSE 312, CSE 331, and CSE 332. Each student (independently of others) takes CSE 311 with probability 0.3, CSE 312 with probability 0.4, CSE 331 with probability 0.1, and CSE 332 with probability 0.2. What is the probability that exactly 31 sign up for CSE 311, 39 sign up for CSE 312, 7 sign up for CSE 331, and 23 sign up for CSE 332

Answers

Answer:

[tex]P(a=31,b=39,c=7,d=23) = 0.000668[/tex]

Step-by-step explanation:

Sample space, n = 100

Let the number of students signed up for CSE 311 = a

Let the number of students signed up for CSE 312 = b

Let the number of students signed up for CSE 331 = c

Let the number of students signed up for CSE 332 = d

Probability of taking CSE 311, [tex]P_a[/tex] = 0.3

Probability of taking CSE 312, [tex]P_b[/tex] = 0.4

Probability of taking CSE 331, [tex]P_c[/tex] = 0.1

Probability of taking CSE 332, [tex]P_d[/tex] = 0.2

[tex]P(a,b,c,d) = \frac{n!}{a! b! c! d!} p_a^{a} p_b^{b} p_c^{c} p_d^{d} \\P(a=31,b=39,c=7,d=23) = \frac{100!}{31! 39! 7! 23!} * 0.3^{31} * 0.4^{39} * 0.1^{7} 0.2^{23}\\P(a=31,b=39,c=7,d=23) = \frac{4.58*10^{111}}{2.13*10^{56}* 5040 }* (1.57*10^{-55})\\P(a=31,b=39,c=7,d=23) = 0.000668[/tex]

Tom takes a cancer test and the test is advertised as being 99% accurate: if you have cancer you will test positive 99% of the time, and if you don't have cancer, you will test negative 99% of the time. If 1% of all people have cancer and Tom tests positive, what is the prob that Tom has the disease

Answers

Answer:

99% chance tommy has it

Step-by-step explanation:

cuz do da math

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