The order of the periods of oscillation from largest to smallest is:
T1 > T3 > T2 > T4
How to find the smallest?The period of oscillation for a mass-spring system is given by the formula:
T = 2π √(m/k)
Where T is the period, m is the mass of the oscillating object and k is the spring constant.
Using this formula, we can find the periods of oscillation for the four mass-spring systems:
m = 2 kg, k = 2 N/m: T = 2π √(2 kg / 2 N/m) = 2π √(1) = 2π secondsm = 2 kg, k = 4 N/m: T = 2π √(2 kg / 4 N/m) = 2π √(0.5) = π secondsm = 4 kg, k = 2 N/m: T = 2π √(4 kg / 2 N/m) = 2π √(2) = 2π √(2) = 2π √(2) secondsm = 1 kg, k = 4 N/m: T = 2π √(1 kg / 4 N/m) = 2π √(0.25) = π/ √(2) secondsSo the order of the periods of oscillation from largest to smallest is:
T1 > T3 > T2 > T4
Where T1 is the period of the mass-spring system with m = 2 kg and k = 2 N/m, T3 is the period of the mass-spring system with m = 4 kg and k = 2 N/m, T2 is the period of the mass-spring system with m = 2 kg and k = 4 N/m, and T4 is the period of the mass-spring system with m = 1 kg and k = 4 N/m.
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a basketball player grabbing a rebound jumps vertically upward. if the player leaves the ground with a speed of 3.53 m/s, how long, in seconds, will the player remain in air?
In order to calculate time, we need to know one more variable, the gravitational acceleration of earth which is 9.8 m/s^2 and the force exerted on the player's legs, which can be calculated by F=ma.
In order to determine how long the player will remain in the air, we would need to know the player's upward acceleration (which can be affected by factors such as the player's mass and the force exerted on the player's legs as they jump) as well as the player's initial upward velocity. Without this information, it is not possible to calculate how long the player will remain in the air.
In physics, an object's vertical motion can be described by the equation:
y = vi*t + (1/2)at^2
where y is the vertical displacement (or height) of the object, vi is the initial upward velocity, t is the time in the air, and a is the upward acceleration.
If we know the initial upward velocity (vi) and the acceleration (a), we can use this equation to solve for the time in the air (t). The acceleration of the object is determined by various factors such as the force applied on the object and the mass of the object.
In this case, we know the initial upward velocity of the basketball player is 3.53 m/s, but we don't have the acceleration value, which means we cannot solve for time. In order to calculate time, we need to know one more variable, the gravitational acceleration of earth which is 9.8 m/s^2 and the force exerted on the player's legs, which can be calculated by F=ma.
Therefore, without additional information, it is not possible to calculate the time the player will remain in the air.
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an object is thrown straight up with an initial velocity of 20.0 m/s, and there is an air resistance force which would cause an acceleration of 3.00 m/s2 opposite the direction of motion. with what speed does the object return to the ground?
As the object is thrown up with the initial velocity of 20.0 m/s, and there is an air resistance force that would cause an acceleration of 3.00 m/s2, the speed of the object as a return to the ground is 10.8 m/s.
Kinematic equations
The kinematic equations are a set of equations that describe the motion of an object with constant acceleration.
When we have an initial velocity value, it is written as Vo, while for the final velocity, we simply write V or Vt. As an object moves through the air, air resistance slows the object’s speed.
The formula of the kinematic equation used for solving this case is
Vt = V0 + at (the gravity is 10 m/s2)
[tex]Vt = Vo + (-g-a)t\\\0 = 20 + (-10-3)t\\0 = 20-13t\\\13t = 20\\\t = \frac{20}{13}[/tex]
After the time is known, now we can insert the value into the following formula :
[tex]Vt = Vo + (g-a)t\\Vt = 0 + 7.\frac{20}{13} \\Vt = 0 + \frac{140}{13} \\\Vt = 10.8 m/s[/tex]
Thus, the speed of the object returns to the ground after being thrown up with an initial velocity of 20.0 m/s and acceleration of 3.00 m/s2, which is 10.8 m/s.
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identify the main period of motion for a machine operating (and vibrating) at a rotational speed of 1780 cpm in units of seconds.
0.034 second is the main time period of the motion for a machine which is operating at a speed of 1780 cpm.
Time period of an object is the time required for it to complete its one cycle or oscillation. Angular frequency is angular displacement of any object of the waves per unit time. The formula for time is, T = 1/f
where T is time-period and f is frequency.
Operating speed of the machine = 1780 cpm (cycle per minute)
Cycle in one minute = 1780
Cycle in 1 second = 1780/60 = 29.67 cycles
Time required in one cylcle, T = 1/29.67 = 0.034 second
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a race car starts from rest, speeds up with constant acceleration, and reaches a final velocity of 80 m/s. what was the average velocity of the car in m/s?
The average velocity of the car is 40m/s
The average velocity of an object can be determined by dividing the change in position by the change in time.
For this situation, the vehicle begins from rest (initial velocity of 0 m/s) and arrives at a final velocity of 80 m/s.
We can use the equation:
Average velocity = (final velocity + initial velocity) / 2
Average velocity = (80 m/s + 0 m/s) / 2
Average velocity = 40 m/s
This is the average velocity of the vehicle during the entire time interval. Remember that this isn't equivalent to the instantaneous velocity at one point in time, which can be not quite the same as the average velocity.
It's important to take note of that on the off chance that the vehicle's speed increase isn't constant, the average velocity won't rise to the final velocity in addition to the initial velocity isolated by two.
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A sailor is walking on an aircraft carrier and is observed by a stationary barge. The sailor's velocity according to the barge is 36 m/s. At the same time, the barge observed the aircraft carrier moving at 43 m/s. What is the velocity of the sailor relative to the aircraft carrier?
The velocity of the sailor relative to the aircraft carrier is - 7 m/s.
What is the velocity of the sailor relative to the aircraft carrier?
The velocity of the sailor relative to the aircraft carrier is calculated by applying the principle of relative velocity as shown below.
Vs/c = Vs - Vc
where;
Vs is the velocity of the sailorVc is the velocity of the aircraftThe velocity of the sailor relative to the aircraft carrier is calculated as;
Vs/c = 36 m/s - 43 m/s
Vs/c = -7 m/s
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1. the magnitude (amplitude) of a vibration velocity signal is 0.23 ips at 1170 cpm. find the equivalent displacement amplitude in mils pk-pk and acceleration amplitude in g
In this case, the acceleration amplitude would be (0.23 ips x 1170 cpm)2 = 546.7 g.
What is acceleration?Acceleration is the rate of change of velocity over time. It is a vector quantity, meaning that it has both magnitude and direction. The magnitude of acceleration is the rate at which the velocity changes, and the direction of acceleration is the same as the direction of the velocity.
Displacement amplitude:
The formula for displacement amplitude is displacement amplitude = velocity amplitude / (2πf).
In this case, the displacement amplitude would be 0.23 ips / (2π x 1170 cpm) = 0.00196 inches pk-pk. Converting to mils pk-pk, this would be 1.96 mils pk-pk.
Acceleration amplitude:
The formula for acceleration amplitude is acceleration amplitude = (velocity amplitude x f)2.
In this case, the acceleration amplitude would be (0.23 ips x 1170 cpm)2 = 546.7 g.
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what is the gauge pressure profile of the water against a section of the container? arrow lengths against the wall indicates pressure magnitude.
Correct Question:
what is the gauge pressure profile of the water against a section of the container?
Gauge pressure is the pressure in relation to atmospheric pressure. For pressures greater than atmospheric pressure, gauge pressure is positive. For pressures lower than atmospheric pressure, gauge pressure is negative.
Pg stands for gauge pressure, which has the following relationships with absolute pressure: pg is equal to p - pa, where Pa is the local atmospheric pressure. Example: The tyre pressure, as determined by a vehicle tyre gauge, is 32.0 psi. The local atmosphere has a pressure of 14.2 psi.
There is pressure between two items that are in touch. The pressure profile is the distribution of pressure throughout the whole contact area.
Since the majority of gauges measure pressure in relation to atmospheric pressure, which acts as the zero point, this form of reading is simply referred to as "gauge pressure." But anything that is not a total vacuum is seen as being under pressure of some kind.
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Joiya grabs a cold bottle of water from the refrigerator and carries it across her dining room. The dining room is at room temperature.
Which of the following describe possible ways heat would be transferred in this system?
The possible ways that heat can be transferred in this system are:
Radiation Conduction How can heat be transferred in this system ?The most typical method of heat transfer is conduction, which involves the direct exchange of heat between two things.
Heat waves are created during the radiation heat transfer process and may be absorbed, reflected, or transmitted through a cooler substance. Earth is warmed by the sun using electromagnetic radiation. Heat waves come from warm bodies.
When Joiya sets the bottle of water down on a table or chair, then by conduction, heat ( or the loss of it ) would move around the table. Radiation would allow for the cold temperature to move into the air around the cold bottle.
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Options for this question include:
Convection Conduction RadiationA roller coaster features a near vertical drop of 150 meters. If the initial velocity was zero, the mass of the cart and riders was 2,000 kg, and the velocity at the end of the drop was 50 m/s, how much of the potential energy was converted into thermal energy?
The amount of the potential energy that was converted into thermal energy is determined as 440,000 J.
What is the potential energy lost to thermal energy?
The amount of the potential energy that was converted into thermal energy is calculated by applying the principle of conservation of energy as follows;
P.E - K.E = Eth
where;
P.E is the potential energyK.E is the kinetic energyEth is the thermal energy( 2,000 kg x 9.8 m/s² x 150 m ) - ¹/₂ (2,000 kg )( 50 m/s )² = Eth
2,940,000 J - 2,500,000 J = Eth
440,000 J = Eth
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How can you differentiate the driver and driven gears in a gear train?
The driver gear is the gear that provides the input motion to the gear train, while the driven gear is the gear that receives motion from the other gears in the train and provides the output motion.
What is driver gear train?This refers to the main or primary gear that majorly drives the other gears found in the gear train.The driver gear is typically connected to a power source, such as an electric motor or a combustion engine, while the driven gear is connected to the load that the gear train is intended to drive. The driver gear is also the one that has the greater torque and the one that rotates faster.
Driven gears refer to the gear that receives motion from the other gears in the train and provides the output motion.
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an experimental rocket designed to land upright falls freely from a height of 2.98 102 m, starting at rest. at a height of 96.5 m, the rocket's engines start and provide constant upward acceleration until the rocket lands. what acceleration is required if the speed on touchdown is to be zero? (neglect air resistance.)
The required acceleration has a magnitude of 19.7 m/s2 directed upwards, correct to three significant figures.
The the purpose of analysis, the motion of rocket is divided into two phases.
Phase 1: the free fall motion of the rocket from the height 2.98*102m to a height 96.5m.
Phase 2: the motion of the rocket due to the acceleration of the rocket also from the height 96.5 m to the point of touchdown y = 0m.
The initial velocity of the rocket is 0m/s when it started to experience a fall from rest under free fall. g = 9.8m/s² t1 is the time taken for phase 1 and t2 is the time taken for phase2.
The final velocity under free fall becomes the initial velocity for the accelerated motion of the rocket in phase 2 and the final velocity or speed in phase 2 is equal to zero.
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At a cost of 9. 0 cents/kWh, estimate how much this would add to your monthly electric energy bill if you made toast four mornings per week (16 times per month)
The cost of making toast 16 times per month at a rate of 9.0 cents/kWh is approximately $0.1 per month.
How does the energy consumption of a device change with the length of usage?
The strength consumption of a tool commonly will increase with the duration of utilization. This is due to the fact maximum devices devour electricity continuously at the same time as in use, no matter how long they're used for. Some gadgets, along with appliances with standby or sleep modes, may devour less strength while now not in use, but will eat extra strength the longer they're used. For example, a fridge will consume extra power over a month than it will over an afternoon, and a pc will devour more energy over a 12 months than it's going to over a month.
A few gadgets, consisting of incandescent light bulbs, will eat extra energy and put on out faster the greater they may be used.
We convert from Watt to kilowatt
650/1000 = 0.65KW
We convert from minutes to hour:
6/60= 0.1 hr
Convert cents to dollars
9/100 = $0.09
Energy cost in KWh= 0.65 × 0.1 × 0.09 ×16= $ 0.1 per month
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If the work required to speed a car up from 10km/h to 20km/h is 5.0 x 10^3 J, what would be the work required to increase the cars speed from 20km/h to 30km/h?
If the work required to speed a car up from 10km/h to 20km/h is 5.0 x 10^3 J, the work required to increase the cars speed from 20km/h to 30km/h is: 8.33 × 10³J.
How to find the work required?Using this formula to determine the work required to increase the cars speed from 20km/h to 30km/h
[tex]Wii = Wi (V^2_2- V^2_1) /v^2_2 - v^2_1[/tex]
Let plug in the formula
Work required = (5 × 10³) (30² -20²) / (20² -10²)
Work required = (5 × 10³) ( 900 - 400) /(400 - 100)
Work required = (5 × 10³) ( 500) / 300
Work required = 8.33 × 10³J
Therefore the Work required is 8.33 × 10³J.
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as a heart chamber contracts, what happens to the pressure of the fluid within it?
The pressure of the fluid inside the heart chamber gets increased when the heart chamber contracts.
A typical heart has 4 chambers, two upper and two lower chambers. The upper two chambers, the right and left, receive incoming blood. The lower two chambers, the more muscular right and left, pump the blood out of the heart. The heart valves, which maintain blood flowing in the right direction, are gates at the chamber openings. We know when a closed chamber which is filled with a fluid is compressed, the fluid inside the chamber tries to come out of the chamber. Which increases the blood pressure in case of a heart chamber.
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When a potential difference of 125V is applied to two parallel plates, the field between them is 4. 25 x 103N/C. How far apart are the plates?
The distance between the two parallel plates can be found using the equation E = V/d where E is the electric field, V is the potential difference and d is the distance between the plates. Thus, d = V/E = 125V / 4.25 x 103N/C = 29.41cm
What is the relationship between electric field, potential difference, and distance in parallel plates?
The relationship between electric field, potential difference and distance in parallel plates is inversely proportional. As the potential difference increases, the electric field between the plates increases and the distance between the plates decreases. And as the distance between the plates increases, the electric field between the plates decreases and the potential difference applied to the plates decreases.
It can be mathematically represented by the formula E = V / d, where E is the electric field, V is the potential difference, and d is the distance between the plates.
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The distance between the two parallel plates can be found using the equation E = V/d , 29.41cm far apart are the plates .
Evaluating :E = V/d
where E is the electric field,
V is the potential difference and
d is the distance between the plates.
Thus, d = V/E
= 125V / 4.25 x 103N/C
= 29.41cm
Potential difference :The relationship between electric field, potential difference and distance in parallel plates is inversely proportional. As the potential difference increases, the electric field between the plates increases and the distance between the plates decreases. And as the distance between the plates increases, the electric field between the plates decreases and the potential difference applied to the plates decreases.
It can be mathematically represented by the formula E = V / d, where E is the electric field, V is the potential difference, and d is the distance between the plates.
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you would like to know whether silicon will float in mercury and you know that can determine this based on their densities. unfortunately, you have the density of mercury in units of kilogrammeter3 kilogram meter 3 and the density of silicon in other units: 2.33 2.33 gramcentimeter3 gram centimeter 3 . you decide to convert the density of silicon into units of kilogrammeter3 kilogram meter 3 to perform the comparison. by which combination of conversion factors will you multiply 2.33 2.33 gramcentimeter3 gram centimeter 3 to perform the unit conversion?
The density of silicon is [tex]2.33 * 10^{-9} kg.m^{3}[/tex]
Given density of silicon is 2.33 gram centimeter cube.
We know that:
100 cm = 1 m
1cm = 1/100m = [tex]10^{-2} m[/tex]
[tex]1 cm^{3} = 10^{-6} m^{3}[/tex]
Also,
1000 gram = 1 kg
1 gram = 1/1000 kg = [tex]10^{-3} kg[/tex]
Now, to convert gram centimeter cube into kilogram meter cube we should multiply by these values.
So, By putting these values we get:
Density = 2.33 * [tex]10^{-3} kg * 10^{-6} m^{3} = 2.33 * 10^{-9}kg. m^{3}[/tex]
The density of material shows the denseness of that material in a specific given area. A material’s density is defined as its mass per unit volume. Density is essentially a measurement of how tightly matter is packed together. It is a unique physical property of a particular object. The principle of density was discovered by the Greek scientist Archimedes. It is easy to calculate density if you know the formula and understand the related units The symbol ρ represents density or it can also be represented by the letter D.To know more about density visit:
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You are to drive 280km on an expreway. The interview i at 11:15 a.m. You plan to drive at 100km/h, o you leave at 8:00 a.m. to allow ome extra time. You drive at
The least speed is required to cover the rest of the trip to arrive in time for the interview is [tex]114.05km/hr[/tex]
Distance and displacement are two quantities that seem to mean the same but are distinctly different with different meanings and definitions. Distance is the measure of “how much ground an object has covered during its motion” while displacement refers to the measure of “how far out of place is an object.”
Here distance formula is,
Δ[tex]d=d_{1} +d_{2}[/tex]
Here we need to find the time left and the distance covered:
T[tex]1[/tex] [tex]=\frac{100}{100}=1hr=60 min[/tex]
T[tex]2[/tex] [tex]=\frac{43}{41} =1.04hr=62.92 min[/tex]
Total time was [tex]3.25hr[/tex][tex]=195min[/tex]
So, Time left is: [tex]1.21hr =72.08min[/tex]
Total distance left to cover is:
D[tex]=280-100-43=137[/tex][tex]km[/tex]
Now minimum speed required is:
[tex]s=\frac{distance}{time} =\frac{137}{1.21} =114.05km/hr[/tex]
Therefore, the least speed is required to cover the rest of the trip to arrive in time for the interview is [tex]114.05 km/hr[/tex].
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Complete question: you are to drive to an interview in another town, at a distance of 280km on a expressway. The interview is at 11:15 a.m. you plan to drive at 100km/h, but then construction work forces you to slow to 41.0km/h for 43.0km what would be the least speed needed for the rest of the trip to arrive in time for the interview?
Point A
Support
3.0m
2.5m
Figure 5
Weight of girl = 600 N
Weight of diving board = 800 N
Water
The support post pushes up on the diving board with a force of 3040 N. The force provides the anti-clockwise moment which keeps the board in equilibrium.
Calculate the distance that the support must be from point A.
The distance that the support must be from point A . 1.2010 3 N.
What is the distance that the support must be from point A?At x = 0, where the x axis is parallel to the diving board, we assume the force acting on the left pedestal to be F1. We define the right pedestal's force as F2 and its location as x=d. W is the diver's weight, which is found at x=L. Setting the total of forces (with upward positive) and the sum of torques (around x2) to zero yields the following two equations:
F 1 +F 2 −W=0
F 1 d+W(L−d)=0
(a) The result of the second equation is F 1 = d L d W = (2.5m 3.0m)
(600N) = 800N, which should be rounded to F 1 = 1.210 3 N. Consequently, F 1 = 1.2010 3 N
(b) F 1 is negative, suggesting a downward force.
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Two restaurant employees push a 730 kg wheeled dumpster along a horizontal surface. After they push the dumpster a distance of 5.5 m starting from rest, its speed is 0.75 m/s. What is the magnitude of the net force on the dumpster?
The net force that acts on the object is 36.5 N.
What is the net force?We have to note that the first thing that we would have to obtain is the acceleration of the object and we can be able to obtain this by the use of the formula;
v ^2 = u^2 + 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance
(0.75)^2 = (0)^2 + 2 * a * 5.5
a = (0.75)^2 / 2 * 5.5
a = 0.5625/11
a = 0.05 m/s^2
The net force is ma
F = 730 kg * 0.05 m/s^2
F = 36.5 N
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How far could a force of 3N pull a wooden block before transferring 12J of energy?
The distance which a force of 3N will pull a wooden block before transferring 12J of energy is 4m.
What is Force?This is referred to as an influence that can change the motion of an object and the unit is Newton.
It has a relationship with distance and work which can be seen below:
Work = Force × distance
12J = 3N × d
d = 12/3 = 4m.
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you are throwing paper airplanes in class, and you throw them hard enough they start out at a horizontal speed of 10fts . however, they have a horizontal deceleration of 4fts . what is the greatest distance away from the initial position that an object can be if it can be struck by the airplane?
The greatest distance away from the initial position that an object can be if it struck by the airplane is 12.5 ft, if the initial speed of the airplane is 10 ft/s.
Initial speed of the paper airplane, u = 10 ft/s
Final speed of the paper airplane, v = 0
deceleration of the airplane, a = -4 ft/s²
By the first equation of motion, v = u -at
Time of flight, t = (v-u)/a
t = (0 - 10)/-4 = 2.5 sec
Maximum distance travelled by the airplane, = S
S = ut + 0.5at²
S = 10 × 2.5 - 0.5 × 4 × 2.5²
S = 12.5 ft
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Help! I have no idea to go about this... Please answer both questions with clear working so that I understand!
(i) The power wasted in heating the wire if the current in part (a) flows in the wire is 53.8 MW.
(ii) The power wasted in heating the wire if the current in part (b) flows in the wire is 17,800 MW.
What is the value of the power wasted in the wire?The value of the power wasted in heating the wire is calculated by applying the following formula.
P = I²R
where;
I is the value of the current flowing in the wireR is the resistance of the wireFor the first case when the resistance, R = 9 Ω and current, I = I,
The power wasted is calculated as;
P = I² x 9
P = 9I²
For 22 kV, the current, I = (22,000 V) / 9 Ω
I = 2,444.44 A
P = 9 x (2,444.44)²
P = 5.38 x 10⁷ W
P = 53.8 x 10⁶ W
P = 53.8 MW
For the second case when the resistance, R = 9 Ω and current, I = I,
The power wasted is calculated as;
P = I² x 9
P = 9I²
For 400 kV, the current, I = (400,000 V) / 9 Ω
I = 44,444.44 A
P = 9 x (44,444.44)²
P = 1.78 x 10¹⁰ W
P = 17,800 x 10⁶ W
P = 17,800 MW
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five equal forces of 10 N are applied at
a point. If the angle between them is
equal, what is the resultant force?
The resultant force is approximately 11.75 N
solving for the resultant force:If five equal forces of 10 N are applied at a point, and the angle between them is equal, then the forces can be considered as forming a regular pentagon.
The angle between any two adjacent forces in a regular pentagon:
180 - 360 degrees
n
where,
n = the number of sides.
In this case, the angle is
180 - 360
5
θ = 108 degrees.
To calculate the resultant force, we can use vector addition. Since the forces are equal and the angle between them is 108 degrees, we can use the law of cosines to find the magnitude of the resultant force. The law of cosines states that the square of the magnitude of the resultant force (R) is equal to the sum of the squares of the individual forces (F) plus twice the product of the individual forces and the cosine of the angle between them (θ).
R² = F² + F² + 2 * (F) *(F)* cos(108)
R² = 10² + 10² + 2(10)(10)cos(108)
R² = 100 + 100 + 200 * (cos(108))
R² = 100 + 100 + 200 * (-0.309016994)
R = ([tex]\sqrt({100 +100 - 62)}[/tex]
R = √138
R = 11.75 N
The magnitude of the resultant force is approximately 11.75 N, which is the force that would be required to replace all five forces.
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which method of naming/locating stars will be the best for giving someone the location of the star?
Celestial navigation is the best method of naming or locating stars, if we have to give someone the location of a star.
With the help of "sights" or time angular measurements taken typically between a celestial body (e.g. the Sun, a planet, the moon or a star) and the visible horizon, Celestial navigation locate a star or any celestial body. However it can also take advantage of measurements between celestial bodies without taking the Earth horizon as reference, such as when the Moon is used in the practice, then it is called "lunars" or lunar distance method, which is used for determining precise time when time is unknown.
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a uniform electric field of 1350 n/c pointing due north exists in a region of space. a point charge of 2.85 nc is then placed in that original electric field. what is the magnitude of the net electric field now at a point 15.5 cm due east of the charge?
The magnitude of the net electric field now at a point 15.5 cm due east of the charge is 1721.15 N/C.
The physical field that surrounds electrically charged particles and pulls or attracts all other charged particles in the vicinity is known as an electric field. The physical field for a system of charged particles is another usage of the term.
Conductive materials are affected by electric fields, which change how electric charges are distributed at their surface. As a result, current travels through the body and to the ground. Circulating currents are induced within the human body by low-frequency magnetic fields.
A uniform electric field of 1350 n/c is already given,
[tex]E_1 = 1350[/tex]
Now, for the point charge, By Coulomb's law,
We get,
[tex]E_2=\frac{Kq}{r^{2} }[/tex]
here, [tex]K = 9*10^{9}[/tex]
According to the question,
[tex]q=2.85*10^{-9} C[/tex]
[tex]r = 0.155 m[/tex]
Putting these values in the formula,
We get,
⇒ [tex]E_2=\frac{(9*10^{9})*(2.85*10^{-9} ) }{(0.155)^{2}}[/tex]
⇒ [tex]E_2= 1067.6 N/C[/tex]
Now,
the net electric field,
⇒ [tex]E = \sqrt{(E_1^{2})+(E_2)^{2} }[/tex]
⇒ [tex]E=\sqrt{(1067.6)^{2} +(1350)^{2} }[/tex]
⇒ [tex]E= 1721.15 N/C[/tex]
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the building block of all elements and the smallest component into which an element can be divided?
a. building blocks
b. element
c. A molecule
d. atom
The building block of all elements and the smallest component into which an element can be divided d. atom
What is the smallest energy building block?
Quarks, the universe's tiniest particles, are significantly smaller and have far greater energy levels than the protons and neutrons in which they are found.
An atom is the smallest unit of an element that retains all of its characteristics.
However, atoms include several subatomic particles, the most significant of which are protons, neutrons, and electrons.
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at what height above the earth is the acceleration due to gravity 50.0% of its value at the surface?
At the height 2650 km, the value of acceleration due to gravity is 50% of its value at the surface.
The new value of gravity at a height h is given as g' = g R²/(R+h)²
As visible from the formula, increasing h results in decreasing gravity.
So, just put g′ = g/2 i.e. 50% less than g where g is gravity at surface. So, we get,
g/2 = g R²/(R+h)²
1/2 = R²/(R+h)²
2/1 = (R+h)²/R²
√2 = (R+h)/R = 1 + h/R
h/R = √2 - 1 = 0.414
h = 0.414 R
As we know radius of the earth = 6400 km, putting it in the above equation,
h = 0.414 R = 0.414(6400) = 2649.6 km
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The half life of a material is 100 years. If you have 1000g, how much will remain after 500 years?
What is upper fixed
point? How can it be measured explain with figure
The upper fixed point, also known as steam point, is the temperature at which pure water boils at normal atmospheric pressure.
In case of the Celsius scale, the upper fixed point is 100°C.
This is the boiling point of pure water at 1atm which is the normal atmospheric pressure.
What is atmospheric pressure?The pressure that the atmosphere exerts on the earth's surface is called atmospheric pressure.
What is boiling point?The temperature at which liquid water starts changing into vapour is called boiling point.
What is Celcius?Celcius is an unit of measuring temperature.
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in what direction is the force of air friction several seconds after the package has been dropped but before it reaches terminal velocity or hits the ground?
After a brief period of falling, the upward air friction on the cargo would equal the downward gravity pull if a parachute opened.
What forces are at work on something falling at its speed of descent?Air resistance reaches its maximum magnitude at the falling object's terminal velocity. Due to the fact that the two forces are acting in opposing directions, there is no net force acting on the item, and its speed has stabilised.
How do forces act on a dropped object as it is falling?In addition, gravity is pulling the thing downward as it falls. Gravity is an imbalanced force at the beginning of a descent. The result is an increase in speed or acceleration for the object. Aerodynamic drag or air resistance is encountered as it accelerates.
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