Answer:
balanced forces
The terms transverse or longitudinal are often used to describe the types of pulses. To what feature of a pulse do these terms refer:____________
Explanation:
Transverse pulse or waves are those in which elements of the pulse move perpendicular to the propagation of the pulse. Whereas, Longitudinal waves are those in which elements of the wave are in same direction as the propagation of the wave. For example Light is a transverse pulse whereas sound is a longitudinal wave.
motion is a change in
A student adds two vectors of magnitudes 48 m and 22 m. What are the maximum and minimum possible values for the resultant of these two vectors.
Answer:
Maximum=70 m
Minimum=26 m
Explanation:
Vector Addition
Since vectors have magnitude and direction, adding them takes into consideration not only the magnitudes but also their respective directions. Two vectors can be totally collaborative, i.e., point to the same direction, or be totally opposite. In the first case, the magnitude of the sum is at maximum. Otherwise, it's at a minimum.
Thus, the maximum magnitude of the sum is 48+22 = 70 m and the minimum magnitude of the sum is 48-22= 26 m
A wire is carrying current vertically downward. What is the direction of the force due to Earth's magnetic field on the wire?
A wire is carrying current vertically downward.
What is the direction of the force due to Earth's magnetic field on the wire?
a) horizontally towards the east
b) horizontally towards the west
c) horizontally towards the south
d) horizontally towards the north vertically upward
Answer: The correct option is A ( horizontally towards the east)
Explanation:
Magnetic field is a region around a magnet or a current- carrying conductor, where a magnetic force is experienced. The magnetic effect of electric current was first discovered in the early 1820 by Oersted. Using a wire that had current flowing through it and a pivoted magnetic needle, he discovered that the direction of deflection depended on the direction of the current and whether the wire was above or below the needle.
From the way the needle turns when current when current carrying wire is held parallel to it, he therefore concluded that:
--> a current has magnetic field all round it,
--> the magnetic field is in a direction perpendicular to the current.
The above discovery was now modified in Fleming's left hand rule which states that when conductor carrying current is placed in a magnetic field, the conductor will experience a force perpendicular to both the field and the flow of current.
Therefore from the question, a vertical wire carrying current in DOWNWARD direction is placed in a HORIZONTAL magnetic field directed to the NORTH. The direction of the force on the wire is to the EAST.
What is the final velocity of an object that starts from rest and accelerates uniformly at 4
m/s2 over a distance of 8 m?
Answer:
8m/s
Explanation:
Given parameters:
Initial velocity = 0m/s
Acceleration = 4m/s²
Distance = 8m
Unknown:
Final velocity = ?
Solution:
To solve this problem, we use the right motion equation and find the unknown.
The right motion equation to solve this problem is given as :
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the unknown acceleration
S is the distance
Now insert the parameters and solve;
v² = 0² + 2 (4) (8)
v² = 64
v = 8m/s
What fraction of an iceberg is submerged? (ρice = 917 kg/m3, ,ρsea = 1030 kg/m3.)
Answer:
Choice d. Approximately [tex]89\%[/tex] of the volume of this iceberg would be submerged.
Explanation:
Let [tex]V_\text{ice}[/tex] denote the total volume of this iceberg. Let [tex]V_\text{submerged}[/tex] denote the volume of the portion that is under the liquid.
The mass of that iceberg would be [tex]\rho_\text{ice} \cdot V_\text{ice}[/tex]. Let [tex]g[/tex] denote the gravitational field strength ([tex]g \approx 9.81\; \rm N \cdot kg^{-1}[/tex] near the surface of the earth.) The weight of that iceberg would be: [tex]\rho_\text{ice} \cdot V_\text{ice} \cdot g[/tex].
If the iceberg is going to be lifted out of the sea, it would take water with volume [tex]V_\text{submerged}[/tex] to fill the space that the iceberg has previously taken. The mass of that much sea water would be [tex]\rho_\text{sea} \cdot V_\text{submerged}[/tex].
Archimedes' Principle suggests that the weight of that much water will be exactly equal to the buoyancy on the iceberg. By Archimedes' Principle:
[tex]\text{buoyancy} = \rho_\text{sea} \cdot V_\text{submerged} \cdot g[/tex].
The buoyancy on the iceberg should balance the weight of this iceberg. In other words:
[tex]\underbrace{\rho_\text{ice} \cdot V_\text{ice} \cdot g}_\text{weight of iceberg} = \underbrace{\rho_\text{sea} \cdot V_\text{submerged} \cdot g}_\text{buoyancy on iceberg}[/tex].
Rearrange this equation to find the ratio between [tex]V_\text{submerged}[/tex] and [tex]V_\text{ice}[/tex]:
[tex]\begin{aligned} &\frac{V_\text{submerged}}{V_\text{ice}} \\&= \frac{\rho_\text{ice} \cdot g}{\rho_\text{sea} \cdot g}\\ &= \frac{\rho_\text{ice}}{\rho_\text{sea}}\ = \frac{917\; \rm kg \cdot m^{-3}}{1030\; \rm kg \cdot m^{-3}} \approx 0.89 \end{aligned}[/tex].
In other words, [tex]89\%[/tex] of the volume of this iceberg would have been submerged for buoyancy to balance the weight of this iceberg.
Thomas the Tank Engine (a train) is going 80 m/s and slows down to 30 m/s over a period of 30s. What is his deceleration? Acceleration= (final velocity-initial velocity)/ time A. -1.67 m/s/s B. 0.67 m/s/s C. -50 m/s/s D. 50 m/s/s
Answer: D
Explanation:
A 1.15 kg book is at rest on the table. What is the magnitude of the normal force that the table is exerting on the book?
Answer:
11.27N
Explanation:
Given parameters:
Mass of the book = 1.15kg
Unknown:
Magnitude of the normal force = ?
Solution:
The normal force is the vertical force exerted by a body on an object.
It can be described as the weight of an object.
Normal force = mass x acceleration due to gravity
Normal force = 1.15 x 9.8 = 11.27N
A diffraction pattern is formed on a screen 150 cm away from a 0.500-mm-wide slit. Monochromatic 546.1-nm light is used. Calculate the fractional intensity I/Imax at a point on the screen 4.10 mm from the center of the principal maximum.
Solution :
The expression for the intensity of light is given by :
[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a \sin \theta}{\lambda}}{\frac{\pi a \sin \theta}{\lambda} }\right)^2$[/tex]
For a small angle, θ
sin θ = tan θ
[tex]$=\frac{y}{L}$[/tex]
Therefore the above equation becomes,
[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a y}{\lambda L}}{\frac{\pi a y}{\lambda L} }\right)^2 $[/tex]
The given data is
λ = 546.1 nm
L = distance between the slit and the screen = 140 cm
= 1.40 m
a = width of the slit
= [tex]$0.50 \times 10^{-3} \ m$[/tex]
Therefore,
[tex]$I=I_{max}\left(\frac{\sin \frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20}}{\frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20} }\right)^2 $[/tex]
[tex]$=\left(\frac{0.170}{9.82}\right)^2$[/tex]
[tex]$= 2.89 \times 10^{-4} \ I_{max}$[/tex]
Therefore the fractional intensity is [tex]$\frac{I}{I_{max}}= 2.89 \times 10^{-4} $[/tex]
if a certain car, going with speed v1, rounds a level curve with a radius r1, it is just on the verge of skidding. if its speed is now doubled, the radius of the tightest curve on the same road that it can round without skidding is:
Answer:
The correct answer is 4R1
Explanation:
According to the given scenario ,the radius of the tightest curve on the same road without skidding is as follows:
As we know that
Centeripetal Acceleration is
= v^2 ÷ r
In the case when velocity becomes 2 times so the r would be 4 times
So, the radius of the tightest curve on the same road without skidding is 4R1
Why does a stop sign appear red?
Answer:
because it’s suppose to be red like a stop light.
Explanation:
So it tells you to stop
a 1220 kg automobile travels at 75 m/s. what net work would be required to bring it to a stop
Answer:
W = - 3431250 [N]
Explanation:
In order to solve this problem, we must use the theorem of work and energy conservation. This theorem tells us that the initial mechanical energy of a body plus the work done on this body must be equal to the final mechanical energy of the body. We must remember that the mechanical energy of a body is equal to the sum of kinetic energies plus potential energy plus elastic energy.
In this problem, we only have kinetic energy.
[tex]E_{1}+W_{1-2}=E_{2}\\where:\\E_{1}=E_{pot}+E_{kine}+E_{elas}\\E_{pot} = 0\\E_{elas}=0\\E_{kine}=\frac{1}{2} *m*v^{2}[/tex]
And we have:
m = mass = 1220 [kg]
v = velocity = 75 [m/s]
As the carriage stops the final kinetic energy is zero.
Now replacing:
[tex]\frac{1}{2} *1220*(75)^{2} +W_{1-2}=0\\W_{1-2}= - 3431250[N][/tex]
Note: The negative force means that the force has to be carried out by the carriage. That is, no external force acts on the car to stop it.
Two forces of 50 N and 30N respectively, are acting on an object. Find the net force (in N) on the object if
A) the forces are acting in the same direction.. B) Together, forces are acting in opposite directions
Answer:
A) 80 N
B) 20 N
Explanation:
A) If the forces acting are in the same direction, then the net force will be a sum of both so many faces..
Thus;
ΣF = 50 + 30
ΣF = 80 N
B) If the forces are acting in the in opposite directions with the larger force pointing in the positive y-axis then, the net force is;
ΣF = 50 - 30
ΣF = 20 N
A diver 50 m deep in 10∘C fresh water exhales a 1.0-cm-diameter bubble. What is the bubble's diameter just as it reaches the surface of the lake, where the water temperature is 20∘C?
Answer:
18.2mm
Explanation:
D = 50m
T1 = 10+273 = 283K
T2 = 20+273 = 293K
R1 = 5x10^-3
Absolute pressure at 50m
P1 = pA + pwateer x g x d
= 101000+ 1000x9.81x50
= 591500pa
New volume of bubble
= P1v1/T1 = p2v2/T2
= 125x10^-9 x 591500x293/101000*283
= 757.9x10^-9m³
R2 = 9.2x10^-3
D2 = 18.2mm
Or 1.82cm
Question 12 of 20
To produce a magnetic field, what does an electromagnet require?
A. A solenoid with no current flowing through it
B. A current flowing through a coil of wire
C. A core made from a magnetic material
D. A copper core
Answer:
B a current flowing through a coil of wire :)
Explanation:
what is the object's position at 6s?
Answer:
6sec and 8 postion
Explanation:
What causes the magnetic field around the wire?
Magnetic field
O A. An electric current
O B. An electric field
PREVIOUS
An electric current causes the magnetic field around the wire. The correct answer is A.
The magnetic field around a wire is caused by the flow of electric current through the wire. When an electric current passes through a wire, it generates a magnetic field that forms circular lines of magnetic flux around the wire. This phenomenon is described by Ampere's law, which states that a magnetic field is produced by an electric current and its strength is directly proportional to the magnitude of the current.
The relationship between the electric current and the magnetic field can be understood using the right-hand rule. If you wrap your right hand around the wire with your thumb pointing in the direction of the current, the curled fingers indicate the direction of the magnetic field lines.
Therefore, an electric field is generated by an electric charge, not by an electric current. While an electric field can exist around a wire if there is a potential difference (voltage) applied across it, it is the flow of electric current that primarily generates the magnetic field.
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12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor = how
many "drinks"?
6 drinks
7 drinks
12 drinks
PLS HURRY
Answer:
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.
Explanation:
In the United States, a standard "drink" of beer has 12 ounces, a standard "drink" of wine has 5 ounces and standard drink of liquor has 1.5 ounces. Then, we obtain the quantity of drinks by dividing the total volume of each drink by its respective unit volume and summing each term. That is:
[tex]N = \frac{12\,oz}{12\,\frac{oz}{dr} }+\frac{12\,oz}{5\,\frac{oz}{dr} }+\frac{3\,oz}{1.5\,\frac{oz}{dr} }[/tex]
[tex]N = 1\,dr+2.4\,dr+2\,dr[/tex]
[tex]N = 5.4\,dr[/tex]
[tex]N = 6\,dr[/tex]
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.
A 3 kg mass is travelling in a circle of 0.1 m radius with a speed of 2 m/s. What is the centripetal acceleration?
a = v² / R = (2 m/s)² / (0.1 m) = 40 m/s²
2
Look at the circult dlagram.
Direction
of current
Battery
Bulb-
What type of circuit is shown?
A. open series circult
B. closed series circuit
C. open parallel circult
D. closed parallel circult
The direction of the current from the positive to the negative battery terminals and the fact that the bulbs are connected in parallel to each other suggests that this circuit is a Closed Parallel Circuit. The correct option is D.
What is the difference between open and closed circuits?An open circuit and a closed circuit are two types of electrical circuits that describe the flow of electrical current through a circuit.
An open circuit is a circuit in which there is a break in the path of the current, meaning that the current cannot flow through the circuit. In an open circuit, the switch is in the "off" position or there is a broken wire, and so no electrical current can flow through the circuit. This means that there is no voltage or electrical energy being transferred from the source to the load.
On the other hand, a closed circuit is a circuit in which there is a complete path for the current to flow through, meaning that the current can flow through the circuit. In a closed circuit, the switch is in the "on" position, and there is a continuous path for the current to flow from the source to the load and back to the source. This means that there is voltage and electrical energy being transferred from the source to the load.
Here in this question,
The direction of the current from the positive to the negative battery and the fact that the bulbs are connected in parallel to each other suggests that this circuit is a Closed Parallel Circuit.
In a closed parallel circuit, the components are connected in parallel to each other, meaning that they are connected to the same two points in the circuit and the current has multiple paths to flow through. The voltage across each component is the same, and the total current flowing through the circuit is divided among the components according to their resistance.
In contrast, an open series circuit is a circuit in which the components are connected in series, meaning that they are connected end to end in a single path, with no other branch points for the current to follow. If one component fails, the circuit becomes open and the current stops flowing.
Therefore, based on the information provided, the circuit described in the question is a Closed Parallel Circuit.
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The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at the instant the first touches the ground. How far above the ground is the second drop at that instant?
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Answer:
The second drop is 3.75 m above the ground
Explanation:
Free Fall Motion
A free-falling object falls under the sole influence of gravity without air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].
The distance traveled by a dropped object is:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
If we know the height h from which the object was dropped, we can find the time it takes fo hit the ground:
[tex]\displaystyle t=\sqrt{\frac{2y}{g}}[/tex]
When the first drop touches the ground there are two more drops in the air: the second drop still traveling, and the third drop just released from the tap.
The total time taken for the first drop to reach the ground is:
[tex]\displaystyle t_1=\sqrt{\frac{2*5}{g}}[/tex]
[tex]t_1 = 1.01\ s[/tex]
Half of this time has taken the second drop to fall:
[tex]t_2 = 1.01\ s/2=0.505\ s[/tex]
It has fallen a distance of:
[tex]\displaystyle y_2=\frac{9.8(0.505)^2}{2}[/tex]
[tex]y_2 = 1.25\ m[/tex]
Thus its height is:
h = 5 - 1.25 = 3.75
The second drop is 3.75 m above the ground
Which has more momentum, a 2000 lb car moving at 100 km/hr or a 4000 lb truck moving at 50 km/hr ?
Answer:
The truck and car have the same momentum.
Explanation:
[tex]m_1[/tex] = Mass of car = [tex]2000\ \text{lb}=2000\times0.45359237\ \text{kg}[/tex]
[tex]v_1[/tex] = Velocity of car = [tex]\dfrac{100}{3.6}\ \text{m/s}[/tex]
[tex]m_2[/tex] = Mass of truck = [tex]4000\times0.45359237\ \text{kg}[/tex]
[tex]v_2[/tex] = Velocity of truck = [tex]\dfrac{50}{3.6}\ \text{m/s}[/tex]
Momentum of car
[tex]p_1=m_1v_1\\\Rightarrow p_1=2000\times0.45359237\times \dfrac{100}{3.6}\\\Rightarrow p_1=25199.58\ \text{kg m/s}[/tex]
Momentum of the truck
[tex]p_2=m_2v_2\\\Rightarrow p_2=4000\times0.45359237\times \dfrac{50}{3.6}\\\Rightarrow p_2=25199.58\ \text{kg m/s}[/tex]
Both the truck and car have the same momentum of [tex]25199.58\ \text{kg m/s}[/tex].
The angle between an incident
ray and the mirror is 40°.
1) What is the angle of reflection?
Answer:
1) 50°
Explanation:
We need to find the angle of incidence first before finding the angle of reflection.
Angle of incidence = 90° - 40°
= 50°
Since the angle of incidence is the same as the angle of reflection, the angle of reflection here would be 50°.
Im need some help with this please
Answer:
c) Aeroplane
Explanation:
The aeroplane has the greatest mass than the other three objects, so it experiences the greatest gravitational force. Hence, the option (c) is the answer.
Shelley is in an elevator that is traveling downward and slowing down at a rate of
0.950 m/s2. If Shelley has a mass of 73.2 kg, what is her apparent weight during this
period?
Answer:
N = 648.55[N]
Explanation:
To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
∑F = Forces applied [N]
m = mass = 73.2 [kg]
a = acceleration = 0.950 [m/s²]
Let's assume the direction of the upward forces as positive, just as if the movement of the box is upward the acceleration will be positive.
By performing a summation of forces on the vertical axis we obtain all the required forces and other magnitudes to be determined.
[tex]-m*g + N = -m*a\\[/tex]
where:
g = gravity acceleration = 9.81 [m/s²]
N = normal force (or weight) measured by the scale = 83.4 [N]
Now replacing:
[tex]-(73.2*9.81)+N=-73.2*0.950\\-718.092+N=-69.54\\N = -69.54+718.092\\N = 648.55[N][/tex]
The acceleration has a negative sign, this means that the elevator is descending at that very moment.
A person holds a ladder horizontally at its center. Treating the ladder as a uniform rod of length 4.15 m and mass 7.98 kg, find the torque the person must exert on the ladder to give it an angular acceleration of 0.396 rad/s2.
Answer:
4.535 N.m
Explanation:
To solve this question, we're going to use the formula for moment of inertia
I = mL²/12
Where
I = moment of inertia
m = mass of the ladder, 7.98 kg
L = length of the ladder, 4.15 m
On solving we have
I = 7.98 * (4.15)² / 12
I = (7.98 * 17.2225) / 12
I = 137.44 / 12
I = 11.45 kg·m²
That is the moment of inertia about the center.
Using this moment of inertia, we multiply it by the angular acceleration to get the needed torque. So that
τ = 11.453 kg·m² * 0.395 rad/s²
τ = 4.535 N·m
The Torque will be "4.535 N.m".
Given:
Mass of ladder,
m = 7.98 kgLength of ladder,
L = 4.15 m
The moment of inertia will be:
→ [tex]I = \frac{mL^2}{12}[/tex]
[tex]= \frac{7.98\times (4.15)^2}{12}[/tex]
[tex]= \frac{7.98\times 17.2225}{12}[/tex]
[tex]= 11.45 \ kg.m^2[/tex]
hence,
The torque will be:
→ [tex]\tau = 11.453\times 0.395[/tex]
[tex]= 4.535 \ N/m[/tex]
Thus the above approach is correct.
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The greater the change in the speed of light in different media
the greater the angle of
Answer:
the angle at which light bends when it enters a different medium depends on its change in speed. The greater the change in speed, the greater the angle of refraction is. For example, light refracts more when it passes from Air to Diamond then it does when it passes from Air to wate.
Answer: Refraction
Explanation:
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Assignment: 02.03 Conservation of Mass
Details
Submit the assignment following the instructions in the lesson.
Due Date
N/A
20
Points Possible
20
Course Contribution
3
Submissions Allowed
0
Submission Number
The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.
Answer:
Steel Wool + Oxygen, Steel wool has a hard texture but is a grayish color. It looks like it's a powder, and also that it was rusted steel wool and then broken apart converted into a powder. So Iron oxide is 7 grams and combined steel wool is 7 grams, so you may assume that the mass has been retained. Yeah, it is a chemical change since the corrosion and rust in steel wool is a chemical process, but iron oxide is triggered by a physical change.
Egg + Heat, In the center, the egg has a yellow yolk while at the edge of the egg there is a kind of liquid, but it is visible, the heat becomes hot but clear The egg transformed into a delicious food called an omelet, which was yolk staid as a liquid but got a little harder, It was retained because the eggshell was 4 grams and the fried egg is 41 grams, but the clear border around it changed color. It is a chemical transition, and it results in the creation of new particles and the chemical bonds split apart and new ones are formed
Water + Heat, Water is a clear liquid, while the heat is very hot yet transparent. Once 5 g of liquid is a gas, it'll become 5 g of water vapor. Water + Heat Water is really a clear liquid. The mass of the liquid water is simply transformed into mass of the water vapor that is freshly created. There was no chemical process although water vapor can also be converted back to water, but it only shifted from a liquid to a gas and the structure did not change.
Zinc + Hydrogen Chloride Zinc, a metal white/silver solid. A clear, colorless liquid fluid with a really low pH in hydrogen chloride In hydrogen chloride, zinc is “dissolved” while releasing a colorless vapor. The liquid, possibly still having a low pH from the remaining acid, stays a colorless liquid.As sparked with a burning wooden splint, the colorless gas gathered in a tube provides a loud bang, because it is neither air trapped in the zinc, nor absorbed in hydropower acids. Well, even if the zinc is 12 grams and not 15 grams, the gas released was 3 grams and, as we all know, 3 + 12 is 15, so you could claim also that volume has also been saved.
Sodium Hydroxide + Copper, Sulfate Sodium hydroxide is a turbid solution and bright blue crystals are formed from copper sulfate A pale blue powder of basic copper hydroxide a solution of neutral salt sulfuric acid would be produced when their solutions are mixed with each other. The combined sodium hydroxide and copper sulfate make a total of 67 grams and the product is split because the sodium sulfate is 47 grams and the copper hydroxide is 20 grams, but all together it is still 67 grams, and you could assume that now the mass has been conserved. The evidence of a response was its image of royal blue basic copper hydroxide precipitates and a neutral salt sodium solution
Explanation:
If 65 kW is to be transmitted over two 0.100 ohm lines, estimate how much power is saved if the voltage is stepped up from 120 V to 1200 V
Answer: 5.91kw
Explanation:
given data:
power = 65kw
voltage stepped up = 120v t0 1200
R 0.100
Solution:
when the it is stepped to 120v
[tex]P = VI \\65000/ 120I\\ I = 541.7A\\[/tex]
power loss
[tex](I^{2} )R*2\\= (541.7^{2})0.100*2\\= 58536.2w[/tex]
when it is stepped to 1200v
[tex]\frac{65000}{1200} \\ I = 54.17A\[/tex]
[tex](I^{2} )R*2\\= (54.17^{2})0.100*2\\= 586.9w[/tex]
total power saved
[tex]= 65kw - 58.5kw - 0.59kw\\= 5.91kw[/tex]
A ball is thrown horizontally at a height of 1.5 meters at a velocity of 70 m/s. Assume no air resistance. How long until the ball reaches the ground?
0.25 s
0.38 s
0.55 s
0.67 s
Answer:
[tex]t = 0.55[/tex]
Explanation:
Given
[tex]Height, s = 1.5m[/tex]
[tex]Velocity, v = 70m/s[/tex]
Required
Determine the time to hit the ground
Using free fall formula:
[tex]S = \frac{1}{2}gt^2[/tex]
Take g as 9.8 and substitute value for S
[tex]1.5 = \frac{1}{2} * 9.8 * t^2[/tex]
[tex]1.5 = 4.9 * t^2[/tex]
Make t^2 the subject
[tex]t^2 = \frac{1.5}{4.9}[/tex]
[tex]t^2 = 0.30612244898[/tex]
Solve for t
[tex]t = \sqrt{0.30612244898[/tex]
[tex]t = 0.55[/tex] -- approximated