For the functions f(x)=−9x^2+9 and g(x)=8x^2+9x, find (f+g)(x) and (f+g)(−1)

Answer:

i think it might be A. 0.2

Step-by-step explanation:

Answer:

104 degrees

Step-by-step explanation:

The angle of the whole set of lines is 140 degrees. In addition, the partial angle of it is also given--which is 36 degrees. In order to solve for the remaining part, Subtract 36 degrees from 140 degrees to get 104 degrees.

Answer: x =40

Step-by-step explanation:

x +x +100 = 180   They form a straight line so they add to 180 degrees.

2x + 100 = 180      solve for x  by combining like terms

       -100    -100   subtract  100 from both sides

2x = 80             Divide both sides by 2

x =40

Answer:

x might be 40°.

Step-by-step explanation:

angle on a straight line =180°

x+100+x =180

2x =180-100

2x=80

2x/2=80/2

x=40°

Answer:

8

Step-by-step explanation:

putting it simple without any terms, half of the line LN is 4, all the other lines inside the rectangle are equal, so just double the length for the length of MO for the answer, 8

The length of the diagonal MO in the provided figure of square LNMO is 8 units long. Option C is correct.

The diagonal of the square is the distance from opposite vertices of it. The length of both the diagonals of the square is equal in length and bisect each other at the intersection point.

In the given image, the length figure LMNO represent a square, The length of the LM is,

[tex]LG=4\rm \; units[/tex]

In the image, point G is the intersection point of the diagonal of the square.

As the diagonals of the square bisect each other at the intersection point. The length of LN is,

[tex]LN=2\times LG\\LN=2\times4\\LN=8[/tex]

The length of both the diagonals of the square is equal in length. Thus,

[tex]MO=LN\\MO=8[/tex]

Hence, the length of the diagonal MO in the provided figure of square LNMO is 8 units long. Option C is correct.

Learn more about the diagonal of the square here;

https://brainly.com/question/92334

Answer:

The curvature is modelled by [tex]\kappa = \frac{e^{-t}}{6\sqrt{2}}[/tex].

Step-by-step explanation:

The equation of the curvature is:

[tex]\kappa = \frac{|\dot {x}\cdot \ddot {y}-\dot{y}\cdot \ddot{x}|}{[\dot{x}^{2}+\dot{y}^{2}]^{\frac{3}{2} }}[/tex]

The parametric componentes of the curve are:

[tex]x = 6\cdot e^{t} \cdot \cos t[/tex] and [tex]y = 6\cdot e^{t}\cdot \sin t[/tex]

The first and second derivative associated to each component are determined by differentiation rules:

First derivative

[tex]\dot{x} = 6\cdot e^{t}\cdot \cos t - 6\cdot e^{t}\cdot \sin t[/tex] and [tex]\dot {y} = 6\cdot e^{t}\cdot \sin t + 6\cdot e^{t} \cdot \cos t[/tex]

[tex]\dot x = 6\cdot e^{t} \cdot (\cos t - \sin t)[/tex] and [tex]\dot {y} = 6\cdot e^{t}\cdot (\sin t + \cos t)[/tex]

Second derivative

[tex]\ddot{x} = 6\cdot e^{t}\cdot (\cos t-\sin t)+6\cdot e^{t} \cdot (-\sin t -\cos t)[/tex]

[tex]\ddot x = -12\cdot e^{t}\cdot \sin t[/tex]

[tex]\ddot {y} = 6\cdot e^{t}\cdot (\sin t + \cos t) + 6\cdot e^{t}\cdot (\cos t - \sin t)[/tex]

[tex]\ddot{y} = 12\cdot e^{t}\cdot \cos t[/tex]

Now, each term is replaced in the the curvature equation:

[tex]\kappa = \frac{|6\cdot e^{t}\cdot (\cos t - \sin t)\cdot 12\cdot e^{t}\cdot \cos t-6\cdot e^{t}\cdot (\sin t + \cos t)\cdot (-12\cdot e^{t}\cdot \sin t)|}{\left\{\left[6\cdot e^{t}\cdot (\cos t - \sin t)\right]^{2}+\right[6\cdot e^{t}\cdot (\sin t + \cos t)\left]^{2}\right\}^{\frac{3}{2}}} }[/tex]

And the resulting expression is simplified by algebraic and trigonometric means:

[tex]\kappa = \frac{72\cdot e^{2\cdot t}\cdot \cos^{2}t-72\cdot e^{2\cdot t}\cdot \sin t\cdot \cos t + 72\cdot e^{2\cdot t}\cdot \sin^{2}t+72\cdot e^{2\cdot t}\cdot \sin t \cdot \cos t}{[36\cdot e^{2\cdot t}\cdot (\cos^{2}t -2\cdot \cos t \cdot \sin t +\sin^{2}t)+36\cdot e^{2\cdot t}\cdot (\sin^{2}t+2\cdot \cos t \cdot \sin t +\cos^{2} t)]^{\frac{3}{2} }}[/tex]

[tex]\kappa = \frac{72\cdot e^{2\cdot t}}{[72\cdot e^{2\cdot t}]^{\frac{3}{2} } }[/tex]

[tex]\kappa = [72\cdot e^{2\cdot t}]^{-\frac{1}{2} }[/tex]

[tex]\kappa = 72^{-\frac{1}{2} }\cdot e^{-t}[/tex]

[tex]\kappa = \frac{e^{-t}}{6\sqrt{2}}[/tex]

The curvature is modelled by [tex]\kappa = \frac{e^{-t}}{6\sqrt{2}}[/tex].

Answer:

1. -6.5x+11

2. 6b-5

3. 3p-5.1

Step-by-step explanation:

[tex]1. \\(x-1)+(12-7.5x)=\\x-1+12-7.5x=\\x-7.5x-1+12=\\-6.5x-1+12=\\-6.5x+11\\\\2.\\b-(4-2b)+(3b-1)=\\b-4+2b+3b-1=\\b+2b+3b-4-1=\\3b+3b-4-1=\\6b-4-1=\\6b-5\\\\3.\\(2p+1.9)-(7-p)=\\2p+1.9-7+p=\\2p+p+1.9-7=\\3p+1.9-7=\\3p-5.1[/tex]

Answer:

[tex]\dfrac{1213}{9999}[/tex]

Step-by-step explanation:

We are required to express [tex]0.\overline{1}+0.\overline{01}+0.\overline{0001}[/tex] as a common fraction.

The bar on top of the decimal part indicates the decimal number is a repeating decimal.

Therefore:

[tex]0.\overline{1}=\dfrac{1}{10-1}= \dfrac{1}{9}\\\\0.\overline{01}=\dfrac{1}{100-1}= \dfrac{1}{99}\\\\0.\overline{0001}=\dfrac{1}{10000-1}= \dfrac{1}{9999}\\\\\\$Therefore$:\\0.\overline{1}+0.\overline{01}+0.\overline{0001} \\=\dfrac{1}{9}+\dfrac{1}{99}+\dfrac{1}{9999}\\\\=\dfrac{1213}{9999}[/tex]

Answer:

The answer is option A

4 x ( 9 + 6)

Hope this helps you

Answer:

V  = 23π/6

Step-by-step explanation:

V = 2π ∫ [a to b] (r * h) dx

y = −x² + 23x − 132

y = −(x² − 23x + 132)

y = −(x − 11) (x − 12)

Parabola intersects x-axis (line y = 0) at x = 11 and x = 12 ----> a = 11, b = 12

r = x

h = −x² + 23x − 132

V = 2π ∫ [11 to 12] x (−x² + 23x − 132) dx

V  = 23π/6

Answer:  G ∩ M = {Anael, Max}

G U S = {Acel, Acton, Anael, Barek, Carl, Carlin, Dario, Kai, Max}

Step-by-step explanation:

intersection ∩ - items found in BOTH sets

union U - the joining of the sets. include EVERYTHING in the sets.

G = (Acel, Acton, Anael, Carl, Dario, Max}

S = {Anael, Barek, Bay, Carlin, Kai, Max}

G ∩ S: Anael and Max are found in both sets

G = (Acel, Acton, Anael, Carl, Dario, Max}

S = {Acton, Anael, Barek,  Carlin, Dario, Kai}

G U S: include everything in G and everything in S. If found in both sets, only list it once.

G U S = {Acel, Acton, Anael, Barek, Carl, Carlin, Dario, Kai, Max}

    Notice that Acton and Anael are in both sets but we only list them once.

Answer:

9.35

Step-by-step explanation:

AAS formula is easier if you add 12+90 then subtract it from 180, thats angle A.

then just write out the formula

sinA/a = sinB/b

Answer:

Step-by-step explanation:

Step1 : Verify Sn is valid for n = 1

Hi

500 *1.025^10 ≈ 640.04

Answer:

Step-by-step explanation:

k = 3 ; 2k + 2 = 2*3 + 2 = 6 + 2 = 8

k = 4;  2k + 2 = 2*4 + 2 = 8 +2 = 10

k =5; 2k + 2 = 2*5 +2 = 10+2 = 12

k=6;  2k +2 = 2*6 + 2 = 12+2 = 14

k = 7 ; 2k + 2 = 2*7 +2 = 14 +2 = 16

k = 8 ; 2k + 2 = 2*8 + 2 = 16 +2 = 18

∑ (2k + 2) = 8 + 10 + 12 + 14 + 16 + 18 = 78

Answer:

The maximum height that the object will reach is of 9 feet.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

[tex]f(x) = ax^{2} + bx + c[/tex]

It's vertex is the point [tex](x_{v}, f(x_{v})[/tex]

In which

[tex]x_{v} = -\frac{b}{2a}[/tex]

If a<0, the vertex is a maximum point, that is, the maximum value happens at [tex]x_{v}[/tex], and it's value is [tex]f(x_{v})[/tex]

In this question:

[tex]f(t) = -16t^{2} + 16t + 5[/tex]

So

[tex]a = -16, b = 16[/tex]

The instant of the maximum height is:

[tex]t_{v} = -\frac{16}{2*(-16)} = 0.5[/tex]

The maximum height is:

[tex]f(0.5) = -16*(0.5)^2 + 16*0.5 + 5 = 9[/tex]

The maximum height that the object will reach is of 9 feet.

Answer:

24

Step-by-step explanation:

Answer:

√75 = 5√3 and √12 = 2√3 so √75 + √12 = 5√3 + 2√3 = 7√3.

Answer:

[tex] 7\sqrt{3} [/tex]

Step-by-step explanation:

[tex] \sqrt{12} \: can \: be \: simplified \: as \: 2 \sqrt{3} \: and \: \sqrt{75} \: canbe \: simplified \: as \: 5 \sqrt{3} \\ after \: simplifying \: we \: can \: add \: them \: up \\ 2 \sqrt{3} + 5 \sqrt{3} = 7 \sqrt{3} [/tex]

Answer:

C(x) = 0.2x^5 - x^2 + 6000

Step-by-step explanation:

Given in the question are restated as follows:

Marginal cos = C'(x) = x^4 - 2x ...................... (1)

Note that marginal cost (C'(x)) refers to the change in the total cost (C(x)) as a result of one more unit increase in the quantity produced. That is, MC refers to the additional cost incurred in order to produce one more unit of a good.

Therefore, TC can be obtained by integrating equation (1) as follows:

C(x) = ∫C'(x) = ∫[x^4 - 2x]dx

C(x) = 1/5x^5 - 2/2x^2 + F ................................ (2)

Where F is the fixed cost. Since the fixed cost is given as $6,000 in the question, we substitute it for F into equation (2) and solve as follows:

C(x) = 0.2x^5 - x^2 + 6000 ......................... (3)

Equation (3) is the total cost function​ C.

Correct question:

The vector matrix [ [tex] \left[\begin{array}{ccc}2\\7\end{array}\right] [/tex] is dilated by a factor of 1.5 and then reflected across the x axis. If the resulting matrix is [a/b] then a=??? and b=???

Answer:

a = 3

b = 10.5

Step-by-step explanation:

Given:

Vector matrix = [tex] \left[\begin{array}{ccc}2\\7\end{array}\right] [/tex]

Dilation factor = 1.5

Since the vector matrix is dilated by 1.5, we have:

[tex] \left[\begin{array}{ccc}1.5 * 2\\1.5 * 7\end{array}\right] [/tex]

= [tex] \left[\begin{array}{ccc}3\\10.5\end{array}\right] [/tex]

Here, we are told the vector is reflected on the x axis.

Therefore,

a = 3

b = 10.5

Answer:

a = 3

b = -10.5

Step-by-step explanation:

got a 100% on PLATO

Answer:

A margin of error of +/- 3%

Step-by-step explanation:

Strenght of surveys:

The lesser the margin of error, the more precise, stronger, the confidence interval is.

The margin of error depends of the number of people surveyed. The more people are surveyed, lower the margin of error is, giving a stronger interval.

In this question:

We want the smaller margin of error, which is given by:

A margin of error of +/- 3%

Answer:

∠CDE

Step-by-step explanation:

Name it by the order of the letters with the point of the angle in the middle

The value of root 10 is between 3 and 3.5

Answer: x = 15, y = 12.5

Step-by-step explanation:

The sum of the three angle measures of a triangle equals 180ᴼ

Since these triangles are vertical, the measures are congruent.

45 + 60 = 105

180 - 105 = 75

So now we know that 5x = 75ᴼ and 6y = 75ᴼ.

To find x, divide 75 by 5

75 / 5 = 15

x = 15

To find y, divide 75 by 6

75 / 6 = 12.5

y = 12.5

Answer:

(2x+16) + (x) = 180

Step-by-step explanation:

The opposite angles of a quadrilateral inscribed inside a circle will be supplementary angles, meaning that A+C=180, and B+D=180. A+C is not given in the answers below, but B+D is, so that is the correct answer.

Hope this helps! Please give brainliest!!

Answer:

C

Step-by-step explanation:

Opposite angles of a quadrilateral are supplementary

The answers are in order

r = −0.08 --> weak negative correlation

r = −0.83 --> strong negative correlation

r = 0.96 --> strong positive correlation

r = 0.06 --> weak positive correlation

The match of each correlation is given by,

r = −0.08  implies a weak negative correlation

r = −0.83  implies a strong negative correlation

r = 0.96  implies strong positive correlation

r = 0.06 implies  weak positive correlation.

We have given that,

The correlation coefficient, r, to its description.

A                                                 B

r = −0.08                             strong negative correlation

r = −0.83                               weak positive correlation                

r = 0.96                               weak negative correlation                    

r = 0.06                                strong positive correlation

We have to match the given relation

If the correlation coefficient is greater than zero, it is a positive relationship. Conversely, if the value is less than zero, it is a negative relationship.

So the correct match is,

r = −0.08  implies a weak negative correlation

r = −0.83  implies strong negative correlation

r = 0.96  implies strong positive correlation.

r = 0.06 is implies  weak positive correlation.

To learn more about the correlation visit:

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Answer:

  30 miles

Step-by-step explanation:

Jose's charges are ...

  j = 5 + 0.30m . . . . . for m miles

Kathy's charges are ...

  k = 8 +0.20m . . . . . for m miles

The charges are the same when ...

 j = k

  5 +0.30m = 8 + 0.20m

  0.30m = 3 + 0.20m . . . . subtract 5

  0.10m = 3 . . . . . . . . . . . . subtract 0.20m

  m = 30 . . . . . . . . . . . . . . . multiply by 10

The charges will be the same for a distance of 30 miles.

Answer:

Step-by-step explanation:

I can help

Answer:

The 95 percent confidence interval for the true mean metal thickness is between 0.2903 mm and 0.2907 mm

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.95}{2} = 0.025[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.025 = 0.975[/tex], so [tex]z = 1.96[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.96\frac{0.000586}{\sqrt{59}} = 0.0002[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 0.2905 - 0.0002 = 0.2903 mm

The upper end of the interval is the sample mean added to M. So it is 0.2905 + 0.0002 = 0.2907 mm

The 95 percent confidence interval for the true mean metal thickness is between 0.2903 mm and 0.2907 mm

Answer:

Step-by-step explanation:

Given that:

[tex]E( \hat \theta _1) = \theta \ \ \ \ E( \hat \theta _2) = \theta \ \ \ \ V( \hat \theta _1) = \sigma_1^2 \ \ \ \ V(\hat \theta_2) = \sigma_2^2[/tex]

If we are to consider the estimator [tex]\hat \theta _3 = a \hat \theta_1 + (1-a) \hat \theta_2[/tex]

a. Then, for  [tex]\hat \theta_3[/tex] to be an unbiased estimator ; Then:

[tex]E ( \hat \theta_3) = E ( a \hat \theta_1+ (1-a) \hat \theta_2)[/tex]

[tex]E ( \hat \theta_3) = aE ( \theta_1) + (1-a) E ( \hat \theta_2)[/tex]

[tex]E ( \hat \theta_3) = a \theta + (1-a) \theta = \theta[/tex]

b) If [tex]\hat \theta _1 \ \ and \ \ \hat \theta_2[/tex] are independent

[tex]V(\hat \theta _3) = V (a \hat \theta_1+ (1-a) \hat \theta_2)[/tex]

[tex]V(\hat \theta _3) = a ^2 V ( \hat \theta_1) + (1-a)^2 V ( \hat \theta_2)[/tex]

Thus; in order to minimize the variance of [tex]\hat \theta_3[/tex] ; then constant a can be determined as :

[tex]V( \hat \theta_3) = a^2 \sigma_1^2 + (1-a)^2 \sigma^2_2[/tex]

Using differentiation:

[tex]\dfrac{d}{da}(V \ \hat \theta_3) = 0 \implies 2a \ \sigma_1^2 + 2(1-a)(-1) \sigma_2^2 = 0[/tex]

⇒

[tex]a (\sigma_1^2 + \sigma_2^2) = \sigma^2_2[/tex]

[tex]\hat a = \dfrac{\sigma^2_2}{\sigma^2_1+\sigma^2_2}[/tex]

This implies that

[tex]\dfrac{d}{da}(V \ \hat \theta_3)|_{a = \hat a} = 2 \ \sigma_1^2 + 2 \ \sigma_2^2 > 0[/tex]

So, [tex]V( \hat \theta_3)[/tex] is minimum when [tex]\hat a = \dfrac{\sigma_2^2}{\sigma_1^2+\sigma_2^2}[/tex]

As such; [tex]a = \dfrac{1}{2}[/tex]       if   [tex]\sigma_1^2 \ \ = \ \ \sigma_2^2[/tex]

Answer:

Step-by-step explanation:

In an isosceles triangle, the base angles are equal. This also means that the length of two sides of the triangle are equal. Looking at triangle ABC, to prove that it is an isosceles triangle, then

Angle CAB = angle CBA

For the second question, to determine how it is known that QS is equivalent to YT, we would recall that the diameter of a circle passes through the center and from one side of the circle to the other side. Assuming R is the center of the circle, then QS and YT are the diameters of the circle and also the diagonals of the rectangle. Thus, the correct option is

The diameters act as diagonals

Answer:

10 rows with 6 passengers per row

Step-by-step explanation:

Let x be the number of rows and y the number of passengers per row.

Then we can interpret the story as the following two equations:

xy=60

(x+2)(y-1)=60

Solving these two equations:

y=60/x

(x+2)(60/x-1)=60     (substitute y)

60 - x + 120/x - 2 = 60 (multiply by -x)

x² + 2x - 120 = 0     (factor)

(x-10)(x+12) = 0

x = 10

y = 60/10 = 6

and indeed 10 * 6 = 60 and also 12 * 5 = 60