Answer:
The tangent vector for [tex]t = 0[/tex] is:
[tex]\vec T (t) = \left \langle \frac{8}{10}, 0, \frac{6}{10} \right\rangle[/tex]
Step-by-step explanation:
The function to be used is [tex]\vec r(t) = \langle 8\cdot t, 10, 3\cdot \sin (2\cdot t)\rangle[/tex]
The unit tangent vector is the gradient of [tex]\vec r (t)[/tex] divided by its norm, that is:
[tex]\vec T (t) = \frac{\vec \nabla r (t)}{\|\vec \nabla r (t)\|}[/tex]
Where [tex]\vec \nabla[/tex] is the gradient operator, whose definition is:
[tex]\vec \nabla f (x_{1}, x_{2},...,x_{n}) = \left\langle \frac{\partial f}{\partial x_{1}}, \frac{\partial f}{\partial x_{2}},...,\frac{\partial f}{\partial x_{n}} \right\rangle[/tex]
The components of the gradient function of [tex]\vec r(t)[/tex] are, respectively:
[tex]\frac{\partial r}{\partial x_{1}} = 8[/tex], [tex]\frac{\partial r}{\partial x_{2}} = 0[/tex] and [tex]\frac{\partial r}{\partial x_{3}} = 6 \cdot \cos (2\cdot t)[/tex]
For [tex]t = 0[/tex]:
[tex]\frac{\partial r}{\partial x_{1}} = 8[/tex], [tex]\frac{\partial r}{\partial x_{2}} = 0[/tex] and [tex]\frac{\partial r}{\partial x_{3}} = 6[/tex]
The norm of the gradient function of [tex]\vec r (t)[/tex] is:
[tex]\| \vec \nabla r(t) \| = \sqrt{8^{2}+0^{2}+ [6\cdot \cos (2\cdot t)]^{2}}[/tex]
[tex]\| \vec \nabla r(t) \| = \sqrt{64 + 36\cdot \cos^{2} (2\cdot t)}[/tex]
For [tex]t = 0[/tex]:
[tex]\| \vec r(t) \| = 10[/tex]
The tangent vector for [tex]t = 0[/tex] is:
[tex]\vec T (t) = \left \langle \frac{8}{10}, 0, \frac{6}{10} \right\rangle[/tex]
if f(x) =2x-1 and g(x)=x^2-3x-2, fins (f+g)(x)
Answer:
[tex](f+g)(x)=x^2-x-3[/tex]
Step-by-step explanation:
If [tex]f(x)=2x-1[/tex], and [tex]g(x)=x^2-3x-2[/tex], then the addition [tex](f+g)(x)[/tex] equals:
[tex](f+g)(x)=2x-1+x^2-3x-2=x^2-3x+2x-2-1=x^2-x-3[/tex]
A driver travels a distance of 119 miles between 09:50 and 11:35. Work out the average speed of the driver
Answer:
68 miles per hour.
Step-by-step explanation:
The time taken for the driver to drive 119 miles is 105 minutes.
The average speed is equal to distance divided by the time taken.
105 minutes is equal to 1.75 hours.
[tex]S=119/1.75[/tex]
[tex]S =68[/tex]
The driver's average speed is 68 miles per hour.
Answer:
Speed = 68 mph
Step-by-step explanation:
Given:
Distance = 119 miles
Time = 1 hour 45 minutes = 1.75 hours
Required:
Speed = ?
Formula:
Average Speed = Total Distance Covered / Total Time Taken
Solution:
Speed = 119/1.75
Speed = 68 mph
If a/b = c/d, which of the following is not true?
1) ad=bc
2) a/c=b/d
3) a+b/b=c+d/d
4) a/d=c/b
5) b/a=d/c
Answer:
Option 4 is not true
Step-by-step explanation:
[tex]\frac{a}{b}=\frac{c}{d}\\\\[/tex]
1)Cross multiply,
ad = bc
So, true
2) a/ c = b/d also true
3) a+b/b = c+d/d also true
For example:
[tex]\frac{1}{4}=\frac{2}{8}\\\\\frac{1+4}{4}=\frac{2+8}{8}\\\\\frac{5}{4}=\frac{10}{8}\\\\[/tex]
When simplifying 10/8, it is 5/4.
5) b/a = d/c is also true
The product of Holly's savings and 3 is 39.
Use the variable h to represent Holly's savings.
Answer:
3h = 39Step-by-step explanation:
The question is incomplete. Here is the complete question.
Translate this sentence into an equation. The product of Holly's height and 3 is 39. Use the variable h to represent Holly's height.
Let holly's savings be h. If the product of Holly's savings and 3 is 39, this can be represented mathematically as h*3 = 39
To get holly's savings "h', we will divide both sides of the equation by 3
h*3 = 39
h*3/ 3= 39/3
h = 13*3/ 3
h = 13 * 3/3
h = 13*1
h = 13
Holly's savings is 13 and the required equation is 3h =39
Which statement implies that A and B are independent events?
O A. P(B|A)= P(B and A)
OB.P(B|A)= P(B)
P(A)
OC. P(B|A)= P(A)
OD. P(B|A)= P(B)
Answer:
Option B
Step-by-step explanation:
When A and B are independent events:
P(A and B) = P(A) * P(B)
OR
P(A|B) = P(A) * P(B)
Halfway through the season, a soccer player has made 15 penalty kicks in 19 attempts. Based on her performance to date, what is the relative frequency probability that she will make her next penalty kick?
Answer:
[tex]\dfrac{15}{19}[/tex]
Step-by-step explanation:
The soccer player so far has made 15 penalty kicks in 19 attempts.
Therefore:
Total Number of trials =19
Number of Successes =15
Therefore, the relative frequency probability that she will make her next penalty kick is:
[tex]=\dfrac{\text{Number of Successes}}{\text{Total Number of Trials}} \\=\dfrac{15}{19}[/tex]
You deal a pile of cards, face down, from a standard 52-card deck. What is the least number of cards the pile must have before you can be assured that it contains at least five cards of the same suit
Answer:
we need at least 17 - card deck
Step-by-step explanation:
From the information given :
We can attempt to solve the question by using pigeonhole principle;
"The pigeonhole principle posits that if more than n pigeons are placed into n pigeonholes some pigeonhole must contain more than one pigeon"
Thus; the minimum number of pigeon; let say at least n pigeons sit on at least one same hole among m hole can be represented by the formula:
m( n - 1 ) + 1
where ;
pigeons are synonymous to card
pigeonholes are synonymous to suits
So; m = 4 ; n = 5
∴ 4 (5 -1 ) + 1 ⇒ 4 (4) + 1
= 16 + 1
= 17
Hence; we need at least 17 - card deck
Graph g(x)=-2|x-5|-4
Answer:
Step-by-step explanation:
Jaden had 2 7/16 yards of ribbon. He used 1 3/8 yards of ribbon to make a prize ribbon. How much does he have now?
EASY!
Answer: 17/16 or 1 1/16
Step-by-step explanation:
BRO IT'S ELEMANTARY FRACTIONS!!!!
Seven new employees, two of whom are married to each other, are to be assigned seven desks that are lined up in a row. If the assignment of employees to desks is made randomly, what is the probability that the married couple will have adjacent desks
Answer:
2/7
Step-by-step explanation:
Seven employees can be arranged in 7! ways. n(S) = 7!
Two adjacent desks for married couple can be selected in 6 ways viz.,(1, 2), (2, 3), (3,4), (4, 5), (5,6),(6,7).
This couple can be arranged in the two desks in 2! ways. Other five persons can be arranged in 5! ways.
So, number of ways in which married couple occupy adjacent desks
= 6×2! x 5! =2×6!
so, the probability that the married couple will have adjacent desks
[tex]\frac{n(A)}{n(s)} =\frac{2\times6!}{7!} \\=\frac{2}{7}[/tex]
What is the area of the trapezoid below? Select one: a. 88 cm2 b. 44√3 cm2 c. 65 cm2 d. 36√3 cm2
Answer: D
Step-by-step explanation:
Since we are not given the height of the trapezoid, we can split this into a triangle and a rectangle. We find the area of each and then add them together. In order to do so, we must use Pythagorean Theorem to find the missing length so that we can find the area.
a²+b²=c²
a²+4²=8²
a²+16=64
a²=48
a=√48
a=4√3
Now that we know the missing length of the triangle, we can find the area of the triangle and the rectangle.
Triangle
A=1/2bh
A=1/2(4)(4√3)
A=8√3
-----------------------------------------------------------------------------------------
Rectangle
A=lw
A=7(4√3)
A=28√3
With our areas, we can add them together.
4√3+28√3=36√3 cm²
Can someone please help me I’m stuck
Answer:
The answer is the first option. ΔRED ~ ΔTAN
Step-by-step explanation:
This is because the letters should be in the same order. Notice how T and R are in the same spots so are E and A, as well as D and N.
Alice skated 3.4 miles on Monday and 2.6 miles on Wednesday. How much farther did she skate on Monday ?
Answer:
.8 miles further on Monday
Step-by-step explanation:
Take the miles on Monday and subtract the miles on Wednesday
3.4 - 2.6 =.8 miles
I'm lost with this problem please help. Write answers as a fractions
Answer: 8/3 and -9/4
Step-by-step explanation:
1. [tex]\frac{2^{3}}{3} = \frac{2 * 2 * 2}{3} = \frac{8}{3}[/tex]
2. In this problem, when raising a whole fraction to a power, you must both raise the numerator and denominator to that power.
[tex]-(\frac{3}{2})^2 = -(\frac{3^2}{2^2}) = -(\frac{9}{4}) = -\frac{9}{4}[/tex]
What is the solution y=-2x+4 and y=x-2
Answer:
Look below
Step-by-step explanation:
The probability that a person in the United States has type B+ blood is 12%. Three unrelated people in the United States are selected at random. Complete parts (a) through (d). (a) Find the probability that all three have type B+ blood. The probability that all three have type B+ blood is nothing. (Round to six decimal places as needed.)
Answer:
The probability that all three have type B+ blood is 0.001728
Step-by-step explanation:
For each person, there are only two possible outcomes. Either they have type B+ blood, or they do not. The probability of a person having type B+ blood is independent of any other person. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
The probability that a person in the United States has type B+ blood is 12%.
This means that [tex]p = 0.12[/tex]
Three unrelated people in the United States are selected at random.
This means that [tex]n = 3[/tex]
Find the probability that all three have type B+ blood.
This is P(X = 3).
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 3) = C_{3,3}.(0.12)^{3}.(0.88)^{0} = 0.001728[/tex]
The probability that all three have type B+ blood is 0.001728
Christian Iris and Morgan each get an equal share of 1/2 of pizza which model represent the fraction of the pizza each person gets
Answer:
CICI
Step-by-step explanation: NO cici
Christian, Iris and Morgan each get an equal share of 1/2 of the pizza and the model 1/6 represent the fraction of the pizza each person gets.
What is division?The division in mathematics is one kind of operation. In this process, we split the expressions or numbers into the same number of parts.
Given:
Christian, Iris and Morgan each get an equal share of 1/2 of the pizza.
To find the fraction of the pizza each person gets:
Divide the amount of pizza by the number of people.
There are 3 people and 1/2 pizza.
The fraction of the pizza each person gets
= The amount of pizza / number of people
The fraction of the pizza each person gets
= (1/2) / 3
Simplifying into multiplication,
The fraction of the pizza each person gets = 1/2 x 1/3
The fraction of the pizza each person gets
= 1/(2x3)
= 1/6
Therefore, the model that represents the requirement is 1/6.
To learn more about the division;
https://brainly.com/question/13263114
#SPJ5
The measurement of the circumference of a circle is found to be 64 centimeters, with a possible error of 0.9 centimeter. (a) Approximate the percent error in computing the area of the circle. (Round your answer to two decimal places.) 2.81 Correct: Your answer is correct. % (b) Estimate the maximum allowable percent error in measuring the circumference if the error in computing the area cannot exceed 1%. (Round your answer to one decimal place.)
Answer:
(a) 2.81%
(b) 0.5%
Step-by-step explanation:
We have the following information from the statement:
P = 64 + - 0.9
(a) We know that the perimeter is:
P = 2 * pi * r
if we solve for r, we have to:
r = P / 2 * pi
We have that the formula of the area is:
A = pi * r ^ 2
we replace r and we are left with:
A = pi * (P / 2 * pi) ^ 2
A = (P ^ 2) / (4 * pi)
We derive with respect to P, and we are left with:
dA = 2 * P / 4 * pi * dP
We know that P = 64 and dP = 0.9, we replace:
dA = 2 * 64/4 * 3.14 * 0.9
dA = 9.17
The error would come being:
dA / A = 9.17 / (64 ^ 2/4 * 3.14) = 0.02811
In other words, the error would be 2.81%
(b) tell us that dA / A <= 0.01
we replace:
[P * dP / 2 * pi] / [P ^ 2/4 * pi] <= 0.01
solving we have:
2 * dP / P <= 0.01
dP / P <= 0.01 / 2
dP / P <= 0.005
Which means that the answer is 0.5%
Suppose f(x)=x^2. Find the graph of f(x-2)
The answer is
Answer:
f(x-2) = (x-2)²
or
f(x-2) = x² -4x + 4
Step-by-step explanation:
Simply plug in (x - 2) into f(x) to find your graph.
Edit (With Picture):
You are moving the graph right 2.
Answer:
Step-by-step explanation:
f(x) = x²
f(x - 2) = (x - 2)²
f(x - 2) = x² - 4x + 4
The grafic is below.
I hope I've helped you.
Graph the function f(x) = 21(0.5)x.
Answer:
is m= 10.5 espero que te ayude
At many golf clubs, a teaching professional provides a free 10-minute lesson to new customers. A golf magazine reports that golf facilities that provide these free lessons gain, on average, $2 comma 1002,100 in green fees, lessons, or equipment expenditures. A teaching professional believes that the average gain is notis not $2 comma 1002,100. Complete parts a through c below. a. In order to support the claim made by the teaching professional, what null and alternative hypotheses should you test? Upper H 0H0: muμ equals= $2 comma 1002,100 Upper H Subscript aHa: muμ not equals≠ $2 comma 1002,100 b. Suppose you select alphaαequals=0.100.10. Interpret this value in the words of the problem. The probablility that the null hypothesis is rejected when the average gain is less than $2 comma 1002,100 is
Answer:
Given:
Mean, u = 2100
A golf magazine reports the mean gain to be $2100, while the teaching professional believes the average gain is not $2100.
Here the null and alternative hypotheses would be:
Null hypothesis:
H0: u = 2100
Alternative hypothesis:
Ha: u ≠ 2100
b) Here, given the level of significance,[tex] \alpha [/tex] as 0.10. This means that:
The probability that the null hypothesis H0 is rejected when average gain is $2100 is 0.10
Please answer this correctly
Answer:
There are 10 teams.
Step-by-step explanation:
Given that the question wants at least 48 swimmers so any numbers above 47 are counted.
In this diagram, there are 10 teams consisting 48 swimmers and above, 48, 52, 53, 63, 76, 79, 82, 84, 85 and 86.
Answer:
10 teams have 48 or more swimmers.
Step-by-step explanation:
If we look at stem 4 there is one team with 48 members.
So counting from there we have:
1 + 2 + 1 + 2 + 4
= 10 teams.
Please answer this correctly
Answer:
9 people
Step-by-step explanation:
37, 39, 41, 46, 61, 63, 69, 77, 80
9 people waited more than 36 minutes.
The 2003 Zagat Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United States. For 15 top-ranking restaurants located in Boston, the average price of a dinner, including one drink and tip, was $48.60. You are leaving on a business trip to Boston and will eat dinner at three of these restaurants. Your company will reimburse you for a maximum of $50 per dinner. Business associates familiar with the restaurants have told you that the meal cost at 5 of the restaurants will exceed $50. Suppose that you randomly select three of these restaurants for dinner.
Required:
a. What is the probability that none of the meals will exceed the cost covered by your company?
b. What is the probability that one of the meals will exceed the cost covered by your company?
c. What is the probability that two of the meals will exceed the cost covered by your company?
d. What is the probability that all three of the meals will exceed the cost covered by your company?
Answer:
a. P(x=0)=0.2967
b. P(x=1)=0.4444
c. P(x=2)=0.2219
d. P(x=3)=0.0369
Step-by-step explanation:
The variable X: "number of meals that exceed $50" can be modeled as a binomial random variable, with n=3 (the total number of meals) and p=0.333 (the probability that the chosen restaurant charges mor thena $50).
The probabilty p can be calculated dividing the amount of restaurants that are expected to charge more than $50 (5 restaurants) by the total amount of restaurants from where we can pick (15 restaurants):
[tex]p=\dfrac{5}{15}=0.333[/tex]
Then, we can model the probability that k meals cost more than $50 as:
[tex]P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{3}{k} 0.333^{k} 0.667^{3-k}\\\\\\[/tex]
a. We have to calculate P(x=0)
[tex]P(x=0) = \dbinom{3}{0} p^{0}(1-p)^{3}=1*1*0.2967=0.2967\\\\\\[/tex]
b. We have to calculate P(x=1)
[tex]P(x=1) = \dbinom{3}{1} p^{1}(1-p)^{2}=3*0.333*0.4449=0.4444\\\\\\[/tex]
c. We have to calcualte P(x=2)
[tex]P(x=2) = \dbinom{3}{2} p^{2}(1-p)^{1}=3*0.1109*0.667=0.2219\\\\\\[/tex]
d. We have to calculate P(x=3)
[tex]P(x=3) = \dbinom{3}{3} p^{3}(1-p)^{0}=1*0.0369*1=0.0369\\\\\\[/tex]
You are building a model sailboat. The plans show that the base of the main sail is 9 cm, the bottom acute angle in the sail is 52°, and the distance between the base of the sail and the deck is 2 cm. What is the height of the mast? a. 12.5 cm b. 11.2 cm c. 13.5 cm d. 11.5 cm
Answer:
c. 13.5 cm
Step-by-step explanation:
In the right triangle formed by the main sail.
Using the trigonometric function
[tex]\tan \theta =\dfrac{\text{Opposite}}{\text{Adjacent}} \\\tan 52^\circ =\dfrac{x}{9} \\x=9 \times \tan 52^\circ\\x=11.52$ cm[/tex]
Therefore:
Height of the mast = 2+11.5=13.5 cm
The height of the mast is 13.5 cm.
what are the possible values of x in 8x^2+4=-1 a. 2+-iroot/3 b. -1+-i/6 c.-1+-i/4 d.1+-i/4 e. 1+-i root 2/4
Answer:
x = ± i sqrt(5/8)
Step-by-step explanation:
8x^2+4=-1
Subtract 4 from each side
8x^2+4-4=-1-4
8x^2 = -5
Divide by 8
8/8x^2=-5/8
x^2 = -5/8
Take the square root of each side
sqrt(x^2) = ±sqrt(-5/8)
x = ±sqrt(-5/8)
x = ±sqrt(5/8) sqrt(-1)
x = ± i sqrt(5/8)
How did the temperature change if: at first it increased by 25 % and then decreased by 40% ?
Please help!!
Answer:
At first it increases by 25%, then you have 1.25x the original temp. A drop of 40% gives you .6 x 1.25, or 75% of the original temperature
Step-by-step explanation:
found that on the web for yuh. I really hope it helped.
Answer:
decreased by 25%
Step-by-step explanation:
Carpetland salespersons average $8000 per week in sales. Steve Contois, the firm's vice president, proposes a compensation plan with new selling incentives. Steve hopes that the results of a trial selling period will enable him to conclude that the compensation plan increases the average sales per salesperson.a. Develop the appropriate null and alternative hypotheses.: - Select your answer -: - Select your answer -b. In this situation, a Type I error would occur if it was concluded that the new compensation plan provides a population mean weekly sales - Select your answer - when in fact it does not.What are the consequences of making this error
Answer:
The null and alternative hypothesis are:
[tex]H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2> 0[/tex]
where μ1 is the population mean sales with compensation plan, and μ2 is the populatiojn mean sales without compensation plan.
A Type I error is made when a true null hypothesis is rejected. In this case, it would be concluded that the compensation plan increases sales, when in fact it does not (at least, not significantly).
The consequences of this error would be that the compensation plan would have evidence to be implemented in the company when in fact it will not bring the results it is expected to have.
Step-by-step explanation:
This hypothesis test will test the claim that the compensation plan increases the average sales per salesperson. This claim will be stated in the alternative hypothesis, and will state that, with the compensation plan, the sales are significantly higher than without the compensation plan.
The null hypothesis, that Steve wants to falsify, will state that the sales will not differ with or withour compensation plan.
We can write this hypothesis as:
[tex]H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2> 0[/tex]
where μ1 is the population mean sales with compensation plan, and μ2 is the populatiojn mean sales without compensation plan.
A Type I error is made when a true null hypothesis is rejected. In this case, it would be concluded that the compensation plan increases sales, when in fact it does not (at least, not significantly).
The consequences of this error would be that the compensation plan would have evidence to be implemented in the company when in fact it will not bring the results it is expected to have. The sales would be expected to increase due to this implementation, and they will not increase, at least, not for the compensation plan.
Based on a poll, 40% of adults believe in reincarnation. Assume that 6 adults are randomly selected, and find the indicated probability. Complete parts (a) through (c) below.
a. What is the probability that exactly 5 of the selected adults believe in reincarnation? Round to 3 decimal places.
b. What is the probability that all of the selected adults believe in reincarnation?
c. What is the probability that at least 5 of the selected adults believe in reincarnation?
Answer:
a. 3.686 %
b. 0.41 %
c. 4.096%
Step-by-step explanation:
We make use of the binomial probability equation, which is as follows:
P = [n! / (n - r)! r!] p ^ r * q ^ (n - r)
where,
n total number samples = 6
r is the selected number, depends on each point (a, b, c)
p is the of believing in reincarnation = 0.40
q = 1 - p = 0.60
to. What is the probability that exactly 5 of the selected adults believe in reincarnation?
So we use r = 5
P = [6! / ((6 - 5)! * 5!)] * [0.40 ^ 5 * 0.60 ^ (6 - 5)]
P = 6 * 0.006144
P = 0.0368 = 3.686%
b. What is the probability that all of the selected adults believe in reincarnation?
So we use r = 6
P = [6! / ((6 - 6)! * 6!)] * [0.40 ^ 6 * 0.60 ^ (6 - 6)]
P = 1 * 0.004096
P = 0.004096 = 0.41%
c. What is the probability that at least 5 of the selected adults believe in reincarnation?
So we use r = 5 to 6
P (r = 5) = [6! / ((6 - 5)! * 5!)] * [0.40 ^ 5 * 0.60 ^ (6 - 5)]
P (r = 5) = 6 * 0.006144
P (r = 5) = 0.0368 = 3.686%
P (r = 6) = [6! / ((6 - 6)! * 6!)] * [0.40 ^ 6 * 0.60 ^ (6 - 6)]
P (r = 6) = 1 * 0.004096
P (r = 6) = 0.004096 = 0.41%
The total is the sum of all:
P (total) = 3.686% + 0.41%
P (total) = 4.096%
1. The Wall Street Journal reported that bachelor’s degree recipients with majors in business average starting salaries of $53,900 in 2012 (The Wall Street Journal, March 17, 2014). The results for a sample of 100 business majors receiving a bachelor’s degree in 2013 showed a mean starting salary of $55,144 with a sample standard deviation of $5,200. Conduct a hypothesis test to determine whether the mean starting salary for business majors in 2013 is greater than the mean starting salary in 2012. Use a = .01 as the level of significance
Answer:
The calculated value t = 4.976 > 2.6264 at 0.01 level of significance
Null hypothesis is rejected
Alternative hypothesis is accepted
The mean starting salary for business majors in 2013 is greater than the mean starting salary in 2012
Step-by-step explanation:
Given Mean of the population μ = $53,900
Given sample size 'n' = 100
Mean of the sample size x⁻ = 55,144
Sample standard deviation 'S' = 5200
Null hypothesis:H₀: There is no difference between the means
Alternative Hypothesis :H₁: The mean starting salary for business majors in 2013 is greater than the mean starting salary in 2012
Test statistic
[tex]t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }[/tex]
[tex]t = \frac{55144-53900}{\frac{5200}{\sqrt{100} } }[/tex]
t = 4.976
Degrees of freedom
ν = n-1 = 100-1 =99
t₀.₀₁ = 2.6264
The calculated value t = 4.976 > 2.6264 at 0.01 level of significance
Null hypothesis is rejected
Alternative hypothesis is accepted
Final answer:-
The mean starting salary for business majors in 2013 is greater than the mean starting salary in 2012
Answer:
We conclude that the mean starting salary for business majors in 2013 is greater than the mean starting salary in 2012.
Step-by-step explanation:
We are given that the Wall Street Journal reported that bachelor’s degree recipients with majors in business average starting salaries of $53,900 in 2012.
A sample of 100 business majors receiving a bachelor’s degree in 2013 showed a mean starting salary of $55,144 with a sample standard deviation of $5,200.
Let [tex]\mu[/tex] = mean starting salary for business majors in 2013.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] [tex]\leq[/tex] $53,900 {means that the mean starting salary for business majors in 2013 is smaller than or equal to the mean starting salary in 2012}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $53,900 {means that the mean starting salary for business majors in 2013 is greater than the mean starting salary in 2012}
The test statistics that would be used here One-sample t-test statistics because we don't know about population standard deviation;
T.S. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean starting salary = $55,144
s = sample standard deviation = $5,200
n = sample of business majors = 100
So, the test statistics = [tex]\frac{55,144-53,900}{\frac{5,200}{\sqrt{100} } }[/tex] ~ [tex]t_9_9[/tex]
= 2.392
The value of t-test statistic is 2.392.
Now, at 0.01 significance level the t table gives a critical value of 2.369 at 99 degree of freedom for right-tailed test.
Since our test statistic is more than the critical value of t as 2.392 > 2.369, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.
Therefore, we conclude that the mean starting salary for business majors in 2013 is greater than the mean starting salary in 2012.