Answer:
The point is neither maximum constructive interference nor perfect destructive interference, the interference is something in between.
Explanation:
Given data in the question;
first we find the wavelength of the sound λ
Then we find the path-length difference to the point from the two speakers, and divide it by the wavelength.
wavelength λ = velocity / frequency = 340 m/s / 1700 Hz = 0.2 m
L1 = 4 m
L2 = √(4² +2² ) m
delta L = L2 - L1 = √(4² +2² ) m - 4 m = 0.472 m
x = deltaL / λ
If the result is nearly an integer, the waves reinforce at the point.
If it is nearly an integer + 0.5, the waves interfere destructively at the point.
If it is neither, the point is "something in between".
so we solve for x
x = 0.472 m / 0.2m
x = 2.36
since its not an integer, it is not point maximum constructive interference
delta L = ( 2x + 1 ).λ/2
x = ((2deltaL/λ) - 1)/2
x = (((2×0.472)/0.2) - 1)/2
x = 3.72 / 2
x = 1.86
Here also, it is not an integer, so it is not a point perfect destructive interference.
Therefore, The point is neither maximum constructive interference nor perfect destructive interference, the interference is something in between.
What is the kinetic energy of a 30 kg dog that is running at a speed of 8.6 m/s (about 19 mi/h)?
Answer:
Uhm thags hsed
Explanation:
Dkrr
You are standing on a street corner with your friend. You then travel 14.0 m due west across the street and into your apartment building. You travel in the elevator 22.0 m upward to your floor, walk 12.0 m north to the door of your apartment, and then walk 6.0 m due east to your balcony that overlooks the street. Your friend is standing where you left her.
Now how far are you from your friend?
Express your answer with the appropriate units.
Answer:
Explanation:
We shall express each displacement vectorially , i for each unit displacement towards east , j for northward displacement and k for vertical displacement .
14 m due west = - 14 i
22.0 m upward in the elevator = 22 k
12 m north = 12 j
6.00 m east = 6 i
Total displacement = - 14 i + 22 k + 12 j + 6 i
D = - 8 i + 12 j + 22 k
magnitude = √ ( 8² + 12² + 22² )
= √ ( 64 + 144 + 484 )
= √ 692
= 26.3 m
Net displacement from starting point = 26.3 m .
1. Two boxes stacked on top of one another weigh 100 kg total. They apply
a friction force of 250N. You apply a force of 300N in the right direction.
What is the total net force and direction of the box?
Answer:
150
Explanation:
Which have the same velocity?
A. A boy walking east at 2 km/h and a man walking east at 4 km/h
B. A car standing still and a truck driving in a circle at 4 km/h
C. A dog walking west at 3 km/h and a cat walking west at 3 km/h
D. A girl walking west at 3 km/h and a boy walking south at 3 km/h
Answer:
answer is b
Explanation:
Consider a 2 m wide and 5 m long slab resting on flat, fixed, earthen bed. The slab is 20 cm thick with uniform properties. You may assume the slab is much longer and wider than it is thick. Write the reduced form of the governing equation for the slab. Clearly identify your coordinate system on a sketch and state your assumptions identifying which terms you are eliminating and why.
Answer:
Explanation:
The coordinate sketch for the system is shown in the attached file below. Also, in the cartesian coordinate system, since the height is less than the length and width, we did neglect the height. Thus, we eliminate the height and converted it to a two-dimension.
A toaster has a resistance of 30 ohms. It draws 2A of current from the outlet. What is the potential difference ?
A. 60v
B. 2v
C. 15v
D.30v
Answer:
60V
Explanation: . V = IR = 1
30*2=60
If a large number of waves pass by a certain point in a given time, the waves have a low frequency. none of the above. a high frequency. it doesn't affect frequency.
Answer:
Another term used to describe a wave is frequency. Since waves are moving, we define frequency as the number of waves that pass a given point in a specified unit of time. The unit commonly used is Hertz which is the number of wave cycles pass a point in one second. So one cycle per second equals one Hertz
Why won’t anyone help me please anybody help me I really need help .
Answer:
1➡️ this is the method of decomposition
2➡️ H2 and O2
3➡️ b
sorry if I am wrong
A man standing on the Earth can exert the same force with his legs as when he is standing on the moon. We know that the mass of the man is the same on the Earth and the moon. We also know that F=ma is true on both the Earth and the moon. Will the man be able to jump higher on the moon than the Earth? Why or why not?
PLEASE HELPPPP
Answer:
yes
Explanation:
earth has gravity force that is high than the moon gravity force which is 1/6 of earth gravity
Earth has gravity force that is high than the moon gravity force which is 1/6 of earth gravity.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The force on the moon is less than earth as gravity is 1/6 on the moon
When man jump than he will jump high on the moon than the earth.
Earth has gravity force that is high than the moon gravity force which is 1/6 of earth gravity.
To learn more about force refer to the link:
brainly.com/question/13191643
#SPJ2
A car company is doing crash tests and has installed forcesensors in the chairs and seatbelts to measure the forces thatare exerted on crash test dummies during a crash. In oneparticular test the sensors measure a horizontal net force onthe dummy of 39,400 N when the car comes to a complete stopfrom an initial speed of 35 m/s in 1.4 m. Treating the dummyas a point particle and assuming it comes to rest in the samedistance, what is the mass of the test dummy used during thistest
Answer:
[tex]m=90.1kg[/tex]
Explanation:
From the question we are told that
Force F=39400
Initial speed [tex]V_1=35m/s[/tex]
Distance[tex]d=1.4m[/tex]
Generally the equation for acceleration is mathematically given by
[tex]a=\frac{V^2-U^2}{2d}[/tex]
[tex]a=\frac{0^2-35^2}{21.4}[/tex]
[tex]a=\frac{0^2-35^2}{21.4}[/tex]
[tex]a=-437.5m/sec^2[/tex]
Generally the equation for mass is mathematically given by
[tex]F=ma\\m=F/a[/tex]
[tex]m=\frac{-39400}{-437.5}[/tex]
[tex]m=90.1kg[/tex]
Besides gravity, what factor keeps the moon and Earth in orbit?
force
inertia
mass
distance
Answer:
interna
Explanation:
please mark as brainllest
A 30kg uniform solid cylinder has a radius of 0.18m. if the cylinder accelerates at 0.023 rad/s^2 as it rotates about an axis through its center, how large is the torque acting on the cylinder? With work please
Answer:
0.011 N-m
Explanation:
Given that
The mass of a solid cylinder, m = 30 kg
The radius of the cylinder, r = 0.18 m
The acceleration of the cylinder, [tex]\alpha =0.023\ rad/s^2[/tex]
It rotates about an axis through its center. We need to find the torque acting on the cylinder. The formula for the torque is given by :
[tex]\tau=I\alpha[/tex]
Where
I is the moment of inertia of the cylinder,
For cylinder,
[tex]I=\dfrac{mr^2}{2}[/tex]
So,
[tex]\tau=\dfrac{mr^2\alpha }{2}\\\\\tau=\dfrac{30\times (0.18)^2\times 0.023 }{2}\\\\\tau=0.011\ N-m[/tex]
So, the required torque on the cylinder is 0.011 N-m.
Orchestra instruments are commonly tuned to match an A-note played by the principal oboe. The Baltimore Symphony Orchestra tunes to an A-note at 440 Hz while the Boston Symphony Orchestra tunes to 442 Hz. If the speed of sound is constant at 343 m/s, find the magnitude of difference between the wavelengths of these two different A-notes. (Enter your answer in m.)
Answer:
Δλ = 3*10⁻³ m.
Explanation:
At any wave, there exists a fixed relationship between the speed of the wave, the wavelength, and the frequency, as follows:[tex]v = \lambda* f (1)[/tex]
where v is the speed, λ is the wavelength and f is the frequency.
Rearranging terms, we can get λ from the other two parameters, as follows:[tex]\lambda = \frac{v}{f} (2)[/tex]
Since v is constant for sound at 343 m/s, we can find the different wavelengths at different frequencies, as follows:[tex]\lambda_{1} =\frac{v}{f_{1}} = \frac{343m/s}{440(1/s)} = 0.779 m (3)[/tex]
[tex]\lambda_{2} =\frac{v}{f_{2}} = \frac{343m/s}{442(1/s)} = 0.776 m (4)[/tex]
The difference between both wavelengths, is just the difference between (3) and (4):[tex]\Delta \lambda = \lambda_{1} - \lambda_{2} = 0.779 m - 0.776m = 3e-3 m (5)[/tex]
⇒ Δλ = 3*10⁻³ m.
inertia is a measure of
a) a push or pull on an object
b) the difficulty of changing an object's motion
c) a velocity of an object
d) none of the above
Answer:
b.. a difficulty of changing an object's motion, that's my ✨ g u e s s ✨
An object is experiencing an acceleration of 12 m/s2 while traveling in a circle of radius 5.0 m. What is its velocity?
Answer:
v = 7.74 m/s
Explanation:
Given that,
The acceleration of the object, a = 12 m/s²
The radius of the circle, r = 5 m
We need to find the velocity of the object. The centripetal acceleration act on the object that is given by :
[tex]a=\dfrac{v^2}{r}\\\\v=\sqrt{ar} \\\\v=\sqrt{12\times 5} \\\\v=7.74\ m/s[/tex]
So, the velocity of the car is 7.74 m/s.
Which equation will tell you the acceleration of the object?
Answer:
In summation, acceleration can be defined as the rate of change of velocity with respect to time and the formula expressing the average velocity of an object can be written as: a =Δ v/ Δt The other 4 equations: d = vit+ (1/2) at2
Explanation:
can someone help me :(
Answer:
1. This is a speed graph.
2. The slope represents how much the item/ thing is moving at how much distance it moved and the minutes it takes it too move how much distance, but the slope is representing the decrease and increase of it.
3. Increasing, kind of rapidly going up since the slope is rising not falling.
Suppose that 6 J of work is needed to stretch a spring from its natural length of 28 cm to a length of 43 cm. (a) How much work is needed to stretch the spring from 33 cm to 38 cm
Answer:
Workdone = 0.67 Joules
Explanation:
Given the following data;
Workdone = 6J
Extension = 43 - 28 = 15cm to meters = 15/100 = 0.15m
The workdone to stretch a string is given by the formula;
Workdone = ½ke²
Where;
k is the constant of elasticity.
e is the extension of the string.
We would solve for string constant, k;
6 = ½*k*0.15²
6 = ½*k*0.0225
Cross-multiplying, we have;
12 = 0.0225k
k = 12/0.0225
k = 533.33N/m
a. To find the workdone when e = 33, 38.
Extension = 38 - 33 = 5 to meters = 5/100 = 0.05m
Workdone = ½*533.33*0.05²
Workdone = 266.67 * 0.0025
Workdone = 0.67 Joules
Therefore, the amount of work (in J) needed to stretch the spring from 33 cm to 38 cm is 0.67.
1) The cause of magnetism is
A. atoms forming “domains” that are arranged randomly
B. atoms forming "domains” that are arranged uniformly
C. atoms forming "dolomites” that are arranged randomly
D. atoms forming “dolomites” that are arranged uniformly
Answer:
I think it's A, I'm not sure though
The floor on a dance hall can take a pressure of 3.5MPa before getting damaged. A lady of mass 60kg wears high heeled shoes. What is the smallest area of the sole of a heel she could wear such that it won't permanently damage the floor
Answer:
smallest area of the heel is 0.000168 m^2
Explanation:
Recall that pressure is defined as: Force / area. Therefore to reach a pressure of 3,500,000 Pa using a force: m * g = 60 kg * 9,8 m/s^2 = 588 N, one needs:
Area = 588 / 3500000 m^2 = 0.000168 m^2
Someone please please please help me with this. I’ll give u whatever rating u want
The vertical forces add up to zero.
The net force on the object is 60N to the right.
F = m • a
60N right = (10kg) • (a)
a = (60N right) / (10kg)
a = 6 m/s^2 to the right
Multi-engine Commercial would be nice.
I need help with this question
Option 3) a Soccer Ball
will travel the farthest distance.
Answer:
a bowling ball
pls follow me and Mark as brainliest and follow me to get free thanks to all your answers
Galileo is considered the father of modern science. Do you agree with this description? Give reasons for your answer.
Answer:
Galileo Galilei pioneered the experimental scientific method and was the first to use a refracting telescope to make important astronomical discoveries
Explanation:
Yes I agree with this. He made significant scientific discoveries that changed the way of life.
A very long, solid cylinder with radius R has positive charge uniformly distributed throughout it, with charge per unit volume r. (a) Derive the expression for the electric field inside the volume at a distance r from the axis of the cylinder in terms of the charge density r. (b) What is the electric field at a point outside the volume in terms of the charge per unit length l in the cylinder
Answer:
Explanation:
From the given information.
The charge density of the cylinder can be computed as:
[tex]\rho = \dfrac{Q_t}{V_t}[/tex]
where:
[tex]Q_t[/tex] = total charge on cylinder
[tex]\rho[/tex] = density of the cylinder
[tex]V_t =[/tex] net volume on cylinder
Considering the charge enclosed by the Gaussian surface; we have:
Q = ρV
Now, determining the volume of the cylinder at a distance r from the axis of the cylinder as follows:
[tex]\int Edsn = \dfrac{q}{\varepsilon_o}[/tex]
Here;
[tex]\hat E \ \ and \ \ \hat n[/tex] are in the same direction;
If we replace [tex]\int Edsn[/tex] with [tex]E ( 2 \pi rl)[/tex] and q with [tex]\rho \pi r^2 l[/tex]; Then:
[tex]E ( 2 \pi rl ) = \dfrac{\rho \pi r^2 l}{\varepsilon _o}[/tex]
By rearrangement;
[tex]E = \dfrac{\rho \pi r^2 l}{ ( 2 \pi rl ) \varepsilon _o}[/tex]
[tex]\mathbf{E = \dfrac{\rho r}{ 2 \varepsilon _o}}[/tex]
(b)
Using the same formula:
[tex]\int Edsn = \dfrac{q}{\varepsilon_o}[/tex]
where;
[tex]\hat E \ \ and \ \ \hat n[/tex] are in the same direction;
If we replace [tex]\int Edsn[/tex] with [tex]E ( 2 \pi rl)[/tex] and [tex]Q_t[/tex] with q;
Then:
[tex]E ( 2 \pi rl ) = \dfrac{Q_t}{\varepsilon _o}[/tex]
[tex]E = \dfrac{Q_t}{( 2 \pi R l ) \varepsilon _o}[/tex]
Replacing [tex]\lambda[/tex] for [tex]\dfrac{Q_t}{l}[/tex].
From above [tex]\lambda[/tex] = the charge per unit length
∴
[tex]\mathbf{E = \dfrac{\lambda}{ 2 \pi R \varepsilon _o}}[/tex]
during what part of their drive are the not moving?
Explain how to identify a starting position on a line.
Answer:
We can easily find out the beginning point of the line by using dot representation. When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system. The vector is a straight line that has a certain end which is fixed to its body.
Position vectors are used to determine the starting position of a line with reference to the origin or starting point of the coordinate system
Position vectors start at the origin and terminate at any arbitrary point.
In terms of position of a line, position vectors depict the exact position of a line from the starting point of the coordinate system.
In terms of direction of the line, the direction of the position vector points from the starting point of the coordinate system towards the given point.
Thus, we can conclude that position vectors are used to determine the starting position of a line with reference to the origin or starting point of the coordinate system.
Learn more here: https://brainly.com/question/20451639
Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
This question is incomplete, the complete question is;
A positive charge of magnitude Q1 = 6.5 nC is located at the origin.
A negative charge Q2 = -3.5 nC is located on the positive x-axis at x = 16.5 cm from the origin. The point P is located y = 10.5 cm above charge Q2.
Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
Answer:
the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C
Explanation:
Given the data in the question;
Q1 = 6.5 nC, Q2 = -3.5 nC
from the image below, to get our angle ∅
tan∅ = opp/adj
tan∅ = 10.5 / 16.5
tan∅ = 0.636363
∅ = tan⁻¹( 0.636363 )
∅ = 32.47°
also, r1 = √( 16.5² + 10.5²)
r1 = √( 272.25 + 110.25 )
r1 = √382.5
r1 = 19.55 cm = 0.1955 m
Now, the x-component of the electric field at point P due to charge Q1 will be;
Ex = E2cos32.47°
= (kQ1/r1²)cos32.47°
we know that; k is Coulomb's law constant ( 9 × 10⁹ N.m²/ C²
Q1 = 6.5 nC = 6.5 × 10⁻⁹ C
so we substitute
= ((9 × 10⁹ × 6.5 × 10⁻⁹) / (0.1955)²) cos32.47°
= (58.5 / 0.03822025) × 0.843672
= 1291.33 N/C
Therefore, the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C
Please answer this question correctly
20 push ups
hope thats correct^^
Which of the following examples, would best represent the input energy and then
'wasted energy forms when watching TV.
A. Chemical, and then heat and electrical.
B. Chemical, and then heat, kinetic, sound
C. Electrical, and light, sound, heat
D. Electrical, and then sound and heat
Answer:
I think the answer is c electrical, and light , sound hewt
how does different color show exist
Answer:Light is made up of wavelengths of light, and each wavelength is a particular colour. The colour we see is a result of which wavelengths are reflected back to our eyes. The visible spectrum showing the wavelengths of each of the component colours. The spectrum ranges from dark red at 700 nm to violet at 400 nm.
Explanation:
hope it helps
Answer:When light hits an object, the object reflects some of that light and absorbs the rest of it. Some objects reflect more of a certain wavelength of light than others. That's why you see a certain colour. For example, a lemon reflects mainly yellow light.
Explanation: