Answer:
Benzene
Explanation:
A denser substance will have a higher or larger mass in the same volume. Therfore benzene will be a denser liquid as the mass is bigger in the same volume compared to ethonal.
You can also work this out by using the density formula which is mass of the substance over the unit of volume.
find weight of 45 kg at height 800 km from earth's surface?
Answer:
The weight is 348.4 N
Explanation:
Effect of the Altitude on the Acceleration of Gravity
The effect of gravity decreases with altitude because greater altitudes mean greater distances from the Earth's center.
The practical formula to calculate the gravity as a function of the altitude h is:
[tex]{\displaystyle g_{h}=g_{0}\left({\frac {R_{\mathrm {e} }}{R_{\mathrm {e} }+h}}\right)^{2}}[/tex]
Where go is the conventional gravitational acceleration = [tex]9.80665\ m/s^2[/tex]
R is the Earth's mean radius at the equator = 6,378 Km
h is the altitude.
At a height of h=800 Km, the acceleration of gravity is:
[tex]{\displaystyle g_{h}=9.80665 m/s^2\left(\frac {6,378 Km }{6,378 Km+800Km}}\right)^{2}}[/tex]
Calculating:
[tex]g_h=7.74\ m/s^2[/tex]
The weight is the product of the acceleration of gravity by the mass of the object, thus:
[tex]W=45\ Kg\cdot 7.74\ m/s^2=348.4\ N[/tex]
The weight is 348.4 N
Why does an object slow down when going uphill
Please explain properly
Answer:
The change in speed on slopes is due to gravity. When going downhill, objects will accelerate (go faster), and when going uphill they will decelerate (slow down). On a flat surface, assuming that there is little friction, they will then maintain a constant speed.
Mark me as BRAINLIEST if this answer helped you!
Which of the above beak depth vs time graphs represent the change in finch beak depth that would occur due to successive years of above average rainfall?
Answer:
A
Explanation:
I just did it :)
Answer:
It is A
Explanation:
I did it and got a 100
On the Moon, astronauts can “bounce” from location to location, but on Earth they cannot move in this way. What physical property changes based on the gravitational force of a planet or moon?
A wagon with a mass of 35 kg is pulled so that it accelerates from 0 m/s to 30 m/s in 15
seconds.
Remember to show all work!
a. What is the acceleration of the wagon?
b. What is the force required to get this acceleration?
Plz help me
Explanation:
a = v-u/t
a is the acceleration of the body
v is the final velocity
u is the initial velocity
t is the time
Given
v = 30m/s
u = 0m/s
t = 15secs
Substitute
a = 30-0/15
a = 30/15
a = 2m/s²
Hence the acceleration of the wagon is 2m/s²
b) Force = mass * acceleration
Given
Mas of the wagon = 35kg
acceleration a = 2m/s²
F = 35*2
F = 70N
Hence the force required to get this acceleration is 70N
a pulling force carried by a rope is called what
Answer:
The pulling force that acts along a stretched flexible connector, such as a rope or cable, is called tension, T. When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.
Explanation:
Why is there no weather on the Moon?
Answer:
the moon has no atmosphere, and it cannot trap heat or insulate the surface.
Explanation:
the moon is too small. ... With weak gravity, gases that are emitted from the surface quickly are lost to outer space.
Which of the following is NOT an undefined term?
A. Line
B. Point
C. Line Segment
D. Plane
A driver of a car traveling at -15m/s applies the brakes, causing a uniform acceleration of +2.0m/s2. If the brakes are applied for 2.5s, what is the velocity of the car at the end of the braking period? How far has the car moved during the braking period?
Given :
Initial velocity, u = -15 m/s.
Acceleration , a = 2 m/s².
Time taken to applied brake, t = 2.5 s.
To Find :
The velocity of the car at the end of the braking period.
How far has the car moved during the braking period.
Solution :
By equation :
[tex]v = u+at\\\\v=-15 + 2\times 2.5\\\\v=-10 \ m/s[/tex]
Now, distance covered by car is :
[tex]s=ut+\dfrac{at^2}{2}\\\\s=(-15)(2.5)+\dfrac{2(2.5)^2}{2}\\\\s=-31.25\ m[/tex]
Hence, this is the required solution.
A jet airliner moving initially at 538 mph (with respect to the ground) to the east moves into a region where the wind is blowing at 937 mph in a direction 23 degrees north of east. What is the new speed of the aircraft with respect to the ground. Answer in units of mph
Answer:
The speed is "1447.576 mph".
Explanation:
The given values are:
Direction (north to east)
= 23°
Wind's speed
= 937 mph
Jet moving at a speed
= 538 mph
Now,
The velocity of jet airliner with respect to the ground will be:
⇒ [tex]v=v_{1}+v_{2}[/tex]
⇒ [tex]v=\sqrt{(538)^2+(987)^2+2(538)(937)\times Cos23^{\circ}}[/tex]
⇒ [tex]=1447.576 \ mph[/tex]
difference between simple machine and complex machine?
Answer:
a simple machine has way less parts than a complex machine like just one pulley or lever. A complex machine has multiple different parts that lead up to one thing being done in the long run.
Explanation:
why can't you run from momentum ?
what is measurement ?
Answer:
Measurement is the assignment of a number to a characteristic of an object or event
Explanation:
Answer:
Measurement is the assignment of a number to a characteristic of an object or event, which can be compared with other objects or event
What is the difference between phi and theta?
A car is traveling 30m/s and slams on the breaks, coming to a complete stop in 5 seconds.
Calculate its acceleration (assuming it was constant). Draw a graph of x-t, v-t and a-t.
Answer:
-6
Explanation:
a=vf-vi/t
vf=0
so that we you subtract vf to vi it will be -30/5=-6
You throw a ball straight up into the air at a velocity of 15 m/s. You want to know how high above your hand the ball will be at exactly 2.5 sec after you released it. You must SHOW ALL WORK to receive credit!!! Of the 5 motion variables - Vi, Vf, a, ΔX, and T, identify which one you are solving for and the magnitudes and directions of all of the others that are known: Which of the motion equations is best to use to determine the height of the ball? How high is the ball above your hand at 2.5 sec after you throw it?
Answer:
6.875mExplanation:
Given
Velocity = 15m/s
Time = 2.5secs
Required
Distance above your hand the ball will be at exactly 2.5secs
using the equation of motion:
ΔX = ViT + 1/2aT²
ΔX is the distance
Vi is the velocity of the ball in air
a is the acceleration due to gravity
T is the time taken
Since the ball is thrown straight up, a = -g
ΔX = ViT - 1/2gT²
Substitute
ΔX = 15(2.5) - 1/2(9.8)(2.5)²
ΔX = 37.5-30.625
ΔX = 6.875m
Hence the ball will be 6.875m above your hand at 2.5secs after you throw it.
How Can the human ear detect the sound
Answer:
Sound waves enter the outer ear and travel through a narrow passageway called the ear canal, which leads to the eardrum. The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear.
Explanation:
The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear. These bones are called the malleus, incus, and stapes.
What charge does Chlorine have after bonding with magnesium
Answer:
A magnesium atom will lose 2 electrons to form a stable 2+ ion. Chlorine is in group 7 of the periodic table. A chlorine atom will gain 1 electron to form a stable 1- ion.
Explanation:
What is the weight of a body at a centre of Earth
draw a diagram of a seismometer showing how the movement of earth is lated into a siesmogram
idk but it seems hard.
Consider a 400g baseball thrown from a height of 1.8m at 35m/s:
a. What is the gravitational potential energy of the baseball?
b. What is the elastic potential energy of the baseball?
c. What is the kinetic energy of the baseball?
d. What is the total mechanical energy of the baseball?
Answer:hhahe
Explanation:
if you go three times around a complete circular lawn of raidius r and reach the starting point, then the displacement is zero. true or false
Answer:
true
Explanation:
the starting point is zero so if you go back to the starting point it'll be zero since displacement is where you left off.
HeLp AsAp!!!!!! How long would it take you to hop 30 meters based on your speed for the 5-meter trial? Show your work!
Hopping =
Distance-5 m
Time-3.41
Speed-1.46
Answer:
20.5s
Explanation:
Given parameters:
Distance = 30m
Unknown:
Time = ?
Solution:
The time it will take to hop a distance of 30m using the speed for the 5m trial is the duration of the trip.
The speed for the 5m trial = 1.46m/s
Now;
Speed = [tex]\frac{distance}{time}[/tex]
Distance = speed x time
time = [tex]\frac{distance }{speed}[/tex]
Input the parameters and solve;
time = [tex]\frac{30}{1.46}[/tex] = 20.5s
Estimate the total mass of ocean on earth
explain the relationship between physics and biology
Answer:
Biology is the study of living organisms. Physics is the study of matter and the laws of nature to understand the behavior of matter and the universe.
A chestnut-colored horse mates with a white-colored horse to produce a roan-colored offspring. What type of inheritance pattern does this genetic expression represent? A. Artificial selection B. Codominance C. Incomplete dominance D. Multiple alleles E. Polygenic inheritance
Answer:
The correct option is B.
Codorminance.
Explanation:
The type of inheritance pattern is codorminance because in codorminance the two alleles in the gene are expressed, no allele was able to masked the express on the other allele. The chestnut colored horse allele is expressed likewise the white
colored allele too is expressed none of the two alleles mask the Expression of the other, the two are expressed to give offsprings roan colored which is an indication of the two expression.
Answer:
Codominance
Explanation:
how does shape of object affect friction
Answer:
There are three types of friction.
1. Slanting friction
2. Sliding friction
3. Rolling friction
In the first two types of friction, the body of the object will come in contact with the irregularities on the surface more than in the case of rolling friction, thus a heavy box in square shape will have more friction than a heavy-duty vehicle.
This is also the reason why all vehicles are having wheels as they reduce friction and makes transportation easier and many people suggest to use a small log of wood to be placed on the bottom of a heavy box with flat bottom so it can moved easily due to reduction of friction
POSSIBLE POINTS: 5
A student throws a ball upward with a force of 50.0 Newtons. The ball reaches a maximum height of 15.0 meters in 2 seconds and then returns back to
his hands. What is the direction of the acceleration at the top?
There is no acceleration at the top
O The acceleration is directed upwards away from the Earth
O The acceleration is directed downwards towards the Earth
O None of the above
Answer:
A
Explanation:
Given that a student throws a ball upward with a force of 50.0 Newtons. The ball reaches a maximum height of 15.0 meters in 2 seconds and then returns back to
his hands.
At maximum height which is the top, the velocity is equal to zero.
According to definition of acceleration, which says; the rate of change of velocity.
Since velocity equal zero, acceleration also will be equal to zero.
Therefore, there is no acceleration at the top.
When an object is said to be in free fall, the object is actually moving..
Problem #2: An apple is thrown upward with an initial velocity of +24.0 m/s. a. Sketch the apple's trip and label what you know. b. How high will the apple go? (Ans: +29.4 m) c. What is the total time needed for the apple to return to its original position? (Ans: 4.90 s)
Answer:
The answer is below
Explanation:
a) The initial velocity (u) = 24 m/s
We can solve this problem using the formula:
v² = u² - 2gh
where v = final velocity, g= acceleration due to gravity = 9.8 m/s², h = height.
At maximum height, the final velocity = 0 m/s
v² = u² - 2gh
0² = 24² - 2(9.8)h
2(9.8)h = 24²
2(9.8)h = 576
19.6h = 576
h = 29.4 m
b) The time taken to reach the maximum height is given as:
v = u - gt
0 = 24 - 9.8t
9.8t = 24
t = 2.45 s
The total time needed for the apple to return to its original position = 2t = 2 * 2.45 = 4.9 s