Find the volume of the cylinder.
1607.7 in 3
2845.7 in 3
6430.7 in 3
401.9 in 3

Answer:

Step-by-step explanation:

3x-11  = x+9

2x = 20

x = 10

Answer:

x=10

Step-by-step explanation:

Answer:

104

Step-by-step explanation:

Just separate the whole thing into two shapes. Multiply the first shape: 12 x 7 = 84

Multiply the second shape: 5 x 4 = 20

Answer:

466.08 m²

Step-by-step explanation:

The figure is composed of a triangle and a semicircle.

Therefore,

Area of the figure = area of the triangle + area of the semicircle

= ½*b*h + ½*πr²

Where,

b = 24 m

h = 20 m

π = 3.14

r = ½ of 24 m = 12 m

Substitute each value into the equation

Area of the figure = ½*24*20 + ½*3.14*12²

= 240 + 226.08

= 466.08 m²

Answer:

im going to guess the last answer. theone that i can't see

Step-by-step explanation:

Answer:

the answer is X=-7

,,,,,

Answer:

it would be x=7

Step-by-step explanation:

brainliest pls

Answer:

The answer is option B. 240

so what was the question again?

Answer:

Step-by-step explanation:

Answer:

D. 8

Step-by-step explanation:

C= 2πr

π= 3.14

C= 25.12

25.12 = 2 * 3.14 * r

r= 4

d= 2r

d= 8

9514 1404 393

Answer:

  720 square feet

Step-by-step explanation:

The lateral area is the area of the central rectangle of the net. It is 12+12+12 = 36 feet long and 20 ft wide.

The lateral area is (36 ft)(20 ft) = 720 ft².

Answer:

[tex]P(X \le 4) = 0.7373[/tex]

[tex]P(x \le 15) = 0.0173[/tex]

[tex]P(x > 20) = 0.4207[/tex]

[tex]P(20\ge x \le 24)= 0.6129[/tex]

[tex]P(x = 24) = 0.0236[/tex]

[tex]P(x = 15) = 1.18\%[/tex]

Step-by-step explanation:

Given

[tex]p = 80\% = 0.8[/tex]

The question illustrates binomial distribution and will be solved using:

[tex]P(X = x) = ^nC_xp^x(1 - p)^{n-x}[/tex]

Solving (a):

Given

[tex]n =5[/tex]

Required

[tex]P(X\ge 4)[/tex]

This is calculated using

[tex]P(X \le 4) = P(x = 4) +P(x=5)[/tex]

This gives:

[tex]P(X \le 4) = ^5C_4 * (0.8)^4*(1 - 0.8)^{5-4} + ^5C_5*0.8^5*(1 - 0.8)^{5-5}[/tex]

[tex]P(X \le 4) = 5 * (0.8)^4*(0.2)^1 + 1*0.8^5*(0.2)^0[/tex]

[tex]P(X \le 4) = 0.4096 + 0.32768[/tex]

[tex]P(X \le 4) = 0.73728[/tex]

[tex]P(X \le 4) = 0.7373[/tex] --- approximated

Solving (b):

Given

[tex]n =25[/tex]

i)

Required

[tex]P(X\le 15)[/tex]

This is calculated as:

[tex]P(X\le 15) = 1 - P(x>15)[/tex] --- Complement rule

[tex]P(x>15) = P(x=16) + P(x=17) + P(x =18) + P(x = 19) + P(x = 20) + P(x = 21) + P(x = 22) + P(x = 23) + P(x = 24) + P(x = 25)[/tex]

[tex]P(x > 15) = {25}^C_{16} * p^{16}*(1-p)^{25-16} +{25}^C_{17} * p^{17}*(1-p)^{25-17} +{25}^C_{18} * p^{18}*(1-p)^{25-18} +{25}^C_{19} * p^{19}*(1-p)^{25-19} +{25}^C_{20} * p^{20}*(1-p)^{25-20} +{25}^C_{21} * p^{21}*(1-p)^{25-21} +{25}^C_{22} * p^{22}*(1-p)^{25-22} +{25}^C_{23} * p^{23}*(1-p)^{25-23} +{25}^C_{24} * p^{24}*(1-p)^{25-24} +{25}^C_{25} * p^{25}*(1-p)^{25-25}[/tex]

[tex]P(x > 15) = 2042975 * 0.8^{16}*0.2^9 +1081575* 0.8^{17}*0.2^8 +480700 * 0.8^{18}*0.2^7 +177100 * 0.8^{19}*0.2^6 +53130 * 0.8^{20}*0.2^5 +12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1 +1 * 0.8^{25}*0.2^0[/tex]  

[tex]P(x > 15) = 0.98266813045[/tex]

So:

[tex]P(X\le 15) = 1 - P(x>15)[/tex]

[tex]P(x \le 15) = 1 - 0.98266813045[/tex]

[tex]P(x \le 15) = 0.01733186955[/tex]

[tex]P(x \le 15) = 0.0173[/tex]

ii)

[tex]P(x>20)[/tex]

This is calculated as:

[tex]P(x>20) = P(x = 21) + P(x = 22) + P(x = 23) + P(x = 24) + P(x = 25)[/tex]

[tex]P(x > 20) = 12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1 +1 * 0.8^{25}*0.2^0[/tex]

[tex]P(x > 20) = 0.42067430925[/tex]

[tex]P(x > 20) = 0.4207[/tex]

iii)

[tex]P(20\ge x \le 24)[/tex]

This is calculated as:

[tex]P(20\ge x \le 24) = P(x = 20) + P(x = 21) + P(x = 22) + P(x =23) + P(x = 24)[/tex]

[tex]P(20\ge x \le 24)= 53130 * 0.8^{20}*0.2^5 +12650 * 0.8^{21}*0.2^4 +2300 * 0.8^{22}*0.2^3 +300 * 0.8^{23}*0.2^2 +25* 0.8^{24}*0.2^1[/tex]

[tex]P(20\ge x \le 24)= 0.61291151859[/tex]

[tex]P(20\ge x \le 24)= 0.6129[/tex]

iv)

[tex]P(x = 24)[/tex]

This is calculated as:

[tex]P(x = 24) = 25* 0.8^{24}*0.2^1[/tex]

[tex]P(x = 24) = 0.0236[/tex]

Solving (c):

[tex]P(x = 15)[/tex]

This is calculated as:

[tex]P(x = 15) = {25}^C_{15} * 0.8^{15} * 0.2^{10}[/tex]

[tex]P(x = 15) = 3268760 * 0.8^{15} * 0.2^{10}[/tex]

[tex]P(x = 15) = 0.01177694905[/tex]

[tex]P(x = 15) = 0.0118[/tex]

Express as percentage

[tex]P(x = 15) = 1.18\%[/tex]

The calculated probability (1.18%) is way less than the advocate's claim.

Hence, we do not believe the claim.

Answer:

hi! how can i help? <3

Step-by-step explanation:

okay i can stand in for you

Answer: 9^ 5

Step-by-step explanation: since there is 5 9’s multiplied by each other, it would be 9 to the 5th power.

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathtt{9\times9\times9\times9\times9}\\\mathtt{= 81\times 81\times9}\\\mathtt{= 6,561\times9}\\\mathtt{= 59,049}\\\mathtt{= 9\times 9\times 9 \times 9 \times 9 \rightarrow 9^5}[/tex]

[tex]\huge\text{Therefore your answer should be:}[/tex]

[tex]\huge\boxed{\mathtt{9^5}}\huge\checkmark[/tex]

[tex]\huge\boxed{\mathtt{Good \ luck \ on \ your \ assignment\ \& \ enjoy}}\\\huge\boxed{\mathtt{your \ day!}}[/tex]

Answer:

29/40

Step-by-step explanation:

1/8 + 3/5 =

We need a common denominator.

8 = 2^3

5 = 5

8 and 5 have no common factors, so the LCD is their product.

LCD = 5 * 8 = 40

1/8 + 3/5 =

= 5/40 + 24/40

= 29/40

Answer:

after the collision cart 1 will stop and cart 2 will keep moving will 0.1.m/s after stop.

Answer:

21 or 23 servings.

Step-by-step explanation:

Answer:

139

Step-by-step explanation:

supplementary angles add up to equal 180

so to find the measure of angle ABC we subtract the given angle from 180

180-41=139

so we can conclude that angle ABC=  139

Step-by-step explanation:

< ABC and < CBD are supplementary angles.

< CBD = 41°

< ABC + < CBD = 180° ( Being supplementary angles)

< ABC + 41° = 180°

< ABC = 180° - 41°

< ABC = 139°

Hope it will help :)❤

Answer:

Aaron must obtain a 96 or higher to achieve the desired score to earn an A in the class.

Step-by-step explanation:

Given that the average of Aaron's three test scores must be at least 93 to earn an A in the class, and Aaron scored 89 on the first test and 94 on the second test, to determine what scores can Aaron get on his third test to guarantee an A in the class, knowing that the highest possible score is 100, the following inequality must be written:

93 x 3 = 279

89 + 94 + S = 279

S = 279 - 89 - 94

S = 96

Thus, at a minimum, Aaron must obtain a 96 to achieve the desired score to earn an A in the class.

Aaron must score atleast 90 marks in third test.

Aaron scores in the first  test = 89

Aaron scores in the second test = 94

And the average of Aaron's three test scores must be at least 93 to earn an A.

Let Aaron scores in the third  test = s

Then,

Average = sum of terms divided by the number of terms.

[tex]\frac{89+94+s}{3} \leq 93\\89+94+s\leq 93\times3\\183+s\leq 279\\s\leq 279-189\\s\leq 90[/tex]

So, Aaron must score atleast 90 marks in third test.

Learn more:https://brainly.com/question/19982277

Answer:

-11

Step-by-step explanation:

[tex]3( - 2) + 5( - 1)[/tex]

[tex] - 6 + ( - 5)[/tex]

[tex] - 11[/tex]

Answer:

14.34mm

Step-by-step explanation:

The formula for the volume of a sphere = 4/3nr³

where

n = 22/7

r = radius

give the volume of the sphere, we can determine the radius

12345 = 4/3 x 22/7 x r³

12345 = 88/21 x r³

divide both sides by 21/88

r³ = 2945.965909

take the cube root of both sides

r = 14.34 mm

Answer:

[tex]\boxed {\boxed {\sf A \approx 3.3 \ in^2}}[/tex]

Step-by-step explanation:

Since we are given the central angle in degrees, we should use the following formula for sector area.

[tex]A= \frac {\theta}{360}* \pi r^2[/tex]

The angle is 42 degrees and the radius is 3 inches. Therefore,

[tex]\theta= 42 \\r=3 \ in[/tex]

[tex]A=\frac {42}{360} * \pi (3 \ in)^2[/tex]

Solve the exponent.

[tex]A=\frac {42}{360} * \pi (9 \ in^2)[/tex]

Multiply all three numbers together.

[tex]A= 0.116666666667* 3.14159265359 * 9 \ in^2[/tex]

[tex]A=3.29867228627 \ in^2[/tex]

Let's round to the tenth place. The 9 in the hundredth place tells us to round the 2 up to a 3.

[tex]A \approx 3.3 \ in^2[/tex]

The area of the sector is approximately 3.3 square inches.

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 22.02

Explanation:

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer:

42

Step-by-step explanation:

¯\_(ツ)_/¯

Answer:

60 tiles left over

Step-by-step explanation:

the lobby needs 30 x 8 = 240 tiles.

she has 6 x 50 = 300 tiles

300 - 240 = 60 left over

Answer:

78.814%

Step-by-step explanation:

mean,  = 480 points.

standard deviation, σ = 100 points.

If 560 is the minimum score, x = 560. We want the % of students who will score BELOW that. Use the formula for z-scores: [tex]z = \frac{x-u}{standard deviation}[/tex] to get the z score: (560-480)/(100) = 0.8.

Using a z-score table: the value under 0.8 is 78.814%.

Answer:

she would be able to buy 6.6

Answer:

its 6.6

Step-by-step explanation:

cause i did that already

Answer:

The annual percentage rate of change for the population of Oregon is of 8.125%.

Step-by-step explanation:

Total percentage change:

Change multiplied by 100 and divided by the initial value.

Change: 8.7 - 4.8 = 3.9 million

Initial value: 4.8

Percentage change: 3.9*100/4.8 = 81.25%

Annual percentage rate of change

81.25% during 10 years(from 2000 to 2010).

So, per year

81.25%/10 = 8.125%

The annual percentage rate of change for the population of Oregon is of 8.125%.

Step-by-step explanation:

Pythagorean Theorem

a^2+b^2=c^2

8^2+15^2=c^2

64+225=c^2

289=c^2

Now square both sides

x=17

Answer:

x = 17

Step-by-step explanation:

[tex]c^{2} = a^{2} + b^{2}[/tex]

[tex]c^{2} = 8^{2} + 15^{2}[/tex]

[tex]c^{2} = 64 + 225[/tex]

[tex]c^{2} = 289[/tex]

[tex]\sqrt{c^2} = \sqrt{289}[/tex]

[tex]c = 17[/tex]