Answer:
11.2
Step-by-step explanation:
11.2 is the only one that looks reasonable if you're considering the length of it lol
The mean temperature for the first 4 days in January was 1°C.
The mean temperature for the first 5 days in January was 3°C.
What was the temperature on the 5th day?
Answer:
Step-by-step explanation:
mean is average, so if we label the first through fifth days of january a-e we can solve it.
So average of the first four is (a+b+c+d)/4 = 1 and the first five is (a+b+c+d+e)/5 = 2. Since it's easy, let's get rid of the fraction in both.
(a+b+c+d)/4 = 1 and (a+b+c+d+e)/5 = 2
a+b+c+d = 4 and a+b+c+d+e = 10
Now, we know a+b+c+d is 4, so we can replace that in the second equation
a+b+c+d+e = 10
4 + e = 10
e = 6
ad since e is the fifth day, we know the temperature of it. Let me know if something here didn't make sense
ANSWER FAST I JUST NEED ANSWER
Answer: 18
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
The graph shows 180 pages on it, and if you go over and down then it shows chapter 18.
Factor y2 - 5y - 1y+ 5 by grouping.
A) (y + 1)(y – 5)
B) (y - 1)(y – 5)
C) (y - 1)(y + 5)
D) (y + 1)(y + 5)
Answer:
C
Step-by-step explanation:
gghiruufkfhfjttyyyyyy
Answer:
the answer is (y-1) (y-5)
Need help with using the graph to find the numbers
Assignment is about evaluating composition of functions from graphs anything helps
Answer:
f(2) = -3
g(-3) = -5
Step-by-step explanation:
----------------------
50 POINTS !!
PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
Plz help me well mark brainliest if correct.....????.
Answer:
12 cubic centimeters
Step-by-step explanation:
So lost. How do I find the area when the height isn’t shown.
Answer:
By taking the height as x most probably
Step-by-step explanation:
What the answer please help me
Answer:
It's c
Step-by-step explanation:
[tex] \sqrt{ {15}^{2} + {8}^{2} } = 17 \\ \sin(x) = \frac{8}{17} \\ \cos(x) = \frac{15}{17} [/tex]
What would you do to solve the system?
System of equations
Click on the correct answer.
12x = 48 - 8y
10x + 8y = 38
?
Add the equations.
12x = 48 - 8y
10x = 38 - By
Subtract the equations.
3. To decide whether to add or subtract,
determine if the values of the
coefficients are the same or opposites:
. If the values are the same, subtract the
equations.
• If the values are opposites or additive
inverses, add the equations.
Remember, you're trying to remove one
variable.
Answer:
To decide whether to add or subtract, determine if the values of the coefficients are the same or opposites:
. If the values are the same, subtract the equations.
• If the values are opposites or additive inverses, add the equations.
Step-by-step explanation:
Given
[tex]12x = 48 - 8y[/tex]
[tex]10x + 8y = 38[/tex]
Required
How to solve
Options (1) and (2) are incorrect because none of the options eliminate x or y.
For option (3),
- Check for the coefficients of x and y
- If they are the same (sign and value), then subtract; otherwise add
For instance:
[tex]12x = 48 - 8y[/tex]
[tex]10x + 8y = 38[/tex]
Rewrite the second equation
[tex]12x = 48 - 8y[/tex]
[tex]10x = 38 - 8y[/tex]
The coefficient of y are the same, so we subtract;
[tex]12x - 10x = 48 - 38 -8y -(-8y)[/tex]
[tex]12x - 10x = 48 - 38 -8y +8y[/tex]
[tex]2x = 10[/tex]
[tex]x= 5[/tex]
See that y has been eliminated
Sarah and all of her siblings have brown hair. She concludes that if her parents have another child, he or she will have brown hair. Is this an example of inductive or deductive reasoning?
a) Deductive.
b) Inductive.
c) Both deductive and inductive.
d) Neither deductive nor inductive.
Answer:
b) Inductive
Step-by-step explanation:
It is correct to say that this is an example of inductive reasoning, because the reasoning is based on a situational perception and not on actual logic. Sarah based her reasoning on a premise that if she and her brothers have brown hair, then if she had another brother, he would also have brown hair.
What is 17% of 13.00
Answer:
The answer is 2.21
Step-by-step explanation:
Answer:
2.21
Step-by-step explanation:
13(.17)
Consider the relationship 5r+8t=10 A. write the relationship as a function r=f(t) B. Evaluate f(-5) C. solve f(t)= 26
Answer:
A) [tex]f(t) = 2 - \frac{8}{5}\cdot t[/tex], B) [tex]f(-5) = 10[/tex], C) [tex]t = -15[/tex] for [tex]f(t) = 26[/tex]
Step-by-step explanation:
A) Let be [tex]f(t) = r[/tex] and [tex]5\cdot r + 8\cdot t = 10[/tex], the latter expression is a function in implicit form and we need to turn it into its explicit form, where [tex]t[/tex] is the independent variable.
[tex]5\cdot r = 10 - 8\cdot t[/tex]
[tex]r = 2 -\frac{8}{5}\cdot t[/tex]
[tex]f(t) = 2 - \frac{8}{5}\cdot t[/tex]
B) If we know that [tex]t = -5[/tex]. then [tex]f(-5)[/tex] is:
[tex]f(-5) = 2 - \frac{8}{5}\cdot (-5)[/tex]
[tex]f(-5) = 10[/tex]
C) If we know that [tex]f(t) = 26[/tex], then we solve for [tex]t[/tex]:
[tex]2 - \frac{8}{5}\cdot t = 26[/tex]
[tex]\frac{8}{5}\cdot t = -24[/tex]
[tex]t = -15[/tex]
In triangle ABC, the complement of < B is < A.
Which statement is not always true?
Answer:
[tex](c)\ \tan B = \sin A[/tex]
Step-by-step explanation:
Given
[tex]\angle A + \angle B = 90[/tex] --- Complement angles
See attachment for complete question
Required
Which is not always true
To do this, we simply test each option
[tex](a)\ \sin A = \cos B[/tex]
The above is always true, if A and B are complements.
Examples are:
[tex]\sin(40) = \cos(50)[/tex]
[tex]\sin(90) = \cos(0)[/tex]
etc
[tex](b)\ \sec A = \csc B[/tex]
The above is always true, if A and B are complements.
The expression can be further simplified as:
[tex]\frac{1}{\cos A} = \frac{1}{\sin B}[/tex]
Cross Multiply
[tex]\sin B = \cos A[/tex]
This is literally the same as (a)
[tex](c)\ \tan B = \sin A[/tex]
The above is not always true, if A and B are complements.
The expression can be further simplified as:
[tex]\frac{\sin B}{\cos B} = \sin A[/tex]
Cross multiply
[tex]\sin B = \sin A * \cos B[/tex]
If A and B are complements. then
[tex]\sin A = \cos B[/tex]
So, we have:
[tex]\sin B = \sin A * \sin A[/tex]
[tex]\sin B = \sin^2 A[/tex]
The above expression is not true, for values of A and B
[tex](d) \cot B = \tan A[/tex]
The above is always true, if A and B are complements.
An example is:
[tex]\cot (55) = \tan (25) = 0.7002[/tex]
etc.
Find the equation of a circle that is centered at the origin and is tangent to the circle (x−6)^2+(y−8)^2=25
Center: ( 6 , 8 )
Radius: 5
Answer:
[tex] x^2 +y^2 = 25 [/tex]
Step-by-step explanation:
Center of the required circle = (0, 0)
Center of the given circle = (6, 8)
Radius of the given circle = 5 units
Distance between the centers of both the circles
[tex] =\sqrt{(6-0)^2 +(8-0)^2} [/tex]
[tex] =\sqrt{(6)^2 +(8)^2} [/tex]
[tex] =\sqrt{36 +64} [/tex]
[tex] =\sqrt{100} [/tex]
[tex] =10\: units [/tex]
Since, required circle is tangent to the given circle with radius 5 units.
Therefore,
Radius of required circle = 10 - 5 = 5 units
Now, Equation of required circle can be obtained as:
[tex] (x - 0)^2 +(y - 0)^2 = 5^2 [/tex]
[tex] (x)^2 +(y)^2 = 25 [/tex]
[tex] x^2 +y^2 = 25 [/tex]
Find the measure of angle QZT.
========================================================
Explanation:
Minor arc QV is 80 degrees because it adds to minor arc VU = 100 to get 80+100 = 180. Note how angle QPU = 180, since it's a straight line and QU is a diameter of the circle.
Add up the minor arcs
TUUVVQto get: 44+100+80 = 224
This means arc TUQ is 224 degrees. Inscribed angle QZT subtends arc TUQ. Use the inscribed angle theorem to say that the inscribed angle is half of the arc it cuts off.
angle QZT = (arc TUQ)/2
angle QZT = 224/2
angle QZT = 112 degrees
Decrease £2123 by 8%
Give your answer rounded to 2 DP
The Decreased amount of £2123 by 8% is approximately; £1953.16
How to find percentage decrease a value?We want to decrease £2123 by 8%.
We can do this by the following formula;
Decreased amount = 2123 * (100% - 8%)
Decreased amount = 2123 * 92%
Decreased amount = £1953.16
Read more about percentage decrease in value at; https://brainly.com/question/11360390
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Can someone plz help with this? Thank you so much.
Answer:
A. 3
Step-by-step explanation:
[tex]y = 3x - 8 \\ at \: (6, \: 1) \\ \frac{dy}{dx} = 3 \\ at \: (x, \: y) \\ gradient = \frac{y - 1}{x - 6} \\ 3 = \frac{y - 1}{x - 6} \\ y - 1 = 3(x - 6)[/tex]
Which group of numbers could be the measures of the sides of a right
triangle?
Answer:
it's B. i individually solved all of them using the pythagorean theorem.
Step-by-step explanation:
"The Pythagorean theorem states that, in a right triangle, the square of the length of the hypotenuse (the side across from the right angle) is equal to the sum of the squares of the other two sides. So if the length of the hypotenuse is c and the lengths of the other two sides are a and b, then c^2 = a^2 + b^2"
sqrt61=6+5
square everything on both sides and ur left with
61=36+25
61=50+11
61=61
boom
Question 3 (4 marks)
A certain retail outlet found that 40% of all customers walking into their store will buy at least one item on
that occasion. Customers make a purchase independently from one another. Calculate the following
probabilities correct to 4 decimal places.
3.1. (2 marks) What is the probability that one or two out of the next four customers will make a purchase?
3.2. (2 marks) What is the probability that at least one out of the next four customers do not make a purchase?
Answer:
3.1 0.6912 = 69.12% probability that one or two out of the next four customers will make a purchase.
3.2 0.9744 = 97.44% probability that at least one out of the next four customers do not make a purchase
Step-by-step explanation:
For each customer, there are only two possible outcomes. Either they make a purchase, or they do not. The probability of a customer making a purchase is independent of any other customer. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
40% of all customers walking into their store will buy at least one item on that occasion.
This means that [tex]p = 0.4[/tex]
4 customers:
This means that [tex]n = 4[/tex]
3.1 What is the probability that one or two out of the next four customers will make a purchase?
This is:
[tex]P(1 \leq X \leq 2) = P(X = 1) + P(X = 2)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 1) = C_{4,1}.(0.4)^{1}.(0.6)^{3} = 0.3456[/tex]
[tex]P(X = 2) = C_{4,2}.(0.4)^{2}.(0.6)^{2} = 0.3456[/tex]
So
[tex]P(1 \leq X \leq 2) = P(X = 1) + P(X = 2) = 0.3456 + 0.3456 = 0.6912[/tex]
0.6912 = 69.12% probability that one or two out of the next four customers will make a purchase.
3.2. What is the probability that at least one out of the next four customers do not make a purchase?
This is:
[tex]P(X \leq 4) = 1 - P(X = 4)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 4) = C_{4,4}.(0.4)^{4}.(0.6)^{0} = 0.0256[/tex]
[tex]P(X \leq 4) = 1 - P(X = 4) = 1 - 0.0256 = 0.9744[/tex]
0.9744 = 97.44% probability that at least one out of the next four customers do not make a purchase
Somebody knows how to do that?
Answer:
p(g) (85 if 3g)
p(g) (135 if 3g)
p(g) (195 if 6g)
lets move p fwd so that 3+3+2 = 8
8 games = 3(85) + 3(135) + 2(195)
= 255 + 405 + 390
= 1050 yards
Statement would be something like > more than 1000 or designed around a division as proof to prove average or mean per game = 1050/8 = 131.25 mean or even the range 405-255 = 150 range whilst the median would be 135
Last question asks '' How many games has James played when he has scored 85 yards? '' The answer would be 1 game can be shown as g or 1g.
Let me know what the statement choices are and I'd be happy to help.
Step-by-step explanation:
Which is an expression in square units that represents the area of the shaded segment of center ofOC
A: 1/4 r^2(3.14-4)
B: 1/4pier^2
C: 1/4pier^2-2r^2
D: 1/2r^2(1/2pie-1)
9514 1404 393
Answer:
D
Step-by-step explanation:
The formula for the area of a segment is ...
A = 1/2r²(θ -sin(θ))
for radius r and central angle θ.
Here, we have θ = π/2, so this becomes ...
A = 1/2r²(π/2 -1) . . . . . matches choice D
An investment of $8500 increases in value by 4.5% every year. How long until the investment reaches about $17323.
Answer:
It would take 16 years and 64 days until the investment reaches about $ 17323
Step-by-step explanation:
Given that an investment of $ 8500 increases in value by 4.5% every year, to determine how long it would take until the investment reaches about $ 17323, the following calculation must be performed:
8,500 x (1 + 0.045 / 1) ^ X = 17,323
8,500 x 1,045 ^ X = 17,323
1,045 ^ X = 17,323 / 8,500
1.045 ^ X = 2.038
1,045 ^ 16,175 = 2,038
X = 16.175
1 = 365
0.175 = X
0.175 x 365 = X
63.875 = X
Therefore, it would take 16 years and 64 days until the investment reaches about $ 17323
if your recipe for minestrone soup call for 3 quart of chicken broth. You have 2 liters. How much more do you need? give answer in quarts.
help me pls I'll give you briliantest if you give me the right answer and no links
Answer:
8
Step-by-step explanation:
your welcome hope this helps :)
Evaluate (3.4x10 4) (4.5x10 3).write your answer in scientific notation
Answer:
1.5×10^8
Step-by-step explanation:
Scientific notation can be regarded as
way to express large or too small numbers conveniently written in decimal form.
Given (3.4x10 4) (4.5x10 3).
To write your in scientific notation
3.4x10^4) (4.5x10^3)
This is multiplication
(3.4x10^4) ×(4.5x10^3)
(3.4x10^4)= 34000
(4.5x10^3)= 4500
Then multiply
4500 × 34000
= 153000000
= 1.5×10^8
help lol -30=5(x+1) x= ?
1.Distribute
-30=5(x+1). x
[tex]-30=5x^{2}+5x[/tex]
2. Move terms to the left side
[tex]-30=5x^{2} +5x[/tex]
[tex]-30-(5x^{2} +5x)=0[/tex]
3. Rearrange terms
[tex]-30-5x^{2} -5x=0[/tex]
[tex]-5x^{2} -5x-30=0[/tex]
Hope this helps! Sorry if I'm wrong
[tex]\huge\text{Hey there!}[/tex]
[tex]\large\text{ORIGINAL EQUATION}\downarrow[/tex]
[tex]\large\textsf{ -30 = 5(x + 1)}[/tex]
[tex]\large\text{TURN the EQUATION}[/tex]
[tex]\large\textsf{5(x + 1) = -30}[/tex]
[tex]\large\text{DISTRIBUTE \textsf{5} WITHIN the PARENTHESES}[/tex]
[tex]\large\textsf{5(x) + 5(1) = -30}[/tex]
[tex]\large\textsf{5(x) = \bf 5x}\\\large\textsf{5(1) = 5}[/tex]
[tex]\rightarrow\large\textsf{5x + 5 = -30}[/tex]
[tex]\large\text{NEW EQUATION: \textsf{5x + 5 = -30}}[/tex]
[tex]\large\text{SUBTRACT \textsf{5} to BOTH SIDES}[/tex]
[tex]\large\textsf{5x + 5 - 5 = -30 - 5}[/tex]
[tex]\large\text{CANCEL out: \textsf{5 - 5} because that gives you \textsf{0}}[/tex]
[tex]\large\text{KEEP: \textsf{-30 - 5} because that helps you solve for your \textsf{x-value}}[/tex]
[tex]\large\textsf{-30 - 5 = \bf -35}[/tex]
[tex]\large\text{NEW EQUATION: \textsf{5x = -35}}[/tex]
[tex]\large\text{DIVIDE \textsf{5} to BOTH SIDES}[/tex]
[tex]\mathsf{\dfrac{5x}{5}= \dfrac{-35}{5}}[/tex]
[tex]\large\text{CANCEL out: }\mathsf{\dfrac{5x}{5}}\large\text{ because that gives you the value of \textsf{1}}[/tex]
[tex]\large\text{KEEP: }\mathsf{\dfrac{-35}{5}}\large\text{ gives you the \textsf{x-value}}[/tex]
[tex]\large\textsf{x = }\mathsf{\dfrac{-35}{5}}[/tex]
[tex]\large\text{SIMPLIFY ABOVE \& YOU HAVE YOUR x-value}[/tex]
[tex]\boxed{\boxed{\large\textsf{ANSWER: \huge \bf x = -7}}}\huge\checkmark[/tex]
[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
NO LINKS, NO OTHER SITES, 100 POINTS
To solve the system of linear equations 3 x minus 2 y = 4 and 9 x minus 6 y = 12 by using the linear combination method, Henry decided that he should first multiply the first equation by –3 and then add the two equations together to eliminate the x-terms. When he did so, he also eliminated the y-terms and got the equation 0 = 0, so he thought that the system of equations must have an infinite number of solutions. To check his answer, he graphed the equations 3 x minus 2 y = 4 and 9 x minus 6 y = 12 with his graphing calculator, but he could only see one line. Why is this? because the system of equations actually has only one solution because the system of equations actually has no solution because the graphs of the two equations overlap each other because the graph of one of the equations does not exist
Answer:
because the graphs of the two equations overlap each other
Step-by-step explanation:
Equations that have an infinite amount of solutions overlap each other when graphed.
This is because equations with an infinite amount of solutions have a similar equation so when graphed you only see one line
Write an equation of the line below in the picture?
Answer:
0,-1, -7-2 is the correct answer
Find the surface area of the sphere.
r = 3 cm
Formulas for Spheres
S.A. = 4tr2
V = grur S.A. = [?] cm2
Round to the nearest tenth.
The surface area of the sphere is 113 square cm
How to determine the surface area?The radius is given as:
r = 3 cm
The surface area is calculated as:
[tex]A = 4\pi r^2[/tex]
So, we have:
[tex]A = 4\pi * 3^2[/tex]
Evaluate the product
A = 113
Hence, the surface area of the sphere is 113 square cm
Read more about surface area at:
https://brainly.com/question/2835293
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Answer: 113
Step-by-step explanation: SA formula is = 4*pi*r^2, input our own values into that, and we get 4*3.14*5^2 = 113.04, round down, and you get 113
Mrs. Nickel puts a variety of wrapped chocolate candies in a bag. There are 5 silver-wrapped candies, 1 purple-wrapped candy, 2 striped candies, and 4 gold-wrapped candies. If 15 students select one candy at a time out of the bag, without looking, and replace the candy after each draw, how many students would be expecting to select a gold-wrapped candy from the bag?
Answer:
5 students would be expecting to select a gold-wrapped candy from the bag.
Step-by-step explanation:
Since Mrs. Nickel puts a variety of wrapped chocolate candies in a bag, and there are 5 silver-wrapped candies, 1 purple-wrapped candy, 2 striped candies, and 4 gold-wrapped candies, if 15 students select one candy at a time out of the bag, without looking, and replace the candy after each draw, to determine how many students would be expecting to select a gold-wrapped candy from the bag, the following calculation must be performed:
5 + 1 + 2 + 4 = 12
4 gold-wrapped candies out of 12 in total
4/12
15 x 4/12 = X
15 x 0.333 = X
5 = X
Therefore, 5 students would be expecting to select a gold-wrapped candy from the bag.