Answer:
x= 5.5
Step-by-step explanation:
(segment piece) x (segment piece) = (segment piece) x (segment piece)
x*4 = 11*2
4x = 22
Divide each side by 4
4x/4 = 22/4
x =5.5
2.
The monthly sales S (in hundreds of units) of baseball equipment for an Internet sporting goods site
are approximated by
77
S=56.9–40.7cos
6
where t is the time in months), with t=1 corresponding to January. Determine the months when
sales exceed 7700 units at any time during the month.
O May through September
O March through August
O March through September
O April through August
O August through April
Answer:
March through August
Step-by-step explanation:
Ok, in order to solve this problem, we must start by building an equation to solve. The original equation was:
[tex]S=56.9-40.7cos (\frac{\pi}{6}t)[/tex]
and we need to figure out the months when the sales exceed 7700 units. Since the equation is given in hundreds of units, we need to divide those 7700 units into one hundred to get 77 hundred units. So we can go ahead and substitute that value in the equation:
[tex]77=56.9-40.7cos (\frac{\pi}{6}t)[/tex]
if you wish you can rewrite the equation so the variable is on the left side of it but it's up to you. So you get:
[tex]56.9-40.7cos (\frac{\pi}{6}t)=77[/tex]
and now we solve for t
[tex]-40.7cos (\frac{\pi}{6}t)=77-56.9[/tex]
[tex]-40.7cos (\frac{\pi}{6}t)=20.1[/tex]
[tex]cos (\frac{\pi}{6}t)=\frac{20.1}{-40.7}[/tex]
[tex]cos (\frac{\pi}{6}t)=-0.4938[/tex]
[tex]\frac{\pi}{6}t=cos^{-1}(-0.4938)[/tex]
[tex]\frac{\pi}{6}t=2.087[/tex]
[tex]t=\frac{2.087(6)}{\pi}[/tex]
[tex]t=3.98 months[/tex]
but there is a second answer to this problem. Notice that the function cos can be 2.87 at [tex]2\pi-2.087=4.1962 rad[/tex] as well, so we repeat the process:
[tex]\frac{\pi}{6}t=4.1962[/tex]
[tex]t=\frac{4.1962(6)}{\pi}[/tex]
[tex]t=8.014 months[/tex]
So now we need to determine on which period of times the number of items sold exceed 77 hundred units so we build different intervals for us to test:
(1,3.98) (3.98,8.014) and (8,014, 13)
and find a test value for each of the intervals and test it.
(1,3.98) t=2
[tex]S=56.9-40.7cos (\frac{\pi}{6}(2))[/tex]
S=36.55
this is less than 77 so this is not our answer.
(3.98,8.014) t=5
[tex]S=56.9-40.7cos (\frac{\pi}{6}(5))[/tex]
S=92.15
this is more than 77 so this is our answer.
(8.014,13) t=10
[tex]S=56.9-40.7cos (\frac{\pi}{6}(10))[/tex]
S=36.55
this is less than 77 so this is not our answer.
so, since our answer is the interval (3.98,8.014)
this means that between the months of march and august we will be sellin more than 7700 units.
A survey showed that among 785 randomly selected subjects who completed four years of college, 144 of them are smokers and 84 do not smoke (based on data from the American Medical Association). Suppose you want to test at the 0.01 significance level the claim that the rate of smoking among those with four years of college is less than the 27% rate for the general population.
A. State the null and alternative hypotheses.
B. Find the sample statistic and the p-value.
C. What is your conclusion?
Answer:
We conclude that the rate of smoking among those with four years of college is less than the 27% rate for the general population.
Step-by-step explanation:
We are given that a survey showed that among 785 randomly selected subjects who completed four years of college, 144 of them are smokers.
Let p = population proportion of smokers among those with four years of college
So, Null Hypothesis, [tex]H_0[/tex] : p [tex]\geq[/tex] 27% {means that the rate of smoking among those with four years of college is more than or equal to the 27% rate for the general population}
Alternate Hypothesis, [tex]H_A[/tex] : p < 27% {means that the rate of smoking among those with four years of college is less than the 27% rate for the general population}
The test statistics that will be used here is One-sample z-test for proportions;
T.S. = [tex]\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }[/tex] ~ N(0,1)
where, [tex]\hat p[/tex] = sample proportion of smokers = [tex]\frac{144}{785}[/tex] = 0.18
n = sample of subjects = 785
So, the test statistics = [tex]\frac{0.18-0.27}{\sqrt{\frac{0.27(1-0.27)}{785} } }[/tex]
= -5.68
The value of z-test statistics is -5.68.
Also, the P-value of the test statistics is given by;P-value = P(Z < -5.68) = Less than 0.0001
Now, at a 0.01 level of significance, the z table gives a critical value of -2.3262 for the left-tailed test.
Since the value of our test statistics is less than the critical value of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.
Therefore, we conclude that the rate of smoking among those with four years of college is less than the 27% rate for the general population.
-36 4/9 - (-10 2/9) -(18 2/9)
Answer: [tex]-44\dfrac{4}{9}[/tex]
Step-by-step explanation:
The given expression: [tex]-36\dfrac{4}{9}-(-10\dfrac{2}{9})-(18\dfrac{2}{9})[/tex]
Here, [tex]36\dfrac{4}{9}=\dfrac{36\times9+4}{9}=\dfrac{328}{9}[/tex]
[tex](10\dfrac{2}{9})=\dfrac{92}{9}\\\\(18\dfrac{2}{9})=\dfrac{9\times18+2}{9}=\dfrac{164}{9}[/tex]
That is
[tex]-36(\dfrac{4}{9})-(-10\dfrac{2}{9})-(18\dfrac{2}{9}) = -\dfrac{328}{9}-(-\dfrac{92}{9})-\dfrac{164}{9}\\\\=-\dfrac{328}{9}+\dfrac{92}{9}-\dfrac{164}{9}\\\\=\dfrac{-328+92-164}{9}\\\\=\dfrac{-400}{9}\\\\=-44\dfrac{4}{9}[/tex]
Write the phrase as an algebraic expression: 3 less than 4 times a number
Answer:
4x-3 is the expression to your question
Answer:
3[tex]\leq[/tex]4x
Step-by-step explanation:
Levi buys a bag of cookies that contains 6 chocolate chip cookies, 9 peanut butter cookies, 8 sugar cookies and 8 oatmeal cookies. What is the probability that Levi reaches in the bag and randomly selects 2 peanut butter cookies from the bag
Answer:
12/155
Step-by-step explanation:
Total number of cookies:
6+9+8+8= 31Probability of getting a peanut butter cookie at first attempt is 9 out of 31:
9/31Probability of getting a peanut butter cookie at second attempt is 8 out of 30 as one already taken and the total number has changed as well:
8/30= 4/15Probability of getting 2 peanut butter cookies is the product of each probability we got above:
9/31×4/15= 12/155Solve for x.
−4x + 60 < 72 OR 14x + 11 < −31
Choose 1 answer:
A) x < -3 or x > -3
B) x > -3
C) x <- 3
D) There are no solutions
E) All values of x are solutions
Answer:
A. x < -3 or x > -3
Step-by-step explanation:
Let's start with the equation -4x + 60 < 72.
-4x + 60 < 72
First using the order of operations, subtract 60 from both sides.
-4x + 60 - 60 < 72 - 60
- 4x < 12
Next we want to divide -4 from both sides to isolate the variable.
-4x/-4 < 12/-4
x > -3
When you divide a negative number, always make sure the change the sign.
Solve the next equation, 14x + 11 < -31, the same way we solved the last.
14x + 11 < -31
Subtract 11 from both sides.
14x + 11 - 11 < -31 -11
14x < -42
Divide 14 from both sides.
14x/14 < -42/14
x < -3
The equations have different signs.
A. x < -3 or x > -3
A United Nations report shows the mean family income for Mexican migrants to the United States is $26,500 per year. A FLOC (Farm Labor Organizing Committee) evaluation of 24 Mexican family units reveals a mean to be $30,150 with a sample standard deviation of $10,560. State the null hypothesis and the alternate hypothesis.
Answer:
The null hypothesis [tex]\mathtt{H_0 : \mu = 26500}[/tex]
The alternative hypothesis [tex]\mathtt{H_1 : \mu \neq 26500}[/tex]
Step-by-step explanation:
The summary of the given statistics is:
Population Mean = 26,500
Sample Mean = 30,150
Standard deviation = 10560
sample size = 24
The objective is to state the null hypothesis and the alternate hypothesis.
An hypothesis is a claim with insufficient information which tends to be challenged into further testing and experimentation in order to determine if such claim is significant or not.
The null hypothesis is a default hypothesis where there is no statistical significance between the two variables in the hypothesis.
The alternative hypothesis is the research hypothesis that the researcher is trying to prove.
The null hypothesis [tex]\mathtt{H_0 : \mu = 26500}[/tex]
The alternative hypothesis [tex]\mathtt{H_1 : \mu \neq 26500}[/tex]
The test statistic can be computed as follows:
[tex]z = \dfrac{\overline X - \mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \dfrac{30150 - 26500}{\dfrac{10560}{\sqrt{24}}}[/tex]
[tex]z = \dfrac{3650}{\dfrac{10560}{4.8989}}[/tex]
[tex]z = \dfrac{3650 \times 4.8989 }{{10560}}[/tex]
z = 1.6933
8. Subtract the polynomials: (3x2 + 5x – 8) – (2x2 - 4x + 3)
please give steps!!
[tex]\\ \sf\longmapsto 3x^2+5x-8-(2x^2-4x+3)[/tex]
[tex]\\ \sf\longmapsto 3x^2+5x-8-2x^2+4x-3[/tex]
[tex]\\ \sf\longmapsto 3x^2-2x^2+5x+4x-8-3[/tex]
[tex]\\ \sf\longmapsto x^2+9x-11[/tex]
Answer:
(3×2+5x-8)-(2×2-4x-3) = (6+5x-8)-(4-4x-3)
= 6+5x-8-4+4x+3
= -3+9x
If θ is an angle in standard position and its terminal side passes through the point (7,-4), find the exact value of
sec
θ
secθ in simplest radical form.
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Answer:
(√65)/7
Step-by-step explanation:
We can use the relation between the secant and the tangent:
sec(θ)² = tan(θ)² +1
sec(θ) = √(1 + (-4/7)²) = √(65/49)
sec(θ) = (√65)/7 . . . . . . secant is positive in the 4th quadrant
. Simplify the expression: 4
2 + 8 ÷ 2.
Answer:
It's C 20
4^2 + 8 divided by 2 = 20
Step-by-step explanation:
point a is at (6,-6) and point c is at (-6, -2)
Find the cooridantes of point b on AC such that AB=3/4 AC
Answer:
(-3,-3)
B=(6-9,6+3)
PLEASE HELP!! WHOEVER GETS IT CORRECT GETS BRAINLIEST!!! By the way, 2 people need to answer so I can mark brainliest.
Answer:
what do you mean ?? i don't understand it con you tell us the question
Help please!!! Thank you
Answer:
Option (G)
Step-by-step explanation:
Let the length of the race = a miles
Since, Speed = [tex]\frac{\text{Distance}}{\text{Time}}[/tex]
Time taken to cover 'a' miles with the speed = 12 mph,
Time taken '[tex]t_1[/tex]' = [tex]\frac{a}{12}[/tex]
Time taken to cover 'a' miles with the speed = 11 mph,
Time taken '[tex]t_2[/tex]' = [tex]\frac{a}{11}[/tex]
Since the time taken by David to cover 'a' miles was 10 minutes Or [tex]\frac{1}{6}[/tex] hours more than the time he expected.
So, [tex]t_2=t_1+\frac{1}{6}[/tex]
[tex]\frac{a}{11}=\frac{a}{12}+\frac{1}{6}[/tex]
[tex]\frac{a}{11}-\frac{a}{12}=\frac{1}{6}[/tex]
[tex]\frac{12a-11a}{132}=\frac{1}{6}[/tex]
a = 22 mi
Therefore, distance of the race = 22 mi
Option (G) is the correct option.
What would be the mass of a cube of tungsten (density of 19.3 g/cm), with sides of
3cm?
Answer:
M= 521.1 g
Step-by-step explanation:
1st. Find the volume of the cube: V=3³=27 cm³
As the weight of V= 1 cm³ cube is 19.3 g the weight of the cube=27 cm³ is
M=27*19.3= 521.1 g
△DOG ~△?
Complete the similarity statement and select the theorem that justifies your answer.
**If they are not similar, select "none" for both parts
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Answer:
nonenoneStep-by-step explanation:
The reduced side ratios, shortest to longest are ...
AC : AT : CT = 8 : 9 : 15
OD : OG : DG = 5 : 6 : 10
These are different ratios, so the triangles are not similar.
A+ Series - Core Mathematics THEORY QUESTIONS Question 1 (SSSCE 2000 Ou 12a) Four angles of a hexagon are 130°, 160°, 112° and 80°. If the remaining angles are equal, find the size of each of them
To solve this question, we have to understand the sum of all angles of a polygon, identify the polygon and doing this, we get that the size of each of the angles are: 119º.
Sum of angles:
The sum of angles of a polygon of n sides is given by:
[tex]S_n = 180(n-2)[/tex]
Hexagon:
6 sides, thus [tex]n = 6[/tex], and:
[tex]S_n = 180(6-2) = 180*4 = 720[/tex]
Angles:
Four are 130°, 160°, 112° and 80°, the other two are equal, so both are x. Then:
[tex]130 + 160 + 112 + 80 + x + x = 720[/tex]
[tex]482 + 2x = 720[/tex]
[tex]2x = 238[/tex]
[tex]x = \frac{238}{2}[/tex]
[tex]x = 119[/tex]
Thus, the size of each of them is of 119º.
For more of the angles of a polygon, you can check https://brainly.com/question/19023938
What is x? Round to the nearest tenth
Answer:
x = 38.7
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp / adj
tan x = 8/10
taking the inverse tan of each side
x = tan ^-1 (8/10)
x=38.65980825
To the nearest tenth
x = 38.7
How to make my answer for 0.70 a fraction
Answer:
0.70 = 7/10
Step-by-step explanation:
Answer:
70/100 or 7/10 (Simplified)
Step-by-step explanation:
0.70 is basically .70 of 1. You can wrote this as a fraction, 70/100. If you divide 70 by 100, it gives you .70.
If you want to simplify it, it becomes 7/10, and if you divide 7 by 10, it also gives you 0.70.
Depends if you want your fraction simplified or not.
have a great day.
Compute the mean and variance of the following probability distribution. (Round your answers to 2 decimal places.) x P(x) 3 .10 11 .30 19 .20 27 .40
Answer:
69.76
Step-by-step explanation:
The mean is the average of the numbers. It can be gotten by adding all the numbers, then divide by how many numbers available.
Variance (σ2) measure the spread between numbers in a data set. That is, it measures how far each number in the set is from the mean .
mean value can be computed using below expression
= ∑x(i)P(x(i))
= 3(0.10)+11(0.30)+19(0.20)+27(0.40)
= 18.2
Therefore, the mean value is 18.2
The variance can be calculated using below expression
variance
= ∑(x(i)-mean)^2 P(x(i))
= (3-18.2)^2 (.10) + (11-18.2)^2 (.30) + (19-18.2)^2 (.20)+(27-18.2)^2(0.40)
= 69.76
Therefore, the variance Vale is 69.76
The volume of a cone varies jointly with the base (area) and the height. The volume is 12.5 ft3 when the base (area) is 15 ft2 and the height is 212 ft. Find the volume of the cone (after finding the variation constant) when the base (area) is 12 ft2 and the height is 6 ft
The volume of the cone, when the base area is 12 ft² and the height is 6 ft, is approximately 24 ft³.
To find the volume of the cone when the base area is 12 ft² and the height is 6 ft, we need to first determine the variation constant relating the volume, base area, and height.
Let's denote the volume of the cone as V, the base area as A, and the height as h. According to the problem, the volume varies jointly with the base area and the height.
Therefore, we can write the following equation:
V = k * A * h
Here k is the variation constant we want to find.
Given one set of values: when A = 15 ft² and h = 2 1/2 ft, V = 12.5 ft³.
Substitute these values into the equation and solve for k:
12.5 ft³ = k * 15 ft² * (2.5 ft)
Now, we can solve for k:
k = 12.5 ft³ / (15 ft² * 2.5 ft)
k = 0.3333 ft
Now that we have the value of the variation constant (k), we can find the volume when A = 12 ft² and h = 6 ft:
V = k * A * h
V = 0.3333 ft * 12 ft² * 6 ft
V = 23.9996 ft³
Therefore, the volume of the cone is 24 ft³.
Learn more about the volume of the cone here:
brainly.com/question/1578538
#SPJ4
The correct question is as follows:
The volume of a cone varies jointly with the base (area) and the height. The volume is 12.5 ft³ when the base (area) is 15 ft² and the height is 2 1/2 ft. Find the volume of the cone (after finding the variation constant) when the base (area) is 12 ft² and the height is 6 ft.
Find all solutions to the equation. 2sin theta - squareroot 3 = 0
Write your answer in radians in terms of pi, and use the "or" button as necessary.
Example: theta = pi/5 + 2 k pi, k element Z or theta = pi/7 + k pi, k element Z
Answer:
[tex]\theta[/tex] =2mπ + π/3 for m ∈ Z.
Step-by-step explanation:
Given the equation [tex]2sin\theta - \sqrt{3} = 0[/tex], we are to find all the values of [tex]\theta[/tex] that satisfies the equation.
[tex]2sin\theta - \sqrt{3} = 0\\\\2sin\theta = \sqrt{3} \\\\sin\theta = \sqrt{3}/2 \\\\\theta = sin{-1} \sqrt{3}/2 \\\\\theta = 60^0[/tex]
General solution for sin[tex]\theta[/tex] is [tex]\theta[/tex] = nπ + (-1)ⁿ ∝, where n ∈ Z.
If n is an even number say 2m, then [tex]\theta[/tex] = (2m)π + ∝ where ∝ = 60° = π/3
Hence, the general solution to the equation will be [tex]\theta[/tex] = 2mπ + π/3 for m ∈ Z.
what are the exponent and coefficient of the expression 4b-^3
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Answer:
exponent: -3coefficient: 4Step-by-step explanation:
The coefficient of a term is its constant multiplier. The exponent is the power to which the base is raised.
The term 4·b^(-3) has an exponent of -3, a base of b and a coefficient of 4.
The exponent is -3; the coefficient is 4.
Answer:
exponent = -3 coefficent = 4
Step-by-step explanation:
Evaluate the expression when x=6 and y=-3.
-x+7y
Answer:
-27
Step-by-step explanation:
Let x = 6 and y = -3
[tex]-(6)+7(-3)\\-6-21\\-27[/tex]
A stegosaurus eats ten twelfths of a plant and then eats two twelfths of the plant later. Estimate how much of the plant the dinosaur ate in all. Explain your thinking.
Answer:
12 Twelfths (12/10)
Step-by-step explanation:
If the dinosaur ate 10 twelfths, then ate 2 twelfths, you need too add that up.
10/12 + 2/12 = 12/10.
The dinosaur ate 12/10 of a plant. (6/5 if needed to simplify)
Hope this helps!
Answer:
0/12
Step-by-step explanation:
The answer is 0/12. We know this because if there are twelve twelfths [12/12] of a plant and the stegosaurus eats ten twelfths [10/12] of a plant then it is 12 - 10 or the fraction form [12/12 - 10/12] then we subtract and we get the answer [2/12]. And then later it says the stegosaurus ate two twelfths [2/12] of a plant then we subtract 2 - 12 or [2/12 - 2/12] that would then equal 0/12.
A tortoise is walking in the desert. It walks 7.5 meters in 3 minutes. What is its speed?
Answer:
Step-by-step explanation:
speed is calculated using formula v=d/t
m= 7.5m
t= 3 min
v=?
v= 7.5m/3min
v= 2.5m/min
Process control and acceptance sampling procedures are most closely related to _____. a. analysis of variance procedures b. hypothesis testing procedures c. interval estimation procedures d. linear regression procedures
Need help please! what is the total length of a 20 mm steel coiled like a spring with a 16 turns and an outer diameter of 600 mm. pitch is 300 mm. Show your solution please coz i don't really know how to do it! thanks
Answer:
L = 29,550 mm (as per BS8110 the length is to the nearest 25)
Step-by-step explanation:
Lets make it so simple and easy.
Let A = 600mm
Let B = 300mm
Let C = 16 as number turns
Let d = 20mm
L = [tex]\sqrt{(3.14 * (600 - 20))^{2} + 300^{2}[/tex] x 16
L = 29,550 mm (as per BS8110 the length is to the nearest 25)
What number when multiplied by itself is 11 greater than the preceding number when it is multiplied by itself
Answer: 5 and 6
Step-by-step explanation:
X^2 - 11 = (X-1)^2
X^2 - 11 = X^2-2X+1
X^2 - X^2 + 2X = 11+1
2X = 12
X = 6
The preceding number is 5
(6)(6)=36 and (5)(5)=25
36-25=11
The number required is 6
Let the number required bee xIf the number is multiplied by itself, it becomes x²
If the result is 11 greater than the preceding number when it is multiplied by itself is expressed as:
x² - 11 = (x - 1)²
x² - 11 = x² - 2x + 1
2x = 11 + 1
2x = 12
x = 6
Hence the number required is 6
Learn more on equation here: https://brainly.com/question/2972832
PLZ HELP ASAP (Algebra)
Answer:
Step-by-step explanation:
Whenever you add two number x and -x and it becomes 0 . IT is the identity property.
Ex:
-1/3 + 1/3 = 0
-1 + 1 = 0
-58 + 58 = 0
Simplify 13 x - 4[ x + (3 - x )].
A.9x-1
B.8x-12
C.13x-12
13x - 4[x + (3 - x)] =
= 13x - 4(x + 3 - x) =
= 13x - 4 · 3 = 13x - 12
C.
Answer:
13x -12
Step-by-step explanation:
13 x - 4[ x + (3 - x )].
Combine like terms inside the brackets
13 x - 4[ 3 -0x]
13x - 4[3]
Multiply
13x -12