Find the solution of the differential equation f' (t) = t^4+91-3/t
having the boundary condition f(1) =1/4

Answers

Answer 1

Answer:

[tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| - \frac{1819}{20}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right  

Equality Properties

Multiplication Property of EqualityDivision Property of EqualityAddition Property of EqualitySubtraction Property of Equality

Algebra I

FunctionsFunction Notation

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Addition/Subtraction]:                                                       [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle f'(t) = t^4 + 91 - \frac{3}{t}[/tex]

[tex]\displaystyle f(1) = \frac{1}{4}[/tex]

Step 2: Integration

Integrate the derivative to find function.

[Derivative] Integrate:                                                                                   [tex]\displaystyle \int {f'(t)} \, dt = \int {t^4 + 91 - \frac{3}{t}} \, dt[/tex]Simplify:                                                                                                         [tex]\displaystyle f(t) = \int {t^4 + 91 - \frac{3}{t}} \, dt[/tex]Rewrite [Integration Property - Addition/Subtraction]:                               [tex]\displaystyle f(t) = \int {t^4} \, dt + \int {91} \, dt - \int {\frac{3}{t}} \, dt[/tex][1st Integral] Integrate [Integral Rule - Reverse Power Rule]:                     [tex]\displaystyle f(t) = \frac{t^5}{5} + \int {91} \, dt - \int {\frac{3}{t}} \, dt[/tex][2nd Integral] Integrate [Integral Rule - Reverse Power Rule]:                   [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - \int {\frac{3}{t}} \, dt[/tex][3rd Integral] Rewrite [Integral Property - Multiplied Constant]:                 [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3\int {\frac{1}{t}} \, dt[/tex][3rd Integral] Integrate:                                                                                 [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| + C[/tex]

Our general solution is  [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| + C[/tex].

Step 3: Find Particular Solution

Find Integration Constant C for function using given condition.

Substitute in condition [Function]:                                                               [tex]\displaystyle f(1) = \frac{1^5}{5} + 91(1) - 3ln|1| + C[/tex]Substitute in function value:                                                                         [tex]\displaystyle \frac{1}{4} = \frac{1^5}{5} + 91(1) - 3ln|1| + C[/tex]Evaluate exponents:                                                                                     [tex]\displaystyle \frac{1}{4} = \frac{1}{5} + 91(1) - 3ln|1| + C[/tex]Evaluate natural log:                                                                                     [tex]\displaystyle \frac{1}{4} = \frac{1}{5} + 91(1) - 3(0) + C[/tex]Multiply:                                                                                                         [tex]\displaystyle \frac{1}{4} = \frac{1}{5} + 91 - 0 + C[/tex]Add:                                                                                                               [tex]\displaystyle \frac{1}{4} = \frac{456}{5} - 0 + C[/tex]Simplify:                                                                                                         [tex]\displaystyle \frac{1}{4} = \frac{456}{5} + C[/tex][Subtraction Property of Equality] Isolate C:                                               [tex]\displaystyle -\frac{1819}{20} = C[/tex]Rewrite:                                                                                                         [tex]\displaystyle C = -\frac{1819}{20}[/tex]Substitute in C [Function]:                                                                             [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| - \frac{1819}{20}[/tex]

∴ Our particular solution to the differential equation is  [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| - \frac{1819}{20}[/tex].

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration

Book: College Calculus 10e


Related Questions

Suppose customers arrive at a single-server ice cream parlor times 3, 6, 15, and 17. Further suppose that it takes the server 7, 9, 6, and 8 minutes, respectively, to serve the four customers. When does customer 4 leave the shoppe

Answers

9514 1404 393

Answer:

  time 33

Step-by-step explanation:

The first customer arrives at time 3, and is finished being served at time 3+7 = 10.

The second customer arrives at time 6, so waits until time 10 to be served. The second customer is finished being served at time 10+9 = 19.

The third and fourth customers arrive at times 15 and 17. The third customer waits until time 19 to be served, and is finished being served at time 19+6 = 25.

The fourth customer waits until time 25 to be served, and is finished being served at time 25+8 = 33.

The fourth customer leaves at time 33.

Type the correct answer in each box. Use numerals instead of words.
Simplify the following polynomial expression.
(5x2 + 133 – 4) - (17:2 + 74 - 19) + (50 – 7)(3x + 1)
1 2 -
+

Answers

Answer:

14

Step-by-step explanation:

The expression for the polynomial is A = 3x² - 10x + 8

What is a polynomial?

Polynomials are mathematical expressions involving variables raised with non-negative integers and coefficients(constants who are in multiplication with those variables) and constants with only operations of addition, subtraction, multiplication and non-negative exponentiation of variables involved.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the polynomial equation be represented as A

Now , the value of A is

A = ( 5x² + 13x - 4 ) - ( 17x² + 7x - 19 ) + ( 5x - 7 ) ( 3x + 1 ) = ax² - bx + c

Let's simplify the left-hand side of the equation using the distributive property and combining like terms:

A = (5x² + 13x - 4) - (17x² + 7x - 19) + (5x - 7)(3x + 1)

A = 5x² + 13x - 4 - 17x² - 7x + 19 + 15x² - 16x - 7

A = 3x² - 10x + 8

Now we have:

a = 3, b = -10, and c = 8

Hence , the final equation is A = 3x² - 10x + 8

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A simple random sample of eight high school students' ACT scores gave the following data: What is a point estimate for μ, the mean test score for the population? a. A point estimate cannot be computed since the data for the whole population are not available. b. 235 c. 29.38 d. 4.84

Answers

Answer: c, is the correct option.

Step-by-step explanation:

The sample mean is the best point estimate for the population mean in a particular study.

Given data of scores: [tex]$\begin{array}{llllllll}27 & 30 & 20 & 29 & 28 & 36 & 34 & 31\end{array}$[/tex]

Sample mean = [tex]\frac{\text{Sum of values}}{\text{Number of values}}[/tex]

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-3/7 (21x - 7)

Answers

Answer:

-9x+3

Step-by-step explanation:

See the steps below:)

if c. p =rs 100, profit =rs 5, then find profit percent​

Answers

Answer:Profit Percent =5%

Step-by-step explanation:

Profit Percent is calculated as =Profit / Cost price x 100

Given that Profit=rs 5

Cost price =rs 100

Profit Percent =rs 5/rs 100 x 100

Profit Percent =5%

There are 8 blue candies, 5 pink candies, 1 white candy, and 6 green candies in a candy jar. You reach in, without looking, and take one. What is the probability that you will choose a green candy? Report your answer as a percent.

Answers

Answer:

30%

Step-by-step explanation:

Find the total number of candies in the jar.

8 + 5 + 1 + 6 = 20

The probability of choosing a green candy is 6/20 = 3/10 = .3 = 30%

Let f (x) = 10/x-4
What is the average rate of change of f (x) from 2 to 8 ?

Enter your response as a decimal.

Answers

Answer:

1.875

Step-by-step explanation:

The rate of change is the derivative of the function.

[tex]f(x) = \frac{10}{x-4}\\\\f'(x)=10\times \frac {d}{dx}\frac{1}{x-4}\\\\f'(x)=\frac{-10}{(x-4)^{2}}\\\\f'(2) = \frac{-10}{(2-4)^{2}} =-2.5\\\\f'(8)= \frac{-10}{(8-4)^{2}} =-0.625\\[/tex]

So, the rate of change is

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Answer:

Hi there! Subscribe to my animations Y0UTUBE channel! Channel name: Let Me Explain Studios. Have a nice day!

Step-by-step explanation:

A regression was run to determine if there is a relationship between hours of tv watched per day (x) and the number of situps a person can do (y).The results of the regression were:y=ax+ba=−1.077b=30.98r2=0.744769r=−0.863Use this to predict the number of situps a person who watches 13.5 hours of TV can do.

Answers

Answer:

The number of situps is: 16.4405

Step-by-step explanation:

Given

[tex]y = ax + b[/tex]

[tex]a =-1.077[/tex]

[tex]b=30.98[/tex]

[tex]r^2 = 0.74476[/tex]

Required

Predict y when [tex]x = 13.5[/tex]

In the result, we have:

[tex]y = ax + b[/tex]

[tex]a =-1.077[/tex]

[tex]b=30.98[/tex]

This implies that:

[tex]y = -1.077x + 30.98[/tex]

To make prediction when [tex]x = 13.5[/tex]

We have:

[tex]y = -1.077*13.5 + 30.98[/tex]

[tex]y = -14.5395 + 30.98[/tex]

[tex]y = 16.4405[/tex]

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Answer:

6

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Explanation:
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The average number of employees that call in sick for the day over the course of a year is 25. The number of employees that call in sick on 12 days are 25, 10, 16, 39, 27, 25, 32, 25, 25, 22, 28, and 14. Enter the sample mean and the population mean in the boxes

Answers

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sample mean (x with the bar on top) =24

Step-by-step explanation:

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Given that is directly proportional to (p-1)2 and p is always positive, find the
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Answers

Answer:

p = 10.8

Step-by-step explanation:

Given that p is directly proportional to (p-1)² and p is always positive, then;

q = k (p-1)²

If q = 30 and p = 7

30 = k(7-1)²

30 = 6²k

30 = 36k

5 = 6k

k = 5/6

To get p when q = 80

q =k (p-1)²

80 = 5/6((p-1)²

480 = 5(p-1)²

480/5 = (p-1)²

(p-1)² = 96

p-1 = √96

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p = 10.8

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Answer:

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4 l 8, 9

5 l 1, 6, 8, 8, 9

6 l 8, 9, 9, 9, 9

7 l 0, 2, 2, 2, 5, 5

8 l 0, 9

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Answers

Answer:

1st pair of complementary angles: ∠c + ∠d

2nd pair of complementary angles: ∠g + ∠h

Step-by-step explanation:

the two solid lines are perpendicular, creating 4 right angles

1st pair of complementary angles: ∠c + ∠d

2nd pair of complementary angles: ∠g + ∠h

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Answer:

x=9

Step-by-step explanation:

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Answer:

d equal 10 this is the answer

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Step-by-step explanation:

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Answer:

7 and 5

Step-by-step explanation:

7+5=12

7-5=2

Marley has marbles of the same size and shape in a bag. There are 2 green, 5
blue, and 3 red marbles in the bag. Marley picks two marbles without looking.
What is the probability he will pick two red marbles?

a) 3/15

b)1/15

c) 3/50

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Answers

Answer:

B.) 1/15

Step-by-step explanation:

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A car is 3 times as old as its tires were when it was as old as the tires Are now.
When it’s tires are as old as the car is now,the car will be a year older than the tires are now.
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Answers

Answer:

Present age of the car = 1.5 years and the tires are 0.5 years old.

Step-by-step explanation:

Let the present age of the car be x years and that of the tires be y years.

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The table represents the balance of Fernando’s loan, y, over a period several months, x. He used technology to create the scatter plot shown and determine the best fit equation to model the data: y = -440.91x + 22,060.70. Determine how long it will take to reach the given balances.

Answers

Answer:

The balance of the loan will be approximately $15,000. - Month 16

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Answer:

A and E

Step-by-step explanation:

B and D is unchangeable, species of bears and types of vegetables that existed in the world never changed.

C only consist of one data, temperature of Chicago at noon yesterday only.

If 4, m & 9 are in continued proportion. Find the value of m.​

Answers

Answer:

M =6

Step-by-step explanation:

T2/T1=T3/T2

M/4=9/m

M^2=36

M=+ or - 6

As m is continued ignore - 6

Then get m =6

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Answers

Answer:

24

Step-by-step explanation:

2b = b+24

2b-b = 24

b = 24

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Answers

The answer is C

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Find the Area of the shaded region. Round your answer to the nearest tenth.

Answers

Answer:

210 ft^2

Step-by-step explanation:

The figure is made up of a rectangle 15 ft by 12 ft and a triangle with base 15 ft and height 4 ft.

A = LW + BH/2

A = (15 ft)(12 ft) + (15 ft)(4 ft)/2

A = 180 ft^2 + 30 ft^2

A = 210 ft^2

Answer:

210ft²

Step-by-step explanation:

Step one, find the area of the square. --->

A= bh (Area equals base times the height)

15×12=180

Step two, find the area of the triangle.

A=bh÷2 (Area equals base times the height divided by 2)

4×15= 60÷2= 30

Step three, add the solutions together

180+30=210

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Answers

Answer:60

Step-by-step explanation:

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Let 0 be an angle such that sec0= -13/12 and cot0<0. Find the exact values of tan0 and sin0.

Answers

Answer:

tan 0 = -2.4

sin 0 = 0.42

Step-by-step explanation:

sec 0 = -13/12 => cos 0 = -12/13

cot 0 < 0 => tan 0 < 0

so, the angle is on second quadrant

=> tan 0 = -12/5 = -2.4

=> sin 0 = 5/12 = 0.42

Answer:

Solution given;

Sec θ=-[tex]\frac{13}{12}[/tex]

cotθ< 0,

It lies in second quadrant.

where sin and cosec is positive.

Now

[tex] \frac{1}{cosθ}=-\frac{13}{12}[/tex]

cosθ=[tex]\frac{12}{13}[/tex]

[tex]\frac{b}{h}[/tex]=[tex]\frac{12}{13}[/tex]

b=12

h=13

By using Pythagoras law

p=[tex] \sqrt{13²-12²}=5 [/tex]

Now

exact values of tan θ=[tex]\frac{p}{b}[/tex]=[tex]\frac{5}{12}[/tex]

since it lies in II quadrant

tan θ=-[tex]\frac{5}{12}[/tex]

and

sinθ=[tex]\frac{p}{h}[/tex]=[tex]\frac{5}{13}[/tex]

since it lies in II quadrant

sin θ=[tex]\frac{5}{13}[/tex]

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