Find the radius of convergence and interval of convergence of the series. (Enter your answer as an improper fraction.) sum_(n = 1)^infinity (7^n (x + 4)^n)/sqrt(n)

Answers

Answer 1

Answer:

L=/x/<1 =x ∈ (-1,1)

Step-by-step explanation:

Find The Radius Of Convergence And Interval Of Convergence Of The Series. (Enter Your Answer As An Improper
Answer 2

To find the radius of convergence and interval of convergence of the series ∑(n = 1 to ∞) [7^n (x + 4)^n / √n], we can use the ratio test. The ratio test states that if the limit of the absolute value of the ratio of consecutive terms is less than 1, the series converges.

Let's apply the ratio test to our series:

|[(7^(n+1) (x + 4)^(n+1)) / √(n+1)] / [(7^n (x + 4)^n) / √n]|

Simplifying and rearranging, we get:|7(x + 4) / √(n+1)|

Taking the limit as n approaches infinity:

lim(n→∞) |7(x + 4) / √(n+1)| = |7(x + 4)|

For the series to converge, |7(x + 4)| must be less than 1. Therefore, we have:

|7(x + 4)| < 1

Solving for x, we get:

-1 < 7(x + 4) < 1

Dividing each inequality by 7, we have:

-1/7 < x + 4 < 1/7

Subtracting 4 from each inequality, we get:

-29/7 < x < -27/7

Thus, the interval of convergence is (-29/7, -27/7), and the radius of convergence is the half-length of the interval, which is 1/7.

Therefore, the series converges for x values within the interval (-29/7, -27/7), and the radius of convergence is 1/7.

To learn more about “convergence” refer to the https://brainly.com/question/17019250

#SPJ11


Related Questions

PLZZZ I NEED HELP I’ll give 20 POINTS
What is the median of the following data set?
(6,3, 9, 1,7)
03
06
08
09

Answers

Answer:

6

Step-by-step explanation:

Arrange the data from smallest to largest

1,3,6,7,9

The median is the middle number

1,3   ,6,   7, 9

The middle number is 6

Simplfy the following expressions:

Answers

Answer:

1st one =  d y^27

2nd one = b 2x^9

Step-by-step explanation:

1st one: since the power is being raised to the power of 3 you multiply the numbers

2nd one: the powers aren't being raised so you add the powers together.

12x^13y^10/6X^4y^10

then dividing for exponents is subtracting them so

2x^9 since y gets canceled out

In an aquarium, there are 7 large fish and 6 small fish. Half of the small fish are red.
One fish is selected at random. Find the probability that it is a small, red fish.
Write your answer as a fraction in simplest form.

Answers

Answer:

3/13

Step-by-step explanation:

There are a total of 13 fish (6+ 7 = 13). There are 3 small, red fish. (1/2 · 6 = 3). Put the number of small, red fish over the total number of fish because the small, red fish is being selected from the entire tank of fish. 3/13 cannot be simplified any further.

Select the expression that is equivalent to (x - 1)2.
O A. x2 - 2x + 2
O B. x2 - x + 2
O C. x2 - x + 1
O D. x2 – 2x + 1

Answers

Answer:

x^2 -2x+1

Step-by-step explanation:

(x - 1)^2

(x-1) * (x-1)

FOIL

first: x^2

outer: -1x

inner: -1x

last: 1

Add together

x^2 -1x-1x+1

Combine like terms

x^2 -2x+1

Answer:

[tex] \boxed{\sf D. \ {x}^{2} - 2x + 1} [/tex]

Step-by-step explanation:

[tex] \sf Expand \: the \: following: \\ \sf \implies {(x - 1)}^{2} \\ \\ \sf \implies (x - 1)(x - 1) \\ \\ \sf \implies x(x - 1) - 1(x - 1) \\ \\ \sf \implies (x)(x) - (1)(x) - (1)(x) - (1)( - 1) \\ \\ \sf \implies {x}^{2} - x - x - ( - 1) \\ \\ \sf \implies {x}^{2} - 2x - ( - 1) \\ \\ \sf \implies {x}^{2} - 2x + 1[/tex]

Use the standard normal table to find P(z ≥ 1.06). Round to the nearest percent.

Answers

Answer:

14%

Step-by-step explanation:

On edge 2020

The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that he must stop at the first signal is 0.36, the analogous probability for the second signal is 0.51, and the probability that he must stop at least one of the two signals is 0.67.What is theprobability that he must stop.
a) At both signals?
b) At the first signal but not at the second one?
c) At exactly on signal?

Answers

Answer:

a) P(X∩Y) = 0.2

b) [tex]P_1[/tex] = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability [tex]P_1[/tex] that he must stop at the first signal but not at the second one can be calculated as:

[tex]P_1[/tex] = P(X) - P(X∩Y)

[tex]P_1[/tex] = 0.36 - 0.2 = 0.16

At the same way, the probability [tex]P_2[/tex] that he must stop at the second signal but not at the first one can be calculated as:

[tex]P_2[/tex] = P(Y) - P(X∩Y)

[tex]P_2[/tex] = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

[tex]P = P_1+P_2\\P=0.16+0.31\\P=0.47[/tex]

PLEASE HELP SOLVE THIS!!!!!

Answers

Answer:

20) -43

21) 25

22)-9

Step-by-step explanation:

20) -6 (-6 + 49)/6 = -43

21) 10 - (-10 - (-1 + 6)) = 25

22) 1 - 10/2 - 5 = -9

Step-by-step explanation:

22

Let's calculate the expression khowing that m= 1 and n = 5

m-[tex]\frac{m+m}{2}[/tex] -nm- [tex]\frac{2m}{2}[/tex]-n m-m-n0-n0-5-5

20

Let's calculate the expression khowing that n= -7 and p= - 6

[tex]\frac{p(p+n^{2}) }{6}[/tex] [tex]\frac{-6(-6+(-7)^{2}) }{6}[/tex][tex]\frac{-6(-6+49)}{2}[/tex] [tex]\frac{-6*43}{6}[/tex] -1*43-43

21

Let's calculate the expression khowing that n = -6 and m = -1 and p = -10

mp-(p-(m-n))mp-(p-m+n)mp-p+m-n(-1)*(-10)-(-10)+(-1)-(-6)10+10-1+620-1+619+625

If we express $2x^2 + 6x + 11$ in the form $a(x - h)^2 + k$, then what is $h$? (ignore the $)

Answers

Answer:

h = - [tex]\frac{3}{2}[/tex]

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

y = 2x² + 6x + 11 ( factor out 2 from the first 2 terms )

   = 2(x² + 3x) + 11

Using the method of completing the square

add/subtract ( half the coefficient of the x- term )² to x² + 3x

y = 2(x² + 2([tex]\frac{3}{2}[/tex] )x + [tex]\frac{9}{4}[/tex] - [tex]\frac{9}{4}[/tex] ) + 11

  = 2(x + [tex]\frac{3}{2}[/tex] )² - [tex]\frac{9}{2}[/tex] + 11

  = 2(x + [tex]\frac{3}{2}[/tex] )² + [tex]\frac{13}{2}[/tex] ← in vertex form

with h = - [tex]\frac{3}{2}[/tex]

If the probability that a randomly chosen college student takes statistics is 0.72, then what is the probability that a randomly chosen college student does not take statistics? Give your answer as a decimal.

Answers

Answer:

0.28

Step-by-step explanation:

If the probability that the student does take statistics is 0.72, then it must mean that the rest of the students will not take statistics.

1 - 0.72 = 0.28

0.28 will be the probability that the student does not take statistics.

Use the function below to find f(4).
f(x)=1/3x4^x


A. 8/3
B.256/3
C.64/3
D.16/3

Answers

Answer:

F(4)=1/3*4^4

F(4)=256/3

Step-by-step explanation:

4^4=256

(1/3)*(256)=

256/3

Simply replace X with 4

Answer:

F(4)=1/3*4^4

F(4)=256/3

Step-by-step explanation:

4^4=256

(1/3)*(256)=

256/3

Suppose that we don't have a formula for g(x) but we know that g(3) = −1 and g'(x) = x2 + 7 for all x.
(a) Use a linear approximation to estimate g(2.95) and g(3.05).
g(2.95) =
g(3.05) =
(b) Are your estimates in part (a) too large or too small? Explain.
A) The slopes of the tangent lines are positive and the tangents are getting steeper, so the tangent lines lie below the curve. Thus, the estimates are too small.
B) The slopes of the tangent lines are positive but the tangents are becoming less steep, so the tangent lines lie below the curve. Thus, the estimates are too small.
C) The slopes of the tangent lines are positive and the tangents are getting steeper, so the tangent lines lie above the curve. Thus, the estimates are too large.
D) The slopes of the tangent lines are positive but the tangents are becoming less steep, so the tangent lines lie above the curve. Thus, the estimates are too large.

Answers

Answer:

g(2.95) ≈ -1.8; g(3.05) ≈ -0.2A) tangents are increasing in slope, so the tangent is below the curve, and estimates are too small.

Step-by-step explanation:

(a) The linear approximation of g(x) at x=b will be ...

  g(x) ≈ g'(b)(x -b) +g(b)

Using the given relations, this is ...

  g'(3) = 3² +7 = 16

  g(x) ≈ 16(x -3) -1

Then the points of interest are ...

  g(2.95) ≈ 16(2.95 -3) -1 = -1.8

  g(3.05) ≈ 16(3.05 -3) -1 = -0.2

__

(b) At x=3, the slope of the curve is increasing, so the tangent lies below the curve. The estimates are too small. (Matches description A.)

Binomial factor of 25x2 + 40xy + 16y2 ?

Answers

Answer:

  (5x +4y)^2

Step-by-step explanation:

The first and last terms are both perfect squares, and the middle term is twice the product of their roots. That means the trinomial is the perfect square trinomial ...

  25x^2 +40xy +16y^2 = (5x +4y)^2

_____

It matches the pattern ...

  a^2 +2ab +b^2 = (a +b)^2

Answer:

(5x +4y)^2

Step-by-step explanation:

Pls help see the picture posted

Answers

I hope this helps you

What is the radius of a circle what circumference is 44cm


A. 42cm
D. 24cm
B. 48cm
C. 12cm​

Answers

Hello!!

Circumference of a circle = 2πr

and

Given, 2πr = 44cm

So,

πr = 44/2 = 22

r = 22 × 7/22

r = 7cm is the answer.

Stay safe and God bless!

- eli <3

Answer:

7 cm

Step-by-step explanation:

Circumference of a circle is 2 π r

2πr = 44

Solve for radius.

r = 44/(2π)

r = 7.002817

Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.
a. Calculate a 95% two-sided confidence interval on the death rate from lung cancer.
b. Using the point estimate of p obtained from the preliminary sample, what sample size is needed to be 95% confident that the error in estimating the true value of p is less than 0.03?
c. How large must the sample be if you wish to be at least 95% confident that the error in estimating p is less than 0.03, regardless of the true value of p?

Answers

Answer:

a) [tex]0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799[/tex]

[tex]0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847[/tex]

The 95% confidence interval would be given by (0.799;0.847)

b) [tex]n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79[/tex]  

And rounded up we have that n=622

c) [tex]n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11[/tex]  

And rounded up we have that n=1068

Step-by-step explanation:

Part a

[tex]\hat p=\frac{823}{1000}=0.823[/tex]

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by [tex]\alpha=1-0.95=0.05[/tex] and [tex]\alpha/2 =0.025[/tex]. And the critical value would be given by:

[tex]z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96[/tex]

The confidence interval for the mean is given by the following formula:  

[tex]\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]

If we replace the values obtained we got:

[tex]0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799[/tex]

[tex]0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847[/tex]

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

[tex] ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]    (a)  

And on this case we have that [tex]ME =\pm 0.03[/tex] and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

[tex]n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}[/tex]   (b)  

And replacing into equation (b) the values from part a we got:

[tex]n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79[/tex]  

And rounded up we have that n=622

Part c

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11[/tex]  

And rounded up we have that n=1068

11- In
how many ways 3 mathematics books, 4 history books ,3
chemisidy books and a biology books can be arranged
on an Shelf so thet all books of the same subjects are
together!​

Answers

Answer:    20,736

Step-by-step explanation:

Math and History and Chemistry and Biology and Subjects

  3!     x        4!        x          3!          x        1!          x        4!       = 20,736

A triangle on a coordinate plane is translated according to the rule T-3,5(x, y). Which is another way to write this rule?
(x, y) - (x - 3, y + 5)
(x, y) - (x-3, y-5)
(x,y) - (x + 3, y-5)
(x, y) = (x + 3, y + 5)

Answers

Answer: Choice A. [tex](x,y) \to (x-3, y+5)[/tex]

Explanation:

The notation [tex]T_{-3,5}(x,y)[/tex]  or means to move any point (x,y) along the vector <-3,5>. Put another way, it says to shift (x,y) three units to the left and five units up. The x portion deals with left or right shifting, the y portion deals with up or down shifting. Since the x portion is negative, we go in the negative direction on the x axis. Y being positive means we move up rather than down.

This all means we end up with the translation rule [tex](x,y) \to (x-3,y+5)[/tex]

As an example, 15,000 Men 18-34 watched program X at 7-8 pm on Monday night. 32,000 Men 18-34 had their TV on during the same time period. There are 200,000 Men 18-34 in the television households in the market. What would be the rating for Men 18-34 for program X? Group of answer choices 47 rating points 7.5 rating points 16 rating points 23.5 rating points

Answers

Answer:

7.5 rating points

Step-by-step explanation:

The computation of the rating for Men 18-34 for program X is shown below:

Given that

Number of men 18 -34 watched a program X = 15,000 = X

Number of men 18 - 34 watched in a same time = 32,000

And, the total households in the market = 200,000 = Y

So, the rating for men 18-34 for program x is

[tex]= \frac{X}{Y}[/tex]

[tex]= \frac{15,000}{200,000}[/tex]

= 7.5 rating points

We simply applied the above formula

Brainliest to whoever gets this correct This word problem has too much information. Which fact is not needed to solve the problem? Tanisha tried to sell all her old CDs at a garage sale. She priced them at $2 each. She put 80 CDs in the garage sale, but she sold only 35 of them. How many did she have left? A. All of the information is needed. B. Tanisha sold the CDs for $2 each. C. Tanisha put 80 CDs in the sale. D. Tanisha sold 35 of the CDs.

Answers

B. tanisha sold the cds for $2 each

Answer:

B. Tanisha sold the CDs for $2 each.

Step-by-step explanation:

Please answer this correctly

Answers

Answer:

Question 2 is the right answer.

Step-by-step explanation:

Answer:

Question 2

Step-by-step explanation:

Temperature in the morning =  2°F  above normal temperature = + 2

Temperature at dinner time = 2° F lower than the morning = -2

+2 - 2 = 0° F

The manufacturer of a certain brand of hot dogs claims that the mean fat content per hot dog is 20 grams. Suppose the standard deviation of the population of these hot dogs is 1.9 grams. A sample of these hot dogs is tested, and the mean fat content per hot dog of this sample is found to be 20.5 grams. Find the probability that the sample mean is at least 20.5 when the sample size is 35.

Answers

Answer:

[tex]z=\frac{20.5-20}{\frac{1.9}{\sqrt{35}}}= 1.557[/tex]

And using the normal standard distribution and the complement rule we got:

[tex]P(z>1.557) =1-P(z<1.557) = 1-0.940 = 0.06[/tex]

Step-by-step explanation:

For this case we define our random variable X as "fat content per hot dog" and we know the following parameters:

[tex]\mu = 20, \sigma =1.9[/tex]

We select a sample of n=35 and we want to find the following probability:

[tex] P(\bar X>20.5)[/tex]

For this case since the sample size is >30 we can use the central limit theorem and we use the z score formula given by:

[tex]z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

Replacing we got:

[tex]z=\frac{20.5-20}{\frac{1.9}{\sqrt{35}}}= 1.557[/tex]

And using the normal standard distribution and the complement rule we got:

[tex]P(z>1.557) =1-P(z<1.557) = 1-0.940 = 0.06[/tex]

Which of the following points is NOT a solution of the inequality y ≥ Ixl + 3?

A. (-3, 0)

B. (-3, 6)

C. (0, 4)​

Answers

Hey there!

To solve this, we need to plug each of our answer options into the inequality and see if it is true. Which ever one doesn't make the inequality true when plugged in is the answer.

OPTION A

(x,y)=(-3,0)

We plug our values into the inequality.

0≥ I-3I+3

You may have noticed the bars surrounding the negative three.. If you didn't know, this is called absolute value. Absolute value is how far the number is from 0 on the number line. -7 is 7 away from 0 on a number line, so the absolute value of -7 is 7. The absolute value of 7 is 7. The absolute value of 0 is 0. Absolute value is signified by these bars. Le'ts finish evaluating.

0≥6

As you can see, zero is not greater than or equal to six. So, option A is false.

Since A is not a solution, we already know that that is the answer, so we don't even need to check B and C. But, we can still evaluate them if you want.

OPTION B

6≥I-3I+3

6≥6

This is true.

OPTION C

4≥I0I+3

4≥3

This is also true.

Therefore, the answer is A. (-3,0)

Have a wonderful day!

Alonzo and Cheryl are both members of a population, and a simple random sample is being conducted. If the chance of Alonzo being selected is 1/2900, what is the chance of Cheryl being selected?

Answers

Answer:

¿Consideras que la gente que discrimina por aspectos como el color de la piel, clase social, por el género, etc., no saben lo que las personas valen y por eso no las valoran?

¿Consideras que la gente que discrimina por aspectos como el color de la piel, clase social, por el género, etc., no saben lo que las personas valen y por eso no las valoran?

Answer: 1/2900

Step-by-step explanation: if they are both in the same population and they are both being randomly selected then they both have the same possibility of being picked

Use a proportion to solve the problem. Round to the nearest tenth as needed.
Triangle in a triangle Find the height of the building. Assume that the height of the person is 5 ft.
104 ft
building
13 ft
5 ft

Answers

Answer:

Height of the building is 40 feet

Step-by-step explanation:

From the figure attached,

Height of the person DE = 5 feet

Let height of the building BC = h feet

Since, ΔABC ~ ΔADE,

Their corresponding sides will be proportional,

[tex]\frac{DE}{BC}=\frac{AD}{AB}[/tex]

[tex]\frac{5}{h}=\frac{13}{104}[/tex]

h = [tex]\frac{104\times 5}{13}[/tex]

h = 40 feet

Therefore, height of the building is 40 feet.

How many meters are in 18,200 milliliter

Answers

Answer:

18.2 :)

Have a great day!!!

i need this fast plz

Answers

Answer:

180-130 = 50 degrees because its same side angle

m<2 = 50

Step-by-step explanation:

the second one m<1 is 105 for the same reason

The monthly starting salaries of students who receive an MBA degree have a standard deviation of $110. What size sample should be selected to obtain a 0.95 probability of estimating the mean monthly income within $20 or less

Answers

Answer:

116.21

Step-by-step explanation:

Using the formula for calculating margin error to tackle the question.

Margin error = [tex]\frac{Z \sigma}{\sqrt{n} }[/tex]

Z is the value at 95% confidence

[tex]\sigma[/tex] is the standard deviation

n is the sample size to be estimated

Since the  mean monthly income is within $20 or less, our margin error will be $20

Given [tex]\sigma[/tex] = $110, Z value at 95% confidence = 1.96 we can calculate the sample side n.

Making n the subject of the formula from the equation above;

[tex]M.E = \frac{Z \sigma}{\sqrt{n} }\\\\\sqrt{n} = \frac{Z \sigma}{M.E } \\\\[/tex]

[tex]n = (\frac{Z \sigma}{M.E })^{2}[/tex]

Substituting the give value into the resulting expression;

[tex]n = (\frac{1.96 * 110}{20})^{2}\\\\n = (\frac{215.6}{20}) ^2\\\\n = 10.78^2\\\\n = 116.21[/tex]

This shows that the sample size that should be selected to obtain a 0.95 probability of estimating the mean monthly income within $20 or less is approximately 116.21

Identify the correct HYPOTHESIS used in a hypothesis test of the following claim and sample data: Claim: "The average annual household income in Warren County is $47,500." A random sample of 86 households from this county is obtained, and they have an average annual income of $48,061 with a standard deviation of $2,351. Test the claim at the 0.02 significance level.

Answers

Answer:

We accept H₀

Step-by-step explanation:

Population mean  μ₀ = 47500

Population standard deviation unknown

Sample size    n = 86   degree of freedom  df = 86 - 1  df = 85

Sample mean    μ = 48061

Sample standard deviation 2,351

The claim implies a two tail test with t-studend distributon

Null  Hypothesis                 H₀               μ  =  μ₀

Alternative Hypothesis      Hₐ               μ  ≠  μ₀      

Confidence Interval  mean α = 0,02     and   α/2  =  0,01

With α/2 and df = 85, from t-table we find  t(c)  critical value

t(c) = 2,3710

We compute t(s) as

t(s)  =  ( μ - μ₀ ) / s /√n

t(s)  = ( 48061 - 47500 )/ 2351/√86

t(s)  = 561 * 9,273 / 2351

t(s) = 2,212

Now we compare t(s) and t(c)

t(s) < t(c)       2,212  < 2,371

Then we are in the acceptance region. We accept H₀

Hurry!! Determine the intervals for which the function shown below is decreasing.

Answers

Answer:

everywhere except between 2 and 5

(between -inf and 2 and between 5 and inf)

Step-by-step explanation:

Tublu buys a cylindrical water tank of height 1.4m and diameter 1.1 to catch rainwater off his roof.he has a full 2 liters tin of paint in his store and decides to paint the tank (not the base) If he uses 25ml to cover 1m^2 will he have enough paint to cover the tank with one layer of paint

Answers

Answer:

  yes

Step-by-step explanation:

The lateral area of a cylinder is ...

  LA = πdh

Putting in the given numbers, we find the area to be ...

  LA = π(1.1 m)(1.4 m) ≈ 4.838 m²

At 25 mL per m², the amount of paint Tublu needs is ...

  (4.838 m²)(25 mL/m²) = 120.95 mL

2 liters is 2000 mL, so Tublu easily has enough paint for one layer.

___

The amount he has is enough for more than 16 coats of paint, so he could paint inside and out with the paint he has.

Answer:

he should.

Step-by-step explanation:

Other Questions
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