Find the principal.
Annual rate of interest = 6.5 \%=6.5%equals, 6, point, 5, percent
Period = 4=4equals, 4 years
Total interest= 1222=1222equals, 1222 rupees

Answer is : 4700

Other ppl be giving me the wrong answer don't trust them lol

Answer:

z₁(s)  = - 1.53

Step-by-step explanation:

a)  Value of  z   or   z₁(s)   area to the right is .9370

 1  -  0.9370  =  0.063

Then if area to the left is   0.063     z₁(s)  = - 1.53

Points J, K and M form a triangle.

In this triangle you are given the angles for JKM (50) and KJM (60)

The 3 inside angles of a triangle need to equal 180.

The third angle JMK would be 180 minus the two given angles:

JMK = 180 - 50 - 60 = 70

JMK = 70 degrees

Answer:

3/20

1/5

Step-by-step explanation:

Sample space :

10 - faced die :

(1, 2, 3, 4,5, 6, 7,8, 9, 10)

Coin = (H, T)

P(H) = 1/2

Multiple of 3 = 3, 6, 9 = 3

P(Multiple of 3) = 3 / 10

P(H and multiple of 3) = 1/2 * 3/10 = 3 /20

2.)

P(tail) = 1/2

Prime numbers = (2, 3, 5, 7) = 4

P(A prime number) = 4 / 10

P(tail and prime number) = 1/2 * 4 /10 = 4 /20 = 1/5

Step-by-step explanation:

DAG = DG

120=120°

DHG + DG =360°

DHG +120° =360°

DHG+120°-120°=360°-120°

DHG°=240°

answer

three

explain hope this helps

Answer:

The number of defective bulbs in the shipment should be around 15, give or take 4.

Step-by-step explanation:

For each bulb, there are only two possible outcomes. Either it is defective, or it is not. The probability of a bulb being defective is independent of any other bulb. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Suppose the probability at a light bulb factory of a bulb being defective is 0.11

This means that [tex]p = 0.11[/tex]

Shipment of 133 bulbs:

This means that [tex]n = 133[/tex]

Mean and standard deviation:

[tex]E(X) = np = 133*0.11 = 14.63[/tex]

[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{133*0.11*0.89} = 3.61[/tex]

Rounding to the nearest integers:

The number of defective bulbs in the shipment should be around 15, give or take 4.

The mean, range, and median will vary if the outlier is eliminated. Options A, B, and C are correct.

The arithmetic mean is a term used to describe the average. It's the ratio of the total number of observations to the sum of the observations.

The data set is;

1,6,8,8,8

Outliers in a dataset or graph are extreme values that stand out significantly from the main pattern of values.

There is an aberration in the graph below, on the far left. The value in January is much lower than the value in the other months.

If the outlier is removed mean, range, and median will changes.

Hence options A, B and C are correct.

To learn more about mean refer:

https://brainly.com/question/13451489

#SPJ2

Answer:

a) 120 possible experimental runs

b) 8 possible experimental runs

c) 0

Step-by-step explanation:

a. For the experiment, there are 6 different temperatures (T), 5 different pressures (P), and 4 different catalysts (C). We can find the total number of combinations using the product rule.

N = T × P × C

N = 6 × 5 × 4 = 120

b) If we use only the lowest temperature, we have T = 1, and if we use the two lowest pressures, we have P = 2. We can find the total number of combinations using the product rule.

N = T × P × C

N = 1 × 2 × 4 = 8

c) If we perform 5 experimental runs with 4 possible catalysts, it is not possible to use a different catalyst each time. At least, 1 catalyst must be repeated twice. Then, the event "a different catalyst is used on each run" has a probability of 0.

Answer:

C. 8/25 - 19/25i

Step-by-step explanation:

Given that:

[tex]\dfrac{4-i}{3+4i}[/tex]

[tex]= \dfrac{(4-i) (3-4i)}{(3+4i)(3-4i)}[/tex]

[tex]= \dfrac{(4-i) (3-4i)}{(3+4i)(3-4i)} \\ \\ =\dfrac{12 -16i -3i+4i^2}{9 - 12i +12i -16i^2} \\ \\ = \dfrac{12-19i+4i^2}{9-16i^2} \\ \\ = \dfrac{8-19i}{25}[/tex]

[tex]=\dfrac{8}{25}- \dfrac{19i}{25}[/tex]

Answer:

3<+2=13 is the answer

Step-by-step explanation:

Answer: The probability that a value is less than 36.8 is 0.9993.

Step-by-step explanation:

Let X be the random variable that normally distributed.

Given: [tex]\mu=32,\sigma=1.5[/tex]

The probability that a value is less than 36.8 = [tex]P(X<36.8)[/tex]

[tex]=P(\frac{X-\mu}{\sigma}<\frac{36.8-32}{1.5})\\\\=P(Z<3.2)\ \ \ [Z=\frac{X-\mu}{\sigma}]\\\\=0.9993[/tex][Using P-value calculator]

Therefore, The probability that a value is less than 36.8 is 0.9993.

Answer:

The length would be 25/5 which is 4.8

Answer:

l=8 or -3

Step-by-step explanation:

You can write this into an equation!

It will be l*(l-5)=24

Now, we can just solve.

We have to expand the equation and so on.

Answer:

y = 5 sin (2x) + 4

Step-by-step explanation:

this is sines function,

the amplitude is [9 - (-1)]/2 = 10/2 = 5

the period is 2πx/π = 2x

the x-axis of actual function is at y = 4

so, the function is :

y = 5 sin (2x) + 4

Answer:

C. √18, √7, 5

Step-by-step explanation:

_____________

Answer:

870,406

Step-by-step explanation:

870,046

Hope this helps

Answer:

b

Step-by-step explanation:

Answer:

B is the correct answer

Hope this helps!! :D

Answer:

Sydney is incorrect

Step-by-step explanation:

We cannot start adding Tanks A and B because they have a different denominator.

So we have to find the Least Common Denominator (LCD)

The LCD is 18 so...

[tex]\frac{2}{3} =\frac{12}{18}[/tex]  

I'm sorry I gtg to class...

Answer:

Step-by-step explanation:

We get to use the simple version of the half life equation:

[tex]N=N_0(\frac{1}{2})^{\frac{t}{H}[/tex] where N is the amount of radioactive element left after a specific number of years,

N0 is the initial amount of the element,

t is the number of years (our unknown), and

H is the Half life of the element. For us,

N is 61

N0 is 70,

t is unknown,

H is 24 years. Filling in:

[tex]61=70(.5)^{\frac{t}{24}[/tex]. We begin by dividing both sides by 70 to get:

[tex].8714285=(.5)^{\frac{t}{24}[/tex] and then take the natural log of both sides:

[tex]ln(.8714285=ln(.5)^{\frac{t}{24}[/tex] which allows us to bring down the exponent to the front on the right side:

[tex]ln(.8714285)=\frac{t}{24}ln(.5)[/tex]. We divide both sides by ln(.5) to get:

[tex].1985457976=\frac{t}{24}[/tex] and then multiply both sides by 24 to get:

t = 4.8 years

[tex]hey \\ 260miles \: in \: 4 \: hours \\ how \: many \: miles \: per \: hour = \\ 260 \div 4 = 65miles[/tex]

Answer:

The hypotenuse measures 8.48 meters.

Step-by-step explanation:

Given that a right isosceles triangle has legs of 6 meters long each, to find the length of the hypotenuse to the nearest tenth of a meter the following calculation must be performed, through the application of the Pythagorean theorem:

6 ^ 2 + 6 ^ 2 = X ^ 2

36 + 36 = X ^ 2

√ 72 = X

8.48 = X

Therefore, the hypotenuse measures 8.48 meters.

Answer:

4. 84.82 6. 7238.23 5. 1415.81 7. 1570.8

Step-by-step explanation:

Answer:

4. 254.47ft^3

5. 4247.43yd^3

6. 21714.69 in^3

7. 4712.39 ft^3

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

C) 86

Step-by-step explanation:

To find the mean you first add all of the numbers together. So you would add 75+90+84+95=344. Then you would divide the sum by the amount if numbers there are. So it would be 344÷4 =86

Hope this helped :)

Answer:

x = 75, 90 , 84, 95

[tex]Mean = \frac{ \sum x}{n}= \frac{75+90+84+95}{4} = 86[/tex]

Answer:

2/8 - 1/5x

1/4 - 1/5x

5/20 - 4/20x

*all possible answers listed above*

Step-by-step explanation:

Are there choices?

Answer:

y = 5/4x - 14

Step-by-step explanation:

Given:

Passes through (8, -4)

Slope (m) = 5/4

Slope-intercept equation:

y - y1 = m(x - x1)

y - (-4) = 5/4(x - 8)

y + 4 = 5/4x - 10

y = 5/4x - 14

y = ( x + 9 )^2 - 2

................................

................................

Answer:

volume = 7/8 cubic units

Step-by-step explanation:

[tex]volume = base \ area \times height = \frac{1}{2} \times \frac {7}{4} = \frac{7}{8} units^3[/tex]