Find the perimeter of ΔABC

Answer:

Option C

Step-by-step explanation:

Answer:

B.

You need to subtract 1 term because you don't include the starting 5

4^10 - 1 =  4^9

You multiply 5 by 4 each time for 9 times so it is 5 x 4^9

Hope this helps

Step-by-step explanation:

Answer:

the 2nd

Step-by-step explanation:

Answer:

c)    [tex]2\frac{23}{30}[/tex]     d)[tex]1\frac{23}{24}[/tex]

7)    a.   [tex]6\frac{3}{11}[/tex]  kg                  b.   [tex]6 \frac{2}{3}[/tex]  cm               c. 20 cm

d.  [tex]9\frac{9}{10}[/tex] kg                  e. 10 g             f. [tex]23 \frac{1}{4}[/tex]  kg

Step-by-step explanation:

c)  [tex]8\frac{2}{3}[/tex]   -   [tex]5\frac{9}{10}[/tex]

First we will change to improper fraction and then solve

[tex]\frac{26}{3} - \frac{59}{10}[/tex]

=  [tex]\frac{260 - 177}{30}[/tex]

= [tex]\frac{83}{30}[/tex]

we will now change to mixed number

= [tex]2\frac{23}{30}[/tex]

d)  [tex]8\frac{1}{8} - 6\frac{1}{6}[/tex]

we will first change it to improper fraction and then solve

= [tex]\frac{65}{8} - \frac{37}{6}[/tex]

= [tex]\frac{390 - 296}{48}[/tex]

= [tex]\frac{94}{48}[/tex]

we can reduce the fraction

=[tex]\frac{47}{24}[/tex]

we will change it mixed number

=[tex]1\frac{23}{24}[/tex]

7)  

a.   [tex]\frac{3}{11}[/tex]   of 23

=  [tex]\frac{3}{11}[/tex]   × 23

=  [tex]\frac{69}{11}[/tex]

=[tex]6\frac{3}{11}[/tex]  kg

b. [tex]\frac{2}{3}[/tex]   of 10 cm

= [tex]\frac{2}{3}[/tex]   × 10 cm

= [tex]\frac{20}{3}[/tex]  cm

=[tex]6 \frac{2}{3}[/tex]  cm

c. [tex]\frac{5}{6}[/tex]   of 24cm

=    [tex]\frac{5}{6}[/tex]   × 24 cm

6 will divide 24

=5 × 4 cm

= 20 cm

d.  [tex]\frac{3}{10}[/tex]  of  33 kg

=  [tex]\frac{3}{10}[/tex]  ×  33 kg

=[tex]\frac{99}{10}[/tex]  kg

=[tex]9\frac{9}{10}[/tex] kg

e. [tex]\frac{2}{7}[/tex]   of  35 g

=  [tex]\frac{2}{7}[/tex]   ×  35 g

7 will go into 35

=2×5 g

=10 g

f. [tex]\frac{3}{4}[/tex]  of  31 kg

= [tex]\frac{3}{4}[/tex]  ×  31 kg

=[tex]\frac{93}{4}[/tex] kg

=[tex]23 \frac{1}{4}[/tex]  kg

Answer:

0.

Step-by-step explanation:

Fair dice are dice that have 6 sides, and the probability of rolling a side is the same as rolling another.

Since each die has 6 sides, the most you can get from the two dice are 6 + 6 = 12. Therefore, getting a 13 is impossible. So, there is a probability of 0.

Hope this helps!

Answer: A. Only A

Step-by-step explanation:

A has exactly one output for every input but B has different outputs for an input.

Answer:

proof

Step-by-step explanation:

Statements

Reasons

<2 is congruent to <5; Segment AB is congruent to Segment DE

Given

<3≅<4

Vertical angle theorem

ΔCDB≅ΔCAE

AAS

Segment BC is congruent to Segment EC

CPCTC

The segment BC is congruent to segment EC and this can be proven by using the properties of a triangle and the given data.

Given :

The following steps can be used in order to prove that segment BC is congruent to segment EC:

Step 1 - Using the triangle properties it can be proven that segment BC is congruent to segment EC.

Step 2 - According to the vertical angle theorem, angle 3 is congruent to angle 4.

Step 3 - Now, according to the AAS (Angle Angle Side) postulate, triangle CDB is similar to triangle CAE.

Step 4 - So, according to the CPCTC, segment BC is congruent to segment EC.

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Answer:

1/3000

Step-by-step explanation:

3 meters to centimeters:

3 × 100 = 300

= 1/10 ÷ 300

= 1/10/300

= 1/(10×300)

= 1/3000

Answer:

Step-by-step explanation:

surface area of cylinder=2 πr²+2πrh

=2πr(r+h)

=2π×12(12+18)

=24π×30

=720π

≈2261.9 cm²

Answer:

\the zeroes are (2√3)/ 3, (√3)/4,

or -1.15, 0.43 to the nearest hundredth.

Step-by-step explanation:

I am assuming you want to find the zeroes of this function:

4√3 x^2+5x-2√3 = 0

Using the quadratic formula:

x = [ -5 +/- √((5)^2 - 4 * 4√3  * -2√3) ]  / (2 * 4√3 )

=  ( - 5 +/- √(25 - (-32*3)) / 8√3

= (-5 +/- √ 121) / 8√3

= (-5 - 11) / 8√3 or  (-5 + 11) / 8√3

=  -16/8√3 or 6/8√3

= -16√3/ 24 or  6√3 / 24

= -2√3/ 3 or √3/4.

Answer:

Step-by-step explanation:

We can use the intercept form of the equation of a line, then solve for y.

Intercept form

  x/(x-intercept) +y/(y-intercept) = 1

  x/-4 +y/8 = 1

__

Solving for y, we have ...

  -2x +y = 8 . . . . multiply by 8

  y = 2x +8 . . . .  add 2x

The coefficient of x is 2, so the slope is 2.

__

The graph shows you the rise is 8 for a run of 4, so ...

  slope = rise/run = 8/4

  slope = 2

Answer:

value of x=9

so value of large number is 90 and smaller number is 9

Answer:

1620

Step-by-step explanation:

If a number decreased by 95% is 81, then

5% is 81.

So, the number = 100/5 x 81= 20 x 81 = 1620

Hope this helps

Answer:

the answer is 1620

Step-by-step explanation:

Answer:

-7, -4, 3

Step-by-step explanation:

Tn = 2n² - 3n - 6

Answer:

w = 77°

Step-by-step explanation:

From the picture attached,

WXYZ is a quadrilateral having 4 interior angles,

m∠y = 90°

Therefore, (2x - 10) = 90°

2x = 90 + 10

2x = 100

x = 50

Now, m∠z = (x + 15)° = 65°

m∠x = (3x - 22)° = 150 - 22

                          = 128°

Sum of interior angles of a polygon = (n - 2)×180°

where n = Number of sides of the polygon

If n = 4,

m∠u + m∠x + m∠y + m∠z = (4 - 2) × 180°

w + 128 + 90 + 65 = 360

w = 360 - 283

w = 77°

Therefore, measure of w = 77°

Answer:

x=23/3

Step-by-step explanation:

x=c+ay

7=c+3a     | *(-1)

9=c+6a

-7=-c-3a

9=c+6a

------------

9-7=c-c+6a-3a

2=3a

a=2/3

7=c+3*2/3

7=c+2

-2   -2

5=c

so   x=5+2/3*y

when y=4 then  x=5+2/3*4=5+8/3

x=15/3+8/3

x=23/3

Answer:

Point used by Harold was:

(7, 0)

Step-by-step explanation:

Given that

Equation of linear function used by Harold:

[tex]y = 3(x - 7)[/tex]

We know that linear equation in point slope form can be represented as:

[tex]y - y_1 = m(x - x_1)[/tex]

Where [tex](x_1,y_1)[/tex] are the coordinates of a given point.

[tex]m[/tex] is the slope of line.

Formula for Slope, m is given as:

[tex]m = \dfrac{y_2-y_1}{x_2-x_1}[/tex]

Where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are the two points on the line.

If slope and a point with coordinates [tex](x_1,y_1)[/tex] is know, the equation of a line can be represented in linear form as:

[tex]y - y_1 = m(x - x_1)[/tex] ....... (1)

Now, the given equation is:

[tex]y = 3(x - 7)[/tex]

Re-writing the equation with a slight modification:

[tex]y-0 = 3(x - 7)[/tex]

Now, comparing the above equation with equation (1):

We get that:

[tex]x_1=7\\y_1=0[/tex]

So, the point used by Harold is (7, 0).

Answer:

(7,0)

Step-by-step explanation:

Answer:

5pi/3

Step-by-step explanation:

For two angles to be co-terminal, one must differ from the other by a multiple of 2pi.

The angle of consideration is 5pi/3

Let us consider the options one by one and see if they differ from the angle of consideration by a multiple of 2pi.

5pi/3 - pi/3 = 4pi/3

5pi/3 - 2pi/3 = 3pi/3 = pi

5pi/3 - 4pi/3 = pi/3

5pi/3 - 5pi/3 = 0 = 0(2pi)

5pi/3 is co-terminal with itself

Answer:

Rectangular area attached to the back of the building

two sides of legth 7 m and one side of 14 m

Step-by-step explanation:

We need to compare quantity of fencing material to be used in both cases

1.Option

A = 100 m²          dimensions of storage area  "x"    and "y"

x*y = 100     y = 100/x

The perimeter of the storage area is

p = 2*x + 2*y       ⇒ p = 2*x + 2*100/x

p(x) = 2*x + 200/x

Taking drivatives on both sides of the equation

p´(x) = 2 - 200/x²

p´(x) = 0         ⇒        2 - 200/x² = 0

2*x² - 200 = 0       x² = 100

x = 10 m

and  y = 100/10      

y = 10 m

Required fencing material in first option

2*10 + 2*10  =  40 m

2.-Option

Following the same procedure

A = 98 m²       y = A/x         y = 98/x

p = 2*x + y             p(x) =  2*x  +  98/x

p´(x)  = 2 - 98/x²             p ´(x) = 0

2 - 98/x²  = 0

2*x²  = 98           x² =  49

x = 7 m       and        y   =  98/ 7         y  = 14 m

Total quantity of fencing material

p = 2* 7 + 14         p = 28

Therefore option 2 is more convinient from economic point of view

Optimal design rectangular storage area with two sides of 7 m and one side of 14 m

Answer:

114.96 pounds at angle 81.76°

Step-by-step explanation:

Let i be the component along x-axis and j be the component along y-axis.

First force that is given is 150 acting at angle 40; [tex]F1 = 150cos170i + 150sin40j = 114.91i +96.42j[/tex]

The second force 100 is acting at angle 170;

[tex]F2 = 100cos170i + 100sin170j = -98.48i + 17.36j[/tex]

We now have the resultant force, which is: [tex]114.91i + 96.42j + (-98.48i + 17.36j) = 16.43i + 113.78j[/tex]

Magnitude of resultant:

[tex]\sqrt{16.43^{2} + 113.78^{2} }[/tex] = 114.96 pounds

Angle it makes with horizontal; inverse tangent of [tex]\frac{(113.78)}{(16.43)}[/tex] = 81.76 degrees

Hope this helps; Brainliest appreciated!

Answer:

The correct option is;

D) x² + 72·x - 7920 = 0

Step-by-step explanation:

The time it takes the car to stop = x/24 seconds

the average speed during stopping = x/2 feet per second

Given that the car was initially travelling at x feet per second and it takes the car 165 feet to stop after the driver takes 1.5 seconds at the initial speed x before the break is applied, we have;

Total distance traveled = (x/24)×(x/2) + x×1.5 = 165

= x²/48 + 1.5·x = 165

Multiply through by 48, we have;

x² + 72·x = 7920

Which gives the equation as follows;

x² + 72·x - 7920 = 0.

Answer:

C) line b and line c

Step-by-step explanation:

On edge

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The system of equations that do not have any solution is line b and line c. Hence, the correct option is C.

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is the y-intercept.

The equation of line a passing through (-1,0) and (1,2) are,

m = (0-2)/(-1-1) = -2/-2 = 1

y= x + c

0 = -1 + c

c = 1

Equation of line 1, y=x+1

The equation of line b passing through (-2,2) and (-1,-1) are,

m = (2+1)/(-2+1) = 3/-1 = -3

y= -3x + c

-1 = -3(-1) + c

c = -4

Equation of line 1, y=-3x-4

The equation of line c passing through (0,3) and (1,0) are,

m = (3-0)/(0-1) = 3/-1 = -3

y= -3x + c

3 = -3(0) + c

c = 3

Equation of line 1, y=-3x+3

Also, the equation of line d is y=1

The solution of two-equation is the point at which the two equations are not intersecting. Therefore, the system of equations that do not have any solution is line b and line c.

Hence, the correct option is C.

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Answer:

1080

Step-by-step explanation:

Answer:

1) For [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex], the standard form is [tex](x-2)^2 + (y+6)^2 = 60\\[/tex]

2) For [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex], the standard form is [tex](x + 3)^2 + (y - 4)^2 = 35\\[/tex]

3) For [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex],  the standard form is [tex](x + 2)^2 + (y+ 3)^2 = 18\\[/tex]

4) For [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex],  the standard form is [tex](x - 1)^2 + (y+ 2)^2 = 11\\[/tex]

5) For [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex],  the standard form is [tex](x - 6)^2 + (y+ 4)^2 = 56\\[/tex]

6) For[tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex], the standard form is [tex](x+1)^2 + (y-6)^2 = 46\\\\[/tex]

Step-by-step explanation:

This can be done using the completing the square method.

The standard equation of a circle is given by [tex](x - a)^2 + (y-b)^2 = r^2[/tex]

1) For [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex]

[tex]x^2 - 4x + y^2 + 12y = 20\\x^2 - 4x + 2^2 + y^2 + 12y + 6^2 = 20 + 4 + 36\\(x-2)^2 + (y+6)^2 = 60\\[/tex]

Therefore, for [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex], the standard form is [tex](x-2)^2 + (y+6)^2 = 60\\[/tex]

2) For [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex]

[tex]x^2 + 6x + y^2 - 8y = 10\\x^2 + 6x + 3^2 + y^2 - 8y + 4^2 = 10 + 9 + 16\\(x + 3)^2 + (y- 4)^2 = 35\\[/tex]

Therefore, for [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex], the standard form is [tex](x + 3)^2 + (y - 4)^2 = 35\\[/tex]

3)  For [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex]

Divide through by 3

[tex]x^2 + y^2 + 4x + 6y = 5[/tex]

[tex]x^2 + y^2 + 4x + 6y = 5\\x^2 + 4x + 2^2 + y^2 + 6y + 3^2 = 5 + 4 + 9\\(x + 2)^2 + (y+ 3)^2 = 18\\[/tex]

Therefore, for [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex],  the standard form is [tex](x + 2)^2 + (y+ 3)^2 = 18\\[/tex]

4)  For [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex]

Divide through by 5

[tex]x^2 + y^2 - 2x + 4y = 6[/tex]

[tex]x^2 + y^2 -2x + 4y = 6\\x^2 - 2x + 1^2 + y^2 + 4y + 2^2 = 6 + 1 + 4\\(x - 1)^2 + (y+ 2)^2 = 11\\[/tex]

Therefore, for [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex],  the standard form is [tex](x - 1)^2 + (y+ 2)^2 = 11\\[/tex]

5) For [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex]

Divide through by 2

[tex]x^2 + y^2 - 12x - 8y = 4[/tex]

[tex]x^2 + y^2 - 12x - 8y = 4\\x^2 - 12x + 6^2 + y^2 - 8y + 4^2 = 4 + 36 + 16\\(x - 6)^2 + (y+ 4)^2 = 56\\[/tex]

Therefore, for [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex],  the standard form is [tex](x - 6)^2 + (y+ 4)^2 = 56\\[/tex]

6) For [tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex]

[tex]x^2 + 2x + y^2 - 12y = 9\\x^2 + 2x + 1^2 + y^2 - 12y + 6^2 = 9 + 1 + 36\\(x+1)^2 + (y-6)^2 = 46\\[/tex]

Therefore, for[tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex], the standard form is [tex](x+1)^2 + (y-6)^2 = 46\\\\[/tex]

For Plato / Edmentum

Just to the test and got it right ✅

Answer: 5/55

Step-by-step explanation:

1/11 x 5 = 5/55

So, the fifth equivalent fraction to 1/11 is 5/55.

The 5th equivalent fraction should be [tex]5\div 55[/tex]

Since the fraction is [tex]1\div 11[/tex]

So here the 5th equivalent should be

[tex]= 1\div 11 \times 5\div 5[/tex]

= [tex]5\div 55[/tex]

Here 5 represent the numerator and 55 represent the denominator.

Therefore, we can concluded that The 5th equivalent fraction should be [tex]5\div 55[/tex]

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Answer:

y = csc (x) + 2

Step-by-step explanation:

From the graph, we can derive the parent function y = csc(x). Notice how there are asymptotes at x = 2πk and x = π + 2πk, which is where csc(x) is undefined.

Finally, we can see a vertical shift of 2 which we can see from the mid-line of the graph which is at y = 3.

Answer:

c

Step-by-step explanation:

edg 2021

Answer:

Step-by-step explanation:

Total marbles = 5  + 6 + 2 = 13

P( getting blue ball from first draw) = 5/13

The marble is not replaced. So, Now total marbles will be 12 & number blue marbles will be 4

P( getting blue ball from second draw) = 4/12 = 1/3

P(getting two blues) = [tex]\frac{5}{13}*\frac{1}{3}\\[/tex]

                                  = 5/39

Answer:

6) g = 11p

7) This equation is an example of direct variaction because it is proportional because can make a slanted line with the equation C = 6g + 15

Step-by-step explanation:

Well to find g we seperate g and combine like terms,

[tex]81 = 6g + 15[/tex]

So we subtract 15 from both sides 66 = 6g,

66/6 = 11.

So g = 11.

Answer:

[tex]\boxed{\mathrm{view \: explanation}}[/tex]

Step-by-step explanation:

2)

a) elimination method

b) substitution method

c) substitution method

For the first part we can elimate the y variable by subtracting the equations. We can then find the value of x.

For the second part we can substitute y as 2x+5 in the second equation and solve for x.

For the third part we can substitute y as 4x+3 in the first equation and solve for x.

3)

[tex]\boxed{\mathrm{view \: attachment}}[/tex]

Answer:

There are 1000 millimeters in a meter.

Step-by-step explanation:

I really hope this helps in any way.

Answer:

1,000

Step-by-step explanation:

The word millimeter has the prefix of 'milli-'.

'Milli-' means a thousand.

Applying the prefix meaning to the word, a millimeter would be a thousandth of a meter.

There are 1,000 millimeters in a meter.

Brainilest Appreciated.

Answer:

first option

Step-by-step explanation:

Using the rules of logarithms

log x - log y = log ([tex]\frac{x}{y}[/tex] )

log[tex]x^{n}[/tex] ⇔ n log x

ln e = 1

Given

4 + 5[tex]e^{x+2}[/tex] = 11 ( subtract 4 from both sides )

5[tex]e^{x+2}[/tex] = 7 ( divide both sides by 5 )

[tex]e^{x+2}[/tex] = [tex]\frac{7}{5}[/tex] ( take ln of both sides )

ln [tex]e^{x+2}[/tex] = ln ([tex]\frac{7}{5}[/tex] )

(x + 2) lne = ln ([tex]\frac{7}{5}[/tex] )

x + 2 = ln ([tex]\frac{7}{5}[/tex] ) ( subtract 2 from both sides )

x = ln([tex]\frac{7}{5}[/tex] ) - 2