Find the measure of angle B:

Answer:

Distribute the 2 through to the (x-5)

Step-by-step explanation:

After that you get x by itself and stuff like that, but first is distributing.

Answer:

$16.35

Step-by-step explanation:

26.16/8 = $3.27 per gallon. 3.27x5= 16.35, so she has to pay $16.35 for an extra 5 gallons.

Answer:

c= -5

Step-by-step explanation:

Answer:

Try the first one but I think i that it

Step-by-step explanation:

Hope that helps

56%      

thx r points

bye

I typing this because it said the answer was too

Answer:

first one, -4+-5=-9

second one, is d, -6 14/15

Step-by-step explanation:

i hope this helps.    :)

Answer:

Step-by-step explanation:

Given

Substitute h  and find the value of x:

Answer:

X = -1/2 or 1/2

Step-by-step explanation:

When the square root of  a number is found, this usually results in 2 solutions which may be equal in size but opposite in signs.

As such,

X^2=1 to find x find the root of both sides

X = √1

X = -1 or 1

Going by this

4x^2=1

Divide both sides by 4

X^2=1 /4

taking the square root of both sides

X = √1/4

The root of 1 is -1 or 1 while that of 4 is -2 or 2 hence,

X = -1/2 or 1/2

Answer:

[tex]since \: the \: three \: sides \: are \: not\: equal : \\ its \: a \to \:\underline{\boxed{scalene}} \\ line \: \overline{AB} = 2 \\ line \: \overline{AC}= 6 \\ line \: \overline{BC} = 2 \sqrt{10} [/tex]

Step-by-step explanation:

[tex]to \: prove \: this \to \: we \: will \: need \: to \: find \\ \: the \: lenghts \: of \: the \: sides \: of \: \\ this \: triangle \to \\ using \: the \: shortest \: distance \: between \: \\ two \: points \to \: d \: = \sqrt{( {x_2 -x_1) }^{2} + (y_2 - y_1)^{2} } \\ \\ \underline{ \boxed{\overline{AB}}} \\ line \: \overline{AB} \: has \: points \to: ( - 3, - 3) \: and \:( 3, 5) \\ d \: = \sqrt{ (( - 3) - ( - 3))^{2} +( 5 - 3))^{2} } \\ d = \sqrt{(0) + (4)} \\ d = \sqrt{4} \\ \boxed{ d = 2 = AB} \\ \\ \underline{ \boxed{\overline{AC}}} \\ line \: \overline{AC} \: has \: points \to: ( - 3, - 3) \: and \:( 5, - 1) \\ d \: = \sqrt{ (( - 3) - ( - 3))^{2} +(( - 1) - 5)^{2} } \\ d = \sqrt{(0) + ( - 6) {}^{2} } \\ d = \sqrt{36} \\ \boxed{ d = 6 = AC} \\ \\ \underline{ \boxed{\overline{BC}}} \\ line \: \overline{BC} \: has \: points \to: ( 3, 5) \: and \:( 5, - 1) \\ d \: = \sqrt{ (5 - 3)^{2} +(( - 1) - 5)^{2} } \\ d = \sqrt{(2) {}^{2} + ( - 6) {}^{2} } \\ d = \sqrt{40} \\ \boxed{ d =2 \sqrt{10} = BC} \\ its \: a \: scalene : since \: the \: three \: sides \: are \: not\: equal[/tex]

Answer:

You should probably use a website called desmos if u ever need to graph somethin

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

We are given the number 107.263.

Using place value, locate the hundredths place.

107.263

The number 6 is in the hundredths place.

Hope this helps.

Answer:

Part A: If Beatrice inputs −8 into the function, she must get an output of 8.

Part B: (−4,8) , (4,−8) , (8,−4)

Step-by-step explanation:

Part A:

We know that a function is a relation that maps elements from one set (The domain, the set of the inputs) into elements from another set (the range, the set of the outputs)

Such that each input can be mapped into only one output.

Then if we know that our function maps the input -8 into the output 8.

Always that we use this function with the input -8. we will have the same output, 8.

Then we can conclude that the correct option to the first part is:

"If Beatrice inputs −8 into the function, she must get an output of 8. "

Part B:

Remember, -8 is mapped into 8, then the point (−8,4) (this says "-8 is mapped into 4) can never be on the graph of the function.

But the points:

(−4,8) , (4,−8) , (8,−4)

Could be on the graph of the function.

Answer:

correct A:-8,8

B: -4,8

Step-by-step explanation:

Answer:the answer is 70 u welcome text me if wrong armstrongtamarion

Step-by-step explanation:

Answer:

try photo math it's meant for this kind of stuff

Answer:

The solutions are:

[tex]x=0,\:x=-3,\:x=4[/tex]

Step-by-step explanation:

Given the function

[tex]f(x) = x(x+3)(x - 4)[/tex]

In order to determine the zeros of the function, we substitute f(x) = 0

[tex]0\:=\:x\left(x+3\right)\left(x\:-\:4\right)[/tex]

switch sides

[tex]x\left(x+3\right)\left(x-4\right)=0[/tex]

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

[tex]x=0\quad \mathrm{or}\quad \:x+3=0\quad \mathrm{or}\quad \:x-4=0[/tex]

Thus,

x = 0

and solving x + 3 = 0

x + 3 = 0

subtracting 3 from both sides

x + 3 - 3 = 0 - 3

x = -3

and solving x - 4 = 0

x - 4 = 0

x - 4 + 4 = 0 + 4

x = 4

Therefore, the solutions are:

[tex]x=0,\:x=-3,\:x=4[/tex]

Step-by-step explanation:

The Answer is C I got it right on edge.

Answer:

B) 6(4x + 3y)

Step-by-step explanation:

I got that one wrong I got a 90 but B is it

Answer:

a/3b^2

Step-by-step explanation:

16a^2b^3c^6/48ab^5c^6

the c^6 cancel out, then simplify a^2 and a: ​16a^2b^3/48ab^5 = ​16ab^3/48b^5

Then divide 48 and 16 you get 3 ​16ab^3/48b^5 = ab^3/3b^5

And lastly, simplify b^3 and b^5  ab^3/3b^5 =

a/3b^2

Answer:

Your answer is: (-1/2, 3/2)

Step-by-step explanation:

y = x + 2

y = -3x

Use substitution by plugging the second equation into the first.

-3x = x +2

Subtract x from both sides to combine the variables.

-4x = 2

Divide both sides by -4 to isolate the variable x.

x = 2/-4

Simplify.

x = -1/2

Plug x into one of the equations to find y.

y = (-1/2) + 2

y = 3/2

Plug x into the other equation to confirm your answer.

y = -3(-1/2)

y = 3/2

Your answer is: (-1/2, 3/2)

Answer:

d.(-1,4)

Step-by-step explanation:

Option D is correct, the coordinates of the image D are (-1, 4)

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

To find the coordinates of the image D, we need to apply the dilation transformation centered at R(-3, 5). Let the scale factor be k.

The x-coordinate of D will be shifted k times the distance between 1 and -3, which is 4 units, from the x-coordinate of R, which is -3. So we have:

0.5 = -3 + k(4)

Solving for k, we get:

k = 1.375

Similarly, the y-coordinate of D will be shifted k times the distance between 3 and 5, which is 2 units, from the y-coordinate of R, which is 5. So we have

R: (x, y) = (-3, 5)

D: (x, y) = (-3 + 1.375(1 - (-3)), 5 + 1.375(3 - 5))

D: (x, y) = (-1, 4)

Therefore, the coordinates of the image D are (-1, 4), which is option D.

To learn more on Graph click:

https://brainly.com/question/17267403

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Answer:26

Step-by-step explanation:

a squared+b squared= the hypotenuse squared

Input

10 squared+24 squared=the hypotenuse squared

100+576=676 squared

Now we need to find the square route of 676 because this is the hypotenuse squared, and we need to find the hypotenuse. And the square route of 676 is 26.

Answer:

[tex]\sqrt{25}[/tex]

Step-by-step explanation:

Answer:

y= -4x^2 + 15x - 14

Step-by-step explanation:

A parabola is always in the form y = ax^2 + bx + c.

Substitute each point to produce different equations:

-14 = 0a + 0b + c = c

so c = -14

-3 = a1^2 + b1 + c = a + b - 14

so a + b = 11

0 = a2^2 + b2 + c = 4a + 2b -14 = 0

so 4a + 2b = 14

if we double a + b = 11 we get 2a + 2b = 22

Subtract this from 4a + 2b = 14 and we get 2a = -8 so a= -4 and b = 11 - a = 15

We don't need to use the (3,5) points as we have all the information we need.

Answer:

y= -4x^2 + 15x - 14

Step-by-step explanation:

Answer:

[tex]x=2\sqrt{2}[/tex], [tex]x=-2\sqrt{2}[/tex], [tex]x=4i[/tex], [tex]x=-4i[/tex]

Step-by-step explanation:

[tex]x^4+11x^2=3x^2+128[/tex]

First, we subtract 128 from both sides:

[tex]x^4+11x^2-128=3x^2[/tex]

Then, we subtract [tex]3x^2[/tex] from both sides:

[tex]x^4+8x^2-128=0[/tex]

Rewrite the equation:

[tex]u^2+8u-128=0[/tex]

Insert and solve:

[tex]u^2+8u-128=0\\u=8,u=-16\\x^2=8:x=2\sqrt{2},x= -2\sqrt{2} \\x^2=-16:x=4i,x=-4i[/tex]

Please give Brainliest

Answer:

D)  √130

The distance of the given points

AB = √130

Step-by-step explanation:

Explanation:-

Given points are A(-3,6) and B( 4,-3)

The distance formula

   AB = [tex]\sqrt{x_{2}-x_{1})^{2} +(y_{2} -y_{1} )^{2} }[/tex]

 AB = [tex]\sqrt{(4-(-3))^{2} +(-3-6)^{2}[/tex]

 AB = [tex]\sqrt{(7)^{2} +(-9)^{2} }[/tex]

AB = [tex]\sqrt{49+81}[/tex]

AB = √130