Answer:
Resultant = 54.67 N
Direction: 50.2° to the horizontal
Explanation:
Note: Since both forces form a right angle triangle, As shown in the diagram below,
Applying
Pythagoras theorem,
a² = b²+c²..................... Equation 1
From the question,
a = R, b = 42 N, c = 35 N
Substitute these values into equation 1
R² = 42²+35²
R² = 1764+1225
R² = 2989
R = √2989
R = 54.67 N
Direction
tanФ = a/b
Where Ф = direction of the resultant
tanФ = 42/35
tanФ = 1.2
Ф = tan⁻¹(1.2)
Ф = 50.2° to the horizontal
g A meteoroid is in a circular orbit 600 km above the surface of a distant planet. The planet has the same mass as Earth but has a radius that is 90 % of Earth's (where Earth's radius is approximately 6370 km ). What is the gravitational acceleration of the meteoroid
Answer:
Explanation:
gravitational acceleration of meteoroid
= GM / R²
M is mass of planet , R is radius of orbit of meteoroid from the Centre of the planet .
R = (.9 x 6370 + 600 )x 10³ m
= 6333 x 10³ m
M , mass of the planet = 5.97 x 10²⁴ kg .
gravitational acceleration of meteoroid
= GM / R²
= (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ kg / (6333 x 10³ m)²
9.92m/s²
What forces are acting on the race car while it is in motion? (hint: there are 3
forces)
Answer:
the forces acting on the car while moving are - frictional force, applied force , air resistance and gravity.:
Which nucleus completes the following equation?
Answer:
b
Explanation:
b
Answer: c
Explanation:
A p e x
True False: Marke each statement as true or false.
shift
1. Light intensity affects the rate of photosynthesis.
in
2. Energy is required by all organisms for life.
3. The ability of a plant to repair tissue depends on respiration.
4. The gas needed for photosynthesis is carbon dioxide (CO2).
5. Plants only carry on photosynthesis, not respiration.
6. Respiration can occur without photosynthesis.
Answer:
1) true 2) true 3) true 4) true 5) false 6) false
Explanation:
12)A black body is heated from 27°C to 127° C. The ratio of their energies of radiations emitted will be
a)3:4
c)27:64
b)9:16
d)81:256
Answer:
[tex]81:256[/tex].
Explanation:
Let [tex]T[/tex] denote the absolute temperature of this object.
Calculate the value of [tex]T[/tex] before and after heating:
[tex]T(\text{before}) = 27 + 273 = 300\; \rm K[/tex].
[tex]T(\text{after}) = 127 + 273 = 400\; \rm K[/tex].
By the Stefan-Boltzmann Law, the energy that this object emits (over all frequencies) would be proportional to [tex]T^4[/tex].
Ratio between the absolute temperature of this object before and after heating:
[tex]\displaystyle \frac{T(\text{before})}{T(\text{after})} = \frac{3}{4}[/tex].
Therefore, by the Stefan-Boltzmann Law, the ratio between the energy that this object emits before and after heating would be:
[tex]\displaystyle \left(\frac{T(\text{before})}{T(\text{after})}\right)^{4} = \left(\frac{3}{4}\right)^{4} = \frac{81}{256}[/tex].
b. Why are the resources listed in part (a) considered "renewable"?
Answer:
I would need to see the part a to be more specific but this may help:
resources like solar, water, wind are considered renewable because they will never run out, they can be replenished over and over again. There will always be a sun (and if there wasn't then we'd have bigger conserns than renewable energy) and the wind will always blow. It can never run out because you use too much unlike coal and fossil fuels.
Hope this helps!
A planet moves in a circular orbit of radius 4.5x10^15 m with a period of 4
days. What is its velocity?
Answer:
2.6x10^{10}
Explanation:
please do follow me
A bird is standing on an electric transmission line carrying 3000 A of current. A wire like this has about 3.0 x 10-5 22 of resistance per meter. The bird's feet are 6 cm apart. The bird itself has a resistance of about 4 x 105 12. The bird experiences a potential difference of 0.0054 V. What current goes through the bird?
Answer:
13.5 x 10^-9 A
Explanation:
Yes
Describe each of the FITT training principles. (Site 1
Answer:
The FITT principles are an exercise prescription to help participants understand how long and how hard they should exercise. FITT is acronym that stands for Frequency, Intensity, Time, and Type. FITT can be applied to exercise in general or specific components of exercise.
Explanation:
A golf club rotates 215 degrees and has a length (radius) equal to 29 inches. The time it took to swing the club was 0.8 seconds. What is the average linear velocity (inches/second) of the golf club
Answer:
The average linear velocity (inches/second) of the golf club is 136.01 inches/second
Explanation:
Given;
length of the club, L = 29 inches
rotation angle, θ = 215⁰
time of motion, t = 0.8 s
The angular speed of the club is calculated as follows;
[tex]\omega = (\frac{\theta}{360} \times 2\pi, \ rad) \times \frac{1}{t} \\\\\omega = (\frac{215}{360} \times 2\pi, \ rad) \times \frac{1}{0.8 \ s} \\\\\omega = 4.69 \ rad/s[/tex]
The average linear velocity (inches/second) of the golf club is calculated as;
v = ωr
v = 4.69 rad/s x 29 inches
v = 136.01 inches/second
Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second
is burning trash a physical change or chemical change?
Two loudspeakers in a plane are 2.0 m apart and in phase with each other. Both emit 700 Hz sound waves into a room where the speed of sound is 341 m/s. A listener stands 5.0 m in front of the loudspeakers and 2.0 m to one side of the center line. Is the interference at this point completely constructive, completely destructive, or in between
Answer:
interference is between destructive and constructive
Explanation:
The interference of two sound waves periodicity in phase by the speakers is
Δr = [tex]\frac{\phi }{2\pi } \ \lambda[/tex]
in this case they indicate that the frequency is f = 700 Hz, the wave speed is
v =λ f
λ = v / f
λ = 341/700
λ = 0.487 m
Let's use the Pythagorean theorem to find the distance that each wave travels
r₁ = [tex]\sqrt{x^2 + y^2}[/tex]
let's measure the distance from speaker 1
r₁ = [tex]\sqrt{5^2 + 1^2}[/tex]
r₁ = 5,099 m
the distance from the second speaker
r₂ = \sqrt{x^2 + y^2}
r₂ = [tex]\sqrt{5^2 +3^2}[/tex]
r₂= 5.831 m
the difference in the way is
Δr = r₂ -r₁
Δr = 5,831 - 5,099
Δr = 0.732 m
[tex]\frac{ \phi }{2\pi }[/tex] = Δr /λ
\frac{ \phi }{2\pi } = 0.732 / 0.487
\frac{ \phi }{2\pi } = 1.50
this is the phase difference this phase difference is approximately
Ф= [tex]\frac{\pi }{2}[/tex] =1.57,
so the interference is between destructive ( Ф = π) and constructive (Ф=2π)
A given container of 5.0 kg of water maintains a constant temperature over 24 hours. If its mass doesn't change, what statements would support identifying it as a closed system.
I. Only energy was exchanged with its surroundings.
II. Its mass was constant because the water lost to evaporation was replaced with an equal volume of water.
III. It didn't exchange matter or energy with its environment.
IV. External work was used to maintain its internal energy.
A) III
B) l and III
C) II and IV
D) I and IV
Answer:
D) I and IV
Explanation:
A closed system is the one where mass can not enter or leave the system, while the energy can enter o leave the system.
I. This is true according to the definition. Because only energy can enter or leave a closed system.
II. This is not true. Because mass interaction is not allowed in a closed system.
III. This is false. Because energy exchange is allowed.
IV. True. Because energy exchange is possible.
Therefore the correct option is:
D) I and IV
g Suppose you're on a hot air balloon ride, carrying a buzzer that emits a sound of frequency f. If you accidentally drop the buzzer over the side while the balloon is rising at constant speed, what can you conclude about the sound you hear as the buzzer falls toward the ground
Answer:
the observed frequency will reduce but the wavelength will increase
Explanation:
As we know
fo = fs (v/(v-vs))
fo = observed frequency
vs = velocity of source
As per this equation,
When an observer moves away from the stationary source, the observed frequency reduces. Since the observer in the balloon is moving away from the source which itself is moving in opposite direction, the observed frequency will reduce.
Since wavelength = V/fs . The source frequency is unchanged but the velocity is increasing as it is moving in downward direction. Hence, the wavelength will increase
a 4 kg block is moving at 12 m/s on a horizontal frictionless surface. a constant force is applied such that the block slows with an acceleration of 3 m/s^2. how much work must this force do to stop the block?
a. -576 J
b. -360 J
c. -288 J
d. 360 J
e. 576 J
The block comes to a rest from 12 m/s with acceleration 3 m/s^2, which is carried out over a distance x such that
(12 m/s)^2 - 0^2 = 2 (3 m/s^2) x
=> x = (12 m/s)^2 / (2 (3 m/s^2)) = 24 m
The force itself has a magnitude F such that
F = (4 kg) (3 m/s^2)
=> F = 12 N
This force is pointing opposite the direction in which the block is moving, so the work it's performing is negative, and the work done is
W = - (12 N) (24 m) = -288 Nm = -288 J
which makes C the answer.
Light with a single wavelength falls on two slits separated by 0.510 mm. In the resulting interference pattern on a screen 2.24 m away, adjacent bright fringes are separated by 2.88 mm.What is the wavelength of the light that falls on the slits
Answer: 655.7 nm
Explanation:
Given
The slits are separated by [tex]d=0.510\ mm[/tex]
Distance between slits and screen is [tex]D=2.24\ m[/tex]
Adjacent bright fringes are [tex]\beta =2.88\ mm[/tex] apart
Also, the distance between bright fringes is given by
[tex]\Rightarrow \beta =\dfrac{\lambda D}{d}\quad [\lambda=\text{Wavelength of light}]\\\\\text{Insert the values}\\\\\Rightarrow 2.88\times 10^{-3}=\dfrac{\lambda \cdot 2.24}{0.510\times 10^{-3}}\\\\\Rightarrow \lambda =\dfrac{2.88\times 10^{-3}\times 0.510\times 10^{-3}}{2.24}\\\\\Rightarrow \lambda =0.6557\times 10^{-6}\ m\\\Rightarrow \lambda =655.7\ nm[/tex]
Monochromatic light with wavelength 633 nn passes through a narrow slit and a patternappears on a screen 6.0 m away. The distance on the screen between the centers of thefirst minima on either side of the screen is 32 mm. How wide (in mm) is the slit
Answer:
Explanation:
screen distance D = 6 m .
wavelength of light λ = 633 nm.
slit width = d .
Distance between first minima on either side is width of central maxima
= 2 x λD /d
Given
32 x 10⁻³ = 2 x λD /d
d = 2 x λD /32 x 10⁻³
= 2 x 633 x 10⁻⁹ x 6 / 32 x 10⁻³
= 237.37 x 10⁻⁶ m
= .23737 x 10⁻³ m
= .24 mm .
Which planet(s) in the solar system has/have retrograde orbits around the Sun?
A) Uranus
B) Venus and Uranus
C) Earth, Mars, and Saturn
D) Jupiter
Answer:B
Explanation:
Question 15 of 25
You feel warm sitting next to a bright light. Which type of heat transfer are
Experiencing?
Answer:
radiation
Explanation:
What is the electric field strength 7.50 x 10E-1 meters from a 2.8 x 10 E-3 C charged object?
Answer:hi
Explanation:
1 point
4. When mass is in kilograms and velocity is in meters per second then
momentum is in kilograms-meters per second.
True
Ο Ο
False
Answer:
true
Explanation:
momentum = kg (m/s)
momentum = mass × velocity
Activity 4: Caste System - The Hierarchy
Instruction: Label the hierarchy of the caste system. Write your answer on the
space provided.
For an electrical project in a residence, the electrical engineer had resistors
resistances equal to 300 and 100 to assemble a circuit of an electrical appliance that must be connected 12
hours per day. In order to obtain a chain for optimal operation, he came to the conclusion that the best
configuration would be the one shown in the figure below (consider the middle thread as ideal). Knowing that
kWh value is $ 0.35, what is the amount that must be paid for energy consumption over 1 month (30 days)?
Answer:
$ 0.077
Explanation:
We'll begin by calculating the equivalent resistance of the three 300 Ω resistors connected in series. This can be obtained as follow:
Equivalent resistance of the three 300 Ω (R₃₀₀) = 300 + 300 + 300
= 900 Ω
Next, we shall determine the equivalent resistance of the two 100 Ω resistors connected in series. This can be obtained as follow:
Equivalent resistance of the two 100 Ω (R₁₀₀) = 100 + 100
= 200 Ω
Next, we shall determine the equivalent resistance in the circuit. This can be obtained as follow:
Equivalent resistance of the three 300 Ω (R₃₀₀) = 900 Ω
Equivalent resistance of the two 100 Ω (R₁₀₀) = 200 Ω
Equivalent Resistance (R) =?
R = R₃₀₀ × R₁₀₀ / R₃₀₀ + R₁₀₀ (since they are in parallel connections)
R = 900 × 200 / 900 + 200
R = 163.64 Ω
Next, we shall determine the energy in KWh. This can be obtained as follow:
Voltage (V) = 10 V
Resistance (R) = 163.64 Ω
Time (t) for 30 days = 12 × 30 = 360 h
Energy (E) =?
E = V²t / R
E = 10² × 360 / 163.64
E = 100 × 360 / 163.64
E = 36000 / 163.64
E = 220 Wh
Divide by 1000 to express in KWh
E = 220 Wh / 1000 = 0.22 KWh
Finally, we shall determine the amount paid for 1 month (30 days). This can be obtained as follow:
Cost per KWh = $ 0.35
Energy (E) = 0.22 KWh
Cost for 30 days =?
Cost for 30 days = Energy × Cost per KWh
Cost for 30 days = 0.22 × 0.35
Cost for 30 days = $ 0.077
Therefore, the amount that must be paid for 1 month is $ 0.077
A 2.0-m-long rod has a density in kilograms per meter and x is the distance from the left end of the rod. The rod rests horizontally with each end supported by a scale. The force exerted by the left scales is
Answer: Hi your question is incomplete below is the complete question
A 2.0-m long rod has a density in kilograms per meters λ = a + bx, where a=1.0kg/m, b=1.0kg/m2, and x is the distance from the left end of the rod. The rod rests horizontally with each end supported by a scale. The force exerted by the left scale is?
answer : 13.08 N
Explanation:
Determine the force exerted by the left scale
Length of rod = 2.0 m
Density of rod ( λ )= a + bx = 1 + 1x
First step ; Determine the moment
∑ moment = 0 = F * 2 - (( 1 * 2 * g * 2/2) + (1/2 * 2 * 1 * g * (2/3 ) )
∴ F = 4g / 3
= 4 * 9.81 / 3 = 39.24 / 3 = 13.08 N
Stunt car A and stunt car B are identical cars with the same mass of 47.1 kg. They are both traveling at 89.3 m/s. Stunt car A crashes into a hard concrete wall, whereas stunt car B crashes into a large pile of soft sand. They both come to a complete stop after the impact.
Stunt Car A experiences a ______ over a ______ of time.
Stunt Car B experiences a ______ over a ______ of time.
Because of the force experienced by Stunt Car A, it will sustain ______ damage than Stunt Car B.
Answer:
1) HIGH IMPULSE, SHORT INSTANT
2) SMALL IMPULSE, MORE INSTANT OF TIME
more
Explanation:
Let's propose the solution of this exercise, let's use the relationship between momentum and momentum
I = Δp
F t = m v_f - m v₀
indicates that the carriage stops v_f = 0
F t = - m v₀
Therefore, if the impact time decreases, the force must increase and therefore the damages also
Car A collides with a concrete wall that is rigid, therefore the collision occurs in a very short time, car B collides with area, so the collision time is extended, now we can complete the sentences
1) Stunt Car A experiences a _HIGH IMPULSE_ over a SHORT INSTANT__ of time.
2)Stunt Car B experiences a _SMALL IMPULSE_____ over a _MORE INSTANT__ of time.
3) Because of the force experienced by Stunt Car A, it will sustain __MORE____ damage than Stunt Car B.a
3) more
A skydiver weighing 200 lbs with clothes that have a drag coefficient of .325 is falling in an area that has an atmospheric density of 1.225 kg/m2 (and assuming that altitude has a negligible effect on atmospheric density). The skydiver can change the body orientation from straight-erect with a cross-sectional area of 6 sqft to a belly-flat cross-sectional area of 24 sqft. Calculate the terminal velocity of the person when the body has straight and when the body has belly-flat orientations. Calculate the terminal velocity on these two different orientations.
Answer:
The right solution is:
(a) 89.455 m/s
(b) 44.73 m/s
Explanation:
The given values are:
Mass,
m = 200 lbs
or,
= [tex]\frac{200}{2.205} \ kg[/tex]
= [tex]90.7 \ kg[/tex]
Air's density,
[tex]\delta = 1.225 \ kg/m^3[/tex]
Drag coefficient,
[tex]C_d=0.325[/tex]
When body is straight, area,
[tex]A_1=6 \ ft^2[/tex]
As we know,
Terminal velocity,
⇒ [tex]V_t=\sqrt{\frac{2W}{C_d \delta A} }[/tex]
or,
⇒ [tex]=\sqrt{\frac{2mg}{C_d \delta A} }[/tex]
At straight orientation,
⇒ [tex]V_t'=\sqrt{\frac{2\times 90.7\times 9.8}{0.325\times 1.225\times 0.558} }[/tex]
⇒ [tex]=\sqrt{\frac{1777.72}{0.223}}[/tex]
⇒ [tex]=89.455 \ m/s[/tex]
When belly flat,
⇒ [tex]V_t''=\sqrt{\frac{2\times 90.7\times 9.8}{0.325\times 1.225\times 0.558\times 4} }[/tex]
⇒ [tex]=\sqrt{\frac{1777.72}{0.889} }[/tex]
⇒ [tex]=44.73 \ m/s[/tex]
the unit of mass"kilogram" is a fundamental unit. why?
Answer:
kilogram is a fundamental unit because it is one of the 7 fundamental units that serve as a building block for derived units.
Explanation:
Fundamental units are used to measure fundamental quantities. They are fundamental units because they serve as a building block for derived units.
7 fundamental quantities and their corresponding units;
Length – meter
Mass – kilogram
Time - seconds
Temperature - Kelvin
Amount of substance - Moles
Electric Current - Ampere
Luminous intensity - Candela
Thus, kilogram is a fundamental unit because it is one of the 7 fundamental units.
After 60 days, 100g of a certain element has decayed to only 12.5g.
What is the half- life of this element?
А
30 days
B.
8 days
С
20 days
D
5 days
Answer:
8 days
Explanation:
The temperature of a body is from 200 to 300C.The change of temp at absolute scale is
Answer:
mark me brainliest
Explanation:
The change of temperature at absolute scale is. A. 3.73 K
Answer:
373K
Explanation:
300°c - 200°c =100°c
Absolute scale means Kelvin scale so
0°c= 273°c
100°c = 100 + 273
=373K
Please help... I'm confused on what I represents in terms of solving the total current. Would variable would I be singling out?
Answer:
the researcher say hi for us the best pa the best of us are going out to eat that I can get my money toward a little bit but the best of luck to be at work by then and we will see what the status