Find the largest of three consecutive whole numbers such that twice the sum of the two smallest numbers is 13 more than three times the largest number.

Answer:

(Y∩Z)∩X = {r,a,e}

Step-by-step explanation:

U = {a,b,c,d,e,f,............,z)

X = { t,r,i,a,n,g,l,e}

Y = {t,r,a,p,e,z,o,i,d}

Z = {h,y,p,e,r,b,o,l,a}

Firstly,

Y∩Z = {t,r,a,p,e,z,o,i,d} ∩  {h,y,p,e,r,b,o,l,a}    [Intersection : Common Elements]

=> Y∩Z = {r,a,p,e,o}

Now,

(Y∩Z)∩X =  {r,a,p,e,o} ∩ { t,r,i,a,n,g,l,e}

=> (Y∩Z)∩X = {r,a,e}

Answer:

2.5 meters per second

Step-by-step explanation:

9x1000=9000m/h

9000/60/60=2.5m/s

Answer:

2.5 m/s

Step-by-step explanation:

convert kilometers to meters and then use a conversion calc to do the rest

Answer:

3.26%

Step-by-step explanation:

The computation of the probability that she is a student is shown below:

Percentage of student developers = 25.8% = SD

The Percentage of the developer is student = 7.4% = DS

The percentage of the developer is not student = 76.4% = ND

Based on this, the probability is

[tex]= \frac{SD \times DS}{SD \times DS + DS \times ND}[/tex]

[tex]= \frac{25.8\% \times 7.4\%}{25.8\% \times 7.4\% + 7.4\% \times 76.4\%}[/tex]

=3.26%

we simply considered all the elements

(a) The support has length 920 - 720 = 200, so X has probability density

[tex]f_X(x)=\begin{cases}\frac1{200}&\text{for }720\le x\le920\\0&\text{otherwise}\end{cases}[/tex]

X has mean

[tex]E[X]=\displaystyle\int_{-\infty}^\infty xf_X(x)\,\mathrm dx=\frac1{200}\int_{720}^{920}x\,\mathrm dx=\boxed{820}[/tex]

and variance

[tex]V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2[/tex]

The second moment is

[tex]E[X^2]=\displaystyle\int_{-\infty}^\infty x^2f_X(x)\,\mathrm dx=\frac1{200}\int_{720}^{920}x^2\,\mathrm dx=\frac{2,027,200}3[/tex]

and so

[tex]V[X]=\dfrac{2,027,200}3-820^2=\dfrac{10,000}3[/tex]

The standard deviation is the square root of the variance, so

[tex]SD[X]=\sqrt{V[X]}=\sqrt{\dfrac{10,000}3}\approx\boxed{57.73}[/tex]

(b)

[tex]P(X<870)=\displaystyle\int_{-\infty}^{870}f_X(x)\,\mathrm dx=\frac1{200}\int_{720}^{870}\mathrm dx=\frac{870-720}{200}=\boxed{0.75}[/tex]

Answer:

120 ways

Step-by-step explanation:

She has 6 friends and needs 3 people to do jobs. This means that for the first job, she has 6 options for someone to buy beverages, but for the second job, she will now only have 5 options, as somebody is already buying beverages. After she assigns someone to the second job, she now has 4 people to pick from for the third job, as 2 are already doing a job. This means she has 6*5*4 ways to assign her volunteers, or 120 ways.

Answer:

15 49-cent stamps

Step-by-step explanation:

We can solve this problem with the equations 0.49(x) + 0.21(y) = 9.45 and x - 5 = y. Well, 0.49(15) + 0.21(10) = 9.45, so we know that there are 15 49-cent stamps and 10 21-cent stamps. The question is asking for the number of 49-cent stamps, so we can tell Travis bought 15 49-cent stamps.

Hope this helps! Plz give me brainliest, it will help me achieve my next rank.

The number of 49-cent stamps that Travis bought given the equation is 15.

Given this equation: 0.49s+0.21(s−5)=9.45 take the following steps to determine the value of s

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Answer:

d) [25, 1.581]

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation(which is the square root of the variance) [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation, which is also standard error, [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

[tex]\sigma = \sqrt{200}, n = 80[/tex]

So the standard error is:

[tex]s = \frac{\sqrt{200}}{\sqrt{80}} = 1.581[/tex]

By the Central Limit Theorem, the mean is the same, so 25.

The correct answer is:

d) [25, 1.581]

Answer:

b. False.

Step-by-step explanation:

According to the presented information, at the 95% confidence level, the mean number of coats owned will be between 3.1 and 5.2. That does not mean that there is a 95% chance that they will own that many coats; just that you are 95% confident that they will own the coats.

Hope this helps!

Answer:

[tex]b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}[/tex]

Step-by-step explanation:

Given

[tex]f(b) = b^2 - 75[/tex]

Required

Determine the roots

To get the root of the function, then f(b) must be 0;

i.e. f(b) = 0

So, the expression becomes

[tex]0 = b^2 - 75[/tex]

Add 75 to both sides

[tex]75 + 0 = b^2 - 75 + 75[/tex]

[tex]75 = b^2[/tex]

Take square roots of both sides

[tex]\sqrt{75} = \sqrt{b^2}[/tex]

[tex]\sqrt{75} = b[/tex]

Reorder

[tex]b = \sqrt{75}[/tex]

Expand 75 as a product of 25 and 3

[tex]b = \sqrt{25*3}[/tex]

Split the expression

[tex]b = \sqrt{25} *\sqrt{3}[/tex]

[tex]b = \±5 *\sqrt{3}[/tex]

[tex]b = \±5 \sqrt{3}[/tex]

[tex]b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}[/tex]

The options are not clear enough; however the roots of the equation are [tex]b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}[/tex]

Answer:

54

give me brainliest please please please and follow my page

Step-by-step explanation:

To find length of KC...we need to find the length of HM and MU first ...

so....HM= 96- 78 = 14

JU = 96 + HM = 96 + 14 = 110

....

KU = 110 - JK = 110 - 82 = 28

....

UN = 105+ 82 -( 96 + 14 )

187 - 110

= 77

UC = 77 - 51 = 26

KC = UC + KU = 26 + 28 = 54

The length of [tex]\overline{KC}[/tex] along line [tex]\overline{JN}[/tex] is given as 54 (Option A) See the computation below.

To determine the length of [tex]\overline{KC}[/tex], the length of [tex]\overline{HM}[/tex] and [tex]\overline{MU}[/tex]must first be derived.

[tex]\overline{HM}[/tex] = 96 - 78

[tex]\overline{HM}[/tex] = 14

[tex]\overline{JU}[/tex] = 96 + [tex]\overline{HM}[/tex]

= 96 + 14

[tex]\overline{JU}[/tex]= 110

[tex]\overline{KU}[/tex] = 110 - [tex]\overline{JK}[/tex]

= 110 - 82

[tex]\overline{KU}[/tex]= 28

[tex]\overline{UN}[/tex] = 105+ 82 -( 96 + 14 )

=187 - 110

[tex]\overline{UN}[/tex]= 77

[tex]\overline{UC}[/tex] = 77 - 51

[tex]\overline{UC}[/tex]= 26

Thus,

[tex]\overline{KC}[/tex] = [tex]\overline{UC}[/tex] + [tex]\overline{KU}[/tex]

[tex]\overline{KC}[/tex]= 26 + 28

[tex]\overline{KC}[/tex]= 54

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Answer:

ΔSTV and ΔUTV

UV and SV

∠U and ∠S

∠TVU and ∠SVT

Step-by-step explanation:

A D E F

ΔSTV And Δ UTV , UV and SV , ∠ U and ∠  S ,  ∠ TVU  and   ∠ SVT  are congruent .

Two figures are said to be congruent if we can superimpose them on each other. For congruency there are three criteria:

For congruency firstly check first part of question which is STV and  TVU triangles because two corresponding sides TS and TU and SV and UV and angle TSV and angle TUV are equal so these two triangles are congruent.

ST and TV are not congruent

angle STV AND SVT are also non congruent

UV and SV are congruent because these are shown in the figure that these are equal.

Angle U and S are congruent as these are the alternate angles of the two triangles.

Angle TVU and SVT are also congruent because these are also alternate angles.

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Answer:

B

Step-by-step explanation:

Answer:

a) Expected Value of Claims = $32,000

b) Average premium per claim, in order to break-even on claim costs

= $5,333.33

c) To make a profit of $60 per policy (i.e. a total profit of $360 ($60 x 6), it must charge:

= $5,393.33 per policy

Step-by-step explanation:

a) Data and Calculations:

Amount of Claim      Probability   Expected Value

$0                               0.60             $0

$50,000                     0.25             $12,500

$100,000                   0.09                 9,000

$150,000                   0.04                 6,000

$200,000                  0.01                 2,000

$250,000                 0.01                 2,500

Expected Cost of claims =          $32,000

b) Average premium per claim, in order to break-even on claim costs

= Total Claim cost divided by number of policies

= $32,000/6 = $5,333.33

c) To make a profit of $60 per policy (i.e. a total profit of $360 ($60 x 6), it must charge:

Total Claim cost + Total profit / 6 or Average Premium plus Profit per policy =

= ($32,000 + $360)/6 or $5,333.33 + $60

= $32,360/6 or $5,393.33

= $5,393.33

The total expected value is $32000, the average premium so that it breaks even on its claim  costs are $5333.33 and the company charge to make a profit of $60 per policy is $5393.33.

Given :

The table shows claims and their probabilities for an insurance company.

Amount of Claim          Probability               Expected Value

$0                                      0.60                             0

$50000                             0.25                            $12500

$100000                            0.09                            $9000

$150000                            0.04                             $6000

$200000                           0.01                              $2000

$250000                            0.01                             $2500

A) So, the total expected value is = 12500 + 9000 + 6000 + 2000 + 2500

                                                   =  $32000

B) The average premium is given by:

[tex]=\dfrac{32000}{6}[/tex]

= $5333.33

C) The company charge to make a profit of $60 per policy is:

[tex]= \dfrac{32000+360}{6}[/tex]

[tex]=\dfrac{32360}{6}[/tex]

= $5393.33

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Answer:

We accept null hypothesis

Step-by-step explanation:

We assume a normal distribution

The population mean  μ₀ = 65 mph      

Sample mean     μ  = 63,2  mph ( calculated from data )

Sample standard deviation  σ  =  7,309

Sample size    n  = 8

Degree of freedom  is   n - 1         8 - 1   = 7

As n < 30  we have to use the t-student test

We will do our test with a confidence interval of  95 % that means            α = 5  %

or α = 0,05 and as we are going through a two-tail test α/2  = 0,025

Test Hypothesis:

Null Hypothesis:                                  H₀              μ  =   μ₀

Alternate Hypothesis                          Hₐ              μ  ≠   μ₀

From  t-student table for the degree of freedom 7,  α/2  = 0,025 two-tail test we find tc

tc = 2,365

And  calculate ts   as

ts = ( μ - μ₀ ) / σ /√n

ts = ( 63,2 - 65 ) / 7,309/ √8

ts = - 1,8 *2,828/ 7,309

ts = - 5,091 /7,309

ts = - 06965

Now we compare   ts and tc

tc = 2,365      or  tc = - 2,365    ( by simmetry)   tc = -2,37

and  ts = -0,06965      ts = - 0,07

As |ts| < |tc|

ts is in the acceptance zone so we accept null hypothesis

Answer:

-0.70

Step-by-step explanation:

For the tabulated value the mean is calculated as:

Mean = (60.5 + 63.2 + 54.7 + 51.6 + 72.3 + 70.7 + 67.2 + 65.4)/8

= 505.6/8

Mean \bar{x}= 63.2

and population mean as assumption u= 65

and given that the sample standard deviation is: s= 7.309

The test statistic is calculated as:

Ζ = Τ –μ 63.2 - 65 = -0.696 -0.70 S

Hence the T statistic would be -0.70

Answer:

Step-by-step explanation:

Given that:

mean (μ) = 476 grams, standard deviation (σ) = 36 grams. P(z) = 19%

The z score shows by how many standard deviation the raw score is above or below the mean. It is given by the equation:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Since the 19% weigh more, therefore 81% (100% - 19%) weigh less.

From the normal distribution table, the z score that corresponds to a probability of 81%(0.81) = 0.87

We substitute z = 0.88 in the z score equation to find the raw score. Therefore:

[tex]z=\frac{x-\mu}{\sigma}\\0.87=\frac{x-476}{36}\\ x-476=31.32\\x=31.32+476\\x=507.32\\[/tex]

x ≅ 507 grams

Therefore 19% of fruits weigh more than 507 grams

Answer:

The correct answer will be "0.3043".

Step-by-step explanation:

The given values are:

[tex]\mu = 15[/tex]

[tex]n=41[/tex]

[tex]\sigma^2=25[/tex]

then,

[tex]\sigma=5[/tex]

If researchers know representative sample n > 30 and default deviation those who use z-test

∴  [tex]P(x>15.4)[/tex]

⇒  [tex]1-P(x<15.4)[/tex]

⇒  [tex]1-P(\frac{x-\mu}{\frac{\sigma}{\sqrt{n} } } <\frac{15.4-15}{\frac{5}{\sqrt{41} } } )[/tex]

⇒  [tex]1-P(Z<0.51225)[/tex]

⇒  [tex]1-0.695762[/tex]

⇒  [tex]0.3043[/tex]

Answer:

The total number of ways to select 2 CDs from 8 CDs is 28.

Answer:

in 1,2 options they r in exponential form

in 4,option also, we can write it as xpower1/2 so this also in exponential form

but in third option y=x there is no exponential form

Answer:

78 grams

Step-by-step explanation:

20% is 1/5

1/5 of 65 is 13

65 + 13 = 78

brainliest?

Answer:

A) Null hypothesis; H0: μ1 − μ2 ≤ 0

Alternative hypothesis; Ha: μ1 − μ2 > 0

B) Test statistic = t = 1.878

C) p-value is 0.038823.

D) Reject the Null hypothesis H0

Step-by-step explanation:

We are given;

α = 0.05

n1 = 16

n2 = 10

bar x1 = 6.82

bar x2 = 6.28

s1 = 0.65

s2 = 0.75

A) The hypothesis is as follows;

Null hypothesis; H0: μ1 − μ2 ≤ 0

Alternative hypothesis; Ha: μ1 − μ2 > 0

B) Formula yo determine the test statistic is;

t = ((bar x1) - (bar x))/√((s1)²/n1) + (s2)²/n2))

Plugging in the relevant values, we have;

t = (6.82 - 6.28)/√((0.65)²/16) + (0.75)²/10))

t = 0.54/√(0.02640625 + 0.05625)

t = 0.54/0.2875

t = 1.878

C) The formula for the degree of freedom is;

Δ = [(s1)²/n1) + (s2)²/n2))]²/[((s1²/n1)²/(n1 - 1)) + ((s2²/n2)²/(n1 - 1))  

Plugging in the relevant values, we have;

Δ = [(0.65)²/16) + (0.75)²/10))]²/[((0.65²/16)²/(16 - 1)) + ((0.75²/10)²/(10 - 1))  

Δ = 0.00683205566/(0.000046486 + 0.0003515625)

Δ ≈ 17

Thus, the P-value;

From online p-value calculator from t-score and DF which i attached, we have the p-value as;

The p-value is 0.038823.

D) The p-value result is significant at p < 0.05

Thus, we reject the Null hypothesis H0

A) Null hypothesis: μ1 − μ2 ≤ 0

B) Test statistic = t = 1.878

C) The p-value is 0.038823.

D) Reject the Null hypothesis H0.

What all information we have ?

α = 0.05

n1 = 16

n2 = 10

bar x1 = 6.82

bar x2 = 6.28

s1 = 0.65

s2 = 0.75

Part A)

The hypothesis is as follows;

Null hypothesis; H0: μ1 − μ2 ≤ 0

Alternative hypothesis; Ha: μ1 − μ2 > 0

Part B)

The formula to determine the test statistic is :

t = ((bar x1) - (bar x))/√((s1)²/n1) + (s2)²/n2))

t = (6.82 - 6.28)/√((0.65)²/16) + (0.75)²/10))

t = 0.54/√(0.02640625 + 0.05625)

t = 0.54/0.2875

t = 1.878

The formula to determine the test statistic is t = 1.878.

Part C)

The formula for the degree of freedom is;

Δ = [(s1)²/n1) + (s2)²/n2))]²/[((s1²/n1)²/(n1 - 1)) + ((s2²/n2)²/(n1 - 1))  

Δ = [(0.65)²/16) + (0.75)²/10))]²/[((0.65²/16)²/(16 - 1)) + ((0.75²/10)²/(10 - 1))  

Δ = 0.00683205566/(0.000046486 + 0.0003515625)

Δ ≈ 17

Thus, the P-value is 0.038823.

Part D)

The p-value result is significant at p < 0.05 is :

Thus, we reject the Null hypothesis H0.

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Answer:

A. [tex]\frac{9}{10}[/tex]

B. 1

C. [tex]\frac{2}{6}[/tex] or [tex]\frac{1}{3}[/tex]

D. [tex]\frac{2}{30}[/tex] or [tex]\frac{1}{15}[/tex]

E. [tex]\frac{12}{70}[/tex] or [tex]\frac{6}{35}[/tex]

F. [tex]\frac{6}{90}[/tex] or [tex]\frac{1}{15}[/tex]

G. [tex]\frac{9}{32}[/tex]

H. [tex]\frac{4}{15}[/tex]

Answer:

Step-by-step explanation:

Reducing the given expressions to the lowest terms:

A. 3/10 + 6/10:

B. 1/3 + 1/4 + 1/6:

C. 5/6-3/6:

D. 2/3-6/10:

E. 4/10*3/7:

F. 1/6*6/15:

G. 1/8 divided by 4/9:

H. 1/5 divided by 3/4:

Answer:

NO

Step-by-step explanation:

━━━━━━━☆☆━━━━━━━

▹ Answer

-17 isn't a natural number

▹ Step-by-Step Explanation

Positive integers are only natural numbers, meaning negative numbers aren't natural numbers.

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

Answer:

C(d) = d(2.25) + m(0.3)

Step-by-step explanation:

A taxi company charges $2.25 per ride plus $0.30 per mile.

Let d represent number of rides..

Let m represent number of Miles...

Then let C represent the total cost for each ride at a specific number of Miles.

The linear model representing the cost as a function of d the total ride

C(d) = d(2.25) + m(0.3)

The values stand independently because the customer can choose a different right and a different mile.

Answer:

35 students

Step-by-step explanation:

Take the number of students in the class and multiply by 60% and see if you get an integer number

28 * .60 =16.8  not an integer

32 * .6 =19.2

35 * .6 =21  yes

39*.6 =23.4

Answer:

D.

Step-by-step explanation:

A) ∠V and ∠Y is not the alternate interior angles.

B)∠W and ∠Z is not the alternate interior angles.

C) Not this one because the reflexive property of congruence means that an angle, line segment, or shape is always congruent to itself.

D)∠VXW ≅∠ZXY because they are vertical. ∠W≅∠Y because they are right angles. So, triangles are similar by AA.

Answer:

QS

Step-by-step explanation:

The side opposite to the smallest angle must be the shortest side. The smallest angle is ∠R so the opposite side is QS.

Answer:

Hey there!

Smaller angles are opposite smaller sides, so the side opposite to angle R would be the shortest. (Or side SQ)

Hope this helps :)

Answer:

0.3 m/s

Step-by-step explanation:

The first thing is to attach the allusive graphic to the question. Now yes, let's move on to the solution that would be:

If the through is completely filtered the its volume will:

V = l * [1/2 w * h] = 1/2 l * w * h

Now we derive with respect to time and we are left with:

dV / dt = 1/2 * l * w * dh / dt

We solve by dh / dt and we have:

dh / dt = (2 / (l * w)) * (dV / dt)

We know that l = 8 and w = 5, in addition to dV / dt = 6, we replace:

dh / dt = (2 / (8 * 5)) * (6)

dh / dt = 0.3

Therefore the rate at which the height of the water changes is 0.3 m / s

Answer:

a) D. Reject the null hypothesis. There is sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20.

b) C. Do not reject the null hypothesis. There is not sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20.

Step-by-step explanation:

a) We have a hypothesis test with the following hypothesis:

[tex]H_0: \mu=20\\\\H_a:\mu> 20[/tex]

The significance level is 0.05 for this right-tailed test.

The sample size is n=17.

This means we have 16 degrees of freedom.

[tex]df=n-1=17-1=16[/tex]

The test statistic has already been calculated and has a value of t=3.1.

This test is a right-tailed test, with 16 degrees of freedom and t=3.1, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t>3.1)=0.0034[/tex]

As the P-value (0.0034) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that the new paint has a reflectometer reading higher than 20.

b. The hypothesis are the same as point a:

[tex]H_0: \mu=20\\\\H_a:\mu> 20[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=10-1=9[/tex]

The significance level is 0.01.

The test statistic has already been calculated and has a value of t=1.8.

This test is a right-tailed test, with 9 degrees of freedom and t=1.8, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t>1.8)=0.0527[/tex]

As the P-value (0.0527) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.01, there is not enough evidence to support the claim that the new paint has a reflectometer reading higher than 20.