Find the equivalent function of sin(180+x)

Answers

Answer 1

Answer:

The equivalent function of [tex]sin\left(180^{\circ }+x\right)[/tex] will be: [tex]-\sin \left(x\right)[/tex]

i.e.

[tex]\sin \left(180^{\circ \:}+x\right)=-\sin \left(x\right)[/tex]

Step-by-step explanation:

Considering the function

[tex]sin\left(180^{\circ }+x\right)[/tex]

Solving

[tex]sin\left(180^{\circ }+x\right)[/tex]

Using the angle sum identity:

[tex]\sin \left(s+t\right)=\sin \left(s\right)\cos \left(t\right)+\cos \left(s\right)\sin \left(t\right)[/tex]

[tex]=\sin \left(180^{\circ \:}\right)\cos \left(x\right)+\cos \left(180^{\circ \:}\right)\sin \left(x\right)[/tex]

as

[tex]\cos \left(180^{\circ \:}\right)=\left(-1\right)[/tex]

[tex]\sin \left(180^{\circ \:}\right)=0[/tex]

so

[tex]=0\cdot \:\cos \:\left(x\right)+\left(-1\right)\cdot \:\sin \:\left(x\right)[/tex]

[tex]=0\cdot \cos \left(x\right)-1\cdot \sin \left(x\right)[/tex]

[tex]=0-1\cdot \sin \left(x\right)[/tex]

[tex]=0-\sin \left(x\right)[/tex]

[tex]=-\sin \left(x\right)[/tex]

So, the equivalent function of [tex]sin\left(180^{\circ }+x\right)[/tex] will be: [tex]-\sin \left(x\right)[/tex]

Therefore:

[tex]\sin \left(180^{\circ \:}+x\right)=-\sin \left(x\right)[/tex]


Related Questions

If it exists, solve for the inverse function of each of the following:
1. f(x) = 25x - 18
6. gala? +84 - 7
7. 10) = (b + 6) (6-2)
3. A(7)=-=-
4. f(x)=x
9. h(c) = V2c +2
+30
10. f(x) =
5. f(a) = a +8
ox-1
2. 9(x) = -1
2x+17
8. () - 2*​

Answers

Answer:

The solution is too long. So, I included them in the explanation

Step-by-step explanation:

This question has missing details. However, I've corrected each question before solving them

Required: Determine the inverse

1:

[tex]f(x) = 25x - 18[/tex]

Replace f(x) with y

[tex]y = 25x - 18[/tex]

Swap y & x

[tex]x = 25y - 18[/tex]

[tex]x + 18 = 25y - 18 + 18[/tex]

[tex]x + 18 = 25y[/tex]

Divide through by 25

[tex]\frac{x + 18}{25} = y[/tex]

[tex]y = \frac{x + 18}{25}[/tex]

Replace y with f'(x)

[tex]f'(x) = \frac{x + 18}{25}[/tex]

2. [tex]g(x) = \frac{12x - 1}{7}[/tex]

Replace g(x) with y

[tex]y = \frac{12x - 1}{7}[/tex]

Swap y & x

[tex]x = \frac{12y - 1}{7}[/tex]

[tex]7x = 12y - 1[/tex]

Add 1 to both sides

[tex]7x +1 = 12y - 1 + 1[/tex]

[tex]7x +1 = 12y[/tex]

Make y the subject

[tex]y = \frac{7x + 1}{12}[/tex]

[tex]g'(x) = \frac{7x + 1}{12}[/tex]

3: [tex]h(x) = -\frac{9x}{4} - \frac{1}{3}[/tex]

Replace h(x) with y

[tex]y = -\frac{9x}{4} - \frac{1}{3}[/tex]

Swap y & x

[tex]x = -\frac{9y}{4} - \frac{1}{3}[/tex]

Add [tex]\frac{1}{3}[/tex] to both sides

[tex]x + \frac{1}{3}= -\frac{9y}{4} - \frac{1}{3} + \frac{1}{3}[/tex]

[tex]x + \frac{1}{3}= -\frac{9y}{4}[/tex]

Multiply through by -4

[tex]-4(x + \frac{1}{3})= -4(-\frac{9y}{4})[/tex]

[tex]-4x - \frac{4}{3}= 9y[/tex]

Divide through by 9

[tex](-4x - \frac{4}{3})/9= y[/tex]

[tex]-4x * \frac{1}{9} - \frac{4}{3} * \frac{1}{9} = y[/tex]

[tex]\frac{-4x}{9} - \frac{4}{27}= y[/tex]

[tex]y = \frac{-4x}{9} - \frac{4}{27}[/tex]

[tex]h'(x) = \frac{-4x}{9} - \frac{4}{27}[/tex]

4:

[tex]f(x) = x^9[/tex]

Replace f(x) with y

[tex]y = x^9[/tex]

Swap y with x

[tex]x = y^9[/tex]

Take 9th root

[tex]x^{\frac{1}{9}} = y[/tex]

[tex]y = x^{\frac{1}{9}}[/tex]

Replace y with f'(x)

[tex]f'(x) = x^{\frac{1}{9}}[/tex]

5:

[tex]f(a) = a^3 + 8[/tex]

Replace f(a) with y

[tex]y = a^3 + 8[/tex]

Swap a with y

[tex]a = y^3 + 8[/tex]

Subtract 8

[tex]a - 8 = y^3 + 8 - 8[/tex]

[tex]a - 8 = y^3[/tex]

Take cube root

[tex]\sqrt[3]{a-8} = y[/tex]

[tex]y = \sqrt[3]{a-8}[/tex]

Replace y with f'(a)

[tex]f'(a) = \sqrt[3]{a-8}[/tex]

6:

[tex]g(a) = a^2 + 8a- 7[/tex]

Replace g(a) with y

[tex]y = a^2 + 8a - 7[/tex]

Swap positions of y and a

[tex]a = y^2 + 8y - 7[/tex]

[tex]y^2 + 8y - 7 - a = 0[/tex]

Solve using quadratic formula:

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]a = 1[/tex] ; [tex]b = 8[/tex]; [tex]c = -7 - a[/tex]

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes

[tex]y = \frac{-8 \±\sqrt{8^2 - 4 * 1 * (-7-a)}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{64 + 28 + 4a}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 }[/tex]

Factorize

[tex]y = \frac{-8 \±\sqrt{4(23 + a)}}{2 }[/tex]

[tex]y = \frac{-8 \±2\sqrt{(23 + a)}}{2 }[/tex]

[tex]y = -4 \±\sqrt{(23 + a)}[/tex]

[tex]g'(a) = -4 \±\sqrt{(23 + a)}[/tex]

7:

[tex]f(b) = (b + 6)(b - 2)[/tex]

Replace f(b) with y

[tex]y = (b + 6)(b - 2)[/tex]

Swap y and b

[tex]b = (y + 6)(y - 2)[/tex]

Open Brackets

[tex]b = y^2 + 6y - 2y - 12[/tex]

[tex]b = y^2 + 4y - 12[/tex]

[tex]y^2 + 4y - 12 - b = 0[/tex]

Solve using quadratic formula:

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]a = 1[/tex] ; [tex]b = 4[/tex]; [tex]c = -12 - b[/tex]

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes

[tex]y = \frac{-4\±\sqrt{4^2 - 4 * 1 * (-12-b)}}{2*1}[/tex]

[tex]y = \frac{-4\±\sqrt{4^2 - 4 *(-12-b)}}{2}[/tex]

Factorize:

[tex]y = \frac{-4\±\sqrt{4(4 - (-12-b))}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{(4 - (-12-b))}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{(4 +12+b)}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{16+b}}{2}[/tex]

[tex]y = -2\±\sqrt{16+b}[/tex]

Replace y with f'(b)

[tex]f'(b) = -2\±\sqrt{16+b}[/tex]

8:

[tex]h(x) = \frac{2x+17}{3x+1}[/tex]

Replace h(x) with y

[tex]y = \frac{2x+17}{3x+1}[/tex]

Swap x and y

[tex]x = \frac{2y+17}{3y+1}[/tex]

Cross Multiply

[tex](3y + 1)x = 2y + 17[/tex]

[tex]3yx + x = 2y + 17[/tex]

Subtract x from both sides:

[tex]3yx + x -x= 2y + 17-x[/tex]

[tex]3yx = 2y + 17-x[/tex]

Subtract 2y from both sides

[tex]3yx-2y =17-x[/tex]

Factorize:

[tex]y(3x-2) =17-x[/tex]

Make y the subject

[tex]y = \frac{17 - x}{3x - 2}[/tex]

Replace y with h'(x)

[tex]h'(x) = \frac{17 - x}{3x - 2}[/tex]

9:

[tex]h(c) = \sqrt{2c + 2}[/tex]

Replace h(c) with y

[tex]y = \sqrt{2c + 2}[/tex]

Swap positions of y and c

[tex]c = \sqrt{2y + 2}[/tex]

Square both sides

[tex]c^2 = 2y + 2[/tex]

Subtract 2 from both sides

[tex]c^2 - 2= 2y[/tex]

Make y the subject

[tex]y = \frac{c^2 - 2}{2}[/tex]

[tex]h'(c) = \frac{c^2 - 2}{2}[/tex]

10:

[tex]f(x) = \frac{x + 10}{9x - 1}[/tex]

Replace f(x) with y

[tex]y = \frac{x + 10}{9x - 1}[/tex]

Swap positions of x and y

[tex]x = \frac{y + 10}{9y - 1}[/tex]

Cross Multiply

[tex]x(9y - 1) = y + 10[/tex]

[tex]9xy - x = y + 10[/tex]

Subtract y from both sides

[tex]9xy - y - x = y - y+ 10[/tex]

[tex]9xy - y - x = 10[/tex]

Add x to both sides

[tex]9xy - y - x + x= 10 + x[/tex]

[tex]9xy - y = 10 + x[/tex]

Factorize

[tex]y(9x - 1) = 10 + x[/tex]

Make y the subject

[tex]y = \frac{10 + x}{9x - 1}[/tex]

Replace y with f'(x)

[tex]f'(x) = \frac{10 + x}{9x -1}[/tex]

what is 4.25% as a decimal ​

Answers

Answer:

0.0425

Step-by-step explanation:

Answer:

0.0425

Step-by-step explanation:

hope this helped ^^

Molly and Cody are selling pies for a school fundraiser. Customers can buy apple pies and
pumpkin pies. Molly sold 1 apple pie and 13 pumpkin pies for a total of $160. Cody sold 14
apple pies and 7 pumpkin pies for a total of $140. What is the cost each of one apple pie and one
pumpkin pie?

Answers

Answer:

12 dollars and 6

Step-by-step explanation:

12 divided by 160 = 12

Sove the equation for all real solutions
-d^2-12d+4=-6d^2​

Answers

Answer:

d=25 or d=2

Step-by-step explanation:

hope that helps!

Answer:

d=2/5 or d=2

Step-by-step explanation:

Step 1: Subtract -6d^2 from both sides.

−d2−12d+4−−6d2=−6d2−−6d2

5d2−12d+4=0

Step 2: Factor left side of equation.

(5d−2)(d−2)=0

Step 3: Set factors equal to 0.

5d−2=0 or d−2=0

d= 2/5 or d=2

Find the slope given the two points:
(3, 70) , (15, 90)

Answers

Answer:

x= 5/3

Step-by-step explanation:

I need help with this

Answers

Answer:

A, B, and C

Step-by-step explanation:

We can substitute each number into each equation

2 < -1 + 5 true

2 > 1 true

1 > 0 true

A is correct

4 < -1 + 5 true

4 > 1 true

1 > 0 true

B is correct

3 < -0 + 5 true

3 > 0 true

0 > 0 true

C is correct

5 < -2 + 5 false

D is incorrect

What are the zeros of this function

Answers

There is no picture attached, but zeroes mean x values.

1. At the beginning of the year, Maria had $100 in her savings account. She plans to spend $10 a
month on a music app. By the end of January, she will have $90, 580 by the end of February,
$70 by the end of March, and so on. Write an equation that describes the amount in her savings
at any given month. Be sure to describe what your variables represent.

Answers

100-10x=y the x represents the months and the y represents the money left

I will mark brainly if anyone can answer this
-2-4(6p-5)
-5(v-6)+10v
and 25 pts

Answers

Answer:

Ich weiß nicht =13

die Antwort -2 -4 (6p-5)

Step-by-step explanation:

PLEASE HELP ME WITH MY MATHE HOMEWORK!

Answers

Answer:

59/6

Step-by-step explanation:

9x6=54

54+5= 59

put the denominator of the fraction to the denominator to the new fraction. I hope this helps.

Which is greatest: 75%, 4/5, or 0.75?

Answers

Answer:

4/5

Step-by-step explanation:

75% = 75/100 = 0.75 = 3/4

4/5 = 80/100 = 80% = 0.80

75 = 75% = 3/4 = 75/100

75%

80% - this is the biggest

75%

HOPE THIS HELPS

PLZZ MARK BRAINLIEST

Answer: 4/5

Step-by-step explanation:

75% = 75/100 same as 0.75

4/5 = 0.80

0.75 already in decimal

Therefore 0.80 is the greatest

The product of 5 and a number x is 1/4 What is the value of x?
x=19/4
x=1/20
x =5/4
x =4 3/4​

Answers

Answer:

x=19/4

Step-by-step explanation:

The product of 5 and a number x is 1/4

Which of the following graphs represents the equation above?

y=1/2x-2

Answers

Answer:

There’s no graphs

Step-by-step explanation:

Answer:

Step-by-step explanation:

Find the missing terms in each geometric sequence.

1. 3, 12, 48 __, __

2. __, __, 32, 64, 128, ...

3. 120, 60, 30, __, __

4. 5, __, 20, 40, __, __

5. __, 4, 12, 36, __, __​

Answers

1. 192, 768 ( it was times 4 )
2. 8, 16 (it was adding the number together 8+8)
3. 15, 7.5 ( it was half of the number)
4. 10, 80, 160 ( times 2 )
5. .75, 108, 324 ( times 4 )

Hope this helped! Lmk if you need more help!

the first blank is 25 the second blank is 10 what is the slope​

Answers

Answer:

5/2

Step-by-step explanation:

25 and 10 so 25/10 or 5/2 or 2 1/2

Jermaine buys T-shirts for $6 each and marks up the price by 45%.
How much does Jermaine charge for each T-shirt (with the mark-up)?

Answers

Answer:

8.7

Step-by-step explanation:

6*1.45=8.7

Find the slope of the line without graphing using the 2 points below.



(-3 , 4) & (13 , 8)



m = _______

Answers

Answer:

Step-by-step explanation:

1. use the slope formula --> (y2-y1)/(x2-x1)

2. (8 - 4)/(13 -(-3))

3. 4/16

4. m = 1/4

SOMEONE ANWSER QUIKLY PLEASE !!!!!


The second of two numbers is one more than twice the first. The sum of the numbers is
40. What are the numbers?

Answers

Answer:

13 + 1/3 and 26+2/3

Step-by-step explanation:

so one is twices a large as the first. so 40/3 = 13 + 1/3 so thats one of your awnsers the larger one is 2 times larger so13 +1/3 * 2 is 26+2/3 hope this helps! :D

Answer:

First Number is 13

Second Number is 27

Step-by-step explanation:

let x = first number

let 2x + 1 = second number

x + (2x + 1) = 40

3x + 1 = 40

    - 1      -1

3x = 39

/3      /3

x = 13

13 x 2 = 26 + 1 = 27

12 IF APOR is similar to AXYZ, which of the following statements must be true?

Answers

Answer:

F

Step-by-step explanation:

There's no Q in APOR or AXYZ


1. Dilate A using P as the center of dilation and a scale factor of 3. Label the new point
A'.
2. Dilate Busing Pas the center of dilation and a scale factor of 2. Label the new point B'

Answers

Answer:

Step-by-step explanation:

Rule for the dilation of a point by a scale factor 'k',

(x, y) → (kx, ky)

If we impose this rule in this problem,

k = [tex]\frac{\text{Distance of A' from P}}{\text{Distance of A from P}}[/tex]

1). If k = 3

   Therefore, Distance of A' from P = 3(Distance of A from P)

   And point A' will be on the third circle.

2). If k = 2

   Distance of B' from P = 2(Distance of B from P)

   Since, B is on circle 2, B' will be on circle 4.

Now we can plot these points A' and B' on the graph.

After the dilation point A becomes A' and it is at a distance of 3 units from point P and after the dilation point B becomes B' and it is at a distance of 2 units from point P.

1)

Given :

Dilate A using P as the center of dilation and a scale factor of 3.

Let the coordinates of point A be (x,y) then after dilation point A becomes A'(3x , 3y). So, the distance of the point A' from the point P is 3 units

2)

Given :

Dilate Busing P as the center of dilation and a scale factor of 2.

Let the coordinates of point B be (x',y') then after dilation point B becomes B'(2x' , 2y'). So, the distance of the point B' from the point P is 2 units

For more information, refer to the link given below:

https://brainly.com/question/2856466

What is the rectangular form of r=8sin(0)

Answers

Step-by-step explanation:

the regular form of r=8

If you earn $134 in 8 hours, how much do you earn per hour?

Answers

Answer:$16.75

Step-by-step explanation:

Please Help

Please let me know how to do it, I don't only want the answer. Thank you!
(4y+3)-(y-2)

(There is no equal sign in the math problem)

Answers

Add like terms. Ignore parenthesis. And change the negative in front of the 2 into a positive. 4y minus y and 3 plus 2 makes... 3y+5

please help i’ll give brainliest

Answers

Answer:

87.5

Step-by-step explanation:

2 inches is 70 miles. .5 inches is 17.5 and add them together and you get 87.5.

Please mark brainliest.

Answer: D. 87.5 miles

Step-by-step explanation:

They have given us a scale that 1 inch = 35 miles.

Since the distance is 2.5 inches, we have to multiply 2.5 inches by 35 miles.

1 in. = 35 miles

2.5 in = x

2.5 times 35 = 87.5 miles

hope this helps!

what is 9 time 64 what does it equal to

Answers

Answer:

It's 576 if you mean 64 times 9!

Step-by-step explanation:

z = 24a - 2b

solve for a​

Answers

Answer:

a= (Z + 2b)/24

Step-by-step explanation:

given:

Z = 24a - 2b

to solve for a, we will try to move "a" to one side of the equation and all other terms to the other side:

Z = 24a - 2b    (add 2b to both sides)

Z + 2b = 24a -2b +2b

Z + 2b = 24a  (switch sides)

24a = Z + 2b (divide both sides by 24)

a/24 = (Z + 2b)/24

a= (Z + 2b)/24

I WILL GIVE THE BRAINLIEST
Jack works after school. each day he earns a set amount, plus an hourly wage. the following table represents a linear function f jack can use to determine to his pay.
hours: 1, 2, 3 | Pay: 18, 28, 38
SLOPE is 10.
Using the slope, find the y-intercept and write the function.​

Answers

Answer:

The y intercept is (0, 8). The equation of the function is f(x) = 10x + 8

Step-by-step explanation:

Given that after 1 hour of work, Jack will make 18 dollars and the slope is 10, subtract 10 dollars from 18 dollars to find his set amount, or y-intercept.

18 - 10 = 8 dollars.

Now that we have the m and b values, we can create our equation.

The equation in standard form is f(x) = mx +b, where m = the slope and b = the y-intercept. Plug our values in and the equation will be f(x) = 10x + 8. You can test if this is correct by plugging in x values from the table and seeing if your calculated value correctly corresponds to the given y value in the table.

the time, t, in seconds, is required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters is given this equation

Answers

Answer:

C. [tex] d = \frac{at^2}{2} [/tex]

Step-by-step explanation:

Given:

[tex] t = \sqrt{\frac{2d}{a}} [/tex]

Required:

Make d the subject of the formula.

SOLUTION:

[tex] t = \sqrt{\frac{2d}{a}} [/tex]

Square both sides

[tex] t^2 = (\sqrt{\frac{2d}{a}})^2 [/tex]

[tex] t^2 = \frac{2d}{a} [/tex]

Multiply both sides by a

[tex] a*t^2 = \frac{2d}{a}*a [/tex]

[tex] at^2 = 2d [/tex]

Divide both sides by 2

[tex] \frac{at^2}{2} = \frac{2d}{2} [/tex]

[tex] \frac{at^2}{2} = d [/tex]

[tex] d = \frac{at^2}{2} [/tex]

32a + 28 = 0
(Factor completely.)

Answers

Answer:           0.875

Step-by-step explanation:

Which property should be used next in this solution process?
3x + 2 + 3 = 7(x - 1) – 4
3x + 5 = 7(x - 1) – 4
A. Commutative Property of Addition
B. Identity Property of Multiplication
C. Associative Property of Multiplication
D.
Distributive Property

Answers

Answer:

niwebfasfbjsdfb

Step-by-step explanation:

jsdfhsdbfjhadsjbdsfhb

the answer would be d
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