find the equation of the line passing through the points (2,4) and (3,2). find both green and grey box

Answer:

  Mark the points of intersection between circle A and line AB.

Step-by-step explanation:

The attached shows an inscribed square created using technology. We started with point A and B, drew the circle with radius AB, and drew the line AB. Then we marked point C at the intersection of circle A and line AB.

We had a perpendicular to AB drawn through A, and marked its intersection with circle A as points D and E. Finally, we drew inscribed square BDCE.

__

Other answer choices may somehow be involved. We'd need to see the construction to be sure. The one shown above seemed most likely.

Answer:

Options (3), (4), and (5).

Step-by-step explanation:

From the figure attached,

∠JKM is a straight angle on a segment JKM.

PK is a perpendicular drawn on segment JKM at point K.

Option (1). [tex]\overrightarrow{KQ}[/tex] is a angle bisector

Not True.

Option (2). ∠LKQ is bisected.

Not True.

Option (3). m∠JKL = 45°

Since [tex]\overrightarrow{KL}[/tex] is an angle bisector of angle JKP which is equal to 90°.

True.

Option (4). m∠MKQ + m∠PKQ = m∠PKM

True.

Option (5). [tex]\overrightarrow{PK}[/tex] is a angle bisector.

Since [tex]\overrightarrow{PK}[/tex] is an angle bisector of straight angle JKM.

True.

Option (6). ∠JKL ≅ ∠QKM

Not True.

Therefore, options (3), (4) and (5) are correct.

Answer:

$94.125

Step-by-step explanation:

Answer:

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.025}{1.28})^2}=655.36[/tex]  

And rounded up we have that n=656

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 80% of confidence, our significance level would be given by [tex]\alpha=1-0.80=0.20[/tex] and [tex]\alpha/2 =0.10[/tex]. And the critical value would be given by:

[tex]z_{\alpha/2}=\pm 1.28 [/tex]

Solution to the problem

The margin of error for the proportion interval is given by this formula:  

[tex] ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]    (a)  

Since we don't have prior info for the proportion of interest we can use [tex]\hat p=0.5[/tex] as estimator. And on this case we have that [tex]ME =\pm 0.025[/tex] and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

[tex]n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}[/tex]   (b)  

And replacing into equation (b) the values from part a we got:

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.025}{1.28})^2}=655.36[/tex]  

And rounded up we have that n=656

Answer:

The graph of the probability density function is attached.

Step-by-step explanation:

The probability function for this random number generator will be like the uniform distribution and defined for X ∈ [0, 1].

The probability density function can be written as:

[tex]f(x)={\begin{cases}{\dfrac {1}{1-0}}=1&\mathrm {for} \ 0\leq x\leq 1,\\[8pt]0&\mathrm {for} \ x<0\ \mathrm {or} \ x>1\end{cases}}[/tex]

The graph of the probability density function is attached.

Answer:

3| 4 4 7

4| 0 3 4

5| 5 5 5

6| 0 1 3 8 9

7| 9

8| 1 4 6 8

hope it helps!

Step-by-step explanation:

Check the numbers and list out the tens digit in stem (that is 3-8) and then write the corresponding leaf values

Answer:

The answer is option B

Step-by-step explanation:

Since 12 is greater than - 6

Hope this helps

Answer:

12 > -6

Step-by-step explanation:

A positive number is always greater than a negative number

12 > -6

Answer:

20

Step-by-step explanation:

If the two triangles are similar, then corresponding sides must share a constant ratio. This means that:

[tex]\dfrac{10}{6}=\dfrac{25}{15}=\dfrac{x}{12}[/tex]

Let's use the second ratio:

[tex]\dfrac{25}{15}=\dfrac{x}{12}[/tex]

Multiply both sides by 12:

[tex]\dfrac{25\cdot 12}{15}=x \\\\x=20[/tex]

Hope this helps!

Answer:

24

Step-by-step explanation:

hello

let's note x the number we are looking for

[tex]\dfrac{x}{12}=6\\<=> x = 6*12=72[/tex]

so 1/3 of it equals

[tex]\dfrac{72}{3}=24[/tex]

another way to see it is that 12=4*3

so 1/3 of it equals 6*4=24

hope this helps

a² + b² = c²

5² + 12² = c²

25 + 144 = c²

169 = c²

c = √169

c = 13

Answer:

the answer is 13

Step-by-step explanation:

Answer:

20%

Step-by-step explanation:

Answer:

20%

Step-by-step explanation: All you have to do is 16 divided by 80 which is 0.2. 0.2 as a decimal is 20%.

Answer:

let’s make a Unit rate.

$20/4 hours = $5 per hour

So you earn $5 in 1 hour if you earn $20 in 4 hours.

hope this helps and pls mark me brainliest if it did ;)

Answer:

$5

Step-by-step explanation:

Let's set up a proportion using the following setup.

money/hours=money/hours

We know that $20 is earned in 4 hours. We don't know how much is earned in 1 hour, so we can say $x is earned in 1 hour.

$20/4 hours= $x/1 hour

20/4=x/1

x/1 is equal to x.

20/4=x

Divide 20 by 4.

5=x

$5 is earned in 1 hour.

Answer:

Standard errors are 0.049, 0.035, 0.022, and 0.016.

Step-by-step explanation:

The given value of population proportion (P) = 0.56

Given sample sizes (n ) 100, 200, 500, and 1000.

Now standard error is required to calculate.

Use the below formula to find standard error.

When sample size is n = 100

[tex]\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{100}} =0.049[/tex]

When sample size is n = 200

[tex]\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{200}} = 0.035[/tex]

When sample size is n = 500

[tex]\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{500}} =0.022[/tex]

When sample size is n = 1000

[tex]\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{1000}} = 0.016[/tex]

Answer:

107.9 ft

Step-by-step explanation:

Imagine Kite is a point A. The person ,who keeps the string is point B.

The height of flying is AC=85 ft.  So we have right triangle ABC :angle C=90 degrees, angle B is 52 degrees. Length of AB (triangle ABC hypotenuse) is the length of the string.

AB=AC/sinB=85/sin52=107.8665...=approx 107.9 ft

Answer:

The bounded area  is: [tex]\frac{73}{6}\approx 12.17[/tex]

Step-by-step explanation:

Let's start by plotting the functions that enclose the area, so we can find how to practically use integration. Please see attached image where the area in question has been highlighted in light green. The important points that define where the integrations should be performed are also identified with dots in darker green color. These two important points are: (2, 6) and (3, 1)

So we need to perform two separate integrals and add the appropriate areas at the end. The first integral is that of the difference of function y=x+4 minus function y=(1/3)x , and this integral should go from x = 0 to x = 2 (see the bottom left image with the area in red:

[tex]\int\limits^2_0 {x+4-\frac{x}{3} } \, dx =\int\limits^2_0 {\frac{2x}{3} +4} \, dx=\frac{4}{3} +8= \frac{28}{3}[/tex]

The next integral is that of the difference between [tex]y=-x^2+10[/tex] and the bottom line defined by: y = (1/3) x. This integration is in between x = 2 and x = 3 (see bottom right image with the area in red:

[tex]\int\limits^3_2 {-x^2+10-\frac{x}{3} } \, dx =-9+30-\frac{3}{2} -(-\frac{8}{3} +20-\frac{2}{3} )=\frac{39}{2} -\frac{50}{3} =\frac{17}{6}[/tex]

Now we need to add the two areas found in order to get the total area:

[tex]\frac{28}{3} +\frac{17}{6} =\frac{73}{6}\approx 12.17[/tex]

Answer:

6,720 ways

Step-by-step explanation:

Since in the problem arrangemnt is being asked this is a problem of permutation.

No . of ways of arranging r things out of n things is given by

P(n,r) =   n!/(n-r)!

In the problem given we have to arrange 5 objects from set of 8 objects.

Here n = 8 and p = 5

it can be done in in

P(8,5) =   8!/(8-5)! ways

8!/(8-5)!  = 8!/3! = 8*7*6*5*4*3!/3! = 8*7*6*5*4 = 6,720

Thus,  number of ways to  arrange 5 objects from a set of 8

different objects is P(8,5) =   8!/(8-5)! =  6,720 .

Answer:

x= -24

Step-by-step explanation:

(4+8+x+12)/4=0

4+8+x+12=0

x= -24

Answer:

a. x = 4

b. x = 17.5

Step-by-step explanation:

a. 5x/2 + 1 = 11

5x/2 = 10

5x = 20

x = 4

b. 2x/7 - 3 = 2

2x/7 = 5

2x = 35

x = 35/2

Answer:

a) x = 4

b) x = 17.5

Step-by-step explanation:

a)

(5x)/2 + 1 = 11

(5x)/2 = 10

5x = 20

x = 4

b)

(2x)/7 - 3 = 2

(2x)/7 = 5

2x = 35

x = 17.5

Answer: x=3 y=1

Step-by-step explanation:

Answer:

To solve for x we can write:

x² - y² = 55

x² = y² + 55

x = ±√(y² + 55)

To solve for y:

x² - y² = 55

y² = x² - 55

y = ±√(x² - 55)

Answer:

Step-by-step explanation:

Baltimore orioles : 1,000,000 + 1,000,000 + 500,000

Click 2 full bag and 1 half bag

Kansas city royals : 1,000,000 +500,000

Click 1 full bag and 1 half bag

Newyork Yankees  : 1,000,000 + 1,000,000 + 1,000,000 +1,000,000 +1,000,000 + 500,000

Click 5 full bag + 1 half bag

Answer:

The length of a 95% confidence interval for mean Age is 3.72.

Step-by-step explanation:

The data is provided for the age of 100 adults.

The mean and standard deviation are:

[tex]\bar x=47.8\\\\s=9.3744[/tex]

As the sample size is too large the z-interval will be used for the 95% confidence interval for mean.

The critical value of z for 95% confidence level is, z = 1.96.

The length of a confidence interval is given by:

[tex]\text{Length}=2\cdot z_{\alpha/2}\cdot\frac{s}{\sqrt{n}}[/tex]

           [tex]=2\times 1.96\times\frac{9.3744}{\sqrt{100}}\\\\=3.6747648\\\\\approx 3.67\\\\\approx 3.72[/tex]

Thus, the length of a 95% confidence interval for mean Age is 3.72.

Answer:

r₁ = 3.583cm

V₁= 192.55cm³

r₂= 5.176cm

V₂ = 580.283cm³

r₃ = 5.255cm

V₃ = 607.479cm³

Step-by-step explanation:

assuming circumferences of each balloons are given as follows C₁ = 22.5cm, C₂ = 32.5cm and C₃ = 33cm

Recall C = 2πr

volume of a sphere is 4/3πr³

Answer:

a) x = 94 units/month

b) s = 51.50 units/month

Step-by-step explanation:

The adequate point estimation of the population mean and standard deviation are the sample mean and sample standard deviation.

a) Point estimation of the population (sample mean)

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(94+105+85+94+92)\\\\\\M=\dfrac{470}{5}\\\\\\M=94\\\\\\[/tex]

b) Point estimation of the population standard deviation (sample standard deviation)

[tex]s=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2\\\\\\s=\dfrac{1}{4}((94-94)^2+(105-94)^2+(85-94)^2+(94-94)^2+(92-94)^2)\\\\\\s=\dfrac{206}{4}\\\\\\s=51.50\\\\\\[/tex]

Using statistical concepts, it is found that:

a) The point estimate for the population mean is of: [tex]\overline{x} = 94[/tex]

b) The point estimate for the population standard deviation is of: [tex]s = 7.18[/tex]

Item a:

In this problem, the sample is: 94, 105, 85, 94, 92.

Thus, the mean is:

[tex]\overline{x} = \frac{94 + 105 + 85 + 94 + 92}{5} = 94[/tex]

Item b:

Then:

[tex]s = \sqrt{\frac{(94-94)^2+(105-94)^2+(85-94)^2+(94-94)^2+(92-94)^2}{4}} = 7.18[/tex]

A similar problem is given at https://brainly.com/question/13451786

Answer:

15

Step-by-step explanation:

38=10+13+c

c=38-10-13=15

Hope this helps!

Answer:

A. Repeat the process many times (1000). If 6 correct out of 8 cups rarely occurs, then it is most likely that the woman was just guessing as to what was poured first.

Step-by-step explanation:

Since tossing a coin 8 times implies 8 cups of tea, with the given conditions.

The sample space = 1000

Then;

             [tex]\frac{6}{8}[/tex] × 1000 = 750

If 6 correct out of 8 cups occurs (750 out of 1000), the woman got 750 correctly. Thus it can be inferred that it is likely that she knew what was poured first, either the tea or milk.

But, if 6 correct out of 8 cups rarely occurs (i.e 250 out of 1000), then it is most likely that the woman was just guessing as to what was poured first.

Answer:

The base length (which is the length on MN) is 4 and the height (which is LM) is 6 so the area is 4 * 6 / 2 = 12 sq. units.

Answer:

A) 12 square units

Step-by-step explanation:

On Edge

Answer:

81

Step-by-step explanation:

let the terms be a,ar,ar²

r=2/3

a+a(2/3)+a(2/3)²=171

multiply by 9

9a+6a+4a=171×9

19 a=171×9

a=(171×9)/(19)

a=9×9=81

Answer:

Two factor ANOVA

Step-by-step explanation:

They two factor ANOVA is used to determined if there is an interaction between the two independent variables on the dependent variable which in this case study are

The two independent variables are:

One member of each twin pair gets this early discrimination training, but the other does not.

While the dependent variable is their respective IQ scores.

Thus, we can use this test to determine whether the effect of one of the independent variable is the same for all other values of the other independent variable and vice versa using their IQ scores.

Answer:

88.93% probability that he let through more than 2 goals if the opposite team made 60 shots on goal.

Step-by-step explanation:

For each shot, there are only two possible outcomes. Either he lets it through, or he does not. Shots are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

The goalkeeper of the USA ice hockey National Team, Jonathan Quick, saved 91.6% of shots during his entire career in the NHL.

So he let in a goal in 100 - 91.6 = 8.4% of the shots, so [tex]p = 0.084[/tex]

60 shots:

This means that [tex]n = 60[/tex]

Estimate the probability that he let through more than 2 goals if the opposite team made 60 shots on goal.

Either he lets two or less goals, or he lets more than 2. The sum of the probabilities of these outcomes is 1. So

[tex]P(X \leq 2) + P(X > 2) = 1[/tex]

We want [tex]P(X > 2)[/tex].

Then

[tex]P(X > 2) = 1 - P(X \leq 2)[/tex]

In which

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{60,0}.(0.084)^{0}.(0.916)^{60} = 0.0052[/tex]

[tex]P(X = 1) = C_{60,1}.(0.084)^{1}.(0.916)^{59} = 0.0285[/tex]

[tex]P(X = 2) = C_{60,2}.(0.084)^{2}.(0.916)^{58} = 0.0770[/tex]

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0052 + 0.0285 + 0.0770 = 0.1107[/tex]

[tex]P(X > 2) = 1 - P(X \leq 2) = 1 - 0.1107 = 0.8893[/tex]

88.93% probability that he let through more than 2 goals if the opposite team made 60 shots on goal.