Find the area of an 11-gon with side length 5 inches.

Answer: the answer is 48 inches

Step-by-step explanation:

Answer:

It must be number 2.

1 and 3 number is wrong as parallelogram don't need have right angle

Answer:

Step-by-step explanation:

(2u+3u)(u+v)-2u+3v

=2u(u+v)+3u(u+v)-2u+3v

=2u^2+2uv+3u^2+3uv-2u+3v

=5u^2+5uv-2u+3v

Answer:

Para un vaso de [tex]V = 25\pi\,cm^{3}[/tex], las dimensiones del vaso son [tex]r \approx 2.321\,cm[/tex] y [tex]h \approx 4.642\,cm[/tex].

Para un vaso de [tex]V = 1000\,cm^{3}[/tex], las dimensiones del vaso son [tex]r \approx 5.419\,cm[/tex] y [tex]h \approx 10.839\,cm[/tex].

Step-by-step explanation:

El vaso se puede modelar como un cilindro recto. El enunciado pregunta por las dimensiones del vaso tal que su área superficial ([tex]A_{s}[/tex]), en centímetros cuadrados, sea mínima para el volumen dado ([tex]V[/tex]), en centímetros cúbicos. Las ecuaciones de volumen y área superficial son, respectivamente:

[tex]V = \pi\cdot r^{2}\cdot h[/tex] (1)

[tex]A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r\cdot h[/tex] (2)

De (1):

[tex]h = \frac{V}{\pi\cdot r^{2}}[/tex]

En (2):

[tex]A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot \left(\frac{V}{\pi\cdot r} \right)[/tex]

[tex]A_{s} = 2\cdot \left(\pi\cdot r^{2}+V\cdot r^{-1} \right)[/tex]

Asumamos que [tex]V[/tex] es constante, la primera y segunda derivadas de la función son, respectivamente:

[tex]A'_{s} = 2\cdot (2\pi\cdot r -V\cdot r^{-2})[/tex]

[tex]A'_{s} = 4\pi\cdot r - 2\cdot V\cdot r^{-2}[/tex] (3)

[tex]A''_{s} = 4\pi + 4\cdot V \cdot r^{-3}[/tex] (4)

Si igualamos [tex]A'_{s}[/tex] a cero, entonces hallamos los siguientes puntos críticos:

[tex]4\pi\cdot r - 2\cdot V\cdot r^{-2} = 0[/tex]

[tex]4\pi\cdot r = 2\cdot V\cdot r^{-2}[/tex]

[tex]4\pi\cdot r^{3} = 2\cdot V[/tex]

[tex]r^{3} = \frac{V}{2\pi}[/tex]

[tex]r = \sqrt[3]{\frac{V}{2\pi} }[/tex] (5)

Ahora, si aplicamos este valor a (4), tenemos que:

[tex]A_{s}'' = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }[/tex]

[tex]A''_{s} = 4\pi + 8\pi[/tex]

[tex]A_{s}'' = 12\pi[/tex] (6)

De acuerdo con este resultado, el valor crítico está asociado al área superficial mínima. Ahora, la altura se calcula a partir de (5) y (1):

[tex]h = \frac{V}{\pi\cdot \left(\frac{V}{2\pi} \right)^{2/3} }[/tex]

[tex]h = \frac{2^{2/3}\cdot \pi^{2/3}\cdot V}{\pi\cdot V^{2/3}}[/tex]

[tex]h = \frac{2^{2/3}\cdot V^{1/3}}{\pi^{1/3}}[/tex]

Si [tex]V = 25\pi\,cm^{3}[/tex], entonces las dimensiones del vaso son:

[tex]r = \sqrt[3]{\frac{25\pi\,cm^{3}}{2\pi} }[/tex]

[tex]r \approx 2.321\,cm[/tex]

[tex]h = \frac{2^{2/3}\cdot (25\pi\,cm^{3})^{1/3}}{\pi^{1/3}}[/tex]

[tex]h \approx 4.642\,cm[/tex]

Un litro equivale a 1000 centímetros cúbicos, las dimensiones del vaso son:

[tex]r = \sqrt[3]{\frac{1000\,cm^{3}}{2\pi} }[/tex]

[tex]r \approx 5.419\,cm[/tex]

[tex]h = \frac{2^{2/3}\cdot (1000\,cm^{3})^{1/3}}{\pi^{1/3}}[/tex]

[tex]h \approx 10.839\,cm[/tex]

Answer:

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Step-by-step explanation:

3 adults and 1 child go to a park. The admission fee for adults is x, and the fee for children is y. They spent a total of 15 dollars. Solve for x and y.

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hope it helps

sorry if it doesn't. I'm the person who solves the problems, not creates them

Answer:

B

Step-by-step explanation:

they rest The two by five and separate the square

Answer:

this is good looking nice photo but li can't give you answer of that sorry.

Step-by-step e this https://www.commonlit.org/en/students/student_lesson_activities

all of the above which is e

Answer:

perimeter for rectangle: (x-2+x+2)×2=4x

perimeter for triangle : 2x-8+2x-8+x+6

=5x-10

The question said both geometry has same perimeter,so we have equation :

4x=5x-10

=>x= 10

put x in triangle's perimeter: 2×10-8+2×10-8+10+6

= 40

Step-by-step explanation:

the answer is C, hope you understand it

Answer:

11 hours

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:   5 25  14 02

herb garden is 1/8 The area of her vegetable garden

herb garden is 6 square feet

vegetable garden = ???

herb garden / vegetable garden  =   1/8      solve for vegetable garden

herb garden × 8  =  vegetable garden

       6 ft² ×  8  =  __________ ft²      

Answer:

A. A triangle can be equilateral and obtuse at the same time

Step-by-step explanation:

All angles in an equilateral triangle are 60° therefore they cannot be above 90° and less than 180°

Answer: I believe it is C.

Step-by-step explanation: Because if you take 4 x 20 = 80

If  I am wrong sorry.

Answer:

228.9

Step-by-step explanation:

Answer:

228.6

Step-by-step explanation:

Multiply the inches by 2.54

90 x 2.54 = 228.6

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

57.5

Step-by-step explanation:

The expected frequency of West Campus and Failed :

Let :

Failed = F

East Campus = C

West Campus = W

Passed = P

Frequency of FnW :

[(FnE) + (FnW) * (PnW) + (FnW)] / total samples

[(52 + 63) * (63 + 37)] / 200

[(115 * 100)] / 200

11500 / 200

= 57.5

n(Failed n East campus)

Answer:

57.5

Step-by-step explanation:

Got it right on the test.

Answer:

SA = 484 cm²

Step-by-step explanation:

Surface area of the composite figure = surface area of the larger rectangular prism + (surface area of the smaller rectangular prism - base area of the smaller rectangular prism)

✔️Surface are of the larger rectangular prism = 2(LW + LH + WH)

L = 7 cm

W = 7 cm

H = 12 cm

S.A = 2(7*7 + 7*12 + 7*12) = 434 cm²

✔️Surface are of the smaller rectangular prism = 2(LW + LH + WH)

L = 7 cm

W = 2 cm

H = 2 cm

S.A = 2(7*2 + 7*2 + 2*2) = 64 cm²

✔️Base area of the smaller rectangular prism = L*W

L = 7 cm

W = 2 cm

Area = 7*2 = 14 cm²

✅Surface area of the composite figure = 434 + (64 - 14)

= 434 + 50

= 484 cm²

Answer and Step-by-step explanation:

To find the value of x, set the sides BC and AD equal to each other (we can do this because we are told that the figure is a parallelogram, and those sides are congruent as stated in the properties of a parallelogram).

16x - 15 = 30 + 11x

Subtract 11x from both sides of the equation.

5x - 15 = 30

Add 15 to both sides of the equation.

5x = 45

Divide both sides of the equation by 5.

x = 9

So, the answer is 9, which is equal to x.

#teamtrees #PAW (Plant And Water)

Answer:

x = 1.67

Step-by-step explanation:

We know that in a parallel, opposite sides are parallel and congruent, therefore we can solve for x, by:

(BC) = (AD)

16x - 15 = 30 - 11x

(+11x) + 16x - 15 = 30

27x - 15 = 30

27x = 45

x = 45/27

x = 1.67

Therefore, x = 1.67

Hope this helps!

Answer:

Max (-7/2, 97/4)

Domain: all real numbers

Range: (negative infinity, 97/4)

Step-by-step explanation:

Im assuming this is a quadratic equation y = -x^2-7x+12

The max/min are the vertex (-b/2a)

Answer:

341.6

Step-by-step explanation:

This problem asks one to subtract (58.4) from (400).

400 - 58.4 = 341.6

Less than is subtraction.

Subtract 58.4 from 400

400 - 58.4 = 341.6

The answer is 341.6

Answer:

Solution given:

1.

diameter(d)=6mm

base(b)=8mm

height (h)=5mm

Area of figure=area of parallelogram +area of semi circle

2.

for triangle

base[b]=6ft

height(h)=9ft

for square

length[l]=9ft

Area of figure=area of square +area of triangle

Answer:

take 28 degree as reference angle

using sine angle

sin28=p/h

0.46=10/h

0.46h=10

h=10/0.46

h=21.73

therefore hypotenuse =21.73

again using sine rule

take 25 degree as reference angle

sin 25=p/h

0.42=SR/21.73

0.42*21.73=SR

9.12=SR

9.1=SR

Step-by-step explanation:

Answer:

second

Step-by-step explanation:

[tex]\frac{2x}{5} +\frac{1x}{5} +\frac{5}{8} -\frac{2}{8} = \frac{3x}{5} +\frac{3}{8}[/tex]

Answer:

3/5 x + 3/8

remove parentheses:

2/5x + 5/8 + 1/5x - 1/4

simplify terms:

3/5x + 5/8 - 1/4

make 1/4 have a common denominator to 15/8 by multiplying 2/2.

3/5x + 5-2/8 =

3/5x + 3/8

Answer:

[tex]0.4138[/tex]

Step-by-step explanation:

Given

[tex]x \to storm[/tex]

[tex]\mu_x = 1.0[/tex]

[tex]y \to fire[/tex]

[tex]\mu_y = 1.5[/tex]

[tex]z \to theft[/tex]

[tex]\mu_z = 2.4[/tex]

Let the event that the above three factors is greater than 3 be represented as:

[tex]P(A > 3)[/tex]

Using complement rule, we have:

[tex]P(A > 3) = 1 - P(A \le 3)[/tex]

This gives:

[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]

-----------------------------------------------------------------------------------------------------------

The exponential distribution formula of each is:

[tex]P(x \le k) = 1 - e^{-\frac{k}{\mu}}[/tex]

So, we have:

[tex]k = 3; \mu_x = 1[/tex]

[tex]P(x \le 3) = 1 - e^{-\frac{3}{1}} = 1 - e^{-3} = 0.9502[/tex]

[tex]k=3; \mu_y = 1.5[/tex]

[tex]P(y \le 3) = 1 - e^{-\frac{3}{1.5}} = 1 - e^{-2} = 0.8647[/tex]

[tex]k = 3; \mu_z = 2.4[/tex]

[tex]P(z \le 3) = 1 - e^{-\frac{3}{2.4}} = 1 - e^{-1.25} = 0.7135[/tex]

-----------------------------------------------------------------------------------------------------------

[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]

[tex]P(A > 3) = 1 - (0.9502 * 0.8647 *0.7135)[/tex]

[tex]P(A > 3) = 1 - 0.5862[/tex]

[tex]P(A > 3) = 0.4138[/tex]

-> 4x= 66-10

-> 4x= 56

-> x= 56/4

-> x= 14

mark me brainliestttt plsss :)))

Answer:

x = 14.

Step-by-step explanation:

4x + 10 = 66

4x + 10 - 10 = 66 - 10

4x = 56

x = 56/4 = 14.

Answer:

When something is inversely proportional it can be solved by using the equation:

y = k/x

where k is the constant.

So using this we can plug in x and y to find the value of k.

3 = k/4.

Next we isolate k and find that k = 12. Now we use this to find the value of y when x = 8. Plug in x and you get y = 12/8 or y = 3/2 or 1.5.

Another way to solve this is to look at how the value of x changes. When the value of x goes up, the value of y goes down.

In other words, when x is multiplied by some number, y is divided by that number. In this equation we can see that x is multiplied by 2 to go from 4 to 8.

Thus, y must be divided by 2.

Thus, y = 3/2 or 1.5.

Answer:

Step-by-step explanation:

y is inversely proportional to tan x means  

                                                            [tex]y \ \alpha \ \frac{1}{tan x}\\\\y = k \times \frac{1}{tanx}[/tex]

Given y = 2 when x =30° . So we will find k.

                            [tex]y =k \times \frac{1}{tanx } \\\\2 = k \times \frac{1}{tan 30}\\\\k = 2 \times tan 30 = 2 \times \frac{1}{\sqrt{3}} = \frac{2}{\sqrt{3} }[/tex]

Now x is doubled, x = 60°, find y

                         [tex]y = k \times \frac{1}{tanx}\\[/tex]

                            [tex]= \frac{2}{\sqrt{3}} \times \frac{1}{tan 60}\\\\= \frac{2}{\sqrt{3}} \times \sqrt{3}\\\\=2[/tex]