Find each missing measure.



PLSS help

Answer:

Use the drawing tools to form the correct answer on the graph.

Graph the line that represents this equation:

Step-by-step explanation:

Answer:

I'm sorry i cant help you rn, download symbolab or math solver, I'm sure you will find your answer g

Answer:

where is the numer line?

Step-by-step explanation:

Answer:

9-3m

Step-by-step explanation:

m and -4m are like terms, combining them yields (1m-4m) which is -3m. The 9 is a constant.

Answer:

you add and subtract

Step-by-step explanation:

You need to match the sum/difference with the expression

Example -

A. 5x+2x 15x+2y (B)

B. 7x+8x+2y. 7x (A)

That's how you match it

Answer:

137.44 units^3

Step-by-step explanation:

Answer:

Step-by-step explanation:

We are to rank the options given in the question to correctly prove the theorem that: "If A & B are set, and A is a subset of B"

To arrange the steps in the correct order, we have:

(a) Assume that B is countable

(b) The elements of B can be listed as b1, b2, b3

(c) Since A is a subset of B, taking the subsequence of {bn} that contains the terms that are in A gives a listing of the elements of A.

(d) Therefore A is countable, contradicting the hypothesis.

(e)  Thus B is not countable

Answer:

560/9 or around 63 cubes

Step-by-step explanation:

2 2/3 -> 8/3

3 1/3 -> 10/3

2 1/3-> 7/3

7/3 x 8/3= 56/9

56/9 x 10/3 = 560/27

560/27 divided by 1/3

= 560/9

Answer:

Step-by-step explanation:

according to the question

[tex] \begin{cases}x + 29 = 7x + 5 \\ 8y - 35 =3y \end{cases}[/tex]

[tex] \begin{cases}x -7x= 5-29 \\ 8y - 3y=35 \end{cases}[/tex]

[tex] \begin{cases}-6x= -24\\ 5y=35 \end{cases}[/tex]

[tex] \begin{cases}\frac{-6x}{-6}=\frac{-24}{-6} \\ \frac{5y}{5}=\frac{35}{5} \end{cases}[/tex]

[tex] \therefore \begin{cases} x=4\\ y=7 \end{cases}[/tex]

Answer:

Also need help

Answer:

20

Step-by-step explanation:

Hello There!

So first we need to determine what the formula for area of a trapezoid is

[tex]A=\frac{a+b}{2} h[/tex]

where a and b = bases and h = height

the given information is the area and the two bases

so we plug in the given information and solve for h

[tex]180=\frac{4+14}{2} h\\4+14=18\\\frac{18}{2} =9\\180=9h[/tex]

divide each side by 9

[tex]\frac{180}{9} =20\\\frac{9h}{9} =h[/tex]

we're left with

h=20

so we can conclude that the height is 20

Answer:

x = -9

Step-by-step explanation:

3^16 = (1/9)^x

9^18 = 9^-x

On comparing co-efficients :

-x = 9

x = -9

Answer:

1. 5(a-6) = 5a-30

2. 2(3a-b) = 6a-2b

3. 5(-5x+3) = -25x+15

4. -(2c+3) = -2c-3

Both of their first step are correct (Show your calculations to explain)

x-9 = 5

x = 14

2x-18 = 10

2x = 28

x = 14

Step-by-step explanation:

All Above

Answer:

b

Step-by-step explanation:

12 13 15 15 15 16 19

mean: 15

median: 15

mode: 15

range: 7

Answer:

12, 13, 15, 15, 15, 16, 19

Step-by-step explanation:

Mean: 15

Median: 15

Mode: 15

Range: 7

Answer:

I believe it's A=5 times 9 but since the triangle is special (3-4-5), it could be 12 times 5. Hope this kinda help :)

Answer:

I hope some of these help (examples)

Step-by-step explanation:

Line AB contains points A (1, 2) and B (−2, 6) The slope of line AB is

a)zero

b)undefined

c)positive

d)negative

The equation of line CD is (y−3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD?

Line CD contains points A (4, 6) and B (−2, 6). The slope of line CD is

Line QR contains (2, 8) and (3, 10) Line ST contains points (0, 6) and (−2, 2). Lines QR and ST are

The equation of line QR is y = negative 1 over 2x + 1. Write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6).

The equation of line CD is y = −2x − 2. Write an equation of a line parallel to line CD in slope-intercept form that contains point (4, 5).

Line QR contains (2, 8) and (3, 10) Line ST contains points (0, 6) and (−2, 2). Lines QR and ST are

parallel because the product of the slopes is −1

perpendicular because the product of the slopes is −1

parallel because the slopes are the same

perpendicular because the slopes are the same

Question 2

(06.02 LC)

The equation of line CD is (y−3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD?

1 over 2

2

negative 1 over 2

−2

Question 3

(06.02 LC)

Line CD contains points A (4, 6) and B (−2, 6). The slope of line CD is

zero

undefined

positive

negative

Question 4

(06.02 MC)

The equation of line QR is y = negative 1 over 2x + 1. Write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6).

y = 2x + 16

y = negative 1 over 2x + 17 over 2

y = − 1 over 2x + 7 over 2

y = 2x − 4

Question 5

(06.02 MC)

The equation of line CD is y = −2x − 2. Write an equation of a line parallel to line CD in slope-intercept form that contains point (4, 5).

y = −2x + 13

y = negative 1 over 2x + 7

y = 1 over 2x + 3

y = − 2x − 3

On the first question, the formula would be  m=\frac{y2-y1}{x2-x1} and the value we got is -4/3, so D.

On the second quesiton, the slope in the given equation of the line is -2, its negative reciprocal is 1/2, so A.

On the third question, use the slope formula above and the value you would get is zero, so A.

On the fourth question, the equation of the line perpendicular to line QR is y=2x+b, to find b, just substitute the point (5,6) to the equation. That would make b = -4. the final equation of the line would be: y=2x-4, so D.

On the fifth question, the equation of the line parallel to line QR is y = -2x + b. substitute the point (4,5) to the equation, and you'll get b = 13. the final equation of the line would be y=-2x+13, so A.

D,A,A,D,A

1) Determine the slope of the line that is perpendicular to the equation below.

y = -3x + 4

Type your answer as a reduced fraction, if necessary, like this: 3/4

2) Which line is parallel to the line with this equation?

3x – 4y = 24

A) 8y-6x=32

B) 3x-5y=25

C) y=-3/4x -6

D) y+3 = 3(x-4)

3) Determine which equation is in slope-intercept form for the line that passes through (5, 0) and is perpendicular to the line below.

y = -5/2x + 6

A) y=-2/5x - 2

B) y=5/2x+2

C) y=5/2x-2

D) y=2/5x-2

4) Line 1 contains the points (6, -5) and (2, 7). Which of the given pairs of coordinates could be contained by Line 2 if Line 1 is parallel to Line 2?

HINT: Remember that two parallel lines share NO points.

A) (2,7) and (11,10)

B) (6,-5) and (-1, 3)

C) (9,8) and (6, 9)

D) (5,6) and (9, -6)

5) What value should replace the "?" to make the equations parallel?

Type your answer as a reduced fraction, using the "/" symbol to separate the numerator and denominator, like this: 2/5

y=5/3 x - 8

y=? x + 9

6)Determine whether the pair of lines is parallel, perpendicular, or neither.

y = 7x and y – 28 = 7(x – 4)

A) parallel

B) perpendicular

C) Neither

1) m=-2

2) C) y=-3/4x -6

3) D) y=2/5x-2

I hope this helps:)

Answer:

7()=11

8()=42

I could barely see the answer for number 9 sorry :(

Step-by-step explanation:

the 7() is 2(3)+5

2(3)=6

6+5=11

Question (8)

c^2+3a x b

c(6)^2+ 3(3) x 2/3

36+9 x 2/3

36+6=42

Answer:

(7)=11

(8)=42

Step-by-step explanation:

here

Answer:

c

Step-by-step explanation:

Answer:

is C guys

Step-by-step explanation:

Answer:

a) 0.5 = 50% of flanges exceed 1 millimeter.

b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

[tex]P(X > x) = \frac{b - x}{b - a}[/tex]

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

This means that [tex]a = 0.95, b = 1.05[/tex]

(a) Determine the proportion of flanges that exceeds 1.00 millimeters.

[tex]P(X > 1) = \frac{1.05 - 1}{1.05 - 0.95} = \frac{0.05}{0.1} = 0.5[/tex]

0.5 = 50% of flanges exceed 1 millimeter.

(b) What thickness is exceeded by 90% of the flanges?

This is x for which:

[tex]P(X > x) = 0.9[/tex]

So

[tex]\frac{1.05 - x}{1.05 - 0.95} = 0.9[/tex]

[tex]1.05 - x = 0.9*0.1[/tex]

[tex]x = 1.05 - 0.9*0.1[/tex]

[tex]x = 0.96[/tex]

A thickness of 0.96 millimeters is exceeded by 90% of the flanges

Answer:

A is the correct answer

Answer:

B

Step-by-step explanation:

The first number should represent the lawns, and the second should represent the money he makes on each lawn.

A is incorrect because the numbers are swapped; Ryan does not earn one dollar for mowing 20 lawns.

C is wrong because if Ryan mows zero lawns, how can he make money. Although the multiplication is correct, it does not start at zero.

D is wrong because it is counting the price up by ten instead of adding 20.

B is right because every lawn is 20 more dollars, and that is what is shown.  

Answer:

$546000

Step-by-step explanation:

($65000×8%)(2)

Answer:

2:10 PM

Step-by-step explanation:

5+35+15=55 mins

1:15+55 mins=2:10PM

Answer:

15

Step-by-step explanation:

x=2,z=6

2+6(4)-5-3(2)

2+24-5-6

26-11

15

x = 2 & z = 3x

Answer:

2x(2x2 -6x) + (7x - 21)

Step-by-step explanation:

4x3 - 12x2 + 7x -21

Answer:its library to police station

Step-by-step explanation:

Answer:

When t = 3, y = 12.  y = 4t, for t>0

Step-by-step explanation:

8 = 4 x 2; y = 4 x 3 = 12.

Answer:

The quartile 3 is 0.3

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

[tex]f(x) = \mu e^{-\mu x}[/tex]

In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.

The probability that x is lower or equal to a is given by:

[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]

Which has the following solution:

[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]

The probability of finding a value higher than x is:

[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]

X~Exp (0.2)

This means that [tex]m= 0.2, \mu = \frac{1}{0.2} = 5[/tex]

Find the quartile 3.

The 3rd quartile is the 75th percentile, for which [tex]P(X \leq x) = 0.75[/tex], or [tex]P(X > x) = 1 - 0.75 = 0.25[/tex]

Since

[tex]P(X > x) = e^{-\mu x}[/tex]

[tex]e^{-5x} = 0.25[/tex]

[tex]\ln{e^{-5x}} = \ln{0.25}[/tex]

[tex]-5x = \ln{0.25}[/tex]

[tex]x = -\frac{\ln{0.25}}{5}[/tex]

[tex]x = 0.277[/tex]

Rounding to the nearest tenth, the quartile 3 is 0.3.