\dfrac k{2}+\dfrac12=3
2
k
+
2
1
=3
Answer:
it 5
Step-by-step explanation:
i got i correct
Name: ___________________________________________ Class: ___________
Real World Situation
Bryce spent $5.26 on some apples priced at $0.64 each and some pears priced at
$0.45 each. At another store he could have bought the same number of apples at
$0.32 each and the same number of pears at $0.39 each, for a total cost of $3.62. How
many apples and how many pears did Bryce buy?
Write equations in Standard Form.
Equation 1 (Store 1) Equation 2 (Store 2)
___________________________________ ____________________________________
Solve both equations in Standard Form. Show all work.
HINT: Replace the given values for x in the equation and solve for y
Equation 1
x (x,y)
0
1
2
3
4
5
6
Equation 2
x (x,y)
0
1
2
3
4
5
6
Solution:- ( , )
Identify the solution and state what it means in context of the problem.
_______________________________________________________________________________________________
_______________________________________________________________________________________________
________________________________________________________________________________
Use Substitution Method to solve the system of Equations. Show all work and state
the solution.
Solution: ( , )
Explain in your own words your process of solving the System of Equations using
Substitution Method.
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_________________________________________________________________
Use Elimination Method to solve the system of Equations. Show all work and state the
solution.
Solution: ( , )
Explain in your own words your process of solving the System of Equations using
Elimination Method.
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_________________________________________________________________
Use Graphing Method to solve the system of Equations. Show all work and state the
solution.
Solution: ( , )
Explain in your own words your process of solving the System of Equations using
Graphing Method.
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_______________________________________________________________________________________________
Reflection:
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_______________________________________________________________________________________________
_________________________________________________________________
Name_____________________________________ Class:______________ 2020-2021 Score:
Circumstances of Performance Students comments: I have learned that
___independent work __________________________________________________________________
___in class __________________________________________________________________
___as Homework __________________________________________________________________
___with a partner __________________________________________________________________
___with teacher feedback
___with an opportunity for revision Teacher comments/Next Steps:
__________________________________________________________________
Peer Reflection:
___________________________________________________________________
___________________________________________________ ___________________________________________________________________
___________________________________________________ ___________________________________________________________________
___________________________________________________ ___________________________________________________________________
Let the number of apples be x and that of pears be y, then:
0.64x + 0.45y = 5.26 . . . (1)
0.32x + 0.39y = 3.62 . . . (2)
(2) x 2 => 0.64x + 0.78y = 7.24 . . . (3)
(1) - (3) => -0.33y = -1.98
y = -1.98 / -0.33 = 6
From (2), 0.32x + 0.39(6) = 3.62
0.32x = 3.62 - 2.34 = 1.28
x = 1.28 / 0.32 = 4
459,450,441, find the 37th term
Answer:
135
Step-by-step explanation:
So, our first term is 459.
Lets find what our change in terms is. To do this, lets subtract the frist term by the second:
459-450
This will get you 9.
Now that we know our change per term, lets find our 37th term.
All we need to do, is take our first term, and subtract it by our change in terms times the amount of terms.(Note that we already know are 1st term, so we are multiplying the change in terms by 36, not 37. )
So this is what we can use to solve for this:
459-(9x37)
This equals
135.
Hope this helps!
Step-by-step explanation:
first term = a = 459
common difference = d = 450 - 459 = -9
nth term = an
n = -9
an = a + (n-1)d
= 459 +(37-1)-9
= 459 + (36)-9
= 459 -324
= 135
37 th term = 135
plz mark my answer as brainlist if you find it useful for you. hope this will be helpful to you .
solve: log3(x)+log3(x-2)=log3(x+10)
log3 ( x ) + log3 ( x - 2 ) = log3 ( x + 10 )
log3 ( x )( x - 2 ) = log3( x + 10 )
log3 ( x^2 - 2x ) = log3( x + 10 )
x^2 - 2x = x + 10
x^2 - 3x - 10 = 0
( x - 5 )( x + 2 ) = 0 ==》x = 5 Or x = - 2
There are 5 horses and 15 elephants in a circus. how to Simplify the ratio of horses to elephants.
Answer:
5:15 simplified is 1:3
Hope this helps!
Answer:
5:15 simplified (or divided by 5) is 1:3
Step-by-step explanation:
Can Someone Help Me With This I Beg You.
simplify 2(-3x -6) I want to simplify it but I'm not sure how
Answer:
-6x-12
Step-by-step explanation:
2(-3x-6)
Multiply: 2(-3x)+2(-6)
so answer is -6x-12
simplify the ratio 25:15:10
Answer:
60%
Convert fraction (ratio) 15 / 25 Answer: 60%
The actual length of side y is 22cm. Use the scale drawing to find the length of side x.
Given:
The actual length of side y is 22cm.
To find:
The length of side x by using the scale drawing.
Solution:
We know that the corresponding sides of original figure and scale drawing are proportional.
[tex]\dfrac{x}{1.8}=\dfrac{y}{1.4}[/tex]
[tex]\dfrac{x}{1.8}=\dfrac{22}{1.4}[/tex]
[tex]x=\dfrac{22}{1.4}\times 1.8[/tex]
[tex]x\approx 28.286[/tex]
Therefore, the length of side x is about 28.286 cm.
simplify the expression
Answer:
[tex]\frac{2*x - 2}{2*x} - \frac{3*x + 2}{4*x} = \frac{x - 6}{4*x}[/tex]
Step-by-step explanation:
We have the expression:
[tex]\frac{2*x - 2}{2*x} - \frac{3*x + 2}{4*x}[/tex]
The first thing we want to do, is to have the same denominator in both equations, then we need to multiply the first term by (2/2), so the denominator becomes 4*x
We will get:
[tex](\frac{2}{2} )\frac{2*x - 2}{2*x} - \frac{3*x + 2}{4*x} = \frac{4*x - 4}{4*x} - \frac{3*x + 2}{4*x}[/tex]
Now we can directly add the terms to get:
[tex]\frac{4*x - 4}{4*x} - \frac{3*x + 2}{4*x} = \frac{4*x - 4 - 3*x - 2}{4*x} = \frac{x - 6}{4*x}[/tex]
We can't simplify this anymore
BIG JIM/LITTLE JIM PROBLEM When Big Jim stands on a bench that is 15 inches high, the top of his head is 53 inches above the top of Little Jim’s head. Big Jim’s height is twice that of Little Jim’s height. How tall is Big Jim? How tall is Little Jim?
Answer:
Let J = height of Little Jim. Then Big Jim's height is 2J.
when big jim stands on a bench that is 15 inches high, the top of his head is 53 inches above the top of little jims head.
The above given sentence means 15+ 2J= J+53.
15+2J = J+53
2J-J = 53-15
J = 38 inchesJimmy and his friends want to sign up for a game rental service. They have information on game rental plans from four different companies. The friends plan to rent 15 games per month. Which plan is the BEST? Use substitution to determine the best price.
A-GameStop; pay $5 for each game ordered. (5g)
B-Level-up Games; pay $25 to join and $2 for each game ordered (2g + 25)
C-Game Changer; pay $20 to join and $2.50 for each game ordered (2.5g + 20)
D-Game Land; pay $60 per month for unlimited amount of game rentals (60)
Answer: A
Step-by-step explanation:
It’s the cheapest
victor is keeping track of winter temperatures for a project. yesterday the thermometer read 12°F, and today the temperature has dropped 7°F. he wants to determine the temperature today. which operation should he use to solve this problem?
A) addition
B) subtraction
C) multiplication
D) division
Answer: subtraction
Step-by-step explanation:
i did the assignment.
Based on the table, how much more money would a electrician earn earn than a social worker over a 20 year career?
A) $11,390
B) $112,250
C) $123,640
D) 227,800
Write as an algebraic expression: Five times the difference of the cube of y
and the square of x
A. 5y^3 + 5x^2
B. (5y)^3 - (5x)^2
C. 5(y^3 - x^2)
D. (5y - 5x)^6
The answer would be:
C. 5(y^3 - x^2)
A 20-foot ladder leans against a wall, making a 70° angle with the ground. To the nearest tenth of a foot, how far up the wall will the ladder reach? 6.8 6.9 I 3) 18.7 18.8
Answer:
4) 18.8
Step-by-step explanation:
What we are trying to find is the opposite of the triangle with the angle and the hypotenuse. The equation for that is sin(degrees) = opp/hyp
the degrees is 70, the opposite is x, and the hypotenuse is 20
sin(70) = x/20
0.93969262078 = x/20
18.7938524 = x
18.7938524 rounds to 18.8 so the answer is 4
What is the best approximation of the length of the radius in a circle with an area of 167 m2?
a. 4.6 meters
b.4.0 meters
c. 2.3 meters
d.5.1 meters
Answer:
r = 7.3 m
Step-by-step explanation:
A = (pi)(radius)^2, so, if A = 167 m^2, r^2 is found as follows:
167 m^2
r^2 = -------------- = 53.158 m^2
3.14
Taking the square root of both sides, we get
r = 7.3 m
This is correct, because A = (pi)(radius)^2 becomes (3.14)(7.3 m)^2 = 167.4 m^2
Answer plsss........
1. x+12
2. x-8
3. 3*x
4. x^(2)+5
5. (x/2)+7
6. 4*(x+6)
7. (1/2)*x
8. 2x+8
9. x^(2)+3
10. (x/3)+12
Additional activity
1. 2-50
2.20/4=5
3.100-50=50
4.three times two then add to four equals ten
5. the diffrence of eight and four
What is the area of the polygon? Show your work.
Answer:
33 square units
Step-by-step explanation:
Assuming that each line on this grid increases by a value of one, the area of the polygon can be determined by breaking it down into a large rectangle and two smaller triangles.
Area of the rectangleThe area of a rectangle is simply [tex]A = bh[/tex], where b represents the base and h represents the height.
Counting the size of each side, we can determine that they are 6 units for the base and 4 units for the height.
Substituting in the values, we get:
[tex]A = (6)(4)\\A = 24[/tex]
The area of the rectangle is 24 square units
Area of the trianglesThe area of a triangle is simply [tex]A = \frac{1}{2} bh[/tex].
The base of each triangle is 3, and the height of each triangle is also 3.
Substituting in the values, we get:
[tex]A = \frac{1}{2} (3)(3)\\A = \frac{1}{2} (9)\\A = 9 / 2\\A = 4.5[/tex]
The area of each triangle is 4.5 square units
Area of the polygonTo get the area of the polygon, we simply add up the area of the rectangle and both triangles
[tex]A = 24 + 4.5 + 4.5\\A = 24 + 9\\A = 33[/tex]
The total area of the polygon is 33 square units.
What are a) the ratio of the perimeters and b) the ratio of the area of the larger figure to the smaller figure?
Answer:
Suppose that we have two similar figures.
Then if a given side of one of the figures has a measure M, the correspondent side in the other figure has a measure M' = k*M
Where k is the scale factor.
Then if the perimeter of the first figure is P, the perimeter of the other figure will be P' = k*P
And if the area of the first figure is A, then the area of the other figure will be:
A' = k^2*A
Then the quotient between the perimeters is:
P'/P = k
And the ratio between the areas is
A'/A = k^2
So what we need to do, is find the value k.
In the image, we can see that the base of the larger figure is 30 yd, and the base of the smaller figure is 12 yd.
If we define the smaller figure as the original one, then we will have:
M = 12 yd
M' = 30 yd
M' = 30yd = k*12yd = k*M
Solving for k we get:
k = 30yd/12yd = 2.5
Then the ratio between the perimeters is:
P'/P = k = 2.5
And the ratio of the area of the larger figure (A') to the smaller figure (A) is:
A'/A = k^2 = (2.5)^2 = 6.25
A cylinder has a base diameter of 10cm and a height of 7cm. What is its volume in cubic cm, to the nearest tenths place?
Answer:
volume = 549.5 cm³
Step-by-step explanation:
base area m= πr² = (3.14)(5²) = 78.5 cm²
volume = base area x height = 78.5 x 7 = 549.5 cm³
Answer:
549.5 cm3
Step-by-step explanation:
get this right N I’ll give you brain list!
Answer:
[tex]y=\frac{1}{4} +x[/tex]
Step-by-step explanation:
use desmos graphing calculator
Andre wrote the expression −3+6x÷5 to represent the relationship shown in the table. Find two other expressions that also represent the relationship shown in the table. Select all that apply.
A.
5÷(−3)+6x
B.
6x−3
5
C.
6x÷5+(−3)
D.
(−3+6)+x÷5
E.
6
5x−3
F.
3+(−6x÷5)
Answer:
C is the correct answer
Step-by-step explanation:
Select all shapes that have a volume of 36pi cubic units. (see attached picture)
Answer:
a B and c because there the shape of the big triangles
Given the points A(4,6) and B(8, −2), what is the length of segment AB in units?
F √5
G 2√5
H 4√5
J 4
Answer:
Hi! The answer to your question is H. [tex]4\sqrt{5}[/tex]
Step-by-step explanation:
[tex]Y1 = 6[/tex]
[tex]Y2 = -2[/tex]
[tex]X1 = 4[/tex]
[tex]X2 = 8[/tex]
[tex]AB = \sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]
[tex]AB = \sqrt{(8-4)^2+(-2-6)^2}[/tex]
[tex]AB =\sqrt{(4)^2+(-8)^2}[/tex]
[tex]AB = \sqrt{16+64}[/tex]
[tex]AB = 4\sqrt{5}[/tex]
☆*: .。.。.:*☆☆.*: .。..。.:*☆☆*: .。.。.:*☆☆.*: .。..。.:*☆
☁Brainliest is greatly appreciated!☁
Hope this helps!!
- Brooklynn Deka
_________________ please help!!!!!!!
Answer:
The answer would be C)5
Step-by-step explanation:
The unknown triangle is half of the size of the original triangle, The right side measurement basically hints to the actual answer.
A company that cleans carpets charges its customers a fixed amount for supplies plus an
additional amount per hour of cleaning. The graph models the linear relationship between the
total amount charged and the number of hours of cleaning.
What is the maximum percentage of net spendable income that should be set aside for housing? (It’s not 38)
A.25%
B.36%
C.38%
D.28%
Answer:
Step-by-step explanation:
It is 38% cause The maximum percentage of a families net spendable income should have at least 38% set aside for housing expenses.
6 x 2/3 ??? yeah ik its not helping
Answer:
6 * 2/3 = 12/3 = 4
Step-by-step explanation.
you can think about it like this: 6 * 1/3 * 2
1/3 of 6 is 2 because 2 * 3 is 6
2 * 2 is 4, therefore the correct answer is 4
remember doing 6 * 2/3 is the same as doing 6/1 * 2/3 if that helps
Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt.
xy = 6
(a) Find dy/dt, given x = 4 and dx/dt = 11.
dy/dt =
(b) Find dx/dt, given x = 1 and dy/dt = –9.
dx/dt =
Answer:
A)
[tex]\displaystyle \frac{dy}{dt}=-\frac{33}{8}[/tex]
B)
[tex]\displaystyle \frac{dx}{dt}=\frac{3}{2}[/tex]
Step-by-step explanation:
x and y are differentiable functions of t, and we are given the equation:
[tex]xy=6[/tex]
First, let's differentiate both sides of the equation with respect to t. So:
[tex]\displaystyle \frac{d}{dt}\left[xy\right]=\frac{d}{dt}[6][/tex]
By the Product Rule and rewriting:
[tex]\displaystyle \frac{d}{dt}[x(t)]y+x\frac{d}{dt}[y(t)]=0[/tex]
Therefore:
[tex]\displaystyle y\frac{dx}{dt}+x\frac{dy}{dt}=0[/tex]
A)
We want to find dy/dt when x = 4 and dx/dt = 11.
Using our original equation, find y when x = 4:
[tex]\displaystyle (4)y=6\Rightarrow y=\frac{3}{2}[/tex]
Therefore:
[tex]\displaystyle \frac{3}{2}\left(11\right)+(4)\frac{dy}{dt}=0[/tex]
Solve for dy/dt:
[tex]\displaystyle \frac{dy}{dt}=-\frac{33}{8}[/tex]
B)
We want to find dx/dt when x = 1 and dy/dt = -9.
Again, using our original equation, find y when x = 1:
[tex](1)y=6\Rightarrow y=6[/tex]
Therefore:
[tex]\displaystyle (6)\frac{dx}{dt}+(1)\left(-9)=0[/tex]
Solve for dx/dt:
[tex]\displaystyle \frac{dx}{dt}=\frac{3}{2}[/tex]