Explain what you understand by Millennial Generation​

Answers

Answer 1

Answer:

refers to the generation of people born between the early 1980s and 1990s


Related Questions

Phenotype is the actual genes that make a person True or False​

Answers

Answer:

True?

Explanation:

Genotype and phenotype are two fundamental terms in the science of genetics. ... An organism's genotype is the set of genes in its DNA responsible for a particular trait. An organism's phenotype is the physical expression of those genes.

The term "phenotype" refers to the observable physical properties of an organism; these include the organism's appearance, development, and behavior. An organism's phenotype is determined by its genotype, which is the set of genes the organism carries, as well as by environmental influences upon these genes.

This is why I think it's true. You don't have to read the rest,but that's why I know.

Answer:

The answer is true

Explanation:

I dont know but trust is probably true.

A 1.5 V battery is connected to a 1,000 μF capacitor in series with a 150 Ω resistor. a. What is the maximum current that flows through the resistor during charging? b. What is the maximum charge on the capacitor? c. How long does the capacitor take to reach a potential of 1.0V?

Answers

Answer:

[tex]0.01\ \text{A}[/tex]

[tex]0.0015\ \text{C}[/tex]

[tex]0.0608\ \text{s}[/tex]

Explanation:

[tex]V_0[/tex] = Voltage = 1.5 V

[tex]C[/tex] = Capacitance = [tex]1000\ \mu\text{F}[/tex]

[tex]R[/tex] = Resistance = [tex]150\ \Omega[/tex]

Current is given by

[tex]I=\dfrac{V_0}{R}\\\Rightarrow I=\dfrac{1.5}{150}\\\Rightarrow I=0.01\ \text{A}[/tex]

Current flowing in the resistor is [tex]0.01\ \text{A}[/tex].

Charge is given by

[tex]Q=CV\\\Rightarrow Q=1000\times 10^{-6}\times 1.5\\\Rightarrow Q=0.0015\ \text{C}[/tex]

The charge on the capacitor is [tex]0.0015\ \text{C}[/tex].

Voltage is given by

[tex]V=V_0e^{-\dfrac{t}{RC}}\\\Rightarrow t=-RC\ln\dfrac{V}{V_0}\\\Rightarrow t=-150\times 1000\times 10^{-6}\times\ln\dfrac{1}{1.5}\\\Rightarrow t=0.0608\ \text{s}[/tex]

Time taken to reach 1 V is [tex]0.0608\ \text{s}[/tex].

You have a well-trained athlete (although not specifically a track athlete) come to the lab to perform a Wingate anaerobic test (WAnT). The subject is a 24-year-old male. He is 89.2kg, and 1.85 m tall. His Resting HR is 47 bpm, and his BMI is ~26.The participant does a warm-up on the cycle ergometer to prepare for the test. You are getting the weights ready to be applied to the flywheel. How much resistance will you use (in kg)

Answers

Answer:

6.69 kg

Explanation:

Given that:

The mass of the athlete = 89.2 kg

Height = 1.85 m

Resting HR = 47 bpm

BMI = ~26

The essence of the Wingate anaerobic test is to evaluate and access how much energy is released by phosphagen breakdown and anaerobic glycolysis. By applying a fixed amount of weight to that same cycle's weight tray, tension is added to the flywheel. The flywheel resistance is usually set at 0.075 kg per kilogram of body weight.

For athlete sprinters, the resistance is usually set at 1.0 kg which is then multiplied by the body mass up to 1.3 kg

Hence, the amount of the resistance applied for the athlete  = (0.075 × 89.2)kg

= 6.69 kg

Track and field is an individual sport.
True or False?

Answers

Most events in track and field are individual except relay races. Therefore, it would probably be true.

Track and field is an individual sport. This statement is True.

What is Track and field ?

Track and field is a sport which includes jumping, running, and throwing. it is also know as track and field athletics, or track. This sport is organized in a stadium in which there are running tracks, set up for high jump and long jump and field for throwing. Hence the name is track and field. In this sport different participant participate to get one winner from each game from each weight group. The International Association of Athletics Federations(IAAF) is the international governing body for track and field.

The two most prestigious international track and field competitions are the athletics competition at the Olympic Games and the World Athletics Championships. World Athletics, formerly known as the International Association of Athletics Federations (IAAF),

Hence Track and field is an individual sport.

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URGENT!!!!!!!!!: If an electromagnetic wave has a frequency of 6 x 10^5 Hz, what is its
wavelength? Use v/f. The speed of light is 3 x 10^8 m/s.

Answers

Answer:

A

Explanation:

because the speed divide by the frequency is equal to the wavelength(in meters)

5×10² m

Help pls. Edge 2021- Motion in space

Answers

Collaboration is critical to successful product design, and with Solid Edge, OEMs and suppliers can improve and manage collaboration across design teams, regardless of location. By reducing design revisions and communication delays, our customers enjoy quicker time-to-market and increased profitability.

Typical novae occur when (a) a red-giant star ejects a planetary nebula; (b) two neutron stars merge, forming a more massive neutron star; (c) an extremely massive star collapses, and also ejects its outer atmosphere; (d) matter accreted from a companion star unstably ignites on the surface of a white dwarf; or (e) a neutron star’s magnetic field becomes strong enough to produce two oppositely directed jets of rapidly moving particles.

Answers

Answer:

I think its d matter accreted from a companion star unstable ignites on the surface of a white dwarf.

Describe the processes that take place inside the nucleus for the following decays; Beta- decay and Beta+ decay.

Answers

Answer:

Explanation:

(a) Electron Emission (Beta- decay):

When an unstable nucleus decays by the emission of Beta- particle, its charge number ‘Z’ increases by 1 but, its mass number ‘A’ remains unchanged. The transformation is represented by the equation:  

[tex]_zX^A\ -------->\ _{Z+1}Y^A\ +\ _{-1}e^0[/tex]

It is called ‘Negative Beta Decay’. It is more common than alpha decay.

Example:

[tex]_6C^{14}\ -------->\ _{7}N^{14}\ +\ _{-1}e^0[/tex]

Note:  

There are no electrons in a nucleus so, with the emission of a particle, one of the neutrons is converted to a proton and an electron.

[tex]_0n^1\ --------->\ _1P^1\ +\ _{-1}e^0[/tex]

(b) Positron Emission (Beta+ decay):

When an unstable nucleus decays by the emission of the positron, its charge number ‘Z’ decreases by 1 but,  its mass number ‘A’ remains unchanged. The transformation is represented by the equation:

[tex]_zX^A\ -------->\ _{Z-1}Y^A\ +\ _{+1}e^0[/tex]

Examples:

[tex]_{15}P^{30}\ -------->\ _{14}Si^{30}\ +\ _{+1}e^0[/tex]

Note:  

Inside the nucleus, only a proton can be transformed into a neutron with the emission of a positron (anti-particle of electron)

[tex]_1P^1\ -------->\ _0n^1\ +\ _{+1}e^0[/tex]

PLS HELPP MEEE
Fiber-optic cables rely on total internal reflection.


Please select the best answer from the choices provided

T
F

Answers

the answer would be true

A 1500 kg tractor pulls a 750 kg trailer north and applies a 2250 N force on it. What is the force on the tractor?

Answers

Answer:

law of Action and Reaction     F = 2250 N

Explanation:

The tractor and the trailer are two bodies that interact, therefore, by the law of Action and Reaction, the force that one applies on the other is equal to the force that the second body (trailer) applies on the first (tractor), but with opposite direction

          F = 2250 N

directed from trailer to tractor

What is acceleration?​

Answers

[tex]\huge\boxed{✍ ACCELERATION\hookrightarrow}[/tex]

Acceleration is defined as the rate of change of velocity with respect to time / rate of change of velocity in unit time.

It's a vector quantity (it has both magnitude & direction).

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

# ꧁❣ RainbowSalt2²2² ࿐

23. Lunar Gravity Compare the force holding a
10.0-kg rock on Earth and on the Moon. The
gravitational field on the Moon is 1.6 N/kg.

Answers

Explanation:

Given

mass of the rock is 10 kg

Force requires to hold the rock is equal to its weight

Weight is given by the product of mass and acceleration due to gravity

Weight on the earth surface

[tex]\Rightarrow W_e=10\times 9.8\\\Rightarrow W_e=98\ N[/tex]

Weight on the moon surface

[tex]\Rightarrow W_m=1.6\times 10\\\Rightarrow W_m=16\ N[/tex]

So, the force holding the rock on earth is approximately 6 times the force on the moon.

A metal spherical shell with inner radius 14 cm and outer radius 24 cm has a net charge of 1= -3 nC. At the center of the shell is a small particle with charge Q2= -7 nC. What is the charge density in (C/m2) on the outer surface of the spherical shell?

Answers

Answer:

I don't no the answer sorry

oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student observes that a particular spring-mass system has a frequency of oscillation of 10 Hz. the spring constant of the spring is 250 N/m. what is the mass?​

Answers

Answer:

Mass, m = 6.18 kg

Explanation:

Given the following data;

Frequency, F = 10 Hz

Spring constant, k = 250 N/m

We know that pie, π = 22/7

To find the mass, we would use the following formula;

F = 1/2π√(k/m)

Where;

F is the frequency of oscillation.

k is the spring constant.

m is the mass of the spring.

Substituting into the formula, we have;

10 = 1/2 * 22/7 * √250/m

10 = 22/14 * √250/m

Cross-multiplying, we have;

140 = 22 * √250/m

Dividing both sides by 22, we have;

140/22 = √250/m

6.36 = √250/m

Taking the square of both sides, we have;

6.36² = (√250/m)²

40.45 = 250/m

Cross-multiplying, we have;

40.45m = 250

Mass, m = 250/40.45

Mass, m = 6.18 kg

A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 5.00 m at constant speed. If the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do

Answers

Answer:

1568 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 80 Kg

Distance (d) = 5 m

Coefficient of kinetic friction (μ) = 0.4

Workdone (Wd) =?

Next, we shall determine the normal reaction. This can be obtained as follow:

Mass (m) = 80 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal reaction (N) =?

N = mg

N = 80 × 9.8

N = 784 N

Next, we shall determine force of friction. This can be obtained as follow:

Coefficient of kinetic friction (μ) = 0.4

Normal reaction (N) = 784 N

Force of friction (F) =?

F = μN

F = 0.4 × 784

F = 313.6 N

Finally, we shall determine the work done. This can be obtained as follow:

Distance (d) = 5 m

Force of friction (F) = 313.6 N

Workdone (Wd) =?

Wd = F × d

Wd = 313.6 × 5

Wd = 1568 J

Thus, the workdone is 1568 J

HELPPPPPP!!!! Jupiter has a gravity that is 2.4 times that of Earth. A person has a mass of 60kg. What is the mass of this person on Jupiter?



60 kg

144 kg

600N

1440N

Answers

60

because mass of an object never change

but weight can change for example if it's

mass is 60kg 5he wieght will be 60kg * 9.8m/s²

=588N

The temperatures of one northeastern state range from 105° F in the summer to -25°F in the winter. Express this temperature range in degrees Celsius and in kelvins. *

Answers

Farenheit is an interesting unit so the conversions get a bit weird.

To convert from Farenheit to Celcius you follow this formula:

T(°C) = (T(°F) - 32) × 5/9

It is also easier to convert to Celcius to Kelvin shown in this formula:

T(K) = T(°C) + 273.15

To Answer your question:

105° F = 40.5°C

-25° F = -31.7°C

105° F = 313.65K

-25° F = 241.45K

Convert 0.00553s to cs

Answers

Answer: 0.553

Explanation:

0.553 hope it helps ur welcome

Pls help! What is the average speed of an airplane that travels from New York to Los Angeles, a total distance of 4800 km, in 6.0 hours?
A.
800 km/hr
B.
80 km/hr
C.
0.00125 km/hr
D.
28,800 km/hr

Answers

Answer:

800 meters per hour

Explanation:

800 meters per hour is the average speed of an airplane that travels from New York to Los Angeles, a total distance of 4800 km, in 6.0 hours.

Water in an electric teakettle is boiling. The power absorbed by the water is 0.90 kW. Assuming that the pressure of vapor in the
kettle equals atmospheric pressure, determine the speed of effusion of vapor from the kettle's spout if the spout has a cross-
sectional area of 1.60 cm2. Model the steam as an ideal gas.​

Answers

Answer:

v = 4.233  m/s

Explanation:

By applying the rate of boiling from [tex]Q= mL_v[/tex];

the rate of the boiling can be described as:

[tex]\mathcal{P} = \dfrac{Q}{\Delta t} \\ \\ \mathcal{P} = \dfrac{mL_v}{\Delta t}[/tex]

The mode of the steam (water vapor) as an ideal gas can be illustrated by formula:

[tex]P_oV_o = nRT[/tex] --- (1)

where;

n = number of moles;

[tex]n = \dfrac{mass (m)}{Molar mass (M)}[/tex]

Then; equation (1) can be rewritten as:

[tex]P_oV_o = (\dfrac{m}{M}) RT \\ \\ \dfrac{P_oV}{\Delta T} = \dfrac{m}{\Delta t} ( \dfrac{RT}{M})[/tex]

[tex]\dfrac{m}{\Delta t} = \dfrac{\mathcal{P}}{L_v}[/tex]

Then:

[tex]P_o \times A \times v= \dfrac{\mathcal{P}}{L_v}\Big ( \dfrac{RT}{M }\Big)[/tex]

making (v) the subject of the formula:

[tex]v= \Big ( \dfrac{\mathcal{P} RT}{M\times L_v \times P_o \times A }\Big)[/tex]

Given that:

[tex]\mathcal{P}[/tex] = 0.90  kW = 900 W

R(rate constant) = 8.314 J/mol.K

Temperature at 100° C = 373K

For water vapor:

molar mass= 18.015 g/mol ≅ 0.0180 kg/mol

Latent heat of vaporisation [tex]L_v[/tex] = 2.26 × 10⁶ J/kg

Atmospheric pressure [tex]P_o = 1.013 \times 10^6 \ N/m^2[/tex]

Cross sectional area A =1.60 cm² = 1.60 × 10⁻⁴ m²

[tex]v= \Big ( \dfrac{900 W (8.314 \ J/mol.K)(373)}{0.0180 \ kg/mol) (2.26 \times 10^6 \ J/kg) (1.013 \times 10^5 \ N/m^2)(1.60 \times 10^{-4} \ m^2)}\Big)[/tex]

v = 4.233  m/s

A region of vacuum contains both a uniform electric field with magnitude E and a uniform magnetic field with magnitude B.
Part A What is the ratio E/B if the energy density for the magnetic field equals the energy density for the electric field? Express your answer in volts per meter-tesla to three significant figures. IVO ADV A O O ?
Part B If E = 750 V/m, what is B, in teslas, if the magnetic field and electric-field energy densities are equal? Express your answer in teslas. O ALQ * R O 2 ?

Answers

Answer:

A)    E / B = 2.99 10⁸  V/ mT,  B)     B = 2.50 10⁻⁶ T

Explanation:

A) the expressions for the energy densities are:

         u_E = ½ ε₀ E²

         u_B = ½ B² /μ₀

indicate that the two densities are equal

         ½ ε₀ E² = ½ B² /μ₀  

         E / B =  1 /[tex]\sqrt{\epsilon_o \ \mu_o }[/tex]

we calculate

         E / B = 1 / √( 8.85 10⁻¹² 4π 10⁻⁷

         E / B = 1 /√( 11.1212 10⁻¹⁸)

         E / B = 0.29986 10⁹9

         E / B = 2.99 10⁸  V/ mT

B) for this case E = 750 V / m, ask the magnetic field

         E / B =  1 /[tex]\sqrt{\epsilon_o \ \mu_o}[/tex]

         B = E [tex]\sqrt{\epsilon_o \ \mu_o}[/tex]

         

we calculate

        B = 750 √(8.85 10⁻¹² 4π 10⁻⁷

        B = 750 3.3348 10⁻⁹

        B = 2.50 10⁻⁶ T

The ratio E/B if the energy density for the magnetic field equals the energy density for the electric field

Energy densities can be expressed as

        u_E = ½ ε₀ E²

        u_B = ½ B² /μ₀

When the two densities are equal we use the formula

        ½ ε₀ E² = ½ B² /μ₀  

             E / B =  1 / μ₀  

             E / B = 1 / √( 8.85 10⁻¹² 4π 10⁻⁷)

             E / B = 1 /√( 11.1212 10⁻¹⁸)

             E / B = 0.29986 10⁹

             E / B = 2.99 10⁸  V/ mT

If the magnetic field and electric-field energy densities are equal and  E = 750 V / m, we can deduce that

      E / B =  1 / √ ξ₀ μ₀

       B = E √ ξ₀ μ₀

We substitute the values into the equation

        B = 750 √(8.85 10⁻¹² 4π 10⁻⁷)

        B = 750 3.3348 10⁻⁹

        B = 2.50 10⁻⁶ T

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A ball of mass 8kg falls from rest from a height of 100m. Neglecting air resistance, calculate its total energy after falling a distance of 40m.​

Answers

Answer:

Total energy, T= 4704 Joules

Explanation:

Given the following data;

Mass = 8kg

Initial height, h1 = 100m

Final height, h2 = 40 m

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the total energy, T;

T = mg(h1 - h2)

T = 8 * 9.8 * (100 - 40)

T = 78.4 * 60

Total energy, T= 4704 Joules

A person is 88 J of work lifting a grocery bag straight off the ground to a height of 1.7 m what is a grocery bags mass

Answers

Answer:

5.277 kg

Explanation:

Since the formula for work is W = F * d and we are given distance and work, the force on the grocery bag is 88 = F * 1.7 F = 88 / 1.7 = 51.765 N.

We also know that force follows the equation F = m * a. Since the constant gravitational acceleration on earth is 9.81 m / s^2, we can find the mass through 51.765 = m * 9.81 m = 51.765/9.81 = 5.277 kg

Which of these would have the most kinetic energy?
O A. a stormy ocean
O B. a running stream
O C. an icy lake
O D. a lake in summer

Answers

Answer:

A stormy ocean, having the most kinetic energy means it moves more and faster

Convert 13.7g to mg

Answers

13.7 grams is 13700 mg

Two events are observed in a frame of reference S to occur at the same space point, the second occurring 1.80 s after the first. In a frame S′ moving relative to S, the second event is observed to occur 2.05 s after the first. What is the difference between the positions of the two events as measured in S^?

Answers

Answer:

The difference between the positions of the two events as measured in = 3.53 *10^8 m/s

Explanation:

As we know -

[tex]\Delta x = -\gamma \mu\Delta t[/tex]

Here,

[tex]\Delta x[/tex] is the difference between the positions of the two events as measured in S^

[tex]\gamma[/tex] [tex]= \frac{1}{\sqrt{1-\frac{\mu^2}{c^2} } }[/tex]

And

[tex]\mu[/tex] = 0.547 c

Substituting the given values in above equation, we get -

[tex]\Delta x = (0.547 c)*\frac{1}{\sqrt{1-\frac{\mu^2}{c^2} } }*2.15\\\Delta x = (0.547 c)*\frac{1}{\sqrt{1-\frac{(0.547 c)^2}{c^2} } }*2.15\\\Delta x = (0.547 *3*10^8)*\frac{1}{\sqrt{(1-\(0.547 )^2 } }*2.15\\\Delta x = 3.53 *10^8[/tex]meter per second

A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 11 A, and that of the vacuum cleaner is 4.0 A. Determine the power consumed by (a) the blow-dryer and (b) the vacuum cleaner. (c) Determine the ratio of the energy used by the blow-dryer in 15 minutes to the energy used by the vacuum cleaner in one- half hour.

Answers

Answer:

(a) P₁ = 1320 W

(b) P₂ = 480 W

(c) [tex]\frac{E_1}{E_2} = 0.46[/tex]

Explanation:

(a)

The power consumed by the blow dryer can be calculated as follows:

[tex]P_1 = VI[/tex]

where,

P₁ = Power Consumed by the blow dryer = ?

V = Voltage = 120 V

I = Current Rating of the blow dryer = 11 A

Therefore,

[tex]P_1 = (120\ V)(11\ A)\\[/tex]

P₁ = 1320 W

(b)

The power consumed by the blow dryer can be calculated as follows:

[tex]P_2 = VI[/tex]

where,

P₂ = Power Consumed by the vacuum cleaner = ?

V = Voltage = 120 V

I = Current Rating of the vacuum cleaner = 4 A

Therefore,

[tex]P_2 = (120\ V)(4\ A)\\[/tex]

P₂ = 480 W

(c)

[tex]\frac{E_1}{E_2} = \frac{P_1t_1}{P_2t_2}[/tex]

where,

E₁ = Energy used by the blow-dryer

E₂ = Energy used by the vacuum cleaner

t₁ = time of use of the blow-dryer = (15 min)(60 s/1 min) = 900 s

t₂ = time of use of the vacuum cleaner = (1.5 h)(3600 s/1 h) = 5400 s

Therefore,

[tex]\frac{E_1}{E_2} = \frac{(1320\ W)(900\ s)}{(480\ W)(5400\ s)}\\\\\frac{E_1}{E_2} = 0.46[/tex]

Two cars collide in an intersection. The speed limit in that zone is 30 mph. The car (mass of 1250 kg) was going 17.4 m/s (38.9 mph) the truck (2020 kg) t boned the car in the middle of the intersection. The car was slowed down to only 6.7 m/s. The truck after colliding with the car was going 10.3 m/s. How fast did the truck go into the intersection?

Answers

Answer:

u₂ = 3.7 m/s

Explanation:

Here, we use the law of conservation of momentum, as follows:

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2\\[/tex]

where,

m₁ = mass of the car = 1250 kg

m₂ = mass of the truck = 2020 kg

u₁ = initial speed of the car before collision = 17.4 m/s

u₂ = initial speed of the tuck before collision = ?

v₁ = final speed of the car after collision = 6.7 m/s

v₂ = final speed of the truck after collision = 10.3 m/s

Therefore,

[tex](1250\ kg)(17.4\ m/s)+(2020\ kg)(u_2)=(1250\ kg)(6.7\ m/s)+(2020\ kg)(10.3\ m/s)\\\\(2020\ kg)(u_2) = 8375\ N.s + 20806\ N.s - 21750\ N.s\\\\u_2=\frac{7431\ N.s}{2020\ kg}[/tex]

u₂ = 3.7 m/s

if something is frictionless does it have thermal energy

Answers

Answer:

No

Explanation:

because there is no pressure

A man has 887.5 J of kinetic energy while running with a velocity of 5 m/s. What is his mass?

Answers

Answer:

The mass of the man is 71 kg

Explanation:

Given;

kinetic energy of the man, K.E = 887.5 J

velocity of the man, v = 5 m/s

The mass of the man is calculated as follows;

K.E = ¹/₂mv²

where;

m is the mass of the man

2K.E = mv²

m = 2K.E / v²

m = (2 x 887.5) / (5)²

m = 71 kg

Therefore, the mass of the man is 71 kg

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