Answer:
The steps involved in determining a Molecular Formula are: Find the mass of the empirical formula. Divide the molecular mass by the mass of the empirical formula. Multiply each subscript in the empirical formula by the answer.
Explanation:
Calculate the mass, in grams, of 912 atoms of iron, Fe (1 mol of Fe
has a mass of 55.85 g).
Answer:
8.45 × 10⁻²⁰ g
Explanation:
Step 1: Given data
Number of atoms of Fe (N): 912 atomsMolar mass of Fe (M): 55.85 g/molStep 2: Calculate the mass, in grams, of 1 atom of Fe
We will use Avogadro's number: there are 6.02 × 10²³ atoms of Fe in 1 mole of Fe.
55.85 g/mol × 1 mol/6.02 × 10²³ atom = 9.27 × 10⁻²³ g/atom
Step 3: Calculate the mass corresponding to 912 atoms
9.27 × 10⁻²³ g/atom × 912 atom = 8.45 × 10⁻²⁰ g
Given this balanced equation:
1 Cu + 1 H2SO4 -> 1 CuSO4 + 1 H2
If you have 22.45 moles of H2SO4 , how many mole of CuSO4 can you make?
Answer value
Why are cars manufactures exploring hydrogen fuel cell technology as a possiable replacement for gasoline burning engines
What is the voltage in a circuit is the current is 3 amps and the resistance is 3 ohms
Answer:
9
Explanation:
V=I*R
3*3
Thats the answer
Describe how naturally
acidic rainwater can affect a
mountain of limestone.
Answer:
The naturally acidic rain will gradually wear the mountain of limestone away.
Hope it helps!
Which of the following wavelength does NOT belong to visible light?
A.
690 nm
B.
900 nm
C.
500 nm
D.
390 nm
Answer:
I think is A 690 nm or c 500 nm
The wavelength that does not belong to visible light is 900 nm. The correct option is B.
What is visible light?Visible light is the electromagnetic spectrum that an eye can see. The wavelength of visual light is 382 700 nanometers. The daylight is the most visible light whose wavelength is 515 NM and whose color is green and yellow. The infrared, the range of spectrums of visible light, falls between infrared and ultraviolet light.
Wavelength is the distance of 1 wave to another wave full stop as light moves in the form of waves, that difference between one crust to another crust is called the wavelength of the light.
As the wavelength of visible light is 382 700 NM option b 900 NM will be will not fall under the spectrum of visible light.
Thus, the correct option is B. 900 nm.
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The temperature of an oxyacetylene torch flame can reach as high as 3137 °C. What is this temperature in Fahrenheit and Kelvin? Please show work.
Answer:
A)3410K
B)5678.6 °F
Explanation:
✓ To convert Celcius to Kelvin expression below can be used
K= °C + 273
We were given T=3137 °C
= 3137 + 273= 3410K
✓To convert Celcius to Fahrenheit, expression below can be used
°F =(°C × 9/5) + 32
We were given T=3137 °C
°F= (3137 × 9/5) + 32
= 5646.6+32
=5678.6 °F
The fertilization in __________happens outside the female's body
Answer:
Frogs
Explanation:
Answer:
Hello there! I'm assuming frog and or dog :)
Determine the entropy change for the combustion of gaseous propane, C3H8, under standard state conditions to give gaseous carbon dioxide and water.
Answer:
ΔS°reaction = 100.9 J K⁻¹ (mol C₃H₈)⁻¹
Explanation:
The equation for the reaction is given as;
C₃H₈(g) + 5O₂(g) → 4H₂O(g) + 3CO₂(g)
In order to determine the entropy change, we have to use the entropy valuues for the species in the reaction. This is given as;
S°[C₃H₈(g)] = 269.9 J K⁻¹ mol⁻¹
S°[O₂(g)] = 205.1 J K⁻¹ mol⁻¹
S°[H₂O(g)] = 188.8 J K⁻¹ mol⁻¹
S°[CO₂(g)] = 213.7 J K⁻¹ mol⁻¹
The unit of entropy is J K⁻¹ mol⁻¹
Entropy change for the reaction is given as;
ΔS°reaction = ΔS°product - ΔS°reactant
ΔS°reaction = [(4 * 188.8) + (3 * 213.7)] - [269.9 + (5 * 205.1)]
ΔS°reaction = 100.9 J K⁻¹ (mol C₃H₈)⁻¹
The entropy change for the combustion of gaseous propane, under standard state conditions 100.9 J K⁻¹.
The equation for the combustion of gaseous propane is given as follows:-
C₃H₈(g) + 5O₂(g) → 4H₂O(g) + 3CO₂(g)
In order to determine the entropy change, we have to use the entropy values for the species in the reaction. This is as follows:-
S°[C₃H₈(g)] = 269.9 J K⁻¹ mol⁻¹
S°[O₂(g)] = 205.1 J K⁻¹ mol⁻¹
S°[H₂O(g)] = 188.8 J K⁻¹ mol⁻¹
S°[CO₂(g)] = 213.7 J K⁻¹ mol⁻¹
The unit of entropy is J K⁻¹ mol⁻¹
Entropy change for the reaction is given as;
ΔS°reaction =nproduct ΔS°product - nreactantΔS°reactant
ΔS°reaction = [(4mol * 188.8 J K⁻¹ mol⁻¹) + (3 mol * 213.7 J K⁻¹ mol⁻¹)] - [(1 mol*269.9J K⁻¹ mol⁻¹ )+ (5 mol* 205.1 J K⁻¹ mol⁻¹)]
ΔS°reaction = 100.9 J K⁻¹
So, the entropy change for the combustion of gaseous propane is 100.9 J K⁻¹ .
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Radiation is different than the other types of heat transfer because
Explanation:
Heat transfer by radiation tends to be minimal in many everyday instances. This is in part, due to the 4th power exponentiation of the heat transfer equation that governs radiative heat transfer.
For instance, a bar of metal of 75 ºF will interact with your body, from a distance, when your body is at 98 ºF. But the temperature difference of 14 ºF will be so low, that it is difficult to feel or detect. However, if that bar was heated to 120º F and set close to you, you may begin to feel the heat from radiation. Then, if the bar was heated to the point that it began to glow red, several hundred degrees, not only would you feel it, but it may make you uncomfortably hot very quickly. If it was then heated to being white hot, you would almost certainly be burned by it, not by touching it, but simply by the radiative heat transfer. Again, its the 4th power exponent that really makes radiative heat transfer a powerful force when the temperature increases to a high level.
Another example from a text that I once used set an example of a person in a room with their body temperature at 98 ºF. In one case, the walls of the room surrounding the body are said to be 50º F, but in the other case, the walls are said to be 100º F. In both cases, the air in the room is said to be 75ºF. The question is asked: why is the person colder in the room with 50 ºF walls, when the air is the same temperature in both cases.
The answer is that the 100 ºF walls are acting to slightly warm the body, whereas the 50º F walls are actually taking heat away from the body by way of radiative heat transfer. You can do the equations to see exactly how much the different temperatures of the walls will effect this situation.
One final example - if you look into a thermos, you will see a highly reflective liner inside of the thermos. This is a radiant barrier, and it is put into the thermos to keep the liquid inside from losing heat by way of radiation. The reflective film will transfer back most of the heat that would otherwise be lost by radiating to the outer surface of the thermos, after which it would conduct through the side of the thermos. So a thermos provides a good example of a solution for heat transfer in the form of radiation.
The hybridisation of the central atom in ICL-2
a) sp.
b) sp2
c) sp3d d)sp3
Explanation:
For ICl²-, the central iodine atom is bonded to the 2 chlorine atoms and has 3 lone electron pairs.
Altogether it has 5 electron domains, which means it is sp3d hybridized. (C)
5. Write the two resonance hybrids for the carbocation that would be formed by protonation at C-1 of 2-methyl-1,3-pentadiene. Without doing a calculation, would you expect C-2 or C-4 (the two end carbons of the allylic cation) to have the most positive charge on it
Answer:
Follows are the solution to this question:
Explanation:
Please find the complete solution in the attached file.
Which elements make up 95 percent (by weight) of the human body?
A gas has a pressure of 0.0370 atm at 50.0°C. What is the pressure at 0.00°C?
MnO4 - is a stronger oxidizing agent than ReO4 - . Both ions have charge-transfer (LMCT) bands; however, the charge-transfer band for ReO4 - is in the ultraviolet, whereas the corresponding band for MnO4 - is responsible for its intensely purple color. Are the relative positions of the charge-transfer absorptions consistent with the oxidizing abilities of these ions? Explain
Answer:
[tex]$MnO^-_4$[/tex] is a strong oxidizing agent.
Explanation:
The 5d orbitals of Re are higher in energy than 3 d orbitals of Mn. So an LMCT ligand to metal charge transfer excitation requires more energy of [tex]$ReO^-_4$[/tex].
Also, since the molecular orbitals are derived primarily from 3d orbitals of [tex]$MnO^-_4$[/tex] are lower in energy than the corresponding MO's of [tex]$ReO^-_4$[/tex], [tex]$MnO^-_4$[/tex] is better able to accept the electrons.
So it is a better oxidizing agent.
The ligand to metal charge transfer band in ReO4- occurs in the near UV region hence ReO4 - appears colorless.
The electron configuration of Re is Xe 4f14 5d5 6s2 and the electron configuration of Mn is [Ar] 3d5 4s2. We can see that Mn^7+ and Re^7+ have empty d orbitals.
The color of MnO4 - must result from ligand to metal charge transfer hence the purple color of MnO4 -. In the case of ReO4 -, the ligand to metal charge transfer occurs at a much higher energy owing to the fact that 5d orbitals are involved. This transition occurs in the near UV region hence ReO4 - appears colorless. The ligand to metal charge transfer in MnO4- involves lower energy 3d orbitals hence it occurs in the visible region of the spectrum.
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Enter the electron configuration for I+ using noble gas shorthand notation.
In the first box enter the noble gas (notice the brackets). In the following boxes enter the number that goes in front of the orbital followed by the superscript.
For example, the electron configuration for sulfur is: [Ne]3s2 3p4
so the first box would have Ne in it followed by 3, then 2, then 3 then 4.
If you do not need an orbital, just enter 0 (zero) in the boxes for the coefficient and superscript.
[ ] s f d p
Find the element in the periodic table and count over
to the right the number of negative charges on your anion.
This element has the same electron configuration as your anion.
Which noble gas precedes the element? Knowing the s, p, d, and f blocks
of elements in the periodic table, deduce the the electron configuration
of the element from the preceding noble gas. Remember that the
1p 1d, 2d, 1f, 2f, and 3f orbitals are forbidden energy levels (they do not exist).
Answer:
[Kr] 4d10 5s2 5p4
Explanation:
The Symbol I represents Iodine. It has atomic number of 53. The full electronic configuration is given as;
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p5
However the question requested for the configuration of I+.
I+ is a cation and it simply refers to an iodine atom that has lost a single electron. The electronic configuration of I+ is given as;
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p4
Using Noble gas shorthand representation, we have;
[Kr] 4d10 5s2 5p4
Complete the following reaction: Li + S -->
Answer:
Li2S
Explanation:
Hope this helps.
Answer:
can u do an real answer pls so i can help u thanks
All camels are basically similar in structure. They have developed adaptations for
coping with both heat and dehydration.
Which of the following does not benefit the camel as a means of preventing dehydration?
A. Camels can extract water from their solid wastes.
B. Camels’ ears are lined with fur to keep out sand and other blowing matter.
C. Their kidneys are capable of concentrating urine to reduce water loss.
D. Camels are able to locate water in any environment.
Answer:
B. Camels’ ears are lined with fur to keep out sand and other blowing matter.
10 points Part F
Identify at least two limitations of the simulation. How do these limitations influence the
simulation's ability to model the synthesis of ammonia?
Answer and Explanation:
When using simulations, it is important that the researcher knows some limitations. This is because the simulations do not behave exactly like what they represent, in addition to not presenting very important details for analysis and without approximations of what really happens with what they are representing. When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.
When using simulations, it is important that the researcher knows some limitations. This is because the simulations do not behave exactly like what they represent, in addition to not presenting very important details for analysis and without approximations of what really happens with what they are representing. When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.
If you were to mass the reactants before the reaction and then mass the products after the reaction,what would you expect to find? Why? How is this related to balancing your equations?
Explanation:
What would you expect to find?
- The masses of the reactants would be equal to the masses of the product.
Why?
- This is due to the law of conservation of matter which states that matter is neither created nor destroyed in an isolated system but converted from one form to the other.
How is this related to balancing your equations?
- This is why during balancing of equations, we must ensure that the number of atoms in the reactant side must be equal to the number of atoms in the product side.
What is the electronegativity and bond polarity like in the "head" vs. the "tail" ends of soap?
Answer:
gay
Explanation:
very gay
In a reaction that produces carbon dioxide, the theoretical yield is 59 grams. During the experiment, the reaction actually produced 52.9 grams of carbon dioxide. Determine the percent yield.
Answer:
mole ratio, which is equivalent to a 1;1 mole ratio, to a gram ratio. This means that when the reaction consumes 84.03 g of carbon monoxide, it should theoretically produce 132.03 g of carbon dioxide. Use this gram ratio to calculate the theoretical yield for your reaction.
Explanation:
Calculate [H+] and [OH-] as required for each of the following
solutions at 25 °C, and state whether the solution is neutral, acidic,
or basic.
a. 1.0x 10-5 MOH-
Q
b. 1.0x 10-7 MOH-
c. 10.0 MH+
Explanation:
The relationship between H+ and OH- at 25 °C is given as;
[H+} x [OH-] = 1.0 x 10-14 M
a. 1.0 x 10-5 M OH-
[OH-] = 1.0 x 10-5 M
[H+] = 1.0 x 10-14 M / [OH-] = 1.0 x 10-14 M / 1.0 x 10-5 M
[H+] = 1.0 x 10^(-14+5)
[H+] = 1.0 x 10^(-9)
pH = - log [H+]
pH = - log [10^(-9)]
pH = 9
This is a basic solution
b. 1.0 x 10-7 M OH-
[OH-] = 1.0 x 10-7 M
[H+] = 1.0 x 10-14 M / [OH-] = 1.0 x 10-14 M / 1.0 x 10-7 M
[H+] = 1.0 x 10^(-14+7)
[H+] = 1.0 x 10^(-7)
This is a neutral solution since [H+] and [OH-] are equal
c. 10.0 M H+
[H+] = 1.0 x 10 M
[OH-] = 1.0 x 10-14 M / [H+] = 1.0 x 10-14 M / 1.0 x 10 M
[OH-] = 1.0 x 10^(-14-1)
[OH-] = 1.0 x 10^(-15)
pH = - log [H+]
pH = - log [10^(1)]
pH = -1
This is an acidic solution since it has a pH of -1
According to the graph, what is the instantaneous speed of the object at 5 seconds? *
Captionless Image
4 m/s
7 m/s
0.25 m/s
3 m/s
Answer:4m/s
Explanation:The reason why that the answer is because I am Smart.
Which statement best describes the coriolis effect
The coriolis effect is responsible for many large scale weather patterns. The coriolis force is responsible for the deflection of objects. It is this effect which drive the global wind and ocean circulation patterns. The correct option is C.
What is coriolis effect?The apparent effect produced by a rotating frame of reference is defined as the coriolis effect. This effect occurs when an object moving along a straight path is viewed from a non-fixed frame of reference.
Because of the earth's rotation, when an object moving in a straight path is viewed from earth, it appears to lose its course. So the travelling long distances around the earth appear to move at a curve instead of a straight line due to coriolis effect.
The coriolis effect is found to be strongest near poles and it is absent at the equator. The coriolis force is an apparent force caused by the rotation of earth.
Thus the correct option is C.
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Your question is incomplete, most probably your question was:
Which statement best describes the coriolis effect
A. The oceans that receive more rain have water with lower salinity.
B. Closer to the poles, the temperature of ocean water decreases.
C. The rotation of Earth causes the apparent path of ocean currents
to curve,
D. Ocean water becomes denser the deeper you go underwater.
No pain no gain . which figure of speech is this
Answer:
No pain, no gain is a proverb that means in order to make progress or to be successful, one must suffer. This suffering may be in a physical or mental sense. The phrase no pain, no gain was popularized in the 1980s by the American actress, Jane Fonda.
what information is shown in the infographics?
Answer:
An infographic is a collection of imagery, charts, and minimal text that gives an easy-to-understand overview of a topic. As in the example below, infographics use striking, engaging visuals to communicate information quickly and clearly. Infographics are a valuable tool for visual communication.
The pain reliever morphine contains 17.900 g C, 1.680 g H, 4.225 g O, and 1.228 g N. Determine the empirical Formula.
Answer: The empirical formula is [tex]C_{17}H_{19}O_3N[/tex]
Explanation:
Mass of C= 17.900 g
Mass of H = 1.680 g
Mass of O = 4.225 g
Mass of N = 1.228 g
Step 1 : convert given masses into moles.
Moles of C =[tex]\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{17.990g}{12g/mole}=1.5moles[/tex]
Moles of H =[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.680g}{1g/mole}=1.680moles[/tex]
Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{4.225g}{16g/mole}=0.264moles[/tex]
Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{1.228g}{14g/mole}=0.087moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = [tex]\frac{1.5}{0.087}=17[/tex]
For H = [tex]\frac{1.680}{0.087}=19[/tex]
For O =[tex]\frac{0.264}{0.087}=3[/tex]
For N = [tex]\frac{0.087}{0.087}=1[/tex]
The ratio of C : H: O: N = 17: 19: 3: 1
Hence the empirical formula is [tex]C_{17}H_{19}O_3N[/tex]
Select the option that best represents recycling food waste
O turning food scraps into biogas
O donating unused food to food pantries
O incinerating leftover food
O feeding scraps to livestock
Answer:
feeding leftover or scraps to livestock
Explanation:
Because feeding leftover healthy food instead of leaving livestock to eat garbage is good for health of the animals and they give good quality of milk, eggs, meat, etc in return
Please help me I need this really quick
Answer:
The answer is (a)
.
.
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