Exit ticket: A lamp is plugged into a 110 Volt electrical outlet. There is a 9 Watt LED bulb in the lamp. a. What is
the current in the bulb? b. What is the resistance of the bulb?

Answers

Answer 1

Answer:

(a) 0.081 A (b) 1358.02 ohms

Explanation:

Voltage, V = 110 volt

Power of a LED bulb, P = 9 Watt

(a) Let the current is I. The formula for ower in terms of voltage and power is given by :

P = VI

[tex]I=\dfrac{P}{V}\\\\I=\dfrac{9}{110}\\\\=0.081\ A[/tex]

(b) Let R is the resistance of the bulb. Using Ohm's law as follows :

V = IR

[tex]R=\dfrac{V}{I}\\\\R=\dfrac{110}{0.081}\\\\=1358.02\ \Omega[/tex]

Hence, this is the required solution.

Answer 2

(a) The current in the bulb is 82mA

(b) The resistance of the bulb is 1340 Ω

Given information:

Supply voltage, V = 110V

The power rating of the bulb, P = 9 W

Electrical Power:

(a) Current in the bulb:

The electrical power is given by:

P = VI

where V is the voltage, and I is the current

So, I = P/V

I = 9W / 110V = 0.082A

I = 82 mA

(b) Resistance of the bulb:

According to the Ohm's Law:

The relation between voltage (V), current (I), and resistance (R) is given by:

V = IR

110 = 0.082R

R = 1340 Ω

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Related Questions



During a laboratory experiment, the temperature of the gas in a balloon is varied and the

volume of the balloon is measured.

A)

Which quantity is the independent variable?

B)

Which quantity is the dependent variable?

Answers

A. The IV is the temperature of gas in the balloon.

B. The DV is the volume of the balloon.

This is because the temperature of the gas is the variable being manipulated in the experiment (Independent) and the volume is changing based on the shifts of the temperature (thus volume is Dependent).

what are the Standard System of unit​

Answers

Answer:

SI

Explanation:

function Of The glottis​

Answers

Answer:

Their function is to produce sound by allowing the free edges of the folds to vibrate against one another and also to act as the laryngeal sphincter when they are closed.

Answer:

The glottis is found within the larynx, and the epiglottis is a flap-like structure on top of the trachea. When swallowing, it will press downward to partially close off the trachea. Function of the glottis and epiglottis do to help prevent food and liquid from entering the air passage (trachea)

Can I please get brainliest

A motorcyclist sees a branch in the road and hits the brakes, slowing down at -6.42 m/s. if it takes him 2.85 seconds to stop, what was his starting velocity?

Answers

Use the definition of average acceleration:

a = ∆v / t

If v is the starting speed, then ∆v = 0 - v, so solve for v :

-6.42 m/s² = (0 - v) / (2.85 s)

v = (6.42 m/s²) (2.85 s)

v ≈ 18.3 m/s

While the boys were playing baseball, one of the boys decides to kick his soccer ball high into the air. As the ball goes upward, which type of energy is increasing?
A.) Kinetic Energy
B.) Thermal Energy
C.) Potential Energy
D.) Mechanical Energy​

Answers

A.) Kinetic energy is the answer

Two children are spinning on a miracle round. What is 50 cm from the center and the other is 100 cm from the center. Which child has the larger linear speed?

Answers

Answer:

The one that is 100 cm from the center.

Explanation:

Given that merry-go-round means moving at uniform circular motion or constant angular speed. Hence the person who is closer to the center is moving at a slower speed, while the one far away from the center has a larger linear speed because he has moved a long distance in the same amount of time, despite being on these objects.

To illustrate

A with the 50 cm

B with the 100 cm

Hence, to get speed, we have

A = 2 * pi * 50 / T

B = 2 * pi * 100 / T

And by the explanation of angular speed

We have w = 2*pi/T where w is the angular speed in radians/s

Hence we have

A = 50w

B = 100w

Therefore, the one that is 100 cm from the center has a larger linear speed.

F = M x G

Find the force of gravity acting upon a 1500Kg Hippopatamus.

Answers

Answer:........... .. .....

A car of mass 1470 kg is on an icy driveway
inclined at an angle of 40◦. The acceleration of gravity is 9.8 m.
If the incline is frictionless, what is the acceleration of the car Answer in units of m/s

Answers

Answer:

  a = 7.5 m / s²

Explanation:

For this exercise let's use Newton's second law, let's create a coordinate system with the x axis parallel to the plane and the y axis perpendicular to the plane

Y axis

       N - W cos θ = 0

       N = mg cos θ

X axis

       W sin θ = m a

 

       mg sin θ = m a

        a = g sin θ

let's calculate

        a = 9.8 cos 40

        a = 7.5 m / s²

1. Discuss how we use trial and error, algorithms, heuristics, and insight to solve problems. For each concept, define the term and then describe an incident (either from your own experience or that of a friend) in which the concept was used to determine a solution to a specific problem. You must use specific details of the incident and terms from our module to show me you understand the concept. (Total 64 points)
2., How can confirmation bias and fixation can interfere with effective problem solving. In this portion of your response, for each concept, define the term and then describe an incident (either from your own experience or that of a friend) in which the concept interfered with an appropriate solution being determined. You must use specific details of the incident and terms from our module to show me you understand the concept. (Total 32 pts).

Answers

Answer: used concepts to simplify and order the world around us, categories: objects, events, ideas, or people

hierarchies: subdivide categories into smaller more detailed units, prototypes: best example

algorithm: time-consuming but thorough set of rules or procedures

heuristics: simpler way of thinking, solve problems but maybe incorrect solutions

insight: flash of inspiration that solves problem

representativeness heuristic: judge likelihood of things in terms of how they represent our prototype

availability heuristic: judge likelihood of things based on how vivid they are or how readily they come to mind.

Explanation: i hope that helped!


A group of students is making paper airplanes. They think that the kind of paper and the design of the airplane may affect how for each paper airplane fles. The students first test if the kind of paper affects how far the
airplane fies. They make
several otrplanes out of different kinds of paper, using
the same design Why is it important that all the airplanes have the same design?

Help please !!

Answers

Answer:

The reason why it is important that all the airplanes have the same design is that the students first test is an experiment to determine the effect of the paper kind on the distance the airplane flies

The first experiment, therefore measures the effect of the independent variable, which is the kind of paper on the dependent variable, which is how far the paper flies

The constant or the factor held constant in the experiment is the design of the airplane, so as to ensure that changes in the distance flown by the airplane are due to the changes in the kind of paper alone

Explanation:

A ball is released from a hot air balloon moving downward with a velocity of
-10.0 meters/second and a height of 1,000 meters. How long did it take the ball to reach the surface of Earth? Given: g = -9.8 meters/second2.
A
11.2 seconds
B.
12.1 seconds
C.
13.3 seconds
D.
13.5 seconds
E.
14.2 seconds

Answers

the answer is b. 12.1 seconds

Which material rises from cracks in oceanic crust?

Answers

Answer:

trenchs and magma

Explanation:

Answer: Ridges form along cracks (divergent boundaries) in the oceanic crust (Molten rock (magma) rises through these cracks and pushes to both sides. When it cools, it forms new oceanic crust. The old crust is pushed away and new crust takes over. This is called Sea-Floor Spreading.

1. A motorcycle stunt driver rides his motorcycle off a small ledge

that is 8.4 meters high. His initial velocity as he rides off the cliff is

24 m/s in the horizontal direction.

a. How long does it take before he lands on the ground below?

b. How far away from the base of the cliff does he travel while in

the air?

Answers

Answer:

Explanation:

Given

Height S = 8.4m

Initial velocity u = 24m/s

Required

Time it will take to reach the ground

Using the equation of motion

S = ut +1/2gt²

8.4 = 24t + 1/2(9.8)t²

8.4 = 24t+4.9t²

4.9t²+24t - 8.4 = 0

Multiply through by 10

49t²+240t-84 = 0

Factorize

t = -240±√240²-4(49(-84)/2(49)

t = -240±√57600+16464/98

t = -240±√74064/98

t = -240±272.15/98

t = 32.15/98

t = 0.328seconds

Hence it takes 0.328seconds before it lands on the ground below.

b) The horizontal distance is the range expressed as;

R = u²/g

R = 27²/9.8

R = 729/9.8.

R = 74.39m

a. The time it took before the motorcycle stunt driver lands on the ground below is 1.31 seconds.

b. The distance from the base of the cliff that the motorcycle stunt driver traveled while in  the air is 31.44 meters.

Given the following data:

Maximum height = 8.4 meters.Initial velocity = 24 m/s.

We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex]

a. To determine how long (time) it took before the motorcycle stunt driver lands on the ground below:

At maximum height, time is given by the formula:

[tex]Time = \sqrt{\frac{2H}{g} }[/tex]

Where:

g is the acceleration due to gravity.H is the maximum height.

Substituting the given parameters into the formula, we have;

[tex]Time = \sqrt{\frac{2\times 8.4}{9.8} }\\\\Time = \sqrt{\frac{16.8}{9.8} }\\\\Time =\sqrt{1.7413}[/tex]

Time = 1.31 seconds.

b. To determine how far (distance) away from the base of the cliff the motorcycle stunt driver traveled while in  the air:

[tex]Horizontal\;distance = horizontal\;speed \times time\\\\Horizontal\;distance = 24 \times 1.31[/tex]

Horizontal distance = 31.44 meters.

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if a truck goes 30 kilometers in 30 minutes what is the average speed ​

Answers

Answer:

60 km per hour

Explanation:

if you drive for 30 min and go 30km then if you drive for 60 min(1hr) then you would have driven 60km.

Answer:

60

Explanation:

hope this helps

Which procedure would best demonstrate that moving magnet causes an electric current to flow in a wire coil?

Answers

Answer:

D

Explanation:

I took the test

The procedure that would best demonstrate that moving magnet causes an electric current to flow in a wire coil is connect a wire coil to an ammeter. Move a bar magnet into and out of the wire coil as you observe the ammeter. The correct option is D.

What is electric current?

The flow of electricity in an electronic circuit, as well as the amount of electricity flowing through a circuit, are referred to as electric current. It is expressed in amperes (A).

The greater the value in amperes, the more electricity flows through the circuit.

When an electron is introduced into a wire, a free electron is attracted to a proton in order to be neutral.

Forcing electrons out of their orbits can result in an electron shortage. Electric current is the continuous movement of electrons in a wire.

Connecting a wire coil to an ammeter is the best way to demonstrate that a moving magnet causes an electric current to flow in a wire coil. As you watch the ammeter, move a bar magnet in and out of the wire coil.

Thus, the correct option is D.

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what is static electricity? explain how electrons are involved
please answer asap ​

Answers

Answer:

Electricity produced via friction is a development of electric charges on articles. Energizes construct when negative electrons are moved starting with one article then onto the next. The article that surrenders electrons turns out to be decidedly charged, and the item that acknowledges the electrons turns out to be contrarily charged. This can occur in a few different ways.

Explanation:

[tex]\mathrm {All, done!}[/tex]

What is the voltage drop across the 10.0 Ω resistor?

Answers

Answer:

its 120 C

Explanation:

its 120 C

The voltage drop across the 10.0 Ω resistor is c)120V

What is voltage drop in a circuit ?

Voltage drop is the decrease of electrical potential along the path of a current flowing in an electrical circuit.

since , all three resistors 10Ω , 20 Ω and 30Ω are in series combination

this implies that voltage drop across each resistor will be same as the total voltage drop in the circuit because in parallel combination voltage remain same in the circuit buy current get divided in each branch  

hence , the voltage drop across the 10.0 Ω resistor = 120 V

  correct answer c) 120 V

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Una curva de radio R = 75 [m] tiene un peralte hecho de tal forma que un auto andando a v1 = 35 [m/s] no derrape incluso con el piso congelado (sin roce). ¿Cuál es el coeficiente de roce estático mínimo necesario entre las ruedas y el pavimento para que, en un día seco y soleado, el auto no derrape cuando avanza a v2 = 118 [m/s]?

Answers

Answer:

053.

Explanation:

Given that the radius of curvature of the path, R = 75 m.

Speed of the car on that path , [tex]v_1 = 35 m/s[/tex]

The centripetal force,[tex]F_c[/tex] acting on the body having mass, m, when it moves with the velocity v  on curved path having radiusR

Ris[tex]F_c = mv^2/R[/tex]

Gravitational force, [tex]F_g[/tex] = mg.

Let tha angle of superelevation is [tex]\theta.[/tex]

As the car does not skid even with zero friction, so

[tex]mg\sin\theta = (mv_1^2)/2 \cos\theta[/tex]

[tex]\Rightarrow \tan\theta = v_1^2/2g=\cdots(i)[/tex]

On sunny day, let the minimun static friction coefficient between the wheels and the pavement is [tex]\mu.[/tex]  

As [tex]v_2[/tex] = 118 m/s is greater than   v_so the car tends to skid in upper direction and the frictional

force,f, will acts is downward direction.

As there is no skidding, so

[tex]f+ mg\sin\theta= (m(v_2)^2)/R\cos\theta[/tex]

[tex]\Rightarrow f=(m(v_2)^2)/R\cos\theta - mg\sin\theta[/tex]

where [tex]f= \mu N.[/tex]

[tex]So, \mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{N} \cdots(ii)[/tex]

Where N is the normal reaction can be determined by balancing the force in perpendicular direction of the plane.

[tex]N= mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta[/tex]

From equation (ii)

[tex]\mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]

[tex]=\frac{-g\tan\theta+v^2/R}{v_2^2\tan\theta+g}[/tex]

[tex]= \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]

[tex]=\frac{-g(v_1^2/2g)+v^2/R}{v_2^2(v_1^2/2g)+g}[/tex]

[tex]= \frac{v_2^2/R-v_1^2/R}{g+v_2^2/R\times v_1^2/Rg}[/tex]

[tex]=\frac{118^2/75-35^2/75}{9.81+118^2/75\times 35^2/(75\times 9.81)}[/tex]

=0.53

Hence, the minimum coefficient of friction is 0.53.


The place where potential energy is zero is
a) At height equal to double the radius of the earth
b) At infinity
c) At a height equal to half the radius of the earth
d) At a depth equal to 1/3 radius of the earth​

Answers

Answer:

D. At a depth equal to 1/3 radius of the earth

If your talking about orbit objects then it’s at infinity

the velocity of a car changes from 5 m/s to 20 m/s in 30 sec the acceleration?​

Answers

Answer:

0.5m/s2

..............

a = vf -vi/t
Velocity final - velocity initial/ time
(20 m/s - 5 m/s)/ 30s
15 m/s/ 30s = 0.5 m/s^2

PLEASE

HELP!!!

Jacob and Matthew are pulling a 20 kg box filled with chocolate along the ground, while Savannah is trying to pull it back in the other direction. Jacob is pulling with 50 N, Matthew with 40 N, and Savannah is pulling with 60 N in a negative direction. Draw an FBD; it should have 5 forces on it. Find the net Force. Then calculate the acceleration of the box. Lastly, calculate the acceleration if Mathew decides to run for his life and stop pulling.

Answers

Explanation:

N/B: Please see attached a rough sketch of the free body diagram for your reference.

From the diagram, the weight W is acting downward and the resultant R is in the positive direction

Given data

mass m=20kg

Forces

Jacob is pulling with 50 N,

Matthew with 40 N, and

Savannah is pulling with 60 N in a negative direction

Required

The net force

Net force= 50+40-(60)

               =90-60

               =30N in the possitive direction(in Jacob and Mathew's direction)

we know that F=ma

a=F/m

a= 30/20

a=1.5m/s^2

if Mathew decides to run for his life and stop pulling the net force will be

Net force=50-60=-10N (in Savannah's direction)

a=F/m

a=10/20

a=0.5m/s^2

What is the weight of a 500g ball? (gravity is 9.8 m/s)​

Answers

Answer:

4,900

Explanation:

you find the weight by multiplying the ball in grams to the gravity

The weight or force due to gravity of a 500 g ball is 4.9 N.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Given in the question  a 500 g ball,

Weight = mass.gravity

Weight = .5*9.8

Weight = 4.9 N

The weight or force due to gravity of a 500 g ball is 4.9 N.

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Definition of uniform speed​

Answers

Answer:

Uniform Speed: A body is said to be moving with uniform speed, if it covers equal distances in equal intervals of time. Variable Speed: A body is said to be moving with variable speed if it covers unequal distances in equal intervals of time.

Explanation:

I got it from google

Answer:

Speed is a measure of how fast an object is moving at a given instant of time. It is a scalar quantity. Its unit is m/s. For a body covering equal distances in equal time intervals, the speed is called uniform speed.

Explanation:

A motorbike is traveling to the left with a speed of 27.0 m s 27.0 s m ​ 27, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction when the rider slams on the brakes. The bike skids 41.5 m 41.5m41, point, 5, start text, m, end text with constant acceleration before it comes to a stop. What was the acceleration of the motorbike as it came to a stop?

Answers

Answer:

Explanation:

Initial velocity , u = 27 m/s

displacement before stop,  s = 41.5 m .

final velocity,  v = 0

acceleration a = ?

v² = u² + 2 a s

0 = 27² + 2 x a x 41.5

a = - 27² / 2 x 41.5

= - 8.78 m /s

Find the horizontal and vertical components of 75.0 N at 65 degrees

Answers

Horizontal component = 75 · cosine(65°)  =  31.7 N  

Vertical component = 75 · sine(65°)  =  68.0 N

1. A ball is thrown straight up.if the launch velocity is 15 m/s, at what velocity will the ball return to the thrower's hand?

2. A boat moves across a river going 18 m/s. At the same time there is a current flowing at a right angle to the boat at 6 m/s. What is the resulting velocity of the boat?​

Answers

Answer:

1) The velocity of the ball return to the thrower's hand is -15 meters per second.

2) The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].

Explanation:

1) Let suppose that ball experiments a free fall, that is an uniform accelerated motion, in which effects from gravity and Earth's rotation can be neglected. The velocity of the ball is represented by the following equations of motion:

Position

[tex]v_{o}\cdot t -\frac{1}{2}\cdot g\cdot t^{2} = 0[/tex]

[tex]t\cdot \left(v_{o}-\frac{1}{2}\cdot g\cdot t \right) = 0[/tex] (1)

Velocity

[tex]v = v_{o}-g\cdot t[/tex] (2)

Where:

[tex]t[/tex] - Time, measured in seconds.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v_{o}[/tex] - Initial velocity of the ball, measured in meters per second.

[tex]v[/tex] - Final velocity of the ball, measured in meters per second.

From (1), we get the time when the ball returns to the thrower's hand:

[tex]v_{o}-\frac{1}{2}\cdot g\cdot t = 0[/tex]

[tex]t = \frac{2\cdot v_{o}}{g}[/tex]

And then we apply this result in (2):

[tex]v = v_{o}-g\cdot \left(\frac{2\cdot v_{o}}{g} \right)[/tex]

[tex]v = -v_{o}[/tex] (3)

Then, the velocity of the ball return to the thrower's hand is -15 meters per second.

2) The resulting velocity of the boat ([tex]\vec v_{B}[/tex]) is represented by the vectorial sum of the velocity of the boat relative to the river ([tex]\vec v_{B/R}[/tex]) and the velocity of the river ([tex]\vec v_{R}[/tex]), both measured in meters per second, that is:

[tex]\vec v_{B} = \vec v_{R}+\vec {v}_{B/R}[/tex] (4)

If we know that [tex]\vec v_{R} = 6\,\hat{i}\,\left[\frac{m}{s} \right][/tex] and [tex]\vec v_{B/R} = 18\,\hat{j}\,\left[\frac{m}{s} \right][/tex], then the resulting velocity of the boat is:

[tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex]

The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].

Two forces of magnitude 40N and 70N acts on an object calculate and write the resultant force acting on the object and the resultant a
direction of force when both the force act in opposite direction

A) 70N in the direction of lesser force

B) 110N,opposite direction

C) 30N,in the direction of the greater force

D) 30N in the direction of lesser force​

Answers

Explanation:

Required Answer

70N-40N=30N

30N in lesser force

An airplane is flying with velocity of 70km\hr in north east direction .The wind is blowing 30km\hr from north to south.What is the resultant displacement of the aeroplane in 4 h

Answers

Answer:

The resultant displacement of the airplane in 4 hours is 212.8 km.

Explanation:

The components of the airplane's velocity and wind's velocity are:

Airplane:

[tex] v_{a_{x}} = v_{a}cos(45) = 70 km/h*cos(45) = 49.50 km/h [/tex]

[tex] v_{a_{y}} = v_{a}sin(45) = 70 km/hsin(45) = 49.50 km/h [/tex]

Wind:

[tex] v_{w_{x}} = 0 [/tex]

[tex] v_{w_{y}} = v_{w} = -30 km/h [/tex]

Now, to know the new velocity of the airplane we to find the result vector:

[tex] v_{x} = v_{a_{x}} + v_{w_{x}} = 49.50 km/h + 0 = 49.50 km/h [/tex]

[tex]v_{y} = v_{a_{y}} + v_{w_{y}} = 49.50 km/h - 30 km/h = 19.50 km/h[/tex]  

Now, the magnitude of the new speed of the airplane is:

[tex] v_{a} = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(49.50 km/h)^{2} + (19.50 km/h)^{2}} = 53.20 km/h [/tex]

Finally, after 4 hours the resultant displacement of the airplane is:

[tex] x = v*t = 53.20 km/h*4 h = 212.8 km [/tex]

Therefore, the resultant displacement of the airplane in 4 hours is 212.8 km.

I hope it helps you!                                        

A ball weighing 2.0 N falls through a distance of 4 m.

Answers

Answer:

This question is incomplete, a possible question would be to calculate the work done by the ball.

Work done = 8J

Explanation:

Work done by an object is calculated my multiplying the force by the distance.

The weight of this ball is 2.0N, which also represents the force exerted by the ball. The ball travels through a distance of 4m

Hence, work done = F × d

Work done = 2N × 4m

Work done = 8Nm or 8J

can somone pls help me??!! i’m very stuck

Answers

Answer:

graph b

Explanation:

graph a isnt constant

graph c is slower (less steep slope)

graph d is slowing down (starts high ends low)

Other Questions
Define concentration gradient. List two other names by which the Hudson River has been identified. Please define: Mercantilism, Import, Export, Enumerated article, Legislature, Indentured servant. Maria's plant grew 3 1/4 inches every month for 2 1/2 months. How many inches did Maria's plant grow during that time? Kevin wants to buy 2.5 pounds of chicken at $6.49 per pound. How much will he pay? How many moles of Cl2 are needed in order to produce 100.0 grams of FeCl3 given the followingequation: 2 Fe + 3 Cl2 2 FeCl3BT 1) Elle va lance la balle. ( lance / lanc / lancer )2) Les enfants du lit. ( sauter / saut / sautent )3) La femme la pomme. ( attraper / a attrap / attrapent )4) Cette horloge . ( marcher / marche / marchent )5) Ne pas par-dessus la clture ! ( saute / saut / sautes )6) Cest difficile de cet ordinateur. ( rpare / rparer / rpar )7) Cet ordinateur portable . ( marchent / marche / marcher )8) mon vlo, sil vous plat. ( rpar / rparez / rparer )9) Est-ce que tu peux cet arbre ? ( grimpe / grimper / ne grimpe pas )could someone do this for me lol Over the course of his famous conditioning experiments, what did Pavlovs dogs learn? A. They learned to eat food at the ring of a bell. B. They learned to ring a bell in order to get fed. C. They learned to eat when they began salivating. D. They learned to salivate at the sound of a bell. PSYCHOLOGY What system do we use to bind periods, eras, etc., of time together? Which sentence is written in standard English?Andrew and John have always been frenemies.O Leo realized that what he was saying was ridiculouso We saw some ginormous redwood trees in northern California,The outfit Olivia wore to the costume party was on point Giovanni justifies whether the expression -4x-8 is equivalent to -2(x+1)-2(x+3) by letting x=3 in both expressions. What is the value of each expression when x=3.3 and -204 and 4-20 and -203 and 4 At Saturday nights football game there were 18 less fans than half the fans at Friday nights game. There were x fans at Fridays game. Write an expression to represent the number of fans at Saturdays game. Given x:y:z = 7:2:5 and the value ofx - z =18. Find the value of x+y+z.Diberi x:y:z = 7:2:5 dan nilai x - 2 =18.Cari nilai bagi x+y+zA 14B. 126C. 210D. 232 5. Describe the different causes of climate change. Solve for x.14 = 28 + 7x y=_x+_ what would be the answer What is the difference between a social issue and a social problem? which one is it [photo is attached] Greek civilization was known for creating:A.a religion that worshipped only one god.B.philosophies based on logic and reason.C.powerful armies using gunpowder.D.a society that did not allow slavery. Which is an example of cultural appropriation?A. A white actor made up to look like an Asian in a film about karateO B. A non-Christian person wearing a cross on a necklace because itis fashionableO C. A non-American Indian person going to a sweat lodge because ithas become a popular place to goO D. All of the above