I’ll give you 15 points if you know the answers to this question
It would be B)no.
Hope This Helps!
what is the equivalent property of 8(4x - 3)
Answer:
=32x−24
Step-by-step explanation:
7. Which of the following expressions contains like terms?
5xy - 13y
5x - 13xy
5xy - 13x
5xy - 13xy
Answer:
The last one
Step-by-step explanation:
Due to there being xy's in both terms
3/4 x 25 please bro and i need to make this longerrrr
Answer:
18.75
Step-by-step explanation:
18.75
What is the fraction shown above?
Farmer Ben has only ducks and cows 24 in total. He can’t remember how many of each he
has. He knows that the animals have a total of 66 legs. Assuming that each animal has all legs intact
and no extra limbs, how many of each animal does farmer Ben have? Draw a clear diagram to answer
this question.
Help ME and plzz show your work thank you love
what unfortunate mistake did the champion ice skater make with his gold medal
Answer:
He Had It Bronzed
Step-by-step explanation:
Hope this help pls mark as brainlest!!
Reflect a figure with vertices A(1,2) B (3,6), C(-1,2), and D(-2,-2)
across the x-axis. Find the coordinates of the new image.
A) C(-1,2) --> C' (-1,-2)
B) B(3,6) --> B' (3,-6)
C) A(1,2) --> A' (1,-2)
D) D(-2,-2)--> D' (-2,2)
Answer:
1,2 = 1,negative2
3,6 = 3,negative 6
-1,2 = negative 1, negative 2
-2,-2 = negative2, 2
Step-by-step explanation:
Sorry all i could do was reflect the coordinates across the x-axis.
The figure reflected along x-axis will have vertices A(1, -2), B (3, -6), C(-1, -2), and D(-2, 2).
What is reflection along the x-axis?When we reflect a figure along the x-axis the coordinate point of y changes its sign, (x, y) becomes (x, - y).
Think of holding the x-axis with two fingers and rotating it.
Given, we reflect a figure with vertices A(1,2) B (3,6), C(-1,2), and D(-2,-2)
across the x-axis.
∴ The rotated coordinate will be A(1, -2), B (3, -6), C(-1, -2), and D(-2, 2).
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12+22+32+...+102 =?
Answer:
750 is the answer. Hope it helps!
Suppose X has an exponential distribution with mean equal to 11. Determine the following: (a) (Round your answer to 3 decimal places.) (b) (Round your answer to 3 decimal places.) (c) (Round your answer to 3 decimal places.) (d) Find the value of x such that . (Round your answer to 2 decimal places.)
Answer:
[tex]P(X > 11) = 0.368[/tex]
[tex]P(X > 22) = 0.135[/tex]
[tex]P(X > 33) = 0.050[/tex]
[tex]x = 33[/tex]
Step-by-step explanation:
Given
[tex]E(x) = 11[/tex] --- Mean
Required (Missing from the question)
[tex](a)\ P(X>11)[/tex]
[tex](b)\ P(X>22)[/tex]
[tex](c)\ P(X>33)[/tex]
(d) x such that [tex]P(X <x)=0.95[/tex]
In an exponential distribution:
[tex]f(x) = \lambda e^{-\lambda x}, x \ge 0[/tex] --- the pdf
[tex]F(x) = 1 - e^{-\lambda x}, x \ge 0[/tex] --- the cdf
[tex]P(X > x) = 1 - F(x)[/tex]
In the above equations:
[tex]\lambda = \frac{1}{E(x)}[/tex]
Substitute 11 for E(x)
[tex]\lambda = \frac{1}{11}[/tex]
Now, we solve (a) to (d) as follows:
Solving (a): P(X>11)
[tex]P(X > 11) = 1 - F(11)[/tex]
Substitute 11 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]
[tex]P(X > 11) = 1 - (1 - e^{-\frac{1}{11}* 11})[/tex]
[tex]P(X > 11) = 1 - (1 - e^{-\frac{11}{11}})[/tex]
[tex]P(X > 11) = 1 - (1 - e^{-1})[/tex]
Remove bracket
[tex]P(X > 11) = 1 - 1 + e^{-1}[/tex]
[tex]P(X > 11) = e^{-1}[/tex]
[tex]P(X > 11) = 0.368[/tex]
Solving (b): P(X>22)
[tex]P(X > 22) = 1 - F(22)[/tex]
Substitute 22 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]
[tex]P(X > 22) = 1 - (1 - e^{-\frac{1}{11}* 22})[/tex]
[tex]P(X > 22) = 1 - (1 - e^{-\frac{22}{11}})[/tex]
[tex]P(X > 22) = 1 - (1 - e^{-2})[/tex]
Remove bracket
[tex]P(X > 22) = 1 - 1 + e^{-2}[/tex]
[tex]P(X > 22) = e^{-2}[/tex]
[tex]P(X > 22) = 0.135[/tex]
Solving (c): P(X>33)
[tex]P(X > 33) = 1 - F(33)[/tex]
Substitute 33 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]
[tex]P(X > 33) = 1 - (1 - e^{-\frac{1}{11}* 33})[/tex]
[tex]P(X > 33) = 1 - (1 - e^{-\frac{33}{11}})[/tex]
[tex]P(X > 33) = 1 - (1 - e^{-3})[/tex]
Remove bracket
[tex]P(X > 33) = 1 - 1 + e^{-3}[/tex]
[tex]P(X > 33) = e^{-3}[/tex]
[tex]P(X > 33) = 0.050[/tex]
Solving (d): x when [tex]P(X <x)=0.95[/tex]
Here, we make use of:
[tex]P(X<x) = F(x)[/tex]
Substitute [tex]F(x) = 1 - e^{-\lambda x}[/tex]
[tex]P(X<x) = 1 - e^{-\lambda x}[/tex]
So, we have:
[tex]0.95 = 1 - e^{-\lambda x}[/tex]
Subtract 1 from both sides
[tex]0.95 -1= 1-1 - e^{-\lambda x}[/tex]
[tex]-0.05=- e^{-\lambda x}[/tex]
Reorder the equation
[tex]e^{-\lambda x} = 0.05[/tex]
Substitute 1/11 for [tex]\lambda[/tex]
[tex]e^{-\frac{1}{11} x} = 0.05[/tex]
Solve for x:
[tex]x = -\frac{1}{1/11}\ ln(0.05)[/tex]
[tex]x = -11\ ln(0.05)[/tex]
[tex]x = 32.9530550091[/tex]
[tex]x = 33[/tex] --- approximated
At a deli, Joe bought 2.2 pounds of coleslaw for $7.15. What was the unit price?
Answer:
$3.25 for 1 pound of coleslaw
Step-by-step explanation:
i think,.
Which statement is true if a is the fourth root of 16, Show your work
a x a x a x a = 16
a = 164
4a = 16
a = 16/4
Given:
The statement is " a is the fourth root of 16".
To find:
The true statement for the given statement.
Solution:
The given statement is
a is the fourth root of 16.
Mathematically, it can be written as
[tex]a=\sqrt[4]{16}[/tex]
Taking power 4 on both sides.
[tex]a^4=(\sqrt[4]{16})^4[/tex]
[tex]a\times a\times a\times a=16[/tex]
Therefore, the correct option is A.
A true statement , if a is the fourth root of 16 is
a x a x a x a = 16
Important Information :
'a' is the fourth root of 16'a' is the fourth root of 16 can be written as
[tex]a=\sqrt[4]{16}[/tex]
To remove fourth root, we take exponent 4 on both sides
[tex]a=\sqrt[4]{16}\\(a)^4=(\sqrt[4]{16})^4[/tex]
Exponent 4 and fourth root will get cancelled
[tex]a^4=16\\a \cdot a\cdot a \cdot a=16[/tex]
a x a x a x a = 16
A true statement , if a is the fourth root of 16 is
a x a x a x a = 16
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What is the discriminate of y=x^2-8x+2
Answer:
56
Step-by-step explanation: Use the values of a, b, and c to find the discriminant.
Answer:
[tex]\Delta =56[/tex]
Step-by-step explanation:
We are given:
[tex]y = x^2 - 8x + 2[/tex][tex]y=x^2-8x+2[/tex]
So, a = 1, b = -8, and c = 2.
The discriminant (symbolized by Δ) is given by:
[tex]\Delta =b^2-4ac[/tex]
So, our discriminant in this case will be:
[tex]\Delta=(-8)^2-4(1)(2)=64-8=56[/tex]
Since our discriminant is a positive value, our equation has two real roots.
2. Two boxes are being shipped at a facility. One
box weighs 25.09 pounds, and the other box
weighs 25.018. Which box weighs more? Explain
and prove your answer.
Answer:
i think 25.09 weighs more
Step-by-step explanation: well simply 25.018 has more decimal places down therefore making it a smaller number
sorry if you get it wrong :c
ILL GIVE BRAINLEST !!!!
Enter an equation for the function that includes the points. Give your answer in the form a(b*). In the
event that a = 1, give your answer in the form b*.
(1, 12) and (2, 144)
The equation is f(x)=
Help quick plzzzzz Plzzzzzzzzzzzzz
12873t456473892220-209873
Let f(x) = 4x - 1, h(x) = - X-3.
Find (f o h)(-5).
Answer:
(f o h)(-5)=-33
Step-by-step explanation:
Let f(x) = 4x - 1, h(x) = - X-3.
(f o h)=4(-x-3)-1
(f o h)=-4x-12-1
(f o h)=-4x-13
(f o h)(-5)=-4(-(-5))-13
(f o h)(-5)=-20-13
(f o h)(-5)=-33
Write a plan to prove that angle 1 is congruent to angle 2
Answer:
alternate interior angles
Step-by-step explanation:
<1 is congruent to <2 by alternate interior angles
Please help me!!!!
Ernest bought some cans of paint and 4/5 of a liter of special paint additive formulated to reduce mildew. Before painting his house, he used all of the additive to put 2/5 of a liter of additive in each can. How many cans of paint did Ernest buy?
Answer:
He bought 2 cans of paint
Step-by-step explanation:
If he put ⅖ in each, and ⅘ total, he would have had 2 cans
Quantity of special paint additive Ernest bought = [tex] \tt \frac{4}{5} \: of \: a \: litre [/tex]
Quantity of additive he put in each can = [tex] \tt \frac{2}{5} \: of \: a \: litre [/tex]
Number of cans of paint he bought :
[tex] =\tt \frac{4}{5} \div \frac{2}{5} [/tex]
[tex] = \tt\frac{4}{5} \times \frac{5}{2} [/tex]
[tex] = \tt\frac{4 \times 5}{5 \times 2} [/tex]
[tex] =\tt \frac{20}{10} [/tex]
[tex]\color{plum} = \tt2 \: paint \: cans[/tex]
▪︎Therefore, Ernest bought 2 paint cans.
An Airbus A320 jet flies 5 hours west with a 40-mph tailwind. Returning against the wind takes 7 hours. Find the speed of the jet with no wind.
Answer:
The speed of the jet with no wind is 240 miles per hour.
Step-by-step explanation:
The speed of the jet with no wind is equivalent to the speed of the jet relative to wind. Physically speaking, we have the following system of linear equations under the assumption that both speeds of wind and jet are constant:
In favor of wind
[tex]\frac{s}{t_{F}} = v_{W}+v_{J/W}[/tex] (1)
Against wind
[tex]-\frac{s}{t_{A}} = v_{W} -v_{J/W}[/tex] (2)
Where:
[tex]s[/tex] - Travelled distance, measured in miles.
[tex]t_{F}[/tex], [tex]t_{A}[/tex] - Time, measured in hours.
[tex]v_{W}[/tex] - Wind speed, measured in miles per hour.
[tex]v_{J/W}[/tex] - Jet speed relative to wind, measured in miles per hour.
If we know that [tex]t_{F} = 5\,h[/tex], [tex]t_{A} = 7\,h[/tex], [tex]v_{W} = 40\,\frac{mi}{h}[/tex], then the speed of the jet with no wind is:
[tex]\frac{s}{5} = 40 + v_{J/W}[/tex] (3)
[tex]-\frac{s}{7} = 40-v_{J/W}[/tex] (4)
[tex]\frac{s}{5}-40 = 40 +\frac{s}{7}[/tex]
[tex]\frac{s}{5}-\frac{s}{7} = 80[/tex]
[tex]\frac{7\cdot s - 5\cdot s}{35} = 80[/tex]
[tex]2\cdot s = 2800[/tex]
[tex]s = 1400\,mi[/tex]
From (3), we find that speed of the jet with no wind is:
[tex]v_{J/W} = \frac{s}{5}-40[/tex]
[tex]v_{J/W} = \frac{1400}{5}-40[/tex]
[tex]v_{J/W} = 240\,\frac{mi}{h}[/tex]
The speed of the jet with no wind is 240 miles per hour.
sophie uses 18 beads to make a neckalace , 3/6 of the beads are purple
Answer:
9 beads are purple
Step-by-step explanation:
we know that
To find out how many beads are purple, multiply the total beads by the fraction of the beads that are purple
so
therefore
9 beads are purple
Another way to solve the problem is convert the fraction in percentage
we have
so
If the total are 18 beads
50% is 9 beads
therefore
9 beads are purple
Identify the percent of change as an increase or decrease. Then find the percent of
change. Round to the nearest tenth of a percent, if necessary.
$18.75 to $18.60
Answers:
Increase; 15%
Decrease; 0.15%
Decrease: 0.008%
Decrease; 0.8%
Answer:
Decreasing; 0.8%
solve and recieve brain list I took a better picture
a classroom is 30 feet wide the ceiling is 10 feet above the floor what is the volume
Answer:
300 sqft
Step-by-step explanation:
30 times ten is 300 and the measure is feet squared
Answer:
9000 ft 3
Step-by-step explanation:
SOMEONE PLZZ HELP, I HAVE A TEST AND DONT KNOW HOW TO DO THIS!!
Find the radius of the circle. The center of the circle is (2, -3) and a point that lies on the circle is (-1, -2).
Answer:
[tex]\displaystyle r = \sqrt{10}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Coordinates (x, y)Geometry
Definition of a radius - the center of a circle to any point to the circumferenceAlgebra II
Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Step-by-step explanation:
Step 1: Define
Center (2, -3) → x₁ = 2, y₁ = -3
Circumference point (-1, -2) → x₂ = -1, y₂ = -2
In this case, the distance d from the center to the circumference point would be the radius r of the circle.
Step 2: Find Radius r
[Distance Formula] Define equation [Radius]: [tex]\displaystyle r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Substitute in points [Radius]: [tex]\displaystyle r = \sqrt{(-1-2)^2+(-2--3)^2}[/tex][Radius] [√Radical] (Parenthesis) Simplify: [tex]\displaystyle r = \sqrt{(-1-2)^2+(-2+3)^2}[/tex][Radius] [√Radical] (Parenthesis) Subtract/Add: [tex]\displaystyle r = \sqrt{(-3)^2+(1)^2}[/tex][Radius] [√Radical] Evaluate exponents: [tex]\displaystyle r = \sqrt{9+1}[/tex][Radius] [√Radical] Add: [tex]\displaystyle r = \sqrt{10}[/tex]What is the factors for x squared plus 5x - 6
Answer:
=[tex](x-1)(x+6)[/tex]
Step-by-step explanation:
Answer:
[tex]x^{2} +5x-6=(x-1)(x+6)[/tex]
Step-by-step explanation:
What value of m gives the system infinitely many solutions?
-X + 4y = 32
y = mx + 8
4y=32+x
y=32+x/4
32+x/4=mx+8
32+x=4mx+32
32-32+x=4mx
x=4mx
x/:=4m
1=4m
m=1/4
Which graph represents the parametric equations x = 1 – t2 and y = 2t, where 0 ≤ t ≤ 5?
ANSWER: A
After plotting the above equation on the coordinate plane, we can see the graph of the function.
What are parametric equations?A parametric equation in mathematics specifies a set of numbers as functions of one or more independent variables known as parameters.
We have two parametric equations:
x = 1 – t² and
y = 2t
t = y/2 and
0 ≤ t² ≤ 5
1 ≤ 1 - t²≤ 4
1 ≤ x≤ 4
Plug the above value in x = 1 – t²
x = 1- (y/2)²
x = 1 - y²/4
4x = 4 - y²
y² = 4(1 - x)
Thus, after plotting the above equation on the coordinate plane, we can see the graph of the function.
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If y= cx" and dy/dx =
4/root x
what are the values of c and n?
Answer:
c = 8
n = 1/2
Step-by-step explanation:
Since dy/dx is the derivative form, we can integrate the answer to get the value of y.
The values of c and n are obtained by forming the equations as 1/2 and 8 respectively.
What is differentiation?The differentiation of a function is defined as rate of change of its value at a point. It can be written as f'(x) = (f(x + h) - f(x)) /(x + h - x).
It can be stated in terms of geometry as the slope of tangent of the function at a given point.
It is given as y = cxⁿ and dy/dx = 4/√x.
Take the derivative of y = cxⁿ with respect to x as,
dy/dx = cd(xⁿ)/dx
⇒ nc × xⁿ⁻¹
Compare the obtained derivative with 4/√x to obtain,
nc = 4 and n - 1 = -1/2
⇒ n = 1/2 and c = 8
Hence, the values of c and n are 1/2 and 8 respectively.
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