Answer:
Every noticeable event, transaction, interaction, request and reply, and so on are being expectantly captured and saved in storage appliances and arrays for real-time as well as posterior investigations create something we call it Big Data.
Another way to look at is that it comprises massive amounts of data that keeps on growing exponentially over time so much so that it cannot be processed or analyzed using usual data processing techniques.
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If you are asked to design an optimal workflow using technology for a car accident claim process, what factors would you consider to build into the solution? Explore existing workflow technology and discuss which software solutions meet the workflow requirements?
Answer:
The factors to consider when building a solution for optical workflow for car accident are the type of claim to be modelled, also to examine the level of automation in vehicles.
Some of the software solutions that meet the requirements are the A1 Tracker which is very effective to the enterprise business and small business working with insurance. we also have the Mutual expert, Ninja Quote.
Explanation:
Solution
In suggesting an optical workflow for the car accident claim process it is of importance to understand the following factors such as, the type of claim to be modelled, it will be determined by the policy that the clients have for their cars. this will assist in classifying the workflow and giving a clear path of the design.
The number of expected claims is also a very important factor that should be added in the design. Another important factor to examine the level of automation of the vehicles, this can be very useful in collecting the accident data in a more efficient way and also making it simple to design the model.
Presently there are several workflow softwares in the insurance that have encouraged a great deal and have made the workflow in the insurance companies more greater.
Some of the soft wares are the A1 Tracker which are very effective and efficient in are highly applicable to the enterprise business and small business working with insurance, the software is convenient in monitoring the work progress in the company.
The other soft wares that have been quite useful in the industry for example the Insly, ISI enterprise, Mutual expert, Ninja Quoter among others. These software are some of the best soft wares available in the market that have met the workflow requirement in the insurance sector.
#Write a function called 'string_type' which accepts one #string argument and determines what type of string it is. # # - If the string is empty, return "empty". # - If the string is a single character, return "character". # - If the string represents a single word, return "word". # The string is a single word if it has no spaces. # - If the string is a whole sentence, return "sentence". # The string is a sentence if it contains spaces, but # at most one period. # - If the string is a paragraph, return "paragraph". The # string is a paragraph if it contains both spaces and # multiple periods (we won't worry about other # punctuation marks). # - If the string is multiple paragraphs, return "page". # The string is a paragraph if it contains any newline # characters ("\n"). # #Hint: think carefully about what order you should check #these conditions in. # #Hint 2: remember, there exists a count() method that #counts the number of times a string appears in another #string. For example, "blah blah blah".count("blah") #would return 3.
Answer:
I am writing a Python program:
def string_type(string):
if string=="": //if the string is empty
return "empty"
elif string.count(".")>1: #if the period sign occurs more than once in string
if string.count("\n"): #checks if the new line occurs in the string
return "page" #if both the above cases are true then its a page
return "paragraph" # if the period sign condition is true then its a para
elif string.count(" ")>=1: #if no of spaces in string occur more than once
return "sentence" #returns sentence
elif len(string)==1: # if length of the string is 1 this
return "character" #returns character
else: #if none of the above conditions is true then its a word
return "word" #returns word
Explanation:
def string_type(string): this is the definition of method string_type which takes a string as argument and determines whether the type of string is a word, paragraph, page, sentence or empty.
if string=="" this if condition checks if the string is empty. If this condition is true then the method returns "empty"
elif string.count(".")>1 This condition checks if the string type is a paragragh
string.count(".")>1 and if string.count("\n") both statements check if the string type is a page.
Here the count() method is used which is used to return the number of times a specified string or character appears in the given string.
Suppose the string is "Paragraphs need to have multiple sentences. It's true.\n However, two is enough. Yes, two sentences can make a paragraph."
The if condition first checks if count(".")>1 which means it counts the occurrence of period i.e. "." in the string. If the period occurs more than once this means it could be a page. But it could also be a paragraph so in order to determine the correct string type another if statement if string.count("\n") inside elif statement determines if the string is a page or not. This statement checks the number of times a new line appears in the string. So this distinguishes the string type paragraph from string type page.
elif string.count(" ")>=1: statement determines if the string is a sentence. For example if the string is "i love to eat apples." count() method counts the number of times " " space appears in the string. If the space appears more than once this means this cannot be a single word or a character and it has more than one words. So this means its a sentence.
elif len(string)==1: this else if condition checks the length of the string. If the length of the string is 1 this means the string only has a single character. Suppose string is "!" Then the len (string) = 1 as it only contains exclamation mark character. So the method returns "character" . If none of the above if and elif conditions evaluates to true then this means the string type is a word.
Answer:
def string_type(string):
if string=="": //if the string is empty
return "empty"
elif string.count(".")>1: #if the period sign occurs more than once in string
if string.count("\n"): #checks if the new line occurs in the string
return "page" #if both the above cases are true then its a page
return "paragraph" # if the period sign condition is true then its a para
elif string.count(" ")>=1: #if no of spaces in string occur more than once
return "sentence" #returns sentence
Explanation:
"The correct syntax for passing an array as an argument to a method when a method is called and an array is passed to it is: "
Question:
"The correct syntax for passing an array as an argument to a method when a method is called and an array is passed to it is: "
A) a[0]..a[a.length]
B) a()
C) a
D) a[]
Answer:
The correct answer is A.
An example is given in the attachment.
Cheers!
A network technician is designing a network for a small company. The network technician needs to implement an email server and web server that will be accessed by both internal employees and external customers. Which of the following would BEST secure the internal network and allow access to the needed servers?
A. Implementing a site-to-site VPN for server access.
B. Implementing a DMZ segment for the server
C. Implementing NAT addressing for the servers
D. Implementing a sandbox to contain the servers
Answer:
(B) Implementing a DMZ segment for the servers
Explanation:
DMZ is the short form for Demilitarized Zone. It is the temporary storage between an internal or private LAN and the public Internet. The main purpose of the DMZ is to give additional layer of security to a company's LAN (Local Area Network).
Once there are services to be provided to users on the public Internet, such services should be added to the DMZ. A few services that are worth implementing a DMZ segment for are;
i. Email servers
ii. Web servers
iii. Proxy servers
iv. FTP servers
An organization's IRP prioritizes containment over eradication. An incident has been discovered where an attacker outside of the organization has installed crypto-currency mining software on the organization's web servers. Given the organization's stated priorities, which of the following would be the NEXT step?
a. Remove the affected servers from the network.
b. Review firewall and IDS logs to identify possible source IPs.
c. Identify and apply any missing operating system and software patches
d. Delete the malicious software and determine if the servers must be reimaged
Answer:
a. Remove the affected servers from the network.
Explanation:
An organization's incident response process (IRP) can be defined as all of the process involved in the cleanup and recovery of data when they fall victim to an attack or cybersecurity breach. The incident response process comprises of six (6) important stages and these are;
1. Preparation.
2. Detection and analysis (identification).
3. Containment.
4. Eradication.
5. Recovery.
6. Review of incident activities.
When an organization's IRP prioritizes containment over eradication and an incident is discovered, where an attacker outside the organization installed a crypto-currency mining software on the organization's web servers. Given the organization's stated priorities, the cybersecurity engineer should remove the affected servers from the network.
A containment process is focused on taking steps to eliminate or contain the attack. It basically involves acting swiftly in response to the attack, so as to prevent it from spreading across board or in order to mitigate the damage already caused.
In this context, the cybersecurity engineer should remove the affected servers from the network in accordance with the organization's IRP priority (containment).
Furthermore, he could take a step further to contain the attack by installing a firewall and updating their policies in the Intrusion Prevention System (IPS) of the organization.
The UNIX operating system started the concept of socket which also came with a set of programming application programming interface (API) for 'socket level' programming. A socket was also uniquely identified:
a. as the combination of IP address and port number to allow an application within a computer to set up a connection with another application in another computer without ambiguity.
b. the port number to clearly identify which application is using TCP.
c. IP address to make sure the Internet device using the socket is delineated.
d. the access network, such as Ethernet or Wi-Fi so that multiple LAN devices could be installed on a single computer.
Answer:
(a). as the combination of IP address and port number to allow an application within a computer to set up a connection with another application in another computer without ambiguity.
Explanation:
The explanation is in the answer.
Identify and write the errors given in the flowchart (with steps and flowchart) : Start ↓ Input A,B ↓ Average = (A + B + C) / 3 ↓ Print Average ↓ Stop
Answer:
i will send you the answers in the next 10minute
Write a function SwapArrayEnds() that swaps the first and last elements of the function's array parameter. Ex: sortArray = {10, 20, 30, 40} becomes {40, 20, 30, 10)
#include
/* Your solution goes here
*/ int main(void) {
const int SORT_ARR_SIZE = 4;
int sortArray[SORT_ARR_SIZE];
int i;
int userNum;
for (i = 0; i < SORT_ARR_SIZE; ++i) {
scanf("%d", &sortArray[i]);
}
SwapArrayEnds(sortArray, SORT_ARR_SIZE);
for (i = 0; i < SORT_ARR_SIZE; ++i) {
printf("%d ", sortArray[i]);
}
Answer:
Here is the SwapArrayEnds()
//function with two parameters; the array and array size
void SwapArrayEnds(int sortArray[],int SORT_ARR_SIZE){
int temp; //temporary variable to hold the first element of sortArray
if(SORT_ARR_SIZE > 1){ //if sortArray size is greater than 1
temp = sortArray[0]; // set value of temp to the first element of sortArrray
sortArray[0] = sortArray[SORT_ARR_SIZE-1]; // set the value of first element of sortArray to the last element of sortArray
sortArray[SORT_ARR_SIZE-1] = temp; } } // set last element value to temp
Explanation:
Lets understand the working of the above function with the help of an example. Suppose the sortArray has the following elements: {10,20,30,40}. So the size of this array is 4.
if(SORT_ARR_SIZE > 1) has an if statement which checks if the array size is greater than 1. This condition evaluates to true as 4 > 1. So the body of if condition executes.
Next the statement temp = sortArray[0]; sets the value of temp variable to the value of first element of sortArray. As sortArray[0] means the element at 0-th index position of the sortArray. So using the above example the first element of the array is 10. So temp = 10.
Next the statement sortArray[0] = sortArray[SORT_ARR_SIZE-1]; sets the last element of the sortArray to the position of first element of the sortArray.
SORT_ARR_SIZE-1 is the position of last element of the array. As the size of sortArray is 4, so 4-1 = 3 which points to the last element. Now this element is moved to the first position of the array. This means that the value of first element of array becomes 40 as the element at 3-th index of the sortArray is 40.
Next the statement sortArray[SORT_ARR_SIZE-1] = temp moves the value in temp variable to the last position of the sortArray. As we know that the value of temp= 10. So this element 10 of the sortArray is positioned at SORT_ARR_SIZE-1 position of sortArray which is 4-1 = 3-th index of sortArray. This simply means that 10 is moved to the last position of sortArray.
So now the final sortArray becomes: 40,20,30,10 as the first and last element of the array are swapped using above function SwapArrayEnds().
The program along with the output is attached in screenshot.
Functions are collection of codes or instructions merged together to act as one.
The function, where comments are used to explain each line is as follows:
//This defines the function
void SwapArrayEnds(int sortArray[],int SORT_ARR_SIZE){
//This increments the array element at index 0
sortArray[0] += sortArray[SORT_ARR_SIZE-1];
//This replaces the last element with the first
sortArray[SORT_ARR_SIZE-1]= sortArray[0]- sortArray[SORT_ARR_SIZE-1];
//This replaces the first element with the last
sortArray[0]= sortArray[0]- sortArray[SORT_ARR_SIZE-1];
}
At the end of the function, the first and the last elements of the array are swapped.
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A network technician is designing a network for a small company. The network technician needs to implement an email server and web server that will be accessed by both internal employees and external customers. Which of the following would best secure the internal network and allow access to the needed servers?
A. Implementing a site-to-site VPN for server access.B. Implementing a DMZ segment for the server.C. Implementing NAT addressing for the servers.D. Implementing a sandbox to contain the servers.
Answer:
Option A (Implementing a site-to-site VPN for server access) seems to be the correct choice.
Explanation:
A site-to-site configuration is something that a single Open VPN network links several more separate networks linked. Technologies through one network will access machines in all the other computer systems in that connection model, including conversely. Implementing this would be extremely straightforward, for as much further even though Access Server was indeed implicated.The much more challenging aspect happens when interacting regarding firewalls including privacy filtering methods, as well as modifying the forwarding table in internet gateways, as several of them from different manufacturers but instead prototypes which they may not be able to log many of these.This rather gateway device uses an Open VPN with a Linux VPN client, to create a connection between various channels. If someone's server hardware is also measured accurately then perhaps a site-to-site configuration could be accomplished which works straightforwardly throughout all systems in both cable systems.Other choices are not related to the given instance. So that Option A would be the right one.
a. A hard disk has four surfaces (that's top and bottom of two platters). Each track has 2, 048 sectors and there are 131, 072 (2^17) tracks per surface. A block holds 512 bytes. The disk is not "zoned." What is the total capacity of this disk?
b. Given the disk in Part 1, how much data can be accessed without moving the disk heads. (That, is, what is the capacity of one cylinder?)
Answer:
Explanation:
Given that:
number of surfaces on a hard disk = 4
number of sectors = 2048 sectors
number of tracks per surface = 131, 072 (2^17)
a block holds 512 bytes.
Since, 'The disk is not "zoned.".....
then, Number of bytes / sector = 512
a) What is the total capacity of this disk?
The total capacity of the disk is:[tex]= 4 \ surfaces \times 131072 \dfrac{tracks}{surfaces} \times 2048 \dfrac{sector}{tracks} \times 512 \dfrac{bytes}{sector}[/tex]
[tex]= 5.49755814\times 10^{11} \ bytes[/tex]
= 549755814 KB ( kilobytes)
= 549755.814 MB (megabytes)
=549.755814 GB (gigabytes)
b. Given the disk in Part 1, how much data can be accessed without moving the disk heads. (i.e what is the capacity of one cylinder?)
The capacity of one cylinder can be estimated by determining the capacity of one surface and the capacity of one track.
The capacity of one surface = [tex]131072\dfrac{tracks}{surface} \times 2048 \dfrac{sector}{tracks} \times 512\dfrac{bytes}{sector}[/tex]
The capacity of one surface = [tex]1.37438953 \times 10^{11[/tex] byte = 137.44 GB
Capacity of one track = 2048 sectors/track × 512 bytes/sector
Capacity of one track = 1048576 Bytes/track
Capacity of one track =1048 KB/track
Capacity of one track ≅ 1 MB/track
Since the hard disk contains four surfaces
∴
capacity of one cylinder = 1 MB/track × 4 track/cylinder
capacity of one cylinder = 4 MB
What is the output of the following Python statements? def recurse(a): if (a == 0): print(a) else: recurse(a) recurse(0)
Answer:
d) 0 1 1 2
The above piece of code prints the Fibonacci series.
Explanation:
def a(n):
if n == 0:
return 0
elif n == 1:
return 1
else:
return a(n-1)+a(n-2)
for i in range(0,4):
print(a(i),end=" ")
In the Programming Process which of the following is not involved in defining what the program is to do:_____________ Group of answer choices
a. Compile code
b. Purpose
c. Output
d. Input
e. Process
Answer:
a. Compile code
Explanation:
In programming process, the following are important in defining what a program is to do;
i. Purpose: The first step in writing a program is describing the purpose of the program. This includes the aim, objective and the scope of the program. The purpose of a program should be defined in the program.
ii. Input: It is also important to specify inputs for your program. Inputs are basically data supplied to the program in order to perform a task. Valid inputs are defined in the program.
iii. Output: Many times, when inputs are supplied to a program the resulting effects are shown in the outputs. The way the output will be is defined in the program.
iv. Process: This involves the method by which inputs are being mapped into outputs. The process implements the functionality of the program by converting inputs into their corresponding outputs. The process is defined in the program.
Compile code is not a requirement in defining what a program is to do. It just allows the source code of the program to be converted into a language that the machine understands.
Modify short_names by deleting the first element and changing the last element to Joe. Sample output with input: 'Gertrude Sam Ann Joseph'
Answer:
I am writing a Python program:
For taking input from user:
user_input = input() # takes input from user
short_names = user_input.split() #splits user_input into list of strings
short_names.pop(0) # removes the first element of the list i.e. Gertrude
short_names[-1] = "Joe" #sets the last element to Joe
print(short_names) #prints modified list of Sam Ann Joe
If you do not want to take input from user:
short_names=['Gertrude', 'Sam', 'Ann', 'Joseph'] #list of 4 elements
short_names=short_names[1:] # removes the first element Gertrude
short_names.pop() # removes last element i.e. Joseph from list
short_names.append('Joe') #adds Joe to the end of the list
print(short_names) #prints modified list Sam Ann Joe
If you do not want to use pop() and append() methods:
short_names = ['Gertrude', 'Sam', 'Ann', 'Joseph'] #creates list of 4 values
short_names = short_names[1:] # removes first value i.e. Gertrude from list
short_names[-1] = "Joe" #set the last element to Joe
print(short_names) #prints modified list Sam Ann Joe
Explanation:
The first program takes the names from the user, splits them into list of strings, then pop(0) has given index value 0 which means 1st value in the list. So it removes and returns first value from the list. Next statement sets the last value of list to Joe.
The second program has a hard coded list ['Gertrude', 'Sam', 'Ann', 'Joseph']
short_names = short_names[1:] removes the first value of the short_names list i.e. Gertrude. Next pop() removes and returns last value in the list i.e. Joseph from list. Last statement append('Joe') adds Joe to the end of the list.
The third program has a list of 4 elements. short_names = short_names[1:] removes first value i.e. Gertrude from list and short_names[-1] = "Joe" sets the last element to Joe.
The function was implemented using the JavaScript language, the shift, pop and push function was used to get the desired output
Array and String OperationsThe function bellow is written in JavaScript
function shortName (short_names){
short_names.shift() // The first element "Gertrude" was removed
short_names.pop() //The last element "Joseph" was removes
short_names.push("joe") //"Joe" is added to the new list
return short_names //The new list is returned as output
}
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Shovels and Shingles is a small construction company consisting of 12 computers that have Internet access. The company's biggest concern is that a wily competitor will send e-mail messages pretending to be from Shovels and Shingles in order to get confidential information. Write down an encryption solution that best prevents a competitor from receiving confidential information and justify the recommendation.
Answer:
The Encryption solution that best prevents a competitor from receiving confidential information is the SSL(secure Socket Layer) Or TLS(Transport Layer Security).
Explanation:
Solution:
From my own perspective the encryption solution that i will use that prevents s a competitor from receiving confidential information and justify the recommendation is the SSL(secure Socket Layer) Or TLS(Transport Layer Security).
This is because in this case we have to share data confidentially (information need to be hidden from Unauthorized security access. also these provides the Transport Layer security that we needed in above example above.
The purpose of these protocol is to provide server and client authentication, Data confidentiality,and Data integrity (protected from unauthorized change). Application Layer client/server program such as HTTP that uses the service of TCP can encapsulate their data in SSL Packets.
SSL (Secure Socket Layer): is defined as the normal technology for protecting an internet connection secure and defend any sensitive data that is being sent between two systems, and not allowing criminals from reading and changing any information sent, including potential personal details.
TLS (Transport Layer security): It is a procedure that allows data integrity and privacy over Internet communications.
what kind of company would hire an information support and service employee?
-software development
-computer repair
-website development
-network administration
Answer:
it's a
Explanation:
Write a method named isPalindrome that accepts a string parameter and returns true if that string is a palindrome, or false if it is not a palindrome. For this problem, a palindrome is defined as a string that contains exactly the same sequence of characters forwards as backwards, case-insensitively. For example, "madam" or "racecar" are palindromes, so the call of isPalindrome("racecar") would return true. Spaces, punctuation, and any other characters should be treated the same as letters; so a multi-word string such as "dog god" could be a palindrome, as could a gibberish string such as "123 $$ 321". The empty string and all one-character strings are palindromes by our definition. Your code should ignore case, so a string like "Madam" or "RACEcar" would also count as palindromes.
Answer:
The programming language is not stated;
However, I'll answer this question using Java Programming Language;
The method is as follows;
public static void isPalindrome(String userinput)
{
String reverse = "";
int lent = userinput.length();
int j = lent - 1;
while(j >= 0)
{
reverse = reverse + userinput.charAt(j);
j--;
}
if(reverse.equalsIgnoreCase(userinput))
{
System.out.println("True");
}
else
{
System.out.println("False");
}
}
Explanation:
This line defines the method isPalindrome with a string parameter userinput
public static void isPalindrome(String userinput) {
This line initializes a string variable
String reverse = "";
This line gets the length of the userinput
int len = userinput.length();
The following while-loop gets the reverse of userinput and saved the reversed string in reverse
int j = lent - 1;
while(j >= 0)
{
reverse = reverse + userinput.charAt(j);
j--;
}
The following if statement checks if userinput and reverse are equal (cases are ignored)
if(reverse.equalsIgnoreCase(userinput))
{
System.out.println("True"); This line is executed if the if condition is true
}
else
{
System.out.println("False"); This line is executed if otherwise
}
} The method ends here
Write a program that asks the user to input a positive integer and then calculates and displays the factorial of the number. The program should call a function named getN
Answer:
The program is written in python and it doesn't make use of any comment;
(See explanation section for line by line explanation)
def getN(num):
fact = 1
for i in range(1, 1 + num):
fact = fact * i
print("Factorial: ",fact)
num = int(input("Number: "))
if num < 0:
print("Invalid")
else:
getN(num)
Explanation:
The function getNum is defined here
def getN(num):
Initialize the result of the factorial to 1
fact = 1
Get an iteration from 1 to the user input number
for i in range(1, 1 + num):
Multiply each number that makes the iteration
fact = fact * i
Print result
print("Factorial: ",fact)
Ths line prompts user to input number
num = int(input("Number: "))
This line checks if user input is less than 0; If yes, the program prints "Invalid"
if num < 0:
print("Invalid")
If otherwise, the program calls the getN function
else:
getN(num)
The following code uses a nested if statement.
if (employed == 'Y')
cout << "Employed!" << endl;
else if (employed == 'N')
cout << "Not Employed!" << endl;
else
cout << "Error!" << endl;
a. True
b. False
Answer:
true
Explanation:
else if used so I think it's true
The score of a student in two subjects are inserted in the B2 and C2 cells and the passing score for each subject is 60. Which of these functions will you insert in the D2 cell so that it returns TRUE if at least one score is greater than or equal to 60, or else it returns FALSE
Answer:
=OR(B2>=60, C2>=60)
Explanation:
If you want to check if at least one of the scores is equal to or greater than 60, you should use the OR function. The OR function tests multiple conditions and returns TRUE if at least one is met. Therefore, the function in cell D2 would be:
= OR(B2>=60, C2>=60)
In other to obtain the boolean value True if one of two or more conditions are met, the OR operator is used. Hence, the appropriate function is =OR(B2>=60, C2>=60)
The OR opertor gives a True value if one of the two conditions is met., if the student scores 60 or above in one of the two subjects, the output will be True. Similarly, if the student score above 60 in both, the output will be true.Hence, the appropriate function is =OR(B2>=60, C2>=60).
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Because Java byte code is the same on all computers, compiled Java programs Group of answer choices Cannot run on Linux systems Must be re-compiled for each different machine it is run on Are highly portable Are non-existent
Answer:
Are highly portable.
Explanation:
Java is a object oriented and class-based programming language. It was developed by Sun Microsystems on the 23rd of May, 1995.
Java was designed by a software engineer called James Gosling and it is originally owned by Oracle. Also, worthy of mention is the fact that Java was originally known as Oak.
Generally, Java as a software application usually are developed having a ".jar", ".class" or ".java" filename extensions.
Because Java byte code is the same on all computers, compiled Java programs are highly portable. This simply means that, the Java byte code was designed such that it has very few implementation dependency, thus, once the code is written, it can run on all computer platforms that supports the Java programming language.
Hence, the Java byte code is a write once, run anywhere software program.
The Java byte code instructions are read and executed by a computer program known as a Java Virtual Machine (JVM).
Additionally, Java program is used for developing varieties of applications such as, mobile, desktop, games, web and application servers etc.
Define stubs for the functions get_user_num) and compute_avg). Each stub should print "FIXME: Finish function_name" followed by a newline, and should return -1. Each stub must also contain the function's parameters Sample output with two calls to get_user_num) and one call to compute_avg): FIXME: Finish get_user_num() FIXME: Finish get_user_num() FIXME: Finish compute_avg() Avg: -1 1 ' Your solution goes here '' 2 4 user_num1 = 0 5 user_num2 = 0 6 avg_result = 0 7 8 user_num1 = get_user_num 9 user_num2 = get_user_num ) 10 avg_result = compute_avg(user_num1, user_num2) 11 12 print'Avg:', avg_result)|
Answer:
Here are the stub functions get_user_num() and compute_avg()
def get_user_num():
print('FIXME: Finish get_user_num()')
return -1
def compute_avg(user_num1, user_num2):
print('FIXME: Finish compute_avg()')
return -1
Explanation:
A stub is a small function or a piece of code which is sometimes used in program to test a function before its fully implemented. It can also be used for a longer program that is to be loaded later. It is also used for a long function or program that is remotely located. It is used to test or simulate the functionality of the program.
The first stub for the function get_user_num() displays FIXME: Finish get_user_num() and then it returns -1.
The seconds stub for the function compute_avg() displays the FIXME: Finish compute_avg() and then it returns -1.
Here with each print statement, there is function name after this FIXME: Finish line. The first function name is get_user_num and the second is compute_avg().
Next the function get_user_num() is called twice and function compute_avg() followed by a print statement: print('Avg:', avg_result) which prints the result. So the program as a whole is given below:
def get_user_num():
print('FIXME: Finish get_user_num()')
return -1
def compute_avg(user_num1, user_num2):
print('FIXME: Finish compute_avg()')
return -1
user_num1 = 0 # the variables are initialized to 0
user_num2 = 0
avg_result = 0
user_num1 = get_user_num() #calls get_user_num method
user_num2 = get_user_num()
avg_result = compute_avg(user_num1, user_num2)
print('Avg:', avg_result)
The method get_user_num() is called twice so the line FIXME: Finish get_user_num() is printed twice on the output screen. The method compute_avg() is called once in this statement avg_result = compute_avg(user_num1, user_num2) so the line FIXME: Finish compute_avg() is printed once on the output screen. Next the statement print('Avg:', avg_result) displays Avg: -1. You can see in the above program that avg_result = compute_avg(user_num1, user_num2) and compute_avg function returns -1 so Avg= -1. The program along with the produced outcome is attached.
More than one component in a particular automotive electric circuit is not working. Technician A starts testing the circuit at the power source. Technician B starts testing the circuit at its load. Who is right?
Hi there! Hopefully this helps!
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The answer is A, testing the circuit at the power source.
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 3, print "Too small". If greater than 10, print "Too large". Otherwise, compute and print 6 * bagOunces followed by " seconds". End with a newline. Example output for ounces = 7:42 seconds#include void PrintPopcornTime(int bagOunces) {}int main(void) {int userOunces;scanf("%d", &userOunces);PrintPopcornTime(userOunces);return 0;}2. Write a function PrintShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, print "Too few.". If more than 4, print "Too many.". Else, print "N: Lather and rinse." numCycles times, where N is the cycle number, followed by "Done.". End with a newline. Example output with input 2:1: Lather and rinse.2: Lather and rinse.Done. Hint: Declare and use a loop variable.#include /* Your solution goes here */int main(void) {int userCycles;scanf("%d", &userCycles);PrintShampooInstructions(userCycles);return 0;}
Answer:
Function 1:#include <stdio.h> //for using input output functions
// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter
void PrintPopcornTime(int bagOunces){
if (bagOunces < 3){ //if value of bagOunces is less than 3
printf("Too small"); //displays Too small message in output
printf("\n"); } //prints a new line
//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10
else if (bagOunces > 10){
printf("Too large"); //displays the message: Too large in output
printf("\n"); //prints a new line }
/*the following else part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */
else {
/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */
//int result;
//result = bagOunces * 6;
//printf("%d",result);
printf("%d",bagOunces * 6); /multiplies value of bagOunces to 6
printf(" seconds");
// seconds is followed with the value of bagOunces * 6
printf("\n"); }} //prints a new line
int main(){ //start of main() function body
int userOunces; //declares integer variable userOunces
scanf("%d", &userOunces); //reads input value of userOunces
PrintPopcornTime(userOunces);
//calls PrintPopcornTime function passing the value in userOunces
return 0; }
Explanation:
Function 2:#include <stdio.h> //header file to use input output functions
// start of the function PrintShampooInstructions body having integer variable numCycles as parameter
void PrintShampooInstructions(int numCycles){
if(numCycles < 1){
//if conditions checks value of numCycles is less than 1 or not
printf("Too few."); //prints Too few in output if the above condition is true
printf("\n"); } //prints a new line
//else if part is executed when the if condition is false and else if checks //value of numCycles is greater than 4 or not
else if(numCycles > 4){
//prints Too many in output if the above condition is true
printf("Too many.");
printf("\n"); } //prints a new line
//else part is executed when the if and else if conditions are false
else{
//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done
for(int N = 1; N <= numCycles; N++){
printf("%d",N);
printf(": Lather and rinse. \n");}
printf("Done.");
printf("\n");} }
int main() //start of the main() function body
{ int userCycles; //declares integer variable userCycles
scanf("%d", &userCycles); //reads the input value into userCycles
PrintShampooInstructions(userCycles);
//calls PrintShampooInstructions function passing the value in userCycles
return 0;}
I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by
printf(": Lather and rinse. \n"); which is followed by printf("Done.");
So at first iteration:
printf("%d",N); prints 1 as the value of N is 1
printf(": Lather and rinse. \n"); prints : Lather and rinse and prints a new line \n.
As a whole this line is printed on the screen:
1: Lather and rinse.
Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.
Now at second iteration:
The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles which means 2=2. So the program control enters the body of loop.
printf("Done."); prints Done after the above two lines.
printf("%d",N); prints 2 as the value of N is 2
printf(": Lather and rinse. \n"); prints : Lather and rinse and prints a new line \n.
As a whole this line is printed on the screen:
2: Lather and rinse.
Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.
The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles which means 3>2. So the loop breaks.
Now the next statement is:
printf("Done."); which prints Done on the screen.
So as a whole the following output is displayed on the screen:
1: Lather and rinse.
2: Lather and rinse.
Done.
The programs along with their outputs are attached.
What happens to weather patterns when a cold front approaches? What happens to
weather patterns when a warm front approaches?
Answer:
The overview including its problem is listed in the explanation segment following.
Explanation:
The cool, unobstructed front develops whenever the cool front overwhelms the warm side or front. The warm front increases over its colder, then gradually move towards the surface of the earth.The subsequent weather system seems to be close to something like a moving warmer front.
So that the above seems to be the right answer.
______is a technology that allows users to access databases that contain case law or statutory law governing a particular issue.
Explanation:
In my opinion this is computer assisted legal search
Letm1, m2,···mnbe distinct numbers on the number line, in the increasing order. Your goalis to color all of them blue. You have magical blue pens with the following property: Whenyou place the pen at co-ordinate x, all the points in the range [x - 5, x + 5] turn blue. Apen can be used only once. Give an algorithm to color all the points using as few pens aspossible. Prove the correctness of the algorithm and derive the runtime.
Answer:
Following are the algorithm to this question:
y = 0 // initialize variable y that assigns the value 0
p = 1 // initialize value 1 in the variable p which also known as starting position
init num = 1//define variable num that assign value 1
for j = 1 to n: //defining loop
y = m[j] - m[p]
if (y > 10) //defining if block
num++; //increment num variable
p=i; //holding loop value in p variable
y= 0//assign value 0 in y variable
Explanation:
Following are the runtime analysis of the above-given algorithm:
The above-provided algorithm is greedy, but if it doesn't exceed the scope, it operates by greedily choosing its next object. Therefore the algorithm selects the fewest number of pens.
Running time:
This algorithm merely iterates once over all the points. The run-time is therefore O(n).
A bank in your town updates its customers’ accounts at the end of each month. The bank offers two types of accounts: savings and checking. Every customer must maintain a minimum balance. If a customer’s balance falls below the minimum balance, there is a service charge of $10.00 for savings accounts and $25.00 for checking accounts. If the balance at the end of the month is at least the minimum balance, the account receives interest as follows:
a. Savings accounts receive 4% interest.
b. Checking accounts with balances of up to $5000 more than the minimum balance receive 3% interest; otherwise, the interest is 5%.
This Java program using Eclipse Indigo reads a customer’s account number ( int type ), account type ( char type; s or S for savings, c or C for checking), minimum balance that the account should maintain, and current balance. The program should then output the account number, account type, current balance, and new balance or an appropriate error message. Test program by running it five times, using the following data:
46728 S 1000 2700
87324 C 1500 7689
79873 S 1000 800
89832 C 2000 3000
98322 C 1000 750
[code]
import java.util.*;
public class bank
{
public static void main (String [] args)
{int num,error=1,itype=0;
char type =0;
double min,cur =0,balanc =0,rate=0;
Scanner in=new Scanner(System.in);
System.out.println("Enter account number: ");
num=in.nextInt();
while(error==1)
{
System.out.println("Enter account type(s-savings or c-checking):");
type=in.next().charAt(0);
if(type=='c'||type=='C')
{itype=1;
error=0;
rate=3/100.;
}
else if(type=='s'||type=='S')
{itype=0;
error=0;
rate=4/100.;
}
if(error==1)
System.out.println("Invalid type-re enter");
}
System.out.println("Enter minimum balance: ");
min=in.nextDouble();
System.out.println("Enter current balance: ");
cur=in.nextDouble();
balance = cur;
if(itype==1)
{ if(cur>min+5000)
rate=5/100.;
else if(cur
cur-=25;
}
else
if(cur
cur-=10;
cur=cur+rate*cur;
System.out.printf("After interest and fees your balance is = $%.2f\n",cur);
System.out.println("Your account number: " + num);
System.out.println("Your account type: " + type);
System.out.printf("Your starting balance: $%.2f\n ", balanc);
System.out.printf("Your new balance: $%.2f\n", cur);
}
}
[/code]
Answer:
This is your corrected code and the output of each test example. I have also added comments with the provided code to make the code understandable. I have also changed itype variable to from int to String in order to print the account type (Savings or Checking) in output.
import java.util.*;
public class bank{ //class name
public static void main (String [] args) //start of main function body
{int num,error=1; //declare variables
String itype=" "; //stores Checking or Savings account type
char type =0; //type variable which is one of savings S or checking C
double min,cur =0,balance =0,rate=0;
//declare variables for minimum balance, current balance, interest rate
Scanner in=new Scanner(System.in);
System.out.println("Enter account number: "); //prompts user to enter acc no
num=in.nextInt(); //reads input account number
while(error==1) {
//asks user to enter account type C or S
System.out.println("Enter account type(s-savings or c-checking):");
type=in.next().charAt(0); //reads the input character of account type
if(type=='c'||type=='C') //if user inputs c or C
{itype= "Checking"; //set itype to Checking when user input c or C
error=0; //set value of error to 0 means user entered valid type input
rate=3/100.; } // Savings accounts receives 3% interest
else if(type=='s'||type=='S') //if user enters S or s that shows Savings account
{itype= "Savings"; //set itype to Savings when user input s or S
error=0; //set error to 0 means there is no error
rate=4/100.; } //Savings accounts receives 4% interest
if(error==1) //in case of error in giving input
System.out.println("Invalid type-re enter"); } //asks user to input again
System.out.println("Enter minimum balance: "); //asks user to enter min bal
min=in.nextDouble(); //reads value of input minimum balance
System.out.println("Enter current balance: ");
// reads value of input current balance
cur=in.nextDouble();
balance = cur;
if(itype=="Checking") //if the account type is checking
{ if(cur>min+5000) //Checking accounts interest is 5%
{rate=5/100.;
cur=cur+rate*cur; //computes new balance
System.out.printf("New balance: $%.2f\n", cur);} //returns new balance value
/*If a customer’s balance falls below the minimum balance, there is a service charge of $25.00 for checking accounts */
else if(cur<min)
{cur-=25;
System.out.printf("New balance: $%.2f\n", cur);} returns the value of new
}
if(itype=="Savings"){ //if account type is Savings
/*If a customer’s balance falls below the minimum balance, there is a service charge of $10.00 for savings accounts */
if(cur<min)
{cur-=10;
System.out.printf("New balance: $%.2f\n", cur);}
else
//Savings accounts receive 4% interest
{cur=cur+rate*cur;
System.out.printf("New balance: $%.2f\n", cur);}}
/* as the program should output account number, account type, current balance, and new balance so i have commented out the extra print statements below */
//System.out.printf("After interest and fees your balance is = $%.2f\n",cur);
System.out.println("Account Number: " + num);
System.out.println("Account type: " + itype);
System.out.printf("Current balance: $%.2f\n ", balance); //the result is //displayed up to 2 decimal place .2f } }
Explanation:
Following is the output of each test example:
46728 S 1000 2700
Account Number: 46728
Account type: Savings
Current balance: $2700.00
New balance: $2808.00
87324 C 1500 7689
Account Number: 87324
Account type: Checking
Current balance: $7689.00
New balance: $8073.45
79873 S 1000 800
Account Number: 79873
Account type: Savings
Current balance: $800.00
New balance: $790
89832 C 2000 3000
Account Number: 89832
Account type: Checking
Current balance: $3000.00
New balance: $3090.00
98322 C 1000 750
Account Number: 98322
Account Type: Checking
Current balance: $1000.00
New Balance: $725.00
The best way to avoid driving impaired is to...
A. avoid drinking.
B. stay under the legal BAC limit.
C. keep a taxi fare on hand.
Answer:
the answer is A avoid drinking 10 Tips to Avoid Driving Drunk
Explanation:
Give someone your keys. Find someone trustworthy who isn't drinking and hand over your keys for the night. ...
Don't drink on an empty stomach. ...
Know your body and pace yourself. ...
Take public transit. ...
Spend the night. ...
Wait an hour or two. ...
Stop drinking 90 minutes before you plan to leave. ...
Take the night off from drinking. hope this helps you :)
Between Handshake protocol, change cipher suite, alert and appplication data protocols, the first one to use is:
a. Handshake protocol.
b. Appplication data protocol.
c. Alert protocol.
d. Change cipher suite protocol.
Answer:
c is the answer I'm pretty sure but wait for more
Select the option that is not true. 1. Timestamp and Validation schedulers are both optimistic schedulers. 2. Timestamp and Validation schedulers can be used to remove physically unrealizable behaviour. 3. Timestamp and Validation schedulers guarantee serializability. 4. Timestamp and Validation schedulers perform most effectively on transactions that perform writes.
Answer:
3. Timestamp and Validation schedulers guarantee serializability.
Explanation:
Timestamp is a sequence of information encoded when a certain event occurs at a given time that information is decoded and message is identified. Time schedulers is optimistic scheduler and it removes physically unrealizable behavior. Timestamp cannot guarantee serializability. It can detect unrealizable behavior.