Equal masses of water at 80°C and paraffin at 20°C are mixed in a container. The specific
heat capacity of water is twice that of paraffin. What is the final temperature of the
mixture?
O 60°C
O 50°C
O 40°C
O 30°C

Answer:

Summary

Motion in one dimension

Reading Quiz

Class Quiz

Kinematic equations

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Example #1

Example #2

Graphs of motion applet

constant speed

constant acceleration

vectors & graphs applet

graphical analysis applet

Example #3

Example #4

Self-quiz applet

Interactive Example 2-9

Answer:

Equal to 30°C.

Explanation:

The final temperature of both objects are equal to 30°C because of the conduction heat from one object to another. Both objects have same mass of 2 kg and both were isolated from the external environment so conduction of heat occurs from the more hotter body to the less hotter body until the temperature of both objects are equal to each other.

The final temperature of both objects is less than 30° C

The specific heat of an object is the minimum required quantity of heat needed to raise the temperature of 1 gram of the object(substance) by 1° C.

From the parameters given:

Using the Calorimetry principle, we need to understand that the heat lost by an object at a high temperature is proportionally equal to that heat gained by the object at a low temperature.

i.e.

[tex]\mathbf{Q_{lost}= Q_{gain}}[/tex]

[tex]\mathbf{ms_B \Big[40^0 \ C - \theta_o\Big]= ms_A \Big [ \theta_o - 20^0 \ C \Big]}[/tex]

Given that:

Then, let us consider a scenario where [tex]\mathbf{S_A = 1.5S_B}[/tex]

Thus;

[tex]\mathbf{S_B \Big[40^0 \ C - \theta_o\Big]= 1.5S_B \Big [ \theta_o - 20^0 \ C \Big]}[/tex]

[tex]\mathbf{40^0 \ C - \theta_o= 1.5 \theta_o - 20^0 \ C}[/tex]

[tex]\mathbf{ 2.5\theta_o= 70^0 \ C}[/tex]

[tex]\mathbf{ \theta_o= \dfrac{70^0 \ C}{2.5}}[/tex]

[tex]\mathbf{ \theta_o=28 ^0 C}[/tex]

Therefore, we can conclude that since the specific heat of object A is larger than that of object B i.e. [tex]\mathbf{S_A> S_B}[/tex], then the final temperature [tex]\mathbf{ \theta_o<30 ^0 C}[/tex]

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Answer:

Approximately [tex]3.01\; \rm m[/tex].

Explanation:

Decompose each vector into the sum of two vectors: a horizontal one (parallel to the arrow that points to the right) and a vertical one (parallel the arrow that points upwards.)

Vector [tex]\sf A[/tex] is horizontal and is at an angle of [tex]0^\circ[/tex] with the horizon.  

Vector [tex]\sf B[/tex] is at an angle of [tex]30^\circ[/tex] below the horizon.

Calculate the sum of vector [tex]\sf A[/tex] and vector [tex]\sf B[/tex].

The horizontal component of vector [tex]\sf A[/tex] and vector [tex]\sf B[/tex] are opposite to one another. Therefore, the length of the horizontal component of [tex]\sf (A + B)[/tex] would be the difference between the length of the horizontal components of vector [tex]\sf A\![/tex] and of vector [tex]\sf B\![/tex]:

[tex]\displaystyle (6.00\; \rm m) \times \frac{\sqrt{3}}{2} - 5.00\; \rm m \approx 0.196152\; \rm m[/tex].

The length of the vertical component of vector [tex]\sf A[/tex] is [tex]0\; \rm m[/tex]. Therefore, the length of the vertical component of [tex]\sf (A + B)[/tex] would be equal to the length of the vertical component of vector [tex]\sf B[/tex], [tex]\displaystyle 6.00\; \rm m \times \frac{1}{2} = 3.00\; \rm m[/tex].

Therefore, the length of the horizontal and vertical component of [tex]\sf (A + B)[/tex] are approximately [tex]0.196152\; \rm m[/tex] and [tex]3.00\; \rm m[/tex], respectively. The length of vector [tex]\sf (A + B)\![/tex] would be approximately:

[tex]\displaystyle \sqrt{(0.196152\; \rm m)^{2} + (3.00\; \rm m)^{2}} \approx 3.01\; \rm m[/tex].

Answer:

the total force vector, on test charge is points from origin to point C( 1, 1 )

Explanation:

Given the data in the question, as illustrated in the image below;

from the Image, OA = 1, OB = AC = 1

so using Pythagoras theorem

a² = b² + c²

a = √( b² + c² )

so

OC = √( OB² + AC² )

we substitute

OC = √( OA² + AC² )

OC = √( 1² + 1² )

OC = √( 1 + 1 )

OC = √2

Coordinate of C( 1, 1 )

Hence, the total force vector, on test charge is points from origin to point C( 1, 1 )

Answer:

C. Decreasing the pressure

Explanation:

Answer:

6.621 minutes per mile  

Explanation:

the .621 is repeating

The correct answer is (A) 8.3mm.

The total displacement will be the vector sum of the two displacements given in the question.

let the displacement to the south represent vector A = 5mm in magnitude directed toward south.

let the displacement to the south-west represent vector B = 4mm in magnitude directed toward south-west.

The angle between vector A and vector B is 45°, the angle between south and south-west.

SO the resultant

R = vectro A + vector B

[tex]R=\sqrt{A^{2}+B^{2}+2ABcos(45) } \\\\R=\sqrt{25+16+40*\frac{1}{\sqrt{2} } } \\\\R=8.3mm[/tex]

The ant's displacement is 8.3 mm in magnitude.

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Answer:

there are no pictures attached.

Whenever a body is in motion there is always a friction to oppose the motion.

"Friction is a force that resists the motion of one object against another."

Friction is a force that opposes relative motion between surfaces in contact. One of the simpler characteristics of friction is that it is parallel to the contact surface between surfaces and always in a direction that opposes motion or attempted motion of the systems relative to each other.

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Answer:

16.1 N

Explanation:

From the question,

F = ma.............................. Equation 1

Where F = horizontal force, m = mass of the object, a = acceleration .

Given: m = 7.0 kg, a = 2.3 m/s²

Substitute this values into equation 1

F = (7.0×2.3)

F = 16.1 N.

Hence the magnitude of the horizontal force is 16.1 N

Answer:

2

Explanation:

She's attracted with a great force back to earth's surface

Answer:

The velocity of the particles is "0.36×10⁸ m/s".

Explanation:

The given values are:

Magnetic field strength,

B = 5.0×10⁻⁴ N/Amp

In another experiment,

F = 1.8×10⁴

By considering the Lorentz force, the velocity will be:

⇒  [tex]qE=qvB[/tex]

then,

⇒  [tex]v=\frac{F}{B}[/tex]

On substituting the given values, we get

⇒     [tex]=\frac{1.8\times 10^4}{5.0\times 10^{-4}}[/tex]

⇒     [tex]=0.36\times 10^8 \ m/s[/tex]

Answer:

B. Fahrenheit measures temperature!

At highest point above h from initial position .

And then ball B come to point A with same velocity v and after that elastic collision between A and B .

B get rest and A move with velocity v by momentum conservation .

The momentum of ball 1 is mv and momentum of the ball 2 is -mv. Therefore, option (C) is correct.

The momentum of an object can be explained as the function of the object's mass and object's velocity. Momentum (p) can be used to determine kinetic energy and is the multiplication of velocity (v) and mass (m).

The momentum is the vector quantity because the velocity is the vector while mass is the scalar. So the product of the vector and scalar quantity is a vector.

The momentum can be determined from the mathematical formula:

p = m×v

The momentum can be described as a conserved quantity but it can be zero if the object is stationary because the velocity of an object is zero.

The mass of both balls is 'm' but they are moving in different directions, therefore, the velocity of one ball will be 'v' while the ball will be - v. Therefore the momentum of one ball is mv and the other ball is - mv.

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Answer:

Hydrosphere and atmosphere

Explanation:

Answer:

attract each other

Explanation:

..........

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Power and Energy.

As a pendulum swings from the bottom position to the top position, it gains a height which means it gains the Potential energy.

hence we can say that, kinetic energy is changed into potential energy.

So, the Option A.) is correct.

Answer:

I think it's A)

Explanation:

it could be wrong i don't know hope it's not good luck!

Answer:

I think it's a repulsive force

Explanation:

Given info: The Number of turns in the wire is 580 the diameter of  

tube is [tex]8.00 \mathrm{~cm}[/tex] and the length of the tube up to which wire is wrapped is [tex]36.0 \mathrm{~cm}[/tex].  

Formula to calculate the inductance of the coil is,  

[tex]L=\frac{\mu_{0} N^{2} A}{l}[/tex]  

Here,  

[tex]L[/tex] is inductance of the coil.  

[tex]\mu_{0}[/tex] is the permittivity.  

[tex]N[/tex] is the number of turns.  

[tex]l[/tex] is the length up to which wire is wrapped.  

[tex]A[/tex] is the cross sectional area of the coil.  

The expression for the area is,  

[tex]A=\frac{\pi d^{2}}{4}[/tex]

Substitute [tex]\frac{\pi d^{2}}{4}[tex] for [tex]A[/tex] in equation (1).  

[tex]L=\frac{\left(\mu_{0} N^{2}\right) \frac{d d^{2}}{4}}{l}[/tex]

Substitute 580 for [tex]N, 4 \pi \times 10^{-7}[tex] for [tex]\mu_{0}, 8.00 \mathrm{~cm}[tex] for [tex]d[tex] and [tex]36.0 \mathrm{~cm}[tex] for [tex]l .[/tex]  

[tex]\begin{array}{c}  

=\frac{4 \pi \times 10^{-7} \times 580 \times 580 \times \frac{x(8.00 \mathrm{~cm} \times 8.00 \mathrm{~cm})}{4}}{36 \mathrm{~cm}} \\  

=5.90 \mathrm{mH}  

\end{array} [/tex]

Conclusion:  

Therefore, the inductance of the given single conductor wire is  

[tex]5.90 \mathrm{mH} .[/tex]

Given info: The rate of increasing current [tex]4.00 \mathrm{~A} / \mathrm{s}[/tex] and the inductance of the coil [tex]5.90 \mathrm{mH}[/tex].

The generated emf is,

[tex]

\varepsilon=L \frac{d i}{d t}

[/tex]

Here,

[tex]\varepsilon[/tex] is the generated emf.

[tex]L[tex] is the inductance of the coil.

[tex]\frac{d i}{d t}[tex] is the rate of change of current.

Substitute [tex]5.90 \mathrm{mH}[tex] for [tex]L[tex] and [tex]4.00 \mathrm{~A} / \mathrm{s}[tex] for [tex]\frac{d i}{d t}[/tex]

[tex]\begin{array}{c}

\varepsilon=5.90 \mathrm{mH} \times 4.00 \mathrm{~A} / \mathrm{s} \\

= & 23.6 \mathrm{mV}

\end{array}[/tex]

Conclusion:

Therefore, the generated emf is [tex]23.6 \mathrm{mV}[/tex].

Answer:

First there is a need to convert 80.0 km/h to m/s. It is equivalent to (200 / 9) m/s. Because the body stops after 4.25 seconds, its acceleration is -(200/9/4.25) m/s^2. The needed force to stop the 2500 kg truck is equal to the product of its mass and its acceleration.

Solving for the net force to stop the 2500 kg truck

Force = mass * acceleration

Force = 2500 kg * -(200/9/4.25) m/s^2

Force = −13072 N or about −13.07 kN

The force exerted on the truck is −13072 N or about −13.07 kN

Answer:

19.5 is answer Dee oo w e je e8 d c hehe udhdhd r

The height of the basketball player which is 6 ft 10.5 inches will be 209.55 centimeters.

A unit conversion expresses the same property as a different unit of the measurement of a quantity. For instance, the time can be expressed in the units of minutes instead of hours, while the distance can be converted from miles to kilometers, or feet, or any other measure of length.

1 ft = 30.48 cm

6 ft = 182.88 cm

1 inch = 2.54 cm

10.5 inch = 26.67 cm

Therefore, the total height in unit of centimeters will be (182.88 + 26.67) will be 209.55 centimeters.

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Answer:

Force of [tex]37.44 * 10^{8}[/tex] Kgm/s^2 must be  applied to the piston to raise oil to a height of 6.0 m

Explanation:

As we know,

Pressure is the force per unit area

Or [tex]P = \frac{F}{A}[/tex]

Force [tex]= P * A[/tex]

Pressure is the product of density, gravitational constant and height

[tex]P = 780 * 10 * 6[/tex]

Force

[tex]= P * A\\= 780 * 10*6*8*10^4\\= 37.44 * 10^{8}[/tex]Kgm/s^2

The force that must be applied to the piston to raise oil will be 37.44 ×10⁸ N. Force is defined as the ratio of presure and area. Its unit is Newton.

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

The given data in the problem is;

A is the area of a piston = 8 X 10⁴m².

F is the force=?

h is the height = 6.0 m

Force is defined as the ratio of presure and area. Its unit is Newton.

[tex]\rm P = \frac{F}{A} \\\\ \rm F = P \times A \\\\ \rm F = 780 \times 10^6 \times 8 \times 10^4 \\\\ \rm F = 37.44 \times 10^8[/tex]

Hence the force that must be applied to the piston to raise oil will be 37.44 ×10⁸ N.

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Answer:

A. A soft, shiny, highly reactive metal

Explanation:

Lithium  is located in Group 1, Period 2. lithium is most likely to be soft, shiny, highly reactive nonmetal. Hence option A is correct.

Atom is smallest entity of a body. Body is made up of atoms. it is basic building block of a body. An atom consist of electrons, protons and neutrons as sub atomic particle. whole mass of the atom is concentrated at the center of the atom which we call it as nucleus, nucleus consist of proton and neutron. Electron revolve around the nucleus at determined(fixed) orbit. Total number of protons in the atom decides the atomic number and the elements in the periodic table.

The electrons which are completely filled orbitals are called as core shell electrons and which are not filled completely are called as valence electron. valence electrons are responsible for physical and chemical properties of the element. Elements which are on same column in periodic table have same number of valence electrons .

Hence option A is correct.

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Answer:

  λ = 6 10⁻⁷ m, color orange

Explanation:

This problem is about the interference phenomenon, constructive interference occurs when the path difference is equal to an integer number of wavelengths

          d sim θ = m λ

Let's use trigonometry, remembering that the angles for these experiments are very small.

          Sin θ = y / L

          tan θ = [tex]\frac{sin \theta}{cos \theta}[/tex] = sin θ

          sin θ = y / L

we substitute

         [tex]d \ \frac{y}{L} = m \lambda[/tex]

A) Donut length is requested

        λ = [tex]\frac{d \ y}{m \ L}[/tex]

let's calculate

        λ = 5 10⁻⁵ 0.06 /( 1  5)

        λ = 6 10⁻⁷ m

B) let's express the wavelength in nm

      λ = 6 10⁻⁷ m = 600 nm

this corresponds to the color orange

Answer:

It is the Nucleus

Answer:

Nuclease

Explanation:

Answer:

no it would not. that is an open circuit and it would need to be closed at the switch for current to flow.