Answer:
(-4,2) are solution coordinates
This is the point in which these two lines intersect
3x+y=15 create a word problem
Answer:
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Step-by-step explanation:
3 adults and 1 child go to a park. The admission fee for adults is x, and the fee for children is y. They spent a total of 15 dollars. Solve for x and y.
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hope it helps
sorry if it doesn't. I'm the person who solves the problems, not creates them
Consider the equation y=-x2 - 7x + 12. Determine whether the function has a
maximum or a minimum value. State the maximum or minimum value. What are
the domain and range of the function?
Answer:
Max (-7/2, 97/4)
Domain: all real numbers
Range: (negative infinity, 97/4)
Step-by-step explanation:
Im assuming this is a quadratic equation y = -x^2-7x+12
The max/min are the vertex (-b/2a)
The area of Sophie‘s herb garden is 1/8 The area of her vegetable garden. The area of her herb garden is 6 square feet. What is the area of her vegetable garden
Answer:
see below
Step-by-step explanation: 5 25 14 02
herb garden is 1/8 The area of her vegetable garden
herb garden is 6 square feet
vegetable garden = ???
herb garden / vegetable garden = 1/8 solve for vegetable garden
herb garden × 8 = vegetable garden
6 ft² × 8 = __________ ft²
Can someone help me
What is 90 inches converted into centimetres?
Answer:
228.9
Step-by-step explanation:
Answer:
228.6
Step-by-step explanation:
Multiply the inches by 2.54
90 x 2.54 = 228.6
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
In a small metropolitan area, annual losses due to storm, fire, andtheft are assumed to be independent, exponentially distributed random variableswith respective means 1.0, 1.5, 2.4. Determine the probability that the maximumof these losses exceeds 3.
Answer:
[tex]0.4138[/tex]
Step-by-step explanation:
Given
[tex]x \to storm[/tex]
[tex]\mu_x = 1.0[/tex]
[tex]y \to fire[/tex]
[tex]\mu_y = 1.5[/tex]
[tex]z \to theft[/tex]
[tex]\mu_z = 2.4[/tex]
Let the event that the above three factors is greater than 3 be represented as:
[tex]P(A > 3)[/tex]
Using complement rule, we have:
[tex]P(A > 3) = 1 - P(A \le 3)[/tex]
This gives:
[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]
-----------------------------------------------------------------------------------------------------------
The exponential distribution formula of each is:
[tex]P(x \le k) = 1 - e^{-\frac{k}{\mu}}[/tex]
So, we have:
[tex]k = 3; \mu_x = 1[/tex]
[tex]P(x \le 3) = 1 - e^{-\frac{3}{1}} = 1 - e^{-3} = 0.9502[/tex]
[tex]k=3; \mu_y = 1.5[/tex]
[tex]P(y \le 3) = 1 - e^{-\frac{3}{1.5}} = 1 - e^{-2} = 0.8647[/tex]
[tex]k = 3; \mu_z = 2.4[/tex]
[tex]P(z \le 3) = 1 - e^{-\frac{3}{2.4}} = 1 - e^{-1.25} = 0.7135[/tex]
-----------------------------------------------------------------------------------------------------------
[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]
[tex]P(A > 3) = 1 - (0.9502 * 0.8647 *0.7135)[/tex]
[tex]P(A > 3) = 1 - 0.5862[/tex]
[tex]P(A > 3) = 0.4138[/tex]
If y is inversely proportional to (tan x) and y = 2
when x = 30°, find the value of y when this value
of x is doubled.
Answer:
When something is inversely proportional it can be solved by using the equation:
y = k/x
where k is the constant.
So using this we can plug in x and y to find the value of k.
3 = k/4.
Next we isolate k and find that k = 12. Now we use this to find the value of y when x = 8. Plug in x and you get y = 12/8 or y = 3/2 or 1.5.
Another way to solve this is to look at how the value of x changes. When the value of x goes up, the value of y goes down.
In other words, when x is multiplied by some number, y is divided by that number. In this equation we can see that x is multiplied by 2 to go from 4 to 8.
Thus, y must be divided by 2.
Thus, y = 3/2 or 1.5.
Answer:
Step-by-step explanation:
y is inversely proportional to tan x means
[tex]y \ \alpha \ \frac{1}{tan x}\\\\y = k \times \frac{1}{tanx}[/tex]
Given y = 2 when x =30° . So we will find k.
[tex]y =k \times \frac{1}{tanx } \\\\2 = k \times \frac{1}{tan 30}\\\\k = 2 \times tan 30 = 2 \times \frac{1}{\sqrt{3}} = \frac{2}{\sqrt{3} }[/tex]
Now x is doubled, x = 60°, find y
[tex]y = k \times \frac{1}{tanx}\\[/tex]
[tex]= \frac{2}{\sqrt{3}} \times \frac{1}{tan 60}\\\\= \frac{2}{\sqrt{3}} \times \sqrt{3}\\\\=2[/tex]
PLEASE HELP!!!!!!!!!!
Answer:
second
Step-by-step explanation:
[tex]\frac{2x}{5} +\frac{1x}{5} +\frac{5}{8} -\frac{2}{8} = \frac{3x}{5} +\frac{3}{8}[/tex]
Answer:
3/5 x + 3/8
remove parentheses:
2/5x + 5/8 + 1/5x - 1/4
simplify terms:
3/5x + 5/8 - 1/4
make 1/4 have a common denominator to 15/8 by multiplying 2/2.
3/5x + 5-2/8 =
3/5x + 3/8
A teacher is comparing the quarter grades between two of her classes. She takes a random sample of 8 students from each class and lists the grades as shown. Find the mean for Class A.
Class A: 80, 83, 74, 91, 76, 87, 93, 72
Class B: 90, 75, 82, 86, 73, 85, 79, 94
henry earns 42 $ for babysitting for 7 hours . If henry charges at the same rate, how many hours will it take him to earn 66$?
Answer:
11 hours
Step-by-step explanation:
Help please just right the ratio for all
ellus
Find the surface area of the composite figure.
2 cm
7 cm
2 cm
12 cm
12 cm
7 cm
7 cm
SA = [?] cm2
Answer:
SA = 484 cm²
Step-by-step explanation:
Surface area of the composite figure = surface area of the larger rectangular prism + (surface area of the smaller rectangular prism - base area of the smaller rectangular prism)
✔️Surface are of the larger rectangular prism = 2(LW + LH + WH)
L = 7 cm
W = 7 cm
H = 12 cm
S.A = 2(7*7 + 7*12 + 7*12) = 434 cm²
✔️Surface are of the smaller rectangular prism = 2(LW + LH + WH)
L = 7 cm
W = 2 cm
H = 2 cm
S.A = 2(7*2 + 7*2 + 2*2) = 64 cm²
✔️Base area of the smaller rectangular prism = L*W
L = 7 cm
W = 2 cm
Area = 7*2 = 14 cm²
✅Surface area of the composite figure = 434 + (64 - 14)
= 434 + 50
= 484 cm²
Se desea construir un vaso de papel en forma de cono circular recto que tenga un volumen de 25πcm3
. Determine las dimensiones del vaso que requiere menos papel. Cuales deben ser si el volumen
es de 1 litro?
Answer:
Para un vaso de [tex]V = 25\pi\,cm^{3}[/tex], las dimensiones del vaso son [tex]r \approx 2.321\,cm[/tex] y [tex]h \approx 4.642\,cm[/tex].
Para un vaso de [tex]V = 1000\,cm^{3}[/tex], las dimensiones del vaso son [tex]r \approx 5.419\,cm[/tex] y [tex]h \approx 10.839\,cm[/tex].
Step-by-step explanation:
El vaso se puede modelar como un cilindro recto. El enunciado pregunta por las dimensiones del vaso tal que su área superficial ([tex]A_{s}[/tex]), en centímetros cuadrados, sea mínima para el volumen dado ([tex]V[/tex]), en centímetros cúbicos. Las ecuaciones de volumen y área superficial son, respectivamente:
[tex]V = \pi\cdot r^{2}\cdot h[/tex] (1)
[tex]A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r\cdot h[/tex] (2)
De (1):
[tex]h = \frac{V}{\pi\cdot r^{2}}[/tex]
En (2):
[tex]A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot \left(\frac{V}{\pi\cdot r} \right)[/tex]
[tex]A_{s} = 2\cdot \left(\pi\cdot r^{2}+V\cdot r^{-1} \right)[/tex]
Asumamos que [tex]V[/tex] es constante, la primera y segunda derivadas de la función son, respectivamente:
[tex]A'_{s} = 2\cdot (2\pi\cdot r -V\cdot r^{-2})[/tex]
[tex]A'_{s} = 4\pi\cdot r - 2\cdot V\cdot r^{-2}[/tex] (3)
[tex]A''_{s} = 4\pi + 4\cdot V \cdot r^{-3}[/tex] (4)
Si igualamos [tex]A'_{s}[/tex] a cero, entonces hallamos los siguientes puntos críticos:
[tex]4\pi\cdot r - 2\cdot V\cdot r^{-2} = 0[/tex]
[tex]4\pi\cdot r = 2\cdot V\cdot r^{-2}[/tex]
[tex]4\pi\cdot r^{3} = 2\cdot V[/tex]
[tex]r^{3} = \frac{V}{2\pi}[/tex]
[tex]r = \sqrt[3]{\frac{V}{2\pi} }[/tex] (5)
Ahora, si aplicamos este valor a (4), tenemos que:
[tex]A_{s}'' = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }[/tex]
[tex]A''_{s} = 4\pi + 8\pi[/tex]
[tex]A_{s}'' = 12\pi[/tex] (6)
De acuerdo con este resultado, el valor crítico está asociado al área superficial mínima. Ahora, la altura se calcula a partir de (5) y (1):
[tex]h = \frac{V}{\pi\cdot \left(\frac{V}{2\pi} \right)^{2/3} }[/tex]
[tex]h = \frac{2^{2/3}\cdot \pi^{2/3}\cdot V}{\pi\cdot V^{2/3}}[/tex]
[tex]h = \frac{2^{2/3}\cdot V^{1/3}}{\pi^{1/3}}[/tex]
Si [tex]V = 25\pi\,cm^{3}[/tex], entonces las dimensiones del vaso son:
[tex]r = \sqrt[3]{\frac{25\pi\,cm^{3}}{2\pi} }[/tex]
[tex]r \approx 2.321\,cm[/tex]
[tex]h = \frac{2^{2/3}\cdot (25\pi\,cm^{3})^{1/3}}{\pi^{1/3}}[/tex]
[tex]h \approx 4.642\,cm[/tex]
Un litro equivale a 1000 centímetros cúbicos, las dimensiones del vaso son:
[tex]r = \sqrt[3]{\frac{1000\,cm^{3}}{2\pi} }[/tex]
[tex]r \approx 5.419\,cm[/tex]
[tex]h = \frac{2^{2/3}\cdot (1000\,cm^{3})^{1/3}}{\pi^{1/3}}[/tex]
[tex]h \approx 10.839\,cm[/tex]
What are the main properties of a parallelogram?
use the parallelogram (ABEF) to help you
Answer:
It must be number 2.
1 and 3 number is wrong as parallelogram don't need have right angle
In order to determine if there is a significant difference between campuses and pass rate, the chi-square test for association and independence should be performed. What is the expected frequency of West Campus and failed
Answer:
57.5
Step-by-step explanation:
The expected frequency of West Campus and Failed :
Let :
Failed = F
East Campus = C
West Campus = W
Passed = P
Frequency of FnW :
[(FnE) + (FnW) * (PnW) + (FnW)] / total samples
[(52 + 63) * (63 + 37)] / 200
[(115 * 100)] / 200
11500 / 200
= 57.5
n(Failed n East campus)
Answer:
57.5
Step-by-step explanation:
Got it right on the test.
Which choice is equivalent to the product below when x is greater than or equal to 0
Answer: I believe it is C.
Step-by-step explanation: Because if you take 4 x 20 = 80
If I am wrong sorry.
convert 4/5 into percent
Which of the following CANNOT be true for a triangle?
A. A triangle can be equilateral and obtuse at the same time.
B. A triangle can be equilateral and equiangular at the same time.
C. A triangle can be isosceles and right at the same time.
D. A triangle can be scalene and obtuse at the same time.
Answer:
A. A triangle can be equilateral and obtuse at the same time
Step-by-step explanation:
All angles in an equilateral triangle are 60° therefore they cannot be above 90° and less than 180°
simply the expression below
Answer:
A
Step-by-step explanation:
Answer:
D. (w-3)/(w-7)
Step-by-step explanation:
(w+3)(w-3)/(w-7)(w+3)
Hence, removing (w+3),
(w-3)/(w-7)
Feel free to mark this as brainliest :D
Plz help me well mark brainliest if correct
all of the above which is e
Last Question Plz Help
Answer:
this is good looking nice photo but li can't give you answer of that sorry.
Step-by-step e this https://www.commonlit.org/en/students/student_lesson_activities
What is the area of the figure below?
2) Use the law of sines to find the length of SR
sin(A)/a=sin(B)/b=sin(C)/c
Answer:
take 28 degree as reference angle
using sine angle
sin28=p/h
0.46=10/h
0.46h=10
h=10/0.46
h=21.73
therefore hypotenuse =21.73
again using sine rule
take 25 degree as reference angle
sin 25=p/h
0.42=SR/21.73
0.42*21.73=SR
9.12=SR
9.1=SR
Step-by-step explanation:
In a dark room, the pupil of a human eye grows to a diameter of about 3.2 x 10 inches. It
bright light, the pupil shrinks to a diameter of about 8 x 10 inches. How much greater is
the pupil's diameter in a dark room than in bright light?
Answer: the answer is 48 inches
Step-by-step explanation:
help please for my math!!!!!!!!!!!
Answer:
perimeter for rectangle: (x-2+x+2)×2=4x
perimeter for triangle : 2x-8+2x-8+x+6
=5x-10
The question said both geometry has same perimeter,so we have equation :
4x=5x-10
=>x= 10
put x in triangle's perimeter: 2×10-8+2×10-8+10+6
= 40
Step-by-step explanation:
the answer is C, hope you understand it
Find the area of each figure. Round to the nearest tenth if necessary.
Answer:
Solution given:
1.
diameter(d)=6mm
base(b)=8mm
height (h)=5mm
Area of figure=area of parallelogram +area of semi circle
base*height+½π(d/2)²8*5+½*π×(6/2)²40+14.1454.4mm²Area :54.14mm²2.
for triangle
base[b]=6ft
height(h)=9ft
for square
length[l]=9ft
Area of figure=area of square +area of triangle
=l²+½*b*h=9²+½*6*9=81+27=108ft²Area: 108ft²Need help with it I don’t know how to do it
URGENT!
Find the value of x for which ABCD must be a parallelogram.
3
9
1
41
Answer and Step-by-step explanation:
To find the value of x, set the sides BC and AD equal to each other (we can do this because we are told that the figure is a parallelogram, and those sides are congruent as stated in the properties of a parallelogram).
16x - 15 = 30 + 11x
Subtract 11x from both sides of the equation.
5x - 15 = 30
Add 15 to both sides of the equation.
5x = 45
Divide both sides of the equation by 5.
x = 9
So, the answer is 9, which is equal to x.
#teamtrees #PAW (Plant And Water)
Answer:
x = 1.67
Step-by-step explanation:
We know that in a parallel, opposite sides are parallel and congruent, therefore we can solve for x, by:
(BC) = (AD)
16x - 15 = 30 - 11x
(+11x) + 16x - 15 = 30
27x - 15 = 30
27x = 45
x = 45/27
x = 1.67
Therefore, x = 1.67
Hope this helps!
solve the following equation 4 x + 10 = 66
-> 4x= 66-10
-> 4x= 56
-> x= 56/4
-> x= 14
mark me brainliestttt plsss :)))
Answer:
x = 14.
Step-by-step explanation:
4x + 10 = 66
4x + 10 - 10 = 66 - 10
4x = 56
x = 56/4 = 14.
factorize (2u+3u)(u+v)-2u+3v
Answer:
Step-by-step explanation:
(2u+3u)(u+v)-2u+3v
=2u(u+v)+3u(u+v)-2u+3v
=2u^2+2uv+3u^2+3uv-2u+3v
=5u^2+5uv-2u+3v