Answer:
elements in the same periodic table group have the same valence electrons
A right triangle ABC has sides /AB/ =9cm, /BC/=12cm find /AC/ and angles ACB and ABC if angle BAC= 90°
fdi9bn 08989089089008i uuuuuuri9ij
Si observamos un incremento de temperatura en un termómetro de 24 oC, ¿a cuántos grados Fahrenheit corresponde dicho incremento? ¿Y si el incremento de temperatura fuese de 24 K?
Responder:
24 ° C = 75.2 ° F 24K = -416.47 ° FExplicación:
La fórmula se utiliza para convertir grados Celsius (° C) en grados Fahrenheit (° F).
x ° C = (y ° F - 32) × 5/9.
Convertir 24 ° C a Fahrenheit
24 = (y ° F - 32) × 5/9.
24 * 9 = 5 (y ° F-32)
216 = 5 años ° F-160
5 ° F = 216 + 160
5 ° F = 376
y ° F = 376/5
y ° F = 75.2
24 ° C = 75.2 ° F
Para convertir Kelvin a Fahrenheit, usaremos la expresión;
(K - 273.15) × 9/5 + 32
Dado K = 24kelvin
24K a ° F = (24− 273.15) × 9/5 + 32
= -249.15 (9/5) + 32
= -448.47 + 32
= -416.47 ° F
24K = = -416.47 ° F
Las esferas metálicas que se muestran en la figura se cargan con 1C cada una. La balanza se equilibra al situar el contrapeso a una distancia x del eje Se pone una tercera esfera a una distancia 2d por debajo de a esfera A y cargada con -2C. Para equilibrar la balanza se debe mover el contrapeso a la derecha, porque?
Answer:
this relationship to be true the value x ’must be positive, so it must move to the right.
Explanation:
En este ejercicio debemos utilizar la relacion de equilibrio rotacional.
Fijemos un sistema de referencia situado en el eje de jiro del sistema y la rotación antihoraria es positiva.
Las esferas estan a la izquierda y el contrapeso ala derecha
W d = w_contrapeso x
donde W es el peso de las esferas de d su distancia hasta eleje de giro
Ahora colocamos la carga negativa debajo de la esfera A, como las cargas son de diferente signo las dos esferas se atraen, lo que crea una fuerza hacia bajos de magnitud
F =k q₁ q₂/r²
F =8,9 10⁹ 1 2/ (2d)²
F = 4,45/d² N
volvamos escribir la ecuación de equilibrio rotacional con esta fuerza
F d + W d = W_contrapeso (x+x’)
(4,45 10⁹ /d²) d + W d = W_conrapeso x+ W contrapesos x’
en la primera ecuación vimos que dos terminos se igualan ,por lo cual se anulan quedando
4,45 10⁹/d = W contrapeso x’
para que esta relación sea cierta el valor e x’ debe ser positivo, por lo cual debe moverse a la derecha.
Traduction
In this exercise we must use the relationship of rotational equilibrium.
Let's fix a frame of reference located on the system's axis of rotation and the counterclockwise rotation is positive.
The spheres are on the left and the counterweight on the right
W d = w_counterweight x
where W is the weight of the spheres of d its distance to the turning axis
Now we place the negative charge under sphere A, as the charges are of different sign the two spheres attract, which creates a downward force of magnitude
F = k q₁ q₂ / r²
F = 8.9 10⁹ 1 2 / (2d)²
F = 4.45 / d² N
let's rewrite the rotational equilibrium equation with this force
F d + W d = W_ counterweight (x + x ’)
(4.45 10⁹ / d²) d + W d = W_counterweight x + W counterweights x’
In the first equation we saw that two tenunos are equal, which is why they cancel, leaving
4.45 10⁹ / d = W counterweight x ’
for this relationship to be true the value x ’must be positive, so it must move to the right.
A schooterist move along a circular path for radius 0.2km for 2 minutes
A ) what is the distance travelled
B) what is the velocity of the schooterist
Answer:
a 1.26 km b 10.5 m/s
Explanation:
A. Distance travelled by the schooterist
Since the schooterist travels in a circular path, the distance moved is the circumference of a circle, C with radius r = 0.2 km
C = 2πr
= 2π(0.2 km)
= 1.26 km
So, the distance travelled by the schooterist is 1.26 km
B. The velocity of the schooterist
The velocity of the schooterist v = distance travelled/time
distance travelled = 1.26 km = 1260 m
time = 2 minutes = 2 × 60 s = 120 s
So, V = 1260 m/120 s
= 10.5 m/s
So, the velocity of the schooterist is 10.5 m/s
HELLLP PLEASE || the graph below shows a conversion of energy for a skydive jumping out of a plane and landing safely on the ground. which energy is represented by line A? A) Potential B) Thermal C) Kinetic D) Total Energy
Answer: If i'm not mistaken I think it A) potential
HELLLP PLEASE || the graph below shows a conversion of energy for a skydive jumping out of a plane and landing safely on the ground. which energy is represented by line A? A) Potential B) Thermal C) Kinetic D) Total Energy
Answer: I maybe wrong but i'm pretty sure its C) Kinetic energy
Question 1
a. Name each of the laboratory equipment labelled V to Z. (5 marks)
b. Mention one use of each of the laboratory equipment
identified in question 'a' above. (5 marks)
Answer:
a. All the laboratory equipment given are very basic equipment used in all the laboratories. Name of each equipment is as follows:
V refers to the tape measure.W refers to dropper.X refers to an inoculating loop.Y refers to a stopwatch.Z refers to the microscope.b. Use of each laboratory equipment identified is:
Tape measures (V) is used to measure the length of objects or distance in a laboratory.Dropper (W) is used to measure unit of drop required to dispensed as one drop or several drops in any experiment.Inoculating loop (X) is used by microbiologists to cultivate microbes on plates and retrieving an inoculum from a culture of microorganisms. Stopwatch (Y) is used to measure the time of any experiment.Microscope (Z) is used to magnify an object to look at it in detail.How to convert 200ml to m(3)?
What happens to the Kinetic Energy of an object if its mass stays the same but its speed is doubled
Answer:
kinetic energy is proportional to the velocity squared, increases in velocity will have an exponentially greater effect on translational kinetic energy. Doubling the mass of an object will only double its kinetic energy, but doubling the velocity of the object will quadruple its velocity.
pls mark as branliest
I NEED HELP PLEASE, THANKS :) What does it mean when white light is diffracted and at a particular location the color seen is blue?
Answer:
This is because white light consists of 7 colours with different angles o deviation or retraction.
Explanation:
When a narrow beam of light is refracted by a prism the light spreads into a band of colours (called the spectrum of light )
But in this case if a blue colour is observed it is due to the angle of refraction ,for instance red is refracted the least and hence is seen
Answer:
When while light is diffracted and at a particular location blue color is seen, this means that blue color is reflected while all other colors will be absorbed. When the blue color is seen denotes the shortest wavelength being reflected and all other being absorbed at the specified location.
10). Three - fourth of the volume of a block which is floating in water extends above the surface
of the water. What is the density of the block?
Answer:
Explanation:
Fill the graduated cylinder partially with water to a level where you can submerge the object and drop the sinker weight into the water. If you don't have a graduated cylinder to fit your object, put a cylinder in a basin, fill it to the top with water and measure the overflow into the basin. Your answer will be less accurate because of the number of times the water has been moved. Note the amount of displacement in milliliters (ml) caused by the sinker and string.
Measure the mass of your object (say a cork) on a balance scale in grams (g). Be sure the object is dry when it is measured. Record its weight. Attach the sinker with the string to the object. If you use a staple or pin, be sure to include that when you measure the displacement of the sinker in step one.
The displacement from equilibrium of an oscillating weight suspended by a spring and subject to the damping effect of friction is given by y(t) = 2e−t cos 4t, where y is the displacement (in centimeters) and t is the time (in seconds). Find the displacement when t = 0, t = 1 4 , and t = 1 2 . (Round your answers to two decimal places.)
Note that the correct times are t = 0, t = 1/4, t = 1/2. You can tell from the spaces between the two digits. i.e 1&4 and 1&2
Answer:
y(0) = 2.00 cm
y(1/4) = 1.56 cm
y(1/2) = 1.21 cm
Explanation:
This is a very simple exercise, the displacement of the oscillating weight from equilibrium has already been modeled by the equation:
[tex]y(t) = 2e^{-t} cos 4t[/tex]
Where y = displacement ( in cm)
and t = time (in seconds)
The task is to find the displacement when t = 0, 1/4 and 1/2
When t = 0 s
[tex]y(0) = 2e^{0} cos 4(0)\\y(0) = 2* 1*1\\y(0) = 2.00 cm[/tex]
When t = 1/4 s
[tex]y(1/4) = 2e^{-1/4} cos 4(1/4)\\y(14) = 2e^{-1/4} cos (1)\\y(1/4) = 1.56 cm[/tex]
When t = 1/2
[tex]y(1/2) = 2e^{-1/2} cos 4(1/2)\\y(14) = 2e^{-1/2} cos (2)\\y(1/2) = 1.21 cm[/tex]
Question 13 of 32
1 Point
For a satellite to orbit Earth at a constant distance, its centrifugal acceleration
must be equal and opposite Earth's gravitational acceleration. If a satellite is
to orbit at a constant distance from Earth at a circular radius of 7,000,000 m,
what is the required velocity of the satellite? (Assume the acceleration due to
Earth's gravity is 8.2 m/s2 at this altitude.)
O A. 8239 m/s
O B. 7576 m/s
C. 6818 m/s
D. 7043 m/s
Answer: B
V = 7576 m/s
Explanation: Given that the
circular radius R = 7,000,000 m,
The acceleration due to Earth's gravity is 8.2 m/s2
Let's use gravitational field strength formula to get the mass of the satellite.
g = Gm/R^2
Where G = 6.674×10^−11m3⋅kg−1⋅s−2
Substitutes all the parameters into the formula
8.2 = (6.674×10^-11 × M)/(7000000)^2
Cross multiply
4.018 × 10^14 = 6.674×10^−11M
Make M the subject of formula
M = 4.018 × 10^14 ÷ 6.674×10^−11
M = 6.02 × 10^24 kg
The Force of attraction experienced by the satellite will be
F = mg
F = 6.02 × 10^24 × 8.2
F = 4.94 × 10^25 N
But centripetal force is
F = MV^2/ R
Where V = velocity of the satellite
Substitute F, M and R into the formula
4.94×10^25 = (6.02×10^24V^2)/ 7 ×10^6
Cross multiply
3.46 × 10^32 = 6.02×10^24V^2
Make V^2 the subject of formula
V^2 = 3.46×10^32 ÷ 6.02×10^24
V^2 = 57403600.2
Find the square root of the value to get V
V = 7576 m/s
The required velocity of the satellite is 7576 m/s approximately
You have a graduated cylinder that you use to measure volume. The cylinder
is marked in 1 ml increments. Which measurement made using this cylinder
contains the correct number of significant digits?
A. 35.5 ml
B. 320.01 ml
C. 75.333 ml
D. 21 ml
Answer:
35.5 ml
Explanation:
The other guy made me get the question wrong lol here ya go good luck
Which condition must be met in order for an equation to be balanced?
Answer:
There must be an equal amount of each element on both sides of the equation. Hope this helps and please marks as the brainliest.
Explanation:
Answer:
The answer is D
Explanation:
Hope this helps!
To which category does galaxy #4 belong? Why does it belong in this category?
Answer:
The Galaxy IV satellite belongs to the HS-601 model category. It was engineered by Hughes Space and Communications Company (HSC)
Explanation:
The Galaxy IV belong in this category because it is a communications satellite. It was built for direct television broadcasting, for private business networks and mobile communications.
Cheers!
Find the average velocity if the takeoff velocity of an airplane on a runway is 300 km/hr with an acceleration of 1 m/s2 . A) 30 sec B) 41.7 sec C) 72.2 sec D) 83.33 sec
Answer:
83.33s
Explanation:
velocity=300km/hr ,acceleration =1m/s2
But before we can make this calculation,we have to make sure that both the acceleration and velocity are in the same units.So I decided to Chang the velocity to m/s.
Converting 300km/hr into m/s;
Changing 300km into m=300000m
Changing 1hr into secs=3600sec
Velocity in m/s=83.33m/s
But Time =velocity/acceleration
=83.33/1
=83.33sec
You have to decide what you want. Your question says "Find the average velocity", but the choices you listed are all times, not velocities.
(300 km/hr) x (1 hr / 3600 sec) = 83.33 meters/sec
-- If the airplane starts from rest and accelerates uniformly at 1 m/s², it'll take 83.33 seconds to reach takeoff speed.
-- If it starts from rest and accelerates uniformly to 83.33 m/s, then its average speed is 41.67 m/s no matter what its acceleration may be.
quick question plz.........If force acting on a body of mass 40kg is doubled. By how much will be the acceleration change?
A. By a factor of 2
B. By a factor of 3
C. By a factor of 4
D. remains the same
Answer:
if i'm not mistaken the answer is A
The new acceleration will be increase by the factor of 2. Hence, option (A) is correct.
Given data:
The mass of body is, m = 40 kg.
We can use the Newton's second law to obtain the result of given problem. As per the Newton's second law, "The force applied by the given object is equal to the product of mass of object and the magnitude of acceleration of object". Then the expression is,
F = ma
a = F/m .....................................................................(1)
Here,
F is the force.
m is the mass.
a is the acceleration.
if the force acting in the mass of body of 40 kg is doubled. Then new acceleration will be,
F' = ma'
(2F) = ma'
2(F/m) = a'
From equation (1) we get,
a' = 2a
Thus, we can conclude that the new acceleration will be increase by the factor of 2. Hence, option (A) is correct.
Learn more about the Newton's Second Law here:
https://brainly.com/question/19860811
A stone is dropped from a tower of height 3600cm.Find the velocity by which it strike the ground.Also,find the time taken to reach the ground.
Answer:
Explanation:
Here h=36m, a=g=10m/s, u=0
Use s=ut+(1/2)at^2
36=0*t+(10t^2)/2
time=2.68 sec
As from the formula of final velovity, v=(2gh)^1/2
v=(2*10*36)^1/2
v=(720)^1/2
v=26.83………This is the final velocity
Answer:
Explanation:
s = vit + 1/2 gt*2
36 = 0 + 1/2 x 9.8 x t*2
t*2 = 7.34
t = 2.7sec
now,
2gs = vf*2 - vi*2
2 x 9.8 x 36 = vf*2 - 0
vf*2 = 705.6
vf = 26.5m/s
Which property of argon is used in light bulbs?
Answer:
Argon belongs to zero group, i.e., is a noble gas and thus is inert. Hence it will not react with the hot filaments. Hence it is used in fluorescent and incandescent light bulbs to stop the oxygen in the light bulbs from corroding the hot tungsten filament.
Explanation:
Which form of government shares goods and services equally, and the political power is disturbing among the people?
Answer:
Socialist
Explanation:
Answer: socialist
Explanation: A socialist form of government is where the goods and services are equally shared, and the political power is distributed among the people.
Austin kicks a soccer ball with an initial velocity of 18.0 m/s at an angle of 35.0°. What are the horizontal and vertical components of the initial velocity? Round your answers to the nearest tenth. vix = m/s viy = m/s
Answer:
(vix, viy) = (14.7 m/s, 10.3 m/s)
Explanation:
The velocities of interest are ...
(vix, viy) = (vi)(cos(35°), sin(35°)) = (18 m/s)(cos(35°), sin(35°))
(vix, viy) = (14.7 m/s, 10.3 m/s)
Answer:
First one = 14.7
Second one = 10.3
Explanation:
EDGE
Which refers to a measure of how acidic or basic a solution is? a]pH b]solubility c]reactiveness d]hardness
Answer:
Option(a) i.e" pH" is the correct answer to the given question .
Explanation:
The main objective of pH value is to determining whether the solution is the acidic or the basic solution.The pH is determining the solution whether it is basic or acidic with the help of there pH value .The range of the pH value is from 0 to 14 with the following parameter it determines whether the solution is basic ,acidic or the neutral solution .
If pH value is 7 then it is neutral solution .If pH value is greater then 7 then the solution is then it is basic solution .If the pH value is less then 7 then the solution is the Acidic solution .All the other option are not determining that whether the solution is acidic or the basic solution that's why these are incorrect option .
Answer:
the answer is A pH
got it right 2020
Explanation:
I NEED HELP PLEASE, THANKS! Describe each Newton Law. :)
Explanation:
1st- states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction.
2nd- states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it. (most important law)
3rd- states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction. (law of action/reaction)
Which property of sugar makes it different from white crystalline sand?
Answer:
The property of sugar which makes it different from sand is that sugar can dissolve in water. Explanation: however the power of dissolving of sand is not present. This is due to the presence of interaction between sugar and water.
Explanation:
I hope that was useful
I NEED HELP PLEASE, THANKS! :) Why is it a good idea to touch a metal pole, or similar conductor, before filling up a car with gas?
Answer:
While filling up the gas, a static discharge can take place which is really dangerous for us. It can even ignite a fire at the gas station. Touching the metal pole or any conductor will pass all of the charge into the Earth and thus we'll keep safe.
Answer:
It is a good idea to touch a metal pole or similar conductor before filling up a car with gas because it will discharge any static electricity on you, making it safer for everyone.
Explanation:
Calculate the volume of the part of the sphere that will be immersed in the mercury when the density of the sphere is 7800kg/metre cubic and volume of 136centrimetre cubic and the density of the mercury is 13600kg/metre cubic
Answer:
78 cm³
Explanation:
The Volume Immersed = (density of object/ density of fluid) x Volume of Object
Vi = (7800/13600) x 136 = 78 cm³
A radioactive isotope has a half-life of 2 hours. If a sample of the element contains 600,000 radioactive nuclei at 12 noon, how many radioactive nuclei would be left at 6 pm?
Answer: There will be 75258 nuclei left at 6 pm.
Explanation:
a) half-life of the radioactive substance:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
[tex]t_{\frac{1}{2}}=\frac{0.69}{k}[/tex]
[tex]k=\frac{0.69}{t_{\frac{1}{2}}}=\frac{0.693}{2hours}=0.346hours^{-1}[/tex]
b) Expression for rate law for first order kinetics is given by:
[tex]A=A_0e^{-kt}[/tex]
where,
k = rate constant
t = time for decomposition = 6 hours ( from 12 noon to 6 pm)
A = activity at time t = ?
[tex]A_0[/tex] = initial activity = 600, 000
[tex]A=600000\times e^{-0.346\times 6}[/tex]
[tex]A=75258[/tex]
Thus there will be 75258 nuclei left at 6 pm.
A train starts from rest .It moves through 1km in 100s with uniform accelaration . What will be its speed at the end pf 100 s
Answer:
Explanation:
Distance = 1 km
= 1000m
Time = 100 sec
Speed = distance / time
= 1000 / 100
= 10 m/s
A 50.0-g hard-boiled egg moves on the end of a spring with force constant k = 25.0 N/m. Its initial displacement is 0.300 m. A damping force Fx=−bvxF
x
​
=−bv
x
​
acts on the egg, and the amplitude of the motion decreases to 0.100 m in 5.00 s. Calculate the magnitude of the damping constant b.
Answer:
The correct answer will be "0.022 kg/s".
Explanation:
The given values are:
Initial amplitude,
A₁ = 0.3 m
Final amplitude,
A₂ = 0.1 m
Mass of a egg,
m = 50.0 g i.e., 0.050 kg
Time,
t = 5 sec
As we know,
⇒ [tex]A_{2}=A_{1}e^{(-\frac{b}{2m})t}[/tex]
So that, the damping constant will be:
⇒ [tex]b=\frac{2m}{t} log \frac{A_{1}}{A_{2}}[/tex]
On putting the estimated values, we get
⇒ [tex]b=\frac{2\times 0.050}{5}log \frac{0.3}{0.1}[/tex]
⇒ [tex]=\frac{0.1}{5} log \frac{0.3}{0.1}[/tex]
⇒ [tex]=0.02 \ log 3[/tex]
⇒ [tex]=0.0219 \ kg/sec \ or \ 0.022 \ kg/s[/tex]