Effciency of a lever is never 100% or more. why?Give reason​

Answers

Answer 1

Answer:

Ideally, the work output of a lever should match the work input. However, because of resistance, the output power is nearly always be less than the input power. As a result, the efficiency would go below [tex]100\%[/tex].  

Explanation:

In an ideal lever, the size of the input and output are inversely proportional to the distances between these two forces and the fulcrum. Let [tex]D_\text{in}[/tex] and [tex]D_\text{out}[/tex] denote these two distances, and let [tex]F_\text{in}[/tex] and [tex]F_\text{out}[/tex] denote the input and the output forces. If the lever is indeed idea, then:

[tex]F_\text{in} \cdot D_\text{in} = F_\text{out} \cdot D_\text{out}[/tex].

Rearrange to obtain:

[tex]\displaystyle F_\text{in} = F_\text{out} \cdot \frac{D_\text{out}}{D_\text{in}}[/tex]

Class two levers are levers where the perpendicular distance between the fulcrum and the input is greater than that between the fulcrum and the output. For this ideal lever, that means [tex]D_\text{in} > D_\text{out}[/tex], such that [tex]F_\text{in} < F_\text{out}[/tex].

Despite [tex]F_\text{in} < F_\text{out}[/tex], the amount of work required will stay the same. Let [tex]s_\text{out}[/tex] denote the required linear displacement for the output force. At a distance of [tex]D_\text{out}[/tex] from the fulcrum, the angular displacement of the output force would be [tex]\displaystyle \frac{s_\text{out}}{D_\text{out}}[/tex]. Let [tex]s_\text{in}[/tex] denote the corresponding linear displacement required for the input force. Similarly, the angular displacement of the input force would be [tex]\displaystyle \frac{s_\text{in}}{D_\text{in}}[/tex]. Because both the input and the output are on the same lever, their angular displacement should be the same:

[tex]\displaystyle \frac{s_\text{in}}{D_\text{in}} =\frac{s_\text{out}}{D_\text{out}}[/tex].

Rearrange to obtain:

[tex]\displaystyle s_\text{in}=s_\text{out} \cdot \frac{D_\text{in}}{D_\text{out}}[/tex].

While increasing [tex]D_\text{in}[/tex] reduce the size of the input force [tex]F_\text{in}[/tex], doing so would also increase the linear distance of the input force [tex]s_\text{in}[/tex]. In other words, [tex]F_\text{in}[/tex] will have to move across a longer linear distance in order to move [tex]F_\text{out}[/tex] by the same [tex]s_\text{out}[/tex].

The amount of work required depends on both the size of the force and the distance traveled. Let [tex]W_\text{in}[/tex] and [tex]W_\text{out}[/tex] denote the input and output work. For this ideal lever:

[tex]\begin{aligned}W_\text{in} &= F_\text{in} \cdot s_\text{in} \\ &= \left(F_\text{out} \cdot \frac{D_\text{out}}{D_\text{in}}\right) \cdot \left(s_\text{out} \cdot \frac{D_\text{in}}{D_\text{out}}\right) \\ &= F_\text{out} \cdot s_\text{out} = W_\text{out}\end{aligned}[/tex].

In other words, the work input of the ideal lever is equal to the work output.

The efficiency of a machine can be measured as the percentage of work input that is converted to useful output. For this ideal lever, that ratio would be [tex]100\%[/tex]- not anything higher than that.

On the other hand, non-ideal levers take in more work than they give out. The reason is that because of resistance, [tex]F_\text{in}[/tex] would be larger than ideal:

[tex]\displaystyle F_\text{in} = F_\text{out} \cdot \frac{D_\text{out}}{D_\text{in}} + F(\text{resistance})[/tex].

As a result, in real (i.e., non-ideal) levers, the work input will exceed the useful work output. The efficiency will go below [tex]100\%[/tex],


Related Questions

A car travels a distance of 98 meters in 10.0 seconds. What is the average speed of the car during this 10.0 second interval?

Answers

Answer:

9.8 m/s

Explanation:

Distance Traveled = 98 m

Total Time = 10 s

Average Speed = Total Distance/Total Time

= 98/10

= 9.8 m/s

Hope this helped...

What are the factors affecting gravitational force?​

Answers

Answer: Distance between objectsMass of objectsForce of gravitational field

A bus is mobing with aspped of 72km/hr .convert this speed in m/s.​

Answers

Answer

ANSWER WITH FULL EXPLANATION

If a speed is given  km/h, then the formula to convert the speed from km/h to m/s is  

km/h = m/s

In other words, if you want to convert the given speed from km/h to m/s, then multiply the given number by  and put "m/s" after it.  

The speed of a car is 72 km/h.  

Converting the speed into m/s

72 km/h =  m/s = 20 m/s

∴ The speed of the car (expressed in m/s) is 20 m/s.

SHORT ANSWER

1km/h=5/18m/s

72km/h=72×5/18m/s

=4×5m/s

=20m/s.

HOPE  THIS HELPS YOU PLEASE MARK ME AS BRAINLIEST

Referring to the image below (based on vectors physics), how does he get F2X = F2Cosθ. I don't understand how he got the equation so that he knows there are equal. I circled it in orange.

Answers

Answer:

Please see explanation below

Explanation:

Recall that trigonometric functions like cosine (cos) and sine (sin) of an angle are defined based on the relationships between the sides and hypotenuse of a right angle triangle:

[tex]sin(\theta)=\frac{opposite}{hypotenuse} \\cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]

where the terms "opposite" and "adjacent" refer to the sides opposite and adjacent to the angle in question.

Based on such, one can solve for example for the "adjacent" side (the horizontal component of the 200 N vector you need to find) to the known angle ([tex]\theta[/tex]) in the following way:

[tex]cos(\theta)=\frac{adjacent}{hypotenuse}\\cos(\theta)=\frac{adjacent}{hypotenuse}\\cos(30^o)=\frac{adjacent}{200}\\adjacent=200\,\,cos(30^o)[/tex]

An atom of tungsten (W) has 74 protons. The atomic mass of tungsten is 183.84.
How many neutrons does an atom of tungsten have? Round your answer to the nearest whole number.
Intro
Done​

Answers

Answer:

110

Explanation:

to find neutrons we have to subtract the atomic number from the atomic mass.

atomic mass = 183.84

atomic no = 74

183.84 - 74 = 109.84

round off = 110

Answer:

110

Explanation:

edg. 2020

A car travels 30.0 km to the south and then turns around and travels 20.0 km to the north in 1.5 hours time. What is the car's total displacement? What is the car's average velocity?
Total displacement = ______ km S
Average velocity = ________ km/h S

Answers

Explanation:

Total displacement =30+20=50 Km

Average velocity =displacement /time

V=50/1.5=33.33km/hr

Answer:

Total Displacement: 10

Average velocity, closest option is 10.

Explanation:

30-20=10

Match the characteristics with the states of matter. does not have a definite shape or volume has definite volume but does not have a definite shape has a definite shape and volume changes to liquid on heating changes to liquid on cooling changes to solid on cooling

Answers

Answer:

does not have a definite shape or volume=gas

has a definite volume but has no shape=liquid

has a definite shape and volume=solid

changes to liquid on heating=melting

changes to solid on cooling=freezes

changes to liquid on cooling=condensation

A motorboat accelerates uniformly from a velocity of 6.5 m/s to the west to a velocity of 1.5 m/s to the west. If its acceleration was 2.7 m/s2 to the east, what was the boat's displacement

Answers

Answer:

The displacement of the boat is 7.41 m

Explanation:

Given;

initial velocity of the motorboat, u = 6.5 m/s west

final velocity of the motorboat, v = 1.5 m/s west

acceleration of the motorboat, a = -2.7 m/s² east

The displacement of the boat is given by;

v² = u² + 2ad

where;

d is the displacement of the motorboat

1.5² = 6.5² + 2(-2.7)d

1.5² -  6.5² = -5.4d

-40 = -5.4d

d = (40) / 5.4

d = 7.41 m

Therefore, the displacement of the boat is 7.41 m

88 L + 120 dL = _____________ L?

Answers

Answer:

100 L

Explanation:

10 dL =  1 L

atomic number of metal and the atomic mass

Answers

Answer:

there are many metals in the periodic table and all have different atomic number and mass

Explanation:

a car travels 50km east east in 30 min what is its velocity in km/h

Answers

Answer:

0.6

Explanation:

PLEASE HELP ME suppose you ride a bicycle around the ,returning to your starting point. At the end of your trip is your average speed greater than, less than, or equal to the magnitude of your average velocity? Explain

Answers

Answer:

Greater than

Explanation:

Distance is the length of the path traveled.  Displacement is the difference between the final position and initial position.

Speed = distance / time

Velocity = displacement / time

Since you return to your starting point, your displacement is 0 m, so your average velocity is 0 m/s.  Therefore, your average speed is greater than your average velocity.

Speed ls a function of distance and time, while velocity is a function of displacement and time. Since the rider returned to his starting point, then the magnitude of the average speed is greater than the magnitude of the average velocity

Average speed = [tex]\frac{distance}{time} [/tex]

Average velocity = [tex]\frac{displacement}{time} [/tex]

The total distance traveled will be sum of the 'to' and 'fro' distance.

The total displacement will be 0 (Final position - Initial position) ; since the rider returned to his starting position.

This means the average velocity will be 0 while the average speed will have a value greater than 0.

Therefore, the average speed will be greater.

Learn more :https://brainly.com/question/23774048

Se suelta una piedra cerca de la superficie lunar y cae libremente durante 7 segundos. La aceleración de la gravedad lunar es de 1,6 m/s² ¿qué velocidad alcanzará?

Answers

Answer:

v = 11.2 m/s

Explanation:

A stone is dropped near the lunar surface and falls freely for 7 seconds. The acceleration of lunar gravity is 1.6 m / s², what speed will it reach?

Given that,

The acceleration due to the gravity of lunar gravity is 1.6 m/s²

A stone is dropped near the lunar surface and falls freely for 7 seconds.

We need to find the speed with which it reach.

The initial velocity of the stone will be 0 as it was at rest.

Using equation of kinematics v=u+at

[tex]v=1.6\times 7\\\\v=11.2\ m/s[/tex]

So, the stone will reach with a speed of 11.2 m/s

Dr. Sampson is studying the effects of caffeine on hunger. He hypothesizes that people who ingest more caffeine experience less hunger pangs throughout the day. He designs a study where one group of participants is given caffeine throughout the day, and the other group is not allowed to have any caffeine. He then has the two groups journal their hunger pangs throughout the day and he compares the results. In this study, the experimental group consists of the participants who:

Answers

Answer:

The participants who were given the coffee

Explanation:

This is the group which the experiment is centered or focused around in order to achieve a result of derive informations regarding their exposure to some things.

Dr. Sampson is studying the effects of caffeine on hunger which means he hypothesizes that people who ingest more caffeine experience less hunger pangs throughout the day. He designs a study where one group of participants is given caffeine throughout the day, and the other group is not allowed to have any caffeine. All this talks about The participants who were given the coffee being the experimental group

1/2mv^2+Fd=mgh solve for F

Answers

Answer:

[tex]F=\frac{mgh-\frac{1}{2} mv^2}{d}[/tex]

Explanation:

Step 1: Write out equation

[tex]\frac{1}{2} mv^2+Fd=mgh[/tex]

Step 2: Subtract FD on both sides

[tex]\frac{1}{2} mv^2=mgh-Fd[/tex]

Step 3: Subtract mgh on both sides

[tex]\frac{1}{2} mv^2-mgh=-Fd[/tex]

Step 4: Divide both sides by -d

[tex]\frac{\frac{1}{2} mv^2-mgh}{-d} =F[/tex]

Step 5: Rewrite

[tex]F=\frac{mgh-\frac{1}{2} mv^2}{d}[/tex]

From a rifle of mass 4 kg, a bullet of mass 50 g is fired with an initial velocity of 35 m/s. Calculate the initial recoil velocity of the rifle.

Answers

[tex]\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}[/tex]

Mass of rifle = 4kg

Mass of bullet = 50g = 0.05kg

Initial velocity of bullet = 35m/s

[tex]\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}[/tex]

Recoil velocity of rifle.

[tex]\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}[/tex]

Recoil velocity of rifle is given by

[tex]\dag\:\boxed{\bf{\purple{V=-\dfrac{mv}{M}}}}[/tex]

M denotes mass of riflem denotes mass of bulletv denotes velocity of bullet

[tex]:\implies\sf\:V=-\dfrac{mv}{M}[/tex]

[tex]:\implies\sf\:V=-\dfrac{0.05\times 35}{4}[/tex]

[tex]:\implies\sf\:V=-\dfrac{1.75}{4}[/tex]

[tex]:\implies\bf\:V=-0.437\:ms^{-1}[/tex]

[Note : -ve sign shows opposite direction]

Answer:

MgVg=MbVb.

4×Vg=0.05×35.

4Vg=1.75.

Vg=1.75/4

=0.4375 ~ 0.4m/s.

During a baseball game, a batter hits a pop-up to a fielder 93 m away.The acceleration of gravity is 9.8 m/s2.If the ball remains in the air for 5.4 s, howhigh does it rise?Answer in units of m

Answers

Explanation:

It is given that, a batter hits a pop-up to a fielder 93 m away, range of the projectile, R = 93 m

The ball remains in the air for 5.4 s, the time of flight is 5.4 s

Time of flight : [tex]T=\dfrac{2v\sin\theta}{g}[/tex]

[tex]5.4=\dfrac{2v\sin\theta}{g}\\\\v\sin\theta=\dfrac{5.4\times 9.8}{2}\\\\v\sin\theta=26.46[/tex]

Maximum height of the projectile : [tex]H=\dfrac{v^2\sin^2\theta}{2g}[/tex]

We need to find H.

So,

[tex]H=\dfrac{(v\sin\theta)^2}{2g}\\\\H=\dfrac{(26.46)^2}{2\times 9.8}\\\\H=35.72\ m[/tex]

So, it will rise to a height of 35.72 m.

An athlete participating in cross-country spends the afternoon practicing, and at the end is completely exhausted from all the hard word, even though their average velocity during the practice was 0 m/s. Explain how this situation is possible.

Answers

Answer: please find the answer in the explanation

Explanation:

Velocity is the distance covered in a specific direction per time taken.

And in velocity, we have final velocity V and initial velocity U.

The definition of average velocity is:

Average velocity = (V + U)/2

Since velocity involves direction, if the initial velocity U is of the same magnitude as the final velocity V and both are of opposite direction. Then,

Average velocity = (-U + V)/2

Since they are of the same magnitude,

V = U.

Therefore,

Average velocity = (-U + U)/2 = 0

A swimmer bounces straight up from a diving board and falls feet first into a pool. She starts with a velocity of 5.00 m/s, and her takeoff point is 1.30 m above the pool.

Required:
a. How long are her feet in the air?
b. What is her highest point above the board?
c. What is her velocity when her feet hit the water?

Answers

Answer:

a

     t =  1.235 s

b

  [tex]h_{max} = 2.55 \ m[/tex]

c

 [tex]v = -7.10 m/s[/tex]

Explanation:

From the question we are told that

    The  initial  velocity is [tex]u = 5.0 \ m/s[/tex]

      The  take of height is  [tex]h = -1.30 \ m[/tex]

The negative sign show that the height is on the negative y-axis when the take off point is consider as the origin

Generally from the kinematic equation we have that

       [tex]s = ut + \frac{1}{2}at^2[/tex]

=>     [tex]-1.30 = 5.0 t + \frac{1}{2} (-9.8)t^2[/tex]

Here g is negative given that the swimmers jump motion is against gravity

    [tex]4.9t^2 - 5t - 1.30[/tex]

solving using quadratic formula we obtain that

    t =  1.235 s

Generally the highest point is mathematically evaluated as

      [tex]h_{max} = \frac{v^2 - u^2 }{2 * (-g) }[/tex]

Here v =  0 m/s since the velocity at the highest point is 0

   [tex]h_{max} = \frac{0^2 - 5^2 }{2 * (-9.8) }[/tex]

   [tex]h_{max} = 2.55 \ m[/tex]

Generally her velocity when the feet hits the water is mathematically evaluated from kinematic equation as

     [tex]v = \pm \sqrt{ u^2 + 2 (-g) * (-h)}[/tex]

      [tex]v = -7.10 m/s[/tex]

The  negative value of the velocity is selected because the velocity is on the negative y-axis

     

     

     

During resistance exercise, muscles are __________. A. working against a force B. repeatedly contracted C. concerted in movement D. all of the aboveImproving muscular strength and endurance slows bone density loss.

Answers

Answer:

the answer is A. working against a force

Explanation:

Answer:

A. working against a force

Explanation:

Question 1 of 10
Which situation is most likely to lead to improving a scientific theory?
O A. Development of new technologies
B. Relaxing government restrictions
C. Repeating an experiment to verify results
D. Increased funding for research

Answers

Answer:

The correct option is;

C. Repeating an experiment to verify results

Explanation:

A scientific theory is a statement explaining an observed natural phenomenon which can be simulated for verification ensuring that all protocols of the scientific method of investigation are observed.

By repeating the experiment under particular conditions such as through verification of data from direct observation such as in astronomy, a scientific theory can be improved by pointing out the natural behavior of the phenomenon to better clarify the assumptions made in the theory.

Answer:

Developing new technologies.

Explanation:

31. A man can lift 600 kg on the surface of the moon. He can lift on the earth is:
(2 Points)
100 kg
O 600 kg
0 60 kg
980 kg​

Answers

Answer:

He can lift on the earth is 60 kg

The person selling the bananas in the market says that they have a "weight" of 1 kg. Explain what is wrong with this statement​

Answers

Answer:

Explanation:

weight is wrong.........weight is usually used for the heaviness in a body,,,,,,,we sell food giving the information that how many mass it contains or how many mass of this food do you want!

i hope you find it right!!!!!!!

Answer:

It should be mass instead of weight

Explanation:

I must use mass or dozen for bananas

1 point
A person is standing on the equator. What is the person's displacement (in kilometers) after 1 revolution of the planet? Facts: The Earth rotates around the axis of
rotation once every 23 hours and 56 minutes. The circumference (distance around something) is 40,075 kilometers.
type your answer

Answers

Answer:

The person has no displacement

Explanation:

The given parameters are

The location of the person = The equator

The distance covered in one revolution = Total distance around the body

The total distance around the Earth = The circumference of the Earth = 40.075 kilometres

The total distance moved by the person standing at the equator during the Earths complete revolution = 40,075 kilometres

The initial location of the person in relation to a fixed point in space outside Earth at the start of the revolution = x km

The final location of the person in relation to the fixed point in space outside Earth at the completion of the revolution = x km

The displacement = Change in position = Final location - Initial location  

∴ The displacement = x km - x km = 0 km.

Select the correct images.

Identity the electromagnets with poles that are reversed from the electromagnet shown above.

Answers

Answer:

I think it is the third one

Explanation:

Everything about it is flipped

The electromagnets with poles that are reversed from the electromagnet  is according to image C.

What is magnet?

A substance which is negative charged at one end and positive charged at another end creating the magnetic field around it.

A bar is a magnet which can attract the particle which are charged. It has two poles North and South.

The electromagnet is find in the electric motor. In the motor, loop made up of conductor is rotated by the effect of magnetic field of permanent magnet.

An electromagnet is a soft metal core made into a magnet by the passage of electric current through a coil surrounding it.

When the poles are reversed, then the direction of current flow is also reversed.

Thus, the correct option is C.

Learn more about magnet.

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If the 20-mm-diameter rod is made of A-36 steel and the stiffness of the spring is k = 61 MN/m , determine the displacement of end A when the 60-kN force is applied. Take E = 200 GPa.

Answers

Answer:

σ = 1.09 mm

Explanation:

Step 1: Identify the given parameters

rod diameter = 20 mm

stiffness constant (k) = 55 MN/m = 55X10⁶N/m

applied force (f) = 60 KN = 60 X 10³N

young modulus (E) = 200 Gpa = 200 X 10⁹pa

Step 2: calculate length of the rod, L

K = \frac{A*E}{L}K=

L

A∗E

L = \frac{A*E}{K}L=

K

A∗E

A=\frac{\pi d^{2}}{4}A=

4

πd

2

d = 20-mm = 0.02 m

A=\frac{\pi (0.02)^{2}}{4}A=

4

π(0.02)

2

A = 0.0003 m²

L = \frac{A*E}{K}L=

K

A∗E

L = \frac{(0.0003142)*(200X10^9)}{55X10^6}L=

55X10

6

(0.0003142)∗(200X10

9

)

L = 1.14 m

Step 3: calculate the displacement of the rod, σ

\sigma = \frac{F*L}{A*E}σ=

A∗E

F∗L

\sigma = \frac{(60X10^3)*(1.14)}{(0.0003142)*(200X10^9)}σ=

(0.0003142)∗(200X10

9

)

(60X10

3

)∗(1.14)

σ = 0.00109 m

σ = 1.09 mm

Therefore, the displacement at the end of A is 1.09 mm

6. If Dr. Swasey is like most psychologists, where does she probably work?
a. university/college
b. self-employed
c. federal government
d. state or local government

Answers

Answer: University/college

Explanation:

A psychologist is someone who studies the cognitive, emotional, and mental states of people by observing and recording how people relate with each other and their environment.

Most psychologists are found in universities in order to help students who have emotional issues or seeking answers to certain questions.

What is used to measure mass?

Answers

Answer:

A balance

Explanation:

Scientists measure mass with a balance, such as a triple beam balance or electronic balance. In science, the volume of a liquid might be measured with a graduated cylinder.

Answer: Scientists often measure mass with a balance

Hope this helps

How many weeks are in 309 seconds?

Answers

Not even a week. If you looking for a number it would be 0.00051091. Again not even a week.

Answer:

0.000510913 weeks...

Not even one week.

I am confused can anyone please answer it There are blast taking place on Sun all the time we reach the heat and energy of the blasts taking place on Sun but why we can't hear the sound produced by these blasts why can't we hear the sound of these blasts???

Answers

Answer:

Umm I think because the sun is too far away from the earth

hope it helps...

Because of the sound wave, the wave cant travel through the vacuum. Also theres no sound in space.

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