Edit cell B15 to include a formula without a function that divides the total regional sales in Quarter 1 (cell B14) by the number of salespeople (cell G2). Don't change the reference to cell G2 that is already there.

Answer:

Advertised window in bytes after one second = 0 bytes.

Explanation:

Given:

Sender bytes = 50,000 bytes

Receiver's initial advertised window = 10,000 bytes

Read rate = 2,000 bytes / per 2 second

Find:

Advertised window in bytes after one second = ?

Computation:

We know that, 10,000 bytes have been buffered in receiving initial advertised window.

Receiver read 2,000 bytes in every 2 second.

So, receiver will not able to read anything in 1 second.

Therefore,

Advertised window in bytes after one second = 0 bytes.

Answer:

The answer is given as below.

Explanation

As the complete question is not given, the complete question is found online and is attached here with.

a)

int values[SIZE] = {2,4,6,8,10};

b)

int *aPtr;

c)

for(i=0;i<SIZE;i++)

printf("%d", values[i]);

d)

aPtr=values;

aPtr=&values[0];

e)

for(i=0;i<SIZE;i++)

printf("%d", *(aPtr+i));

f)

for(i=0;i<SIZE;i++)

printf("%d", *(values+i));

g)

for(i=0;i<SIZE;i++)

printf("%d\n", aPtr[i]);

h)

array subscript notation: values[3]

pointer/offset notation: *(values +3)

pointer subscript notation: aPtr[3]

pointer/offset notation: *(aPtr + 3)

i)

1002512 is the address is referenced by aPtr + 3 and 8 is the value stored at that location.

j)

1002500 is the address referenced by aPtr -= 2 and 2 is stored at that location.

Answer:

#include <iostream>

#include <cmath>

using namespace std;

int main()

{

   double num1, num2, num3, num4, num5, sum = 0;

   cout << "Input: ";

   cin >> num1 >> num2 >> num3 >> num4 >> num5;

   sum = num1 + num2 + num3 + num4 + num5;

   cout << "Output: " << static_cast<int>(round(sum)) << endl;

   return 0;

}

Explanation:

Include cmath to use the round function

Declare the variables

Get the five numbers from the user

Sum them and assign the result to the sum

Round the sum using the round function, and convert the sum to an integer using static_cast statement

Print the sum

Answer:

Web Security Appliance (WSA)

Answer:

utm

Explanation:

UnifiedThreat Management (UTM): A security appliance and/or software tool

which contains a combination of any of the following: antivirus/antimalware, firewall,

proxy server, content filtering, spam filtering, intrusion detection system, intrusion

prevention system, and network access control. The more robust the tool, the

higher the number of features available.

Answer:

If you use Google or gravity forms for registration - the data piles into a database that can be exported like excel. Google Forms for registration will automatically pool the data into a google sheet for collection.

Explanation:

Answer:

def doubles(numbers):

   double_numbers = []

   for i in range(len(numbers)-1):

       if numbers[i+1] == numbers[i] * 2:

           double_numbers.append(numbers[i+1])

   return double_numbers

Explanation:

*The code is in Python.

Create a function called doubles that takes one parameter, numbers

Initialize an empty list, double_numbers, to hold the double values in the numbers that are exactly twice the previous integer

Create a for loop that iterates through the numbers

If the value of the integer is exactly twice the previous integer, add the integer to the double_numbers using append function

When the loop is done, return the double_numbers

Answer: Provided in the explanation section

Explanation:

The full questions says:

write a program that takes in a positive integer as input, and output a string of 1's and 0's representing the integer in binary. for an integer x; the algothm is as long as x is greater than 0 output x % (remainder is either 0 or 1 . x=x/2 in coral language. Note: The above algorithm outputs the 0's and 1's in reverse order.

Ex: If the input is:

6

the output is:

011

CODE:

#include <stdio.h>

int main() {

   int n;

   scanf("%d", &n);

   while (n > 0) {

       printf("%d", n % 2);

       n /= 2;

   }

   printf("\n");

   return 0;

}

2

#include <stdio.h>

int main() {

   int n;

   scanf("%d", &n);

   while (n > 0) {

       printf("%d", n % 2);

       n /= 2;

   }

   return 0;

}

cheers i hope this helped !!

Answer:

The code is given as below: The input and output is as given for one case.

Explanation:

echo -e "Enter A, B or C : \c" #Printing the line on the screen

read -rN 1 test #read the character in the variable test

echo

case $test in #Setting up the case structure for variable test

[[:lower:]] ) #checking all lower case letters

echo You did not enter A, B or C;;

[D-Z] ) #checking upper case letters from D to Z

echo You did not enter A, B or C;;

A ) #Condition to check A

echo You entered A;;

B ) #Condition to check B

echo You entered B;;

C ) #Condition to check C

echo You entered C;;

esac #Exiting the case structure

Answer: Provided in the explanation section

Explanation:

According to the question:

Using the chores.csv file fat the very bottom; write an awk script to return the average number of minutes required to complete a chore. Your solution must handle an undefined number of chores. zero points will be given to solutions that use a static number in their calculation.

Format floating point numbers to 2 decimal places.

Example output;

Average: 28.12

chores.csv

Chore Name,Assigned to,estimate,done?

Laundry,Chelsey,45,N

Wash Windows,Sam,60,Y

Mop kitchen,Sam,20,N

Clean cookware,Chelsey,30,N

Unload dishwasher,Chelsey,10,N

Dust living room,Chelsey,20,N

Wash the dog,Sam,40,N

ANSWER:

BEGIN{

FS=","

}

{

if(NR!=1)

sum += $3

}

END{

avg=sum/NR

printf("Average: %.2f ", avg)

}' ./chores.csv

cheers i hope this helped !!

Answer:

D. WMA

Explanation:

The following audio file formats that is the best suited for listening to music on a portable audio device is WMA.

Answer:

(D) is the answer WMA

Explanation:

Give the other person brainliest ↑↑↑

                                                        hope it helps