Earth’s natural carbon cycle influences the balance of greenhouse gases in the atmosphere but is being impacted by human activity. Evidence of this includes:
A. Ocean acidification and increased volcanic activity Increased tsunamis and ocean acidification
B. Ocean acidification, and increased global average temperatures
C. Decreased volcanic activity and increased tsunamis
D. Increased acid rain and increased tsunamis

Answers

Answer 1

Option B which is "Ocean acidification, and increased global average temperatures".

Earth’s natural carbon cycle regulates the equilibrium of greenhouse gases in the atmosphere, which helps maintain a moderate global temperature. However, human activities are increasing the concentration of greenhouse gases in the atmosphere, leading to a warming trend and other changes in the environment.

Among the human activities that influence Earth's carbon cycle are the burning of fossil fuels, deforestation, and other land-use changes. These activities are causing an imbalance in the carbon cycle, leading to a buildup of carbon dioxide and other greenhouse gases in the atmosphere, trapping heat and contributing to global warming.

Among the evidence of the impact of human activity on the carbon cycle are ocean acidification and increased global average temperatures, among others. Ocean acidification is caused by the increase in carbon dioxide in the atmosphere, which reacts with seawater to form carbonic acid, resulting in an increase in ocean acidity. Increased global average temperatures, on the other hand, are the result of the buildup of greenhouse gases, particularly carbon dioxide, in the atmosphere, which traps heat and warms the planet.

The other options mentioned, such as increased volcanic activity, increased tsunamis, and increased acid rain, are not directly related to the impact of human activity on the carbon cycle. Therefore, the main answer is option B, which is "Ocean acidification, and increased global average temperatures".

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Related Questions

List the major constituents dissolved in seawater in decreasing concentration

Answers

The following are the major constituents dissolved in seawater in decreasing concentration: 1. Chloride ions. Sodium ions. 3. Magnesium ions. 4. Sulfate ions. 5. Calcium ions.

The following are the major constituents dissolved in seawater in decreasing concentration:

1. Chloride ions are abundant in seawater, with a concentration of around 19.3 grams per kilogram of seawater.

2. Sodium ions have a concentration of roughly 10.6 grams per kilogram of seawater.

3. Magnesium ions have a concentration of roughly 1.3 grams per kilogram of seawater.

4. Sulfate ions have a concentration of roughly 2.7 grams per kilogram of seawater.

5. Calcium ions have a concentration of roughly 0.4 grams per kilogram of seawater.

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At which of these latitudes is the air moving fastest? A)10 degrees North B)60 degrees North C)30 degrees North D)45 degrees North

Answers

The latitude at which the air is moving the fastest among these four latitudes is-B. 60 degrees North.

What does it entail?

Latitude: A location on the surface of the Earth is identified by its latitude, a geographic coordinate. Latitude is measured in degrees, with the Equator being defined as zero degrees and the North Pole as 90 degrees.

Likewise, the South Pole is defined as 90 degrees south latitude. Because of the planet's rotation, latitudes that are farther from the Equator have slower air speeds.

As a result, polar latitudes experience frigid temperatures as the cold, dense air settles close to the surface.

The Intertropical Convergence Zone (ITCZ) and the Subtropical Jet Stream are two of the factors that influence latitude air speed. The air moves quickest at the subtropical jet stream.

The following latitudes are listed in the question and the air speeds are compared:

10 degrees North: The latitudes closer to the Equator have slower winds. This is due to the fact that the equatorial zone receives a lot of sunshine, which heats the air. As a result, it has a low atmospheric pressure, and air rises slowly, resulting in low wind speeds.60 degrees North: The polar latitudes have slower air speeds. The North Pole, for example, has minimal winds.30 degrees North: This is one of the latitudes that receive trade winds. The subtropical high pressure region is the area that produces trade winds. As a result, at this latitude, the winds are neither fast nor sluggish.45 degrees North: The prevailing westerlies are the dominant winds at this latitude. This wind is responsible for moving weather systems in the mid-latitudes, and it's neither fast nor sluggish.

Therefore, the fastest air movement is at 60 degrees North.

Hence, option b. is correct.

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WHAT IS THE PRECISION OF THE TRAVERSE? O 1:105,000 O 1:1500 O 1: 20,500 O 1:15,000 WHAT IS THE CORRECTION FOR DEPARTURE AND LATITUDE OF THE PREVIOUS PROBLEM? 0.035 M and 0.025 M O 0.16 M and 0.003 M O 0.08 M and 0.15 M -0.016 Mand -0.003 M D Question 15 8 pts From the previous problem, if the coordinate for Point A was N: 121,311.411 M and E: 310,630.892 M, what is the coordinate for point C? ON: 121,625.193 M and 310,851.89 M N: 121,708.396 M and 310,229.785 M O N:121,824.38 ME: 310,551.751 M 121,559.72 M and 310,531.317 M What is the corrected length of Line EA? 295.178 M 269 M 350.123 M O 267.523 M What is the value of angle D? O 46 degrees 03' 19" 46 degrees 03' 31" 46 degrees 03' 42" 0.63 degrees 45'08" Question 10 8 pts Balance the following interior angles to the right for a polygon traverse. Compute the azimuths assuming a fixed azimuth for line AB of 35 degrees 09' 32" A = 57 DEGREES OO' 50" B= 88 DEGREES 24' 45" C = 126 DEGREES 36' 58" D = 46 DEGREES 03' 25" E = 221 DEGREES 53' 52" WHAT IS THE ADJUSTED ANGLE FOR ANGLE "C" 126 DEGREES 36 56" 126 DEGREES 36' 58" 126 DEGREES 37' 04" 126 DEGREES 37'00" Question 11 8 pts FROM THE PREVIOUS PROBLEM WHAT IS THE AZIMUTH OF LINE EA? 338 DEGREES 08' 40" O 116 DEGREES 14' 46" 158 DEGREES 08' 40" O 518 DEGREES 08' 40"

Answers

we need to apply the corrections to the coordinates of point A. Given that the coordinates of point A are N: 121,311.411 M and E: 310,630.892 M, the corrected coordinates for point C are N: 121,625.193 M and E: 310,851.89 M.

The precision of the traverse is given as 1:15,000.

The correction for departure is 0.035 M and the correction for latitude is -0.003 M.

The corrected length of Line EA is 267.523 M.

The value of angle D is 46 degrees 03' 42".

To balance the interior angles, we need to adjust angle C. The adjusted angle for angle C is 126 degrees 36' 56".

From the previous problem, the azimuth of Line EA is 338 degrees 08' 40".

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