Each table shows a proportional relationship between x and y, Match each table with its constant of proportionality
ху
у
ху
х
y
1 20
2
80
2 0.4
7.5 4,5
2 40
B 320
4 0.8
10
6
3 B0
12 480
9 1.8
17.5 10.5
0.6
0.2
20
40
Have

Answer: 14

Step-by-step explanation:

1/16x = 7/8

x = 7/8*16/1 = 14

He can sell his candy

Give away to people.

Answer:

a) Acceleration = 2.4 m per seconds²

b) Distance traveled = 132 m

Step-by-step explanation:

a). Acceleration of an object is defined by the equation,

v = u + at

Here, v = Final speed

u = Initial speed

a = Acceleration

t = Duration Or time

From the graph attached,

Between t = 0 and t = 5 seconds,

v = 12 meter per second

u = 0

t = 5 seconds

B substituting values in the equation,

12 = 0 + a(5)

a = [tex]\frac{12}{5}[/tex]

a = 2.4 m per seconds²

b). Equation representing distance traveled by an object,

v² = u² + 2as

Here, v = Final speed

u = Initial speed

a = Acceleration

s = Distance traveled

By substituting these values in the given equation,

1). Between t = 0 to t = 5 seconds,

(12)² = 0 + 2(2.4)s

s = [tex]\frac{144}{4.8}[/tex]

s = 30 m

2). Between t = 5 to t = 12 sec

Car moved with a constant speed (Acceleration = 0)

Distance traveled = Speed × Time

                             = 12 × 7

                             = 84 m

3). Acceleration of the car between t = 12 sec to t = 15 sec

By substituting the values in the equation,

v = u - at

0 = 12 - a(3)

a = 4 meter per seconds²

Distance traveled in this duration,

v² = u² - 2as

0 = (12)² - 2(4)s

144 = 8s

s = [tex]\frac{144}{8}[/tex]

s = 18 m

Therefore, total distance covered by the car = 30 + 84 + 18

= 132 meters

Answer:

Scalene

Step-by-step explanation:

Answer: Acute scalene triangle

A triangle with uneven degrees on all sides is known as a scalene triangle. Since none of the degrees are above 90, this triangle can also be described as acute.

Answer:

7,000,000

Step-by-step explanation:

Limit of a function:

The limit of a function is finding looking at it's lateral limits.

If the lateral limits are equal:

The limit exists.

[tex]\lim_{x \rightarrow a} f(x) = \lim_{x \rightarrow a^{+}} f(x) = \lim_{x \rightarrow a^{-}} f(x)[/tex]

If lateral limits are different:

That is:

[tex]\lim_{x \rightarrow a^{+}} f(x) \neq \lim_{x \rightarrow a^{-}} f(x)[/tex], then the limit does not exist.

In this question:

To the left of 1, that is, 0.9999....

[tex]\lim_{x \rightarrow 1^{-}} g(x) = 7,000,000[/tex]

To the right of 1, that is, 1.0001...

[tex]\lim_{x \rightarrow 1^{+}} g(x) = 7,000,000[/tex]

Since the both limits are the same, the limits exists and it's value is of  7,000,000.

Answer:

D

Step-by-step explanation:

It shows it in the quwestions image

Answer:

20 questions

Step-by-step explanation:

There is 15% of the test left and 3 questions

15/3 = 5

85/5 = 17

17+ 3 = 20

Answer:

The answer is 181

Step-by-step explanation:

PEDMAS

1 x 1 + 9 x 20

1 x 1 = 1

1 + 9 x 20

9 x 20= 180

1+180

which equals 181

Answer:

181

Step-by-step explanation:1x1=1 9x20=180+1=181

Thats your answer my fellow brains

Answer:

80

Step-by-step explanation:

18^2 + 80^2 = 82

324 + 160 = c^2

Answer:

80 cm

Step-by-step explanation:

To solve this problem, you can use the pythagorean theorem which is a^2 + b^2 = c^2. We are given that a = 18, and c as the hypotenuse equals to 82. We can plug these numbers into the theorem:

18^2 + b^2 = 82^2

324 + b^2 = 6724

b^2 = 6400

b = 80 cm

Answer:

131.5

Step-by-step explanation:

To find the area of the rectangle, we multiply the base and the height.

In this case, the base is 8 and the height is 13 I think. ( Your picture cuts it off very poorly)

8 x 13 = 104

Now, we need to find the area of the triangle. It is the same equation as the rectangle but we divide the result by 2.

11 * 5 = 55

55/2 = 27.5

27.5 + 104 = 131.5

If it's wrong, it's probably because of the picture. I can't tell what the height is of the rectangle, because it's certainly not 3.

Answer:

10

Step-by-step explanation:

9514 1404 393

Answer:

  (a)  (-3/4, 1/2)

Step-by-step explanation:

There are 4 grid lines between 0 and 1 in each direction, so each grid line represents 1/4 unit. Two of them is 1/2 unit; 3 of them is 3/4 unit. The x-dimension is listed first in the ordered pair.

Point S has coordinates (-3/4, 1/2).

Answer:

a. 3/4

Step-by-step explanation:

6:8

=6/8

=3/4

Hope it Helps

Answer:

b = 7.56

C = 9.24

Step-by-step explanation:

Find the last angle of the triangle.

The sum of all the angles in a triangle is  

180 degrees.

A+

90+55=180

A=35

Then find c

The cosine of an angle is equal to the ratio of the adjacent side to the hypotenuse.

cos(B)=adj/hyp or Cos(55) = 5.3 / c

re write as

C = 5.3 / cos55

This gives you c = 9.24

Then use the Pythagorean theorem to find the unknown side.

[tex]a^{2} +b^{2} = c^{2} \\rewrite as\\ b^{2} = c^{2} - a^{2} \\b^{2} = 9.2^{2} - 5.3^{2} \\b^{2} = 57.29\\b = 7.56[/tex]

Answer:

[tex](-5,-4)[/tex]

Step-by-step explanation:

Given

[tex]P = (5,4)[/tex]

Rotation: 180 degrees counterclockwise

Required

P'

Rotation: 180 degrees counterclockwise

The rule is:

[tex](x,y) \to (-x,-y)[/tex]

So: [tex]P = (5,4)[/tex] becomes

[tex](5,4) \to (-5,-4)[/tex]

Answer:

[tex]Worth = \$284258.1[/tex]

Step-by-step explanation:

Given

[tex]Dimension: 7in\ * 3in\ * 1in[/tex]

[tex]Value = \$1214/oz[/tex] ---- value of Gold

Required

The worth of 1 gold bar

First, calculate the volume (n) of the gold bar

[tex]n = 7in * 3in * 1in[/tex]

[tex]n = 21in^3[/tex]

Next, calculate the weight of the gold bar using:

[tex]w = 11.15n[/tex]

[tex]w = 11.15 * 21[/tex]

[tex]w = 234.15oz[/tex]

Multiply the value of Gold by the weight of the gold bar to get the worth of the gold bar.

[tex]Worth =Value * w[/tex]

This gives:

[tex]Worth = \$1214/oz * 234.15oz[/tex]

[tex]Worth = \$1214 * 234.15[/tex]

[tex]Worth = \$284258.1[/tex]

Answer: 60 + 13 sqrt 10

the top part adds up to 10 and the bottom part is 13

so you get a 7-3-2 sqrt 10 triangle to the left

the area of that is 3 sqrt 10

the area of the leftmost rectangle is 5 * 2sqrt 10 which is 10 sqrt 10

the area of the big vertical rectangle is 5*12 which is 60

so you add them up

60 + 13 sqrt 10

Answer:

LINE GRAPH : the profits of a company over a year

SCATTER PLOT : a person's income based on age

CIRCLE GRAPH : percent of student athletes in each sport

BAR GRAPH: the numbers and types ofdifferent species of fish at an aquarium

Step-by-step explanation:

The scatter plot are useful when trying to create a graphical relationship between two measured variables, like the camparison or relationship between age and income.

Line graph is used to monitor changes in a certain variable over time. Observing the fluctuation or variation in income over a certain period.

The circle graph represents the segmentation of a whole into groups or categories with each segment representing a proportion or percentage of the whole.

The bar graph also useful for categorization using vertical bars.

Answer:

0.088

Step-by-step explanation:

Given two cylinders

Volume of one = 64cm^3

Volume of the other = 729cm^2

Scale factor = Volume of the small/Volume of the large

Scale factor = 64:729

Scale factor = 0.087

Answer:

(D) The passenger's height aloe the ground is increasing by 15.708 meters per minute 7.5 minutes after the ride begins.

Step-by-step explanation:

Here, H(t) is the height after the t minutes of time.

Given :

H'(7.5) = 15.708 meters / minute

H'(t) = [tex]$\frac{d(H(t))}{dt}$[/tex]

     = rate of change of the height

So, here, H'(t) = rate of change of height

Therefore, H'(7.5) = 15.708 meters / minute

It shows that the passenger's height is increasing at rate 15.708 meters per minute at time t = 7.5 minutes after the ride begins.

Answer:

I hope this helps you hehehe :)

Step-by-step explanation:

=√256

=√4×4×4×4

=√4^4

=44/2

=4^2

=16

Answer:

B

Step-by-step explanation:

Answer:

Step-by-step explanation:

From the given information:

There are 30 collections of gems, of which 8 are worthless;

Thus, the number of the genuine diamonds = 30 - 8 = 22.

Let X = random variable;

X consider the value as 0 (for  2 worthless stone selection),

X = 1200(1 worthless stone  & 1 genuine stone)

X = 2400 (2 genuine stones selected)

However, the numbers of ways of selecting and chosen Gems can be estimated as:

[tex](^n_r) = (^{30}_2) \\ \\ \implies \dfrac{30!}{2!(30-2)!} \\ \\ \implies \dfrac{30!}{2!(28)!} \\ \\ \implies \dfrac{30*29*28!}{2!(28)!} \\ \\ \implies \dfrac{30*29}{2*1} \\ \\ \implies 435[/tex]

Thus;

[tex]Pr (X = 0) = \dfrac{(^8_2)}{435}[/tex]

[tex]Pr (X = 0) = \dfrac{\dfrac{8!}{2!(8-2)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8!}{2!(6)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8*7*6!}{2!(6)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8*7}{2*1}}{435} \\ \\ Pr (X = 0) = 0.0644[/tex]

[tex]P(X =1200) = \dfrac{(^{8}_{1})(^{22}_{1})}{435}[/tex]

[tex]P(X =1200) = \dfrac{ \dfrac{8!}{1!(8-1)!}) ( \dfrac{22!}{1!(22-1)!}) }{435}[/tex]

[tex]P(X =1200) = \dfrac{ (8) ( 22) }{435}[/tex]

[tex]P(X =1200) =0.4046[/tex]

[tex]Pr (X = 2400) = \dfrac{(^{22}_2)}{435}[/tex]

[tex]Pr (X = 2400) = \dfrac{\dfrac{22!}{2!(22-2)!}}{435} \\ \\ Pr (X = 2400) = \dfrac{\dfrac{22!}{2!(20)!}}{435} \\ \\ Pr (X = 2400) = \dfrac{\dfrac{22*21*20!}{2!(20)!}}{435} \\ \\ Pr (X =2400) = \dfrac{\dfrac{22*21}{2*1}}{435} \\ \\ Pr (X = 2400) = 0.5310[/tex]

To find E(X):

E(X) = (0 × 0.0644) + (1200 × 0.4046)  + (2400 × 0.5310)

E(X) = 0 + 485.52 + 1274.4

E(X) = 1759.92

Answer:

1. S.A. = 4350 cm²

2. S.A. = 864 cm²

3. S.A. = 240 cm²

4. S.A. = 224 m²

5. S.A. = 301.6 in.²

6. S.A. = 6,082.1 cm²

7. S.A. = 923.6 in.²

Step-by-step explanation:

1. Surface area of the rectangular prism = 2(LW + LH + WH)

L = 45 cm

W = 25 cm

H = 15 cm

S.A. = 2(45*25 + 45*15 + 25*15)

S.A. = 4350 m²

2. Surface area of the cube = 6a²

a = 12 cm

S.A. = 6(12²)

S.A. = 864 cm²

3. Surface area of triangular prism = bh + (s1 + s2 + s3)*H

b = 4 cm

h = 6 cm

s1 = 4 cm

s2 = 7 cm

s3 = 7 cm

H = 12 cm

Plug in the values

S.A. = 4*6 + (4 + 7 + 7)*12

S.A. = 24 + (18)*12

S.A. = 24 + 216

S.A. = 240 cm²

4. Surface area of the square based pyramid = area of the square base + 4(area of 1 triangular face)

S.A. = (8*8) + 4[(8*10)/2]

S.A. = 64 + 4(40)

S.A. = 64 + 160

S.A. = 224 cm²

5. Surface area of the cone = πrl + πr²

r = 6 in.

l = 10 in.

S.A. = π*6*10 + π*r²

S.A. = 60π + 36π

S.A. = 301.592895

S.A. = 301.6 in.² (nearest tenth)

6. Surface area of the sphere = 4πr²

r = 22 cm

S.A. = 4*π*22²

S.A. = 1,936π

S.A. = 6,082.1 cm² (nearest tenth)

7. Surface area of the cylinder = 2πrh + 2πr²

r = 7 in.

h = 14 in.

S.A. = 2*π*7*14 + 2*π*7²

S.A. = 923.6 in.² (nearest tenth)

Answer:

Y values will stay the same

Step-by-step explanation:

Reflecting over the Y axis will alter the distance left and right but not up and down. so only Y remains unchanged

Answer:

Yes, it is a right triangle.

Step-by-step explanation:

8²+15²=17²

64+225=289

289=289 YES, it is a right triangle

Answer:

x = 14 for the first one, x = 60 for the second one

Step-by-step explanation:

Step-by-step explanation:

We know the measure of a straight line is 180° . So that ,

> 5x - 10 + 120 = 180

> 5x = 60 + 10

> 5x = 70

> x = 70/5

> x = 14

Solution 2 :-

> x + 50 + 70 = 180

> x = 180 - 120

> x = 60

Answer:

2/4 nd 4/8

Step-by-step explanation:

Extras; 3/6, 5,10, 6/12

Answer:

2/4 and 3/6 .

Step-by-step explanation:

Given :-

We need to write two fractions which equals to 1/2 . For that we can multiply the denominator and numerator by same number .

First equal fracⁿ :-

[tex]:\implies[/tex] 1/2 × 2/2 = 2/4

Second equal fracⁿ :-

[tex]:\implies[/tex] 1/2 × 3/3 = 3/6