Answer:
Bob's home will worth $296,779.25 after 12 years.
Equation used is [tex]FV = $175,000( 1 + 4.5/100)^(12)\\[/tex]
Step-by-step explanation:
Current value of Bob's house =[tex]FV = $175,000( 1 + 4.5/100)^12\\FV = $175,000( (100+ 4.5)/100)^12\\FV = $175,000( (104.5)/100)^12\\FV = $296,779.25[/tex]
market is improving at 4.5% annually.
This, means that the value of house gets appreciated by 4.5% each year from its previous year value.
This is a problem of compound interest formula
[tex]FV = PV(1+r/100)^n[/tex]
where PV is the present value of any thing
FV is the future value
r is the annual rate of interest
t is the time in number of year for which rate is applicable.
_____________________________________
Given
PV = $175,000.
r = 4.5%
t = 12 years
Value after 12 year will be given by
[tex]FV = $175,000( 1 + 4.5/100)^(12)\\FV = $175,000( (100+ 4.5)/100)^(12)\\FV = $175,000( (104.5)/100)^(12)\\FV = $296,779.25[/tex]
Thus, Bob's home will worth $296,779.25 after 12 years.
Equation used is [tex]FV = $175,000( 1 + 4.5/100)^(12)\\[/tex]
How do you do this [tex]||x-3|-2| ≤1[/tex]
8
Express it in slope-intercept form.
6
Enter the correct answer.
OOO
DONE
Clear all
2
6 8
Answer:
I'm confused what's the question ?
FIND THE MISSING LENGTH INDICATED
Answer:
25 units.
Step-by-step explanation:
The first thing we need to do is find the hypotenuse of the triangle with side lengths 12 and 16. 12^2 + 16^2 = 144 + 256 = 400. sqrt(400) = 20. So, the hypotenuse of that triangle is 20 units.
Because the smaller length of the smaller triangle bisects the largest triangle's right angle, the two triangles are similar, with the side length 12 corresponding to the smaller side length of the larger triangle, the side length 16 corresponding to the 20 unit side, and the 20 unit hypotenuse corresponding to x.
Now that we know the triangles are similar, we can construct a proportion...
[tex]\frac{16}{20} =\frac{20}{x}[/tex]
That means that 4/5 = 20/x
1/5 = 5/x
x = 25
Hope this helps!
HELP ASAPPPPP!
What is the value of Fraction 1 over 2x3 + 3.4y when x = 2 and y = 5?
18
20
21
37
(p.s if its easy im in 5th grade dont judge)
Answer:
can you please make the question more clear!
Step-by-step explanation:
i am guessing you are asking if 1/ (2·2) (3+(3.4·5))=
1/ 4+17+3
1/24?
How should you solve the equation x divided by 15 equals 60? What is the resulting equivalent equation? Choose the correct answer below. A. Divide each side by 15. Then simplify. B. Divide each side by 60. Then simplify. C. Multiply each side by 15. Then simplify. D. Multiply each side by x. Then simplify. E. Divide each side by x. Then simplify. F. Multiply each side by 60. Then simplify. The resulting equivalent equation is x=
Answer:
C; x = 900
Step-by-step explanation:
1. Write out the problem: x/15 = 60
2. Multiply each side by 15 to solve for x. This is because of inverse operations, so if you divide x by 15 you have to multiply 15 to both sides. THis way the 15 cancels out in 15(x/15).
3. Equation then becomes this: x = 15*60
4. Answer: 900
5. Substitute to see if you were right. Ask yourself: Does 900 divided by 15 equal 60. If it does, then you are correct.
x^2 + 20x + 28 = 9 find the graphing/vertex form
Answer: [tex](x+10)^2+119=0[/tex]
Step-by-step explanation:
For a quadratic equation, the vertex form is given by : [tex]y=a(x-h)^2+k[/tex], where (h, k) is the vertex.
The given quadratic equation: [tex]x^2 + 20x + 28 = 9[/tex]
Subtract 9 from both sides
[tex]=x^2+20x+19=0[/tex]
compare this to [tex]x^2+bx=c[/tex], and add [tex](\frac{b}{2})^2[/tex] both sides
b= 20
[tex]x^2+20+100+19=-100[/tex] [(b/2)²=20/2=10]
[tex]\Rightarrow\ x^2+2(x)(10)+10^2+119=0[/tex]
[tex]\Rightarrow\ (x+10)^2+119=0\ \ \ [\because\ (a+b)^2=a^2+b^2+2ab][/tex]
So, the vertex form : [tex](x+10)^2+119=0[/tex]
A t-shirt increased in price by 1/7. After the increase it was priced at £56. What was the original price of the t-shirt?
Answer:
£48
Step-by-step explanation:
56 ÷ 7 = £8
56 - 8 = £48
Please let me know if my answer is correct.
Answer:
48
Step-by-step explanation:
On two investments totaling $13,500, Peter lost 3% on one and earned 5 % on the other. If his net annual receipts were $319, how much was each investment?
In how many ways can we put five identical fruits into three bowls? Note that the bowls may be empty.
Answer:
20
Step-by-step explanation:
Given the figure below, find the values of x and z.
Answer:
X= 6°z= 112°Solution,
Finding the value of X,
[tex]11x + 2 = 68[/tex]
( being vertically opposite angles)
[tex]11x = 68 - 2 \\ 11x = 66 \\ x = \frac{66}{11} \\ x = 6[/tex]
Value of X is 6
Now, finding the value of z
[tex]z + 68 = 180[/tex]
(sum of angle in linear pair)
[tex]z = 180 - 68 \\ z = 112[/tex]
Value of z is 112.
Hope this helps....
Good luck on your assignment...
A department store stocks pants and shorts in the colors black and blue. The relative frequency of their orders for blue pants is half the relative frequency of their orders for black shorts. Which two-way frequency table could represent the data from the store's orders?
Answer:
Table 2
Step-by-step explanation:
The question is to identify the table where the relative frequency of orders for blue pants is half the relative frequency of their orders for black shorts.
We are interested in the number of blue pants and black shorts.
If we name them as p and b respectively, then we are looking for a table where s/p=2
Let's verify relevant data in all tables:
Table 1:
p= 82, s= 41 ⇒ s/p= 41/82 ≠ 2, no, not this oneTable 2:
p= 57, s= 114 ⇒ s/p= 114/57 = 2, yes, it is the oneTable 3:
p= 78, s= 110 ⇒ s/p= 110/78 ≠ 2, no, not this oneTable 4:
p= 44, s= 150 ⇒ s/p= 150/44 ≠ 2, no, not this oneSo only one of tables- the second one from top represents the required data.
Answer:
The second table
Step-by-step explanation:
I did the test.
Which of the points are solutions to the inequality?
Check all that apply.
O (-2,-5)
0 (0.-4)
(1.1)
(3.5)
D (5.5
Answer:
A, C and D
Step-by-step explanation:
The missing inequality is:
y > 2x -4
To verify if a point is a solution, replace x into the equation, compute y, and see their relationship.
Option A: (-2,-5)
2(-2) -4 = -8
y = -5 > -8
then, the point is solution
Option B: (0,-4)
2(0) -4 = -4
y = -4 = -4
then, the point is not solution
Option C: (1,1)
2(1) -4 = -2
y = 1 > -2
then, the point is solution
Option D: (3,5)
2(3) -4 = 2
y = 5 > 2
then, the point is solution
Option E: (5,5)
2(5) -4 = 6
y = 5 < 6
then, the point is not solution
Which of the following are reasons used in the proof that the angle-bisector construction can be used to bisect any angle?
Check all that apply
A. Any Line segment can be extended indefinitely
B. All of the radii of a circle are congruent
C .CPCTC
D. SSS triangle congruence postulate
Answer: B C D
Step-by-step explanation:
just answered it for AP3X
Reasons used in the proof that the angle-bisector construction can be used to bisect any angle are as follows:
B. All of the radii of a circle are congruent
C .CPCTC
D. SSS triangle congruence postulate
What is angle bisector ?" Angle bisector is defined as the ray which divides the angle into two equal parts."
According to the question,
A. Any Line segment can be extended indefinitely is not required to bisect any angle .
Therefore , it is not a correct option.
B. All of the radii of a circle are congruent : To bisect an angle draw an arc with same radii is used in constructing an angle bisector .
Therefore , Option B is a correct option.
C. CPCTC : Corresponding parts of a congruent triangle are congruent is required to proof angle bisector. As it proofs two triangles are congruent.
Therefore, Option C is the correct option.
D. SSS triangle congruence postulate : It is required an important step to prove that two triangles are congruent which imply proof of angle - bisector construction.
Therefore, Option D is the correct option.
Hence, Option B, Option C , Option D are the correct answer.
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If you're good at trigonometry please help me with question nine a and b and show full working out tyyyyyyyy ;)
Problem 9, part a)
Compass bearings always have north as the starting point. This is where 0 degrees is situated, and 360 degrees as well. As the bearing angle increases, you'll turn to the right toward the eastward direction. Effectively you're sweeping out a clockwise rotation. The bearing 322 degrees is in a northwest position as the diagram shows (place the ship at the bottom right corner of the triangle). The bottom right acute angle of the triangle is 322 - 270 = 52 degrees. This is the reference angle we'll use for finding the distance d.
With respect to the reference angle of 52 degrees, the side 18.5 is the opposite side and d is the adjacent side. Use the tangent ratio to get...
tan(angle) = opposite/adjacent
tan(52) = 18.5/d
d*tan(52) = 18.5
d = 18.5/tan(52)
d = 14.4537840903742
The approximate value of d is 14.4537840903742 km
This rounds to 14.5 when rounding to one decimal place.
Answer: 14.5 km=======================================================
Problem 9, part b)
Recall that
distance = rate*time
where "rate" is another term for "speed" or "velocity"
We can solve this for the time to get
time = distance/rate
------
We found the distance back in part a) above. We are given the rate of 48 km/h
So,
time = distance/rate
time = 14.4537840903742/48
time = 0.3011205018828
This is the time it takes in hours. Multiply by 60 to convert to minutes
0.3011205018828 hours = 60*0.3011205018828 = 18.067230112968 minutes
This rounds to the whole number 18
Answer: 18 minutes The functions f(x) and g(x) are shown on the graph.
Rx) = x²
What is g(x)?
simplify the expression [tex]-\frac{4x+7}{2} -\frac{3x-2}{2}[/tex]
Answer:
-(4x + 7)/2 - (3x - 2)/2 = (-4x - 7 - 3x + 2)/2 = (-7x - 5)/2
plzzzzz answer this question about density mass and volume!!!!!!!!!
Answer:
13.896 kg
Step-by-step explanation:
You can find the mass of the bar by first finding the volume.
V = BH
where B = area of the base (the trapezium), and
H = height (distance trapezium between bases)
The area of a trapezium is
A = (b1 + b2)h/2
where b1 and b2 are the lengths of the bases of the trapezium (the parallel sides), and
h = the altitude of the trapezium (distance between the bases of the trapezium)
V = (b1 + b2)h/2 * H
V = (12 cm + 6 cm)(5 cm)/2 * 16 cm
V = 720 cm^3
The volume of the bar is 720 cm^3.
Now we use the density and the volume to find the mass.
density = mass/volume
mass = density * volume
mass = 19.3 g/cm^3 * 720 cm^3
mass = 13,896 g
Now we convert grams into kilograms.
1 kg = 1000 g
mass = 13,896 g * (1 kg)/(1000 g)
mass = 13.896 kg
Answer: 1.3896 kg
Help pleaseeeeeeeeeeeeeeeeeeeeeee
Answer:
The answer is 3 mark as brainliest
Step-by-step explanation:
3 *3-4*4+2*5
9-16+10
9-6=
3
Answer:
Hey there!
3a-4b+2c
3(3)-4(4)+2(5)
9-16+10
3
Your answer would be 3.
Hope this helps :)
From the equation, find the axis of symmetry of the parabola.
y = 4x+ 32x+ 61
a. x= 3
x=-4
C.
b. X= 4
d. X=-3
A triangles angle measures are in the ratio 3: 4: 7. Find the measures of the angles
Step-by-step explanation:
total ratio = 3+4+7 = 14
3/14×180= 38.57°
4/14×180= 51.43°
7/14×180 = 90°
Answer:
total ratio = 3+4+7 = 14
3/14×180= 38.57°
4/14×180= 51.43°
7/14×180 = 90°
Step-by-step explanation:
PLEASE HELP Order these numbers from least to greatest. 2 1/10, 61/10, 3.122, 3.19
Answer: 2 1/10, 3.122, 3.19, 61/10
Step-by-step explanation:
Let's first turn each number into decimal form: (1/10=.1, 2/10=.2,etc.)
2.1, 6.1, 3.122, 3.19. Obviously, the smallest number is 2.1, because it has a 2 in the ones place. Next, we see a tie in the ones place between 3.122 and 3.19. Then we look at the tenths place and see another tie. Then, at the hundredths place, we see that 3.19 is greater that 3.122. Thus, the order of the numbers is 2.1,3.122,3.19,6.1.
Hope it helps <3
A rectangular wall has length 3 less than 4 times the width . I wish to put a silver line along the corners of the wall. The lining costs 25 cents per foot and I spent a total of $18.50 for the lining on the corners of the wall. If painting costs 20 cents per square foot , how much dose it cost to paint the wall? PLEASE ANSWER correctly. I WILL GIVE BRAINLIEST ANSWER TO U IF U DO
Answer:
Step-by-step explanation:
Let width = w units
Length = 4w - 3
Cost for lining corners of wall = $ 18.50
Perimeter of the wall = 18.50/0.25 = 74 ft
2*(length +width ) = 74
2*(4w - 3 + w) =74
2*(5w - 3) =74
10w - 6 = 74 {Add 6 to both sides}
10w - 6 + 6 = 74 + 6
10w = 80
Divide both sides by 10
10w/10 = 80/10
w = 8 ft
Length = 4w - 3 = 4*8 - 3 = 32 - 3
Length = 29 ft
Area of the wall = length * width
= 29 * 8
= 232 square ft
Cost of painting the wall per square feet = 20 cents = 0.20
Cost of painting 232 square feet = 232 * 0.20
= $ 46.40
Dan must choose a shirt, a pair of pants, and a cap for today's outfit. He has 2 shirts, 2 pairs of pants, and 3 caps to choose from. How many different outfits can he make?
Answer:
12 different outfits
Step-by-step explanation:
2 x 2 x 3 = 12 outfits.
Answer:
12
Step-by-step explanation:
He has 2 possibilities for a shirt, 2 possibilities for a pant, and 3 possibilities for a cap. You just multiply them together:
2 * 2 * 3 = 12 outfits
The endpoints of CD¯¯¯¯¯¯¯¯ are C(−8,−6) and D(−4, 10). The coordinates of the midpoint M of CD¯¯¯¯¯¯¯¯ are ( , ).
Answer:
m(-6,2)
Step-by-step explanation:
m=(-8+-4/2,-6+10/2)
=(-12/2,4/2)
=(-6,2)
The coordinates of the midpoint M of CD of the line segment CD with endpoints, C(−8,−6) and D(−4, 10), are (-6,2).
What is midpoint?For a line segment, mid-point is the middle point of it which divides the line segment into the two equal parts.
The formula to find the midpoint using the coordinates of the line is,
[tex]m=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)[/tex]
Here, (x1,y1) and (x2,y2) are the coordinates of the endpoints of the line.
The endpoints of CD are C(−8,−6) and D(−4, 10). To find the coordinates of the midpoint M, put the values in the above formula as,
[tex]m=\left(\dfrac{-8+(-4)}{2},\dfrac{-6+10}{2}\right)\\m=\left(\dfrac{-12}{2},\dfrac{4}{2}\right)\\m=\left(-6,2)[/tex]
Thus, the coordinates of the midpoint M of CD of the line segment CD with endpoints, C(−8,−6) and D(−4, 10), are (-6,2).
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You are making a welding fixture and must cut down a length of copper tubbing from 15 1/8 inches to 8 3/4 inches. If the leftover piece is long enough, you will use it in another fixture . How long will the leftover piece be ? 23 and 7/8 1 and 51/70 7 and 1/8 6 3/8
Answer: [tex]6\dfrac{3}{8}\text{ inches}[/tex]
Step-by-step explanation:
Given: Original length = [tex]15\dfrac{1}{8}[/tex] inches
[tex]=\dfrac{8\times15+1}{8}=\dfrac{121}{8}[/tex] inches ( In improper fraction )
Length of piece cut from original = [tex]8\dfrac{3}{4}[/tex] inches
[tex]=\dfrac{4\times8+3}{4}[/tex][tex]= \dfrac{35}{4}[/tex] inches ( In improper fraction )
Length of piece leftover piece = (Original length ) - (Length of piece cut )
[tex]=\dfrac{121}{8}-\dfrac{35}{4}\\\\=\dfrac{121-2\times35}{8}\\\\=\dfrac{121-70}{8}\\\\=\dfrac{51}{8}\\\\=6\dfrac{3}{8}\text{ inches}[/tex]
Hence, the leftover piece will be [tex]6\dfrac{3}{8}\text{ inches}[/tex] long.
I need help with number 5
Answer:
A
Step-by-step explanation:
62 +65=127
C+127=180
C=180-127=53°
so x=53°
53-y=11
y=53-11=42
Answer: A
Step-by-step explanation:
Since ΔCDE and ΔGHI are congruent triangles, they are equal to each other. This means x-y=11. We want to find y, but we first need to find x. We can do that by finding x° on ΔGHI.
We know that the sum of the angles is 180° in a triangle. We are given 2 angles from ΔCDE. We can use those to find x°.
62+65+x=180 [combine like terms]
127+x=180 [subtract 127 on both sides]
x=53
Now that we have x, we can find y by plugging in.
53-y=11 [subtract both sides by 53]
-y=-42 [divide both sides by -1]
y=42
Three tins, A, B and C, each contain buttons.
Tin A contains x buttons.
Tin B contains 4 times the number of buttons that tin A contains.
Tin C contains 7 fewer buttons than tin A.
The total number of buttons in the three tins is 137
Work out the number of buttons in tin C.
The number of buttons in C is 17 buttons
What is an Equation?
Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the three tins be A , B and C respectively
The number of buttons in tin A = x
The number of buttons in tin B = 4 times the number of buttons in tin A
= 4x
The number of buttons in tin C = 7 fewer buttons than tin A
= x - 7
The total number of buttons in tin A , tin B and tin C together = 137 buttons
So , the total number of buttons =
number of buttons in tin A + number of buttons in tin B + number of buttons in tin C
So , the equation will be
Total number of buttons = x + 4x + ( x - 7 )
x + 4x + ( x - 7 ) = 137
6x - 7 = 137
Adding 7 on both sides , we get
6x = 144
Divide by 6 on both sides , we get
x = 24 buttons
So , the number of buttons in tin A is 24 buttons
So , number of buttons in tin B = 4 x 24
= 96 buttons
Therefore , the number of buttons in tin C = 17 buttons
Hence , the number of buttons in tin C is 17 buttons
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A recent survey found that 65% of high school students were currently enrolled in a math class,43% were currently enrolled in a science class,and 13% were enrolled in both a math and a science class. Suppose a high school student who is enrolled in a math class is selected at random. What is the probability that the student is also enrolled in a science class?
Answer: 0.20
Step-by-step explanation:
As per given :
P(student enrolled in a math class ) = 65% = 0.65
P( student enrolled in a science class) = 43%= 0.43
P( student enrolled in both ) = 13% = 0.13
Formula of conditional probability :
[tex]P(A|B)=\dfrac{P(A\text{ and }B)}{P(B)}[/tex]
Using the above formula,
The probability that the student is enrolled in a science class given that he is enrolled in maths class :
[tex]P(\text{science}|\text{math})=\dfrac{P(\text{science and maths})}{P(\text{math})}\\\\=\dfrac{0.13}{0.65}\\\\=\dfrac{13}{65}\\\\=\dfrac{1}{5}=0.20[/tex]
Hence, the probability that the student is also enrolled in a science class = 0.20 .
Find the common difference for the sequence shown.
56, 49, 42, 35, ...
0-12
0-7
07
To find the common difference, subtract all the numbers in order.
56 - 49 = 7
49 - 42 = 7
42 - 35 = 7
Therefore, common difference is 7.
Best of Luck!
Answer:
The answer is -7
(got this answer right on the lesson)
Step-by-step explanation:
A math class consists of 25 students, 14 female and 11 male. Three students are selected at random to participate in a probability experiment. Compute the probability that a. a male is selected, then two females. b. a female is selected, then two males. c. two females are selected, then one male. d. three males are selected. e. three females are selected.
Answer:
(a) The probability that a male is selected, then two females is 0.4352.
(b) The probability that a female is selected, then two males is 0.3348.
(c) The probability that two females are selected, then one male is 0.4352.
(d) The probability that three males are selected is 0.0717.
(e) The probability that three females are selected is 0.1583.
Step-by-step explanation:
We are given that a math class consists of 25 students, 14 female and 11 male. Three students are selected at random to participate in a probability experiment.
(a) The probability that a male is selected, then two females is given by;
Number of ways of selecting a male from a total of 11 male = [tex]^{11}C_1[/tex]
Number of ways of selecting two female from a total of 14 female = [tex]^{14}C_2[/tex]
Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]
So, the required probability = [tex]\frac{^{11}C_1 \times ^{14}C_2}{^{25}C_3}[/tex]
= [tex]\frac{\frac{11!}{1! \times 10!} \times \frac{14!}{2! \times 12!} }{\frac{25!}{3! \times 22!} }[/tex] {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }
= [tex]\frac{1001}{2300}[/tex] = 0.4352
(b) The probability that a female is selected, then two males is given by;
Number of ways of selecting a female from a total of 14 female = [tex]^{14}C_1[/tex]
Number of ways of selecting two males from a total of 11 male = [tex]^{11}C_2[/tex]
Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]
So, the required probability = [tex]\frac{^{14}C_1 \times ^{11}C_2}{^{25}C_3}[/tex]
= [tex]\frac{\frac{14!}{1! \times 13!} \times \frac{11!}{2! \times 9!} }{\frac{25!}{3! \times 22!} }[/tex] {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }
= [tex]\frac{770}{2300}[/tex] = 0.3348
(c) The probability that two females is selected, then one male is given by;
Number of ways of selecting two females from a total of 14 female = [tex]^{14}C_2[/tex]
Number of ways of selecting one male from a total of 11 male = [tex]^{11}C_1[/tex]
Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]
So, the required probability = [tex]\frac{^{14}C_2 \times ^{11}C_1}{^{25}C_3}[/tex]
= [tex]\frac{\frac{14!}{2! \times 12!} \times \frac{11!}{1! \times 10!} }{\frac{25!}{3! \times 22!} }[/tex] {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }
= [tex]\frac{1001}{2300}[/tex] = 0.4352
(d) The probability that three males are selected is given by;
Number of ways of selecting three males from a total of 11 male = [tex]^{11}C_3[/tex]
Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]
So, the required probability = [tex]\frac{^{11}C_3}{^{25}C_3}[/tex]
= [tex]\frac{ \frac{11!}{3! \times 8!} }{\frac{25!}{3! \times 22!} }[/tex] {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }
= [tex]\frac{165}{2300}[/tex] = 0.0717
(e) The probability that three females are selected is given by;
Number of ways of selecting three females from a total of 14 female = [tex]^{14}C_3[/tex]
Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]
So, the required probability = [tex]\frac{^{14}C_3}{^{25}C_3}[/tex]
= [tex]\frac{ \frac{14!}{3! \times 11!} }{\frac{25!}{3! \times 22!} }[/tex] {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }
= [tex]\frac{364}{2300}[/tex] = 0.1583
(a) The probability that a male is selected, then two females is 0.4352.
(b) The probability that a female is selected, then two males is 0.3348.
(c) The probability that two females are selected, then one male is 0.4352.
(d) The probability that three males are selected is 0.0717.
(e) The probability that three females are selected is 0.1583.