Draw the structural formula for 3-ethyl-3-methyl-1-pentyne. Click the "draw structure" button to launch the drawing utility.

Answer:

Explanation:

The density of carbon tetrachloride can be found by using the formula

From the question

Volume = 225 mL

To find the mass of carbon tetrachloride in the flask subtract the mass of the flask from the total mass of the flask and carbon tetrachloride

That's

mass of carbon tetrachloride =

703.55 - 345.8

= 357.75 g

Substitute the values into the above formula and solve for the density

That's

We have the final answer as.

Density = 1.59 g/mL

Hope this helps you

Answer:

236588

Explanation:

1000 x 237 for an approx. amount

Answer:

236.588 mL in 1 cup.

Explanation:

For this problem, you must know that 1 cup is equal to 8 ounces and that 1 ounce is 29.5735 mL.  Using this information, let' perform the conversion.

1 cup * ( 8 oz / 1 cup ) * ( 29.5735 mL / 1 oz) == ? mL

( 1 cup * 8 oz * 29.5735 mL ) / ( 1 cup * 1 oz) == ? mL

236.588 mL == ? mL

Hence, there are 236.588 mL in 1 cup.

Cheers.

Answer:

a) HCN and NaCN

Explanation:

Buffer solution is made by mixing either a weak base and its salt like ammonia and ammonium chloride or weak acid and its salt like HCN and its salt NaCN or acetic acid and sodium acetate .

In the given option , all of the rest of option has either strong acid or strong base or both  . In the last option both are salt so it can not form buffer solution .

It is capable of keeping the pH of the solution constant .

Answer:

[tex]24540\frac{mg}{m^3}[/tex]

Explanation:

Hello,

In this case, since the 3% by volume is represented as:

[tex]\frac{3L\ CO}{L\ gas}[/tex]

By using the ideal gas equation we compute the density of CO:

[tex]\rho =\frac{MP}{RT} =\frac{28g/mol*1atm}{0.082\frac{atm*L}{mol*K}*298K}= 0.818g/L[/tex]

Then we apply the conversion factors as follows:

[tex]=\frac{3L\ CO}{100L\ gas}*\frac{0.818g\ CO}{1L\ CO} *\frac{1000mg\ CO}{1g\ CO} *\frac{1000L\ gas}{1m^3\ gas} \\\\=24540\frac{mg}{m^3}[/tex]

Regards.

Answer:

6. (2.7*[tex]10^{5}[/tex])

8. (1.0*[tex]10^{4}[/tex])

Explanation:

Answer:

Dual nature of matter is an important concept in JEE physics and is basically the study of different nature that a matter possesses or exhibits. ... Hence, the matter is said to possess dual nature, i.e., it has both the properties of a particle and as well as a wave.

Lowest - Producer - plants (mostly)

They get food by converting sunlight into nutrients

Middle - Consumer - example animals

They eat other living things such as plants or other animals for their nutrients

Top - Decomposer - bacteria/microorganisms

They decompose dead body

sorry if im wrong

Answer:

the answer is B the particles are not chemically bonded, they can only be combined in a certain set ratios

Explanation:

Answer:

1) The order of the reaction is of FIRST ORDER

2)   Rate constant k = 5.667 × 10 ⁻⁴

Explanation:

From the given information:

The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically.

liquid-phase reaction 2A - B signifies that the reaction is of FIRST ORDER where the rate of this reaction is directly proportional to the concentration of A.

The following data was obtained:

t/min                    0         10         20          30             40          ∞

conc B/(mol/L)    0       0.089    0.153     0.200       0.230    0.312

For  a first order reaction:

[tex]K = \dfrac{1}{t} \ In ( \dfrac{C_{\infty} - C_o}{C_{\infty} - C_t})[/tex]

where :

K = proportionality  constant or the rate constant for the specific reaction rate

t = time of reaction

[tex]C_o[/tex] = initial concentration at time t

[tex]C _{\infty}[/tex] = final concentration at time t

[tex]C_t[/tex] = concentration at time t

To start with the value of t when t = 10 mins

[tex]K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 - 0}{0.312 - 0.089})[/tex]

[tex]K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 }{0.223})[/tex]

[tex]K_1 =0.03358 \ min^{-1}[/tex]

[tex]K_1 \simeq 0.034 \ min^{-1}[/tex]

When t = 20

[tex]K_2= \dfrac{1}{20} \ In ( \dfrac{0.312 - 0}{0.312 - 0.153})[/tex]

[tex]K_2= 0.05 \times \ In ( 1.9623)[/tex]

[tex]K_2=0.03371 \ min^{-1}[/tex]

[tex]K_2 \simeq 0.034 \ min^{-1}[/tex]

When t = 30

[tex]K_3= \dfrac{1}{30} \ In ( \dfrac{0.312 - 0}{0.312 - 0.200})[/tex]

[tex]K_3= 0.0333 \times \ In ( \dfrac{0.312}{0.112})[/tex]

[tex]K_3= 0.0333 \times \ 1.0245[/tex]

[tex]K_3 = 0.03412 \ min^{-1}[/tex]

[tex]K_3 = 0.034 \ min^{-1}[/tex]

When t = 40

[tex]K_4= \dfrac{1}{40} \ In ( \dfrac{0.312 - 0}{0.312 - 0.230})[/tex]

[tex]K_4=0.025 \times \ In ( \dfrac{0.312}{0.082})[/tex]

[tex]K_4=0.025 \times \ In ( 3.8048)[/tex]

[tex]K_4=0.03340 \ min^{-1}[/tex]

We can see that at the different time rates, the rate constant of [tex]k_1, k_2, k_3, and k_4[/tex] all have similar constant values

As such :

Rate constant k = 0.034 min⁻¹

Converting it to seconds ; we have :

60 seconds = 1 min

∴

0.034 min⁻¹ =(0.034/60) seconds

= 5.667 × 10 ⁻⁴ seconds

Rate constant k = 5.667 × 10 ⁻⁴

Answer:

Be the anode

Explanation:

The standard hydrogen electrode is regarded as the standard reference electrode and it has been assigned an electrode potential of 0.0V.

If any substance has an electrode potential that is more negative than hydrogen, then that half cell will function as the anode when connected to the standard hydrogen electrode.

Similarly, any substance that has a more positive electrode potential than hydrogen will serve as the cathode when its half cell is connected to the standard hydrogen electrode.

Answer:

20g gas contains and this so allow in tha 36G in per laar

Explanation:

Answer:

No

Explanation:

A white dwarf has a higher surface temperature than a red giant.

Answer:

Kindly check explanation

Explanation:

pm = picometer

Radius of platinum atom = 139 pm

1 pm = 1 × 10^-12 m

Hence,

139 pm = 139 × 10^-12 m

1 pm = 1 × 10^-10 cm

Hence,

139 pm = 139 × 10^-10 cm

B) mass of a single platinum atom = 3.24 × 10²² g

To obtain the diameter of 1 platinum atom in cm:

139 × 10^-10 cm

Number of atoms required :

48.1 cm / 1.39 × 10^-8 cm = 34.60 × 10^8 atoms

Mass in gram of P(t) :

(3.24 × 10²²) × (34.60 × 10^8) = 112.117 × 10^(22+8)

= 112.12 × 10^30 g

C) density (d) = 21.4 g/cm^3, diameter = 1.50 mm

V = πr^2h

h = 48.1cm ; r = 1.5 / 2 = 0.75 mm = 0.075cm

Density = mass / volume

Volume = π * 0.075^2 * 48.1 = 0.8499971cm³

Mass = density × volume

Mass = 21.4g/cm³ × 0.8499971cm³

= 18.19g

Answer:

pH = 12.35

Explanation:

The HCl reacts with NaOH, thus:

HCl + NaOH → NaCl + H₂O

1 mole of HCl reacts per mole of NaOH

To know the pH we must know the moles of NaOH and the moles of HCl that reacts

Moles NaOH and HCl

NaOH: 0.0280L * (0.230mol / L) = 6.44x10⁻³ moles

HCl: 0.0230L * (0.230mol / L) = 5.29x10⁻³

As moles NaOH > Moles HCl, the moles that remains of NaOH are:

Moles NaOH = 6.44x10⁻³ - 5.29x10⁻³ = 1.15x10⁻³ moles NaOH = Moles OH⁻

In 23.0mL + 28.0mL = 51.0mL = 0.0510L:

1.15x10⁻³ moles OH⁻ / 0.0510L =

0.0225M OH⁻

pOH = -log [OH⁻]

pOH = 1.647

And pH = 14 - pOH

Answer:

17.5609g

Explanation:

According to the question, a sample of mass 6.814 grams is added to another sample weighing 0.08753 grams. That is weight of sample 1 + weight of sample 2;

6.814 + 0.08753 = 6.90153grams

Next, the subsequent mixture is then divided into exactly 3 equal parts i.e. 6.90153grams divided by 3

= 6.90153/3

= 2.30051grams.

One of the equal parts is 2.30051grams, which is then multiplied by 7.6335 times I.e. 2.30051 × 7.6335 = 17.5609grams

Therefore, the final mass is 17.5609grams

Answer:

2,4-dinitrophenol

Explanation:

A hydrophobic molecule does not dissolve nor mix with water. The cell membranes are made up of hydrophobic lipids. Hence, hydrophobic molecules easily pass through the cell membrane.

Glucose is partly hydrophilic hence it is transported across the cell membrane by special proteins. However, 2,4-dinitrophenol is a hydrophobic molecule thus it is easily transported across the cell membrane.

Answer:

1.52 g/mL

Explanation:

The formula for finding the density of an object is d = m/v, or density = mass divided by volume.

Therefore, we can input the two values and solve for d.

d = 220/145

d = 44/29

d ≈ 1.52 g/mL

Answer:

Black

Explanation:

Answer:

[tex]pH=4.1[/tex]

Explanation:

Hello,

In this case, for a concentration of 0.42 M of benzoic acid whose Ka is 6.3x10⁻⁵ in 0.33 M sodium benzoate, we use the Henderson-Hasselbach equation to compute the required pH:

[tex]pH=pKa+log(\frac{[base]}{[acid]} )[/tex]

Whereas the concentration of the base is 0.33 M and the concentration of the acid is 0.42 M, thereby, we obtain:

[tex]pH=-log(Ka)+log(\frac{[base]}{[acid]} )\\\\pH=-log(6.3x10^{-5})+log(\frac{0.33M}{0.42M} )\\\\pH=4.1[/tex]

Regards.

Answer:

There are three types of DNA Mutations: base substitutions, deletions and insertions. Single base substitutions are called point mutations, recall the point mutation Glu -----> Val which causes sickle-cell disease. Point mutations are the most common type of mutation and there are two types.

Answer:

Explanation:

Lithium, Potassium and Sodium follow each other in that order when it comes to reactivity.

Succinctly put, Lithium is the most reactive. Potassium is more reactive and Sodium is the least reactive.

Also, for Calcium, Strontium and Barium. It is the least reactive in this order.

Strontium, Barium, Calcium

That is, Strontium is more reactive than Barium, which is more reactive than Calcium. Calcium is the least reactive of the 3

Answer:

Nothing has full knowledge of the world.

Senses can deceive us - science only provides us with an incomplete picture of the world.

Scientists can never be completely unbiased.

Science isn't free from error.

No way of knowing what is real - some things could be illusions

Explanation:

Answer:

A. The neutral-charged neutrons and positive-charged protons are found within the nucleus, and the negative-charged electrons orbit outside the nucleus of the atom.

Explanation:

An atom basically consists of three sub atomic particles. They are; Neutrons, Electrons and Protons.

The Electrons are negatively charged and can be found outside the nucleus of the atom,

The Protons are positively charged and can be found in the nucleus of an atom.

The Neutrons are neutral in terms of charged and can be found in the nucleus along with the protons.

The option that is correct is;

A. The neutral-charged neutrons and positive-charged protons are found within the nucleus, and the negative-charged electrons orbit outside the nucleus of the atom.

The numbers in scientific notation are 291.7 = 2.917 × 10₂ and 0.0960 = 9.60 × 10⁻².

Scientific notation is commonly used in scientific and mathematical calculations, as well as when dealing with very large or very small numbers. It allows for a more compact and manageable representation of these numbers.

To write the numbers in scientific notation, we need to express them in the form of "a × 10^b," where "a" is a number between 1 and 10, and "b" is an integer.

For the number 291.7, write it in scientific notation as:

291.7 = 2.917 × 10²

For the number 0.0960, write it in scientific notation as:

0.0960 = 9.60 × 10⁻²

To learn more about scientific notation, follow the link:

https://brainly.com/question/19625319

#SPJ6

Answer:

Fractional distillation and HP-LC

Explanation:

This is a technique useful for analytes with close boiling points. Any alcohol-ester azotopes can be further refined using high-performance liquid chromatography (HP-LC) column.

Answer:

b and c

Explanation:

the problem was solved through the experiment and tested

Answer:

0.119 g/cm³

Explanation:

Step 1: Given data

Mass of the cube (m): 1.75 g

Side measure (l): 2.45 cm

Step 2: Calculate the volume of the cube

We will use the following expression.

V = l³

V = (2.45 cm)³

V = 14.7 cm³

Step 3: Calculate the density (ρ) of the cube

The density of the cube is equal to its mass divided by its volume.

ρ = m/V

ρ = 1.75 g/14.7 cm³

ρ = 0.119 g/cm³

Answer:

H2O- Hydrogen bonding, dipole dipole, and dispersion

CH4- Dispersion only

CO- Dispersion only

CH2Cl- Dipole dipole and dispersion only

Explanation:

Dipole- dipole interactions exist only in molecules that have a dipole moment such as water and dichloromethane. Water experiences intermolecular hydrogen bonding in addition to dipole-dipole interaction and dispersion forces due to the O-H bond in the molecule.

Nonpolar compounds only have dispersion forces acting between its molecules.

Explanation:

Find out more information about dispersion here:

https://brainly.com/question/3224009

The correct answer is B. Dangerous

Explanation:

The NFPA diamond is used to show how safe or dangerous a substance or material is based on four main categories: Health (blue), Flammability (red), Instability (yellow), special hazards (white). Moreover, the three first hazards are expressed using numbers from 0 to 4, in which 0 means no hazard while 4 is the most dangerous category. For example, in the health square finding 0 means the substance represents no hazard for health, while 4 means the substance is lethal. This means the higher the number in this diamond, the most dangerous the substance is.

Answer:

lower than the separate atoms. Because an electron in this molecular orbital is strongly attracted to both nuclei, the electron is more stable (at lower energy) than it is in the 1s orbital of the hydrogen atom. Because it concentrates electron density between the nuclei, the bonding molecular orbital holds the atoms together in a covalent bond.