Answer:
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Answer:
hi
Explanation:
hi
What is the v if lambda = 8m and f = 20Hz
Wave speed (v) will be 160 m/s
What is Wave speed ?Wave speed is the distance the wave travels in a given amount of time, such as the number of meters it travels per second or Wave speed is the distance travelled by a wave per unit time. It is the speed with which a disturbance of the particle like a crest/ trough, compression / rarefaction propagates through a medium. Its SI unit is m/s.
The Wave speed formula which involves wavelength and frequency is given by: v = f λ Where, v is the velocity of the wave and f is the frequency of the wave.
Wave is a disturbance in which there is a transfer of energy from place to place. The particles of the medium vibrate during wave propagation. In the transverse wave, the particles vibrate up and down and are perpendicular to the direction of wave propagation. In a longitudinal wave, the particles vibrate along the direction of wave propagation.
wave speed = frequency * wavelength
= 20 * 8 = 160 m/s
wave speed is 160 m/s
To learn more about wave speed here
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A person is 88 J of work lifting a grocery bag straight off the ground to a height of 1.7 m what is a grocery bags mass
Answer:
5.277 kg
Explanation:
Since the formula for work is W = F * d and we are given distance and work, the force on the grocery bag is 88 = F * 1.7 F = 88 / 1.7 = 51.765 N.
We also know that force follows the equation F = m * a. Since the constant gravitational acceleration on earth is 9.81 m / s^2, we can find the mass through 51.765 = m * 9.81 m = 51.765/9.81 = 5.277 kg
A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 5.00 m at constant speed. If the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do
Answer:
1568 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 80 Kg
Distance (d) = 5 m
Coefficient of kinetic friction (μ) = 0.4
Workdone (Wd) =?
Next, we shall determine the normal reaction. This can be obtained as follow:
Mass (m) = 80 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (N) =?
N = mg
N = 80 × 9.8
N = 784 N
Next, we shall determine force of friction. This can be obtained as follow:
Coefficient of kinetic friction (μ) = 0.4
Normal reaction (N) = 784 N
Force of friction (F) =?
F = μN
F = 0.4 × 784
F = 313.6 N
Finally, we shall determine the work done. This can be obtained as follow:
Distance (d) = 5 m
Force of friction (F) = 313.6 N
Workdone (Wd) =?
Wd = F × d
Wd = 313.6 × 5
Wd = 1568 J
Thus, the workdone is 1568 J
A man has 887.5 J of kinetic energy while running with a velocity of 5 m/s. What is his mass?
Answer:
The mass of the man is 71 kg
Explanation:
Given;
kinetic energy of the man, K.E = 887.5 J
velocity of the man, v = 5 m/s
The mass of the man is calculated as follows;
K.E = ¹/₂mv²
where;
m is the mass of the man
2K.E = mv²
m = 2K.E / v²
m = (2 x 887.5) / (5)²
m = 71 kg
Therefore, the mass of the man is 71 kg
Water in an electric teakettle is boiling. The power absorbed by the water is 0.90 kW. Assuming that the pressure of vapor in the
kettle equals atmospheric pressure, determine the speed of effusion of vapor from the kettle's spout if the spout has a cross-
sectional area of 1.60 cm2. Model the steam as an ideal gas.
Answer:
v = 4.233 m/s
Explanation:
By applying the rate of boiling from [tex]Q= mL_v[/tex];
the rate of the boiling can be described as:
[tex]\mathcal{P} = \dfrac{Q}{\Delta t} \\ \\ \mathcal{P} = \dfrac{mL_v}{\Delta t}[/tex]
The mode of the steam (water vapor) as an ideal gas can be illustrated by formula:
[tex]P_oV_o = nRT[/tex] --- (1)
where;
n = number of moles;
[tex]n = \dfrac{mass (m)}{Molar mass (M)}[/tex]
Then; equation (1) can be rewritten as:
[tex]P_oV_o = (\dfrac{m}{M}) RT \\ \\ \dfrac{P_oV}{\Delta T} = \dfrac{m}{\Delta t} ( \dfrac{RT}{M})[/tex]
∴
[tex]\dfrac{m}{\Delta t} = \dfrac{\mathcal{P}}{L_v}[/tex]
Then:
[tex]P_o \times A \times v= \dfrac{\mathcal{P}}{L_v}\Big ( \dfrac{RT}{M }\Big)[/tex]
making (v) the subject of the formula:
[tex]v= \Big ( \dfrac{\mathcal{P} RT}{M\times L_v \times P_o \times A }\Big)[/tex]
Given that:
[tex]\mathcal{P}[/tex] = 0.90 kW = 900 W
R(rate constant) = 8.314 J/mol.K
Temperature at 100° C = 373K
For water vapor:molar mass= 18.015 g/mol ≅ 0.0180 kg/mol
Latent heat of vaporisation [tex]L_v[/tex] = 2.26 × 10⁶ J/kg
Atmospheric pressure [tex]P_o = 1.013 \times 10^6 \ N/m^2[/tex]
Cross sectional area A =1.60 cm² = 1.60 × 10⁻⁴ m²
[tex]v= \Big ( \dfrac{900 W (8.314 \ J/mol.K)(373)}{0.0180 \ kg/mol) (2.26 \times 10^6 \ J/kg) (1.013 \times 10^5 \ N/m^2)(1.60 \times 10^{-4} \ m^2)}\Big)[/tex]
v = 4.233 m/s
9.Water flows'along a horizontal pipe of cross sectional area 48cm2 which has a constriction of
cross sectional area 12cm2 at one place. If the speed of the water at the constriction is 36m/s,
calculate the speed in the wider section,
(3mk)
Answer:
v₁ = 9 m/s
Explanation:
Here, we can use the continuity equation, as follows:
[tex]A_1v_1 = A_2v_2[/tex]
where,
A₁ = Cross-sectional area of the wider section = 48 cm²
A₂ = Cross-sectional area of the constriction = 12 cm²
v₁ = speed of flow in wider section = ?
v₂ = speed flow in constriction = 36 m/s
Therefore,
[tex](48\ cm^2)v_1 = (12\ cm^2)(36\ m/s)\\\\v_1 = \frac{(12\ cm^2)(36\ m/s)}{(48\ cm^2)} \\\\[/tex]
v₁ = 9 m/s
oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student observes that a particular spring-mass system has a frequency of oscillation of 10 Hz. the spring constant of the spring is 250 N/m. what is the mass?
Answer:
Mass, m = 6.18 kg
Explanation:
Given the following data;
Frequency, F = 10 Hz
Spring constant, k = 250 N/m
We know that pie, π = 22/7
To find the mass, we would use the following formula;
F = 1/2π√(k/m)
Where;
F is the frequency of oscillation.
k is the spring constant.
m is the mass of the spring.
Substituting into the formula, we have;
10 = 1/2 * 22/7 * √250/m
10 = 22/14 * √250/m
Cross-multiplying, we have;
140 = 22 * √250/m
Dividing both sides by 22, we have;
140/22 = √250/m
6.36 = √250/m
Taking the square of both sides, we have;
6.36² = (√250/m)²
40.45 = 250/m
Cross-multiplying, we have;
40.45m = 250
Mass, m = 250/40.45
Mass, m = 6.18 kg
URGENT!!!!!!!!!: If an electromagnetic wave has a frequency of 6 x 10^5 Hz, what is its
wavelength? Use v/f. The speed of light is 3 x 10^8 m/s.
Answer:
A
Explanation:
because the speed divide by the frequency is equal to the wavelength(in meters)
5×10² m
Pls help! What is the average speed of an airplane that travels from New York to Los Angeles, a total distance of 4800 km, in 6.0 hours?
A.
800 km/hr
B.
80 km/hr
C.
0.00125 km/hr
D.
28,800 km/hr
Answer:
800 meters per hour
Explanation:
800 meters per hour is the average speed of an airplane that travels from New York to Los Angeles, a total distance of 4800 km, in 6.0 hours.
A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 11 A, and that of the vacuum cleaner is 4.0 A. Determine the power consumed by (a) the blow-dryer and (b) the vacuum cleaner. (c) Determine the ratio of the energy used by the blow-dryer in 15 minutes to the energy used by the vacuum cleaner in one- half hour.
Answer:
(a) P₁ = 1320 W
(b) P₂ = 480 W
(c) [tex]\frac{E_1}{E_2} = 0.46[/tex]
Explanation:
(a)
The power consumed by the blow dryer can be calculated as follows:
[tex]P_1 = VI[/tex]
where,
P₁ = Power Consumed by the blow dryer = ?
V = Voltage = 120 V
I = Current Rating of the blow dryer = 11 A
Therefore,
[tex]P_1 = (120\ V)(11\ A)\\[/tex]
P₁ = 1320 W
(b)
The power consumed by the blow dryer can be calculated as follows:
[tex]P_2 = VI[/tex]
where,
P₂ = Power Consumed by the vacuum cleaner = ?
V = Voltage = 120 V
I = Current Rating of the vacuum cleaner = 4 A
Therefore,
[tex]P_2 = (120\ V)(4\ A)\\[/tex]
P₂ = 480 W
(c)
[tex]\frac{E_1}{E_2} = \frac{P_1t_1}{P_2t_2}[/tex]
where,
E₁ = Energy used by the blow-dryer
E₂ = Energy used by the vacuum cleaner
t₁ = time of use of the blow-dryer = (15 min)(60 s/1 min) = 900 s
t₂ = time of use of the vacuum cleaner = (1.5 h)(3600 s/1 h) = 5400 s
Therefore,
[tex]\frac{E_1}{E_2} = \frac{(1320\ W)(900\ s)}{(480\ W)(5400\ s)}\\\\\frac{E_1}{E_2} = 0.46[/tex]
A metal spherical shell with inner radius 14 cm and outer radius 24 cm has a net charge of 1= -3 nC. At the center of the shell is a small particle with charge Q2= -7 nC. What is the charge density in (C/m2) on the outer surface of the spherical shell?
Answer:
I don't no the answer sorry
A region of vacuum contains both a uniform electric field with magnitude E and a uniform magnetic field with magnitude B.
Part A What is the ratio E/B if the energy density for the magnetic field equals the energy density for the electric field? Express your answer in volts per meter-tesla to three significant figures. IVO ADV A O O ?
Part B If E = 750 V/m, what is B, in teslas, if the magnetic field and electric-field energy densities are equal? Express your answer in teslas. O ALQ * R O 2 ?
Answer:
A) E / B = 2.99 10⁸ V/ mT, B) B = 2.50 10⁻⁶ T
Explanation:
A) the expressions for the energy densities are:
u_E = ½ ε₀ E²
u_B = ½ B² /μ₀
indicate that the two densities are equal
½ ε₀ E² = ½ B² /μ₀
E / B = 1 /[tex]\sqrt{\epsilon_o \ \mu_o }[/tex]
we calculate
E / B = 1 / √( 8.85 10⁻¹² 4π 10⁻⁷
E / B = 1 /√( 11.1212 10⁻¹⁸)
E / B = 0.29986 10⁹9
E / B = 2.99 10⁸ V/ mT
B) for this case E = 750 V / m, ask the magnetic field
E / B = 1 /[tex]\sqrt{\epsilon_o \ \mu_o}[/tex]
B = E [tex]\sqrt{\epsilon_o \ \mu_o}[/tex]
we calculate
B = 750 √(8.85 10⁻¹² 4π 10⁻⁷
B = 750 3.3348 10⁻⁹
B = 2.50 10⁻⁶ T
Energy densities can be expressed as
u_E = ½ ε₀ E²
u_B = ½ B² /μ₀
When the two densities are equal we use the formula
½ ε₀ E² = ½ B² /μ₀
E / B = 1 / μ₀
E / B = 1 / √( 8.85 10⁻¹² 4π 10⁻⁷)
E / B = 1 /√( 11.1212 10⁻¹⁸)
E / B = 0.29986 10⁹
E / B = 2.99 10⁸ V/ mT
If the magnetic field and electric-field energy densities are equal and E = 750 V / m, we can deduce thatE / B = 1 / √ ξ₀ μ₀
B = E √ ξ₀ μ₀
We substitute the values into the equation
B = 750 √(8.85 10⁻¹² 4π 10⁻⁷)
B = 750 3.3348 10⁻⁹
B = 2.50 10⁻⁶ T
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23. Lunar Gravity Compare the force holding a
10.0-kg rock on Earth and on the Moon. The
gravitational field on the Moon is 1.6 N/kg.
Explanation:
Given
mass of the rock is 10 kg
Force requires to hold the rock is equal to its weight
Weight is given by the product of mass and acceleration due to gravity
Weight on the earth surface
[tex]\Rightarrow W_e=10\times 9.8\\\Rightarrow W_e=98\ N[/tex]
Weight on the moon surface
[tex]\Rightarrow W_m=1.6\times 10\\\Rightarrow W_m=16\ N[/tex]
So, the force holding the rock on earth is approximately 6 times the force on the moon.
Q.4) Two table tennis balls hang with their centers 10.0 cm apart. The charge on ball
A is +12x10°C, and the charge on Ball B is -15x10°C. What is the force of
attraction between the balls?
Answer:
F = 1.62 x 10¹⁴ N
Explanation:
The electrostatic force of attraction between the balls can be given by the following formula:
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
where,
F = attractive force = ?
k = Colomb's Constant = 9 x 10⁹ N.m²/C²
q₁ = Charge on ball A = 12 C
q₂ = Charge on ball B = 15 C
r = distanc between the balls = 10 cm = 0.1 m
Therefore,
[tex]F = \frac{(9\ x\ 10^9\ Nm^2/C^2)(12\ C)(15\ C)}{(0.1\ m)^2}[/tex]
F = 1.62 x 10¹⁴ N
A ball of mass 8kg falls from rest from a height of 100m. Neglecting air resistance, calculate its total energy after falling a distance of 40m.
Answer:
Total energy, T= 4704 Joules
Explanation:
Given the following data;
Mass = 8kg
Initial height, h1 = 100m
Final height, h2 = 40 m
We know that acceleration due to gravity is equal to 9.8 m/s².
To find the total energy, T;
T = mg(h1 - h2)
T = 8 * 9.8 * (100 - 40)
T = 78.4 * 60
Total energy, T= 4704 Joules
A 1500 kg tractor pulls a 750 kg trailer north and applies a 2250 N force on it. What is the force on the tractor?
Answer:
law of Action and Reaction F = 2250 N
Explanation:
The tractor and the trailer are two bodies that interact, therefore, by the law of Action and Reaction, the force that one applies on the other is equal to the force that the second body (trailer) applies on the first (tractor), but with opposite direction
F = 2250 N
directed from trailer to tractor
can any one help me with this?
HELP ASAP-WILL GIVE BRAINLIEST-NO FILES
When a person is moving a desk, which one of the following has the greater amount of force?
A. the desk itself
B. the push from the person moving the desk
C. the drawers as they slide in and out
Answer:C
Explanation:
Convert 13.7g to mg
Question 1 of 5 Which term describes a measurement of the movement of atoms or molecules within an object? O A. Temperature O B. Heat O C. Pressure O D. Density
Answer:
Temperature
Explanation:
Plz help difference between closed system and open system?
A closed system is a system that is completely isolated from its environment. The physical universe, as we currently understand it, appears to be a closed system. An open system is a system that has flows of information, energy, and/or matter between the system and its environment, and which adapts to the exchange.
D makes the most sense, but you just have to put two and two together and go with your gut feeling, first cross out the answers that don't make sense (A didnt make sense) and go from there! I hope the little bit above me helped you answer or decide :) Good luck!
Convert 0.0334 to scientific notation
Answer:
[tex]3.34 * 10^{-2}[/tex]
Explanation:
Scientific notation is writing a number between 1 and 10, and multiplying the number by a power of 10.
Our number is 0.0334
Let's move the decimal point of the number to make it so that the number is at least 1 and less than 10.
We get: 3.34
We moved the decimal point 2 places to the right, so the power of 10 would be -2
Putting what we got together, the scientific notation for the number is:
[tex]3.34 * 10^{-2}[/tex]
8. Main Idea How do animals reproduce?
Answer: Many multicellular animals like fishes, mammals, birds, etc. reproduce through sexual reproduction process. Even reproduction in domestic animals also occurs through the sexual process. Domestic animals (pets or farm animals) are an essential part of our life. MARK AS BRAINLIST PLZ
Explanation:
Phenotype is the actual genes that make a person True or False
Answer:
True?
Explanation:
Genotype and phenotype are two fundamental terms in the science of genetics. ... An organism's genotype is the set of genes in its DNA responsible for a particular trait. An organism's phenotype is the physical expression of those genes.
The term "phenotype" refers to the observable physical properties of an organism; these include the organism's appearance, development, and behavior. An organism's phenotype is determined by its genotype, which is the set of genes the organism carries, as well as by environmental influences upon these genes.
This is why I think it's true. You don't have to read the rest,but that's why I know.
Answer:
The answer is true
Explanation:
I dont know but trust is probably true.
Two events are observed in a frame of reference S to occur at the same space point, the second occurring 1.80 s after the first. In a frame S′ moving relative to S, the second event is observed to occur 2.05 s after the first. What is the difference between the positions of the two events as measured in S^?
Answer:
The difference between the positions of the two events as measured in = 3.53 *10^8 m/s
Explanation:
As we know -
[tex]\Delta x = -\gamma \mu\Delta t[/tex]
Here,
[tex]\Delta x[/tex] is the difference between the positions of the two events as measured in S^
[tex]\gamma[/tex] [tex]= \frac{1}{\sqrt{1-\frac{\mu^2}{c^2} } }[/tex]
And
[tex]\mu[/tex] = 0.547 c
Substituting the given values in above equation, we get -
[tex]\Delta x = (0.547 c)*\frac{1}{\sqrt{1-\frac{\mu^2}{c^2} } }*2.15\\\Delta x = (0.547 c)*\frac{1}{\sqrt{1-\frac{(0.547 c)^2}{c^2} } }*2.15\\\Delta x = (0.547 *3*10^8)*\frac{1}{\sqrt{(1-\(0.547 )^2 } }*2.15\\\Delta x = 3.53 *10^8[/tex]meter per second
what is the work done on the object by the machine.
The work input is the work done on a machine. (Input work)
if something is frictionless does it have thermal energy
Answer:
No
Explanation:
because there is no pressure
A 1.5 V battery is connected to a 1,000 μF capacitor in series with a 150 Ω resistor. a. What is the maximum current that flows through the resistor during charging? b. What is the maximum charge on the capacitor? c. How long does the capacitor take to reach a potential of 1.0V?
Answer:
[tex]0.01\ \text{A}[/tex]
[tex]0.0015\ \text{C}[/tex]
[tex]0.0608\ \text{s}[/tex]
Explanation:
[tex]V_0[/tex] = Voltage = 1.5 V
[tex]C[/tex] = Capacitance = [tex]1000\ \mu\text{F}[/tex]
[tex]R[/tex] = Resistance = [tex]150\ \Omega[/tex]
Current is given by
[tex]I=\dfrac{V_0}{R}\\\Rightarrow I=\dfrac{1.5}{150}\\\Rightarrow I=0.01\ \text{A}[/tex]
Current flowing in the resistor is [tex]0.01\ \text{A}[/tex].
Charge is given by
[tex]Q=CV\\\Rightarrow Q=1000\times 10^{-6}\times 1.5\\\Rightarrow Q=0.0015\ \text{C}[/tex]
The charge on the capacitor is [tex]0.0015\ \text{C}[/tex].
Voltage is given by
[tex]V=V_0e^{-\dfrac{t}{RC}}\\\Rightarrow t=-RC\ln\dfrac{V}{V_0}\\\Rightarrow t=-150\times 1000\times 10^{-6}\times\ln\dfrac{1}{1.5}\\\Rightarrow t=0.0608\ \text{s}[/tex]
Time taken to reach 1 V is [tex]0.0608\ \text{s}[/tex].
PLS HELPP MEEE
Fiber-optic cables rely on total internal reflection.
Please select the best answer from the choices provided
T
F
What is acceleration?
[tex]\huge\boxed{✍ ACCELERATION\hookrightarrow}[/tex]
⎆ Acceleration is defined as the ⇻ rate of change of velocity with respect to time / rate of change of velocity in unit time.
⎆ It's a vector quantity (it has both magnitude & direction).
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