Dr. Michael Kustanov a lead oncologist at Kiev identified following sequence of the gene that was implicated in a unique type of pre-cancer skin called Actinic Keratosis (AK) that causes lesions of the skin when exposed to sun. His lab was determined to edit the gene by CRISPR and restore normal skin in over 2.8 million world-wide. The sequence of the gene is given below: S'AAAGAGTATATTTCAGGTACGAGACGATGGAGGCGG 3' 3' TTT CTCATATAAAGTCCATGC TCT GCTACCTCC GCC 5! From the above information of the cancer gene. Identify the sequence the group would have targeted. (Write the only the sequence that will be targeted. Be very specific No partial credits). Because of this PRECISION CRISPR is a powerful tool. Answer the following questions: 1. The gene target is nucleotides long and write the sequence. ..(do not forget to give the polarity) (5 points) 2. What is the PAM sequence for the AK gene? Write down the sequence (2 points) or 3. Cas9 induced double-strand breaks can be repaired by ..(2 points) ++++++

Answers

Answer 1

AAAGAGTATATTTCAGGTACGAGACGATGGAGGCGGCC-3', the polarity of the sequence is 5' to  of pre-cancer skin called Actinic Keratosis (AK) that causes lesions of the skin when exposed to sun.

Identified by Dr. Michael Kustanov, a lead oncologist at Kiev. His lab was determined to edit the gene by CRISPR and restore normal skin in over 2.8 million world-wide.The sequence of the gene is given below: S'AAAGAGTATATTTCAGGTACGAGACGATGGAGGCGG 3'3' TTT CTCATATAAAGTCCATGC TCT GCTACCTCC GCC 5!

The sequence 5'- AAAGAGTATATTTCAGGTACGAGACGATGGAGGCGGCC-3', is the one that the group would have targeted and it is 39 nucleotides long.2. The PAM (Protospacer Adjacent Motif) sequence for the AK gene is NGG (where N can be any nucleotide), the PAM sequence is 5'-GGC-3'.3.

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Related Questions

Question 4 0.5 pts Which of the following provides the force to push fluids within the glomerulus into the capsule? O Blood Pressure O Osmotic Potential O Skeletal Muscle Contractions O Gravity Questi

Answers

The blood pressure provides the force to push fluids within the glomerulus into the capsule.

The glomerulus is a tiny blood vessel inside the kidney that is involved in the blood filtration process. Its primary function is to filter blood from the renal arteriole (a blood vessel that enters the kidney) and eliminate waste from the bloodstream by allowing water and small molecules to pass through it. The fluid that passes through the glomerulus is referred to as the filtrate or ultrafiltrate.

The Bowman's capsule, also known as the renal corpuscular capsule, surrounds the glomerulus and is part of the kidney's filtration process. The glomerulus filters blood into the Bowman's capsule, which then transports it to the proximal convoluted tubule, where further filtration and processing occur. The Bowman's capsule is critical in preserving the kidneys' ability to filter waste and produce urine.

The force to push fluids within the glomerulus into the capsule is provided by blood pressure. Blood pressure, which is the pressure exerted by the blood on the walls of blood vessels, pushes blood through the kidney, allowing it to be filtered by the glomerulus. As a result, the glomerulus filters waste from the blood and passes it into the Bowman's capsule, which transports it to the proximal convoluted tubule for additional processing.

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37) Which of the following statements is true?
A) As M-cyclin concentration increases, M-cdk activity decreases.
B) As M-cyclin concentration decreases, M-cdk activity increases.
C) M-cyclin concentration does not influence M-cdk activity.
D) As M-cyclin concentration increases, M-cdk activity increases.
38) Which statement is true regarding G-proteins?
A) They can act as an ATPase.
B) Has GTPase activity.
C) It is inactive as a monomer.
D) Are nuclear proteins.

Answers

37) The statement that is true regarding M-cyclin concentration and M-cdk activity is "D) As M-cyclin concentration increases, M-cdk activity increases.

38) The statement that is true regarding G-proteins is "A) They can act as an ATPase.

Explanation:

37) Mitosis is a crucial process that must be tightly regulated to ensure that daughter cells receive the correct chromosome number. The activation of M-cdk (mitosis-promoting factor) is essential for the progression of mitosis.M-cyclin concentration increases during the G2 phase of the cell cycle, resulting in M-cdk activation.

M-cyclin is degraded during mitosis, resulting in the inactivation of M-cdk. M-cyclin concentration and M-cdk activity are directly proportional, according to this data. As M-cyclin concentration increases, M-cdk activity increases, and vice versa.

38) G proteins are signal transducing molecules that are important in cell signaling. They are composed of three subunits: α, β, and γ. G proteins act as molecular switches that activate intracellular signaling pathways by binding to G protein-coupled receptors (GPCRs).

The GTPase activity of Gα subunit hydrolyzes GTP to GDP and results in the inactivation of G proteins. Gα has intrinsic GTPase activity, which allows it to act as an ATPase and hydrolyze GTP to GDP.

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What issues in our modern society can lead to a damaging stress
response? list as many as you can think of.
pls help i need some ideas

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The few issues in present day society that can contribute to a harming stretch reaction is Work-related stretch: Tall work requests, long working hours, need of control, and work frailty can lead to inveterate stretch.

Society issues explained.

Certainly! Here are a few issues in present day society that can contribute to a harming stretch reaction:

Work-related stretch: Tall work requests, long working hours, need of control, and work frailty can lead to inveterate stretch.Money related weight: Financial insecurity, obligation, unemployment, and the fetched of living can all contribute to critical push.Social media and innovation over-burden: Steady network, comparison with others, cyberbullying, and data over-burden can lead to uneasiness and stretch.Relationship issues: Challenges in individual connections, clashes, separate, or need of social bolster can trigger push reactions.Scholarly weight: Unreasonable desires, competition, over the top workload, and execution uneasiness can lead to constant push among understudies.Natural concerns: Climate alter, contamination, characteristic calamities, and biological emergencies can cause push and uneasiness approximately long-term .Wellbeing concerns: Persistent sicknesses, inabilities, terminal illnesses, and the fear of ailment or passing can altogether affect mental well-being.Segregation and social treachery: Prejudice, sexism, homophobia, and other shapes of segregation can lead to constant push and passionate strain.Political distress and societal pressures: Living in politically unstable districts, encountering social distress, or confronting human rights issues can contribute to push.Overpowering desires: Unlikely magnificence guidelines, societal standards, and social weights to comply can lead to unremitting push.Child rearing challenges: Adjusting work and family, need of back, child rearing blame, and weight to raise effective children can cause stretch.Traumatic occasions: Encountering or seeing viciousness, mishaps, characteristic catastrophes, or other traumatic occasions can lead to post-traumatic push clutter (PTSD) or other stress-related disarranges.

It's critical to note that these are fair illustrations, and people may involvement stretch in numerous ways depending on their individual circumstances and flexibility. On the off chance that you're managing with stretch, it's continuously a great thought to look for bolster from companions, family, or mental wellbeing experts who can give direction and help.

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Why are high-density lipoproteins (HDLs) considered "good"?
a. The cholesterol transported by HDLs is destined for
destruction
b. HDLs transport cholesterol to the peripheral tissues for
biosynthesis

Answers

High-density lipoproteins (HDLs) are considered "good" because they are known to have a positive effect on human health by removing cholesterol from the bloodstream and transporting it back to the liver.

This mechanism helps to reduce the amount of cholesterol in the bloodstream and lower the risk of heart disease and stroke. Here is why high-density lipoproteins (HDLs) are considered "good":a. The cholesterol transported by HDLs is destined for destructionThe cholesterol transported.

HDLs is destined for destruction because HDLs carry excess cholesterol from the peripheral tissues to the liver, where it is broken down and removed from the body. This mechanism helps to reduce the amount of cholesterol in the bloodstream, which in turn lowers the risk of heart disease and stroke.

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Allergic reactions of immediate and delayed type. Mechanism, examples clinical forms?

Answers

Allergic reactions can be classified into immediate-type and delayed-type reactions, each with its own mechanisms, examples, and clinical forms. Let's explore them:

Immediate-Type Allergic Reactions:

Mechanism: Immediate-type allergic reactions, also known as type I hypersensitivity reactions, involve the rapid release of histamine and other inflammatory mediators in response to an allergen. Examples: Immediate-type allergic reactions include:

a. Allergic rhinitis (hay fever): Allergens such as pollen, dust mites, or animal dander cause symptoms like sneezing, nasal congestion, itching, and watery eyes. b. Asthma: Allergens or other triggers cause bronchial constriction, coughing, wheezing, and shortness of breath. c. Anaphylaxis: A severe and potentially life-threatening allergic reaction characterized by widespread histamine release, leading to symptoms like difficulty breathing.

Delayed-Type Allergic Reactions:

Mechanism: Delayed-type allergic reactions, also known as type IV hypersensitivity reactions, involve a delayed immune response mediated by T cells. When an individual is exposed to an allergen, specific T cells called sensitized T cells recognize the allergen and trigger an immune response. Examples: Delayed-type allergic reactions include:

a. Contact dermatitis: Allergens such as certain metals (e.g., nickel), cosmetics, or plants (e.g., poison ivy) can cause skin inflammation, redness, itching, and the formation of blisters or rashes. b. Tuberculin reaction: In response to the tuberculin antigen (PPD), individuals previously exposed to Mycobacterium tuberculosis exhibit a delayed hypersensitivity reaction.

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The Cori cycle includes all of the following pathways except: The citric acid cycle O Glycolysis O Fermentation O Gluconeogenesis O The Cori cycle includes all of the above pathways.

Answers

The correct Option is A. The citric acid cycle

The Cori cycle includes all of the following pathways except the citric acid cycle. The Cori cycle refers to a metabolic pathway that occurs between the liver and skeletal muscle cells during periods of high energy demand or anaerobic conditions.

In the Cori cycle, glucose is initially converted to pyruvate through the process of glycolysis, which takes place in the skeletal muscle cells. Pyruvate is then converted to lactate through fermentation, which is an anaerobic process.

The lactate is then transported to the liver, where it undergoes gluconeogenesis, a process in which glucose is synthesized from non-carbohydrate sources.

The purpose of the Cori cycle is to maintain the supply of glucose to the muscles, even when the demand for energy exceeds the capacity of aerobic metabolism.

The lactate produced in the muscle cells is transported to the liver, where it is converted back to glucose and released into the bloodstream for use by other tissues, including the muscles.

The citric acid cycle, also known as the Krebs cycle, is not directly involved in the Cori cycle. It is a central pathway of aerobic metabolism that takes place in the mitochondria and is responsible for the complete oxidation of glucose and the generation of energy-rich molecules such as NADH and FADH2.

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Due to large amounts of ATP available in a cell for hydrolysis, the linear forms of glucose monomers in cells can directly undergo dehydration reactions with each other to form glycosidic linkages producing glycogen, without having to isomerize into the ring forms of glucose monomers. a. True
b. False Cells lining the small intestine are specialized for absorbing nutrients from food. What type of structure might you expect these cells to have? a. A highly folded cell membrane to increase surface area b. Multiple nuclei c. Lots of mitochondria d. A thick cell wall to keep out the toxic molecules e. Lots of ribosomes

Answers

Question 1: This statement "Due to large amounts of ATP available in a cell for hydrolysis, the linear forms of glucose monomers in cells can directly undergo dehydration reactions with Glycogen is formed when multiple glucose molecules join together through glycosidic linkages without undergoing the process of isomerization into ring forms." is True.

Question 2:  The structure that might be expected is option is a. A highly folded cell membrane to increase surface area.

The presence of abundant ATP in cells allows for the direct dehydration reactions between linear glucose monomers, bypassing the need for isomerization into ring forms, resulting in the formation of glycogen through glycosidic linkages.

Question 2: Cells in the lining of the small intestine, which are specialized for nutrient absorption, are likely to possess a extensively folded cell membrane in order to maximize their surface area for efficient nutrient absorption.

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• Transcribe the following strand of DNA into mRNA CCTTACTTATAATGCTCAT GCTA GGAT GAATATTACGAGTACGAT Translate your mRNA strand above into a sequence of amino acids PRACTICE #2 How many nucleotides are required to code for the following sequence of amino acids Leu - Tyr - Arg - Trp - Ser Is it possible to determine the mRNA sequence that is responsible for producing the following sequence of amino acids? Explain... What does this illustrate?

Answers

DNA transcription is a biochemical process in which the DNA molecule's information is transferred to mRNA. This process is a significant part of protein synthesis. The process of protein synthesis is initiated by a transcribed mRNA strand that carries the genetic information from DNA.

The mRNA strand is produced through a transcription process in which the DNA sequence is transcribed into RNA, and the RNA polymerase molecule catalyzes the reaction. Once the mRNA strand is created, it moves out of the nucleus and travels to the cytoplasm, where it interacts with ribosomes to produce proteins.

Transcribe the following strand of DNA into mRNA:

CCTTACTTATAATGCTCATGCTAGGATGAATATTACGAGTACGAT.

The mRNA sequence will be:

GGAAUGAAUAUUACGAGUACGUAUCUAGACGUACGUAG.

The first step in the process of protein synthesis is transcription. The mRNA strand is then translated into a sequence of amino acids using the genetic code. The sequence of amino acids for the mRNA strand above is:

G - N - N - Y - L - S - E - V - D - S - T - R.

This can be calculated with the help of a genetic code chart. It's not possible to determine the mRNA sequence that is responsible for producing a particular sequence of amino acids. It is because there is more than one mRNA sequence that can encode the same protein.

This is due to the genetic code being degenerate, indicating that more than one codon can code for a single amino acid. This phenomenon is known as codon degeneracy. The sequence Leu - Tyr - Arg - Trp - Ser contains 15 nucleotides (5 amino acids × 3 nucleotides per codon = 15 nucleotides).

Hence, at least 15 nucleotides are required to code for this sequence.

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Evolutionary trees (i.e. phylogenies), in general are properly understood by scientists to be A. theories B. hypotheses
C. dogmas
D. facts Which of the following is NOT an assumption of Hardy-Weinberg equilibrium?
A. No mutations occurring B. Non-random mating is occurring C. No selection occurring D. The population size is large What does "fitness" mean when speaking in terms of evolution?
A. Level of overall health of the individual relative to other in its population B. How many offspring an individual produces relative to other in its population C. Level of overall health of the population D. The size and diversity of the gene pool The red spotted damselfish and white spotted damselfish were once considered two different species. Recently they have been redescribed as a single species. Which of the following pieces of evidence, if true, would be a cause for this new description? A. The two types interbreed in nature and produce viable offspring
B. The two types live in the same area and eat the same food C. The two types share a lot of genes
D. The two types look really similar in appearance. Which is/are FALSE regarding what you know about populations? 1. Groups of individuals of the same species II. Populations evolve over time III. Groups of individuals of different species IV. They are the units of evolution
A. II and III B. II and IV C. I, II and IV
D. II, III and IV

Answers

The answer is B. Non-random mating is occurring is NOT an assumption of Hardy-Weinberg equilibrium.

Evolutionary trees (i.e. phylogenies), in general are properly understood by scientists to be hypotheses. The assumption that is NOT of Hardy-Weinberg equilibrium is B. Non-random mating is occurring. When speaking in terms of evolution, "fitness" means how many offspring an individual produces relative to other in its population.

If the red spotted damselfish and white spotted damselfish were to interbreed in nature and produce viable offspring, it would be a cause for this new description. False statements about populations are II and III;

Populations evolve over time and Groups of individuals of different species

.What is the meaning of the term fitness in relation to evolution?

When speaking in terms of evolution, fitness means how many offspring an individual produces relative to others in its population. Fitness is determined by a combination of survival, mating success, and the number of offspring produced. The fittest individuals are the ones that are most successful in reproducing and passing their genes on to the next generation.

What is Hardy-Weinberg equilibrium?

Hardy-Weinberg equilibrium is a fundamental concept in population genetics that describes the relationship between gene frequencies and genotype frequencies in a population. The Hardy-Weinberg equilibrium describes a hypothetical population in which the frequencies of alleles and genotypes do not change over time. It is a model that can be used to test whether a population is evolving or not.

The assumptions of Hardy-Weinberg equilibrium are no mutations occurring, no selection occurring, random mating is occurring, the population size is large, and there is no gene flow. If any of these assumptions are violated, the population will not be in Hardy-Weinberg equilibrium.

Therefore, the answer is B. Non-random mating is occurring is NOT an assumption of Hardy-Weinberg equilibrium.

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Phosphodiesterase is ____________
Select one:
a. a trimeric G protein
b. a photopigment
C. an enzyme that breaks down cGMP
d. an enzyme the synthesizes cGMPX
e. a 7 transmembrane receptor

Answers

Phosphodiesterase is option C. an enzyme that breaks down cGMP

Phosphodiesterase is a family of enzymes that hydrolyze cyclic nucleotides such as cGMP and cAMP. They break down cGMP into GMP and cAMP into AMP, thereby controlling their intracellular levels. PDEs (phosphodiesterases) are ubiquitous enzymes that play an important role in cellular signaling by regulating cyclic nucleotide levels.The intracellular levels of cyclic nucleotides, cAMP, and cGMP, are controlled by the action of PDEs.

They hydrolyze cyclic nucleotides to their inactive form, allowing cells to respond rapidly to new stimuli. The action of PDE inhibitors, such as sildenafil (Viagra), leads to an increase in cGMP levels, resulting in smooth muscle relaxation in the corpus cavernosum, leading to an erection.

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A means of detecting the presence of specific carbohydrate moieties on glycoprotines is O A. ferritin conjugated lectins OB.photobleaching O C. liposome formation O D. SDS-PAGE O E. The freeze fracture technique

Answers

The correct answer is O A. ferritin conjugated lectins. Ferritin conjugated lectins is a method of detecting the presence of specific carbohydrate moieties on glycoproteins.

What is glycoprotein Glycoproteins are proteins in which the carbohydrate group(s) are covalently bonded to the protein chain. Glycoproteins are mostly found on the outer membrane surface of animal cells, and they are involved in cellular recognition and signaling.

Because of their heterogeneity, the identification and characterization of glycoproteins necessitates careful analysis of their carbohydrate moiety. Ferritin conjugated lectins are widely used to detect specific carbohydrate moieties on glycoproteins and to characterize them.

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cholesterol
A contains a single hydroxyl group
B is amphipathic
C is found in animal cells
D all of the above

Answers

Cholesterol is a compound that contains a single hydroxyl group, is amphipathic, and is found in animal cells.

Cholesterol is a sterol molecule that is essential for the structure and function of animal cell membranes. It plays a vital role in maintaining membrane fluidity and integrity. Cholesterol possesses a single hydroxyl group (-OH) on its structure, which allows it to participate in various biochemical reactions. Additionally, cholesterol is classified as an amphipathic molecule, meaning it has both hydrophobic (water-repelling) and hydrophilic (water-attracting) regions. The hydroxyl group in cholesterol contributes to its hydrophilic properties, while the hydrocarbon tail gives it hydrophobic characteristics. This amphipathic nature enables cholesterol to interact with both water-soluble and lipid-soluble components in cellular membranes. Furthermore, cholesterol is primarily found in animal cells, where it is synthesized and plays essential roles in various physiological processes. It is a key component of cell membranes, helps in the formation of lipid rafts, and serves as a precursor for the synthesis of steroid hormones, bile acids, and vitamin D. In summary, cholesterol exhibits all the mentioned characteristics: it contains a single hydroxyl group, is amphipathic, and is predominantly found in animal cells.

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From which purine is caffeine derived and explain with
reaction?

Answers

Caffeine is derived from the purine xanthine. It is a naturally occurring compound found in coffee, tea, cocoa, and other food products. The structure of xanthine contains two fused rings: a pyrimidine ring and an imidazole ring.

Caffeine is a methylated derivative of xanthine.The process of caffeine synthesis involves several chemical reactions. The initial step is the degradation of the nucleic acid adenine to yield hypoxanthine. Hypoxanthine is then oxidized to xanthine in a reaction catalyzed by the enzyme xanthine oxidase. Finally, xanthine is methylated to form caffeine, a reaction that is catalyzed by the enzyme caffeine synthase. The methyl group is derived from S-adenosyl-L-methionine (SAM), a common methyl donor in many biochemical reactions.

Thus, caffeine is derived from the purine xanthine via a series of biochemical reactions that involve the degradation of adenine, oxidation of hypoxanthine, and methylation of xanthine.

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A mutant sex-linked trait called "notched" (N) is deadly in Drosophila when homozygous in females. Males who have a single N allele will also die. The heterozygous condition (Nn) causes small notches on the wing. The normal condition in both male and females is represented by the allele n. Which of the following statement is incorrect about the F1 generation from the cross between XNXn and XnY?
a. Among the male flies, 50% have normal wings and 50% have small notches on the wings. b. The ratio of the male flies and the female flies is 1:2.
c. All the male flies have normal wings.
d. Among the female flies, 50% have normal wings and 50% have small notches on the wings. e. Pleiotropy may be used to describe this gene.

Answers

The statement that is incorrect about the F1 generation from the cross between XNXn and XnY is option c. All the male flies have normal wings.

In Drosophila, the "notched" (N) trait is lethal when homozygous in females and also lethal in males with a single N allele. The heterozygous condition (Nn) causes small notches on the wing. In the given cross between XNXn (female) and XnY (male), the genotype of the offspring can be represented as follows:

Male flies: 50% will have normal wings (XnY) and 50% will have small notches on the wings (XNXn).

Female flies: 50% will have normal wings (XnXn) and 50% will have small notches on the wings (XNXn).

Therefore, the correct statement is that among the male flies, 50% have normal wings and 50% have small notches on the wings. The ratio of male flies to female flies is 1:1, not 1:2 as mentioned in option b. Additionally, it is incorrect to say that all male flies have normal wings, as some will have small notches due to the presence of the N allele. Pleiotropy, the phenomenon where a single gene affects multiple traits, may be applicable to describe the "notched" gene since it influences wing morphology and viability in both sexes.

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Describe each type of infection in the following list and include the mode of transmission in each scenario. Use terms such as primary, secondary, healthcare-associated, STI. mixed, latent, toxemia, chronic, zoonotic, asymptomatic. local, and systemic to describe the types of infections (more than one term may apply, some may not apply to these conditions) I 1) The development of Pneumocystisis pneumonia in an AIDS patient 2) Salmonellosis 3) Hantavirus pulmonary syndrome infection acquired while vacationing in a log cabin

Answers

In conclusion, Pneumocystis pneumonia is a systemic infection that can be transmitted via the airborne route, Salmonellosis is both a local and systemic infection that can be caused by contaminated food or water, and Hantavirus pulmonary syndrome is a local and zoonotic infection that can be transmitted through the air.

Infections can be divided into several types based on their duration, mode of transmission, and causative agent. Here is the explanation of each infection in detail:1) The development of Pneumocystisis pneumonia in an AIDS patientPneumocystis pneumonia is caused by the Pneumocystis jirovecii fungus and is an opportunistic infection that affects individuals who have compromised immune systems, such as AIDS patients. Pneumocystis pneumonia can be transmitted from person to person via the airborne route, making it a local and systemic infection.2) SalmonellosisSalmonellosis is a type of bacterial infection caused by Salmonella bacteria, which are most commonly transmitted via contaminated food or water. Salmonella can cause both local and systemic infections.3) Hantavirus pulmonary syndrome infection acquired while vacationing in a log cabinHantavirus pulmonary syndrome is caused by exposure to rodent droppings, urine, or saliva. This type of infection is zoonotic and can be transmitted through the air, making it a local infection. The symptoms are similar to the flu and can progress to acute respiratory failure, making it a systemic infection.In conclusion, Pneumocystis pneumonia is a systemic infection that can be transmitted via the airborne route, Salmonellosis is both a local and systemic infection that can be caused by contaminated food or water, and Hantavirus pulmonary syndrome is a local and zoonotic infection that can be transmitted through the air.

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Assume that with your nucleic acid extraction procedure you successfully isolated the DNA from the biological material you are working with. Using the equation below calculate the molecular weight of the given partial DNA sequence:
5’-AGTGGTCCTGAGGTCGTAT-3’
Anhydrous Molecular Weight = (An x 313.21) + (Tn x 304.2) + (Cn x 289.18) + (Gn x 329.21) - 61.96 (g/mole)

Answers

Therefore, the approximate molecular weight of the given partial DNA sequence 5’-AGTGGTCCTGAGGTCGTAT-3’ is approximately 3583.03 g/mole.

To calculate the molecular weight of the given partial DNA sequence, we can use the provided equation and substitute the number of occurrences for each nucleotide.

Let's calculate the molecular weight:

An = number of adenine (A) nucleotides = 2

Tn = number of thymine (T) nucleotides = 4

Cn = number of cytosine (C) nucleotides = 4

Gn = number of guanine (G) nucleotides = 5

Anhydrous Molecular Weight = (An x 313.21) + (Tn x 304.2) + (Cn x 289.18) + (Gn x 329.21) - 61.96 (g/mole)

Substituting the values:

Anhydrous Molecular Weight = (2 x 313.21) + (4 x 304.2) + (4 x 289.18) + (5 x 329.21) - 61.96 (g/mole)

Calculating:

Anhydrous Molecular Weight = 626.42 + 1216.8 + 1156.72 + 1646.05 - 61.96 (g/mole)

Anhydrous Molecular Weight 3583.03 g/mole

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Black children are children. 10 times more O 7-8 times more Oless Otwice as likely to die from asthma compared to white The likelihood of developing a chronic disease such as asthma, COPD, or heart disease is correlated most strongly with the gender of the person O the education level of the person Othe ZIP code a person lives in O the affluence of the person

Answers

Black children are 7-8 times more likely to die from asthma compared to white children. The likelihood of developing a chronic disease such as asthma, COPD, or heart disease is most strongly correlated with factors such as the ZIP code a person lives in and the affluence of the person, rather than their gender or education level.

Research has shown significant disparities in health outcomes among different racial and ethnic groups, particularly regarding childhood asthma. Black children are found to be 7-8 times more likely to die from asthma compared to white children. This disparity highlights the unequal burden of asthma and its related complications faced by Black communities.

When considering the likelihood of developing chronic diseases like asthma, COPD (Chronic Obstructive Pulmonary Disease), or heart disease, various factors come into play. While gender and education level may have some influence on health outcomes, studies have consistently shown that social determinants of health play a significant role.

Factors such as the ZIP code a person lives in, which reflects the community's social and economic conditions, and the person's affluence or socio-economic status have a stronger correlation with the likelihood of developing chronic diseases.

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Mature T cells express either the co-receptor CD4 or CD8. Give
two (2) reasons why the expression of a co-receptor is important
for the activation and function of T cells.

Answers

Mature T cells express either the co-receptor CD4 or CD8. The expression of a co-receptor is important for the activation and function of T cells.

The following are two reasons why the expression of a co-receptor is important for the activation and function of T cells:

1. Enhances the specificity of T cellsCD4 and CD8 are critical for T cell development and function, and they aid in antigen recognition. CD4 is important for activating MHC class II-restricted T helper cells, whereas CD8 is important for activating MHC class I-restricted cytotoxic T cells.

The expression of these co-receptors aids in the recognition of the major histocompatibility complex (MHC) molecules, which improves the specificity of T cell responses.

2. Co-receptors provide additional signaling

The expression of CD4 or CD8 on T cells aids in the recognition of peptides bound to MHC molecules. In addition, these molecules provide co-stimulatory signals to T cells, which are essential for full T cell activation.

Co-receptors aid in T cell activation by providing additional signaling to T cells to elicit an effective immune response.

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1. Which of the following is NOT a cooperative relationship to regulate adaptive, specific immune responses?
a. B cells interacting with T-helper cells .
b. B cells interacting with macrophages
c. Cytotoxic T cells interacting with T-helper cells.
d. T-helper cells interacting with antigen -presenting phagocytes .
e. T-helper cells interacting with other T-helper cells of the same type .
2. True or False: Even if they have never been infected with or been immunized against Ebola Virus, most people have the genetic ability to make a primary anti-Ebola adaptive, specific response
3. Smakers often develop respiratory infections when smoking limits the ability of cilia in the throat to remove particulatesThus, smoking leads to a loss
a. Acquired, specific immunity
b. A cellular second line of defense
c. An artificiallyacquired immune function
d. A cellular barrier function
e. A physical barrier function

Answers

1. e. T-helper cells interacting with other T-helper cells of the same type.

2. The statement is false.

The answer is d. A cellular barrier function.

1. The cooperative relationships mentioned in options a, b, c, and d are all involved in regulating adaptive, specific immune responses. B cells interacting with T-helper cells, B cells interacting with macrophages, cytotoxic T cells interacting with T-helper cells, and T-helper cells interacting with antigen-presenting phagocytes are all examples of cooperative interactions that play a role in coordinating and regulating the adaptive immune response. Option e, T-helper cells interacting with other T-helper cells of the same type, does not specifically contribute to the regulation of adaptive immune responses, making it the correct answer

2. False. The genetic ability to mount a primary anti-Ebola adaptive, specific immune response requires prior exposure to the Ebola virus or vaccination. Adaptive immune responses are acquired through the recognition of specific antigens, which requires prior exposure or immunization to generate a memory response. Therefore, individuals who have never been infected with or immunized against Ebola virus would not have the genetic ability to mount a primary anti-Ebola adaptive immune response.

3. The correct answer is d. A cellular barrier function. Smoking affects the cilia in the throat, which are cellular structures responsible for moving mucus and trapped particles out of the respiratory tract. By limiting the ability of cilia to perform their function, smoking compromises the cellular barrier function of the respiratory tract. This impairment can lead to an increased susceptibility to respiratory infections.

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Which of the reactions in the TCA cycle reduce ubiquinone rather than NAD+?
O a-ketoglutarate → succinyl-CoA
O Oxaloacetate + acetyl-CoA → citrate
O Malate → oxaloacetate
O Succinate fumarate
O Isocitrate-a-ketoglutarate

Answers

The reaction in the TCA cycle that reduces ubiquinone rather than NAD+ is "Succinate → Fumarate."

In the TCA cycle, the reduction of NAD+ occurs in three reactions: Isocitrate → α-ketoglutarate, α-ketoglutarate → Succinyl-CoA, and Malate → Oxaloacetate. These reactions involve the transfer of electrons to NAD+, resulting in the formation of NADH.

However, the reaction "Succinate → Fumarate" is different. It involves the conversion of succinate to fumarate and the reduction of ubiquinone (also known as coenzyme Q) to ubiquinol. This reaction is catalyzed by the enzyme succinate dehydrogenase, which is associated with the inner mitochondrial membrane.

The reduction of ubiquinone to ubiquinol in this reaction is important for the electron transport chain, as it allows for the transfer of electrons to complex III, contributing to the generation of ATP during oxidative phosphorylation.

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All fo the following statements about primary bone cancers are
true except
A.
Ewing sarcoma is an aggressive bone tumor of childhood and
adolescence
B.
Unlike bone metasases primary bone can

Answers

All of the following statements about primary bone cancers are true except for statement B.

A. Ewing sarcoma is indeed an aggressive bone tumor that primarily affects children and adolescents. It typically arises in the long bones, such as the femur or tibia, and can also occur in the pelvis or other skeletal sites. Ewing sarcoma requires prompt and aggressive treatment, including chemotherapy, radiation therapy, and surgery.

B. Unlike bone metastases, primary bone cancers do not originate from other cancerous sites and spread to the bones. Primary bone cancers develop within the bones themselves and are classified into different types, such as osteosarcoma, chondrosarcoma, and malignant fibrous histiocytoma. These cancers may arise from bone cells or other connective tissues within the bone. In contrast, bone metastases occur when cancer cells from a primary tumor in another part of the body, such as the breast, lung, or prostate, spread to the bones.

Therefore, statement B is incorrect because primary bone cancers do not generate from other cancerous sites but rather originate within the bones.

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"Explain what is characteristic for humans that produce
cytotoxic granules in their activated cytotoxic T-lymphocytes (CTL)
but that cannot release the granules onto virally infected
cells?

Answers

Humans who produce cytotoxic granules in their activated cytotoxic T-lymphocytes (CTLs) but cannot release the granules onto virally infected cells may have a deficiency in the process known as degranulation.

Degranulation is a crucial step in the immune response, where CTLs release their cytotoxic granules containing perforin and granzymes to induce apoptosis in the target cells. This inability to release cytotoxic granules onto infected cells can be caused by various factors, such as genetic mutations or defects in the molecular machinery involved in degranulation. One possible explanation could be a dysfunction in the docking and fusion of the cytotoxic granules with the plasma membrane of the CTLs, preventing their release. Without the ability to release the granules, these individuals' CTLs would be compromised in their ability to effectively eliminate virally infected cells.

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There are two different phenotypes of a moth species (diploid), black and light grey. Not yet answered Marked out of 2.00 The more recently evolved black colour, is the dominant allele, B, while the recessive allele, b gives a light grey colour. P Flag question The number of ALLELES in the population is 1266. The allele frequencies for the population are as follows: p (B): 0.54 9 (b): 0.46 The expected genotype counts for both homozygotes in this population if it is in Hardy- Weinberg equilibrium would be as follows (rounding to the nearest whole animal): BB homozygote individuals: bb homozygote individuals:

Answers

The question requires us to find the expected genotype counts for both homozygotes in this population if it is in Hardy-Weinberg equilibrium. Before moving forward, let us have a brief understanding of what Hardy-Weinberg equilibrium means.

Now, let us solve the given question.

The population contains two different phenotypes of a moth species (diploid), black and light grey. The dominant allele is B, and the recessive allele is b. The frequency of allele B is 0.54, and the frequency of allele b is 0.46. The total number of alleles in the population is 1266. Therefore,

Number of B alleles in the population = 0.54 x 1266 = 684.84 ≈ 685

Number of b alleles in the population = 0.46 x 1266 = 582.36 ≈ 582

Using the Hardy-Weinberg equation, we can calculate the expected genotype counts.

p2 + 2pq + q2 = 1

Here, p = frequency of allele B = 0.54
q = frequency of allele b = 0.46

p2 = (0.54)2 = 0.2916
q2 = (0.46)2 = 0.2116
2pq = 2(0.54)(0.46) = 0.4992

The expected genotype counts are:

BB homozygote individuals = p2 x total number of individuals
= 0.2916 x 1266
= 369.4 ≈ 369

bb homozygote individuals = q2 x total number of individuals
= 0.2116 x 1266
= 267.8 ≈ 268


Hence, the solution to the given problem is, the expected genotype counts for both homozygotes in this population if it is in Hardy-Weinberg equilibrium would be 369 BB homozygote individuals and 268 bb homozygote individuals.

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Review the protocol for this lab and put the following steps in order.
Dry cells
Fix cells with formaldehyde
Image cells
Put mounting media on cells
Rinse cells with PBS
Treat cells with dynasore
Incubate 30 min
Incubate 10 min
Incubate 3 min

Answers

Here is the step-by-step explanation of the revised order for the lab protocol:

1. Rinse cells with PBS: This step is performed to remove any debris or substances that may interfere with subsequent procedures.

2. Fix cells with formaldehyde: Formaldehyde is a common fixative used to preserve cell structure and prevent degradation during the experiment.

3. Incubate 3 min: This short incubation period allows for specific interactions or reactions to occur between the cells and the substances used in the experiment.

4. Incubate 10 min: A slightly longer incubation period provides sufficient time for more complex processes to take place, such as protein interactions or signaling pathways.

5. Incubate 30 min: This extended incubation period allows for more comprehensive and time-consuming processes to occur, such as cellular uptake or expression changes.

6. Treat cells with dynasore: Dynasore is a specific treatment used in this experiment, likely to study its effects on cellular processes or pathways of interest.

7. Rinse cells with PBS: Another rinse with PBS is performed to remove any residual substances or treatments.

8. Dry cells: The cells are dried, possibly using techniques like air-drying or gentle blotting, to prepare them for the next step.

9. Put mounting media on cells: Mounting media is applied to the cells, which helps to preserve the specimen and provides a suitable medium for imaging.

10. Image cells: Finally, the cells are imaged using an appropriate imaging system or microscope to visualize and analyze the results of the experiment.

Thus, these steps must be followed in proper order.

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Detecting uncut plasmids from the restriction digests

Answers

When detecting uncut plasmids from the restriction digests, you need to follow the steps below:

Step 1: ElectrophoresisAfter performing a restriction digest, the uncut plasmids may be observed in the electrophoresis gel.

These uncut plasmids may be larger than the linearized plasmids, which would be observed in smaller bands on the gel.

Step 2: ObservationWhen uncut plasmids are seen in the gel, it suggests that the restriction digest was not successful or that the enzyme did not work. If no plasmid bands are visible, it could indicate that the plasmid DNA has been degraded or that the gel was not run properly.

It's crucial to determine why the plasmids were not cut before proceeding with further research.

Step 3: Confirm the presence of the plasmids you can also use other methods such as using PCR or gel electrophoresis.

For instance, gel electrophoresis is another technique that can be used to detect uncut plasmids from the restriction digests.

The uncut plasmids have larger sizes, which means they will be present at a higher location on the gel than the linearized plasmids.

PCR is also an option, as it uses primers that are designed to bind specifically to the plasmid and amplify the DNA.

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Question 1 1 F Boiling a solution is an excellent way to sterilize as it will destroy all microbes. True False Question 2 1 pts Which group of organisms tend to be the most resistant to disinfectants? Gram postive organisms O Gram negative organisms Both are equally resistant No answer text provided

Answers

Boiling a solution is an excellent way to sterilize as it will destroy all microbes. True/False. Boiling is one of the oldest and most widely used methods of sterilizing fluids and materials.

Boiling can be an effective way of sterilizing because it kills the bacteria, viruses, and fungi by denaturing their enzymes and other proteins. However, boiling is not a complete method of sterilization as some microbes can survive boiling at 100°C for several minutes.

For this reason, boiling is only used as a disinfectant for heat-resistant items like utensils, glassware, and some laboratory equipment.

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What type of enzyme herable for nating procent of you? Pochorase Dehydrogenate Prophe One QUESTION Which of the flowing statement about con not correct? The more monetosphere componere NAD does not particle the redok reaction The hydroxy poup otse AM portion of Albehytted to become NADPOP The forescente rep election in orde octron but want to under twee reduction The watono come coupled to regeneration of DO NADH FADH Lounge with a cowyucan be reduced in two separating one electronen QUESTION ? About that inhibiteulat or the presentaron mucho entre would come own a ATP we would be able to produce ATP wale would be able to u TCA Fement could NADH wd be de See how would be QUESTIONS Consider the ratio A: D -> When asks we water te wees vat toon te verned by a factor when the concentration of war icles.

Answers

I'm sorry, but I'm having difficulty understanding the questions you're asking. The text appears to contain incomplete or inaccurate statements and questions that are difficult to decipher. If you could please rephrase your questions or provide more context, I'll be happy to assist you.

I apologize for the confusion. The provided text contains incomplete and unclear statements and questions that are difficult to understand. It seems to include fragmented information about enzymes, redox reactions, ATP production, and concentration changes. To provide accurate explanations, I would need clearer and well-structured questions. Please provide specific questions or provide more context so that I can assist you effectively.

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Criticise if the following statement is CORRECT: "Virus causing mumps is highly effective in release of newly synthesized virus after infecting the cells so that the subsequent adsorption and penetration is easily carried out, leading to a spreading from one infected cell to other uninfected cells." (10 marks)

Answers

Lack of clarity: The statement does not clearly specify which virus causing mumps is being referred to.

Mumps is primarily caused by the mumps virus, which belongs to the Paramyxoviridae family. It would be more accurate to specify the particular strain of the mumps virus if that is what is being discussed.

Inaccurate terminology: The term "highly effective" is not appropriate in this context. Instead, it would be more accurate to use terms like "efficient" or "capable" to describe the viral replication and release process.

Inconsistent language: The statement uses the phrase "newly synthesized virus" without prior explanation. It would be clearer to explain that the virus replicates within the infected cells and produces new virus particles.

Misleading information: The statement suggests that the primary role of the virus is to facilitate adsorption and penetration into uninfected cells. While adsorption and penetration are important steps in viral infection, they are not the sole purposes of the virus. The main objective of a virus is to replicate within host cells and produce more virus particles.

Incomplete explanation: The statement does not elaborate on the mechanisms or factors that make the virus effective in releasing newly synthesized viruses. It would be beneficial to provide additional information about the specific molecular or cellular processes involved in the release of viral particles.

Overgeneralization: The statement claims that the virus spreads from one infected cell to other uninfected cells. While this is generally true for many viruses, it does not apply to all viruses or infections. Different viruses employ various mechanisms for spreading within the host, such as direct cell-to-cell transmission or systemic dissemination.

Lack of evidence or references: The statement does not provide any supporting evidence or references to scientific literature. Without reliable sources, it is difficult to assess the accuracy and validity of the statement.

Lack of context: The statement does not mention the specific host organism or provide any contextual information. The effectiveness of viral replication and spread can vary depending on the host's immune response, viral strain, and other factors. Providing more context would help in better understanding the statement.

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Cross reactivity is the origin why we carry blood group antibodies,
explain?

Answers

Cross reactivity is the reason why we carry blood group antibodies. It occurs because the immune system can produce antibodies that recognize and react with similar antigens found on different blood cells.

Cross reactivity is a phenomenon in which antibodies produced by the immune system can recognize and react with antigens that are structurally similar to the original antigen that triggered their production. In the context of blood groups, cross reactivity refers to the ability of antibodies to react with antigens on red blood cells that belong to a different blood group system. The immune system is capable of generating a diverse repertoire of antibodies that can recognize a wide range of antigens. However, due to structural similarities between certain antigens, antibodies can cross react with related antigens. For example, individuals with blood group A produce antibodies against the B antigen, and individuals with blood group B produce antibodies against the A antigen. This cross reactivity occurs because the A and B antigens share some structural similarities, allowing the antibodies to react with both antigens. Cross reactivity in blood group antibodies is important for blood compatibility and transfusion medicine. It helps determine which blood types are compatible for transfusion and which combinations may result in adverse reactions. Understanding the cross reactivity patterns of blood group antibodies is essential to ensure safe and successful blood transfusions.

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Humans affect the carbon cycle by which of the following? destroying vegetation that absorbs carbon dioxide. clearing or cutting down forests. burning fossil fuels. All of the choices are correct.

Answers

All of the choices are correct. Humans affect the carbon cycle by destroying vegetation that absorbs carbon dioxide, clearing or cutting down forests, and burning fossil fuels.What is the Carbon Cycle?Carbon is a basic constituent of all life forms on Earth.

It is the foundation of all life and an essential component of all organic compounds. Carbon dioxide (CO2) is a greenhouse gas that contributes to global climate change when it is present in the atmosphere. However, the majority of the carbon on Earth is held in rocks and sediments.Carbon cycles between the atmosphere, oceans, land, and living things in a number of different ways. The carbon cycle is the process by which carbon is passed through living and non-living things, and it is crucial to life on Earth.

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