Don't just say the answer, please show how you got it so I can know for further use​

Answer:

First one

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

-10

Step-by-step explanation:

The negative integers greater than -5 are: -4, -3, -2, and -1. So,

(-4)+(-3)+(-2)+(-1) = -10

Awnser:

9,12,18

Step-by-step explanation:

you have to add the smallest numbers together and it has to be greater that the greatest number.

9+12= 21

21>18

Answer:

a) Median Height = 66 inches

b) Range of Heights = 18 inches

Step-by-step explanation:

a) The median in a box-and-whisker plot is the second quartile, located between the first and third quartiles indicated by the dashed line. Therefore, the median height is 66 inches.

b) The range in a box-and-whisker plot uses the same process of finding the range of a set of data. You find the difference between the maximum and the minimum values of the data. Therefore, the range of heights is 77 - 59 = 18 inches.

Answer:

32 years old.

Step-by-step explanation:

13 times 2 is 26, and 6 added to 26 is 32.

I hope this helps, have a nice day.

Answer:

b

Step-by-step explanation:

Answer:

its b i took the test

Step-by-step explanation:

x - 9 ≤ 2(9 - x)

x - 9 ≤ 18 - 2x

3x - 9 ≤ 18

3x ≤ 27

x ≤ 9

(just handle it like an equation)

Answer:

(a)

[tex]\mu=54[/tex]    

The standard deviation is  

[tex]\sigma=6.6543[/tex]

(b)

[tex]\mu=246\\\sigma=6.6543[/tex]  

Here sample size is large and np and n(1-p) are both greater than 30. So we can use a normal approximation of binomial distribution. z-score for Y = 234.5 (using continuity correction) is  

[tex]z=-1.73[/tex]

So the approximate probability that at least 235 people in the sample will still be in the Rewards Program after the first four weeks is  

[tex]P(Y\geq 235)=P(Y\geq 234.5)=P(z\geq -1.73)=0.9582[/tex]

Step-by-step explanation:  

Let X is a random variable that shows the number of people who would drop out of the Rewards Program within four weeks. Here X has binomial distribution with parameters n = 300 and p = 0.18.

(a)  

The mean number of people who would drop out of the Rewards Program within four weeks in a sample of this size is  

[tex]\mu=np=300\cdot 0.18=54[/tex]  

The standard deviation is  

[tex]\sigma=\sqrt{np(1-p)}=\sqrt{300\cdot 0.18\cdot 0.82}=6.6543[/tex]  

(b)  

Let Y is a random variable that shows the number of people in the sample who will still be in the Rewards Program after the first four weeks. Here Y has a binomial distribution with parameters n= 300 and p=0.82. So mean of Y is  

[tex]\mu=np=300\cdot 0.82=246\\\sigma=\sqrt{np(1-p)}=\sqrt{300\cdot 0.18\cdot 0.82}=6.6543[/tex]  

Here sample size is large and np and n(1-p) are both greater than 30. So we can use a normal approximation of binomial distribution. z-score for Y = 234.5 (using continuity correction) is

[tex]z=\frac{Y-\mu}{\sigma}=\frac{234.5-246}{6.6543}=-1.73[/tex]  

So the approximate probability that at least 235 people in the sample will still be in the Rewards Program after the first four weeks is  

[tex]P(Y\geq 235)=P(Y\geq 234.5)=P(z\geq -1.73)=0.9582[/tex]

Answer:

The answer is "0.869"

Step-by-step explanation:

Number of sample [tex](n) = 84[/tex]

Number of correct response [tex](X) = 73[/tex]

Calculating the Sample proportion:

Formula:

[tex]\text{Sample proportion}=\frac{\text{number of sample}}{\text{correct responses}}[/tex]

                              [tex]=\frac{n}{X}\\\\= \frac{73}{84} \\\\=0.869[/tex]

Answer:

C

Step-by-step explanation:

Both models represent half of the gymnasium, its just that one is vertical and one is horizontal. Both are basically correct. C is the right answer since it says both models are correct. Each class also does occupy 1/12 of the gymnasium since they get 1/6 of 1/2 of the gymnasium. Of means multiply so 1/6 * 1/2 = 1/12.

Answer:

C, 14

Step-by-step explanation:

The factors of 42 are: 1, 2, 3, 6, 7, 14, 21, 42

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

The factors of 98 are: 1, 2, 7, 14, 49, 98

Then the greatest common factor is 14. (The greatest factor that they all have in common.)

Please vote brainliest, thanks!

Answer:

2nd one

Step-by-step explanation:

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

Answer:

A

Step-by-step explanation:

Answer:

y=6

the first equation:

3(1)+y=9

3+y=9

y=6

the second equation:

y= -4(1)+10

y= -4+10

y=6

I hope this helped! :)

Answer:

The approximate proportion of 1-mile long roadways with potholes numbering between 20 and 70 is 0.9735.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 50, standard deviation = 10.

Between 20 and 70.

The normal distribution is symmetric, which means that 50% of the measures are below the mean and 50% are above.

20

20 = 50 - 3*10

So 20 is 3 standard deviations below the mean. Of the 50% of the measures below the mean, 99.7% are within 3 standard deviations of the mean, that is, above 20.

70

70 = 50 + 2*10

So 70 is 2 standard deviations above the mean. Of the 50% of the measures above the mean, 95% are within 2 standard deviations of the mean, that is, below 70.

Percentage:

0.997*50% + 0.95*50% = 97.35%

As a proportion, 97.35%/100 = 0.9735.

The approximate proportion of 1-mile long roadways with potholes numbering between 20 and 70 is 0.9735.

Answer:

21:50

Step-by-step explanation:

We need to find the ratio of 420 m to 1 km.

We know that,

1 km = 1000 m

So,

The ratio becomes,

[tex]\dfrac{420\ m}{1\ km}=\dfrac{420\ m}{1000\ m}\\\\=\dfrac{42\ m}{100\ m}\\\\=\dfrac{21}{50}[/tex]

So, the required ratio is 21:50.

Answer:

a) In the interval of [1980,1983].

b) In the interval of [1991, 1996].

Step-by-step explanation:

Fuel efficiency:

The fuel efficiency, for the cars, in x years after 1980, is given by:

[tex]E(x) = 0.36x + 15.9[/tex]

15.9 is the fuel efficiency in 1980.

a. In what years was the average fuel efficiency for cars less than 17 mpg (in interval form)?

From 1980 to:

[tex]E(x) < 17[/tex]

[tex]0.36x + 15.9 < 17[/tex]

[tex]0.36x < 1.1[/tex]

[tex]x < \frac{1.1}{0.36}[/tex]

[tex]x < 3.06[/tex]

3.06 = 1980 + 3 = 1983. So

In the interval of [1980,1983].

b. In what years was the average fuel efficiency for cars more than 20 mpg (in interval form)?

From x until 1996.

[tex]E(x) > 20[/tex]

[tex]0.36x + 15.9 > 20[/tex]

[tex]0.36x > 4.1[/tex]

[tex]x > \frac{4.1}{0.36}[/tex]

[tex]x > 11.38[/tex]

11.38 = 1980 + 11 = 1991. So

In the interval of [1991, 1996].

Answer:

Solution given;

diameter[d]=12

we

have

circumference of circle=πd=12π

12 is a required answer.

_________

#LetsStudy

Answer: Hello your question is complete attached below is the complete question

answer :

P ( student will be admitted early or deferred and later admitted ) = 0.4232

Step-by-step explanation:

P ( student will be admitted early or deferred and later admitted )

 =  (number of student admitted early  +  percentage of admitted students initially deffered * number of deffered students ) / Total number of early applications  

 =  ( 1033 + 0.18 * 964 ) / 2851

 = 0.4232

Answer:

answers are 3 and 62

Step-by-step explanation:

the answers were give above. If further instruction needed lmk :)

Answer:

Triangle+ 83.25

Square/ Rectangle = 166.5

Step-by-step explanation:

I need the shape specified

Answer:

The Subtotal cost of all the cakes before tax and delivery

Step-by-step explanation:

(21x+8.25y)

21 is the price of 1 large cake and X is the number of cakes they want to purchase not counting tax and delivery fee.

8.25 is the price of 1 small cake and Y is the number of cakes they want to purchase not counting tax and delivery fee.

Answer:

yes

Step-by-step explanation:

Answer:

54cm and 36cm

Step-by-step explanation:

triangle a : triangle b

50cm² : 16cm²

25 : 8

thus,

area of triangle a :

2cm×25cm

=50cm²

area of triangle b :

2cm×16cm

=32cm²

then,

perimeter of triangle a:

2cm+2cm+25cm+25cm

=54cm

perimeter of triangle b:

2cm+2cm+16cm+16cm

=36cm

Answer:

sí, (yo) quiero un chocolate

Problem 5

------------------

Explanation:

We have these four identities

Notice how computing i^4 leads us back to 1. So i^4 = i^0. The pattern repeats every 4 terms. So we divide the exponent by 4 and look at the remainder. We ignore the quotient entirely. We can see that 28/4 = 7 remainder 0. Meaning that i^28 = i^0 = 1.

We can think of it like this if you wanted

i^28 = (i^4)^7 = 1^7 = 1

Then the sqrt(-36) becomes 6i

So overall, we end up with the final answer of 6i

=============================================

Problem 6

------------------

Explanation:

We'll use the ideas mentioned in problem 5

46/4 = 11 remainder 2

i^46 = i^2 = -1

sqrt(-9) = 3i

The two outside negative signs cancel out, but there's still a negative from -1 we found earlier. So we end up with -3i

In other words, here is one way you could write out the steps

[tex]-i^{46}*-\sqrt{-9}\\\\-i^{2}*-3i\\\\i^{2}*3i\\\\-1*3i\\\\-3i\\\\[/tex]

=============================================

Problem 7

------------------

Work Shown:

i^10 = i^2 because 10/4 = 2 remainder 2

i^19 = i^3 because 19/4 = 4 remainder 3

i^7 = i^3 because 7/4 = 1 remainder 3

Again, all we care about are the remainders.

[tex]i^{10}+i^{19} - i^{7}\\\\i^{2}+i^{3} - i^{3}\\\\i^{2}\\\\-1[/tex]

=============================================

Problem 8

------------------

Work Shown:

i^22*i^6 = i^(22+6) = i^28

Earlier in problem 5, we found that i^28 = i^0 = 1

So,

[tex]i^1 - \left(i^{22}*i^{6}\right)\\\\i^1 - i^{28}\\\\i^1 - i^{0}\\\\i - 1\\\\-1+i[/tex]

Answer:

Your answer is correct

Step-by-step explanation:

B. 112 degrees

Answer:

x = 112

Step-by-step explanation:

x and 68 are supplementary angles so they add to 180

x+68 = 180

x = 180 -68

x = 112

Answer:

15x+30y-220

Step-by-step explanation:

Answer:$221

Step-by-step explanation:

Divide 289 by 17

Get 17, then multiply by 13.

Answer:

$221

Step-by-step explanation:

Use unit rates. First find out how much money Rita makes per hour. To do this, simply divide 289/17=17. Rita makes $17 per hour. We want to find out how much money she makes in 13 hours of work. So, we just need to multiply 17$*13=$221

Hope this helps!

Answer:

y = 100

Step-by-step explanation:

y [tex]\alpha[/tex] [tex](x -1)^{2}[/tex]

y = c ([tex]x^{2}[/tex] - 2x + 1)

When y = 63, x = 4;

63 = c ([tex]4^{2}[/tex] - 2(4) + 1)

     = 9c

63 = 9c

c = [tex]\frac{63}{9}[/tex]

c = 7

Thus,

y = 4([tex]x^{2}[/tex] - 2x + 1)

The value of y when x = 6 can be determined as;

y = 4([tex]6^{2}[/tex] - 2(6) + 1)

   = 4(25)

y = 100

Therefore, y = 100