Do) 13. Which image BEST represents our galaxy?

Answer: B. Evolution

Explanation:

As species grow older over time they will gradually evolve through natural selection and evolution.

The gradual change in a species over time is known as evolution (b).

The process of evolution occurs through several mechanisms, including mutation, migration, and natural selection.

Mutation (a) is the spontaneous change in the genetic material of an organism. These changes can result in new traits that may be advantageous, disadvantageous, or neutral for survival. When mutations occur, they can introduce genetic variation within a population, which serves as the raw material for evolution.

Natural selection is a crucial factor driving evolution. Individuals with advantageous traits that better suit their environment are more likely to survive and reproduce, passing on these advantageous traits to their offspring. Over generations, the frequency of beneficial traits increases in the population, leading to the adaptation and evolution of the species.

Variation (d) encompasses the differences in physical traits and genetic makeup among individuals within a population. This variation is essential for evolution to occur since it provides the raw material for natural selection to act upon.

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Answer: A chemical formula is a way of showing and representing information about a chemical proportion of atoms that constitute a particular chemical compound or molecule

Answer:

12

Explanation:

12

Answer:

you could hurt yourself

Explanation:

Answer

You should never do an exercise such as the bench press without a spotter because you could hurt yourself or push your self too much.

Explanation:

Answer:

Explanation:

A: wrong. Mass and weight are different.

B: Wrong. The mass here and the mass on the moon are the same. The weight, which is Mass * the acceleration  is equal to weight.

C: Correct.

D: Wrong. Weight is not measured in Kg. Mass is.

Answer:

Problem 1-

The acceleration = 5 m/s²

Problem 2 -

The acceleration = 3.[tex]\overline 3[/tex] m/s²

Problem 3 -

The acceleration = 2.5 m/s²

Problem 4-

The force applied = 7.5 N

Problem 5-

The mass of the object,  = 0.5 kg.

Explanation:

Problem 1-

The mass of the ball, m = 0.5 kg

The force (applied) with which it was hit, F = 2.5 N

The acceleration, a = Force/Mass = 2.5 N/(0.5 kg) = 5 m/s²

The acceleration = 5 m/s²

Problem 2 -

The mass of the box, m = 15 kg

The force (applied) with which it was hit, F = 50 N

The acceleration, a = Force/Mass = 50 N/(15 kg) = 10/3 = 3.[tex]\overline 3[/tex] m/s²

The acceleration = 3.[tex]\overline 3[/tex] m/s²

Problem 3 -

The mass of the object, m = 2.0 kg

The force (applied) with which it was hit, F = 5.0 N

The acceleration, a = Force/Mass = 5.0 N/(2.0 kg) = 2.5 m/s²

The acceleration = 2.5 m/s²

Problem 4-

The mass of the object, m = 3.0 kg

The acceleration, a, of the object = 2.5 m/s²

The force applied to it, F = Mass × Acceleration = 3.0 kg × 2.5 m/s² = 7.5 N

The force applied = 7.5 N

Problem 5-

The acceleration, a, of the object = 12 m/s²

The force applied, F = 6.0 N

The mass of the object, m = Force/Acceleration = 6.0 N/(12 m/s²) = 0.5 kg

The mass of the object,  = 0.5 kg.

Answer:

50 or 1.3333

Explanation: Explanation you cancel out the mass and the force to see what your acceleration would be or you could divide F by M

Answer:

the shortest path between two points is displacement..

Explanation:

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Answer:

A magnetic force can convert kinetic energy stored in a magnetic field to potential energy. Kinetic energy can convert potential energy stored in a gravitational field. A magnetic energy can convert potential energy stored in a gravitational field to kinetic energy.

Answer: Got this from a web search... Change the answer up a bit

Explanation:

The distance travelled is the path taken by a body to get from an initial point to an end point in a given period of time, at a certain velocity. If the velocity is constant: Distance = time * velocity. d = v*t.

Answer:

I researched and found it to be TIME * VELOCITY ( d= v*t)

Explanation:

When I use * I just mean multiply. So its time 'multiplied by velocity' in order to get 'distance'

Answer:

weight=mass*gravity

weight=10.0*10

so weight=100N

Answer:

B) 15 m/s

Explanation:

Since most of the answer choices are in m/s, you can try dividing 60 meters/4 seconds in order to get the seconds on the bottom to become 1 second.

You want to find how many meters the object can travel in 1 second, rather than 4 seconds.

Now you can see that for every 1 second of time, the object can travel 15 meters. This corresponds to answer choice B) 15 m/s.

The last option, D, is incorrect because we are not dealing with hours as our unit of time. We are dealing with seconds.

Answer:

b) 15 m/s

hope it help you

Answer:

serial in which container is filled

Solid -base of container

Liquid- above solid

Gas- above liquid

Explanation:

If any mixture of  matter in different state (that solid , liquid or gas )are kept in any container, then substance with higher density will be settled at lowest surface first and similarly the substance with lowest density will be at upper part of container.

In the given container we have to keep solid, liquid and gas

based on this

solid will be at surface of container

above sold will be liquid

above liquid will be presence of Gas

serial in which container is filled

Solid -base of container

Liquid- above solid

Gas- above liquid

Answer:B) Frequency

Explanation:

Answer:

B) Frequency

Explanation:

Answer:

[tex]a \: = \frac{v - u}{t} [/tex]

2 = v-0/2.9

2× 2.9 = v

v = 5.8 m/s

[tex]v \: = \frac{d}{t} [/tex]

5.8 = d/2.9

5.8×2.9 = d

d = 16.82 m

Answer:

q + d = 50

25q + 10d = 980

Explanation:

The equation that can be employed to determine the number of quarters(q), as well as, dimes(d) that Yodelin has would be:

q + d = 50...(1)

25q + 10d = 980...(2)

Multiplying (1) by 25

25q + 25d = 1250 ...(3)

25q + 10d = 980...(4)

subtracting (4) from (3)

15d = 270

d = 18

q = 50 - 18

    = 32

The system of the equations could be

q + d = 50

25q + 10d = 980

Since Yodelin has fifty quarters and dimes. Their total value is $9.80.

So here the equations be

q + d = 50...(1)

25q + 10d = 980...(2)

Now we have to Multiplying (1) by 25

So,

25q + 25d = 1250 ...(3)

25q + 10d = 980...(4)

Now

subtracting (4) from (3)

15d = 270

d = 18

So,

q = 50 - 18

   = 32

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Answer:

B) Decreases

Explanation:

Gravitational force is inversely proportional to distance. As distance between 2 objects increase, gravitational force between the 2 objects decreases.

Hope this helps!

Answer:

The answer would be B

Explanation:

Answer: A,B, and E

Explanation: Just checked I got them right:)

Answer:

yes absolutely

Explanation:

why not

Answer:

16 is d and i have no idea for 17

Answer:

1) t_total = 140 min ,  v = 126.7 m / min ,  2)  v = 0.628 m / s ,

3) v = 0.592 m / s ,  θ = -39.3 º

Explanation:

Here we have some short kinematics problems

1) d₁ = 4200 m at T1 = 25 min

    d₂ = 4.54 km at t2 = 1 h

    d₃ = 9000 m at t3 = 55 min

of the statement the direction of each route is the same

Let's reduce the distances to the SI system

     d₂ = 4.54 km (1000 m / 1 km) = 4540 m

     t₂ = 1 h (60 min / 1 h) = 60 min

Total time is

    t_total = t1 + t2 + t3

   t_total = 25 + 60 +55

   t_total = 140 min

the distance is

    d_total = 4200 + 4540 +9000

     d_total = 17740 m

with movement it is in one dimension and all displacement is in the same direction, distance equals displacement.

Speed ​​is

       v = 17740/140

       v = 126.7 m / min

in the direction of travel

Speed ​​is the modulus of speed

        | v | = 126.7 m / min

2) the angular velocity is

        w = θ / t

In this exercise

        t = 2 min (60 s / 1min) = 120 s

        θ = 30 rev (2π rad / 1 rev) = 60π rad

         w = 60π / 120

         w = 1.57 rad / s

linear velocity  is

        v = w r

        v = 1.57 0.40

        v = 0.628 m / s

velocity is the speed tangential to the  trajectory

3) the data for this exercise are

     distance = (number of steps) (distance of one step)

         d₁ = 500 0.40 m = 200 m West

         d₂ = 400 0.35 m = 140 m North

         d₃ = 300 0.30 m = 90 m East

in a total time of t = 2 min and 120 s

           t = 2  60 + 120 = 240 s

the distance traveled is

x axis we assume the direction towards + x (East) positive

           x_total = d₃ -d₁

           x_total = 90-200 = -110 m

y axis  

          y_total = d₂

          y_total = 140 m

we use the Pythagorean theorem to find the distance0

           D = √ (x_total² + y_total²)

           D = √ (110² + 90²)

           D = 142.13 m

The speed is

           v = D / t

            v = 142.13 / 240

           v = 0.592 m / s

speed is

           v = 0592 m / s

           tan θ = Y / X

           θ = tan -1 y / x

           θ = tan -1 (90 / (- 110))

           θ = -39.3 º

4) This angle is measured on the positive side of the x axis in a clockwise direction

          θ = 1.5 rev (2π rad / 1 rev) = 3π rad

           t = 90 s

the angular velocity is

           w = θ / t

           w = 3πi / 90

           w = 0.1047 rad / s

the speed is

            v = w R

            v = 0.14047 250

            v = 26.17 m / s

velocity is tangent to path

Answer:

The components of the net force acting on the cart are;

Horizontal force, Fₓ ≈ 23.5 N acting east

The vertical force, [tex]F_y[/tex] ≈ 76.96 N

Explanation:

The parameters given in the question are;

The magnitude of the force on the rope acting horizontally to the west = 75 N

The magnitude of the force on the other rope east acting at an angle to the horizontal = 125 N

The angle to the horizontal of the force on the other rope east to the horizontal = 38°

Therefore, we have;

The horizontal component of the force acting east = 125 × cos(38°) ≈ 98.5 N

The net sum of the horizontal forces, ∑Fₓ noting that the horizontal forces are acting in opposite direction is given as follows;

∑Fₓ = 75 - 125 × cos(38°) = 75 - 98.3 = -23.5N

Given that the difference in forces is negative, and hat we took the force acting east as negative, we have that the net horizontal force is acting east with a horizontal component of 23.5N

The net vertical force, ∑F[tex]_y[/tex], is given as follows;

∑F[tex]_y[/tex] = 125 × sin(38°) ≈ 76.96 N

Therefore, the components of the net force acting on the cart are;

Horizontal force, Fₓ ≈ 23.5 N, the vertical force, [tex]F_y[/tex] ≈ 76.96 N

The components of the net force on the cart are 23.5 Newton and 76.96 Newton.

Given the following data:

To find the components of the net force on the cart:

First of all, we would determine the horizontal component of the force acting due east.

[tex]F_y = Fcos(\theta)\\\\F_y = 125cos(38)\\\\F_y = 125 \times 0.7880\\\\F_y = 98.5 \; Newton[/tex]

Next, we would find the resultant horizontal forces:

[tex]\sum F_y = F + F_y\\\\\sum F_y = 75 + (- 98.5)\\\\\sum F_y = -23.5 \;Newton[/tex]

Therefore, the horizontal component of the net force acts in the opposite direction due east.

Horizontal component of the net force = 23.5 Newton

For the vertical component of the net force:

[tex]\sum F_x = Fsin(\theta)\\\\\sum F_x = 125cos(38)\\\\ \sum F_x = 125 \times 0.6157\\\\ \sum F_x = 76.96\; Newton[/tex]

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Answer:

Displacement is 42.426 m NE and the angle is opposite/adjacent or 30/30 which would equal 1 degree which doesn't seem right but hopefully its an answer.

Explanation: