An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability that it will not be enough seats to accommodate all passengers. Assume that the probability that a randomly selected passenger shows up to the airport is 0.96. Find the probability using the normal distribution as an approximation to the binomial distribution.

Answers

Answer 1

Answer:

The probability is   [tex]P(X  >300 ) = 0.97219 [/tex]

Step-by-step explanation:

From the question we are told that

 The capacity of  an Airliner  is  k =  300 passengers

 The sample size n =  320 passengers

  The probability the a randomly selected passenger shows up on to the airport

    [tex]p = 0.96[/tex]

Generally the mean is mathematically represented as

    [tex]\mu  =  n*  p[/tex]

  => [tex]\mu  =  320 *  0.96[/tex]

    => [tex]\mu  = 307.2[/tex]

Generally the standard deviation is  

    [tex]\sigma =  \sqrt{n *  p *  (1 -p ) }[/tex]

=>  [tex]\sigma =  \sqrt{320  *  0.96 *  (1 -0.96 ) }[/tex]

=> [tex]\sigma =3.50 [/tex]

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

  [tex]P(X  > k ) =  P( \frac{ X -\mu }{\sigma }  >  \frac{k - \mu}{\sigma } )[/tex]

Here [tex]\frac{ X -\mu }{\sigma }  =Z (The \ standardized \  value \  of  \ X )[/tex]

=>[tex]P(X  >300 ) =  P(Z >  \frac{300 - 307.2}{3.50} )[/tex]

Now applying  continuity correction we have

    [tex]P(X  >300 ) =  P(Z >  \frac{[300+0.5] - 307.2}{3.50} )[/tex]    

=>    [tex]P(X  >300 ) =  P(Z >  \frac{[300.5] - 307.2}{3.50} )[/tex]

=>    [tex]P(X  >300 ) =  P(Z >  -1.914 )[/tex]

From the z-table  

    [tex]P(Z >  -1.914 ) =  0.97219[/tex]

So

    [tex]P(X  >300 ) = 0.97219 [/tex]


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(you can include my example too depending on what your teacher is looking for)

Step-by-step explanation:

This is a fun one! Think about a ball rolling on a smooth surface, now on a bumpy sandpapery one. Which one do you think is faster? The smooth surface! This is because of this friction of the sandpaper which slows down the ball. On the other hand, the smooth one has very little friction. The same applies to cars.

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Mass - Something that measures the amount of matter in a substance or an object.
Volume - The quantity of three-dimensional space enclosed by a closed surface.
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An airplane maintaining a constant airspeed takes as long to travel 925 mi with wind as it does to travel 775 mi against the wind. If the wind is blowing at 15 mph, what is the rate of the plane in still air

Answers

9514 1404 393

Answer:

  170 mph

Step-by-step explanation:

The speed of the airplane can be represented by s. The travel time will be ...

  time = distance/speed

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Answers

answer:

Juanita spent 1 1/2 times as much as Jared, how much did she spend?

$63

explanation:

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the answer is Juanita spent $63!

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Answers

Answer:

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The total cost of Anya's purchase of home improvement hardware is 132.74  dollars.

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Step-by-step explanation:

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Answers

Answer:

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Answers

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Labor costs. Labor costs for a farmer are $55 per acre for corn and $45 per acre for soybeans. How many acres of each crop should the farmer plant if he wants to spend no more than $6,900 on labor?

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Step-by-step explanation:

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How many solutions does the system of equations below
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Answers

Answer:

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Step-by-step explanation:

The Fashion Store has $6000 available each month for advertising. Newspaper ads cost $200 apiece and no more than 20 can be run per month. Radio ads cost $100 each and no more than 30 can run per month. TV ads cost $800 a piece, with a maximum of 7 available each month. Approximately 1000 women will see each newspaper ad, 800 will hear each radio ad, and 14,000 will see each TV ad. How much of each type of advertising should be used if the store wants to maximize exposure?

Answers

9514 1404 393

Answer:

7 TV ads4 radio ads

Step-by-step explanation:

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  Radio: 800/$100 = 8/$

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__

To maximize exposure, the advertising budget should be spent this way:

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