Distance and Displacement Worksheet

When rotating the device 360 degrees, as long as the does not extend outside the base of stability, the apparatus should remain stable: gravity circle.

The Centre of gravity is a theoretical point in the body where the body’s total weight is thought to be concentrated. It is important to know the centre of gravity because it predicts the behaviour of a moving body when acted on by gravity. It is also useful in designing static structures such as buildings and bridges.

In a uniform gravitational field, the centre of gravity is identical to the centre of mass. Yet, the two points do not always coincide. For the Moon, the centre of mass is very close to its geometric centre. However, its centre of gravity is slightly towards the Earth due to the stronger gravitational force on the Moon’s near side.

In a symmetrically shaped object formed of homogenous material, the centre of gravity may match the body’s geometric centre. However, an asymmetrical object composed of various materials with different masses is likely to have its centre of gravity located at some distance away from its geometric centre. In hollow bodies or irregularly shaped bodies, the centre of gravity lies at a point external to the physical material.

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A point charge of 0.06 c at coordinates (0, 0) will create an electric field at coordinates (2.3, -4.1), which will be directed away from the charge and whose magnitude will decrease as distance from the charge rises.

A point charge generates an electric field that is inversely proportional to the square of the distance from the charge. The electric field at that location will have non-zero x and y components because the point charge is at coordinate (0, 0) and the field is being assessed at coordinate (2.3, -4.1). As the distance from the charge grows, the magnitude of the electric field will diminish. The vector pointing from charge to the location where we wish to locate the E-field may be used to calculate the direction of the electric field at (2.3,-4.1).

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From pressure definition,  the area of the car tires that are in contact with the road is 0.079 m

Pressure can be defined as the ratio of force to area. It is measured in Pascal.

Given that a car weighs 15,000 N and its tires are I flared to a pressure of 190 kPa. How large is the area of the cars tires that are in contact with the road ?

From the definition of Pressure, P = F/A

Where

190000 = 15000/A

A = 15000/190000

A = 0.079 m

A car will have 4 tires. The area of one in contact with the road will be

A = 0.079/4

A = 0.02 m

Therefore, the area of the car tire that is in contact with the road is 0.02 m

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"I understand how to properly use the PEFM to measure my peak expiratory flow and will use it daily to track my lung function," the newly diagnosed asthmatic states in the statement.

Option B is correct.

A peak flow meter measures how quickly you can expel air from your lungs by blowing as forcefully and quickly as you can. This is what peak flow means.

This drop indicates the possibility of an asthma attack. You can figure out what "triggered" the drop in blood pressure by measuring your peak flow, which medications to add or take off, and when you might need emergency care.

A peak flow meter is simple to use. How to figure out your peak flow:

which statement shows that the newly diagnosed asthma patient understands how to use a peak expiratory flow meter (pefm)?

A. Wear gloves during blood glucose monitoring and during any other procedure that involves potential exposure to blood or body fluids.

B. "I understand how to properly use the PEFM to measure my peak expiratory flow and will use it daily to track my lung function."

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The P-waves are the primary waves that are the fastest and the first to arrive at the seismometer.

Seismic waves, which are vibrations caused by the movement of the Earth's crust, are recorded at various locations after an earthquake has occurred. The type of seismic waves recorded at a particular location depends on its distance from the epicenter (point X) of the earthquake.

There are two main types of seismic waves: body waves and surface waves. Body waves, such as P-waves and S-waves, travel through the Earth's interior and can be recorded at any location. Surface waves, such as Love waves and Rayleigh waves, travel along the Earth's surface and are typically recorded closer to the epicenter.

The P-waves are the primary waves that are the fastest and the first to arrive at the seismometer. The S-waves are the secondary waves that are slower and arrive later than P-waves.

In general, the closer a location is to the epicenter, the stronger and more frequent the seismic waves will be.

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Power (in watt) will he use to do the same amount of work in three times the time:

m=100 kgg=10 m/sh=10 m

W=mgh=100×10×10=10000 J

P= t/W

10000/20​

=500 W

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The amount of alcohol consumed will be b. independent variable when participants are tested in a driving simulator after and get a score for accuracy.

What is an Independent variable?

An independent variable is a variable that is manipulated or changed by the researcher in an experiment in order to observe its effect on the dependent variable. In other words, it is a variable that the researcher has control over and changes to test its impact on the outcome.

In this case, the independent variable is the amount of alcohol consumed, as the researcher is manipulating this variable to see how it affects driving performance (the dependent variable).

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The new acceleration of the barrel rider if the speed is doubled is 14.4m/s².

Acceleration in physics refers to the amount by which a speed or velocity increases i.e. the change of velocity with respect to time.

The acceleration of a moving body is directly proportional to the speed of that body i.e. an increase in speed equates to an increase in acceleration.

According to this question, a barrel rider is moving in a circle with a speed of 7.0 m/s. The acceleration of the rider is 7.2 m/s². However, the speed of the object is somehow increased to 14.0 m/s.

This suggests that the acceleration of the rider will also be doubled and hence, be 14.4m/s².

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The reason for the modest preference for 1/2 kx2 is that you only need to measure one variable—the displacement x—in order to identify the stored energy. Utilizing 1/2 F/x necessitates measuring both displacement and force, which is frequently difficult to do.

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Answer:

Explanation:

he modulus of elasticity (E) can be calculated using the formula:Stress = Force / AreaStrain = Change in length / Initial lengthModulus of Elasticity (E) = Stress / StrainWe have the Force = 8000 N, Area = 0.7 m^2, Change in length = 0.002 m and initial length = 5 in = 0.127 mStress = Force / Area = 8000 N / 0.7 m^2 = 11428.57 N/m^2Strain = Change in length / Initial length = 0.002 m / 0.127 m = 0.0157Modulus of elasticity (E) = Stress / Strain = 11428.57 N/m^2 / 0.0157 = 727,279.9 N/m^2So the modulus of elasticity for the material of the bar is 727,279.9 N/m^2This is the ratio of the applied stress to the corresponding strain within the elastic limit, which is a measure of a material's resistance to deformation.

The maximum possible energy loss of the photon is 2.7 x 10-14 J, which is much less than the energy of the photon, 7.3 x 10-19 J.

To Calculate the energy of the photon.

E = hc/λ

E = (6.626 × 10-34 J · s)(3.00 × 108 m/s)/(29 x 10-12 m)

E = 7.3 x 10-19 J

To Calculate the maximum possible energy loss of the photon.

Max energy loss = 2m el (c2)

Max energy loss = 2(9.11 x 10-31 kg)((3.00 x 108 m/s)2)

Max energy loss = 2.7 x 10-14 J

Compare the energy of the photon and the maximum possible energy loss.

Hence, maximum possible energy loss of the photon is 2.7 x 10-14 J, which is much less than the energy of the photon, 7.3 x 10-19 J.

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The Earth's orbit around the Sun is almost circular, therefore, Earth receives about same amount of year-round a.) heat and light

Earth's orbit defines a two-dimensional plane which we call the ecliptic. It takes almost 365 days for the Earth to go around the Sun once.

The Earth's orbit around the Sun is almost circular, Thus, Earth receives about the same amount of year-round sunlight (or known as  solar energy).

Earth's orbit is not a perfect circle and is elliptical, or slightly oval-shaped. This means that there is one point in the orbit where Earth is closest to the Sun, and one where Earth is farthest from the Sun.

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Answer:

KE

Explanation:

It has KE only because it is in motion, but 0 GPE because it is on the ground.  For it to have any GPE it would have to be at some height above the ground.

The Spring constant k (Stiffness ) will be 6.8 Ib/in for the spring which has an unstretched length of 8 in for 10 lb when d = 4in as given in the problem.

As shown in the picture attached the net force on the y-axis is 0. And Fab*4/[tex]\sqrt{160\\}[/tex]} = 10

Fab = 31.61 Ib.

Fab = K(L-L0)

31.62 = k ([tex]\sqrt{160}[/tex] -8 => 6.8 Ib/in

As spring force is a conservative force where each spring has its own k(Spring constant ) which depends upon the material, Turns, and Size of the spring. To calculate Spring force F = -kx, where k is constant and x, is the length displayed by the force (Stretched or unstretched). The Force might be affected by the temperature around as of material used for making the spring.

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The final velocity of plank with respect to the ice will be (-Mg×Vgp)/(Mg+Mp) and it will be in direction opposite to the girl.

Mass of the girl, = Mg

Mass of the plank, = Mp

Velocity of the girl with respect to plank, = Vgp

Velocity of the plank with respect to ice, = Vpi

Velocity of girl with respect to ice, = Vgi

Initially both girl and the plank were at rest with respect to ice, so initial momentum of both was zero. So final momentum of both with respect to ice will be zero.

Mg×Vgi + Mp×Vpi = 0

Mg×Vgi = -Mp×Vpi .....equation (1)

We know that velocity of girl with respect to the ice will be the sum of velocity of the girl with respect to the plank and the velocity of the plank with respect to the ice.

Vgi = Vpi + Vgp.... put this value in equation (1)

Mg×(Vpi + Vgp) = -Mp×Vpi

Mg×Vpi + Mg×Vgp) = -Mp×Vpi

Vpi(Mg + Mp) = -Mg×Vgp

Vpi = -Mg×Vgp/(Mg + Mp)

A negative sign indicates that the velocity of the plank will be in the opposite direction to the girl.

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--The give question is incomplete, the complete question is:

"A girl of mass Mg is standing on a plank of mass Mp. Both are originally at rest on a frozen lake that constitutes a frictionless, flat surface. The girl begins to walk along the plank at a constant velocity Vgp to the right relative to the plank. (The subscript gp denotes the girl relative to the plank.)

What is the velocity Vpi of the plank relative to the surface of the ice? (Use the following as necessary: Vgp, Mg, and Mp. Indicate the direction with the sign of your answer. Let the positive direction be in the direction that the girl walks.)"--

Answer:

66 m/s

Explanation:

Since momentum of the body is conserved

mv=mv

0.25 kg×66m/s=0.25 kg×v

v =0.25kg×66m/s

0.25 kg

v =66m/s

An object can encounter some resistance when moving through the fluid medium of air.

The drag force is the oppositional force applied by the air to a moving object. The size of the cross section A of the front face of the item, the density of the air, and the square of the object's velocity v all contribute to the drag force.

With motion exclusively in the vertical direction and letting

downward be positive, we have that

dv/dt = g - pv, where g = 32 ft/[tex]s^{2}[/tex], and so

dv/dt + pv = g. The integrating factor is [tex]e^{(pt)}[/tex], so

d/dt([tex]e^{(pt)}[/tex] * v) = g×[tex]e^{(pt)}[/tex] ----->

[tex]e^{(pt)}[/tex] * v = (g/p)*[tex]e^{(pt)}[/tex] + C ----->

v(t) = (g/p) + C×[tex]e^{(pt)}[/tex]

Now v(0) = (g/p) + C = 0, and so C = -g/p, giving us

v(t) = (g/p)×(1 - [tex]e^{(pt)}[/tex]).

Now we are given that lim(t->infinity)(v(t)) = 99 mi/h = 145.2 ft/s,

so since [tex]e^{(pt)}[/tex]-> 0 as t -> infinity we have g/p = 145.2 ft/s ------>

p = 32 ft/s^2 / (145.2 ft/s) = 0.2204 s^-1 .

Next, since we have defined downward as positive, the expression

we have for v(t) will equal dy/dt where y(0) = 0 and y increases as

the paratrooper falls. So

dy/dt = v(t) = (g/p)×(1 - [tex]e^{(pt)}[/tex])), so

y(t) = (g/p)×(t + (1/p)×[tex]e^{(pt)}[/tex]) + K.

Now y(0) = (g/p)×(0 + (1/p)) + K = 0 ----->

K = -(g/p^2) = 32 / 0.2204^2 = -658.76 ft, so

y(t) = (145.2)×(t + (4.5372)×e^(-0.2204×t)) - 658.76.

Next, y(6) =  (145.2)×(6 + (4.5372)×e^(-0.2204×6)) - 658.76 = 444.84 feet.

The computed drag coefficient is substantially higher than anticipated.

The free fall distance is the longest distance an individual can travel in a predetermined amount of time. However, the distance covered in the time frame indicated in the news report is significantly greater than the greatest distance that could be covered. Consequently, the news story is exaggerated.

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After colliding, the two objects come to rest together, preserving momentum but not kinetic energy. Some motion energy is transformed to thermal energy, or heat.

A collision occurs in physics when particles, groupings of particles, or solid entities move toward one other and get close enough to interact and exert mutual effect. When two bodies come into direct touch with each other, this is referred to as a collision. The two bodies exert pressures on each other in this situation in a brief period of time. As a result of the collision, the energy and momentum of the bodies involved change. However, there are three types of collisions: elastic, inelastic, and absolutely inelastic. To summarize, momentum is preserved in all three types of collisions. What happens to the kinetic energy is what characterizes the impacts.

Here,

The two objects collide and come to rest together, retaining velocity but not kinetic energy. Some motion energy is converted to thermal energy, often known as heat.

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Since parallax is a difference inside this apparent position of an item when viewed along two separate lines of sight, a very wide gap between perspectives (referred to as the baseline) is necessary to detect a parallax shift in a far-off object.

An object's position changing due to your motion is known as parallax. For instance, if you gaze at a close object and tilt your head slightly to the side, the thing appears to be moving back and forth.

One of the most crucial techniques astronomers use to determine distance is parallax. It is incredibly precise but can only be used for close stars. By calculating how close an object is, the technique appears to move against the background of more distant objects.

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Answer:

A paradox is a statement, proposition, or situation that seems illogical, absurd or self-contradictory, but which, upon further scrutiny, may be logical or true — or at least contain an element of truth. Paradoxes often express ironies and incongruities and attempt to reconcile seemingly opposing ideas.

Explanation:

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It will take approximately 8.3 minutes for light to travel from the Earth to 1 AU

The speed of light is a constant value of about 300,000 km/sec. To find out how long it will take light to travel to 1 AU (which is about 150 million km), we can use the formula:

Time = distance/speed

So we can substitute the values into the formula:

time = 150 million km / 300,000 km/sec

By solving the equation we get:

time = 500 seconds or approximately 8.3 minutes

Therefore, it will take approximately 8.3 minutes for light to travel from the Earth to 1 AU, which is the average distance between the Earth and the Sun.

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The correct option is B. Earth is the size of the tip of the ballpoint pen about 15 metres away from the Sun.

Radius of the sun = 7× 10⁸ m

Radius of the earth = 6.37 × 10⁶ m

Radius of the grape fruit = 7.6 × 10⁻² m

As the sun is said to be the size of the grapefruit, scale = (7.6 × 10⁻²)/(7× 10⁸) = 10⁻¹⁰

This means the scale is approximately, 1: 10⁻¹⁰

So, the size of the earth = 6.37× 10⁶ ×10⁻¹⁰ = 6.37×10⁻⁴ m (size of ballpoint)

As we know that the distance between the sun and the earth = 14.9 × 10¹⁰ m

So, in our scale, distance between the sun and the earth = 14.9× 10¹⁰× 10⁻¹⁰  = 14.9 m

which is approximately 15 meters.

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The Power is equal to 300 J/s or 300 Watts.

A force that causes a displacement is what the term "quantity work" refers to. The duration of this force's action to produce the displacement has nothing to do with work or power. Sometimes the task is completed quite fast, and other times it is completed fairly slowly. For instance, it takes an unusually long time for a rock climber to raise her body a few meters up the cliff's edge. A trail hiker, on the other hand, could quickly raise her body a few meters if she chooses the simpler route up the mountain. Even though they both perform the same amount of labor, the hiker completes it in a lot less time than the rock climber.

The formula for power is ( P = [tex]\frac{W}{t}[/tex] ) or ( P = [tex]\frac{m \times a \times d}{t}[/tex]  )

m ( mass ) = 60 kg

a ( acceleration ) = 10 m/s²

d ( distance ) =  5 m

t ( time ) = 10 s

P ( Power ) = ?

P = [tex]\frac{m \times a \times d}{t}[/tex]

= [tex]\frac{60\times 10 \times 5}{10}[/tex]

= [tex]\frac{3000}{10}[/tex]

= 300 J/s

= 300 Watts

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It's initial speed is 308 m/s.

The kinetic energy of the bullet is converted to potential energy for the whole system therefore we have:

                                [tex]\frac{1}{2}(m_{1} + m_{2} )V^{2} = (m_{1} + m_{2} )gh[/tex]

                                              i.e. [tex]V = \sqrt{2gh}[/tex]

Now by conservation of momentum,

[tex]m_{1} v = (m_{1}+ m_{2} )V[/tex]

[tex]v = (m_{1}+ m_{2} )V / m_{1}[/tex]

[tex]v = (m_{1}+ m_{2} )\sqrt{2gh} / m_{1}[/tex]

Where,

v = initial speed

m1 = mass of pendulum = 2 kg

m2 = mass of bullet = 10 g = 0.01 kg

h = vertical distance = 12 cm = 0.12m

Putting these values in above equation we get : V  = 308 m/s

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The labeled parts of microscope that you would adjust to move the specimen left, right, forward, and backward are called the stage controls.

Microscope is an instrument that is used to observe small objects, even the cells. The lens bends light toward the eye and makes object appear larger than it actually is.

The stage controls consist of two knobs, one for moving the specimen left and right (x-axis), and one for moving specimen forward and backward (y-axis). The knobs are located on the lower part of the microscope's base, near stage where the specimen is placed. These controls allow you to position specimen correctly under the objective lens for observation.

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The wave speed is 01 m/s, which can be calculated by using the formula:

wave speed distance between two successive maxima/time interval between two successive maxima

In this case, the distance between two successive maxima is given as 1.2m and the time

interval between two successive maxima is given as 12s.

So, the wave speed can be calculated as:

wave speed = 1.2m/12s = 0.1 m/s

It is worth mentioning that the wave speed is a scalar quantity, which means it has only magnitude and no direction. The given information is about the transverse wave which is a type of wave in which the oscillation is perpendicular to the direction of energy transfer

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An electron is moving to the right with an initial speed of vo = 3.5 x 10E7 m/s when it enters a

region of space that is L = 3.3 cm wide with a uniform electric field pointing down of magnitude

E = 8.2E4 N/C. The electron will experience electric field

The electron will experience a force due to the electric field, which is given by the equation F = qE, where q is the charge of the electron (a negative value) and E is the electric field.

The force will cause the electron to accelerate in the direction of the field, which is opposite to its initial direction of motion. The acceleration of the electron can be calculated using the equation a = F/m, where m is the mass of the electron.

The distance the electron will travel before it exits the region of space can be calculated using the equation x = v_0t + 0.5a*t^2, where v_0 is the initial velocity and t is the time it takes for the electron to travel through the region.

Therefore, the correct answer is as given above

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The complete question goes thus:

An electron is moving to the right with an initial speed of vo = 3.5 x 10E7 m/s when it enters a

region of space that is L = 3.3 cm wide with a uniform electric field pointing down of magnitude

E = 8.2E4 N/C. What will happen to the electron?

The agents or mechanisms which are not testable, and therefore cannot provide a scientific explanation are spiritual beliefs.

Spiritual beliefs pertain to an existentialist view of life, death, and the essence of existence and involve a connection to a higher power. These  beliefs also include ceremonies and behaviours like meditative practices or prayer as well as interaction with other believers.

Global warming is the gradual heating of the Earth's surface that has been seen ever since pre-industrial era (between 1850 and 1900), and is attributed to human activity, particularly the combustion of fossil fuels, which raises the concentrations of heat-trapping greenhouse gases.

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Answer:

Only protons and neutrons contribute to the mass of an atom.

Explanation:

The frequency would be 1/2pi [tex]\sqrt{\frac{pE}{I}}[/tex].

We know that,

Tau=-pEsinФ captures the sense

and the size of the effect.

This is the restoring torque to return the tilted dipoles to their aligned equilibrium position.

If the amplitude of movement is small,

we may replace sinθ with θ in radians.

Thus τ≈−pEθ.

Since this has a simple negative proportionality to the angle of rotation, the dipole oscillates in a simple harmonic motion,

like a torsion pendulum with a torsion constant

κ=pE. In this case, angular frequency ω is given by

ω² = [tex]\frac{k}{I}[/tex] = [tex]\frac{pE}{I}[/tex]

where I denotes thee rotational inertia of the particular dipole. The frequency of oscillation is

f= ω/ 2pi

=  1/2pi [tex]\sqrt{\frac{pE}{I}}[/tex]

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