Answer:
14.3mL you require to reach the half-equivalence point
Explanation:
A strong acid as HClO₄ reacts with a weak base as CH₃CH₂NH₂, thus:
CH₃CH₂NH₂ + HClO₄ → CH₃CH₂NH₃⁺ + ClO₄⁻
As the reaction is 1:1, to reach the equivalence point you require to add the moles of HClO₄ equal to moles CH₃CH₂NH₂ you add originally. Also, half-equivalence point requires to add half-moles of CH₃CH₂NH₂ you add originally.
Initial moles of CH₃CH₂NH₂ are:
20.8mL = 0.0208L × (0.51mol CH₃CH₂NH₂ / 1L) =
0.0106moles CH₃CH₂NH₂
To reach the half-equivalence point you require:
0.0106moles ÷ 2 = 0.005304 moles HClO₄
As concentration of HClO₄ is 0.37M, volume you require to add 0.005304moles is:
0.005304 moles HClO₄ ₓ (1L / 0.37mol) = 0.0143L =
14.3mL you require to reach the half-equivalence pointWhen The Kb of ethylamine is 6.5 x 10-4 is = 14.3mL you require to reach the half-equivalence point.
What is Ethylamine?
When A strong acid as HClO₄ reacts with a weak base as CH₃CH₂NH₂, Therefore:
Then CH₃CH₂NH₂ + HClO₄ → CH₃CH₂NH₃⁺ + ClO₄⁻
So when the reaction is 1:1, to reach the equivalence point then you instruct to that add the moles of HClO₄ equal to the moles CH₃CH₂NH₂ you add originally. Also, When the half-equivalence point requires you to add half-moles of CH₃CH₂NH₂ you add originally.
Then Initial moles of CH₃CH₂NH₂ are:
After that 20.8mL = 0.0208L × (0.51mol CH₃CH₂NH₂ / 1L) =
Then 0.0106moles CH₃CH₂NH₂To get the half-equivalence point you require is:
Then 0.0106moles ÷ 2 = 0.005304 moles HClO₄
After that As the concentration of HClO₄ is 0.37M, the volume you require to add 0.005304moles is:
Then 0.005304 moles HClO₄ ₓ (1L / 0.37mol) = 0.0143L =
Therefore, 14.3mL you require to reach the half-equivalence point.
Find more information about Ethylamine here:
https://brainly.com/question/21961599
What is the ion symbol for an atom with twenty (20) protons and eighteen (18) electrons?
Answer:
[tex]Ca^{2+}[/tex]
Explanation:
From the periodic table, we can see that the atom with 20 protons is Calcium (Ca).
Each proton has a +1 charge, while each electron has a -1 charge.
Since in this ion, there's 20 protons but only 18 electrons, meaning it has a net charge of +2.
Hence, the ion symbol for the required proton is
[tex]Ca^{2+}[/tex].
(make sure the charge symbol is behind the value.)
Answer:
Ca²+
I agree with the one above
Write the balanced equation for the half reaction for the single replacement
reaction involving iron. This equation considers only the iron cations and the
elemental iron, and it shows how the iron cation (Fe3+) is reduced to become
elemental iron (Fe). How many electrons are represented in this equation? How
does this number of electrons help show a balance of charge on both sides of the
equation? (3 points)
Answer:
Explanation:
The half reaction required
Fe⁺³ + 3 e = Fe
This is a balanced equation
No of atom of Fe on both side = 1
Total charge on the left side = + 3 - 3 = 0
Total charge on the right = 0
three electrons will be required to neutralise +3 charge on the single iron ion .
Identify each of the following half-reactions as either an oxidation half-reaction or a reduction half-reaction.
H2(g) → 2H+(aq) + 2e- oxidation
Cu2+(aq) → + 2e-Cu(s) reduction
Write a balanced equation for the overall redox reaction. Use smallest possible integer coefficients.
Answer:
H₂(g) + Cu²⁺(aq) → 2H⁺(aq) + Cu(s)
Explanation:
In a redox reaction, one half-reaction is the oxidation (where the atom loss electrons) whereas the other reaction is the reduction (Where the atom is gaining electrons.
In the reactions:
H₂(g) → 2H⁺(aq) + 2e⁻ oxidation
Here, the reaction is written as the oxidation because the hydrogen H₂ is in oxidation state 0 and H⁺ in +1. That means each atom is loosing one electron.
Cu²⁺(aq) + 2e⁻ → Cu(s) reduction
And here, the Cu²⁺ is in +2 oxidation state and after the reaction is in Cu(s) 0 state. Thus, each atom is gaining 2 electrons.
The sum of both reactions is:
H₂(g) + Cu²⁺(aq) + 2e⁻ → 2H⁺(aq) + 2e⁻ + Cu(s)
Subtracting the electrons in both sides of the reaction:
H₂(g) + Cu²⁺(aq) → 2H⁺(aq) + Cu(s)Dry ice is solid carbon dioxide. A 0.050-g sample of dry ice is placed in an evacuated 4.6-L vessel at 30 °C. Calculate the pressure inside the vessel after all the dry ice has been converted to CO2 gas.
The answer is 6.1*10^-3 atm.
The pictures and explanations are there.
Ideal gas law is valid only for ideal gas not for vanderwaal gas. The equation used to solve this is PV=nRT. Therefore the pressure of carbon dioxide gas is 0.005 atm.
What is ideal gas equation?Ideal gas equation is the mathematical expression that relates pressure volume and temperature.
Mathematically the relation between Pressure, volume and temperature can be given as
PV=nRT
where,
P = pressure of carbon dioxide gas=?
V= volume of carbon dioxide gas=4.6L
n =number of moles of carbon dioxide gas = given mass ÷Molar mass
=0.050g÷44g/mol
=0.001mole
T =temperature of carbon dioxide gas=303K
R = Gas constant = 0.0821 L.atm/K.mol
substituting the given values, we get
P×4.6L=0.001×0.0821×303
=0.005 atm
Therefore the pressure of carbon dioxide gas is 0.005 atm.
To learn more about ideal gas equation, here:
https://brainly.com/question/14826347
#SPJ5
If you start with 512 grams of aluminum and 1147 grams of copper chloride to make aluminum chloride and copper, what is the limiting reagent? 2Al + 3CuCl -> 2AlCl3 + 3Cu
Answer:
Copper (II) chloride.
Explanation:
Hello,
In this case, considering the described reaction which is also given as:
[tex]2Al + 3CuCl_2 \rightarrow 2AlCl_3 + 3Cu[/tex]
For us to identify the limiting reactant we first compute the available moles of aluminium:
[tex]n_{Al}=512gAl*\frac{1molAl}{27gAl}=19.0molAl[/tex]
Next, we compute the consumed moles of aluminium by the 1147 grams of copper (II) chloride by using their 2:3 molar ratio:
[tex]n_{Al}^{consumed}=1147gCuCl_2*\frac{1molCuCl_2}{134.45gCuCl_2}*\frac{2molAl}{3molCuCl_2} =5.69molAl[/tex]
Thereby, we can infer aluminium is in excess since less moles are consumed than available whereas the copper (II) chloride is the limiting reactant.
Best regards.
Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline.
2C8H18+25O2⟶16CO2+18H2O
How many moles of CO2 are emitted into the atmosphere when 27.6 g C8H18 is burned?
Answer:
[tex]n_{CO_2}=1.93 gCO_2[/tex]
Explanation:
Hello,
In this case, considering the given chemical reaction, we can use the molar mass of octane (114.23 g/mol) and the 2:16 molar ratio with carbon dioxide to compute the emitted moles of CO2 to the atmosphere via the following stoichiometric procedure:
[tex]n_{CO2}=27.6gC_8H_{18}*\frac{1molC_8H_{18}}{114.23gC_8H_{18}} *\frac{16molCO_2}{2molC_8H_{18}} \\\\n_{CO_2}=1.93 gCO_2[/tex]
Which also corresponds to the following mass:
[tex]m_{CO_2}=1.93molCO_2*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=85.0gCO_2[/tex]
Best regards.
Which of the following chemical equations is balanced? A. 4Fe+3O →2Fe O 2 23 B. 4Fe+2O →3Fe O 2 23 C. 3Fe+3O →3Fe O D. 2Fe+O →Fe O 2 23
Answer: [tex]4Fe+3O_2\rightarrow 2Fe_2O_3[/tex]
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced chemical equation is:
[tex]4Fe+3O_2\rightarrow 2Fe_2O_3[/tex]
Thus in the reactants, there are 4 atoms of iron and 6 atoms of oxygen.Thus there will be 4 atoms of iron, and 6 atoms of oxygen in the product as well.
Consider the following reaction: NH4I(s) NH3(g) + HI(g) If a flask maintained at 674 K contains 0.138 moles of NH4I(s) in equilibrium with 4.34×10-2 M NH3(g) and 9.39×10-2 M HI(g), what is the value of the equilbrium constant at 674 K?
Answer:
4.08 × 10⁻³
Explanation:
Step 1: Write the balanced reaction at equilibrium
NH₄I(s) ⇄ NH₃(g) + HI(g)
Step 2: Calculate the equilibrium constant
The equilibrium constant (K) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. Only gases and aqueous species are included.
[tex]K = [NH_3] \times [HI] = 4.34 \times 10^{-2} \times 9.39 \times 10^{-2} = 4.08 \times 10^{-3}[/tex]
merits of modern periodic table?
Answer:
Merits of modern periodic table:The wrong position of some elements like argon, potassium, cobalt and nickel due to atomic weights have been solved by arranging the elements in the order of increasing atomic number without changing their own places.The isotopes of some element have the same atomic numbers. Therefore, they find the same position in periodic table.It separates metals from non-metals.The groups of the table are divided into sub groups A and B due to their dissimilar properties which make the study of elements specific and easier.The representative and transition elements have been separated.Hope this helps...
Good luck on your assignment...
Chemistry question. Image attached.
Answer:
The answer to your question is given below
Explanation:
The balanced equation for the reaction is given below:
CaO(s) + CH4(g) + 2H2O(g) <=> CaCO3(s) + 4H2(g)
1. Writing an expression for the equilibrium constant, K.
The equilibrium constant, K for a reaction is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.
Thus, we can write the equilibrium constant, K for the reaction as follow:
CaO(s) + CH4(g) + 2H2O(g) <=> CaCO3(s) + 4H2(g)
K = [CaCO3] [H2]⁴ / [CaO] [CH4] [H2O]²
2. Based on the value of K, more products will be in the equilibrium mixture since the value of K is a positive large number.
Write the condensed electron configuration for the manganese atom. When writing your answers, do not add spaces and do not try to italicize the orbitals.
Answer:
[tex][Ar]4s^23d^5[/tex]
Explanation:
Hello,
In this case, we write the electron configuration of the manganese atom by noticing its atomic number is 25, so we fill the orbitals and levels up-to 25 electrons as shown below:
[tex]1s^22s^22p^63s^23p^64s^23d^5[/tex]
Moreover, for the condensed electron configuration, we consider the previous noble gas, that is argon, electron configuration which is:
[tex]1s^22s^22p^63s^23p^6[/tex]
By cause of its atomic number that is 18. In such a way, we combine argon's electron configuration with manganese's to obtain its condensed version:
[tex][Ar]4s^23d^5[/tex]
Regards.
If 3.10 moles of P4010 reacted with excess water, how many grams of H3PO4
would be produced?
P4010 +6H20 + 4H3PO4
You Answered
126 g
0 0.007918
Correct Answer
O 1220 g
0.1278
75.98
Answer:
1.22 × 10³ g
Explanation:
Step 1: Write the balanced equation
P₄O₁₀ + 6 H₂O ⇒ 4 H₃PO₄
Step 2: Calculate the moles of H₃PO₄ produced by 3.10 moles of P₄O₁₀
The molar ratio of P₄O₁₀ to H₃PO₄ is 1:4. The moles of H₃PO₄ produced are 4/1 × 3.10 mol = 12.4 mol
Step 3: Calculate the mass corresponding to 12.4 moles of H₃PO₄
The molar mass of H₃PO₄ is 97.99 g/mol.
[tex]12.4 mol \times \frac{97.99g}{mol} = 1.22 \times 10^{3} g[/tex]
If the vinegar were measured volumetrically (e.g., a pipet), what additional piece of data would be needed to complete the calculations for the experiment?
Answer:
the density if vinegar will also be needed
Explanation:
Because this is an experiment of volumetric analysis
Erbium metal (Er) can be prepared by reacting erbium(III) fluoride with magnesium; the other product is magnesium fluoride. Write and balance the equation.
Answer:
2ErF3 + 3Mg → 2Er + 3MgF2
Explanation:
Erbium metal is a member of the lanthaniod series. It reacts with halogens directly to yield erbium III halides such as erbium III chloride, Erbium III fluoride etc.
Erbium metal (Er) can be prepared by reacting erbium(III) fluoride with magnesium; the products are erbium metal and magnesium fluoride. This is a normal redox process in which the Erbium metal is reduced while the magnesium is oxidized. The balanced reaction equation of this process is; 2ErF3 + 3Mg → 2Er + 3MgF2
The cylinder shown contains 0.79 moles of nitrogen, 0.19 moles of oxygen and 0.02 moles carbon dioxide, a total of 1.00 mole of molecules in the approximate proportion in which they are present in air. Of the three gases, only carbon dioxide is appreciably soluble in the water in the well at the bottom. Assume an equilibrium between dissolved and undissolved carbon dioxide at the beginning and sufficient time lapse to reestablish that equilibrium after the change described. If 0.02 mole of carbon dioxide is forced into the cylinder, the solubility of carbon dioxide ... a) increases by a factor of about 50. b) increases by a factor of about 2. c) increases by 2%. d) remains unchanged. e) decreases.
Answer:
b) increases by a factor of about 2.
Explanation:
Ignore the nitrogen and oxygen. Each gas acts independently of the others.
You have 0.02 mol of CO₂ gas at some pressure in equilibrium with the CO₂ in solution.
According to Graham's Law,
S = kp
That is, the solubility of a gas in a liquid is directly proportional to its partial pressure above the liquid.
If you add another 0.02 mol of CO₂, you have doubled the number of moles.
According to Avogadro's Law, doubling the number of moles doubles the pressure.
According to Graham's Law, doubling the pressure doubles the solubility.
The solubility of CO₂ increases by a factor of two.
Select the correct answer
What determines the average kinetic energy of the particles in a gas?
ОА
the number of collisions
OB.
the number of particles
OC. the size of the particles
OD. the temperature
Answer:
Temperature
Explanation:
Kinetic energy of gass molecules is directly propotional to the temperature.
a solution of unknown molecular substance is prepared by dissolving 0.50g of the unknown in 8.0g of benzene. the solution freezes at 3.9. determine the molar mass of the unknown
Answer:
THE MOLAR MASS OF THE UNKNOWN MOLECULAR SUBSTANCE IS 200 G/MOL.
Explanation:
Mass of the unknown substance = 0.50 g
Freezing point of the solution = 3.9 °C
Freezing point of pure benzene = 5.5 °C
Freezing point dissociation constant Kf = 5.12°C/m
First, calculate the temperature difference between the freezing point of pure benzene and the final solution freezing point.
Change in temperature = 5.5 -3.9 = 1.6 °C
Next is to calculate the number of moles or molarity of the compound that dissolved.
Using the formula:
Δt = i Kf m
Assume i = 1
So,
1.6 °C = 1 * 5.12 * x/ 0.005 kg of benzene
x = 1.6 * 0.008 / 5.12
x = 0.0128 / 5.12
x = 0.0025 moles.
Next is to calculate the molar mass using the formula, molarity = mass / molar mass
Molar mass = mass / molarity
Molar mass = 0.50 g /0.0025
Molar mass = 200 g/mol
Hence, the molar mass of the unknown compound is 200 g/mol
Use the balanced combustion reaction above to calculate the enthalpy of combustion for C8H16. C8H16(1)= -174.5kJ/mol. I have no clue how to start this question and need help including the formulas so I know how to do it and some step by step commentary.
Answer:
Explanation:
C₈H₁₆ + 12O₂ = 8 CO₂ + 8H₂O.
a )
Heat of formation of C₈H₁₆
[tex]\triangle H_f (C_6H_{16})=-174.5 kJ[/tex]
[tex]\triangle H_f (CO_2)=-393.5 kJ[/tex]
[tex]\triangle H_f (O_2)= 0[/tex]
[tex]\triangle H_f (H_2O)=-285.82 kJ[/tex]
[tex]\triangle H_{reaction} =[/tex] 8 x - 393.5 - 8 x 285.82 + 174.5x 1
= - 5260.06 kJ
b ) Energy required = 2.905 x 10¹⁵kJ
moles of C₈H₁₆ require to be burnt
= 2.905 x 10¹⁵ / 5260.06
= 55.23 x 10¹⁰ moles
= 55.23 x 10¹⁰ x mol weight of C₈H₁₆ g
= 55.23 x 10¹⁰ x 112 g
= 6185.5 x 10¹⁰ g
= 6185.5 x 10⁷ kg
c )
No of litres of CO₂ produced at NTP = 8 x 22.4 x 55.23 x 10¹⁰ L
= 9897.22 x 10¹⁰ L
At 1520 mm of Hg pressure and 250°C
volume of CO₂
= 9897.22 x 10¹⁰ x 760 x ( 273 + 250) / ( 1520 x 273 )
= 9480.3 x 10¹⁰ L .
What is the absolute magnitude of the rate of change for [NH3] if the
rate of change for [Hz] is 9.00 M/s in the reaction 2 NH3(g) → N2(g) +
3 H2(g)?
Answer:
[tex]r_{NH_3,abs} =6.00\frac{M}{s}[/tex]
Explanation:
Hello,
In this case, we can write the law of mass action for the undergoing chemical reaction, based on the rates and the stoichiometric coefficients:
[tex]\frac{1}{-2}r_{NH_3} =\frac{1}{1} r_{N_2}=\frac{1}{3}r_{H_2}[/tex]
In such a way, knowing the rate of formation hydrogen (H₂), we can know the rate of change of ammonia, that must be negative for consumption:
[tex]r_{NH_3} =\frac{-2}{3}r_{H_2}=\frac{-2}{3}*9.00\frac{M}{s} \\\\r_{NH_3} =-6.00\frac{M}{s}[/tex]
Nevertheless, the absolute magnitude will be positive:
[tex]r_{NH_3,abs} =6.00\frac{M}{s}[/tex]
Best regards.
A 10.0 mL sample of calcium hydroxide solution required 26.85 mL of 0.225 M hydrochloric acid for neutralization. The balanced equation is:
Answer:
[tex]C_{base}=0.302M[/tex]
Explanation:
Hello,
In this case, we can evidence that when calcium hydroxide solution reacts with hydrochloric acid solution, the balanced neutralization reaction turns out:
[tex]2HCl(aq)+Ca(OH)_2\rightarrow CaCl_2(aq)+2H_2O(l)[/tex]
Moreover, the concentration of neutralized calcium hydroxide can be computed by using the 2:1 mole ratio between the base and the acid:
[tex]C_{acid}V_{acid}=2*C_{base}V_{base}\\\\C_{base}=\frac{C_{acid}V_{acid}}{2*V_{base}} =\frac{0.225M*26.85mL}{2*10.0mL}\\ \\C_{base}=0.302M[/tex]
Regards.
What is a ‘control’ in an experiment?
A. A version of the experiment that is unchanged to make sure the experimental data is not due to chance.
B. A person who oversees the experiment to make sure it is following proper procedures.
C. The variable controlled by the scientist to affect the dependent variable.
D. The name for the set of independent and dependent variables that will be controlled by the scientist.
need help asap got 1 minute
D. The name for the set of independent and dependent variables that will be controlled by the scientist.
The statement, that describes the ‘control’ in an experiment is "the name for the set of independent and dependent variables that will be controlled by the scientist."
What is a control in experiment?A control is an element in an experiment that remains intact or unaffected by other variables. An experiment or observation aiming to minimise the influence of variables other than the independent variable is referred to as a scientific control. It serves as a standard or point of reference against which other test findings are measured.
In a scientific experiment, an independent variable is the variable that is modified or manipulated in order to assess the effects on the dependent variable. In a scientific experiment, the dependent variable is the variable that is being tested and measured. The designation given to the set of independent and dependent variables that the scientist will regulate.
Hence the correct option is D.
Learn more about control in an experiment here
https://brainly.in/question/19374703
#SJP3
The percent errors of your experimental values of the specific heats may be quite large. Identify several sources of experimental error.
Answer:
The various sources of such errors are given below.
Explanation:
Sources of uncertainty or error could include necessary splattering of water leading to reduced cold water density as well as elevated temperatures of equilibration.The temperature might not have been reasonably stable when developers evaluated at every phase of the investigation or research.So that the percentage of someone specific produces heat exploratory value systems inaccuracies can be somewhat massive.
Homolysis, or homolytic bond dissociation, produces a very specific type of product under certain reaction conditions. In Part 1, select all the products (in formulae and general chemical terms) that could result from homolysis. In Part 2, select the reaction conditions that are most likely to promote homolysis.
Part 1. Choose all that may occur as possible products of a homolysis reaction.
Choose one or more:_______.
a. hydride ion
b. R3CO
c. Br2
d. H
e. a carbocation
f. H3C
g. H3CO-
h. hydrogen ion
i. a carbon free radical
Part 2. Choose the conditions under which homolysis is likely to occur.
Choose one or more:_______.
a. strong base
b. ultraviolet irradiation
c. high temperature
d. strong acid
e. infrared irradiation
f. low temperature
Answer:
1) R₃CO , H, H₃C, a carbon free radical
2) high temperature, ultraviolet irradiation
Explanation:
1) Homolysis leads to the formation of free radicals (species having a free electron). Thus, answer is :
R₃CO
H
H₃C
a carbon free radical
2) Homolysis require high temperature, ultraviolet irradiation.
The density of a pure substance is its mass per unit volume. The density of cresol has been measured to be 1024 g/L . Calculate the mass of 405mL of cresol.
Answer: The mass of 405 ml of cresol is 415 grams
Explanation:
Density is defined as the mass contained per unit volume.
[tex]Density=\frac{mass}{volume}[/tex]
Given : Density of cresol = 1024 g/L
Volume of cresol = 405 ml = 0.405 L ( 1L=1000ml)
Putting in the values we get:
[tex]1024g/L=\frac{mass}{0.405L}[/tex]
[tex]mass=1024g/L\times 0.405L=415g[/tex]
Thus mass of 405 ml of cresol is 415 grams
When Carl Woese developed the modern system of classification, he broke the previous kingdom of into the two kingdoms of Bacteria and Archaea
Answer:
the answer is monerans
Explanation:
When Carl Woese developed the modern system of classification, he broke the previous kingdom of Monera into the two kingdoms of Bacteria and Archaea.
What kingdom of Monera ?Some biologists believed it made sense to classify prokaryotes as belonging to their own kingdom, the Monera. That served as the foundation for Richard Whittaker and Lynn Margulis's five-kingdom proposal, which enhanced the Haeckel plan by include a kingdom of fungus.
Protists, protozoa, monera, fungi, and viruses have long been proposed as belonging to different kingdoms, but traditional evolutionists during the majority of the 20th century had given none of them any thought.
Later, the Monera kingdom was split into Eubacteria and Archaebacteria by Carl Woese . Moreover, he divided the five kingdoms into three domains: Eukaryotes, Archaea, and Bacteria.
Find more on Kingdom Monera:
https://brainly.com/question/30621598
#SPJ3
Your question is incomplete. But your complete question is as follows:
When Carl Woese developed the modern system of classification, he broke the previous kingdom of into the two kingdoms of _____ into Bacteria and Archaea.
Describe the difference between ionic and molecular compounds. Give an example of each. Check all that apply. Check all that apply. A molecular compound is formed between a metal and a nonmetal (or polyatomic ions), and is held together through the attraction of opposite charges. An example is KCl. An ionic compound is usually formed between two or more nonmetals, and is held together through the sharing of electrons between atoms. An example is SO2. An ionic compound is formed between a metal and a nonmetal (or polyatomic ions), and is held together through the attraction of opposite charges. An example is KCl. A molecular compound is usually formed between two or more nonmetals, and is held together through the sharing of electrons between atoms. An example is SO2. An ionic compound is formed between two or more metals, and is held together through the attraction of opposite charges. An example is Na2Al.
Answer:
An ionic compound is formed between a metal and a nonmetal (or polyatomic ions), and is held together through the attraction of opposite charges. An example is KCl. A molecular compound is usually formed between two or more nonmetals, and is held together through the sharing of electrons between atoms. An example is SO2.
Explanation:
When we talk about ionic bonds, the first thing that must come to mind is the electrostatic attraction between oppositely charged ions. Hence, we know that metals form cations and nonmetals form anions, thus metals could transfer electrons to nonmetals to facilitate the formation of ionic bonds. Ionic bonds could also be formed by the combination of metals with polyatomic ions such as CaCO3. Always keep it in mind that ionic bonds are characterized by electrostatic attraction between any pair of oppositely charged ions.
Molecular compounds are formed by sharing of electrons between nonmetals. We find covalent or polar covalent bonds in molecular compounds such as SO2.
Answer these questions, please.
Answer:
1a. 0.89 gcm¯³
1b. Yes.
1c. Tetrahydrofuran.
2. 0.54 g/mL
Explanation:
1. Data obtained from the question include:
Volume = 0.988 L = 988 cm³
Mass = 879 g
1a. Determination of the density
Density = mass /volume
Density = 879/ 988
Density = 0.89 gcm¯³
Therefore, the density of the liquid is 0.89 gcm¯³
1b. From the given data, it is possible to determine the identity of the liquid.
1c. The density of the liquid is 0.89 gcm¯³. Comparing the density of the liquid obtained with those given in the table, the liquid is tetrahydrofuran
2. Data obtained from the question include:
Mass of empty cylinder = 5.25 g
Mass of cylinder and sodium thiosulfate = 75.82 g
Volume = 130.63 mL
Next, we shall determine the mass of sodium thiosulfate. This can be obtain as follow:
Mass of empty cylinder = 5.25 g
Mass of cylinder and sodium thiosulfate = 75.82 g
Mass of sodium thiosulfate =.?
Mass of sodium thiosulfate = Mass of cylinder and sodium thiosulfate – Mass of empty cylinder
Mass of sodium thiosulfate = 75.82 – 5.25
Mass of sodium thiosulfate = 70.57 g
Finally, we shall determine the concentration of the sodium thiosulfate as follow:
Mass = 70.57 g
Volume = 130.63 mL
Concentration =?
Concentration = mass /volume
Concentration = 70.57/130.63
Concentration = 0.54 g/mL
The concentration of the solution is 0.54 g/mL
A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of CO2 and 0.01961 mol of H2O. The empirical formula of the compound was found to be C3H6O2. Show how this was calculated.
What does the empirical formula tell you about the compound?
The molar mass of the actual compound was found to be 222.27g/mol. Find the molecular formula of this compound. What does the molecular formula tell you about the compound?
Can you see what type of functional group this compound could have?
Answer:
See explanation.
Explanation:
Hello,
In this case, we can show how the empirical formula is found by following the shown below procedure:
1. Compute the moles of carbon in carbon dioxide as the only source of carbon at the products:
[tex]n_C=0.01962molCO_2*\frac{1molC}{1molCO_2} =0.01962molC[/tex]
2. Compute the moles of hydrogen in water as the only source of hydrogen at the products:
[tex]n_H=0.01961molH_2O*\frac{2molH}{1molH_2O}=0.03922molH[/tex]
3. Compute the mass of oxygen by subtracting the mass of both carbon and hydrogen from the 0.4647-g sample:
[tex]m_O=0.4647g-0.01962molC*\frac{12gC}{1molC}-0.03922molH*\frac{1gH}{1molH} =0.1900gO[/tex]
4. Compute the moles of oxygen by using its molar mass:
[tex]n_O=0.1900gO*\frac{1molO}{16gO}=0.01188molO[/tex]
5. Divide the moles of carbon, hydrogen and oxygen by the moles of oxygen (smallest one) to find the subscripts in the empirical formula:
[tex]C=\frac{0.01962}{0.01188}=1.65\\ \\H=\frac{0.03922}{0.01188} =3.3\\\\O=\frac{0.01188}{0.01188} =1[/tex]
6. Search for the closest whole number (in this case multiply by 2):
[tex]C_3H_6O_2[/tex]
Moreover, the empirical formula suggests this compound could be carboxylic acid since it has two oxygen atoms, nevertheless, this is not true since the molar mass is 222.27 g/mol, therefore, we should compute the molar mass of the empirical formula, that is:
[tex]M=12*3+1*6+16*2=74g/mol[/tex]
Which is about three times in the molecular formula, for that reason, the actual formula is:
[tex]C_9H_{18}O_6[/tex]
It suggest that the compound has a highly oxidizing character due to the presence of oxygen, therefore, we cannot predict the distribution of the functional groups as it could contain, carboxyl, carbonyl, hydroxyl or even peroxi.
Best regards.
Hydrogen bonding between polyamide chains plays an important role in determining the properties of a nylon such as nylon 6,6. Draw the structural formulas for two adjacent chains of nylon 6,6, and show where hydrogen-bonding interactions could occur between them.
Answer:
See figure 1
Explanation:
In the structure of nylon 6,6 we have amide groups. In this functional group, We have a nitrogen bond to hydrogen, so in this bond, we will have a dipole, due to the electronegativity difference. Nitrogen has more electronegativity than hydrogen, therefore a positive dipole would be generated in the hydrogen atom. Additionally, in the carbonyl group (C=O) due to the oxygen, we will have also a dipole, in this case, a negative dipole because the oxygen atom has more electronegativity (compare with carbon).
When we put two strings of nylon 6,6 the positive dipole will interact with the negative dipole and vice-versa and we will obtain the "hydrogen bonds".
See figure 1
I hope it helps!
A buffer solution is 0.100 M in both HC7H5O2 and KC7H5O2 has a pH of 4.19. Which of the fo pH values would you expect from the addition of a small amount of a dilute solution of a strong base?
A. 5.79
b. 4.49
c. 3.69
d. 3.89