Answer: [tex]33.31\times 10^{23}[/tex] molecules of [tex]OF_2[/tex]
and 11.06 moles of Flourine
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
1 mole of [tex]OF_2[/tex] contains= [tex]6.022\times 10^{23}[/tex] molecules of [tex]OF_2[/tex]
Thus 5.53 moles of [tex]OF_2[/tex] contains=[tex]\frac{6.022\times 10^{23}}{1}\times 5.53=33.31\times 10^{23}[/tex] molecules of [tex]OF_2[/tex]
1 mole of [tex]OF_2[/tex] contains= 2 moles of Flourine
5.53 moles of [tex]OF_2[/tex] contains=[tex]\frac{2}{1}\times 5.53=11.06[/tex] moles of Flourine
How can we solve food insecurity while reducing food waste?
o inventory food supplies to avoid overbuying
O donate unused food to food banks
O purchase only as much food as you need
O don't throw scraps in the landfill
Answer:
donate unused food to food banks
Explanation:
Becuse food banks processes food to make very fine particles which is mixed with soil and can be given to the plants
What is the voltage in a circuit is the current is 3 amps and the resistance is 3 ohms
Answer:
9
Explanation:
V=I*R
3*3
Thats the answer
How many grams are in 0.500 liters of SBr6?
Please show work if possible or say how to do it
Answer:
250 grams = 0.25 liter
Explanation:
Find the mass of 2.40 moles of CO. gas..
Which of the following things would be the MOST irresistible for a dog?
A
a veterinarian
B
a fire hydrant
C broccoli vomit surprise
Answer:
B.a fire hydrant
hope it helps!
Answer:
a veterinarian
Explanation:
i think
When the number of molecules, atoms, or ions of a particular type (here we consider H ions) is in the hundreds of millions, we can confidently speak of concentrations and analyze an average behavior.
a. True
b. False
Answer:
True.
Explanation:
When the number of molecules, atoms or ions of any element is in the hundreds of millions, we can safely speak of concentrations and analyze a standard behavior, and can even specify the different dilutions used, if there are dilutions. This allows analyzes to be clearly understood by any individual. However, it is not possible to do this if the number of molecules, atoms and ions is very small.
Mass number 107 and 61 neutrons
What is the functional groups of CH3CH2CH(OH)CH2C(CH3)2Br?
Answer:
What is the functional groups of CH3CH2CH(OH)CH2C(CH3)2Br?
MnO4 - is a stronger oxidizing agent than ReO4 - . Both ions have charge-transfer (LMCT) bands; however, the charge-transfer band for ReO4 - is in the ultraviolet, whereas the corresponding band for MnO4 - is responsible for its intensely purple color. Are the relative positions of the charge-transfer absorptions consistent with the oxidizing abilities of these ions? Explain
Answer:
[tex]$MnO^-_4$[/tex] is a strong oxidizing agent.
Explanation:
The 5d orbitals of Re are higher in energy than 3 d orbitals of Mn. So an LMCT ligand to metal charge transfer excitation requires more energy of [tex]$ReO^-_4$[/tex].
Also, since the molecular orbitals are derived primarily from 3d orbitals of [tex]$MnO^-_4$[/tex] are lower in energy than the corresponding MO's of [tex]$ReO^-_4$[/tex], [tex]$MnO^-_4$[/tex] is better able to accept the electrons.
So it is a better oxidizing agent.
The ligand to metal charge transfer band in ReO4- occurs in the near UV region hence ReO4 - appears colorless.
The electron configuration of Re is Xe 4f14 5d5 6s2 and the electron configuration of Mn is [Ar] 3d5 4s2. We can see that Mn^7+ and Re^7+ have empty d orbitals.
The color of MnO4 - must result from ligand to metal charge transfer hence the purple color of MnO4 -. In the case of ReO4 -, the ligand to metal charge transfer occurs at a much higher energy owing to the fact that 5d orbitals are involved. This transition occurs in the near UV region hence ReO4 - appears colorless. The ligand to metal charge transfer in MnO4- involves lower energy 3d orbitals hence it occurs in the visible region of the spectrum.
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what information is shown in the infographics?
Answer:
An infographic is a collection of imagery, charts, and minimal text that gives an easy-to-understand overview of a topic. As in the example below, infographics use striking, engaging visuals to communicate information quickly and clearly. Infographics are a valuable tool for visual communication.
What is the source of most of the salt in the oceans?
human activities adds salt into the ocean
O rivers and streams carry sediment containing salt to the ocean
O marine fish produce salt adding it into the ocean
wind blows the salt into the ocean
A hydrogen atom is removed from the first carbon atom of a butane molecule and is replaced by a hydroxyl group.
Required:
Draw the new molecule formed.
Answer:
See answer below
Explanation:
In this case, let's draw the butane molecule:
CH₃ - CH₂ - CH₂ - CH₃
According to what the exercise states, we removed an atom of hydrogen from the frist carbon. This could be any of the terminals. I'll grab the first from left to right.
CH₂⁺ - CH₂ - CH₂ - CH₃
When this happens, the atom of carbon is lacking one space and it forms a carbocation.
Followed this step, an hydroxile group replace the atom of hydrogen. The hydroxile is the OH, and when we have an alkane with an OH group in the molecule, we are actually converting this molecule into an alcohol, therefore the molecule formed is:
OH - CH₂ - CH₂ - CH₂ - CH₃Hope this helps
Describe how naturally
acidic rainwater can affect a
mountain of limestone.
Answer:
The naturally acidic rain will gradually wear the mountain of limestone away.
Hope it helps!
What is the half life of the graphed material?
Answer:
3 hours
Explanation:
To know the the correct answer to the question given above, it is important we know the definition of half-life.
The half-life of a substance is simply defined as the time taken for half the substance to decay.
Considering the diagram given above, the initial mass of the substance is 100 g.
Half of the initial mass = 100 / 2 = 50 g
Now, we shall determine the time from the graph taken to get to 50 g.
Considering the diagram given above, the time taken to get to 50 g is 3 hours.
Therefore, the half-life of the material is 3 hours.
According to the graph, what is the instantaneous speed of the object at 5 seconds? *
Captionless Image
4 m/s
7 m/s
0.25 m/s
3 m/s
Answer:4m/s
Explanation:The reason why that the answer is because I am Smart.
WHEN YOU SEE A BLUE CAR WHAT COLER IS BEING REFLECTED
Answer:
violet
Explanation:
just violet
oh and you spelled "COLER" wrong, its color or colour if you live somewhere else
Methanol has the formula of CH3OH and can be produced by the reaction of carbon monoxide with hydrogen gas. CO + 2 H2 === CH3OH + heat Using the above chemical reaction, determine how each of the following actions would affect the equilibrium of the system. a. heating the mixture b. adding an excess of carbon monoxide c. removing the methanol as it is formed d. adding a substance that reacts with carbon monoxide
Answer:
See explanation below
Explanation:
Let's answer this by parts.
a) As the reaction is naturally exothermic (Exerts heat), increasing temperature means that the reaction will move forward the direction where its absorbing heat
, so the equilibrium will be favored to the reactant side.
b) In this case, the addition of CO, which is a reactant will favor the reaction to the product side. This is because putting more quantity in the reactants will cause that the equilibrium constant K, increase it's innitial value, and this favors the product side.
c) In this case, it happens something similar to case b. This will cause that the reaction will have to work to cover the loss of methanol, therefore, equilibrium will move to the product side too.
d) In this case, we are adding another substance that reacts with CO, so it means that the other reactant is being removed, therefore, the reaction will work to cover this loss but also to cover the adding of the new substance, causing that the K decrease it's value, so equilibrium will be favored to the reactants side.
Hope this helps
A 52.9g sample of brass, which has a specific heat capacity of 0.375·J·g^−1°C^−1, is put into a calorimeter (see sketch at right) that contains 100.0g of water. The temperature of the water starts off at 15.0°C. When the temperature of the water stops changing it's 18.4°C. The pressure remains constant at 1 atm. Calculate the initial temperature of the brass sample.
Answer: 90.04°C
Explanation: Calorimeter is a device measures the amount of heat of a chemical or physical process. An ideal calorimeter is one that is well-insulated, i.e., prevent the transfer of heat between the calorimeter and its surroundings. So, the net heat change inside the calorimeter is zero:
[tex]q_{1}+q_{2}=0[/tex]
Rearraging, it can be written as
[tex]q_{1}=-q_{2}[/tex]
showing that the heat gained by Substance 1 is equal to the energy lost by Substance 2.
In our case, water is gaining heat, because its temperature has risen and so, brass is losing energy:
[tex]q_{water}=-q_{brass}[/tex]
Calculating:
[tex]m_{w}.c_{w}.\Delta T=-[m_{b}.c_{b}.\Delta T][/tex]
[tex]100.4.18.(18.4-15)=-[52.9.0.375.(18.4-T)][/tex]
Note: final temperature is the same as the substances are in thermal equilibrium.
Solving:
418(3.4)= - 365.01 + 19.8375T
19.8375T = 1786.21
T = 90.04
The initial temperature for the sample of brass was 90.04°.
10 points Part F
Identify at least two limitations of the simulation. How do these limitations influence the
simulation's ability to model the synthesis of ammonia?
Answer and Explanation:
When using simulations, it is important that the researcher knows some limitations. This is because the simulations do not behave exactly like what they represent, in addition to not presenting very important details for analysis and without approximations of what really happens with what they are representing. When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.
When using simulations, it is important that the researcher knows some limitations. This is because the simulations do not behave exactly like what they represent, in addition to not presenting very important details for analysis and without approximations of what really happens with what they are representing. When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.
Select the option that best represents recycling food waste
O turning food scraps into biogas
O donating unused food to food pantries
O incinerating leftover food
O feeding scraps to livestock
Answer:
feeding leftover or scraps to livestock
Explanation:
Because feeding leftover healthy food instead of leaving livestock to eat garbage is good for health of the animals and they give good quality of milk, eggs, meat, etc in return
Read: https://kids.britannica.com/kids/article/DNA/390730 (Links to an external site.)
Answer the following questions:
1. What sort of things does DNA determine for a creature? (Think physical traits)
2. Sometimes there are mistakes in DNA, what are these mistakes called? what sort of things can these mistakes cause?
3. What makes up the sides of the DNA structure?
4. There are four different bases in DNA: adenine, thymine, guanine, and cytosine. About how many total pairs do humans have in their DNA?
Answer:
im not doing your whole homework. but ill give you one cent ;>, whats ur paypal
Explanation:
Complete the following reaction: Li + S -->
Answer:
Li2S
Explanation:
Hope this helps.
Answer:
can u do an real answer pls so i can help u thanks
1. How many molecules are in 4.5 moles?
Answer:
depends on what molecule you are looking for
Explanation:
In one mole of stuff (atoms, molecules, eggses), there are NA individual items of that stuff. So, there are 4.5 × NA BCl3 molecules; i.e. 4.5 × 6.022×1023 ≅ 27×1023 individual molecules of BCl3
Which of the following statements about steroid hormones is true?
A. They bind with receptor proteins in the plasma membrane.
B. They bind to carrier proteins in order to be transported in the blood to
their target cells.
C. They are synthesized from epinephrine in the adrenal gland.
D. They are mostly derivatives of the amino acid tyrosine.
Answer:
B. They bind to carrier proteins in order to be transported in the blood to
their target cells.
Explanation:
Steroid hormones are belongs to the class of chemical compound called steroid. Steroid hormones are majorly secreted by three glands - ovaries, testes and adrenal cortex.
Steroid hormones are released in the blood and are allowed to bind to the specific carrier proteins such as corticosteroid-binding globulin and albumin which helps them to carry to the target cells for the functioning.
The steroid hormone binds to receptor proteins in the target cell and not in the plasma membrane
Hence, the correct answer is "B. They bind to carrier proteins in order to be transported in the blood to their target cells."
Can you think of an example where hydrogen and oxygen combine and release energy with little or no release of heat energy?
When hydrogen and oxygen combine, they form water or hydrogen peroxide, and energy is released in the process.
What are oxygen and hydrogen?
Oxygen and hydrogen are the chemical elements of the periodic table, and they both are gas. Oxygen is the most important gas, which is needed for breathing. It is present at 21% in the atmosphere.
Hydrogen is another gas present in nature. It is the lightest gas, and it has diatomic molecules. It remains gas at normal pressure and temperature, but it becomes liquid at low temperature.
The oxygen and hydrogen readily react and for water, and hydrogen peroxide, the process of reaction of hydrogen and oxygen releases an amount of energy.
Hence, Energy is released during the creation of water or hydrogen peroxide when hydrogen and oxygen mix.
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#SPJ5
The hybridisation of the central atom in ICL-2
a) sp.
b) sp2
c) sp3d d)sp3
Explanation:
For ICl²-, the central iodine atom is bonded to the 2 chlorine atoms and has 3 lone electron pairs.
Altogether it has 5 electron domains, which means it is sp3d hybridized. (C)
5. Write the two resonance hybrids for the carbocation that would be formed by protonation at C-1 of 2-methyl-1,3-pentadiene. Without doing a calculation, would you expect C-2 or C-4 (the two end carbons of the allylic cation) to have the most positive charge on it
Answer:
Follows are the solution to this question:
Explanation:
Please find the complete solution in the attached file.
what amount of heat, in KJ, would be involved in condensing 12.9 g of ch3OH ?(hvap=38.0 kj/mol
Answer:
[tex]Q=-15.3kJ[/tex]
Explanation:
Hello!
In this case, since the enthalpy of vaporization is the contrary of the enthalpy of condensation, we have:
[tex]\Delta _{cond}H=-\Delta _{vap}H=-38.0kJ/mol[/tex]
Now, we convert the grams of CH3OH to moles:
[tex]n=12.9g*\frac{1mol}{32.05g}=0.402mol[/tex]
Thus, we compute the energy as shown below:
[tex]Q=n*\Delta _{cond}H=0.402mol*-38.0\frac{kJ}{mol}\\\\Q=-15.3kJ[/tex]
Which means 15.3 kJ of energy must be back down from the system.
Best regards!
Enthalpy is the measure of the energy that is not available to work. 15.27 kJ of energy is needed to condence 12.9 g of methenol.
Enthalpy:
It is the measure of the energy that is not available to work. It is denoted by [tex]\bold{ \Delta H}[/tex].
The energy of a system can be calculated by the formula,
[tex]\bold{Q = n \times \Delta H}[/tex]
Where,
Q - energy( in kJ)
n - Number of moles
[tex]\bold{ \Delta H}[/tex] - enthalpy
Given here,
[tex]\bold{CH_3OH = 12.9 g}[/tex]
[tex]\bold{\Delta Hvap = 38.1 kJ/mol}[/tex]
molar mass of the [tex]\bold{CH_3OH}[/tex] -
The number of moles of [tex]\bold{CH_3OH}[/tex]
[tex]\bold{n = \frac{w}{m}}\\\\\bold{n = \frac{12.9}{32.03}} \\\\\bold{n = 0.402}[/tex]
Put the values in the formula,
[tex]\bold{Q = 0.402\times 38.0}\\\\\bold{Q =15.27 }[/tex]
Therefore, the 15.27 kJ of energy is needed to condense 12.9 g of methenol.
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On the basis of the information above, a buffer with a pH = 9 can best be made by using
A pure NaH2PO4
B H3PO4 + H2PO4–
C H2PO4– + PO42–
D H2PO4– + HPO42–
E HPO42– + PO43
Answer:
D H2PO4– + HPO42–
Explanation:
The acid dissociation constant for [tex]\mathbf{H_3PO_4 , H_2PO^{-}_4 , HPO_4^{2-}}[/tex] are [tex]\mathbf{7\times 10^{-3}, \ \ 8\times 10^{-8} ,\ \ 5\times 10^{-13}}[/tex] respectively.
[tex]\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}[/tex]
[tex]\mathbf{pka (H_2PO_4^-) = -log (8\times 10^{-8} )=7.1}[/tex]
[tex]\mathbf{pka (HPO_4^{2-}) = -log (5\times 10^{-13} )=12.3}[/tex]
The reason while option D is the best answer is that, the value of pKa for both
[tex]\mathbf{H_2PO^{-}_4 ,\ \& \ HPO_4^{2-}}[/tex] lies on either side of the desired pH of the buffer. This implies that one is slightly over and the other is slightly under.
Using Henderson-Hasselbach equation:
[tex]\mathbf{pH = pKa + log \Big( \dfrac{HPO_4^{2-}}{H_2PO_4^-} \Big)}[/tex]
The compounds that are used for the formulation of the pH 9 buffer are [tex]\rm H_2PO_4^-\;and\;HPO_4^+[/tex]. Thus, option D is correct.
The buffers are the solutions of acids and base of appropriate pH, that are able to limit the change in pH in the reaction mixture.
Which compound is used for pH 9 buffer?The buffer pH is adjusted with the compounds that has been able to add base or acid to the solution.
For the formulation of buffer of specific pH, the acid and base solutions are required.
The compounds that are used for the formulation of the pH 9 buffer are [tex]\rm H_2PO_4^-\;and\;HPO_4^+[/tex], as they are able to provide acid and base to the solution.
Thus, option D is correct.
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H.w. balance the following equations:
a) Iron + chlorine → Iron (iii) chloride
b) Nitrogen + hydrogen → Ammonia
c) Phosphoric acid + sodium carbonate → sodium phosphate + water + carbon dioxide
d) Nitrogen dioxide + water + oxygen → Nitric acid
Answer:
3iron + chlorine=iron3 chloride
nitrogen +3hydrogen
Answer:
a) Iron + chlorine → Iron (iii) chloride
3fe+cl__fe3cl
b) Nitrogen + hydrogen → Ammonia
2N+3h2------2NH3
c) Phosphoric acid + sodium carbonate → sodium phosphate + water + carbon dioxide
2H3PO3+3Na2CO3-----2Na3PO4+3H2O+3CO2
d) Nitrogen dioxide + water + oxygen → Nitric acid
NO2+H2O+O2--NOH
sorry if mistake