Answer:
6.3 atm.
Explanation:
Data obtained from the question include:
Initial pressure (P1) = 6 atm
Initial temperature (T1) = 15°C = 15°C + 273 = 288K
Final temperature (T2) = 30°C = 30°C + 273 = 303K
Final pressure (P2) =..?
Since the volume and number of mole of the hydrogen gas sample is constant, the following equation will used to obtain the new pressure:
P1/T1 = P2/T2
6/288 = P2 /303
Cross multiply
288 x P2 = 6 x 303
Divide both side by 288
P2 = (6 x 303) /288
P2 = 6.3 atm
Therefore, the new pressure of the hydrogen gas sample is 6.3 atm.
Which of the following chemical reactions is reversible?
A. The burning of wood.
OB. The dehydration of copper sulfate (CuSO4).
O C. The neutralization of an acid.
OD. The freezing of water into ice
Reset Selection
The products of a reaction are NaCl and H2O. What does the law of conservation of matter reveal about the reactants in the reaction? A. At least some of the reactants will include NaCl and H2O. B. The reactants will contain only Na, Cl, O, and H in some amounts. C. Na, Cl, O, H, and three other elements were the reactant elements. D. The reactants will have one Na, one Cl, one O, and two H atoms.
Answer:
D
Explanation:
total mass should be equal on both sides
it's a double do displacement reaction
HCl + NaOH --> NaCl + H2O
1. Find the volume ( cm3) of oxygen in: a. 1000cm3 of air b. 50 cm3 of air.
Answer:
A. 210 cm³
B. 10.5 cm³
Explanation:
It is important for us to note that air contains 21% of oxygen, O2. With this idea in mind, let us answer the questions given above.
A. Volume of air = 1000 cm³
Volume of O2 in air =.?
Percentage composition of O2 in air = 21%
Volume of O2 = 21% x 1000
Volume of O2 = 21/100 x 1000
Volume of O2 = 210 cm³
Therefore, the volume of O2 in 1000 cm³ of air is 210 cm³.
B. Volume of air = 50 cm³
Volume of O2 in air =.?
Percentage composition of O2 in air = 21%
Volume of O2 = 21% x 50
Volume of O2 = 21/100 x 50
Volume of O2 = 10.5 cm³
Therefore, the volume of O2 in 50 cm³ of air is 10.5 cm³.
How many molecules are in each sample?
A. 4.9 g H2O
B. 54.4 g N^2
C. 89 g CCI4
D. 11 g C6H12O6
Answer:
To find the number of molecules first find the number of moles.
number of moles (n) = mass / molar mass (M)
then use the formula
N = n × L
where n = number of moles
N = number of entities
L = Avogadro's constant = 6.02 × 10^23entities to find the number of molecules
A. 4.9 g H2O
m = 4.9g
M = (2*1)+(16×1) = 2 + 16 = 18g/mol
n = 4.9/18 = 0.272mol
N = 0.272 × 6.02 × 10^23
= 1.6374*10^23 molecules of H2O
B. 54.4g of N2
m = 54.4g
M(N2) = 14×2 = 28g/mol
n = 54.4/28 = 1.942mol
N = 1.942 * 6.02*10^23
= 1.1690*10^24 molecules of N2
C. 89 g CCI4
m = 89g
M(CCl4) = 12 + (35.5 × 4) = 154g/mol
n = 89/154 = 0.577mol
N = 0.577 × 6.02 × 10^23
= 3.473*10^23 molecules of CCl4
D. 11 g C6H12O6
m = 11g
M(C6H12O6) = (12×6)+(12×1)+(16×6) =
180g/mol
n = 11/180 = 0.0611mol
N = 0.0611 × 6.02×10^23
= 3.678*10^22 molecules of C6H12O6
Hope this helps
PLEASE HELP ! ! ! Three quantum numbers are derived from Schrodinger’s equation that describe the probability of finding an electron around a nucleus: the principal quantum number, the angular momentum quantum number, and the magnetic quantum number. Define each quantum number.
Answer:
Principle Quantum Number: It describes the size of the orbital and the main energy level. It is represented by n. Where, n = 1,2,3,4....stands for K, L, M, N shell and so on..
Angular momentum Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...
Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as . The value of this quantum number ranges from . When l = 2, the value of will be -2, -1, 0, +1, +2.
Answer:
Principal Quantum Number: designates the principal electron shell. Angular Momentum Quantum Number-This quantum number determines it's shape of an orbital and thus it's angular distribution. This quantum number determines the number of orbital numbers, their orientation within the sub-shell.
Principal Quantum Number, n
It describes the size of its orbital and of the main energy level. It is represented by n. Where, n = 1,2,3,4....stands for K, L, M, N shell and so on..
ngular Momentum Quantum Number l
It describes the shape of the orbital and thus the angular distribution. It can take from 0 to (n - 1). That is l = 0,1,2,...,(n - 1)
The magnetic Quantum Number, m
It describes the orientation of the orbitals. It is represented as . The value of this quantum number ranges from . When l = 2, the value of will be -2, -1, 0, +1, +2.
Explanation:
Which answer below correctly identifies the type of change and the explanation for the boiling of water?
o physical change because even though the change caused the temperature of the water to
increase, the water's physical properties remained exactly the same
o physical change because even though gas formation was observed, the water was undergoing a
state change, which means that its original properties are preserved
chemical change because gas formation was observed, which indicated that the water was
transformed into a different substance
O chemical change because a temperature change was observed, which indicated that the water
was transformed into a different substance
Answer:
O chemical change because a temperature change was observed, which indicated that the water
Explanation:
I have taken this class
Which will a positively charged object attract? an object that has a negative charge an object that has a smaller positive charge an object that has no charge an object that has a larger positive charge
Answer:
it will attract an object that has a negative charge
Positively charged objects will attract negatively charged objects.
Law of magnetic attractionsAccording to the law "like charges repel, unlike charges attract', a positively charged substance will repel other positively charged substances.
On the other hand, a positively charged substance will attract every other substance that is negatively charged.
More on the law of magnetic attraction can be found here: https://brainly.com/question/8515415
1.1 The elements with the lowest ionization energy of all element are
O The noble gases
O The alkali metals
O The alkaline earth metals
O The halogens
Answer:
O The alkali metalsThe elements with the lowest ionization energy of all element are alakli metals
Explanation:
According to research,
The element with the lowest ionization energy is cesium (Cs). Cesium has atomic number 55 and is in the fifth row of the periodic table.
Caesium is a soft, silvery-golden alkali metal .