DETERMINE THE BCD EQUIVALENT OF 1100111110101001

Answer:

Explanation:

No, the reading is not expected to be accurate. This is because Relative to Earth, the air on Mars is extremely thin. The Martian atmosphere is primarily carbon dioxide with a much lower surface pressure, and Mars does not have oceans and an Earthlike hydrological cycle so latent heat release is not as important as it is for Earth.

Answer:

i would think a couple of seconds

Answer:

[tex]A_[avg}=1.81m/s[/tex]

Explanation:

From the question we are told that:

North Movement

Velocity[tex]V=2.8[/tex]

Time  [tex]t=46 minuites[/tex]

South movement

Distance [tex]d=3,132[/tex]

Time [tex]t'= 54 minutes[/tex]

Generally the equation for Average Velocity is mathematically given by

[tex]A_[avg}\]frac{Total distance}{Total time}[/tex]

Where

Total distance d_t

[tex]d_t=Souther\ distance\ traveled\ +Northern\ distance\ traveled[/tex]

[tex]d_t=(2.8*46*60)+(3132)[/tex]

[tex]d_t=10860[/tex]

An

Total Time

[tex]T=(46+54)60[/tex]

[tex]T=6000[/tex]

Therefore

[tex]A_[avg}=\frac{d_t}{T}[/tex]

[tex]A_[avg}=\frac{10860}{6000}[/tex]

[tex]A_[avg}=1.81m/s[/tex]

Answer:

Electromagnetic waves are produced whenever electric charges are accelerated. This makes it possible to produce electromagnetic waves by letting an alternating current flow through a wire, an antenna. The frequency of the waves created in this way equals the frequency of the alternating current.

Explanation:

Answer:

1. Reticular formation.

2. Hypothalamus.

3. Thalamus.

4. Hypothalamus.

5. Thalamus.

Explanation:

The human brain consists of various sections and these includes;

I. Anterior Cingulate Cortex (ACC) which resembles a bow or collar surrounding the frontal part of the corpus callosum. This is the frontal part of the cingulate cortex which helps to make complex cognitive functions such as impulse control, decision-making, emotions and empathy.

II. Ventral prefrontal cortex in humans are interconnected with the brain and are responsible for the processing of risk, empathy, fear and social decision-making

III. The Cerebral Cortex: this part of the brain primarily comprises of grey matter, foldable sheets of neurons and forms its outermost layer. Therefore, cerebral cortex is known as the outermost layer of the brain (cerebrum) and thus, makes up half of its weight. It is about 2.5 millimeters in thickness and as such it's able to fold.

1. Reticular formation: regulates and maintains brain's awareness level.

2. Hypothalamus: controls the activity of the pituitary gland.

3. Thalamus: relays impulses from one part of the brain to another.

4. Hypothalamus: regulates body temperature, hunger, and other internal body conditions.

5. Thalamus: connects nerve impulses from body to cortex.

Answer: D. movement of material along a coast by waves that approach at an angle to the shore.​

Explanation:

Longshore drift is also referred to as the littoral druft and it means the sediment that is moved by the longshore current.

Longshore drift is the movement of material along a coast by waves which approach at an angle to the shore but then recede down the beach.

Therefore, the correct option is D.

16 because complementary angles equal up to 90. 2x+58 = 90 x= 16

Answer:

   v_s = 34.269 m / s

Explanation:

This is a Doppler effect exercise, in this case the observer is fixed and the sound source is moving.

         f ’= f  [tex]\frac{v}{v \mp v_s }[/tex]

where the negative sign is used for when the source approaches the observer and the positive sign for when the source moves away from the observer

In this case when f ’= 5500 Hz approaches and when f’ = 4500 Hz moves away, let's write the two expressions together

          5500 = f ([tex]\frac{v}{v - v_s }[/tex])

          4500 = f ( [tex]\frac{v}{v + vs}[/tex])

let's solve these two equations

           [tex]\frac{5500}{4500} = \frac{v+v_s}{v-v_s}[/tex]

           1.222 (v-v_s) = v + v_s

            v_s (1+ 1.22) = v (1.222 -1)

            v_s = v   [tex]\frac{0.222}{2.223}[/tex]

the speed of sound in air is v = 343 m / s

            v_s = 343 0.09990

             v_s = 34.269 m / s

Answer:

The answer is option no. A

Answer:

v_f = 10.38 m / s

Explanation:

For this exercise we can use the relationship between work and kinetic energy

          W = ΔK

note that the two quantities are scalars

Work is defined by the relation

          W = F. Δx

the bold are vectors.  The displacement is

          Δx = r_f -r₀

          Δx = (11.6 i - 2j) - (4.4 i + 5j)

          Δx = (7.2 i - 7 j) m

          W = (4 i - 9j). (7.2 i - 7 j)

remember that the dot product

           i.i = j.j = 1

           i.j = 0

           W = 4  7.2 + 9  7

           W = 91.8 J

the initial kinetic energy is

           Ko = ½ m vo²

           Ko = ½ 2.0 4.0²

           Ko = 16 J

we substitute in the initial equation

          W = K_f - K₀

          K_f = W + K₀

          ½ m v_f² = W + K₀

          v_f² = 2 / m (W + K₀)

          v_f² = 2/2 (91.8 + 16)

           v_f = √107.8

          v_f = 10.38 m / s

Answer:

carbon d

Explanation:

Answer:

h = 18.65 m

Explanation:

Given that,

The mass of a boulder, m = 268 kg

The potential energy at the hill, E = 50,000 J

We need to find the height of the hill.

We know that, the potential energy of an object is given by :

E = mgh

Where

h is the height of the hill

So,

[tex]h=\dfrac{E}{mg}\\\\h=\dfrac{50000}{268\times 10}\\\\h=18.65\ m[/tex]

So, the height of the hill is 18.65 m.

[tex]\\ \sf\longmapsto PE=mgh[/tex]

[tex]\\ \sf\longmapsto 50000=268(10)h[/tex]

[tex]\\ \sf\longmapsto 50000=2680h[/tex]

[tex]\\ \sf\longmapsto h=\dfrac{50000}{2680}[/tex]

[tex]\\ \sf\longmapsto h=18.65m[/tex]

Answer:

D Venus

Explanation:

in terms of size, average, density, mass and surface gravity venus is similar to earth

Answer:

the correct answers is D

Explanation:

Thermal energy can be transferred by three methods: conduction, convention, and radiation.

Radiation transfer occurs when there is no movement of matter for the exchange of energy.

In this case, checking the correct answers is D

since in this case the transfer is between light and sand without matter exchange

Answer:

Yes

Explanation:

Answer:

Following are the solution to the given question:

Explanation:

Its strength from both charges is equivalent or identical. The power is equal. And it is passed down

[tex]F=\frac{kq_1q_2}{r^2}[/tex]

Therefore, the extent doesn't rely on the fact that charges are the same or different. Newton's third law complies with Electrostatic Charges due to a couple of charges. They are similar in magnitude, and they're in the other way.

[tex]|F_{12}| = |F_{21}|[/tex]

-A solid has a definite shape and volume.

-Solids in general have higher density.

-In solids, intermolecular forces are strong.

Answer:

Explanation:

Power of defective eye = (1 / near point )+ (1 / lens-retina distance )

1 / .0198 m  =  (1 / near point )+ (1 / .02 m  )

= 50.50 = (1 / near point )+ 50

0.50 = 1 / near point

near point = 1 / .5 = 2m

= 200 cm .

for near point at 25 cm , convex lens will be required.

u = - 25 cm , v = - 200 cm ,

1 / v - 1 / u = 1 /f for lens

- 1 / 200 +  1 / 25 = 1 / f

= .04 - .005 = 1 /f

.035 = 1 / f

f = 28.57 cm = 0.2857 m

power = 1 /f

= 1 / 0.2857

= 3.5 D .

i v ) option is correct .

Answer:

F =28.57 N

Explanation:

Assuming that the spring is ideally followed  Hooke's law, This means

F=kx

Here F is the force required to stretch or compress the spring through x distance.

the amount of the work done in the displacement of the spring would be:

W = ∫F.dx

=∫kx dx

=1/2kx^2

=1/2k×0.14^2

⇒ 0.0098k =2

⇒ k = 204.081

Therefore, the force (in Newtons) that holds the spring stretched at the same distance.

F = 204.081×0.14

F =28.57 N

Answer:

E = 66.44 J

Explanation:

From the law of conservation of energy:

Total Mechanical Energy at Start = Total Mechanical Energy at the End

Potential Energy at Start = Kinetic Energy at End + Energy Lost

[tex]mgh = \frac{1}{2} mv^2 + E\\\\E = mgh - \frac{1}{2} mv^2\\\\[/tex]

where,

E = Energy turned into heat = ?

m = mass of block = 2 kg

g = acceleration due to gravity = 9.81 m/s²

h = height = 12 m

v = final speed = 13 m/s

Therefore,

[tex]E = (2\ kg)(9.81\ m/s^2)(12\ m)-\frac{1}{2} (2\ kg)(13\ m/s)^2\\\\E = 235.44\ J - 169\ J\\[/tex]

E = 66.44 J

Answer:

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{6}{3} \\ = 2[/tex]

We have the final answer as

Hope this helps you

Answer:

Rest and motion are the relative terms because they depend on the observer's frame of reference. So if two different observers are not at rest with respect to each other, then they too get different results when they observe the motion or rest of a body.

Explanation With Example:

Imagine you are sitting inside a moving bus. When you look outside you will observe that you are moving. ... With respect to the roof of bus, you are at rest. Hence it is concluded that rest and motion are relative terms.

Given :

The temperature of 10 kg of a substance rises by 55oC when heated.

To Find :

The  temperature rise when 22 kg of the substance is heated with the same quantity of heat.

Solution :

We know, change in temperature when heat is given to object is given by :

[tex]\Delta H = m S\Delta T[/tex]

It is given that same amount of heat is given in both the cases also the substance is same.

So,

[tex]M_1 S \Delta T_1 = M_2 S \Delta T_2\\\\10\times 55 = 22 \times \Delta T_2\\\\\Delta T_2 = 25^o\ C[/tex]

Hence, this is the required solution.

Answer:

[tex]x_2=1.60m[/tex]

Explanation:

From the Question We are told that

Initial Force [tex]F_1=5800N[/tex]

Final Force [tex]F_2=6500N[/tex]

Distance between the front and rear wheels \triangle x=3.20 m

Since

 [tex]\triangle x=3.20 m[/tex]

Therefore

 [tex]x_1+x_2=3.20[/tex]

 [tex]x_1=3.20-x_2[/tex]

Generally the equation for The center of mass is at x_2 is mathematically

given by

 [tex]x_2 =\frac{(F_1x_1+F_2x_2)}{(F_1+F_2)}[/tex]

 [tex]x_2=3.20F_1-\frac{x_2F_1+F_2x_2}{(F_1+F_2)}[/tex]

 [tex]2*F_1*x_2 =3.20F_1[/tex]

 [tex]x_2=1.60m[/tex]

Center of gravity of a body is the  sum of its moments divided by the overall weight of the object. The distance between the front wheels and the truck's center of gravity is 1.6 meters.

Given-

Scale reading value when the front wheels drive over the scale [tex]m_{1}[/tex] is 5800 N.

Scale reading value when the rear wheels drive over the scale [tex]m_{2}[/tex] is 6500 N

Distance between the front and rear wheel [tex]\bigtriangleup x[/tex] is 3.20 meters.

Let, the distance between the front wheels and the truck's center of gravity is [tex]x_{2}[/tex].

Since sum of the distance between front wheel to truck's center of gravity [tex]x_{1}[/tex], and rear wheel to truck's center of gravity [tex]x_{2}[/tex], is equal to the distance between the front and rear wheel [tex]\bigtriangleup x[/tex]. Therefore,

[tex]\bigtriangleup x=x_{1} +x_{2}[/tex]

[tex]3.20=x_{1} +x_{2}[/tex]

[tex]x_{1} =3.20-x_{2}[/tex]

For the distance between the front wheels and the truck's center of gravity is the formula of center of gravity can be written as,

[tex]x_{2} =\dfrac{m_{1}x_{1}+m_{2} x_{2} }{m_{1} +m_{2} }[/tex]

[tex]x_{2} =\dfrac{5800\times (3.20- x_{2})+6500\times x_{2} }{5800 +6500 }[/tex]

[tex]1230 x_{2} ={18560-5800 x_{2}+6500 x_{2} }[/tex]

[tex]x_{2}= 1.6[/tex]

Hence, the distance between the front wheels and the truck's center of gravity is 1.6 meters.

For more about the center of gravity, follow the link below-

https://brainly.com/question/20662119

Answer:

V = 346.15 Volts

Explanation:

Given that,

Diameter of the sphere, d = 0.390 cm

Radius, r = 0.195 cm

Charge, [tex]q=75\ pC =75\times 10^{12}\ C[/tex]

The electric potential near its surface is given by :

[tex]V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 75\times 10^{-12}}{0.195\times 10^{-2}}\\\\V=346.15\ V[/tex]

So, the potential near its surface is equal to 346.15 V.

Answer:

the electric charge in the Earth is -5.91 × 10⁵ C

Explanation:

Given the data in the question;

Electric field E = 131 N/C

we know that; radius of the earth r = 6,371 km = 6371000 m

and Coulomb's constant k = 8.99 × 10⁹ Nm²/c²

Now, using the following formula to calculate the charge;

E = k × Q/r²

we make Q the subject of the formula

Q = Er² / k

so we substitute

Q = [ 131 N/C × ( 6371000 m )² ] / 8.99 × 10⁹ Nm²/c²

Q = [ 5.317242971 × 10¹⁵ ] / [ 8.99 × 10⁹ ]

Q = 5.91 × 10⁵ C

Since the electric field pointing downward

Q = -5.91 × 10⁵ C

Therefore,  the electric charge in the Earth is -5.91 × 10⁵ C