Answer:
Standard reduction potential is an intensive property---- True
Reduction takes place at the anode ----- False
The half reaction with the lower standard reduction potential will be at the cathode in a galvanic cell ------false
The half reaction with the higher standard reduction potential will be at the cathode in a galvanic cell ------ True
Explanation:
An intensive property is a property of a substance which is inherent in it and part of its nature. It does not depend on the amount of substance present in the substance. Standard reduction potential is an intensive property.
In a galvanic cell, oxidation takes place at the anode and reduction takes place at the cathode. At the anode, the electrode potential is more negative (an oxidation) while at the cathode the reduction potential is less negative (a reduction).
Reduction potential is an intensive property of cell, reduction takes place at cathode of galvanic cell, the half reaction with the lower standard reduction potential will be at the anode in a galvanic cell and half reaction with the higher standard reduction potential will be at the cathode in a galvanic cell.
What is Galvanic cell?
Galvanic cell is also known as voltaic cell, and in this cell electric current is originated from spontaneous redox reaction.
In the galvanic cell, anode is a negatively charged electrode in which oxidation process takes place and value of electrode potential is more negative. Cathode is a positively charged electrode in which reduction process takes place and electrode potential is less negative. And intensive property is not depends on the amount of substance.
Hence, correct statements are true, false, false and true.
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A student was directed to convert the mass of a boulder from kg to pounds.
Conversion factor: 1 pound = 454 g
The mass is 22 kg. The student calculated the weight to be 0.048 pounds.
Is this correct? If not, what went wrong?
Answer:
Incorrect
Explanation:
Given that,
The mass of a boulder, m = 22 kg
We need to find the weight of the student in pounds.
We know that,
1 pound = 454 g
or
1 g = (1/454 pounds)
22 kg = 0.022 grams
So,
0.022 grams = [tex]\dfrac{0.022}{454}\ pounds[/tex]
= 0.000048 pounds
The student says the weight is 0.048 pounds. It means he was incorrect.
Determine the m/v% of a solution where 5 g of sugar is dissolved in enough water to yield 250 mL of total solution
Answer:
2 %m/v
Explanation:
Step 1: Given data
Mass of sugar (solute): 5 gVolume of solution: 250 mLStep 2: Calculate the %m/v of sugar in the solution
We will use the following expression.
%m/v = mass of sugar/volume of solution × 100%
%m/v = 5 g/250 mL × 100% = 2 %m/v
This means that there are 2 grams of sugar every 100 milliliters of solution.
find the percentage of mass in each of the element Ca ( HCO3)2 (Ca= 40, H = 1, O = 16, C= 35)
Answer:
% Ca = 24.69%
% H = 1.2%
% C = 14.8%
% O = 59.25%
Explanation:
The percentage by mass of each element can be calculated by dividing the mass of each element in the compound by the molar mass of the compound.
Molar mass of Ca(HCO3)2
Where; (Ca= 40, H = 1, O = 16, C= 12)
= 40 + {1 + 12 + 16(3)}2
= 40 + {13 + 48}2
= 40 + {61}2
= 40 + 122
= 162g/mol
- % mass of Ca = 40/162 × 100
= 0.2469 × 100
= 24.69%
- % mass of H = 2/162 × 100
= 0.012 × 100
= 1.2%
- % mass of C = 24/162 × 100
= 0.148 × 100
= 14.8%
- % mass of O = 96/162 × 100
= 0.5925 × 100
= 59.25%
describe one similarity and one difference between amylopectin and glycogen?
Answer: The main difference between amylopectin and glycogen is that amylopectin is an insoluble form whereas glycogen is a soluble form. The 1,4-alpha glycosidic bonds form the linear chain of both amylopectin and glycogen while 1,6-alpha glycosidic bonds form the branches.
Explanation:
The distance that is covered by the wave in one second is called
Answer:
The distance that is covered by the wave in one second is called frequency.
Explanation:
what is the name of this structure here please and thanks
Answer:
look at the file that the other person sent
Concentration is ? 
anyone know the name of this structure please
How much mass of water (H₂O) do I need to mass out if I need 2.5 moles for a reaction?
Answer:
45g
Explanation:
Use the Mole = Mass x Mr equation:
Rearrange the above equation to find mass,
Mass = 2.5 moles x 18 (Mr of H₂O) = 45g
Therefore answer is 45g
Answer:
Given
number of moles (n) =2 . 5 mol
R.tc maas of H2O (m) =?
sln
H2O =(1x2+16)
=18g/mol
n=m/mr
m=nxmr
m=2.5x18
m=45g
mass of water is 45g
A balloon filled with helium has a volume of 30.0 L at a pressure of 100 kPa and a temperature of 15.0°C. What will the volume of the balloon be if the temperature is decreased to -80.0°C and the pressure remains constant?
Answer:
[tex]V_2=20.1L[/tex]
Explanation:
Hello there!
In this case, since this is a problem in which the pressure of the gas remains constant, we can use the Charles' law as a directly proportional relationship between temperature (in Kelvins) and volume given by:
[tex]\frac{V_2}{T_2} =\frac{V_1}{T_1}[/tex]
Thus, solving for the final volume as the temperature is decreased to -80.00 °C, we obtain:
[tex]V_2=\frac{V_1T_2}{T_1}[/tex]
[tex]V_2=\frac{30.0L*(-80+273)K}{(15+273)K} \\\\V_2=20.1L[/tex]
Best regards!
Phosphoric acid is neutralized by potassium hydroxide according to the following reaction:
KOH (aq) + H3PO4 (aq) → K3PO4 (aq) + H2O (1)
What is the concentration of a phosphoric acid solution if 25.0 mL are exactly neutralized by 20.0 mL of 2.000 M KOH solution?
2.54 mL of ethanol to mol ethanol
help me with this question
In physical and chemical changes, the number of atoms and weight of the object always stays the same.
In a chemical change, the substance changes into a different substance.
I'm pretty sure this next one is can or can not be seperated, depending on what has been mixed. Not positive tho.
How are ocean waves formed? gravity energy transfer conduction radiation
Answer:
I apologize that I'm late and all But your answer is B. Energy Transfer.
Explanation:
The waves transfer energy to the sand for example.
help pls i give twenty points and brainlist
Answer:
C and B are the correct answers
HELP!
The law of conservation of energy states:
A. Energy increases exponentially with times
B. Total energy decreases due to energy output.
C. Energy cannot be created or destroyed.
D. Energy always remains in the same form.
Answer:
C
Explanation:
energy cannot be created or destroyed like solar energy for instance. it is already energy because it comes from the sun and for other reason.
Hope this helps!
Any help?
The Kb for hydroxylamine, HONH2, is 1.1 x 10 -8
. What would be the pH of a solution
prepared by placing 1.34 g of HONH2 in 0.500 L of water?
Answer:
pH = 9.475
Explanation:
Hello there!
In this case, according to the basic ionization of the hydroxylamine:
[tex]HONH_2+H_2O\rightarrow HONH_3^++OH^-[/tex]
The resulting equilibrium expression would be:
[tex]Kb=\frac{[HONH_3^+][OH^-]}{[HONH_2]} =1.1x10^{-8}[/tex]
Thus, we first need to compute the initial concentration of this base by considering its molar mass (33.03 g/mol):
[tex][HONH_2]_0=\frac{1.34g/(33.03g/mol)}{0.500L} =0.0811M[/tex]
Now, we introduce [tex]x[/tex] as the reaction extent which provides the concentration of the hydroxyl ions to subsequently compute the pOH:
[tex]1.1x10^{-8}=\frac{x^2}{0.0811-x}[/tex]
However, since Kb<<<<1, it is possible to solve for [tex]x[/tex] by easily neglecting it on the bottom to obtain:
[tex]x=[OH^-]=\sqrt{1.1x10^{-8}*0.0811}= 2.99x10^{-5}[/tex]
Thus, the pOH is:
[tex]pOH=-log(2.99x10^{-5})=4.525[/tex]
And the pH:
[tex]pH=14-4.525\\\\pH=9.475[/tex]
Regards!
how many core electrons does magnesium ion have
Answer:
10 core electrons
Explanation:
Answer:
Magnesium has 10 core electrons
Why glucose (monosaccharide) and maltose (disaccharide) give positive Benedict test?
Answer:
please give me brainlist and follow
Explanation:
Substance in water + 3 mL Benedict's solution, then boil for few minutes and allow to cool. The common disaccharides lactose and maltose are directly detected by Benedict's reagent because each contains a glucose with a free reducing aldehyde moiety after isomerization.
Glucose and maltose give a positive Benedict test because they have a free carbonyl group to undergo oxidation.
Explanation:
The monosaccharides are sugars that cannot be further hydrolyzed into simpler sugars like glucose, fructose, ma, etc.The disaccharides are sugars that on hydrolysis give two monosaccharide units like sucrose, lactose, maltose, etc.The polysaccharides are sugars that on hydrolysis give more than two monosaccharide units like sucrose, lactose, maltose, etc.Reducing sugars are which have a free carbonyl group that oxidizes into a carboxylic acid and reduces Benedict reagent like glucose, maltose, etc.Non-reducing sugars which don't have a free carbonyl group like sucrose, all polysaccharides, etc.Benedict test is a chemical test performed to test the presence of reducing sugars.The Benedict reagent is a complex made up of sodium citrate, sodium carbonate, and copper sulfate pentahydrate.The positive test for reducing sugar will be the red coloration of the solution due to the formation of copper(II) oxide.So, from this, we can conclude that glucose and maltose give a positive Benedict test because they have a free carbonyl group to undergo oxidation.
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NEED A AWNSER ASAP PLEASE!!!!
Answer:
2. the second one is the answer
Because it shows both potential and kinetic energy
What do you call the reaction between magnesium hydroxide and hydrochloric acid?
Answer:
neutralization reaction
The neutralization reaction is the reaction between Mg(OH)2 (a weak base) and HCl (a strong acid).
Explanation:
The following pairs of soluble solutions can be mixed. In some cases, this leads to the formation of an insoluble precipitate. Decide, in each case, whether or not an insoluble precipitate is formed.
a. AlCl3 and K3PO4
b. RbCO3 and NaCl
c. Na2CO3 and MnCl2
d. K2S and NH4Cl
e. CaCl2 and (NH4)2CO3
Answer:
See explanation
Explanation:
Let us see what happens when each solution is mixed;
a) AlCl3(aq) + K3PO4(aq) ------> 3KCl(aq) + AlPO4(s)
A precipitate is formed here
b) RbCO3(aq) + NaCl(aq) -------> This is an impossible reaction hence no solid precipitate is formed here
c) MnCl2(aq) + Na2CO3(aq) → 2NaCl(aq) + MnCO3(s)
A precipitate is formed.
d) K2S(aq) + 2NH4Cl(aq) ------> 2KCl(aq) + (NH4)2S(aq)
No solid precipitate is formed
e) CaCl2(aq) + (NH4)2CO3(aq) → CaCO3(s) + 2NH4Cl(aq)
A solid precipitate is formed
Mg(OH)2 is a compound. How many different elements are found in this compound?
Ο Α. 1
ОВ. 3 3
O c. 2
Answer:
3
Explanation:
3 different elements are found
Mg - magnesium
O -oxygen
H - hydrogen
'
mark brainliest
Answer: 3
Explanation:
Experimental Data
Enter the data shown in the video for Unknown Sulfate #23 below or where required, calculate the value from your data:
Mass of empty 250-mL beaker (from video) =129.536g
Mass of 250-mL beaker and unknown sulfate (from video) =129.840g
Mass of unknown sulfate (calculated) =0.304g
Mass of empty crucible (from video) =10.320g
Mass of crucible and barium sulfate (from video) =10.723g
Mass of barium sulfate =0.403g
Calculations and Conclusions
Calculate the mass of sulfate in the unknown sample:
Mass of sulfate in unknown =_______g
Calculate the percentage by mass of sulfate in the unknown sample:
Mass percent of sulfate in unknown =
%
The cation in the unknown sulfate is one of the following:
Al3+ Na+ Ni2+ K+ NH4+ Cd2+
For each of these six cations, write the formula of its sulfate, and calculate the percentage mass of sulfate in the compound.
Formula of aluminum sulfate =
Mass percent of sulfate in aluminum sulfate =
%
Formula of sodium sulfate =
Mass percent of sulfate in sodium sulfate =
%
Formula of nickel(II) sulfate =
Mass percent of sulfate in nickel(II) sulfate =
%
Formula of potassium sulfate =
Mass percent of sulfate in potassium sulfate =
%
Formula of ammonium sulfate =
Mass percent of sulfate in ammonium sulfate =
%
Formula of cadmium sulfate =
Mass percentage of sulfate in cadmium sulfate =
You read a primary source and a secondary source that discuss the same
experiment. There is a difference in the conclusions made by these two
sources. Which should you trust more, and why?
A. The primary source, because it is more confusing
B. The secondary source, because it is published in a well-respected
newspaper
C. The secondary source, because it is easier to read
D. The primary source, because it is written by the scientist who did
the work
Answer:
i think it's D tbh, just cus it was the scientist who did the work
Answer:
It depends on secondary sources and references of that secondary source. If it references just that primary source I would compare both of them and see the difference between them. Generally primary sources are more reliable but this situation is different.
Nickel carbonyl decomposes to form nickel and carbon monoxide, like this:
Ni(CO)4 → Ni + 4CO
At a certain temperature, a chemist finds that a 2.7L reaction vessel containing a mixture of nickel carbonyl, nickel, and carbon monoxide at equilibrium has the following composition:
Compound Amount
Ni(CO)4 0.597g
Ni 12.7g
CO 1.98g
Calculate the value of the equilibrium constant for this reaction. Round your answer to significant digits.
Answer: The value of the equilibrium constant for this reaction is [tex]2.8\times 10^{-5}[/tex]
Explanation:
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
Moles of [tex]Ni(CO)_4[/tex] = [tex]\frac{0.597g}{170.7g/mol}=0.0035moles[/tex]
Moles of [tex]Ni[/tex] = [tex]\frac{12.7g}{58.7g/mol}=0.216moles[/tex]
Moles of [tex]CO[/tex] = [tex]\frac{1.98g}{28.01g/mol}=0.071moles[/tex]
Volume of solution = 2.7 L
Equilibrium concentration of [tex]Ni(CO)_4[/tex] = [tex]\frac{0.0035mol}{2.7L}=1.29\times 10^{-3}M[/tex]
Equilibrium concentration of [tex]Ni[/tex] = [tex]\frac{0.216mol}{2.7L}=0.08M[/tex]
Equilibrium concentration of [tex]CO[/tex] = [tex]\frac{0.071mol}{2.7L}=0.026M[/tex]
The given balanced equilibrium reaction is,
[tex]Ni(CO)_4\rightleftharpoons Ni+4CO[/tex]
The expression for equilibrium constant for this reaction will be,
[tex]K_c=\frac{[Ni]^1\times [CO]^4}{[Ni(CO_4]^1}[/tex]
Now put all the given values in this expression, we get :
[tex]K_c=\frac{(0.08)^1\times (0.026)^4}{(1.29\times 10^{-3})^1}[/tex]
[tex]K_c=2.8\times 10^{-5}[/tex]
Thus the value of the equilibrium constant for this reaction is [tex]2.8\times 10^{-5}[/tex]
What is the name of PbS2
Answer:
Lead sulfide.
Explanation:
150. g of aluminum chloride in 0.450 liters of solution, what is the concentration? (any examples are helpful, thank you)
Answer:
2.49 M
Explanation:
Step 1: Given data
Mass of AlCl₃: 150. gVolume of solution: 0.450 LStep 2: Calculate the moles AlCl₃ (solute)
The molar mass of AlCl₃ is 133.34 g/mol.
150. g × 1 mol/133.34 g = 1.12 mol
Step 3: Calculate the molar concentration of AlCl₃
Molarity is equal to the moles of solute divided by the liters of solution.
M = 1.12 mol/0.450 L = 2.49 M
A compound contains 53% Al and 47% O by mass. What
is the empirical formula of this compound?
Answer:
Al2O3
Explanation:
Empirical formula is found by converting percent composition into a mole ratio.
First, assume you have a 100g sample of the substance. This allows you to make your percent composition into grams.
100% = 100g
53% = 53g Al
47% = 47g O
Next, divide each substance's mass by their molar mass. This converts your number to moles.
[tex]53g Al / 27g Al = 1.96 mol\\\\47g O/16g O = 2.93mol[/tex]
Next, divide both mol answers by the smallest number of moles.
[tex]1.96mol/1.96mol = 1\\2.93mol/1.96mol = 1.5[/tex]
Usually, these answers would be your subscripts for your empirical formula. However, we cannot have a decimal subscript, so we will multiply our answers by a factor of 2 to get to a whole number. This gives us 2 moles of Al and 3 moles of oxygen, or a formula of Al2O3.
Considering the definition of empirical formula, the correct answer is the second option: the empirical formula is Al₂O₃.
Definition of empirical formulaThe empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.
Empirical formula in this caseAssuming a 100 grams sample, the percentages match the grams in the sample. So you have 53 grams of Al and 47 grams of O.
Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:
Al: [tex]\frac{53 grams}{27 \frac{grams}{mole} }[/tex]= 1.9629 moles
O: [tex]\frac{47 grams}{16 \frac{grams}{mole} }[/tex]= 2.9375 moles
The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:
Al: [tex]\frac{1.9629 moles}{1.9629 moles}[/tex]= 1
O: [tex]\frac{2.9375 moles}{1.9629 moles}[/tex]≅ 1.5
You cannot have a decimal subscript, so you will multiply our answers by a factor of 2 to get to a whole number:
Al: 1× 2= 2
O: 1.5× 2= 3
Therefore the Al:O mole ratio is 2: 3
Finally, the correct answer is the second option: the empirical formula is Al₂O₃.
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igneous sedimentary, and metamorphic rocks are found at the same cliff side.Which statement is correct?
Answer:
The metamorphic rock and sedimentary rock were already at this location and magma flowed into other rocks
Explanation: